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CELE Reinforced & Prestressed ConcreteReinforced Concrete SlabsRevision Notes

Quick revision notes for Reinforced Concrete Slabs — the one-page refresher for CELE aspirants. Every item on this page has appeared in recent CELE Reinforced & Prestressed Concrete papers, so revising these is the shortest path to a confident performance in Professional Regulation Commission (PRC) — Board of Civil Engineering's CELE 2026.

Exam context

The Civil Engineer Licensure Examination is conducted by Professional Regulation Commission (PRC) — Board of Civil Engineering and is scheduled for May and November 2026. The Reinforced & Prestressed Concrete subtest is marked as "Core" in the official pattern, and Reinforced Concrete Slabs appears in position 5th of 7 in the CELE Reinforced & Prestressed Concrete review rotation. Passing mark: 70% weighted average, no sub-test below 50%. Recent CELE 2026 papers have drawn roughly a meaningful share of questions from this subject.

Reinforced Concrete Slabs - Revision Notes

Reinforced concrete slabs are horizontal plate elements that transfer floor and roof loads to the supporting beams, walls, or columns. In the PRC Civil Engineer Licensure Examination, slab problems typically test: (1) classification as one-way or two-way, (2) minimum thickness for deflection control per NSCP 2015 (aligned with ACI 318), (3) flexural steel design per 1-metre strip, (4) shrinkage and temperature steel, and (5) two-way slab moment analysis via the coefficient method or Direct Design Method (DDM). Mastery of these five areas — with careful attention to the common board-exam pitfalls — is essential for exam success.

Sections

Formulas

Example

Panel: 3 m × 7 m → ratio = 7/3 = 2.33 ≥ 2 → ONE-WAY. Panel: 5 m × 6 m → ratio = 6/5 = 1.2 < 2 → TWO-WAY.

Formula

Aspect Ratio = L_long / L_short

Variables

L_long = longer panel dimension (m or mm); L_short = shorter panel dimension (m or mm)

Application

Classification of slab type. If ratio ≥ 2 → one-way; if ratio < 2 → two-way.

Exam Tips

  • Always write the ratio as LONG ÷ SHORT. If your answer is less than 1, you inverted it — flip it.
  • Board exams often present a borderline panel (ratio = 1.95 or 2.05) — be precise in your classification.
  • When a problem says 'supported on two sides only,' classify as one-way immediately without computing the ratio.
  • Memorise the boundary: ratio ≥ 2 → one-way; ratio < 2 → two-way (not ≤ 2, not > 2).

Key Points

  • A rectangular slab supported on all four sides is classified by its aspect ratio: ratio = L_long / L_short.
  • If L_long / L_short ≥ 2, the slab acts as a ONE-WAY slab — it bends primarily across the short span.
  • If L_long / L_short < 2, the slab acts as a TWO-WAY slab — it bends significantly in both directions.
  • A slab supported on only two opposite sides is ALWAYS one-way, regardless of the aspect ratio.
  • One-way slabs are designed as a series of independent 1-metre wide beam strips spanning in the short direction.
  • Two-way slabs require consideration of moments in both the long and short directions simultaneously.
  • The critical distinction affects the entire design approach, load path, and reinforcement layout.
  • Philippine practice follows NSCP 2015 Section 406 for one-way slabs and Section 408 for two-way slabs.

Definitions

Term

One-Way Slab

Definition

A slab in which the structural action is essentially in one direction only — the short span. Loads are carried as a series of parallel beams to the two supporting edges.

Importance

Simpler to design; governed by flexure in one direction plus shrinkage/temperature steel in the perpendicular direction.

Term

Two-Way Slab

Definition

A slab in which significant bending occurs in both the short and long span directions. Requires reinforcement in both directions to resist induced moments.

Importance

More complex analysis; used when the panel is nearly square (ratio < 2). Common in flat plate and flat slab systems.

Term

Aspect Ratio

Definition

The ratio of the longer span to the shorter span of a rectangular slab panel. It is the key parameter for classification.

Importance

The single most important classification criterion; using it backwards is the most common board-exam error.

Section Title

One-Way vs. Two-Way Slab Classification

Common Mistakes

  • Inverting the ratio — computing L_short / L_long instead of L_long / L_short. The ratio must always be ≥ 1.
  • Forgetting that a slab on only two opposite sides is always one-way, even if the panel is nearly square.
  • Applying one-way formulas to a two-way panel and vice versa — this fundamentally changes the design.
  • Using centre-to-centre beam spacings instead of clear spans for span ratios.

Formulas

Example

L = 4000 mm, fy = 420 MPa: h_min = 4000/20 = 200 mm.

Formula

h_min (simply supported) = L / 20

Variables

L = clear span (mm); h_min = minimum slab thickness (mm). For fy ≠ 420 MPa, multiply by (0.4 + fy/700).

Application

One-way solid slab, both ends simply supported, to waive deflection check.

Example

L = 4800 mm, fy = 420: h_min = 4800/24 = 200 mm.

Formula

h_min (one end continuous) = L / 24

Variables

L = clear span (mm). Modify by (0.4 + fy/700) if fy ≠ 420 MPa.

Application

One-way slab with one end pinned and one end continuous (e.g., end span of a continuous slab).

Example

L = 5600 mm, fy = 415 MPa: h_min = (5600/28)(0.4 + 415/700) = 200 × 0.993 = 198.5 → use 200 mm.

Formula

h_min (both ends continuous) = L / 28

Variables

L = clear span (mm). Modify by (0.4 + fy/700) if fy ≠ 420 MPa.

Application

One-way slab with both ends continuous over supports — interior spans of a continuous slab.

Example

L = 1500 mm, fy = 275 MPa: h_min = (1500/10)(0.4 + 275/700) = 150 × 0.793 = 118.9 → use 120 mm.

Formula

h_min (cantilever) = L / 10

Variables

L = clear span of cantilever (mm). Modify by (0.4 + fy/700) if fy ≠ 420 MPa.

Application

Cantilevered one-way slab measured from face of support to free end.

Example

Simply supported, L = 3500 mm, fy = 415 MPa: h_min = (3500/20)(0.4 + 415/700) = 175 × 0.993 = 173.8 → use 175 mm.

Formula

h_min (adjusted) = (L / divisor) × (0.4 + fy / 700)

Variables

Divisor = 20, 24, 28, or 10 depending on support condition; fy in MPa; L in mm.

Application

General formula for any fy. When fy = 420 MPa, the factor = 0.4 + 420/700 = 1.0 exactly (confirming tabulated values).

Exam Tips

  • Memorise the four divisors as a sequence: 20, 24, 28, 10 (SS → 1-end cont. → 2-end cont. → cantilever).
  • Quick check: if fy = 420 MPa, the factor = exactly 1.0 — no adjustment needed. For fy = 415 MPa, factor ≈ 0.993 (very close to 1.0).
  • For fy = 275 MPa, factor = 0.4 + 275/700 = 0.793 — significantly smaller, giving a thinner minimum slab.
  • If the problem asks 'minimum thickness to satisfy deflection without calculation,' that is the h_min formula.
  • Round the final answer UP — never round down a minimum requirement.

Key Points

  • NSCP 2015 Section 406.3.1 (ACI 318-19 Table 7.3.1.1) provides minimum thicknesses for one-way solid slabs to waive explicit deflection calculations.
  • The tabulated values apply for normal-weight concrete (wc ≈ 2400 kg/m³) and fy = 420 MPa.
  • For other values of fy, multiply the tabulated h_min by the factor (0.4 + fy/700).
  • Four support conditions are covered: simply supported, one end continuous, both ends continuous, and cantilever.
  • The span L used in the formula is the CLEAR SPAN in the direction of bending.
  • If the actual thickness provided is less than h_min, explicit deflection calculation per NSCP Section 406.6 is required.
  • For two-way slabs, separate thickness criteria (including αf and βs) apply per NSCP 2015 Section 408.3.
  • Always round UP to the nearest 5 mm or 10 mm increment in practice.

Definitions

Term

Minimum Thickness (h_min)

Definition

The smallest allowable slab thickness at which explicit deflection calculations are not required under NSCP 2015, assuming normal-weight concrete and the specified fy.

Importance

A threshold value below which the designer must perform detailed deflection checks — commonly tested in board exams as a direct computation.

Term

fy Correction Factor

Definition

The multiplier (0.4 + fy/700) applied to the tabulated minimum thickness when steel yield strength differs from 420 MPa.

Importance

Often overlooked in board exam computations — forgetting this factor when fy = 275 or 415 MPa is a top pitfall.

Term

Clear Span (Ln)

Definition

The net distance between the faces of the supporting members (beams, walls, or columns). It is NOT the centre-to-centre spacing.

Importance

Using centre-to-centre span instead of clear span overstates h_min and is a common error.

Section Title

Minimum Slab Thickness for Deflection Control

Common Mistakes

  • Using centre-to-centre span L instead of the clear span Ln in the h_min formula.
  • Forgetting the (0.4 + fy/700) correction factor when fy ≠ 420 MPa (e.g., fy = 415 MPa gives factor = 0.993, not 1.0).
  • Rounding DOWN instead of UP — always round up to the next millimetre or practical increment.
  • Using the wrong divisor for the support condition — e.g., using L/20 for a continuous slab interior span instead of L/28.
  • Applying the one-way minimum thickness table to two-way slab problems.

Formulas

Example

Mu = 15 kN·m/m, d = 150 mm: Rn = (15×10⁶)/(0.90×1000×150²) = 0.741 MPa.

Formula

Rn = Mu / (φ × b × d²)

Variables

Mu = factored moment (N·mm/mm or N·mm/m, converted to N·mm); φ = 0.90; b = 1000 mm (per-metre strip); d = effective depth (mm).

Application

Compute the nominal moment coefficient to enter the ρ equation. Note: Mu in N·mm = kN·m × 10⁶.

Example

f'c = 28, fy = 415, Rn = 0.741: ρ = (0.85×28/415)[1−√(1−2×0.741/(0.85×28))] = 0.05735×0.03162 = 0.001814.

Formula

ρ = (0.85 f'c / fy) × [1 − √(1 − 2Rn / (0.85 f'c))]

Variables

f'c = concrete compressive strength (MPa); fy = steel yield strength (MPa); Rn = from previous formula.

Application

Compute the required steel ratio from the factored moment. Apply only when slab is tension-controlled.

Example

ρ = 0.001814, b = 1000, d = 150: As = 0.001814×1000×150 = 272 mm²/m.

Formula

As = ρ × b × d

Variables

ρ = steel ratio (dimensionless); b = 1000 mm; d = effective depth (mm). As is in mm²/m.

Application

Required main flexural steel per metre width. Compare to As,min (temperature steel on full h).

Example

As = 315 mm²/m, using 10 mm bars (Ab = 78.5 mm²): s = (78.5×1000)/315 = 249 mm → use 200 mm (round down for safety).

Formula

s = (Ab × 1000) / As

Variables

Ab = cross-sectional area of one bar (mm²); As = required steel (mm²/m); s = centre-to-centre spacing (mm).

Application

Convert the required steel area per metre to a practical bar spacing.

Example

h = 175 mm: s_max = min(3×175, 450) = min(525, 450) = 450 mm.

Formula

s_max (main steel) = min(3h, 450 mm)

Variables

h = total slab thickness (mm). The lesser of 3 times the slab thickness or 450 mm.

Application

Upper limit on bar spacing for main flexural reinforcement in one-way slabs (NSCP 2015 Sec. 406.7.3).

Exam Tips

  • Always convert Mu to N·mm: 1 kN·m = 10⁶ N·mm.
  • Memorise common bar areas: 10 mm (78.5 mm²), 12 mm (113.1 mm²), 16 mm (201.1 mm²), 20 mm (314.2 mm²), 25 mm (490.9 mm²).
  • After finding As from the ρ formula, always compare to As,temp = 0.0018bh and use the LARGER value.
  • Round bar spacing DOWN to a convenient number (e.g., computed 249 mm → specify 200 mm) to ensure adequate steel.
  • Check s_max = min(3h, 450 mm) as a final step — if computed spacing exceeds this, use s_max.

Key Points

  • A one-way slab is designed as a rectangular beam of unit width b = 1000 mm.
  • The factored moment Mu (in kN·m/m) is computed per unit width of slab.
  • The design procedure follows beam flexure: compute Rn, solve for ρ, find As.
  • The result As is in mm²/m — it represents the required steel area per 1 metre width of slab.
  • Convert As to bar spacing: s = (Ab × 1000) / As, where Ab is the area of one bar (mm²).
  • The minimum As for slabs in the main direction is governed by the shrinkage/temperature minimum on the full slab thickness h (not d).
  • Maximum bar spacing for main steel: min(3h, 450 mm) per NSCP 2015 Section 406.7.3.
  • Effective depth d = h − cover − half bar diameter; typical cover for slabs = 20 mm (protected) or 40 mm (exposed).
  • Phi factor (φ) = 0.90 for tension-controlled flexure (NSCP 2015 Section 421.2.1).

Definitions

Term

Unit Strip (1-Metre Strip)

Definition

A 1000-mm wide representative strip of slab used as the design beam. All quantities (load, moment, steel) are expressed per metre width.

Importance

The foundational concept for one-way slab design — all computations scale to a 1 m width.

Term

Effective Depth (d)

Definition

The distance from the extreme compression fibre to the centroid of the tension reinforcement: d = h − cover − db/2.

Importance

Directly appears in Rn and As computations; a small error in d produces a significant error in the design.

Term

Bar Spacing (s)

Definition

The centre-to-centre distance between adjacent parallel bars in the slab, in mm. Calculated from the required As and the area of the selected bar size.

Importance

The final practical output of slab design — what is physically placed in the field and specified in drawings.

Section Title

Flexural Steel Design — Per-Metre Strip Method

Common Mistakes

  • Forgetting to convert Mu from kN·m to N·mm (multiply by 10⁶) before computing Rn.
  • Using h (total thickness) instead of d (effective depth) in the Rn formula.
  • Not checking the computed As against the minimum (shrinkage/temperature steel on h) — the minimum often governs for thin slabs.
  • Rounding bar spacing UP instead of DOWN (rounding UP gives fewer bars and less steel than required).
  • Using φ = 0.85 (for shear) instead of φ = 0.90 (for flexure).

Formulas

Example

h = 175 mm, fy = 415 MPa: As,temp = 0.0018 × 1000 × 175 = 315 mm²/m.

Formula

As,temp = ρ_temp × b × h

Variables

ρ_temp = 0.0018 (fy = 415–420 MPa) or 0.0020 (fy = 275 MPa); b = 1000 mm (per-metre strip); h = total slab thickness (mm).

Application

Minimum steel area (mm²/m) for shrinkage and temperature control, placed perpendicular to main bars.

Example

h = 175 mm: s_max = min(5×175, 450) = min(875, 450) = 450 mm.

Formula

s_max (temperature steel) = min(5h, 450 mm)

Variables

h = total slab thickness (mm). The lesser of 5 times the slab thickness or 450 mm.

Application

Maximum allowable spacing for shrinkage/temperature bars (NSCP 2015 Sec. 406.7.3).

Example

As,temp = 315 mm²/m, 10 mm bars (Ab = 78.5): s = (78.5×1000)/315 = 249 mm < 450 mm → use 200 mm.

Formula

s_temp = (Ab × 1000) / As,temp

Variables

Ab = area of one temperature bar (mm²); As,temp = minimum temperature steel (mm²/m).

Application

Convert required temperature steel to bar spacing for the selected bar diameter.

Exam Tips

  • Two values to memorise: ρ_temp = 0.0018 (fy = 415/420 MPa) and ρ_temp = 0.0020 (fy = 275 MPa).
  • Temperature steel always uses FULL THICKNESS h, not d. Main steel uses d in moment calculations but h for the minimum check.
  • When a problem gives both Mu (for main steel) and asks for temperature steel — two separate calculations, both per 1 m strip.
  • If As,calc from flexure < As,temp from temperature minimum, use the temperature minimum as the ACTUAL As to provide.
  • Spacing: compute s, check against min(5h, 450) for temperature bars. Round computed spacing DOWN.

Key Points

  • Temperature and shrinkage reinforcement is placed perpendicular to the main flexural steel to control cracking.
  • It resists cracking caused by concrete drying shrinkage and thermal deformation — not flexure.
  • The minimum ratio ρ_temp depends on fy: use 0.0020 for fy = 275 MPa (Grade 40) and 0.0018 for fy = 415–420 MPa (Grade 60).
  • As,temp is computed on the FULL slab thickness h (not effective depth d).
  • Maximum spacing for temperature steel: min(5h, 450 mm) per NSCP 2015.
  • In the main direction of a thin slab, As from the flexure calculation may be less than As,temp — in that case, the temperature minimum governs.
  • Temperature steel is provided in BOTH faces for thick slabs (h > 300 mm is a common practical threshold).
  • NSCP 2015 Section 406.6 (ACI 318 Section 7.6.1) provides these minimum ratios.

Definitions

Term

Shrinkage and Temperature Steel

Definition

Minimum reinforcement placed perpendicular to the main flexural steel to limit crack widths caused by concrete shrinkage and temperature changes. It does not resist computed flexural loads.

Importance

Required by NSCP in ALL one-way slabs — its minimum often governs the main steel area in lightly loaded slabs.

Term

ρ_temp

Definition

The minimum steel ratio for shrinkage and temperature reinforcement: 0.0018 for Grade 60 (fy = 415–420 MPa) and 0.0020 for Grade 40 (fy = 275 MPa). Applied to full thickness h.

Importance

Two distinct values by grade — using 0.0018 for Grade 40 steel under-reinforces the slab.

Section Title

Shrinkage and Temperature Steel

Common Mistakes

  • Computing As,temp using d (effective depth) instead of h (full thickness) — always use total thickness for temperature steel.
  • Applying ρ_temp = 0.0018 when fy = 275 MPa — the correct value is 0.0020 for Grade 40 steel.
  • Forgetting to check temperature minimum against the computed main steel As — the larger governs.
  • Using the temperature spacing limit (min 5h, 450 mm) for main steel, or vice versa — they have different limits.

Formulas

Example

wu = 15 kN/m², L2 = 5 m, Ln = 5.5 m: Mo = (15 × 5 × 5.5²)/8 = (15 × 5 × 30.25)/8 = 2268.75/8 = 283.6 kN·m.

Formula

Mo = (wu × L2 × Ln²) / 8

Variables

Mo = total factored static moment per panel (kN·m); wu = factored uniform load (kN/m²); L2 = transverse panel dimension centre-to-centre of supports (m); Ln = clear span in the direction of analysis (m).

Application

Total static moment for a DDM panel. This Mo is then distributed into negative and positive moments and to column/middle strips.

Example

Mo = 283.6 kN·m: M_neg = 0.65 × 283.6 = 184.3 kN·m; M_pos = 0.35 × 283.6 = 99.3 kN·m.

Formula

M_neg (interior) = 0.65 × Mo ; M_pos = 0.35 × Mo

Variables

For interior spans: 65% of Mo to negative (hogging at supports), 35% to positive (sagging at midspan).

Application

Distribution of total static moment Mo to moment regions per DDM (NSCP 2015 Table 408.10.4.2).

Example

For a flat plate with no edge beams, 75% of the negative moment goes to the column strip.

Formula

M_cs = fraction × M_neg or M_pos

Variables

M_cs = moment assigned to column strip; fraction = specified by NSCP tables (typically 60–75% of total strip moment for various conditions).

Application

Distribute the negative or positive moment to the column strip; the balance goes to the middle strip.

Example

C_a = 0.048, w = 10 kN/m², Ls = 4 m: M_a = 0.048 × 10 × 4² = 7.68 kN·m/m in the short direction.

Formula

Coefficient Method: M = C × w × Ls²

Variables

C = tabulated moment coefficient (dimensionless, from NSCP/ACI tables); w = total service or factored load (kN/m²); Ls = short span length (m).

Application

Moment analysis for two-way slabs on stiff beams. Coefficients vary with edge conditions (simply supported, continuous, fixed) and ratio La/Lb.

Exam Tips

  • Mo = wu L2 Ln² / 8 — think of it as an equivalent simply-supported span beam moment.
  • For interior spans (DDM): split Mo as 65% negative, 35% positive. For end spans: use NSCP Table 408.10.4.2 (varies by edge condition).
  • Verify DDM applicability before applying it — board exam problems sometimes test whether conditions are met.
  • The coefficient method uses SHORT SPAN in M = C w Ls²; coefficients Ca (short direction) and Cb (long direction) are read from separate tables.
  • Two-way punching shear at columns is a separate check — do not confuse it with flexural design.

Key Points

  • Two-way slabs develop bending moments in both the short and long directions simultaneously.
  • Three main analysis methods are used: (1) Coefficient Method, (2) Direct Design Method (DDM), (3) Equivalent Frame Method (EFM).
  • The Coefficient Method is used for slabs supported on stiff beams (not flat plates). Moments = C × w × Ls², with C tabulated by edge condition and aspect ratio.
  • DDM and EFM are applicable to flat plates and flat slabs supported directly on columns.
  • DDM requires: minimum 3 spans, rectangular panels, successive span ratio ≤ 1/3, no offset columns, and LL/DL ≤ 2 (NSCP 2015 Sec. 408.10).
  • The total static moment Mo is the starting point for DDM — distributed to column and middle strips.
  • Column strip occupies the middle half of each panel width (L2/2 centred on the column line).
  • Middle strip is the remainder between two column strips in adjacent panels.
  • NSCP 2015 specifies the percentage of Mo distributed to positive and negative moment regions and to column vs. middle strips.

Definitions

Term

Total Static Moment (Mo)

Definition

The sum of the maximum positive and average negative factored bending moments in a panel, computed as Mo = wu L2 Ln² / 8. It is the reference moment for DDM distribution.

Importance

The central quantity in DDM — all strip moments are fractions of Mo. An error here propagates to all subsequent design steps.

Term

Column Strip

Definition

A design strip of slab with width equal to half the panel width L2, centred on the column line. It carries the larger share of moments due to proximity to the supports.

Importance

Column strips attract more moment than middle strips — reinforcement is heavier here.

Term

Middle Strip

Definition

The slab strip between two column strips of adjacent panels. It carries the remaining moment not assigned to the column strips.

Importance

Lighter reinforcement than column strips — easy to confuse which strip gets which fraction of moment.

Term

Direct Design Method (DDM)

Definition

An approximate analysis procedure in NSCP 2015 Section 408.10 for two-way slabs on columns that distributes Mo directly using prescribed fractions — no frame analysis required.

Importance

Commonly tested in board exams due to its step-by-step nature and specific applicability conditions.

Term

Flat Plate

Definition

A two-way slab supported directly on columns without beams or drop panels. The simplest flat slab system, but most susceptible to punching shear failure at column heads.

Importance

A common system in Philippine residential and commercial buildings — DDM or EFM governs the analysis.

Section Title

Two-Way Slab Analysis

Common Mistakes

  • Using the full panel span L instead of the clear span Ln in the Mo formula.
  • Confusing L2 (transverse span) and Ln (clear span in direction of analysis) — they are different lengths.
  • Applying DDM to slabs that violate the applicability conditions (e.g., LL/DL > 2, irregular panels).
  • Assigning 100% of the column strip moment fraction to only ONE direction of reinforcement.
  • Using the coefficient method coefficients for flat plates (they only apply to slabs on stiff beams).

Connections

  • BEAM FLEXURE (Chapter 2): One-way slab design is a direct extension — b = 1000 mm and the Rn–ρ procedure is identical. The only addition is the temperature steel minimum check.
  • LOAD COMBINATIONS (Chapter 1): The factored load wu = 1.2DL + 1.6LL is used in both Mu computation and in the DDM formula for Mo. Understanding load factoring is a prerequisite.
  • SHEAR DESIGN: Slabs typically do not use shear reinforcement and are designed so that Vc ≥ Vu. Two-way (punching) shear at column heads is a critical additional check for flat plates and flat slabs.
  • DEFLECTION CONTROL: The minimum thickness table directly avoids the need for deflection calculations per NSCP Section 406.6. If h < h_min, the full deflection check (using Ie = effective moment of inertia) must be performed.
  • CONTINUOUS BEAM ANALYSIS: For multi-span continuous slabs, ACI moment coefficients (NSCP Section 406.5) can be used to estimate design moments at supports and midspan without a full frame analysis.
  • PRESTRESSED CONCRETE: Prestressed slabs use unbonded tendons (common in Philippine high-rise construction) and are governed by different minimum thickness and stress limit criteria — a key subject area in the same exam topic.
  • FOUNDATION DESIGN: Two-way (flat slab) behaviour also appears in mat (raft) foundations, where the slab spans between column bases and is analysed using similar DDM concepts.
  • RA 544 (Engineering Law): All structural design and documentation must be signed and sealed by a licensed Civil Engineer or Structural Engineer. The NSCP 2015 is the legally adopted design code per DPWH and NBC (PD 1096) in the Philippines.

Exam Strategy

For board exam slab problems, follow a strict five-step attack: (1) CLASSIFY — compute L_long/L_short first; if ≥ 2, one-way; if < 2, two-way. Write this ratio clearly. (2) MINIMUM THICKNESS — if asked, use the correct divisor (20/24/28/10) and apply the fy factor if fy ≠ 420 MPa. (3) FLEXURAL STEEL — for one-way: set b = 1000 mm, convert Mu to N·mm (×10⁶), compute Rn → ρ → As. For two-way DDM: compute Mo, split to M_neg/M_pos, then to column/middle strip. (4) TEMPERATURE CHECK — compute As,temp = ρ_temp × 1000 × h; use the LARGER of As,flex and As,temp. (5) SPACING — compute s = Ab×1000/As, round DOWN, check s_max = min(3h,450) for main or min(5h,450) for temperature. Time allocation: classification + minimum thickness = 1–2 min; full flexural design = 3–5 min; DDM moment distribution = 5–8 min. Know your bar areas cold — board exams do not always provide them. Practice at least 10 full slab design problems before the exam.

Quick Review Questions

A rectangular slab panel measures 4.5 m × 8.0 m and is supported on all four sides. Is it a one-way or two-way slab?

Aspect ratio = L_long / L_short = 8.0 / 4.5 = 1.78. Since 1.78 < 2, the panel is a TWO-WAY slab. Both spans are significant and reinforcement must be designed in both directions. Note: 8.0/4.5 = 1.778, which is less than 2 — this is a common board-exam trap where the spans look very different but the ratio is still below 2.

Find the minimum thickness of a one-way slab with both ends continuous, clear span Ln = 5.6 m, and fy = 415 MPa.

For both-ends-continuous: divisor = 28. fy adjustment factor = 0.4 + 415/700 = 0.4 + 0.593 = 0.993. h_min = (5600/28)(0.993) = 200(0.993) = 198.6 mm. Round UP to 200 mm. Note: fy = 415 MPa gives a factor slightly less than 1.0 (compared to 420 MPa), so the minimum thickness is marginally reduced — but in practice still rounds to 200 mm.

A 180 mm thick slab uses fy = 275 MPa steel. Calculate the required temperature steel per metre width and the maximum allowable spacing.

For fy = 275 MPa (Grade 40), ρ_temp = 0.0020. As,temp = 0.0020 × 1000 × 180 = 360 mm²/m. Maximum spacing = min(5h, 450) = min(900, 450) = 450 mm. If 12 mm bars are used (Ab = 113.1 mm²), spacing = (113.1×1000)/360 = 314 mm < 450 mm → use 300 mm.

A one-way slab strip (b = 1000 mm, d = 160 mm, h = 185 mm, f'c = 28 MPa, fy = 415 MPa) carries Mu = 12 kN·m/m. Find the required As and determine which governs: flexure or temperature minimum.

Step 1: Rn = (12×10⁶)/(0.90×1000×160²) = 12,000,000/23,040,000 = 0.521 MPa. Step 2: ρ = (0.85×28/415)[1−√(1−2×0.521/(0.85×28))] = 0.05735[1−√(1−0.04376)] = 0.05735×0.02234 = 0.001281. Step 3: As,flex = 0.001281×1000×160 = 205 mm²/m. Step 4: As,temp = 0.0018×1000×185 = 333 mm²/m. Since 205 < 333, TEMPERATURE GOVERNS. Provide 333 mm²/m.

For a DDM two-way flat plate, wu = 12 kN/m², L2 = 6 m, Ln = 5.4 m. Calculate the total static moment Mo and the interior span positive and negative moment values.

Mo = wu L2 Ln² / 8 = (12 × 6 × 5.4²)/8 = (12 × 6 × 29.16)/8 = 2099.5/8 = 262.4 kN·m. For interior spans per NSCP DDM: negative moment = 0.65 × Mo = 0.65 × 262.4 = 170.6 kN·m; positive moment = 0.35 × Mo = 0.35 × 262.4 = 91.8 kN·m. These are then distributed further to column and middle strips per NSCP Table 408.10.5.

What is the maximum allowable bar spacing for (a) main flexural steel and (b) temperature/shrinkage steel in a slab with h = 200 mm?

Per NSCP 2015 Section 406.7.3: Main steel maximum spacing = min(3h, 450 mm) = min(600, 450) = 450 mm. Temperature steel maximum spacing = min(5h, 450 mm) = min(1000, 450) = 450 mm. In this case, for h = 200 mm, BOTH limits evaluate to 450 mm (since 3h = 600 > 450 and 5h = 1000 > 450). For thinner slabs, the 3h or 5h term may govern.

A slab strip requires As = 285 mm²/m. Using 12 mm diameter bars (Ab = 113.1 mm²), find the required bar spacing and verify against s_max for a 160 mm slab.

Computed spacing s = (Ab × 1000)/As = (113.1 × 1000)/285 = 396.8 mm. s_max = min(3h, 450) = min(3×160, 450) = min(480, 450) = 450 mm. Since 396.8 mm < 450 mm, the computed spacing is acceptable. Round DOWN to 350 mm for a practical specification. Never round up bar spacing beyond the computed value — that would provide less steel than required.

State two conditions that must be met for a slab to qualify for the Direct Design Method (DDM) per NSCP 2015.

NSCP 2015 Section 408.10.2 lists five applicability conditions for DDM. These ensure the slab behaviour is regular enough for the simplified moment distribution to be valid. If ANY condition is violated, the Equivalent Frame Method (EFM) or a more rigorous analysis must be used. Common board exam question: 'which condition is violated?' given a set of panel properties.

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