Civil Service Exam (Subprofessional) Numerical Ability — Algebra, Exponents & Number SeriesFlash Cards
If you only have 15 minutes a day for Algebra, Exponents & Number Series in the lead-up to the Civil Service Exam (Subprofessional), spend them on these flashcards. CSC rewards reviewers who can recall a fact without a cue — that's what flashcards train, and this deck is built around exactly the cues Civil Service Exam (Subprofessional) papers usually supply.
Exam context
Civil Service Commission (CSC) runs the Career Service Examination — Subprofessional Level on Bi-annual — March and August 2026. Its Numerical Ability section sits under a "~25% weightage" weighting, and Algebra, Exponents & Number Series is the 5th chapter in the 9-chapter Civil Service Exam (Subprofessional) Numerical Ability rotation. The Civil Service Exam (Subprofessional) passing mark is 80%, and the most recent 2026 paper drew about 17 questions from Numerical Ability.
Algebra, Exponents & Number Series - Flashcards
Master the essential concepts of algebra, exponents, and number series with these comprehensive flashcards. These cards cover fundamental algebraic operations, laws of exponents, and pattern recognition in number sequences - key skills for success in Philippine civil service exams and college entrance tests like UPCAT, NMAT, and ACET.
Cards
What is the Product Rule for exponents and how do you apply it?
The Product Rule states that when multiplying two exponents with the same base, you keep the base and add the powers: a^m × a^n = a^(m+n). Example: 5^3 × 5^2 = 5^(3+2) = 5^5. This rule works for any real numbers m and n, including negative exponents.
Tags
- product_rule
- exponent_operations
- intermediate
Topic
Laws of Exponents
Card Id
FC1
Difficulty
intermediate
Image Prompt
Quotient Rule
The Quotient Rule for exponents: When dividing two exponents with the same base, keep the base and subtract the powers: a^m ÷ a^n = a^(m-n). Example: 10^5 ÷ 10^3 = 10^(5-3) = 10^2 = 100. This helps avoid negative exponents by putting the answer in the appropriate position.
Tags
- definition
- quotient_rule
- basic
Topic
Laws of Exponents
Card Id
FC2
Difficulty
basic
Image Prompt
What happens when you raise a power to another power?
Use the Power Rule: (a^m)^n = a^(mn). Multiply the exponents together. Example: (2^3)^4 = 2^(3×4) = 2^12 = 4,096. Another example: Express 8^3 as a power with base 2: Since 8 = 2^3, then 8^3 = (2^3)^3 = 2^9.
Tags
- power_rule
- exponent_operations
- intermediate
Topic
Laws of Exponents
Card Id
FC3
Difficulty
intermediate
Image Prompt
Zero-Exponent Rule
Any non-zero number raised to the power of zero equals 1: a^0 = 1 (where a ≠ 0). Examples: 5^0 = 1, (-3)^0 = 1, (999)^0 = 1. This rule is fundamental for simplifying expressions and solving equations.
Tags
- definition
- zero_exponent
- basic
Topic
Laws of Exponents
Card Id
FC4
Difficulty
basic
Image Prompt
How do you handle negative exponents?
Negative Exponent Rule: a^(-m) = 1/a^m. A negative exponent means take the reciprocal and make the exponent positive. Example: 2^(-2) = 1/2^2 = 1/4. For fractions: (3/4)^(-2) = (4/3)^2 = 16/9.
Tags
- negative_exponents
- reciprocal
- intermediate
Topic
Laws of Exponents
Card Id
FC5
Difficulty
intermediate
Image Prompt
Fractional Exponent Rule
Fractional exponents represent roots: a^(1/n) = ⁿ√a. The denominator of the fraction becomes the index of the root. Example: 4^(1/2) = √4 = 2, 8^(1/3) = ∛8 = 2. For a^(m/n) = ⁿ√(a^m) or (ⁿ√a)^m.
Tags
- definition
- fractional_exponents
- advanced
Topic
Laws of Exponents
Card Id
FC6
Difficulty
advanced
Image Prompt
What are the 6 steps for simplifying exponential expressions?
1. Apply Product Rule (add exponents with same base) 2. Apply Quotient Rule (subtract exponents) 3. Apply Power Rule (multiply exponents) 4. Apply Zero-Exponent Rule (anything^0 = 1) 5. Apply Negative Exponent Rule (move to opposite position) 6. Simplify coefficients and reduce fractions
Tags
- process
- systematic_approach
- intermediate
Topic
Simplifying Expressions
Card Id
FC7
Difficulty
intermediate
Image Prompt
Arithmetic Sequence
A sequence where the difference between consecutive terms is constant. Formula for nth term: aₙ = a₁ + (n-1)d, where a₁ is the first term, d is the common difference, and n is the term number. Example: 2, 5, 8, 11, 14... has d = 3.
Tags
- definition
- arithmetic_sequence
- basic
Topic
Number Series
Card Id
FC8
Difficulty
basic
Image Prompt
How do you identify and continue a geometric sequence?
Geometric Sequence: Each term is obtained by multiplying the previous term by a constant ratio (r). Formula: aₙ = a₁ × r^(n-1). Example: 3, 6, 12, 24, 48... has r = 2. To find the next term, multiply the last term by the common ratio: 48 × 2 = 96.
Tags
- geometric_sequence
- pattern_recognition
- intermediate
Topic
Number Series
Card Id
FC9
Difficulty
intermediate
Image Prompt
What characterizes a Fibonacci sequence?
Fibonacci Sequence: Each term is the sum of the two preceding terms. Pattern: aₙ = aₙ₋₁ + aₙ₋₂. Example: 1, 1, 2, 3, 5, 8, 13, 21... where 1+1=2, 1+2=3, 2+3=5, etc. This pattern appears frequently in nature and mathematics.
Tags
- fibonacci
- sum_pattern
- intermediate
Topic
Number Series
Card Id
FC10
Difficulty
intermediate
Image Prompt
Solve: 8x⁵/4x² = ?
Apply the quotient rule and simplify coefficients: 8x⁵/4x² = (8/4) × (x⁵/x²) = 2 × x⁵⁻² = 2x³ Always separate coefficients from variables and apply exponent rules to each part.
Tags
- application
- quotient_rule
- basic
Topic
Algebraic Simplification
Card Id
FC11
Difficulty
basic
Image Prompt
What is an exponent sequence and how do you recognize it?
Exponent Sequence: All terms are perfect powers (squares, cubes, etc.). Two types: 1. Perfect squares: 4, 9, 16, 25, 36, 49... (2², 3², 4², 5², 6², 7²...) 2. Perfect cubes: 8, 64, 216, 512, 1000... (2³, 4³, 6³, 8³, 10³...) Look for patterns in the base numbers or exponents.
Tags
- exponent_sequence
- perfect_powers
- intermediate
Topic
Number Series
Card Id
FC12
Difficulty
intermediate
Image Prompt
Compare arithmetic and geometric sequences
Arithmetic Sequence: - Constant difference between terms - Linear growth pattern - Formula: aₙ = a₁ + (n-1)d - Example: 5, 8, 11, 14... Geometric Sequence: - Constant ratio between terms - Exponential growth/decay - Formula: aₙ = a₁ × r^(n-1) - Example: 5, 10, 20, 40...
Tags
- comparison
- sequence_types
- intermediate
Topic
Number Series
Card Id
FC13
Difficulty
intermediate
Image Prompt
In the sequence 3, 8, 15, 24, 35, ?, what's the pattern and next term?
This is an alternating sequence. Find the differences: 8-3=5, 15-8=7, 24-15=9, 35-24=11 The differences form: 5, 7, 9, 11... (increasing by 2 each time) Next difference: 11+2=13 Next term: 35+13=48
Tags
- application
- alternating_sequence
- advanced
Topic
Number Series
Card Id
FC14
Difficulty
advanced
Image Prompt
What is a mixed sequence in number series?
Mixed Sequence: Uses multiple arithmetic operations in a pattern. Example: 10, 22, 46, 94, 190, ? Pattern: multiply by 2, then add 2 10×2+2=22, 22×2+2=46, 46×2+2=94, 94×2+2=190, 190×2+2=382 These sequences require identifying the combination of operations used.
Tags
- mixed_sequence
- multiple_operations
- advanced
Topic
Number Series
Card Id
FC15
Difficulty
advanced
Image Prompt
Simplify: (3x²y⁻²)(4xy³)
Multiply coefficients and apply product rule for exponents: (3x²y⁻²)(4xy³) = (3×4)(x²×x¹)(y⁻²×y³) = 12x²⁺¹y⁻²⁺³ = 12x³y¹ = 12x³y Remember: when multiplying with same base, add the exponents.
Tags
- application
- product_rule
- intermediate
Topic
Algebraic Operations
Card Id
FC16
Difficulty
intermediate
Image Prompt
What is a two-stage sequence?
Two-Stage Sequence: The differences between consecutive terms form their own pattern (arithmetic or geometric). Example: 1, 3, 5, 9, 11 - missing terms can be found by analyzing that differences should be 2, 2, 4, 2, following a pattern. First find the pattern in differences, then fill in missing terms.
Tags
- two_stage_sequence
- difference_patterns
- advanced
Topic
Number Series
Card Id
FC17
Difficulty
advanced
Image Prompt
Evaluate: 2⁻³ × 2⁵ ÷ 2¹
Apply exponent rules step by step: 2⁻³ × 2⁵ ÷ 2¹ = 2⁻³⁺⁵⁻¹ = 2¹ = 2 Alternatively: 2⁻³ × 2⁵ = 2² = 4, then 4 ÷ 2¹ = 4 ÷ 2 = 2 Both methods give the same answer.
Tags
- application
- multiple_operations
- intermediate
Topic
Exponent Calculations
Card Id
FC18
Difficulty
intermediate
Image Prompt
Combination Sequence
Combination Sequence: Uses elements from different sequence types (like alternating between operations). Example: 3, 3, 3, 6, 3, 9, 3, 12... Pattern: Odd positions stay constant (3), even positions increase by 3 (3, 6, 9, 12...) This combines constant and arithmetic patterns.
Tags
- definition
- combination_sequence
- advanced
Topic
Number Series
Card Id
FC19
Difficulty
advanced
Image Prompt
What are the key strategies for solving number series problems?
1. Look for constant differences (arithmetic) 2. Check for constant ratios (geometric) 3. Examine if terms are perfect powers 4. Try sum patterns (Fibonacci-type) 5. Look for alternating patterns 6. Check differences between differences 7. Consider mixed operations 8. Identify if it's a combination sequence Always verify your pattern with given terms before finding the answer.
Tags
- strategy
- systematic_approach
- intermediate
Topic
Problem-Solving Strategies
Card Id
FC20
Difficulty
intermediate
Image Prompt
Tag Distribution
Basic
4
Advanced
6
Strategy
1
Comparison
1
Definition
5
Application
4
Intermediate
10
Topic Distribution
Number Series
8
Laws Of Exponents
6
Algebraic Operations
2
Problem Solving Strategies
4
Previous chapter
Ratio, Proportion & Percentage
Next chapter
Word Problems — Speed/Distance/Age, Discount & Interest
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