FEUCAT Mathematics — Perimeter, Area, Volume & Equation of a LineFlash Cards
Practice flashcards for FEUCAT Mathematics — Perimeter, Area, Volume & Equation of a Line. Built for the retrieval-practice technique that consistently outperforms re-reading. Covers every high-yield concept Far Eastern University tests in this chapter of the FEUCAT 2026.
Exam context
The Far Eastern University College Admission Test is conducted by Far Eastern University and is scheduled for Q3–Q4 2026. The Mathematics subtest is marked as "Core section" in the official pattern, and Perimeter, Area, Volume & Equation of a Line appears in position 6th of 9 in the FEUCAT Mathematics review rotation. Passing mark: Competitive overall score. Recent FEUCAT 2026 papers have drawn roughly a meaningful share of questions from this subject.
Perimeter, Area, Volume & Equation of a Line - Flashcards
Master the essential formulas for mensuration (perimeter, area, volume) and linear equations through problem-solving practice. These concepts are frequently tested in UPCAT and other Philippine entrance exams. Focus on understanding when and how to apply each formula through step-by-step problem solving.
Cards
Find the perimeter of a rectangle with length 12 cm and width 8 cm.
Formula: P = 2(l + w) Step 1: Identify values → l = 12 cm, w = 8 cm Step 2: Substitute → P = 2(12 + 8) Step 3: Calculate → P = 2(20) = 40 cm Answer: 40 cm
Tags
- rectangle
- perimeter
- basic_calculation
Topic
Perimeter
Card Id
FC1
Difficulty
easy
Image Prompt
A square has a perimeter of 36 meters. What is the length of each side?
Formula: P = 4s, so s = P/4 Step 1: Given P = 36 m Step 2: Substitute → s = 36/4 Step 3: Calculate → s = 9 m Step 4: Check: 4 × 9 = 36 ✓ Answer: 9 meters
Tags
- square
- perimeter
- reverse_calculation
Topic
Perimeter
Card Id
FC2
Difficulty
easy
Image Prompt
Find the circumference of a circle with radius 5 cm. (Use π = 3.14)
Formula: C = 2πr Step 1: Given r = 5 cm, π = 3.14 Step 2: Substitute → C = 2 × 3.14 × 5 Step 3: Calculate → C = 31.4 cm Alternative: C = πd = 3.14 × 10 = 31.4 cm Answer: 31.4 cm
Tags
- circle
- circumference
- pi_calculation
Topic
Perimeter
Card Id
FC3
Difficulty
medium
Image Prompt
Calculate the area of a rectangle with length 15 m and width 9 m.
Formula: A = lw Step 1: Identify values → l = 15 m, w = 9 m Step 2: Substitute → A = 15 × 9 Step 3: Calculate → A = 135 m² Remember: Area is always in square units! Answer: 135 m²
Tags
- rectangle
- area
- basic_multiplication
Topic
Area
Card Id
FC4
Difficulty
easy
Image Prompt
Find the area of a triangle with base 10 cm and height 6 cm.
Formula: A = ½bh Step 1: Identify values → b = 10 cm, h = 6 cm Step 2: Substitute → A = ½ × 10 × 6 Step 3: Calculate → A = ½ × 60 = 30 cm² Common mistake: Don't forget the ½! Answer: 30 cm²
Tags
- triangle
- area
- fraction_calculation
Topic
Area
Card Id
FC5
Difficulty
easy
Image Prompt
Calculate the area of a circle with diameter 14 cm. (Use π = 22/7)
Formula: A = πr² Step 1: Convert diameter to radius → r = 14/2 = 7 cm Step 2: Substitute → A = (22/7) × 7² Step 3: Calculate → A = (22/7) × 49 = 22 × 7 = 154 cm² Common mistake: Using diameter instead of radius! Answer: 154 cm²
Tags
- circle
- area
- diameter_to_radius
Topic
Area
Card Id
FC6
Difficulty
medium
Image Prompt
Find the area of a trapezoid with parallel sides 8 m and 12 m, and height 5 m.
Formula: A = ½(b₁ + b₂)h Step 1: Identify values → b₁ = 8 m, b₂ = 12 m, h = 5 m Step 2: Substitute → A = ½(8 + 12) × 5 Step 3: Calculate → A = ½(20) × 5 = 10 × 5 = 50 m² Answer: 50 m²
Tags
- trapezoid
- area
- parallel_sides
Topic
Area
Card Id
FC7
Difficulty
medium
Image Prompt
Calculate the volume of a cube with side length 4 cm.
Formula: V = s³ Step 1: Identify value → s = 4 cm Step 2: Substitute → V = 4³ Step 3: Calculate → V = 4 × 4 × 4 = 64 cm³ Remember: Volume is always in cubic units! Answer: 64 cm³
Tags
- cube
- volume
- power_calculation
Topic
Volume
Card Id
FC8
Difficulty
easy
Image Prompt
Find the volume of a rectangular prism with length 6 m, width 4 m, and height 3 m.
Formula: V = lwh Step 1: Identify values → l = 6 m, w = 4 m, h = 3 m Step 2: Substitute → V = 6 × 4 × 3 Step 3: Calculate → V = 72 m³ Tip: Multiply in any order: 6×4=24, then 24×3=72 Answer: 72 m³
Tags
- rectangular_prism
- volume
- three_dimensions
Topic
Volume
Card Id
FC9
Difficulty
easy
Image Prompt
Calculate the volume of a cylinder with radius 3 cm and height 8 cm. (Use π = 3.14)
Formula: V = πr²h Step 1: Identify values → r = 3 cm, h = 8 cm, π = 3.14 Step 2: Substitute → V = 3.14 × 3² × 8 Step 3: Calculate → V = 3.14 × 9 × 8 = 226.08 cm³ Answer: 226.08 cm³
Tags
- cylinder
- volume
- pi_calculation
Topic
Volume
Card Id
FC10
Difficulty
medium
Image Prompt
Find the volume of a cone with radius 6 cm and height 9 cm. (Use π = 3.14)
Formula: V = ⅓πr²h Step 1: Identify values → r = 6 cm, h = 9 cm, π = 3.14 Step 2: Substitute → V = ⅓ × 3.14 × 6² × 9 Step 3: Calculate → V = ⅓ × 3.14 × 36 × 9 = ⅓ × 1017.36 = 339.12 cm³ Common mistake: Forgetting the ⅓ factor! Answer: 339.12 cm³
Tags
- cone
- volume
- one_third_factor
Topic
Volume
Card Id
FC11
Difficulty
medium
Image Prompt
Calculate the volume of a sphere with radius 3 cm. (Use π = 3.14)
Formula: V = ⁴⁄₃πr³ Step 1: Identify values → r = 3 cm, π = 3.14 Step 2: Substitute → V = ⁴⁄₃ × 3.14 × 3³ Step 3: Calculate → V = ⁴⁄₃ × 3.14 × 27 = ⁴⁄₃ × 84.78 = 113.04 cm³ Answer: 113.04 cm³
Tags
- sphere
- volume
- four_thirds_factor
Topic
Volume
Card Id
FC12
Difficulty
hard
Image Prompt
Find the slope of the line passing through points (2, 3) and (6, 11).
Formula: m = (y₂ - y₁)/(x₂ - x₁) Step 1: Identify points → (x₁,y₁) = (2,3), (x₂,y₂) = (6,11) Step 2: Substitute → m = (11 - 3)/(6 - 2) Step 3: Calculate → m = 8/4 = 2 Slope = 2 (line rises 2 units for every 1 unit right) Answer: m = 2
Tags
- slope
- two_points
- rise_over_run
Topic
Equation of a Line
Card Id
FC13
Difficulty
medium
Image Prompt
Write the equation of a line with slope 3 and y-intercept -2.
Use slope-intercept form: y = mx + b Step 1: Identify values → m = 3, b = -2 Step 2: Substitute → y = 3x + (-2) Step 3: Simplify → y = 3x - 2 This line passes through (0, -2) and rises 3 units per 1 unit right Answer: y = 3x - 2
Tags
- slope_intercept_form
- y_intercept
- linear_equation
Topic
Equation of a Line
Card Id
FC14
Difficulty
easy
Image Prompt
Find the equation of a line passing through (1, 4) with slope 2.
Use point-slope form: y - y₁ = m(x - x₁) Step 1: Identify values → (x₁,y₁) = (1,4), m = 2 Step 2: Substitute → y - 4 = 2(x - 1) Step 3: Expand → y - 4 = 2x - 2 Step 4: Solve for y → y = 2x + 2 Answer: y = 2x + 2
Tags
- point_slope_form
- given_point
- algebraic_manipulation
Topic
Equation of a Line
Card Id
FC15
Difficulty
medium
Image Prompt
Convert 3x + 2y = 12 to slope-intercept form.
Goal: Get y = mx + b form Step 1: Start with 3x + 2y = 12 Step 2: Subtract 3x from both sides → 2y = -3x + 12 Step 3: Divide by 2 → y = -3x/2 + 6 Step 4: Simplify → y = -1.5x + 6 Slope = -1.5, y-intercept = 6 Answer: y = -1.5x + 6
Tags
- standard_to_slope_intercept
- algebraic_manipulation
- form_conversion
Topic
Equation of a Line
Card Id
FC16
Difficulty
medium
Image Prompt
Are the lines y = 2x + 3 and y = 2x - 1 parallel, perpendicular, or neither?
Compare slopes: Line 1: y = 2x + 3 → slope = 2 Line 2: y = 2x - 1 → slope = 2 Since m₁ = m₂ = 2, the slopes are equal Rule: Parallel lines have equal slopes Answer: Parallel
Tags
- parallel_lines
- slope_comparison
- line_relationships
Topic
Equation of a Line
Card Id
FC17
Difficulty
easy
Image Prompt
Find the slope of a line perpendicular to y = 3x + 5.
Step 1: Find slope of given line → m₁ = 3 Step 2: Use perpendicular rule → m₁ × m₂ = -1 Step 3: Substitute → 3 × m₂ = -1 Step 4: Solve → m₂ = -1/3 Rule: Perpendicular slopes are negative reciprocals Answer: m = -1/3
Tags
- perpendicular_lines
- negative_reciprocal
- slope_relationship
Topic
Equation of a Line
Card Id
FC18
Difficulty
medium
Image Prompt
A rectangular garden has area 48 m² and width 6 m. Find its perimeter.
Step 1: Find length using A = lw 48 = l × 6 → l = 48/6 = 8 m Step 2: Calculate perimeter using P = 2(l + w) P = 2(8 + 6) = 2(14) = 28 m Step 3: Check: Area = 8 × 6 = 48 ✓ Answer: 28 m
Tags
- area_to_perimeter
- rectangle
- multi_step
Topic
Mixed Problems
Card Id
FC19
Difficulty
medium
Image Prompt
When do you use the formula V = ⅓πr²h and what does each variable represent?
Use for: Volume of a cone When: You have a circular base tapering to a point Variables: • V = volume (cubic units) • r = radius of circular base • h = height from base to apex • ⅓ factor distinguishes cone from cylinder Example: Cone with r=4, h=9 → V = ⅓π(16)(9) = 48π Answer: Cone volume formula
Tags
- cone_volume
- formula_meaning
- when_to_use
Topic
Formula Application
Card Id
FC20
Difficulty
medium
Image Prompt
Tag Distribution
Easy
6
Hard
1
Medium
12
Problem Solving
20
Basic Calculation
4
Formula Application
8
Topic Distribution
Area
4
Volume
5
Perimeter
3
Mixed Problems
1
Equation Of A Line
6
Formula Application
1
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