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Exam Answer TemplatesCivil Service Exam (Professional) · Numerical Ability

Civil Service Exam (Professional) Numerical Ability — Algebra, Exponents & Number SeriesExam Answer Templates

Answer templates for Algebra, Exponents & Number Series questions in the Civil Service Exam (Professional): how to set out a solution step by step, with model answers.

Super Tutor's review for Civil Service Exam (Subprofessional) uses these same chapters, so they live here in the Civil Service Exam (Professional) section.

Algebra, Exponents & Number Series - Exam Answer Templates

Proper answer writing is crucial for maximizing your scores in Civil Service examinations and college entrance tests. These templates show you exactly how to structure your answers to earn full marks. Each template demonstrates the precise format, key terms, and step-by-step approach that examiners expect. Following these patterns will help you write clear, complete answers that demonstrate your understanding while meeting all marking criteria.

Answer templates

Simplify: 3^4 × 3^2

Laws of Exponents - Product Ruleeasyshort answer2 marks

Examiner tip

Always write the exponent law you're using - this shows you understand the concept, not just memorized calculations

Model answer

Given: 3^4 × 3^2

Using the Product Rule for exponents: a^m × a^n = a^(m+n)
3^4 × 3^2 = 3^(4+2) = 3^6 = 729

Therefore, 3^4 × 3^2 = 729

Answer structure

  • Line 1: State the given expression [0.5 marks]
  • Line 2: Apply the correct exponent law [1 mark]
  • Line 3: Calculate the final answer [0.5 marks]

Scoring breakdown

1 mark

Criteria

Correctly applies product rule of exponents

1 mark

Criteria

Arrives at correct final answer

Common mark deductions

  • Not showing the rule used
  • Arithmetic errors in final calculation
  • Not stating the final answer clearly

Key phrases to include

  • Product Rule
  • a^m × a^n = a^(m+n)
  • final answer

Find the next term in the series: 2, 5, 8, 11, 14, ?

Number Series - Arithmetic Sequenceeasyshort answer3 marks

Examiner tip

Always show the pattern-finding process explicitly - don't just state the answer

Model answer

Given series: 2, 5, 8, 11, 14, ?

Step 1: Find the pattern
5 - 2 = 3
8 - 5 = 3
11 - 8 = 3
14 - 11 = 3

Step 2: Identify the sequence type
This is an arithmetic sequence with common difference d = 3

Step 3: Find the next term
Next term = 14 + 3 = 17

Therefore, the next term is 17.

Answer structure

  • Step 1: Calculate differences between consecutive terms [1 mark]
  • Step 2: Identify the type of sequence [1 mark]
  • Step 3: Apply pattern to find next term [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly identifies the common difference

1 mark

Criteria

Recognizes it as arithmetic sequence

1 mark

Criteria

Calculates correct next term

Common mark deductions

  • Not showing difference calculations
  • Incorrect identification of sequence type
  • Arithmetic errors

Key phrases to include

  • arithmetic sequence
  • common difference
  • pattern

Solve for x: 2^(x+1) = 16

Exponential Equationsmediumshort answer3 marks

Examiner tip

Always verify your answer by substituting back into the original equation

Model answer

Given: 2^(x+1) = 16

Step 1: Express 16 as a power of 2
16 = 2^4

Step 2: Rewrite the equation
2^(x+1) = 2^4

Step 3: Since bases are equal, equate exponents
x + 1 = 4
x = 4 - 1
x = 3

Verification: 2^(3+1) = 2^4 = 16 ✓

Therefore, x = 3

Answer structure

  • Step 1: Express the right side as power of same base [1 mark]
  • Step 2: Apply the principle that equal bases mean equal exponents [1 mark]
  • Step 3: Solve for the variable and verify [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly converts 16 to 2^4

1 mark

Criteria

Properly equates exponents

1 mark

Criteria

Solves correctly and shows verification

Common mark deductions

  • Not converting to same base
  • Algebraic errors
  • Missing verification step

Key phrases to include

  • express as power
  • equal bases
  • verification

Evaluate: (8x^3y^6)/(4x^2y^4)

Laws of Exponents - Quotient Rulemediumshort answer2 marks

Examiner tip

Break down complex expressions into manageable parts - coefficients, then each variable separately

Model answer

Given: (8x^3y^6)/(4x^2y^4)

Step 1: Separate coefficients and variables
= (8/4) × (x^3/x^2) × (y^6/y^4)

Step 2: Apply quotient rule for exponents
= 2 × x^(3-2) × y^(6-4)
= 2 × x^1 × y^2
= 2xy^2

Therefore, (8x^3y^6)/(4x^2y^4) = 2xy^2

Answer structure

  • Step 1: Separate numerical and variable parts [1 mark]
  • Step 2: Apply quotient rule and simplify [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly applies quotient rule for exponents

1 mark

Criteria

Simplifies to correct final form

Common mark deductions

  • Incorrect application of quotient rule
  • Arithmetic errors with coefficients
  • Not simplifying completely

Key phrases to include

  • quotient rule
  • a^m/a^n = a^(m-n)
  • simplify

What is 4^0 + 5^0?

Laws of Exponents - Zero Exponent Ruleeasyvery short answer1 mark

Examiner tip

Remember: any non-zero number to the power 0 always equals 1

Model answer

4^0 + 5^0 = 1 + 1 = 2
(Any non-zero number raised to power 0 equals 1)

Answer structure

  • Apply zero exponent rule and calculate [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly applies zero exponent rule to get answer 2

Common mark deductions

  • Not knowing that a^0 = 1
  • Arithmetic errors

Key phrases to include

  • zero exponent rule
  • equals 1

Find the missing term in the geometric series: 3, 6, 12, ?, 48

Number Series - Geometric Sequencemediumshort answer3 marks

Examiner tip

Always verify your answer fits the pattern by checking it works with surrounding terms

Model answer

Given series: 3, 6, 12, ?, 48

Step 1: Find the common ratio
r = 6/3 = 2
r = 12/6 = 2

Step 2: Verify it's a geometric series
Common ratio r = 2 (constant)

Step 3: Find the missing term
Missing term = 12 × 2 = 24

Verification: 24 × 2 = 48 ✓

Therefore, the missing term is 24.

Answer structure

  • Step 1: Calculate common ratio from given terms [1 mark]
  • Step 2: Confirm geometric sequence pattern [1 mark]
  • Step 3: Apply ratio to find missing term [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly identifies common ratio as 2

1 mark

Criteria

Recognizes geometric sequence pattern

1 mark

Criteria

Calculates missing term correctly

Common mark deductions

  • Not identifying the common ratio
  • Calculation errors
  • Missing verification

Key phrases to include

  • geometric series
  • common ratio
  • verification

Simplify: (3^2)^3

Laws of Exponents - Power Ruleeasyshort answer2 marks

Examiner tip

State the exponent law you're using - it shows conceptual understanding

Model answer

Given: (3^2)^3

Using Power Rule: (a^m)^n = a^(mn)
(3^2)^3 = 3^(2×3) = 3^6

Calculating: 3^6 = 729

Therefore, (3^2)^3 = 729

Answer structure

  • Apply power rule for exponents [1 mark]
  • Calculate final numerical value [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly applies power rule to get 3^6

1 mark

Criteria

Evaluates 3^6 = 729 correctly

Common mark deductions

  • Incorrect application of power rule
  • Calculation errors
  • Not showing the rule

Key phrases to include

  • Power Rule
  • (a^m)^n = a^(mn)

Express 2^(-3) as a positive exponent.

Laws of Exponents - Negative Exponent Rulemediumshort answer2 marks

Examiner tip

Always express negative exponents as positive fractions unless specifically asked for decimal form

Model answer

Given: 2^(-3)

Using Negative Exponent Rule: a^(-n) = 1/a^n
2^(-3) = 1/2^3 = 1/8

Therefore, 2^(-3) = 1/8

Answer structure

  • Apply negative exponent rule [1 mark]
  • Calculate final fraction form [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly applies negative exponent rule

1 mark

Criteria

Calculates 1/8 as final answer

Common mark deductions

  • Not knowing negative exponent rule
  • Arithmetic errors
  • Leaving answer as decimal instead of fraction

Key phrases to include

  • Negative Exponent Rule
  • a^(-n) = 1/a^n

Find the 8th term in the arithmetic sequence: 5, 9, 13, 17, ...

Arithmetic Sequencesmediumshort answer3 marks

Examiner tip

Always state the formula you're using - it demonstrates method knowledge even if calculation errors occur

Model answer

Given: Arithmetic sequence 5, 9, 13, 17, ...
To find: 8th term (a₈)

Step 1: Identify first term and common difference
a₁ = 5
d = 9 - 5 = 4

Step 2: Use arithmetic sequence formula
aₙ = a₁ + (n-1)d
a₈ = 5 + (8-1)×4
a₈ = 5 + 7×4
a₈ = 5 + 28
a₈ = 33

Therefore, the 8th term is 33.

Answer structure

  • Step 1: Identify first term and common difference [1 mark]
  • Step 2: Apply arithmetic sequence formula [1 mark]
  • Step 3: Calculate final answer [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly identifies a₁ = 5 and d = 4

1 mark

Criteria

Uses correct formula aₙ = a₁ + (n-1)d

1 mark

Criteria

Calculates a₈ = 33 correctly

Common mark deductions

  • Wrong common difference calculation
  • Formula errors
  • Arithmetic mistakes

Key phrases to include

  • arithmetic sequence
  • common difference
  • formula aₙ = a₁ + (n-1)d

Solve: x³ = 27

Basic Exponential Equationseasyvery short answer1 mark

Examiner tip

Memorize perfect cubes up to 10³ for quick recognition

Model answer

x³ = 27
x = ∛27 = 3

Therefore, x = 3

Answer structure

  • Take cube root of both sides to find x = 3 [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly finds x = 3 by taking cube root

Common mark deductions

  • Not recognizing 27 as perfect cube
  • Calculation errors

Key phrases to include

  • cube root
  • ∛27 = 3

Find the pattern and next two terms: 1, 4, 9, 16, 25, ?, ?

Number Series - Perfect Squaresmediumshort answer3 marks

Examiner tip

Look for common mathematical sequences like squares, cubes, or factorial patterns

Model answer

Given series: 1, 4, 9, 16, 25, ?, ?

Step 1: Analyze the pattern
1 = 1²
4 = 2²
9 = 3²
16 = 4²
25 = 5²

Step 2: Identify the sequence type
This is a perfect squares sequence: n²

Step 3: Find next two terms
6² = 36
7² = 49

Therefore, the next two terms are 36 and 49.

Answer structure

  • Step 1: Express each term as perfect square [1 mark]
  • Step 2: Identify pattern as n² sequence [1 mark]
  • Step 3: Calculate next two terms [1 mark]

Scoring breakdown

1 mark

Criteria

Recognizes each term as a perfect square

1 mark

Criteria

Identifies pattern as consecutive squares

1 mark

Criteria

Correctly finds 36 and 49

Common mark deductions

  • Not recognizing perfect square pattern
  • Calculation errors
  • Finding only one term instead of two

Key phrases to include

  • perfect squares
  • n² sequence
  • pattern

Simplify: 16^(1/4)

Laws of Exponents - Fractional Exponentsmediumshort answer2 marks

Examiner tip

Remember that fractional exponents represent roots - the denominator tells you which root to take

Model answer

Given: 16^(1/4)

Using Fractional Exponent Rule: a^(1/n) = ⁿ√a
16^(1/4) = ⁴√16

Since 16 = 2⁴, we have:
⁴√16 = ⁴√(2⁴) = 2

Therefore, 16^(1/4) = 2

Answer structure

  • Apply fractional exponent rule [1 mark]
  • Evaluate the fourth root correctly [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly applies fractional exponent rule

1 mark

Criteria

Evaluates to get final answer 2

Common mark deductions

  • Not knowing fractional exponent rule
  • Incorrect root calculation
  • Not recognizing 16 as 2⁴

Key phrases to include

  • Fractional Exponent Rule
  • a^(1/n) = ⁿ√a
  • fourth root

Explain the steps to simplify exponential expressions using the laws of exponents. Give an example.

Complete Laws of Exponents Overviewhardlong answer5 marks

Examiner tip

Structure your answer with clear headings and always include a worked example to demonstrate application

Model answer

Steps to Simplify Exponential Expressions:

Step 1: Apply Product Rule
Multiply terms with same base by adding exponents: aᵐ × aⁿ = aᵐ⁺ⁿ

Step 2: Apply Quotient Rule
Divide terms with same base by subtracting exponents: aᵐ ÷ aⁿ = aᵐ⁻ⁿ

Step 3: Apply Power Rule
Raise a power to another power by multiplying exponents: (aᵐ)ⁿ = aᵐⁿ

Step 4: Apply Zero Exponent Rule
Any non-zero number to power 0 equals 1: a⁰ = 1

Step 5: Apply Negative Exponent Rule
Convert negative exponents to positive: a⁻ⁿ = 1/aⁿ

Example: Simplify (2³ × 2⁵) ÷ 2⁴
Step 1: 2³ × 2⁵ = 2³⁺⁵ = 2⁸ (Product Rule)
Step 2: 2⁸ ÷ 2⁴ = 2⁸⁻⁴ = 2⁴ (Quotient Rule)
Step 3: 2⁴ = 16

Therefore, the expression simplifies to 16.

Answer structure

  • Step 1: Explain Product Rule with formula [1 mark]
  • Step 2: Explain Quotient Rule with formula [1 mark]
  • Step 3: Explain Power Rule with formula [1 mark]
  • Step 4: Explain Zero and Negative Exponent Rules [1 mark]
  • Step 5: Provide complete worked example [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly states Product Rule

1 mark

Criteria

Correctly states Quotient Rule

1 mark

Criteria

Correctly states Power Rule

1 mark

Criteria

States Zero and Negative Exponent Rules

1 mark

Criteria

Provides correct worked example

Common mark deductions

  • Missing any of the five rules
  • Incorrect formulas
  • Poor or missing example
  • Not showing step-by-step solution

Key phrases to include

  • Product Rule
  • Quotient Rule
  • Power Rule
  • Zero Exponent Rule
  • Negative Exponent Rule
  • worked example

Find the sum of first 6 terms of the geometric series: 2, 6, 18, 54, ...

Geometric Series - Sum Formulahardlong answer5 marks

Examiner tip

Always verify your common ratio with at least two consecutive pairs before proceeding

Model answer

Given: Geometric series 2, 6, 18, 54, ...
To find: Sum of first 6 terms (S₆)

Step 1: Identify first term and common ratio
a₁ = 2
r = 6/2 = 3

Step 2: Verify common ratio
18/6 = 3 ✓
54/18 = 3 ✓

Step 3: Find the 5th and 6th terms
a₅ = 2 × 3⁴ = 2 × 81 = 162
a₆ = 2 × 3⁵ = 2 × 243 = 486

Step 4: Use geometric series sum formula
Sₙ = a₁(rⁿ - 1)/(r - 1)
S₆ = 2(3⁶ - 1)/(3 - 1)
S₆ = 2(729 - 1)/2
S₆ = 2(728)/2
S₆ = 728

Therefore, the sum of first 6 terms is 728.

Answer structure

  • Step 1: Identify first term and common ratio [1 mark]
  • Step 2: Verify the common ratio [1 mark]
  • Step 3: Find remaining terms if needed [1 mark]
  • Step 4: Apply geometric series sum formula [1 mark]
  • Step 5: Calculate final answer correctly [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly identifies a₁ = 2 and r = 3

1 mark

Criteria

Verifies common ratio is consistent

1 mark

Criteria

Uses correct geometric series sum formula

1 mark

Criteria

Substitutes values correctly into formula

1 mark

Criteria

Calculates final sum as 728

Common mark deductions

  • Wrong common ratio
  • Using wrong formula
  • Calculation errors
  • Not verifying the ratio

Key phrases to include

  • geometric series
  • common ratio
  • sum formula Sₙ = a₁(rⁿ - 1)/(r - 1)
  • verification

Identify the type of sequence and find the general term: 1/2, 1/4, 1/8, 1/16, ...

Sequence Identification and General Termsmediumshort answer3 marks

Examiner tip

For geometric sequences, always express the general term in its simplest form

Model answer

Given sequence: 1/2, 1/4, 1/8, 1/16, ...

Step 1: Find the pattern
(1/4)/(1/2) = 1/2
(1/8)/(1/4) = 1/2
(1/16)/(1/8) = 1/2

Step 2: Identify sequence type
This is a geometric sequence with:
a₁ = 1/2
r = 1/2

Step 3: Find general term
For geometric sequence: aₙ = a₁ × rⁿ⁻¹
aₙ = (1/2) × (1/2)ⁿ⁻¹
aₙ = (1/2)ⁿ
aₙ = 1/2ⁿ

Therefore, this is a geometric sequence with general term aₙ = 1/2ⁿ

Answer structure

  • Step 1: Calculate ratios to find pattern [1 mark]
  • Step 2: Identify as geometric sequence [1 mark]
  • Step 3: Derive general term formula [1 mark]

Scoring breakdown

1 mark

Criteria

Correctly identifies common ratio as 1/2

1 mark

Criteria

Recognizes geometric sequence pattern

1 mark

Criteria

Derives correct general term aₙ = 1/2ⁿ

Common mark deductions

  • Not identifying sequence type
  • Wrong common ratio
  • Incorrect general term formula

Key phrases to include

  • geometric sequence
  • common ratio
  • general term
  • aₙ = a₁ × rⁿ⁻¹

Mark wise strategy

Direct application of a single concept or rule. Show minimal working but ensure accuracy.

1 mark1-2 lines30 seconds to 1 minute

Do

  • State the rule/formula if applicable
  • Give a clear final answer
  • Show one key step if needed

Don't

  • Over-explain simple concepts
  • Show unnecessary working
  • Leave answer unclear

Apply one main concept with clear working. Show method and arrive at correct answer.

2 marks3-4 lines1-2 minutes

Do

  • State what rule you're using
  • Show the key calculation step
  • Present final answer clearly

Don't

  • Skip the method/rule
  • Make careless arithmetic errors
  • Forget to state the final answer

Multi-step solution requiring 2-3 concepts. Show clear progression from given to answer.

3 marks4-6 lines2-3 minutes

Do

  • Break into logical steps
  • Show all working clearly
  • Verify answer when possible
  • Label steps appropriately

Don't

  • Jump steps without explanation
  • Mix up different concepts
  • Forget intermediate calculations

Comprehensive answer covering multiple concepts or detailed explanation with examples.

5 marks8-12 lines4-6 minutes

Do

  • Use clear headings/structure
  • Provide complete explanations
  • Include worked examples
  • Cover all required points
  • Show mastery of topic

Don't

  • Rush through explanations
  • Miss key concepts
  • Provide incomplete examples
  • Write without structure

General answer writing tips

  • Always show your work step-by-step for numerical problems - partial credit is often given for correct methods
  • Use proper mathematical notation and symbols - this demonstrates technical proficiency
  • State the given information clearly at the beginning of your answer
  • Circle or box your final answer to make it easily identifiable
  • For exponent problems, apply laws systematically and show each step
  • In number series questions, identify the pattern first, then explain your reasoning
  • Use clear headings like 'Given:', 'To Find:', and 'Solution:' for organized presentation
  • Double-check your arithmetic calculations before writing the final answer

Diagrams

Laws of Exponents Overview

Comprehensive mind map showing all six laws of exponents with their formulas and key concepts

Number Series Identification Process

Step-by-step flowchart for identifying and solving different types of number series questions

Exponent Simplification Steps

Sequential process showing the systematic approach to simplifying exponential expressions using all relevant laws

Algebra, Exponents & Number Series is chapter 5 of 9 in the Numerical Ability part of Super Tutor's Civil Service Exam (Professional) review. The Career Service Examination — Professional Level is given by Civil Service Commission (CSC); its dates, format and passing rules are on the Civil Service Exam (Professional) page. See the Civil Service Exam (Professional) guide.

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