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USTET MathematicsTrigonometryFlash Cards

Practice flashcards for USTET Mathematics — Trigonometry. Built for the retrieval-practice technique that consistently outperforms re-reading. Covers every high-yield concept University of Santo Tomas tests in this chapter of the USTET 2026.

Exam context

University of Santo Tomas runs the University of Santo Tomas Entrance Test on Early Q4 2026. Its Mathematics section sits under a "Core section" weighting, and Trigonometry is the 7th chapter in the 9-chapter USTET Mathematics rotation. The USTET passing mark is Competitive overall score, and the most recent 2026 paper drew about a meaningful share of questions from Mathematics.

Trigonometry - Flashcards

Master trigonometry concepts through problem-solving practice! These flashcards focus on applying trigonometric functions, identities, and theorems to solve real problems. Each card presents a practical problem with step-by-step solutions to build your problem-solving skills for UPCAT and other college entrance exams.

Cards

Find sin θ, cos θ, and tan θ if the point (-3, 4) lies on the terminal side of angle θ in standard position.

Step 1: Find r using distance formula: r = √(x² + y²) = √((-3)² + 4²) = √(9 + 16) = √25 = 5 Step 2: Apply definitions: • sin θ = y/r = 4/5 • cos θ = x/r = -3/5 • tan θ = y/x = 4/(-3) = -4/3 Answer: sin θ = 4/5, cos θ = -3/5, tan θ = -4/3

Tags

  • coordinate_plane
  • standard_position
  • basic_functions
  • medium

Topic

Trigonometric Functions

Card Id

FC1

Difficulty

medium

Image Prompt

Convert 135° to radians.

Step 1: Use conversion formula: radians = degrees × (π/180°) Step 2: Substitute: 135° × (π/180°) Step 3: Simplify: (135π)/180 = (3π)/4 Answer: 3π/4 radians

Tags

  • degree_to_radian
  • conversion
  • easy

Topic

Angle Measurement

Card Id

FC2

Difficulty

easy

Image Prompt

A ladder 10 meters long leans against a wall, making a 60° angle with the ground. How high up the wall does the ladder reach?

Step 1: Identify the right triangle - ladder is hypotenuse (10m), height is opposite to 60° angle Step 2: Use sine function: sin 60° = opposite/hypotenuse Step 3: sin 60° = height/10 Step 4: height = 10 × sin 60° = 10 × (√3/2) = 5√3 Step 5: Calculate: 5√3 ≈ 8.66 meters Answer: 5√3 or approximately 8.66 meters

Tags

  • word_problem
  • sine_function
  • real_world
  • medium

Topic

Right Triangle Applications

Card Id

FC3

Difficulty

medium

Image Prompt

Find the exact value of cos 240°.

Step 1: Determine the quadrant - 240° is in Quadrant III (180° < 240° < 270°) Step 2: Find reference angle: 240° - 180° = 60° Step 3: In Quadrant III, cosine is negative Step 4: cos 240° = -cos 60° = -1/2 Answer: -1/2

Tags

  • reference_angle
  • quadrant_III
  • exact_values
  • medium

Topic

Unit Circle and Reference Angles

Card Id

FC4

Difficulty

medium

Image Prompt

If sin θ = 3/5 and θ is in Quadrant II, find cos θ and tan θ.

Step 1: Use Pythagorean identity: sin²θ + cos²θ = 1 Step 2: (3/5)² + cos²θ = 1 Step 3: 9/25 + cos²θ = 1 Step 4: cos²θ = 1 - 9/25 = 16/25 Step 5: cos θ = ±4/5, but in Quadrant II, cosine is negative, so cos θ = -4/5 Step 6: tan θ = sin θ/cos θ = (3/5)/(-4/5) = -3/4 Answer: cos θ = -4/5, tan θ = -3/4

Tags

  • pythagorean_identity
  • quadrant_II
  • problem_solving
  • medium

Topic

Pythagorean Identity

Card Id

FC5

Difficulty

medium

Image Prompt

Find the arc length of a circle with radius 8 cm if the central angle is 45°.

Step 1: Convert angle to radians: 45° × (π/180°) = π/4 radians Step 2: Use arc length formula: s = rθ (where θ is in radians) Step 3: s = 8 × (π/4) = 2π cm Step 4: Calculate decimal: 2π ≈ 6.28 cm Answer: 2π cm or approximately 6.28 cm

Tags

  • arc_length
  • radian_measure
  • circle_geometry
  • easy

Topic

Arc Length

Card Id

FC6

Difficulty

easy

Image Prompt

In a right triangle, if the opposite side is 7 and the hypotenuse is 25, find sin θ, cos θ, and tan θ.

Step 1: Find adjacent side using Pythagorean theorem: a² + 7² = 25² Step 2: a² + 49 = 625, so a² = 576, therefore a = 24 Step 3: Apply trigonometric ratios: • sin θ = opposite/hypotenuse = 7/25 • cos θ = adjacent/hypotenuse = 24/25 • tan θ = opposite/adjacent = 7/24 Answer: sin θ = 7/25, cos θ = 24/25, tan θ = 7/24

Tags

  • pythagorean_theorem
  • basic_ratios
  • right_triangle
  • medium

Topic

Right Triangle Trigonometry

Card Id

FC7

Difficulty

medium

Image Prompt

Simplify: sin²θ + cos²θ + tan²θ - sec²θ

Step 1: Use fundamental identities: sin²θ + cos²θ = 1 and sec²θ - tan²θ = 1 Step 2: Rearrange the second identity: tan²θ - sec²θ = -1 Step 3: Substitute: (sin²θ + cos²θ) + (tan²θ - sec²θ) Step 4: = 1 + (-1) = 0 Answer: 0

Tags

  • fundamental_identities
  • simplification
  • algebraic_manipulation
  • hard

Topic

Trigonometric Identities

Card Id

FC8

Difficulty

hard

Image Prompt

Find the coterminal angle between 0° and 360° for the angle 890°.

Step 1: Since 890° > 360°, subtract multiples of 360° Step 2: 890° ÷ 360° = 2.47..., so we subtract 2 × 360° = 720° Step 3: 890° - 720° = 170° Step 4: Check: 0° ≤ 170° ≤ 360° ✓ Answer: 170°

Tags

  • coterminal_angles
  • angle_reduction
  • easy

Topic

Coterminal Angles

Card Id

FC9

Difficulty

easy

Image Prompt

A tree casts a shadow 15 meters long when the angle of elevation of the sun is 35°. Find the height of the tree.

Step 1: Draw right triangle - height is opposite to 35°, shadow is adjacent Step 2: Use tangent function: tan 35° = height/shadow Step 3: tan 35° = height/15 Step 4: height = 15 × tan 35° Step 5: height ≈ 15 × 0.7002 ≈ 10.5 meters Answer: Approximately 10.5 meters

Tags

  • word_problem
  • tangent_function
  • angle_of_elevation
  • medium

Topic

Angle of Elevation

Card Id

FC10

Difficulty

medium

Image Prompt

Convert 5π/6 radians to degrees.

Step 1: Use conversion formula: degrees = radians × (180°/π) Step 2: (5π/6) × (180°/π) Step 3: Simplify: (5 × 180°)/6 = 900°/6 = 150° Answer: 150°

Tags

  • radian_to_degree
  • conversion
  • easy

Topic

Angle Measurement

Card Id

FC11

Difficulty

easy

Image Prompt

If csc θ = 13/5, find sin θ and determine which quadrants θ could be in.

Step 1: Use reciprocal identity: csc θ = 1/sin θ Step 2: 13/5 = 1/sin θ, so sin θ = 5/13 Step 3: Since sin θ > 0, θ must be in Quadrant I or II Step 4: Verify: csc θ = 1/(5/13) = 13/5 ✓ Answer: sin θ = 5/13; θ is in Quadrant I or II

Tags

  • cosecant
  • reciprocal_identity
  • quadrant_analysis
  • medium

Topic

Reciprocal Functions

Card Id

FC12

Difficulty

medium

Image Prompt

In triangle ABC, a = 8, b = 6, and C = 60°. Find side c using the Law of Cosines.

Step 1: Apply Law of Cosines: c² = a² + b² - 2ab cos C Step 2: c² = 8² + 6² - 2(8)(6)cos 60° Step 3: c² = 64 + 36 - 96 cos 60° Step 4: c² = 100 - 96(1/2) = 100 - 48 = 52 Step 5: c = √52 = √(4×13) = 2√13 Step 6: c ≈ 7.21 Answer: c = 2√13 or approximately 7.21

Tags

  • law_of_cosines
  • triangle_solving
  • hard

Topic

Law of Cosines

Card Id

FC13

Difficulty

hard

Image Prompt

Find all values of θ between 0° and 360° where sin θ = -√2/2.

Step 1: Recognize that |sin θ| = √2/2 corresponds to reference angle 45° Step 2: Since sin θ < 0, θ must be in Quadrant III or IV Step 3: For Quadrant III: θ = 180° + 45° = 225° Step 4: For Quadrant IV: θ = 360° - 45° = 315° Step 5: Verify: sin 225° = sin 315° = -√2/2 ✓ Answer: θ = 225° and θ = 315°

Tags

  • trigonometric_equations
  • special_values
  • quadrant_analysis
  • hard

Topic

Solving Trigonometric Equations

Card Id

FC14

Difficulty

hard

Image Prompt

A wheel with radius 4 inches rotates through an angle of 2π/3 radians. How far does a point on the rim travel?

Step 1: This is an arc length problem where the point travels along the arc Step 2: Use arc length formula: s = rθ Step 3: s = 4 × (2π/3) = 8π/3 inches Step 4: Calculate decimal: 8π/3 ≈ 8.38 inches Answer: 8π/3 inches or approximately 8.38 inches

Tags

  • arc_length
  • circular_motion
  • real_world
  • medium

Topic

Arc Length Applications

Card Id

FC15

Difficulty

medium

Image Prompt

If tan θ = -3/4 and θ is in Quadrant II, find sin θ and cos θ.

Step 1: In Quadrant II, sin θ > 0 and cos θ < 0 Step 2: Use identity: tan²θ + 1 = sec²θ Step 3: (-3/4)² + 1 = sec²θ, so 9/16 + 1 = sec²θ Step 4: sec²θ = 25/16, so sec θ = ±5/4 Step 5: In Quadrant II, sec θ < 0, so sec θ = -5/4 Step 6: cos θ = 1/sec θ = -4/5 Step 7: sin θ = tan θ × cos θ = (-3/4) × (-4/5) = 3/5 Answer: sin θ = 3/5, cos θ = -4/5

Tags

  • quadrant_II
  • tangent_given
  • identity_application
  • hard

Topic

Quadrant Analysis

Card Id

FC16

Difficulty

hard

Image Prompt

Find the exact value of sin 30° + cos 60° - tan 45°.

Step 1: Recall special angle values: • sin 30° = 1/2 • cos 60° = 1/2 • tan 45° = 1 Step 2: Substitute: 1/2 + 1/2 - 1 Step 3: Calculate: 1 - 1 = 0 Answer: 0

Tags

  • special_angles
  • exact_values
  • arithmetic
  • easy

Topic

Special Angles

Card Id

FC17

Difficulty

easy

Image Prompt

In triangle PQR, P = 45°, Q = 75°, and side p = 10. Find side q using the Law of Sines.

Step 1: First find angle R: R = 180° - 45° - 75° = 60° Step 2: Apply Law of Sines: p/sin P = q/sin Q Step 3: 10/sin 45° = q/sin 75° Step 4: q = 10 × (sin 75°/sin 45°) Step 5: sin 45° = √2/2 ≈ 0.707, sin 75° ≈ 0.966 Step 6: q = 10 × (0.966/0.707) ≈ 13.66 Answer: q ≈ 13.66

Tags

  • law_of_sines
  • triangle_solving
  • calculator_needed
  • hard

Topic

Law of Sines

Card Id

FC18

Difficulty

hard

Image Prompt

Verify the identity: (1 + cos θ)(1 - cos θ) = sin²θ

Step 1: Expand left side using difference of squares: (1 + cos θ)(1 - cos θ) = 1² - (cos θ)² Step 2: Simplify: = 1 - cos²θ Step 3: Use Pythagorean identity: sin²θ + cos²θ = 1 Step 4: Rearrange: sin²θ = 1 - cos²θ Step 5: Substitute: 1 - cos²θ = sin²θ ✓ Answer: Identity verified. Both sides equal sin²θ.

Tags

  • identity_verification
  • algebraic_manipulation
  • pythagorean_identity
  • medium

Topic

Identity Verification

Card Id

FC19

Difficulty

medium

Image Prompt

A surveyor measures the angle of elevation to the top of a building as 25° from a point 50 meters away. Find the height of the building.

Step 1: Draw right triangle - building height is opposite to 25° angle, 50m is adjacent Step 2: Use tangent function: tan 25° = height/50 Step 3: height = 50 × tan 25° Step 4: tan 25° ≈ 0.466 Step 5: height = 50 × 0.466 = 23.3 meters Answer: Approximately 23.3 meters

Tags

  • surveying
  • angle_of_elevation
  • real_world_problem
  • medium

Topic

Applications of Trigonometry

Card Id

FC20

Difficulty

medium

Image Prompt

Tag Distribution

Easy

4

Hard

6

Medium

10

Real World

4

Exact Values

3

Word Problem

6

Problem Solving

12

Quadrant Analysis

3

Topic Distribution

Special Angles

2

Angle Measurement

3

Trigonometric Functions

4

Law Of Sines And Cosines

2

Trigonometric Identities

3

Right Triangle Applications

3

Applications Of Trigonometry

1

Unit Circle And Reference Angles

2

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