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Flash CardsCivil Service Exam (Professional) · Numerical Ability

Civil Service Exam (Professional) Numerical Ability — Algebra, Exponents & Number SeriesFlash Cards

Civil Service Exam (Professional) Numerical Ability flashcards on Algebra, Exponents & Number Series. Note the cards you get wrong and come back to them.

Super Tutor's review for Civil Service Exam (Subprofessional) uses these same chapters, so they live here in the Civil Service Exam (Professional) section.

Algebra, Exponents & Number Series - Flashcards

Master the essential concepts of algebra, exponents, and number series with these comprehensive flashcards. These cards cover fundamental algebraic operations, laws of exponents, and pattern recognition in number sequences - key skills for success in Philippine civil service exams and college entrance tests like UPCAT, NMAT, and ACET.

Flashcards

What is the Product Rule for exponents and how do you apply it?

Laws of Exponentsintermediate

Answer

The Product Rule states that when multiplying two exponents with the same base, you keep the base and add the powers: a^m × a^n = a^(m+n). Example: 5^3 × 5^2 = 5^(3+2) = 5^5. This rule works for any real numbers m and n, including negative exponents.

Quotient Rule

Laws of Exponentsbasic

Answer

The Quotient Rule for exponents: When dividing two exponents with the same base, keep the base and subtract the powers: a^m ÷ a^n = a^(m-n). Example: 10^5 ÷ 10^3 = 10^(5-3) = 10^2 = 100. This helps avoid negative exponents by putting the answer in the appropriate position.

What happens when you raise a power to another power?

Laws of Exponentsintermediate

Answer

Use the Power Rule: (a^m)^n = a^(mn). Multiply the exponents together. Example: (2^3)^4 = 2^(3×4) = 2^12 = 4,096. Another example: Express 8^3 as a power with base 2: Since 8 = 2^3, then 8^3 = (2^3)^3 = 2^9.

Zero-Exponent Rule

Laws of Exponentsbasic

Answer

Any non-zero number raised to the power of zero equals 1: a^0 = 1 (where a ≠ 0). Examples: 5^0 = 1, (-3)^0 = 1, (999)^0 = 1. This rule is fundamental for simplifying expressions and solving equations.

How do you handle negative exponents?

Laws of Exponentsintermediate

Answer

Negative Exponent Rule: a^(-m) = 1/a^m. A negative exponent means take the reciprocal and make the exponent positive. Example: 2^(-2) = 1/2^2 = 1/4. For fractions: (3/4)^(-2) = (4/3)^2 = 16/9.

Fractional Exponent Rule

Laws of Exponentsadvanced

Answer

Fractional exponents represent roots: a^(1/n) = ⁿ√a. The denominator of the fraction becomes the index of the root. Example: 4^(1/2) = √4 = 2, 8^(1/3) = ∛8 = 2. For a^(m/n) = ⁿ√(a^m) or (ⁿ√a)^m.

What are the 6 steps for simplifying exponential expressions?

Simplifying Expressionsintermediate

Answer

  1. Apply Product Rule (add exponents with same base)
  2. Apply Quotient Rule (subtract exponents)
  3. Apply Power Rule (multiply exponents)
  4. Apply Zero-Exponent Rule (anything^0 = 1)
  5. Apply Negative Exponent Rule (move to opposite position)
  6. Simplify coefficients and reduce fractions

Arithmetic Sequence

Number Seriesbasic

Answer

A sequence where the difference between consecutive terms is constant. Formula for nth term: aₙ = a₁ + (n-1)d, where a₁ is the first term, d is the common difference, and n is the term number. Example: 2, 5, 8, 11, 14... has d = 3.

How do you identify and continue a geometric sequence?

Number Seriesintermediate

Answer

Geometric Sequence: Each term is obtained by multiplying the previous term by a constant ratio (r). Formula: aₙ = a₁ × r^(n-1). Example: 3, 6, 12, 24, 48... has r = 2. To find the next term, multiply the last term by the common ratio: 48 × 2 = 96.

What characterizes a Fibonacci sequence?

Number Seriesintermediate

Answer

Fibonacci Sequence: Each term is the sum of the two preceding terms. Pattern: aₙ = aₙ₋₁ + aₙ₋₂. Example: 1, 1, 2, 3, 5, 8, 13, 21... where 1+1=2, 1+2=3, 2+3=5, etc. This pattern appears frequently in nature and mathematics.

Solve: 8x⁵/4x² = ?

Algebraic Simplificationbasic

Answer

Apply the quotient rule and simplify coefficients:
8x⁵/4x² = (8/4) × (x⁵/x²) = 2 × x⁵⁻² = 2x³
Always separate coefficients from variables and apply exponent rules to each part.

What is an exponent sequence and how do you recognize it?

Number Seriesintermediate

Answer

Exponent Sequence: All terms are perfect powers (squares, cubes, etc.). Two types:

  1. Perfect squares: 4, 9, 16, 25, 36, 49... (2², 3², 4², 5², 6², 7²...)
  2. Perfect cubes: 8, 64, 216, 512, 1000... (2³, 4³, 6³, 8³, 10³...)

Look for patterns in the base numbers or exponents.

Compare arithmetic and geometric sequences

Number Seriesintermediate

Answer

Arithmetic Sequence:

  • Constant difference between terms
  • Linear growth pattern
  • Formula: aₙ = a₁ + (n-1)d
  • Example: 5, 8, 11, 14...

Geometric Sequence:

  • Constant ratio between terms
  • Exponential growth/decay
  • Formula: aₙ = a₁ × r^(n-1)
  • Example: 5, 10, 20, 40...

In the sequence 3, 8, 15, 24, 35, ?, what's the pattern and next term?

Number Seriesadvanced

Answer

This is an alternating sequence. Find the differences:
8-3=5, 15-8=7, 24-15=9, 35-24=11
The differences form: 5, 7, 9, 11... (increasing by 2 each time)
Next difference: 11+2=13
Next term: 35+13=48

What is a mixed sequence in number series?

Number Seriesadvanced

Answer

Mixed Sequence: Uses multiple arithmetic operations in a pattern. Example: 10, 22, 46, 94, 190, ?
Pattern: multiply by 2, then add 2
10×2+2=22, 22×2+2=46, 46×2+2=94, 94×2+2=190, 190×2+2=382
These sequences require identifying the combination of operations used.

Simplify: (3x²y⁻²)(4xy³)

Algebraic Operationsintermediate

Answer

Multiply coefficients and apply product rule for exponents:
(3x²y⁻²)(4xy³) = (3×4)(x²×x¹)(y⁻²×y³) = 12x²⁺¹y⁻²⁺³ = 12x³y¹ = 12x³y
Remember: when multiplying with same base, add the exponents.

What is a two-stage sequence?

Number Seriesadvanced

Answer

Two-Stage Sequence: The differences between consecutive terms form their own pattern (arithmetic or geometric). Example: 1, 3, 5, 9, 11 - missing terms can be found by analyzing that differences should be 2, 2, 4, 2, following a pattern. First find the pattern in differences, then fill in missing terms.

Evaluate: 2⁻³ × 2⁵ ÷ 2¹

Exponent Calculationsintermediate

Answer

Apply exponent rules step by step:
2⁻³ × 2⁵ ÷ 2¹ = 2⁻³⁺⁵⁻¹ = 2¹ = 2

Alternatively: 2⁻³ × 2⁵ = 2² = 4, then 4 ÷ 2¹ = 4 ÷ 2 = 2
Both methods give the same answer.

Combination Sequence

Number Seriesadvanced

Answer

Combination Sequence: Uses elements from different sequence types (like alternating between operations). Example: 3, 3, 3, 6, 3, 9, 3, 12...
Pattern: Odd positions stay constant (3), even positions increase by 3 (3, 6, 9, 12...)
This combines constant and arithmetic patterns.

What are the key strategies for solving number series problems?

Problem-Solving Strategiesintermediate

Answer

  1. Look for constant differences (arithmetic)
  2. Check for constant ratios (geometric)
  3. Examine if terms are perfect powers
  4. Try sum patterns (Fibonacci-type)
  5. Look for alternating patterns
  6. Check differences between differences
  7. Consider mixed operations
  8. Identify if it's a combination sequence

Always verify your pattern with given terms before finding the answer.

Diagrams

Algebra, Exponents & Number Series Overview

Comprehensive overview showing the three main areas of this chapter and their key components, illustrating how exponents, algebra, and number patterns connect in numerical ability problems.

Exponent Simplification Process

Step-by-step flowchart showing the systematic approach to simplifying exponential expressions, following the six-step process covered in the reference materials.

Number Series Pattern Recognition

Decision tree for identifying different types of number series patterns, helping students systematically approach sequence problems by checking each pattern type in logical order.

Algebra, Exponents & Number Series is chapter 5 of 9 in the Numerical Ability part of Super Tutor's Civil Service Exam (Professional) review. The Career Service Examination — Professional Level is given by Civil Service Commission (CSC); its dates, format and passing rules are on the Civil Service Exam (Professional) page. See the Civil Service Exam (Professional) guide.

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