FEUCAT Mathematics — TrigonometryFlash Cards
Flashcards for Trigonometry reviewers. Front of card: a question or prompt. Back of card: the answer plus a short explanation. Every card is calibrated to the way FEUCAT tests Trigonometry in its Mathematics subtest.
Exam context
The Far Eastern University College Admission Test is conducted by Far Eastern University and is scheduled for Q3–Q4 2026. The Mathematics subtest is marked as "Core section" in the official pattern, and Trigonometry appears in position 7th of 9 in the FEUCAT Mathematics review rotation. Passing mark: Competitive overall score. Recent FEUCAT 2026 papers have drawn roughly a meaningful share of questions from this subject.
Trigonometry - Flashcards
Master trigonometry concepts through problem-solving practice! These flashcards focus on applying trigonometric functions, identities, and theorems to solve real problems. Each card presents a practical problem with step-by-step solutions to build your problem-solving skills for UPCAT and other college entrance exams.
Cards
Find sin θ, cos θ, and tan θ if the point (-3, 4) lies on the terminal side of angle θ in standard position.
Step 1: Find r using distance formula: r = √(x² + y²) = √((-3)² + 4²) = √(9 + 16) = √25 = 5 Step 2: Apply definitions: • sin θ = y/r = 4/5 • cos θ = x/r = -3/5 • tan θ = y/x = 4/(-3) = -4/3 Answer: sin θ = 4/5, cos θ = -3/5, tan θ = -4/3
Tags
- coordinate_plane
- standard_position
- basic_functions
- medium
Topic
Trigonometric Functions
Card Id
FC1
Difficulty
medium
Image Prompt
Convert 135° to radians.
Step 1: Use conversion formula: radians = degrees × (π/180°) Step 2: Substitute: 135° × (π/180°) Step 3: Simplify: (135π)/180 = (3π)/4 Answer: 3π/4 radians
Tags
- degree_to_radian
- conversion
- easy
Topic
Angle Measurement
Card Id
FC2
Difficulty
easy
Image Prompt
A ladder 10 meters long leans against a wall, making a 60° angle with the ground. How high up the wall does the ladder reach?
Step 1: Identify the right triangle - ladder is hypotenuse (10m), height is opposite to 60° angle Step 2: Use sine function: sin 60° = opposite/hypotenuse Step 3: sin 60° = height/10 Step 4: height = 10 × sin 60° = 10 × (√3/2) = 5√3 Step 5: Calculate: 5√3 ≈ 8.66 meters Answer: 5√3 or approximately 8.66 meters
Tags
- word_problem
- sine_function
- real_world
- medium
Topic
Right Triangle Applications
Card Id
FC3
Difficulty
medium
Image Prompt
Find the exact value of cos 240°.
Step 1: Determine the quadrant - 240° is in Quadrant III (180° < 240° < 270°) Step 2: Find reference angle: 240° - 180° = 60° Step 3: In Quadrant III, cosine is negative Step 4: cos 240° = -cos 60° = -1/2 Answer: -1/2
Tags
- reference_angle
- quadrant_III
- exact_values
- medium
Topic
Unit Circle and Reference Angles
Card Id
FC4
Difficulty
medium
Image Prompt
If sin θ = 3/5 and θ is in Quadrant II, find cos θ and tan θ.
Step 1: Use Pythagorean identity: sin²θ + cos²θ = 1 Step 2: (3/5)² + cos²θ = 1 Step 3: 9/25 + cos²θ = 1 Step 4: cos²θ = 1 - 9/25 = 16/25 Step 5: cos θ = ±4/5, but in Quadrant II, cosine is negative, so cos θ = -4/5 Step 6: tan θ = sin θ/cos θ = (3/5)/(-4/5) = -3/4 Answer: cos θ = -4/5, tan θ = -3/4
Tags
- pythagorean_identity
- quadrant_II
- problem_solving
- medium
Topic
Pythagorean Identity
Card Id
FC5
Difficulty
medium
Image Prompt
Find the arc length of a circle with radius 8 cm if the central angle is 45°.
Step 1: Convert angle to radians: 45° × (π/180°) = π/4 radians Step 2: Use arc length formula: s = rθ (where θ is in radians) Step 3: s = 8 × (π/4) = 2π cm Step 4: Calculate decimal: 2π ≈ 6.28 cm Answer: 2π cm or approximately 6.28 cm
Tags
- arc_length
- radian_measure
- circle_geometry
- easy
Topic
Arc Length
Card Id
FC6
Difficulty
easy
Image Prompt
In a right triangle, if the opposite side is 7 and the hypotenuse is 25, find sin θ, cos θ, and tan θ.
Step 1: Find adjacent side using Pythagorean theorem: a² + 7² = 25² Step 2: a² + 49 = 625, so a² = 576, therefore a = 24 Step 3: Apply trigonometric ratios: • sin θ = opposite/hypotenuse = 7/25 • cos θ = adjacent/hypotenuse = 24/25 • tan θ = opposite/adjacent = 7/24 Answer: sin θ = 7/25, cos θ = 24/25, tan θ = 7/24
Tags
- pythagorean_theorem
- basic_ratios
- right_triangle
- medium
Topic
Right Triangle Trigonometry
Card Id
FC7
Difficulty
medium
Image Prompt
Simplify: sin²θ + cos²θ + tan²θ - sec²θ
Step 1: Use fundamental identities: sin²θ + cos²θ = 1 and sec²θ - tan²θ = 1 Step 2: Rearrange the second identity: tan²θ - sec²θ = -1 Step 3: Substitute: (sin²θ + cos²θ) + (tan²θ - sec²θ) Step 4: = 1 + (-1) = 0 Answer: 0
Tags
- fundamental_identities
- simplification
- algebraic_manipulation
- hard
Topic
Trigonometric Identities
Card Id
FC8
Difficulty
hard
Image Prompt
Find the coterminal angle between 0° and 360° for the angle 890°.
Step 1: Since 890° > 360°, subtract multiples of 360° Step 2: 890° ÷ 360° = 2.47..., so we subtract 2 × 360° = 720° Step 3: 890° - 720° = 170° Step 4: Check: 0° ≤ 170° ≤ 360° ✓ Answer: 170°
Tags
- coterminal_angles
- angle_reduction
- easy
Topic
Coterminal Angles
Card Id
FC9
Difficulty
easy
Image Prompt
A tree casts a shadow 15 meters long when the angle of elevation of the sun is 35°. Find the height of the tree.
Step 1: Draw right triangle - height is opposite to 35°, shadow is adjacent Step 2: Use tangent function: tan 35° = height/shadow Step 3: tan 35° = height/15 Step 4: height = 15 × tan 35° Step 5: height ≈ 15 × 0.7002 ≈ 10.5 meters Answer: Approximately 10.5 meters
Tags
- word_problem
- tangent_function
- angle_of_elevation
- medium
Topic
Angle of Elevation
Card Id
FC10
Difficulty
medium
Image Prompt
Convert 5π/6 radians to degrees.
Step 1: Use conversion formula: degrees = radians × (180°/π) Step 2: (5π/6) × (180°/π) Step 3: Simplify: (5 × 180°)/6 = 900°/6 = 150° Answer: 150°
Tags
- radian_to_degree
- conversion
- easy
Topic
Angle Measurement
Card Id
FC11
Difficulty
easy
Image Prompt
If csc θ = 13/5, find sin θ and determine which quadrants θ could be in.
Step 1: Use reciprocal identity: csc θ = 1/sin θ Step 2: 13/5 = 1/sin θ, so sin θ = 5/13 Step 3: Since sin θ > 0, θ must be in Quadrant I or II Step 4: Verify: csc θ = 1/(5/13) = 13/5 ✓ Answer: sin θ = 5/13; θ is in Quadrant I or II
Tags
- cosecant
- reciprocal_identity
- quadrant_analysis
- medium
Topic
Reciprocal Functions
Card Id
FC12
Difficulty
medium
Image Prompt
In triangle ABC, a = 8, b = 6, and C = 60°. Find side c using the Law of Cosines.
Step 1: Apply Law of Cosines: c² = a² + b² - 2ab cos C Step 2: c² = 8² + 6² - 2(8)(6)cos 60° Step 3: c² = 64 + 36 - 96 cos 60° Step 4: c² = 100 - 96(1/2) = 100 - 48 = 52 Step 5: c = √52 = √(4×13) = 2√13 Step 6: c ≈ 7.21 Answer: c = 2√13 or approximately 7.21
Tags
- law_of_cosines
- triangle_solving
- hard
Topic
Law of Cosines
Card Id
FC13
Difficulty
hard
Image Prompt
Find all values of θ between 0° and 360° where sin θ = -√2/2.
Step 1: Recognize that |sin θ| = √2/2 corresponds to reference angle 45° Step 2: Since sin θ < 0, θ must be in Quadrant III or IV Step 3: For Quadrant III: θ = 180° + 45° = 225° Step 4: For Quadrant IV: θ = 360° - 45° = 315° Step 5: Verify: sin 225° = sin 315° = -√2/2 ✓ Answer: θ = 225° and θ = 315°
Tags
- trigonometric_equations
- special_values
- quadrant_analysis
- hard
Topic
Solving Trigonometric Equations
Card Id
FC14
Difficulty
hard
Image Prompt
A wheel with radius 4 inches rotates through an angle of 2π/3 radians. How far does a point on the rim travel?
Step 1: This is an arc length problem where the point travels along the arc Step 2: Use arc length formula: s = rθ Step 3: s = 4 × (2π/3) = 8π/3 inches Step 4: Calculate decimal: 8π/3 ≈ 8.38 inches Answer: 8π/3 inches or approximately 8.38 inches
Tags
- arc_length
- circular_motion
- real_world
- medium
Topic
Arc Length Applications
Card Id
FC15
Difficulty
medium
Image Prompt
If tan θ = -3/4 and θ is in Quadrant II, find sin θ and cos θ.
Step 1: In Quadrant II, sin θ > 0 and cos θ < 0 Step 2: Use identity: tan²θ + 1 = sec²θ Step 3: (-3/4)² + 1 = sec²θ, so 9/16 + 1 = sec²θ Step 4: sec²θ = 25/16, so sec θ = ±5/4 Step 5: In Quadrant II, sec θ < 0, so sec θ = -5/4 Step 6: cos θ = 1/sec θ = -4/5 Step 7: sin θ = tan θ × cos θ = (-3/4) × (-4/5) = 3/5 Answer: sin θ = 3/5, cos θ = -4/5
Tags
- quadrant_II
- tangent_given
- identity_application
- hard
Topic
Quadrant Analysis
Card Id
FC16
Difficulty
hard
Image Prompt
Find the exact value of sin 30° + cos 60° - tan 45°.
Step 1: Recall special angle values: • sin 30° = 1/2 • cos 60° = 1/2 • tan 45° = 1 Step 2: Substitute: 1/2 + 1/2 - 1 Step 3: Calculate: 1 - 1 = 0 Answer: 0
Tags
- special_angles
- exact_values
- arithmetic
- easy
Topic
Special Angles
Card Id
FC17
Difficulty
easy
Image Prompt
In triangle PQR, P = 45°, Q = 75°, and side p = 10. Find side q using the Law of Sines.
Step 1: First find angle R: R = 180° - 45° - 75° = 60° Step 2: Apply Law of Sines: p/sin P = q/sin Q Step 3: 10/sin 45° = q/sin 75° Step 4: q = 10 × (sin 75°/sin 45°) Step 5: sin 45° = √2/2 ≈ 0.707, sin 75° ≈ 0.966 Step 6: q = 10 × (0.966/0.707) ≈ 13.66 Answer: q ≈ 13.66
Tags
- law_of_sines
- triangle_solving
- calculator_needed
- hard
Topic
Law of Sines
Card Id
FC18
Difficulty
hard
Image Prompt
Verify the identity: (1 + cos θ)(1 - cos θ) = sin²θ
Step 1: Expand left side using difference of squares: (1 + cos θ)(1 - cos θ) = 1² - (cos θ)² Step 2: Simplify: = 1 - cos²θ Step 3: Use Pythagorean identity: sin²θ + cos²θ = 1 Step 4: Rearrange: sin²θ = 1 - cos²θ Step 5: Substitute: 1 - cos²θ = sin²θ ✓ Answer: Identity verified. Both sides equal sin²θ.
Tags
- identity_verification
- algebraic_manipulation
- pythagorean_identity
- medium
Topic
Identity Verification
Card Id
FC19
Difficulty
medium
Image Prompt
A surveyor measures the angle of elevation to the top of a building as 25° from a point 50 meters away. Find the height of the building.
Step 1: Draw right triangle - building height is opposite to 25° angle, 50m is adjacent Step 2: Use tangent function: tan 25° = height/50 Step 3: height = 50 × tan 25° Step 4: tan 25° ≈ 0.466 Step 5: height = 50 × 0.466 = 23.3 meters Answer: Approximately 23.3 meters
Tags
- surveying
- angle_of_elevation
- real_world_problem
- medium
Topic
Applications of Trigonometry
Card Id
FC20
Difficulty
medium
Image Prompt
Tag Distribution
Easy
4
Hard
6
Medium
10
Real World
4
Exact Values
3
Word Problem
6
Problem Solving
12
Quadrant Analysis
3
Topic Distribution
Special Angles
2
Angle Measurement
3
Trigonometric Functions
4
Law Of Sines And Cosines
2
Trigonometric Identities
3
Right Triangle Applications
3
Applications Of Trigonometry
1
Unit Circle And Reference Angles
2
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