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CELE Strength of MaterialsShear and Moment DiagramsSummary

If you are short on review time for the CELE 2026, Shear and Moment Diagrams is the kind of Strength of Materials chapter you cannot skip. PRC asks about Shear and Moment Diagrams every cycle, usually in several forms — definition recall, quick application, and one scenario-based item. This summary handles all three in under 400 words so you walk into the full notes with context already locked in.

Exam context

Professional Regulation Commission (PRC) — Board of Civil Engineering runs the Civil Engineer Licensure Examination on May and November 2026. Its Strength of Materials section sits under a "Core" weighting, and Shear and Moment Diagrams is the 3rd chapter in the 8-chapter CELE Strength of Materials rotation. The CELE passing mark is 70% weighted average, no sub-test below 50%, and the most recent 2026 paper drew about a meaningful share of questions from Strength of Materials.

Shear and Moment Diagrams - Summary

Shear and moment diagrams (SFD and BMD) are the foundational tools for analyzing beam behaviour under loading. They graphically represent how internal shear force and bending moment vary along the length of a structural member. Mastering these diagrams is essential for PRC licensure—nearly every reinforced concrete design problem (ACI 318), steel member selection (AISC 360), and deflection calculation begins with correctly identifying the maximum shear and moment from these diagrams. The ability to sketch them quickly and read critical values is the difference between passing and failing the structural analysis portions of the examination.

Key Concepts

When a beam is cut at any section and one side is isolated, the cut face must supply two internal effects to maintain equilibrium: (1) Shear force V – the transverse (vertical) internal force balancing transverse loads on that side, and (2) Bending moment M – the internal moment balancing the moment of those loads about the section. These are found by applying equilibrium equations to the free body of one isolated side: V = ΣF_transverse and M = ΣM_about_section.

Concept

Shear Force (V) and Bending Moment (M)

Importance

Critical foundation; all beam design and deflection analysis depend on accurately determining V and M at every section along the member. Errors here cascade through the entire design process.

Shear is positive when the resultant force to the left of a section acts upward (equivalently, the internal shear pair acts clockwise on an element). Bending moment is positive when it causes the beam to be concave up (sagging)—compression on top, tension at the bottom—like a smile. Negative moment is concave down (hogging)—tension on top, compression at bottom—like a frown. Memory aid: positive moment = 'smile', negative = 'frown'.

Concept

Sign Convention (Positive = Sagging, Negative = Hogging)

Importance

The most commonly misapplied concept in PRC exams. Reversing the sign leads to inverted diagrams and wrong design, especially over interior supports of continuous beams. Must be automatic.

Before drawing any diagram, solve for all support reactions using the three equilibrium equations: ΣF_x = 0, ΣF_y = 0, ΣM = 0. Reactions depend on support type: roller (1 vertical reaction), pin (vertical + horizontal), fixed (vertical + horizontal + moment). Statically determinate beams (simply supported, cantilever, overhanging) have exactly 3 unknowns; indeterminate beams require additional methods (slope-deflection, flexibility, etc., covered in Structural Theory).

Concept

Support Reactions and Equilibrium

Importance

No correct SFD or BMD is possible without correct reactions. This is the first step and must never be skipped, regardless of time pressure in exams.

From equilibrium of a differential beam element: dV/dx = −w(x) and dM/dx = V(x), where w(x) is the load intensity. In practical (integral) form: ΔV = −(area under load diagram), and ΔM = area under shear diagram. These allow sketching without equations: (1) slope of shear diagram = −load intensity, (2) slope of moment diagram = shear, (3) where V = 0, moment reaches a local extreme (critical for locating M_max).

Concept

Load–Shear–Moment Relationships (Differential and Integral Forms)

Importance

These are the 'fast lane' to SFD and BMD on exams. Understanding the area method and slope rules reduces diagram construction time by 50–70% compared to writing segment equations. Essential for time-constrained exams.

Integration raises the degree of a curve by one: a point load creates constant shear (degree 0 polynomial) and linear moment (degree 1). A uniformly distributed load creates linear shear (degree 1) and parabolic moment (degree 2). A uniformly varying (triangular) load creates parabolic shear (degree 2) and cubic moment (degree 3). Moment is always at least one degree higher than shear (since M is the integral of V).

Concept

Degree Rule and Curve Continuity

Importance

Allows rapid sketch validation. If your moment curve is parabolic but the shear is not linear, something is wrong. This self-check catches errors before calculations.

A downward concentrated force causes a sudden vertical drop (downward jump) in the shear diagram equal to the load magnitude. A concentrated couple (applied moment) causes a sudden vertical jump in the moment diagram equal to the couple magnitude but does not affect shear (no transverse force). These jumps are the signature of concentrated effects; distributed effects produce smooth curves.

Concept

Discontinuities: Point Loads and Applied Couples

Importance

Failing to draw these jumps correctly is a common error. Point loads jump shear; couples jump moment. Forgetting these leads to wrong M_max locations.

Since dM/dx = V, the moment is stationary (slope = 0) wherever V = 0. This is where internal moment reaches a local maximum or minimum. For simply supported beams with symmetric loading, M_max is at midspan. For unsymmetric loading or cantilevers, you must solve for the point where V crosses zero. This is the pivotal step in many board problems.

Concept

Location of Maximum Moment: Where V = 0 or Changes Sign

Importance

Identifying M_max location is half the work in any beam design problem. Many students calculate V but then forget to find where it becomes zero. This step is non-negotiable for correct design.

Simply supported, cantilever, and overhanging beams have 3 unknowns and 3 equilibrium equations → statically determinate (solvable immediately). Fixed, continuous, and propped cantilever beams have more than 3 unknowns → statically indeterminate (require compatibility equations, covered in Structural Theory). The PRC exam assumes familiarity with determinate cases at this level; indeterminate beams appear in Structural Theory & Analysis topics.

Concept

Beam Classifications and Reaction Redundancy

Importance

Distinguishing determinate from indeterminate is essential. You cannot solve an indeterminate beam with equilibrium alone. Misidentifying this wastes exam time and produces nonsense answers.

Systematic procedure: (1) find all reactions, (2) divide the beam at every point where loading changes (supports, point loads, start/end of distributed loads, applied couples), (3) for each segment, cut at distance x and isolate one free body, (4) apply ΣF_y = 0 for V(x) and ΣM = 0 for M(x), (5) plot V(x) and M(x) over each segment. This always works but is slower than the area method for simple beams.

Concept

Method of Sections: Systematic Segment Analysis

Importance

The most reliable method when you are unsure. It is slower but guarantees correctness if equations are set up properly. Useful as a verification tool.

Important Points

  • Reactions must be found before drawing any diagram. Use ΣF_x = 0, ΣF_y = 0, ΣM = 0 on the entire beam.
  • Positive shear = upward force on the left face of a cut section (clockwise internal pair on the element). Positive moment = sagging (concave up, tension at bottom).
  • Maximum moment occurs at sections where shear equals zero or changes sign. This is the key to locating M_max without writing equations.
  • The slope of the shear diagram equals the negative of the load intensity at that point: dV/dx = −w(x).
  • The slope of the moment diagram equals the shear at that point: dM/dx = V. Where V = 0, moment has a horizontal tangent (local extremum).
  • The change in shear between two points equals the negative of the area under the load diagram: ΔV = −(area under w).
  • The change in moment between two points equals the area under the shear diagram: ΔM = area under V.
  • A point load causes a sudden drop in shear equal to the load; a concentrated couple causes a sudden jump in moment but does not affect shear.
  • Degree of moment curve = degree of shear curve + 1. Point load → V constant, M linear. UDL → V linear, M parabolic. UVL → V parabolic, M cubic.
  • For cantilevers, the maximum moment (and shear) occur at the fixed support. For simply supported beams with symmetric loading, extrema occur at midspan.
  • Overhanging beams can have larger hogging moment at the interior support than sagging moment in the span. Always check both.
  • Uniformly varying (triangular) load: resultant = (1/2) × base × height, acting at the centroid (L/3 from the larger-intensity end, 2L/3 from the zero end).
  • For statically determinate beams, equilibrium equations alone suffice. For indeterminate beams, additional compatibility conditions (slope-deflection, virtual work) are required.

Chapter Objectives

  • Understand the physical meaning of internal shear force and bending moment in beams
  • Apply the standard sign convention for shear and moment (sagging positive, hogging negative)
  • Construct shear and moment diagrams using the method of sections
  • Apply the load–shear–moment relationships (differential and integral forms) to sketch diagrams without writing equations
  • Locate the maximum moment by identifying where shear equals zero or changes sign
  • Analyze common beam configurations: simply supported, cantilever, overhanging, and fixed beams
  • Recognize and handle discontinuities (point loads, applied couples, distributed loads)
  • Apply results to practical design scenarios (reinforced concrete per ACI 318, structural steel per AISC 360)

Concept Relationships

The type of support (roller, pin, fixed) determines how many and what kinds of reactions develop. A roller provides only a vertical reaction perpendicular to the rolling surface; a pin provides vertical and horizontal; a fixed support provides vertical, horizontal, and moment. These reactions are the boundary conditions that determine the magnitude and shape of the SFD and BMD.

Relationship

Support Types → Reaction Types → Magnitude and Direction of Reactions

Exam Relevance

Understanding this hierarchy allows quick verification of reaction feasibility. If your pin reaction has a moment component, something is wrong.

Load is the rate of change of shear (dV/dx = −w). Integrating load over a region gives the total change in shear. This relationship allows area-based calculations and is the core of the fast-sketch method.

Relationship

Load Intensity w(x) → Slope of Shear Diagram → Change in Shear Between Points

Exam Relevance

This relationship is the practical shortcut on board exams. Instead of writing V(x) equations segment by segment, you can read areas under the load diagram.

Shear is the rate of change of moment (dM/dx = V). Integrating shear over a region gives the total change in moment. Critically, where shear equals zero, moment is at a local extremum. This is the primary tool for locating maximum moment without calculus.

Relationship

Shear Force V(x) → Slope of Moment Diagram → Location of M_max

Exam Relevance

Finding M_max is 90% of the solution in most beam design problems. Recognizing that M peaks where V = 0 is the conceptual shortcut that separates quick solvers from slow ones.

The three diagrams are connected by successive integration: load is integrated to get shear, shear is integrated to get moment. Each diagram encodes information about the lower-level one: the shape (concavity) of the shear diagram reflects the load, and the shape of the moment diagram reflects the shear.

Relationship

Load Diagram → Shear Diagram → Moment Diagram (Hierarchical Integration)

Exam Relevance

This hierarchy allows verification. If the moment curve is not smooth where shear is smooth, an error exists. Checking curve continuity and shape against the load is a fast validation.

Simply supported (2 reactions) beams typically have positive (sagging) moment in the span and zero moment at supports. Cantilevers (1 reaction + 1 moment at fixed end) have negative (hogging) moment throughout. Overhanging beams have both sagging and hogging regions; the largest moment is often at an interior support (hogging), not in the span.

Relationship

Simply Supported vs. Cantilever vs. Overhanging: Reaction Count and Moment Sign Pattern

Exam Relevance

Recognizing the typical moment sign pattern for each beam type allows rapid sense-checking. If a simply supported beam shows hogging throughout, you have made an error.

Determinate beams (simply supported, cantilever, overhanging) have exactly 3 unknowns and are solvable by equilibrium alone. Indeterminate beams (fixed, continuous, propped cantilever) have more than 3 unknowns and require additional compatibility equations (part of Structural Theory & Analysis, not core Strength of Materials).

Relationship

Statically Determinate vs. Indeterminate Beams: Number of Unknowns vs. Equilibrium Equations

Exam Relevance

Identifying beam type quickly determines your solution strategy. Attempting equilibrium-only methods on an indeterminate beam will fail. This classification is a gatekeeper decision on exams.

Practical Applications

ACI 318 requires engineers to design flexural reinforcement based on the maximum bending moment M_u (factored). The SFD and BMD are drawn first (often at service loads or factored loads depending on the design stage); the maximum moment value and its location are then used to determine the required area of tension steel A_s = M_u / (φ f_y d). Shear diagram is used to place shear reinforcement (stirrups). Forgetting to locate the actual peak moment (not just scanning the diagram) results in undersized beams or unnecessary steel.

Application

Reinforced Concrete Beam Design (ACI 318)

Prc Exam Relevance

Multiple-choice and problem-solving questions on RC design always require SFD/BMD. The examiners test whether you can both draw the diagram and extract the maximum correctly.

AISC 360 requires selection of the lightest steel section (I-beam, wide-flange, channel) that resists the maximum moment without exceeding allowable stress: σ = M / S ≤ σ_allow, where S is the elastic section modulus. The SFD and BMD are used to find M_max; the location of maximum shear determines where lateral bracing must be provided. Incorrect moment values lead to either over-designed (uneconomical) or under-designed (unsafe) members.

Application

Structural Steel Member Selection (AISC 360)

Prc Exam Relevance

Steel design problems on the PRC exam routinely present a loading diagram and ask for member selection. Candidates must extract maximum moment and shear correctly to choose the appropriate section.

Methods such as integration of the moment curvature (double integration method), conjugate beam method, and virtual work all depend on knowing M(x) along the entire span. The SFD and BMD are the starting point; from M(x) you compute curvature, which is integrated to find slope and deflection. Without correct SFD and BMD, deflection calculations are meaningless.

Application

Beam Deflection Calculations

Prc Exam Relevance

Deflection problems require both correct moment diagrams and subsequent integration. Errors in the diagram propagate directly to wrong deflection values. This is a two-stage problem type common in PRC exams.

When analysing the internal moment in footing beams or retaining wall cantilevers, the same SFD and BMD methods apply. A cantilever footing under soil pressure (distributed load) has maximum hogging moment at the face of the column. Retaining walls under lateral earth pressure (triangular load distribution) require finding the maximum moment, which is not at the base but at the point where shear (lateral force resultant) equals zero.

Application

Foundation and Retaining Wall Design

Prc Exam Relevance

Foundation problems in PRC exams often disguise beam analysis inside a geotechnical context. Recognizing that a footing or wall is a cantilever or beam and drawing the SFD/BMD accordingly is the key to solving these questions.

The Philippine National Structural Code (NSCP 2015) requires SFD and BMD as part of structural design drawings. The code mandates specific design loads, load combinations, and safety factors (e.g., load factors of 1.2 for dead load, 1.6 for live load in ultimate limit state). The diagrams must be drawn at the factored load level for ultimate design and at service load level for serviceability checks (deflection, cracking). Correct interpretation of NSCP load combinations directly affects the shape and magnitude of the diagrams.

Application

Building Code Compliance (NSCP 2015)

Prc Exam Relevance

PRC problems often include NSCP load factors. Candidates must correctly apply these to compute factored loads before drawing SFD and BMD, then use the maximum moment at the factored level for design.

For bridges and long-span structures, concentrated loads (vehicles, point masses) and distributed loads (self-weight, pavement, distributed live load) both contribute to the SFD and BMD. The diagrams may be highly irregular, with multiple peaks and valleys. Overhanging sections (cantilever arms beyond supports) create hogging moments that can exceed mid-span sagging moments. The fast area-based method becomes essential for hand calculations when diagrams are complex.

Application

Bridge and Long-Span Beam Analysis

Prc Exam Relevance

Bridge problems are common in structural engineering portions of the PRC exam. Candidates must identify all load types, find reactions, and then sketch or describe the SFD and BMD correctly, often under time pressure.

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In summary

Shear and moment diagrams are not just academic exercises—they are the essential language of structural analysis. Every RC beam design (ACI 318), every steel member selection (AISC 360), every deflection calculation, and every bridge analysis in professional practice begins with correctly drawn SFD and BMD. For PRC licensure, mastery of this topic is non-negotiable. The ability to rapidly construct these diagrams by hand, read the maximum moment and its location, and apply those values to design is what separates candidates who pass from those who do not. The key skills are (1) always finding reactions first, (2) remembering the sign convention (sagging = positive, hogging = negative), (3) using the relationship dM/dx = V to locate M_max where V = 0, and (4) recognizing that overhanging beams and cantilevers often hide their maximum moment at interior supports or fixed ends, not in the span. Practice sketching diagrams under time constraints, check for physical reasonableness (curve degrees, discontinuities, support boundary conditions), and you will solve the majority of board exam structural problems efficiently and correctly.

Next steps

After mastering this chapter, proceed to (1) **Beam Deflection**: apply the moment diagrams you have drawn to calculate slopes and displacements using integration or the conjugate beam method. (2) **Columns and Combined Loading**: extend your understanding of internal forces to axial stress plus bending stress. (3) **Statically Indeterminate Beams** (Structural Theory & Analysis): apply the slope-deflection method or flexibility method to continuous beams and fixed beams, which have more unknowns than equilibrium equations alone can solve. (4) **Reinforced Concrete Design (ACI 318)**: use your maximum moment values to size flexural reinforcement, and your shear diagram to design shear reinforcement (stirrups) and anchorage. (5) **Structural Steel Design (AISC 360)**: select plate girders, I-beams, and wide-flanges based on moment capacity and lateral bracing requirements from your diagrams. All of these advanced topics assume that drawing and reading SFD and BMD is automatic. Return to this chapter whenever you find yourself unsure about moment or shear values in later problems—the root cause is often a misunderstood concept here. For PRC exam review, dedicate time to solving 10–15 diverse beam problems (various support types, mixed loading) until you can sketch correct diagrams in under 5 minutes per problem. This speed and accuracy are what the examiners reward.

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