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USTET MathematicsStatistics & ProbabilityFlash Cards

The research on retention is unambiguous: retrieval practice beats re-reading for exam prep. These Statistics & Probability flashcards give USTET candidates a structured way to apply that for the Mathematics subtest, card by card, against the concepts University of Santo Tomas uses most often on the 2026 paper.

Exam context

University of Santo Tomas runs the University of Santo Tomas Entrance Test on Early Q4 2026. Its Mathematics section sits under a "Core section" weighting, and Statistics & Probability is the 8th chapter in the 9-chapter USTET Mathematics rotation. The USTET passing mark is Competitive overall score, and the most recent 2026 paper drew about a meaningful share of questions from Mathematics.

Statistics & Probability - Flashcards

Master Statistics & Probability concepts through practice problems and step-by-step solutions. These flashcards focus on problem-solving techniques essential for UPCAT and other college entrance examinations. Each card includes worked examples with detailed explanations to build your mathematical reasoning skills.

Cards

Find the mean of the data set: 85, 92, 78, 96, 88, 91, 84

Step 1: Add all values: 85 + 92 + 78 + 96 + 88 + 91 + 84 = 614 Step 2: Count the number of values: 7 Step 3: Divide sum by count: Mean = 614 ÷ 7 = 87.71 Answer: The mean is approximately 87.71

Tags

  • mean
  • central_tendency
  • basic_calculation

Topic

Measures of Central Tendency

Card Id

FC1

Difficulty

easy

Image Prompt

Find the median of: 15, 23, 12, 19, 27, 21, 18, 25, 16

Step 1: Arrange in ascending order: 12, 15, 16, 18, 19, 21, 23, 25, 27 Step 2: Count values: 9 (odd number) Step 3: Find middle position: (9+1) ÷ 2 = 5th position Step 4: Identify 5th value: 19 Answer: The median is 19

Tags

  • median
  • central_tendency
  • ordering

Topic

Measures of Central Tendency

Card Id

FC2

Difficulty

easy

Image Prompt

Find the mode of: 7, 8, 9, 7, 6, 8, 7, 5, 8, 7

Step 1: Count frequency of each value: - 5 appears 1 time - 6 appears 1 time - 7 appears 4 times - 8 appears 3 times - 9 appears 1 time Step 2: Identify most frequent value: 7 appears most (4 times) Answer: The mode is 7

Tags

  • mode
  • frequency
  • central_tendency

Topic

Measures of Central Tendency

Card Id

FC3

Difficulty

easy

Image Prompt

Calculate the range of: 45, 52, 38, 61, 47, 55, 42

Step 1: Identify highest value: 61 Step 2: Identify lowest value: 38 Step 3: Apply range formula: Range = Highest - Lowest Step 4: Calculate: Range = 61 - 38 = 23 Answer: The range is 23

Tags

  • range
  • dispersion
  • basic_calculation

Topic

Measures of Dispersion

Card Id

FC4

Difficulty

easy

Image Prompt

A fair coin is tossed 3 times. What is the probability of getting exactly 2 heads?

Step 1: List sample space: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT (8 outcomes) Step 2: Identify favorable outcomes (exactly 2 heads): HHT, HTH, THH (3 outcomes) Step 3: Apply probability formula: P(E) = Favorable outcomes / Total outcomes Step 4: Calculate: P(2 heads) = 3/8 Answer: The probability is 3/8 or 0.375

Tags

  • probability
  • coin_toss
  • sample_space

Topic

Basic Probability

Card Id

FC5

Difficulty

medium

Image Prompt

How many ways can 5 students be arranged in a row for a photo?

Step 1: Identify this as a permutation problem (order matters) Step 2: Apply factorial formula: n! = n × (n-1) × (n-2) × ... × 1 Step 3: Calculate: 5! = 5 × 4 × 3 × 2 × 1 Step 4: Compute: 5! = 120 Answer: There are 120 different arrangements

Tags

  • permutation
  • factorial
  • arrangement

Topic

Permutations

Card Id

FC6

Difficulty

easy

Image Prompt

In how many ways can you choose 3 books from 8 books on a shelf?

Step 1: Identify as combination (order doesn't matter) Step 2: Apply combination formula: C(n,r) = n! / [r!(n-r)!] Step 3: Substitute: C(8,3) = 8! / [3!(8-3)!] = 8! / (3! × 5!) Step 4: Simplify: = (8 × 7 × 6) / (3 × 2 × 1) = 336/6 = 56 Answer: There are 56 ways to choose 3 books from 8

Tags

  • combination
  • selection
  • formula_application

Topic

Combinations

Card Id

FC7

Difficulty

medium

Image Prompt

A card is drawn from a standard deck. What is the probability of getting a red card or a face card?

Step 1: Identify events: A = red card, B = face card Step 2: Calculate P(A): 26 red cards out of 52 = 26/52 Step 3: Calculate P(B): 12 face cards out of 52 = 12/52 Step 4: Calculate P(A and B): 6 red face cards = 6/52 Step 5: Apply addition rule: P(A or B) = P(A) + P(B) - P(A and B) Step 6: Calculate: = 26/52 + 12/52 - 6/52 = 32/52 = 8/13 Answer: The probability is 8/13

Tags

  • probability
  • addition_rule
  • deck_cards

Topic

Probability Rules

Card Id

FC8

Difficulty

medium

Image Prompt

Find the variance of the data set: 2, 4, 6, 8, 10

Step 1: Find the mean: (2+4+6+8+10)/5 = 30/5 = 6 Step 2: Calculate deviations from mean: (2-6)=-4, (4-6)=-2, (6-6)=0, (8-6)=2, (10-6)=4 Step 3: Square the deviations: 16, 4, 0, 4, 16 Step 4: Find average of squared deviations: (16+4+0+4+16)/5 = 40/5 = 8 Answer: The variance is 8

Tags

  • variance
  • dispersion
  • calculation

Topic

Measures of Dispersion

Card Id

FC9

Difficulty

medium

Image Prompt

Two dice are rolled. What is the probability that the sum is 7?

Step 1: Total possible outcomes: 6 × 6 = 36 Step 2: Find favorable outcomes (sum = 7): (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) = 6 outcomes Step 3: Apply probability formula: P(sum=7) = 6/36 = 1/6 Answer: The probability is 1/6 ≈ 0.167

Tags

  • probability
  • dice
  • compound_events

Topic

Basic Probability

Card Id

FC10

Difficulty

medium

Image Prompt

When do you use the combination formula instead of permutation formula?

Use COMBINATION when: - Order doesn't matter - You're selecting/choosing items - Example: Choosing team members, selecting cards Use PERMUTATION when: - Order matters - You're arranging items - Example: Seating arrangements, ranking contestants Key difference: C(n,r) = P(n,r) ÷ r! because combinations eliminate the ordering factor

Tags

  • combination
  • permutation
  • concept_understanding

Topic

Permutations vs Combinations

Card Id

FC11

Difficulty

medium

Image Prompt

Calculate P(8,3) - the number of 3-digit arrangements from digits 1,2,3,4,5,6,7,8

Step 1: Identify as permutation (order matters for arrangements) Step 2: Apply formula: P(n,r) = n!/(n-r)! Step 3: Substitute: P(8,3) = 8!/(8-3)! = 8!/5! Step 4: Simplify: = 8 × 7 × 6 × 5!/5! = 8 × 7 × 6 Step 5: Calculate: = 336 Answer: There are 336 different 3-digit arrangements

Tags

  • permutation
  • arrangement
  • formula_application

Topic

Permutations

Card Id

FC12

Difficulty

medium

Image Prompt

Find the median of: 12, 15, 18, 20, 22, 25 (even number of values)

Step 1: Verify data is arranged: 12, 15, 18, 20, 22, 25 ✓ Step 2: Count values: 6 (even number) Step 3: Find middle positions: 3rd and 4th values Step 4: Identify middle values: 18 and 20 Step 5: Calculate median: (18 + 20)/2 = 38/2 = 19 Answer: The median is 19

Tags

  • median
  • even_count
  • central_tendency

Topic

Measures of Central Tendency

Card Id

FC13

Difficulty

medium

Image Prompt

A bag contains 5 red balls, 3 blue balls, and 2 green balls. What is the probability of drawing a blue ball?

Step 1: Count total balls: 5 + 3 + 2 = 10 balls Step 2: Count favorable outcomes (blue balls): 3 Step 3: Apply probability formula: P(blue) = Favorable/Total Step 4: Calculate: P(blue) = 3/10 = 0.3 Answer: The probability is 3/10 or 0.3 or 30%

Tags

  • probability
  • basic_calculation
  • favorable_outcomes

Topic

Basic Probability

Card Id

FC14

Difficulty

easy

Image Prompt

Calculate the standard deviation if the variance is 25

Step 1: Recall relationship: Standard deviation = √(variance) Step 2: Substitute given variance: SD = √25 Step 3: Calculate: SD = 5 Answer: The standard deviation is 5 Note: Standard deviation is always the positive square root of variance

Tags

  • standard_deviation
  • variance
  • relationship

Topic

Measures of Dispersion

Card Id

FC15

Difficulty

easy

Image Prompt

How many 4-letter words can be formed from MATHEMATICS if no letter is repeated?

Step 1: Count distinct letters in MATHEMATICS: M-A-T-H-E-M-A-T-I-C-S Distinct letters: M, A, T, H, E, I, C, S = 8 letters Step 2: Need 4-letter arrangements from 8 distinct letters Step 3: Apply permutation: P(8,4) = 8!/(8-4)! = 8!/4! Step 4: Calculate: = 8 × 7 × 6 × 5 = 1,680 Answer: 1,680 different 4-letter words can be formed

Tags

  • permutation
  • word_formation
  • no_repetition

Topic

Permutations with Restrictions

Card Id

FC16

Difficulty

hard

Image Prompt

Find the probability of getting at least one head when flipping a coin 3 times

Method 1 (Complement): Step 1: P(at least 1 head) = 1 - P(no heads) = 1 - P(all tails) Step 2: P(all tails) = P(T) × P(T) × P(T) = (1/2)³ = 1/8 Step 3: P(at least 1 head) = 1 - 1/8 = 7/8 Method 2 (Direct): Count favorable outcomes from sample space Total: 8 outcomes, Favorable: 7 outcomes (all except TTT) Answer: The probability is 7/8

Tags

  • probability
  • complement_rule
  • at_least

Topic

Probability Rules

Card Id

FC17

Difficulty

medium

Image Prompt

A committee of 4 people is to be formed from 6 men and 4 women. How many committees can have exactly 2 men?

Step 1: Need exactly 2 men and 2 women Step 2: Choose 2 men from 6: C(6,2) = 6!/(2!4!) = 15 Step 3: Choose 2 women from 4: C(4,2) = 4!/(2!2!) = 6 Step 4: Apply multiplication principle: Total = C(6,2) × C(4,2) Step 5: Calculate: = 15 × 6 = 90 Answer: 90 committees can be formed with exactly 2 men

Tags

  • combination
  • committee_formation
  • restrictions

Topic

Combinations with Restrictions

Card Id

FC18

Difficulty

hard

Image Prompt

The mean of 5 numbers is 24. If four numbers are 20, 22, 26, 28, find the fifth number.

Step 1: Use mean formula: Mean = Sum/Count Step 2: Calculate total sum: Sum = Mean × Count = 24 × 5 = 120 Step 3: Find sum of known numbers: 20 + 22 + 26 + 28 = 96 Step 4: Find fifth number: Fifth number = Total sum - Sum of known Step 5: Calculate: Fifth number = 120 - 96 = 24 Answer: The fifth number is 24

Tags

  • mean
  • missing_value
  • reverse_calculation

Topic

Measures of Central Tendency

Card Id

FC19

Difficulty

medium

Image Prompt

Two events A and B are independent. If P(A) = 0.4 and P(B) = 0.3, find P(A and B).

Step 1: Recall independence rule: For independent events, P(A and B) = P(A) × P(B) Step 2: Substitute given values: P(A and B) = 0.4 × 0.3 Step 3: Calculate: P(A and B) = 0.12 Answer: P(A and B) = 0.12 or 12% Note: Independence means one event doesn't affect the other's probability

Tags

  • probability
  • independent_events
  • multiplication_rule

Topic

Independent Events

Card Id

FC20

Difficulty

medium

Image Prompt

Tag Distribution

Dispersion

3

Combination

3

Permutation

4

Probability

7

Easy Difficulty

6

Hard Difficulty

3

Central Tendency

5

Basic Calculation

4

Medium Difficulty

11

Formula Application

3

Topic Distribution

Combinations

2

Permutations

3

Basic Probability

4

Probability Rules

2

Independent Events

1

Measures Of Dispersion

3

Measures Of Central Tendency

5

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