CELE Strength of Materials — Stresses in BeamsSummary
For anyone preparing for the CELE 2026, Stresses in Beams is a must-know chapter in Strength of Materials. Professional Regulation Commission (PRC) — Board of Civil Engineering tests this area consistently — expect a meaningful fraction of the Strength of Materials subtest to come from Stresses in Beams. This page summarises the big ideas, the terms you should know cold, and the patterns CELE uses in its Stresses in Beams questions.
Exam context
Professional Regulation Commission (PRC) — Board of Civil Engineering runs the Civil Engineer Licensure Examination on May and November 2026. Its Strength of Materials section sits under a "Core" weighting, and Stresses in Beams is the 4th chapter in the 8-chapter CELE Strength of Materials rotation. The CELE passing mark is 70% weighted average, no sub-test below 50%, and the most recent 2026 paper drew about a meaningful share of questions from Strength of Materials.
Stresses in Beams - Summary
Understanding stresses in beams is fundamental to civil engineering design across reinforced concrete, structural steel, and timber construction. Once the bending moment (M) and shear force (V) are determined from shear force and bending moment diagrams (SFD/BMD), the engineer must calculate the internal stresses they produce. Bending moment creates flexural (bending) stress that varies linearly through the beam's depth, while shear force produces horizontal and vertical shear stresses distributed parabolically. These stresses directly govern cross-sectional adequacy—the critical gateway to proportioning beams in reinforced concrete (per ACI 318-19), structural steel (per AISC 360-16), and timber (per NSCP 2015 Wood Design). This chapter develops the flexure formula, section modulus, horizontal shear-stress formula, and combined stress effects, then demonstrates their application in practical beam design for strength.
Key Concepts
For a linearly elastic beam bent by moment M, plane sections remain plane, so strain—and stress—varies linearly through depth. At distance y from the neutral axis (NA), the bending stress is σ = My/I, where I is the second moment of inertia about the centroidal axis. The maximum bending stress occurs at the extreme fiber (y = c): σ_max = Mc/I = M/S. Sagging (positive) moment places the bottom fiber in tension and the top in compression. This is the foundational equation in strength of materials and beam design.
Concept
The Flexure (Bending) Formula
Importance
Essential for all beam design; directly used in ACI 318 (reinforced concrete), AISC 360 (steel), and NSCP 2015 (timber). Every PRC exam tests this formula.
The section modulus S = I/c combines moment of inertia and distance to extreme fiber into a single design parameter. It simplifies the flexure formula to σ_max = M/S. For a rectangular section (width b, depth h): S = bh²/6. For a solid circle (diameter d): S = πd³/32. In design, the required section modulus is simply S_req = M_max/σ_allow, after which standard shapes or custom sections are selected to match or exceed S_req. Section modulus grows with the square of depth for rectangles—why I-beams and deep sections are far more bending-efficient than flat plates.
Concept
Section Modulus and Design Shortcut
Importance
Provides the practical shortcut used by designers every day. Eliminates the need to calculate I separately if a handbook gives S. Frequently tested on licensure exams in rapid design scenarios.
The neutral axis (NA) is the surface in a beam where bending stress is zero. For symmetric sections under bending alone, it coincides with the centroidal axis. For unsymmetric sections (e.g., T-beams, L-channels), the NA must be located by calculating the centroid: ȳ = Σ(A_i × y_i) / Σ A_i. Once the NA is found, distances c_top and c_bottom to the extreme fibers may differ, leading to unequal maximum stresses in top and bottom fibers—a crucial point in reinforced concrete T-beam design where the larger tension controls reinforcement.
Concept
Neutral Axis and Centroid
Importance
Critical for unsymmetric sections common in real design (T-beams, channels, built-up sections). Misidentifying the NA leads to grossly incorrect stress calculations. Regular examination topic.
A transverse shear force V produces shear stress τ given by τ = VQ/(Ib), where Q is the first moment of area of the section above (or below) the level of interest, taken about the NA; I is the moment of inertia of the entire section; and b is the width at that level. Shear stress is zero at top and bottom fibers (where Q = 0) and maximum at the neutral axis. For a rectangular section: τ_max = 3V/(2A). For a solid circle: τ_max = 4V/(3A). For a wide-flange I-beam, approximately τ_max ≈ V/A_web because the web carries nearly all shear. The distribution is parabolic, not linear—opposite to bending stress.
Concept
Horizontal Shear Stress in Beams
Importance
Required for complete beam design; often the governing criterion in short, heavily loaded beams. Shear failure is brittle and dangerous. Must be checked in every real design per AISC 360 and ACI 318.
Q is the area above (or below) the level of interest multiplied by the distance from that area's centroid to the neutral axis: Q = A_above × d_centroid. For a rectangular section at distance y from the NA, Q = b × [(c² − y²)/2]. Q is maximum at the neutral axis and zero at the extreme fibers. Correct calculation of Q is essential; many students mistakenly use the entire section's Q or measure distances from the wrong reference, leading to wrong shear stresses.
Concept
First Moment of Area (Q)
Importance
A fundamental quantity in shear calculations. Exam questions often test Q calculation for non-standard sections. Miscomputing Q invalidates the entire shear-stress result.
When a beam is fabricated from separate pieces joined by fasteners (nails, bolts, welds) or adhesive, the connectors must resist the horizontal shear flow q = VQ/I at each joint. The shear flow has units of force per unit length (e.g., N/mm or kN/m). If each connector has capacity F (in newtons), the required spacing s (in mm) is s = F/q. This formula is used to specify nail/bolt spacing in built-up wood beams, weld size in plate girders, and glue-line strength in laminated members—all common practical problems.
Concept
Shear Flow and Built-Up Beam Design
Importance
Directly applicable to NSCP 2015 timber design and fabrication of steel plate girders per AISC 360. Frequently appears in practical design and PRC exam scenarios.
When a member carries both axial force P and bending moment M (as in a short column with eccentric load, M = P×e), the total stress at a fiber is the superposition of axial and bending components: σ = P/A ± Mc/I. The extreme fibers see σ_max,min = P/A ± Mc/I. If the load is applied within the kern (core) of the section, all fibers remain in compression (or tension, depending on load sign). The kern is defined by the region where no bending moment would cause stress reversal; for a rectangle, the kern extends h/6 each way from the centroid ('middle-third rule'). Load outside the kern produces tension—often undesirable in masonry, concrete footings, and retaining walls.
Concept
Combined Axial and Bending Stress (Eccentric Loading)
Importance
Essential for design of short columns, footings, and masonry elements per NSCP 2015. The middle-third rule is a classic PRC board-exam topic. Kern analysis is fundamental to stability and crack control.
A common source of confusion: bending stress σ = My/I is linear through depth (zero at NA, maximum at extreme fibers), while shear stress τ = VQ/(Ib) is parabolic (maximum at NA, zero at extreme fibers). For a rectangular section: bending stress varies as a triangle, shear stress as a parabola. At the extreme fibers, bending stress is maximum but shear is zero. At the neutral axis, bending stress is zero but shear is maximum. This inverse relationship is crucial: the bottom fiber of a simple beam carries the largest bending tension but no shear; the neutral axis carries the largest shear but no bending stress.
Concept
Stress Distribution: Linear (Bending) versus Parabolic (Shear)
Importance
Conceptual understanding separates competent engineers from those who memorize formulas. This distinction is tested in design problems where both flexure and shear must be checked, and different failure modes dominate in different regions.
A systematic approach ensures nothing is missed: (1) Construct SFD and BMD to find M_max and V_max at critical sections. (2) For flexure: calculate S_req = M_max / σ_allow, then select a section (from tables or custom) meeting or exceeding S_req. (3) For shear: verify that τ_max = VQ/(Ib) ≤ τ_allow (using 3V/2A for rectangular sections as a quick check). (4) If deflection limits apply, check maximum deflection per Chapter 5. (5) In short, heavily loaded beams, shear often governs; in long beams, flexure or deflection usually dominates. Always design for both; one may be hidden until checked.
Concept
Design Procedure for Beams
Importance
The practical engineering sequence taught in NSCP 2015, AISC 360, and ACI 318. Every design project follows this logic. PRC exams test both the formula application and the judgment of which criterion is critical.
Real beams often have unsymmetric cross-sections (T-beams in composite floors, channel sections, L-angles). The neutral axis is not at mid-depth. The procedure: (1) Find the centroid (and thus the NA location) by ȳ = Σ(A_i y_i) / Σ A_i. (2) Calculate moment of inertia about the NA using the parallel-axis theorem: I = Σ[I_local + A_i d_i²]. (3) Calculate c_top and c_bottom as distances from NA to extreme fibers—these are different. (4) Compute σ_top = Mc_top/I and σ_bottom = Mc_bottom/I separately; they are not equal. In reinforced concrete, the larger tension stress (usually at the bottom in a simply supported T-beam) governs the reinforcement design.
Concept
Unsymmetric Sections (T-Beams, Channels, etc.)
Importance
T-beams are ubiquitous in composite and reinforced concrete design per ACI 318. The tension fiber controls reinforcement; the compression fiber is usually not critical (concrete provides ample compression strength). A common exam trap: students forget that σ_top ≠ σ_bottom in unsymmetric sections.
Rather than derive τ = VQ/(Ib) for each section every time, useful closed-form maxima exist: For a rectangle (width b, depth h, area A = bh): τ_max = 3V/(2A) = 3V/(2bh). For a solid circle (diameter d, area A = πd²/4): τ_max = 4V/(3A) = 16V/(3πd²). For a wide-flange I-beam, the web carries nearly all shear, so τ_max ≈ V/A_web (an approximation useful for quick checks). These formulas are time-savers during design and board exams; students should memorize them.
Concept
Maximum Shear Stress in Common Sections
Importance
These simplified formulas appear repeatedly in design practice, handbooks, and PRC exams. Memorizing them saves time and reduces error risk compared to deriving Q for each case.
Important Points
- Bending stress σ = My/I is linear; shear stress τ = VQ/(Ib) is parabolic—opposite distributions.
- Maximum bending stress occurs at the extreme fibers (y = c); maximum shear stress occurs at the neutral axis.
- The flexure formula σ_max = Mc/I = M/S is the practical shortcut: section modulus S = I/c combines geometry into one number.
- For rectangular sections: S = bh²/6, not bh³/6—height is squared, not cubed. This difference grows cubic strength with depth.
- The neutral axis for any section passes through the centroid; for unsymmetric sections, use ȳ = Σ(A_i y_i) / Σ A_i to locate it.
- In unsymmetric sections (T-beams, channels), c_top ≠ c_bottom, so σ_top ≠ σ_bottom. The larger stress (usually tension in the bottom fiber of a simply supported T-beam) governs design.
- For shear, remember the factor: rectangular τ_max = 3V/(2A), circular τ_max = 4V/(3A). The factor accounts for the parabolic distribution.
- Shear flow q = VQ/I has units of force per unit length. In built-up beams, connector spacing s = F/q, where F is connector capacity.
- Combined axial + bending stress: σ = P/A ± Mc/I. Stay within the kern (middle third for rectangles) to avoid tension in members that should resist only compression.
- Short, heavily loaded beams are often shear-governed (τ is the limiting factor); long, lighter beams are usually flexure- or deflection-governed.
- Always calculate both M_max and V_max from the SFD/BMD, then design for both flexure and shear. Whichever is more restrictive controls.
- Sign convention: sagging (positive) moment puts bottom fiber in tension, top in compression.
- Unit consistency is critical: use N·mm with mm⁴ to get MPa; use N·m with m⁴ to get Pa.
- Common board-exam errors: wrong Q calculation, forgetting the 1.5 factor for rectangular shear, confusing I and S, mixing up which fiber is in tension/compression.
Chapter Objectives
- Derive and apply the flexure (bending) formula σ = My/I to locate neutral axis and calculate maximum flexural stresses
- Understand how bending stress varies linearly through depth (zero at neutral axis, maximum at extreme fibers)
- Apply section modulus S = I/c as a practical design tool for rapid section selection
- Calculate horizontal shear stress using τ = VQ/(Ib) and recognize its parabolic distribution (maximum at neutral axis, zero at top/bottom)
- Determine shear stress in common sections: rectangular (τ_max = 3V/2A), circular (τ_max = 4V/3A), and wide-flange (approximately V/A_web)
- Design shear-connected members (built-up beams) using shear flow q = VQ/I and connector spacing formulas
- Combine axial and bending stresses for eccentric loading and identify the kern (core) of a section
- Perform complete beam design for both flexure and shear, understanding which governs in short versus long beams
- Solve unsymmetric cross-section problems (e.g., T-beams) where neutral axis is not at mid-depth
Concept Relationships
Section modulus S is derived from moment of inertia: S = I/c. Both measure a section's bending efficiency. However, S is the practical design parameter because σ_max = M/S eliminates the need to separately know I and c. I is fundamental for shear-stress calculations τ = VQ/(Ib) and deflection (Chapter 5).
Relationship
Moment of Inertia ↔ Section Modulus
The neutral axis coincides with the centroidal axis. Locating the centroid (ȳ) determines the NA location. Once NA is known, distances c to extreme fibers are defined, which then determine both I (about the NA) and S = I/c. For unsymmetric sections, this chain of dependencies is critical: centroid → NA → c values → I → S and stress calculations all follow in sequence.
Relationship
Neutral Axis ↔ Centroid ↔ Section Properties
Shear force V from the SFD drives shear stress via τ = VQ/(Ib). Q depends on the geometry above/below the level of interest. The higher the Q (further the sheared area from NA), the higher the τ at that point. This explains why τ_max occurs at the NA (where Q is maximum): τ_max = V × Q_max / (I × b).
Relationship
Shear Force (V) → First Moment (Q) → Shear Stress (τ)
The shear stress distribution τ(y) = VQ(y)/(Ib) defines the internal shear stress at each level y. At a joint (interface between pieces in a built-up beam), the total shear force per unit length is the shear flow q = VQ/I. The connector at that joint must resist q; spacing s = F/q ensures adequacy. Understanding τ distribution is the key to sizing connectors.
Relationship
Shear Stress Distribution ↔ Shear Flow in Built-Up Beams
Superposition allows σ_total = σ_axial + σ_bending = P/A ± Mc/I. This extends the flexure formula to members experiencing both forces simultaneously (e.g., short columns, eccentrically loaded footings). The kern is the region where load can act without changing sign of stress; it emerges naturally from the combined formula.
Relationship
Bending Stress + Axial Stress = Combined (Eccentric Load) Stress
In a given beam, either flexural stress or shear stress may be the limiting factor. Short beams with heavy loads often fail in shear first; long, slender beams fail in bending first. The design process checks both and accepts the more restrictive limit. Understanding when each governs helps engineers make rapid judgments about proportions (e.g., deeper sections for bending, wider webs for shear).
Relationship
Flexure-Governed versus Shear-Governed Design
A complete causal chain: choice of width, depth, shape, etc., → I, c calculations → S = I/c → stress calculations σ = M/S, τ = VQ/(Ib) → comparison with allowables → accept or redesign. Every design iteration cycles through this chain. Understanding the relationships allows engineers to judge whether increasing width or depth is more effective for the problem at hand.
Relationship
Cross-Section Geometry → Moment of Inertia → Section Modulus → Stress → Design
Practical Applications
Reinforced concrete beams use the flexure formula to determine the tension and compression stresses in concrete and steel. The neutral axis location (determined by the area of reinforcement) affects the moment arm and thus the moment capacity. Once bending stress is found, reinforcement is proportioned to carry tension in the bottom fiber of a simply supported beam. Shear stress τ = VQ/(Ib) at the critical section determines whether shear reinforcement (stirrups) is required per ACI 318 Section 11.1. Many problems involve unsymmetric sections (T-beams, flanged sections) where c_top and c_bottom differ significantly.
Application
Reinforced Concrete Beam Design (ACI 318-19)
Steel beams are designed using the flexure formula to ensure that σ_max = M/S does not exceed the flexural strength F_b (often based on lateral-torsional buckling, per AISC 360 Chapter F). Section modulus S is a key parameter in steel design; tables of standard shapes (W, S, C, L sections) list S for rapid selection. Shear capacity is checked using τ = V/A_web (for I-sections, the web carries most shear). Built-up plate-girder beams must have connection details (welds or bolts) sized using shear flow q = VQ/I to ensure the flange-to-web connection can carry the horizontal shear.
Application
Structural Steel Beam Design (AISC 360-16)
Timber beams are proportioned using the flexure formula σ_max = M/S ≤ F_b (allowable bending stress, adjusted for load duration, moisture, etc.). For rectangular timber (the most common form), S = bh²/6 is applied directly. Shear is checked using τ_max = 3V/(2A) ≤ F_v (allowable shear). In built-up timber beams (e.g., laminated beams or beams made from multiple planks), nailing patterns are designed using shear flow q = VQ/I; nail spacing is set so that s = F_nail / q ensures nails carry the required shear.
Application
Timber Beam Design (NSCP 2015 Wood Design)
Composite beams (steel section acting together with a concrete slab) have a transformed neutral axis determined by the steel area and concrete area weighted by the modular ratio n = E_steel / E_concrete ≈ 8–10. The neutral axis location differs from either material alone, requiring careful calculation of I about the transformed axis. The flexure formula then yields bending stresses in both steel and concrete. Shear transfer between steel and concrete (shear studs) is designed using shear flow: connector spacing is set by s = F_connector / q, where q = VQ/I_transformed.
Application
Composite Beam Design
Short, thick members (footings, retaining wall stems) often carry eccentric loads. The combined stress formula σ = P/A ± Mc/I applies. For a footing, the pressure (stress) should not exceed soil bearing capacity and, in concrete, should not cause excessive tension (which concrete is weak in). The kern criterion ensures that eccentric loads remain within the middle third (kern) to avoid tension. For a rectangular footing of width B, the kern extends B/6 each side; if the load is further than B/6 from centerline, tension appears and uplift may occur.
Application
Footing and Retaining Wall Design
Engineers rapidly select beams by calculating S_req = M_max / σ_allow, then consulting standard shape tables (e.g., AISC shapes, timber sections) to find the lightest section with S ≥ S_req. This shortcut avoids calculating I and c separately. Once a candidate section is chosen, shear is verified using τ_max = V/A_web (steel) or τ_max = 3V/(2A) (timber). If either criterion is not met, the next larger section is selected and checked again.
Application
Beam Section Selection from Tables
When a beam is fabricated by riveting, bolting, or welding separate plates, or by laminating timber planks, the connectors must resist the horizontal shear flow q = VQ/I at each joint. For a steel plate girder, the welds joining flange to web are sized to carry q (typically a fillet weld size is specified per AISC 360 J2.4). For timber laminations, adhesive thickness or nail spacing is set by s = F / q. The critical regions are near the supports where V is large and Q (of the connected part) is significant.
Application
Built-Up Girder Fabrication (Steel Plate Girders, Laminated Beams)
Shear failure is sudden and brittle; unlike bending, which may give warning through deflection or cracking, shear can cause catastrophic collapse. Equations τ_max = 3V/(2A) for rectangles and τ_max = 4V/(3A) for circles allow rapid checks. In reinforced concrete, stirrups (vertical shear reinforcement) are required when τ exceeds τ_c (concrete contribution); the stirrup spacing is set by ACI 318 equations based on τ and the stirrup strength. Engineers must never neglect shear design, especially in short, heavily loaded beams and corbels.
Application
Design Against Shear Failure
Many real beams have unsymmetric sections (T-beams in composite construction, channels, L-sections). The procedure is systematic: (1) locate the centroid and thus the NA, (2) calculate I about the NA, (3) measure c_top and c_bottom, (4) find σ_top and σ_bottom separately. In a reinforced concrete T-beam in positive bending, c_bottom > c_top, so σ_bottom > σ_top; the tension in the bottom governs reinforcement. This is why many T-beams have bottom reinforcement only (the top is in compression and concrete handles it). Engineers must not assume σ_top = σ_bottom in unsymmetric sections; doing so leads to underdesign.
Application
Checking Unsymmetric Sections
In summary
Stresses in beams form the theoretical foundation for all structural design in reinforced concrete, structural steel, and timber. The flexure formula σ = My/I and the shear-stress formula τ = VQ/(Ib) are not abstract equations—they are the direct consequences of equilibrium, material linearity, and the assumption that plane sections remain plane during bending. Mastering these formulas, understanding when each is critical (bending in long beams, shear in short beams), and learning to apply them to both symmetric and unsymmetric sections are essential skills for the PRC Civil Engineer Licensure Examination and professional practice. The design procedure—find M and V from the SFD/BMD, check both flexure and shear, iterate to a section that satisfies all criteria—is the gateway to the detailed design methods in ACI 318 (reinforced concrete), AISC 360 (structural steel), and NSCP 2015 (timber and general design). Equally important is the conceptual insight: bending stress is maximum where shear is minimum (at the extreme fibers), and vice versa (maximum shear at the neutral axis). This inverse relationship explains why I-sections are efficient (deep sections maximize bending capacity), why webs can be relatively thin (little bending occurs there but shear must be checked), and why understanding section geometry drives good engineering design. Every beam you encounter in practice—from a simple wooden floor joist to a massive plate-girder bridge—is designed using these principles. Invest time in understanding the formulas, working through examples with various section shapes, and recognizing which criterion is critical in a given scenario. Success on the board exam and in your engineering career depends on this mastery.
Next steps
Proceed to Chapter 5 (Deflection of Beams), where the slope and deflection of bent beams are calculated using the same moment diagrams and moment of inertia from this chapter. Understanding how curvature (proportional to M/EI) integrates to give deflection is the next layer of beam analysis. Additionally, review worked examples in NSCP 2015 Section 2.2 (Structural Analysis and Design) and ACI 318 Chapter 6 (Flexural Design) to see how the flexure formula is applied in real design. Practice unsymmetric section problems (T-beams, channels) to build confidence in centroid and moment-of-inertia calculations. Finally, work through complete beam-design problems where you must size a section for a given load, check both flexure and shear, and verify deflection—this is the type of multi-step problem you will encounter on the PRC exam and in professional practice.
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