FEUCAT Mathematics — Statistics & ProbabilityFlash Cards
Flashcards specifically for Statistics & Probability in the FEUCAT 2026. Every card has been tuned to match Far Eastern University's preferred question style. Practise them during your commute, at lunch, or before bed — they are designed for short bursts of high-retention review.
Exam context
The Far Eastern University College Admission Test is conducted by Far Eastern University and is scheduled for Q3–Q4 2026. The Mathematics subtest is marked as "Core section" in the official pattern, and Statistics & Probability appears in position 8th of 9 in the FEUCAT Mathematics review rotation. Passing mark: Competitive overall score. Recent FEUCAT 2026 papers have drawn roughly a meaningful share of questions from this subject.
Statistics & Probability - Flashcards
Master Statistics & Probability concepts through practice problems and step-by-step solutions. These flashcards focus on problem-solving techniques essential for UPCAT and other college entrance examinations. Each card includes worked examples with detailed explanations to build your mathematical reasoning skills.
Cards
Find the mean of the data set: 85, 92, 78, 96, 88, 91, 84
Step 1: Add all values: 85 + 92 + 78 + 96 + 88 + 91 + 84 = 614 Step 2: Count the number of values: 7 Step 3: Divide sum by count: Mean = 614 ÷ 7 = 87.71 Answer: The mean is approximately 87.71
Tags
- mean
- central_tendency
- basic_calculation
Topic
Measures of Central Tendency
Card Id
FC1
Difficulty
easy
Image Prompt
Find the median of: 15, 23, 12, 19, 27, 21, 18, 25, 16
Step 1: Arrange in ascending order: 12, 15, 16, 18, 19, 21, 23, 25, 27 Step 2: Count values: 9 (odd number) Step 3: Find middle position: (9+1) ÷ 2 = 5th position Step 4: Identify 5th value: 19 Answer: The median is 19
Tags
- median
- central_tendency
- ordering
Topic
Measures of Central Tendency
Card Id
FC2
Difficulty
easy
Image Prompt
Find the mode of: 7, 8, 9, 7, 6, 8, 7, 5, 8, 7
Step 1: Count frequency of each value: - 5 appears 1 time - 6 appears 1 time - 7 appears 4 times - 8 appears 3 times - 9 appears 1 time Step 2: Identify most frequent value: 7 appears most (4 times) Answer: The mode is 7
Tags
- mode
- frequency
- central_tendency
Topic
Measures of Central Tendency
Card Id
FC3
Difficulty
easy
Image Prompt
Calculate the range of: 45, 52, 38, 61, 47, 55, 42
Step 1: Identify highest value: 61 Step 2: Identify lowest value: 38 Step 3: Apply range formula: Range = Highest - Lowest Step 4: Calculate: Range = 61 - 38 = 23 Answer: The range is 23
Tags
- range
- dispersion
- basic_calculation
Topic
Measures of Dispersion
Card Id
FC4
Difficulty
easy
Image Prompt
A fair coin is tossed 3 times. What is the probability of getting exactly 2 heads?
Step 1: List sample space: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT (8 outcomes) Step 2: Identify favorable outcomes (exactly 2 heads): HHT, HTH, THH (3 outcomes) Step 3: Apply probability formula: P(E) = Favorable outcomes / Total outcomes Step 4: Calculate: P(2 heads) = 3/8 Answer: The probability is 3/8 or 0.375
Tags
- probability
- coin_toss
- sample_space
Topic
Basic Probability
Card Id
FC5
Difficulty
medium
Image Prompt
How many ways can 5 students be arranged in a row for a photo?
Step 1: Identify this as a permutation problem (order matters) Step 2: Apply factorial formula: n! = n × (n-1) × (n-2) × ... × 1 Step 3: Calculate: 5! = 5 × 4 × 3 × 2 × 1 Step 4: Compute: 5! = 120 Answer: There are 120 different arrangements
Tags
- permutation
- factorial
- arrangement
Topic
Permutations
Card Id
FC6
Difficulty
easy
Image Prompt
In how many ways can you choose 3 books from 8 books on a shelf?
Step 1: Identify as combination (order doesn't matter) Step 2: Apply combination formula: C(n,r) = n! / [r!(n-r)!] Step 3: Substitute: C(8,3) = 8! / [3!(8-3)!] = 8! / (3! × 5!) Step 4: Simplify: = (8 × 7 × 6) / (3 × 2 × 1) = 336/6 = 56 Answer: There are 56 ways to choose 3 books from 8
Tags
- combination
- selection
- formula_application
Topic
Combinations
Card Id
FC7
Difficulty
medium
Image Prompt
A card is drawn from a standard deck. What is the probability of getting a red card or a face card?
Step 1: Identify events: A = red card, B = face card Step 2: Calculate P(A): 26 red cards out of 52 = 26/52 Step 3: Calculate P(B): 12 face cards out of 52 = 12/52 Step 4: Calculate P(A and B): 6 red face cards = 6/52 Step 5: Apply addition rule: P(A or B) = P(A) + P(B) - P(A and B) Step 6: Calculate: = 26/52 + 12/52 - 6/52 = 32/52 = 8/13 Answer: The probability is 8/13
Tags
- probability
- addition_rule
- deck_cards
Topic
Probability Rules
Card Id
FC8
Difficulty
medium
Image Prompt
Find the variance of the data set: 2, 4, 6, 8, 10
Step 1: Find the mean: (2+4+6+8+10)/5 = 30/5 = 6 Step 2: Calculate deviations from mean: (2-6)=-4, (4-6)=-2, (6-6)=0, (8-6)=2, (10-6)=4 Step 3: Square the deviations: 16, 4, 0, 4, 16 Step 4: Find average of squared deviations: (16+4+0+4+16)/5 = 40/5 = 8 Answer: The variance is 8
Tags
- variance
- dispersion
- calculation
Topic
Measures of Dispersion
Card Id
FC9
Difficulty
medium
Image Prompt
Two dice are rolled. What is the probability that the sum is 7?
Step 1: Total possible outcomes: 6 × 6 = 36 Step 2: Find favorable outcomes (sum = 7): (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) = 6 outcomes Step 3: Apply probability formula: P(sum=7) = 6/36 = 1/6 Answer: The probability is 1/6 ≈ 0.167
Tags
- probability
- dice
- compound_events
Topic
Basic Probability
Card Id
FC10
Difficulty
medium
Image Prompt
When do you use the combination formula instead of permutation formula?
Use COMBINATION when: - Order doesn't matter - You're selecting/choosing items - Example: Choosing team members, selecting cards Use PERMUTATION when: - Order matters - You're arranging items - Example: Seating arrangements, ranking contestants Key difference: C(n,r) = P(n,r) ÷ r! because combinations eliminate the ordering factor
Tags
- combination
- permutation
- concept_understanding
Topic
Permutations vs Combinations
Card Id
FC11
Difficulty
medium
Image Prompt
Calculate P(8,3) - the number of 3-digit arrangements from digits 1,2,3,4,5,6,7,8
Step 1: Identify as permutation (order matters for arrangements) Step 2: Apply formula: P(n,r) = n!/(n-r)! Step 3: Substitute: P(8,3) = 8!/(8-3)! = 8!/5! Step 4: Simplify: = 8 × 7 × 6 × 5!/5! = 8 × 7 × 6 Step 5: Calculate: = 336 Answer: There are 336 different 3-digit arrangements
Tags
- permutation
- arrangement
- formula_application
Topic
Permutations
Card Id
FC12
Difficulty
medium
Image Prompt
Find the median of: 12, 15, 18, 20, 22, 25 (even number of values)
Step 1: Verify data is arranged: 12, 15, 18, 20, 22, 25 ✓ Step 2: Count values: 6 (even number) Step 3: Find middle positions: 3rd and 4th values Step 4: Identify middle values: 18 and 20 Step 5: Calculate median: (18 + 20)/2 = 38/2 = 19 Answer: The median is 19
Tags
- median
- even_count
- central_tendency
Topic
Measures of Central Tendency
Card Id
FC13
Difficulty
medium
Image Prompt
A bag contains 5 red balls, 3 blue balls, and 2 green balls. What is the probability of drawing a blue ball?
Step 1: Count total balls: 5 + 3 + 2 = 10 balls Step 2: Count favorable outcomes (blue balls): 3 Step 3: Apply probability formula: P(blue) = Favorable/Total Step 4: Calculate: P(blue) = 3/10 = 0.3 Answer: The probability is 3/10 or 0.3 or 30%
Tags
- probability
- basic_calculation
- favorable_outcomes
Topic
Basic Probability
Card Id
FC14
Difficulty
easy
Image Prompt
Calculate the standard deviation if the variance is 25
Step 1: Recall relationship: Standard deviation = √(variance) Step 2: Substitute given variance: SD = √25 Step 3: Calculate: SD = 5 Answer: The standard deviation is 5 Note: Standard deviation is always the positive square root of variance
Tags
- standard_deviation
- variance
- relationship
Topic
Measures of Dispersion
Card Id
FC15
Difficulty
easy
Image Prompt
How many 4-letter words can be formed from MATHEMATICS if no letter is repeated?
Step 1: Count distinct letters in MATHEMATICS: M-A-T-H-E-M-A-T-I-C-S Distinct letters: M, A, T, H, E, I, C, S = 8 letters Step 2: Need 4-letter arrangements from 8 distinct letters Step 3: Apply permutation: P(8,4) = 8!/(8-4)! = 8!/4! Step 4: Calculate: = 8 × 7 × 6 × 5 = 1,680 Answer: 1,680 different 4-letter words can be formed
Tags
- permutation
- word_formation
- no_repetition
Topic
Permutations with Restrictions
Card Id
FC16
Difficulty
hard
Image Prompt
Find the probability of getting at least one head when flipping a coin 3 times
Method 1 (Complement): Step 1: P(at least 1 head) = 1 - P(no heads) = 1 - P(all tails) Step 2: P(all tails) = P(T) × P(T) × P(T) = (1/2)³ = 1/8 Step 3: P(at least 1 head) = 1 - 1/8 = 7/8 Method 2 (Direct): Count favorable outcomes from sample space Total: 8 outcomes, Favorable: 7 outcomes (all except TTT) Answer: The probability is 7/8
Tags
- probability
- complement_rule
- at_least
Topic
Probability Rules
Card Id
FC17
Difficulty
medium
Image Prompt
A committee of 4 people is to be formed from 6 men and 4 women. How many committees can have exactly 2 men?
Step 1: Need exactly 2 men and 2 women Step 2: Choose 2 men from 6: C(6,2) = 6!/(2!4!) = 15 Step 3: Choose 2 women from 4: C(4,2) = 4!/(2!2!) = 6 Step 4: Apply multiplication principle: Total = C(6,2) × C(4,2) Step 5: Calculate: = 15 × 6 = 90 Answer: 90 committees can be formed with exactly 2 men
Tags
- combination
- committee_formation
- restrictions
Topic
Combinations with Restrictions
Card Id
FC18
Difficulty
hard
Image Prompt
The mean of 5 numbers is 24. If four numbers are 20, 22, 26, 28, find the fifth number.
Step 1: Use mean formula: Mean = Sum/Count Step 2: Calculate total sum: Sum = Mean × Count = 24 × 5 = 120 Step 3: Find sum of known numbers: 20 + 22 + 26 + 28 = 96 Step 4: Find fifth number: Fifth number = Total sum - Sum of known Step 5: Calculate: Fifth number = 120 - 96 = 24 Answer: The fifth number is 24
Tags
- mean
- missing_value
- reverse_calculation
Topic
Measures of Central Tendency
Card Id
FC19
Difficulty
medium
Image Prompt
Two events A and B are independent. If P(A) = 0.4 and P(B) = 0.3, find P(A and B).
Step 1: Recall independence rule: For independent events, P(A and B) = P(A) × P(B) Step 2: Substitute given values: P(A and B) = 0.4 × 0.3 Step 3: Calculate: P(A and B) = 0.12 Answer: P(A and B) = 0.12 or 12% Note: Independence means one event doesn't affect the other's probability
Tags
- probability
- independent_events
- multiplication_rule
Topic
Independent Events
Card Id
FC20
Difficulty
medium
Image Prompt
Tag Distribution
Dispersion
3
Combination
3
Permutation
4
Probability
7
Easy Difficulty
6
Hard Difficulty
3
Central Tendency
5
Basic Calculation
4
Medium Difficulty
11
Formula Application
3
Topic Distribution
Combinations
2
Permutations
3
Basic Probability
4
Probability Rules
2
Independent Events
1
Measures Of Dispersion
3
Measures Of Central Tendency
5
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