Civil Service Exam (Subprofessional) Numerical Ability — Algebra, Exponents & Number SeriesStudy Notes
Thorough study notes for Algebra, Exponents & Number Series — the fastest path from zero to ready for Civil Service Exam (Subprofessional) Numerical Ability. Structured for self-study reviewers who cannot attend a review centre, these notes cover the full concept library plus the Civil Service Exam (Subprofessional)-specific twists Civil Service Commission (CSC) adds to its questions.
Exam context
The Career Service Examination — Subprofessional Level is conducted by Civil Service Commission (CSC) and is scheduled for Bi-annual — March and August 2026. The Numerical Ability subtest is marked as "~25% weightage" in the official pattern, and Algebra, Exponents & Number Series appears in position 5th of 9 in the Civil Service Exam (Subprofessional) Numerical Ability review rotation. Passing mark: 80%. Recent Civil Service Exam (Subprofessional) 2026 papers have drawn roughly 17 questions from this subject.
Algebra, Exponents & Number Series - Study notes
This chapter covers three fundamental topics in numerical ability: algebra, exponents, and number series. These concepts are essential for civil service examinations and other competitive tests in the Philippines. Understanding algebraic operations, mastering the laws of exponents, and recognizing patterns in number series will help you solve problems efficiently and accurately.
Summary
Mastering algebra, exponents, and number series requires understanding fundamental principles and practicing pattern recognition. Algebra provides tools for working with unknown quantities through variables and equations. The laws of exponents simplify complex calculations involving powers. Number series develop logical thinking and pattern recognition skills essential for competitive examinations. Regular practice with these concepts will improve your numerical ability and problem-solving efficiency in academic and professional settings.
Sections
Algebra is the branch of mathematics that uses letters and symbols to represent numbers and quantities in formulas and equations. In algebra, we work with variables (like x, y, a, b) that can represent unknown values or changing quantities. Understanding how to translate words into algebraic expressions and manipulate these expressions is crucial for problem-solving.
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Algebra Fundamentals
Examples
- Translating 'a number increased by 25' becomes x + 25
- Translating 'ten decreased by a number' becomes 10 - x
- Simplifying 3x + 5x = 8x (combining like terms)
- Solving 2x + 13 = 37: subtract 13 from both sides, then divide by 2 to get x = 12
Key Points
- Variables represent unknown numbers or quantities
- Algebraic expressions combine numbers, variables, and operations
- Equations show that two expressions are equal
- The order of operations (PEMDAS) applies to algebraic expressions
- Like terms can be combined by adding or subtracting coefficients
Mathematical operations follow specific properties that help us manipulate expressions and solve equations. The commutative property allows us to change the order of addition or multiplication. The associative property lets us change the grouping of operations. The distributive property shows how multiplication distributes over addition or subtraction.
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Properties of Numbers and Operations
Examples
- Commutative: 5 + 7 = 7 + 5 = 12
- Associative: (2 + 3) + 4 = 2 + (3 + 4) = 9
- Distributive: 3(4 + 5) = 3(4) + 3(5) = 12 + 15 = 27
- Using properties to simplify: 2x + 3x + 5 = 5x + 5
Key Points
- Commutative Property: a + b = b + a and a × b = b × a
- Associative Property: (a + b) + c = a + (b + c) and (a × b) × c = a × (b × c)
- Distributive Property: a(b + c) = ab + ac
- Identity Property: a + 0 = a and a × 1 = a
- Additive inverse: a + (-a) = 0
- Multiplicative inverse: a × (1/a) = 1
Exponents represent repeated multiplication of a number by itself. The laws of exponents provide rules for simplifying expressions with powers. These rules are essential for solving complex algebraic problems efficiently. Understanding these laws helps in calculations involving scientific notation, compound interest, and geometric progressions.
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Laws of Exponents
Examples
- Product Rule: 5^3 × 5^2 = 5^(3+2) = 5^5
- Quotient Rule: 10^5 ÷ 10^3 = 10^(5-3) = 10^2 = 100
- Power Rule: (2^3)^4 = 2^(3×4) = 2^12
- Zero Exponent: 7^0 = 1
- Negative Exponent: 2^(-3) = 1/2^3 = 1/8
- Fractional Exponent: 4^(1/2) = √4 = 2
Key Points
- Product Rule: a^m × a^n = a^(m+n)
- Quotient Rule: a^m ÷ a^n = a^(m-n)
- Power Rule: (a^m)^n = a^(mn)
- Zero Exponent Rule: a^0 = 1 (where a ≠ 0)
- Negative Exponent Rule: a^(-m) = 1/a^m
- Fractional Exponent Rule: a^(1/n) = nth root of a
A number series is a sequence of numbers that follows a specific pattern or rule. Identifying patterns in number series is a crucial skill for competitive examinations. Understanding different types of sequences helps in predicting the next term or finding missing terms in a series.
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Number Series and Sequences
Examples
- Arithmetic: 3, 7, 11, 15, 19 (difference = 4)
- Geometric: 2, 6, 18, 54, 162 (ratio = 3)
- Fibonacci: 1, 1, 2, 3, 5, 8, 13 (each term = sum of previous two)
- Square: 1, 4, 9, 16, 25 (1², 2², 3², 4², 5²)
- Mixed: 5, 7, 21, 55, 117 (pattern: add squares minus 2)
Key Points
- Arithmetic Sequence: constant difference between consecutive terms
- Geometric Sequence: constant ratio between consecutive terms
- Fibonacci Sequence: each term is the sum of two preceding terms
- Square/Cube Sequences: terms are perfect squares or cubes
- Mixed Sequences: combine multiple operations or patterns
- Alternating Sequences: terms follow different sub-patterns
Effective problem-solving in algebra, exponents, and number series requires systematic approaches. Start by identifying what type of problem you're dealing with, then apply the appropriate rules or formulas. For word problems, translate the language into mathematical expressions. For number series, look for patterns by examining differences, ratios, or relationships between terms.
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Problem-Solving Strategies
Examples
- Word problem: 'A number increased by 15 equals 37' → x + 15 = 37, so x = 22
- Exponent simplification: (8x³y⁴z⁶)/(4x²y³z⁵) = 2xyz
- Series pattern: 2, 4, 7, 11, 16, ? → differences are 2, 3, 4, 5, so next difference is 6, answer is 22
- Complex expression: 8 + 4 × (6 ÷ 2) = 8 + 4 × 3 = 8 + 12 = 20
Key Points
- Read problems carefully and identify key information
- Translate word problems into algebraic expressions
- Use PEMDAS order of operations consistently
- Check your work by substituting answers back into original equations
- For series, examine differences between consecutive terms
- Look for multiple patterns in complex sequences
Previous chapter
Ratio, Proportion & Percentage
Next chapter
Word Problems — Speed/Distance/Age, Discount & Interest
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