Civil Service Exam (Subprofessional) Numerical Ability — Algebra, Exponents & Number SeriesExam Answer Templates
Exam answer templates for Algebra, Exponents & Number Series in Civil Service Exam (Subprofessional) Numerical Ability. These are the response frameworks that consistently earn full marks on Civil Service Commission (CSC)'s questions. Each template is tuned to a specific question type — learn them all and your Civil Service Exam (Subprofessional) 2026 performance will reflect it.
Exam context
Civil Service Commission (CSC) runs the Career Service Examination — Subprofessional Level on Bi-annual — March and August 2026. Its Numerical Ability section sits under a "~25% weightage" weighting, and Algebra, Exponents & Number Series is the 5th chapter in the 9-chapter Civil Service Exam (Subprofessional) Numerical Ability rotation. The Civil Service Exam (Subprofessional) passing mark is 80%, and the most recent 2026 paper drew about 17 questions from Numerical Ability.
Algebra, Exponents & Number Series - Exam answer templates
Proper answer writing is crucial for maximizing your scores in Civil Service examinations and college entrance tests. These templates show you exactly how to structure your answers to earn full marks. Each template demonstrates the precise format, key terms, and step-by-step approach that examiners expect. Following these patterns will help you write clear, complete answers that demonstrate your understanding while meeting all marking criteria.
Templates
Simplify: 3^4 × 3^2
Marks
2
Topic
Laws of Exponents - Product Rule
Difficulty
easy
Template Id
T1
Examiner Tip
Always write the exponent law you're using - this shows you understand the concept, not just memorized calculations
Model Answer
Given: 3^4 × 3^2 Using the Product Rule for exponents: a^m × a^n = a^(m+n) 3^4 × 3^2 = 3^(4+2) = 3^6 = 729 Therefore, 3^4 × 3^2 = 729
Question Type
short_answer
Answer Structure
- Line 1: State the given expression [0.5 marks]
- Line 2: Apply the correct exponent law [1 mark]
- Line 3: Calculate the final answer [0.5 marks]
Scoring Breakdown
Marks
1
Criteria
Correctly applies product rule of exponents
Marks
1
Criteria
Arrives at correct final answer
Common Mark Deductions
- Not showing the rule used
- Arithmetic errors in final calculation
- Not stating the final answer clearly
Key Phrases To Include
- Product Rule
- a^m × a^n = a^(m+n)
- final answer
Find the next term in the series: 2, 5, 8, 11, 14, ?
Marks
3
Topic
Number Series - Arithmetic Sequence
Difficulty
easy
Template Id
T2
Examiner Tip
Always show the pattern-finding process explicitly - don't just state the answer
Model Answer
Given series: 2, 5, 8, 11, 14, ? Step 1: Find the pattern 5 - 2 = 3 8 - 5 = 3 11 - 8 = 3 14 - 11 = 3 Step 2: Identify the sequence type This is an arithmetic sequence with common difference d = 3 Step 3: Find the next term Next term = 14 + 3 = 17 Therefore, the next term is 17.
Question Type
short_answer
Answer Structure
- Step 1: Calculate differences between consecutive terms [1 mark]
- Step 2: Identify the type of sequence [1 mark]
- Step 3: Apply pattern to find next term [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly identifies the common difference
Marks
1
Criteria
Recognizes it as arithmetic sequence
Marks
1
Criteria
Calculates correct next term
Common Mark Deductions
- Not showing difference calculations
- Incorrect identification of sequence type
- Arithmetic errors
Key Phrases To Include
- arithmetic sequence
- common difference
- pattern
Solve for x: 2^(x+1) = 16
Marks
3
Topic
Exponential Equations
Difficulty
medium
Template Id
T3
Examiner Tip
Always verify your answer by substituting back into the original equation
Model Answer
Given: 2^(x+1) = 16 Step 1: Express 16 as a power of 2 16 = 2^4 Step 2: Rewrite the equation 2^(x+1) = 2^4 Step 3: Since bases are equal, equate exponents x + 1 = 4 x = 4 - 1 x = 3 Verification: 2^(3+1) = 2^4 = 16 ✓ Therefore, x = 3
Question Type
short_answer
Answer Structure
- Step 1: Express the right side as power of same base [1 mark]
- Step 2: Apply the principle that equal bases mean equal exponents [1 mark]
- Step 3: Solve for the variable and verify [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly converts 16 to 2^4
Marks
1
Criteria
Properly equates exponents
Marks
1
Criteria
Solves correctly and shows verification
Common Mark Deductions
- Not converting to same base
- Algebraic errors
- Missing verification step
Key Phrases To Include
- express as power
- equal bases
- verification
Evaluate: (8x^3y^6)/(4x^2y^4)
Marks
2
Topic
Laws of Exponents - Quotient Rule
Difficulty
medium
Template Id
T4
Examiner Tip
Break down complex expressions into manageable parts - coefficients, then each variable separately
Model Answer
Given: (8x^3y^6)/(4x^2y^4) Step 1: Separate coefficients and variables = (8/4) × (x^3/x^2) × (y^6/y^4) Step 2: Apply quotient rule for exponents = 2 × x^(3-2) × y^(6-4) = 2 × x^1 × y^2 = 2xy^2 Therefore, (8x^3y^6)/(4x^2y^4) = 2xy^2
Question Type
short_answer
Answer Structure
- Step 1: Separate numerical and variable parts [1 mark]
- Step 2: Apply quotient rule and simplify [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly applies quotient rule for exponents
Marks
1
Criteria
Simplifies to correct final form
Common Mark Deductions
- Incorrect application of quotient rule
- Arithmetic errors with coefficients
- Not simplifying completely
Key Phrases To Include
- quotient rule
- a^m/a^n = a^(m-n)
- simplify
What is 4^0 + 5^0?
Marks
1
Topic
Laws of Exponents - Zero Exponent Rule
Difficulty
easy
Template Id
T5
Examiner Tip
Remember: any non-zero number to the power 0 always equals 1
Model Answer
4^0 + 5^0 = 1 + 1 = 2 (Any non-zero number raised to power 0 equals 1)
Question Type
very_short_answer
Answer Structure
- Apply zero exponent rule and calculate [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly applies zero exponent rule to get answer 2
Common Mark Deductions
- Not knowing that a^0 = 1
- Arithmetic errors
Key Phrases To Include
- zero exponent rule
- equals 1
Find the missing term in the geometric series: 3, 6, 12, ?, 48
Marks
3
Topic
Number Series - Geometric Sequence
Difficulty
medium
Template Id
T6
Examiner Tip
Always verify your answer fits the pattern by checking it works with surrounding terms
Model Answer
Given series: 3, 6, 12, ?, 48 Step 1: Find the common ratio r = 6/3 = 2 r = 12/6 = 2 Step 2: Verify it's a geometric series Common ratio r = 2 (constant) Step 3: Find the missing term Missing term = 12 × 2 = 24 Verification: 24 × 2 = 48 ✓ Therefore, the missing term is 24.
Question Type
short_answer
Answer Structure
- Step 1: Calculate common ratio from given terms [1 mark]
- Step 2: Confirm geometric sequence pattern [1 mark]
- Step 3: Apply ratio to find missing term [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly identifies common ratio as 2
Marks
1
Criteria
Recognizes geometric sequence pattern
Marks
1
Criteria
Calculates missing term correctly
Common Mark Deductions
- Not identifying the common ratio
- Calculation errors
- Missing verification
Key Phrases To Include
- geometric series
- common ratio
- verification
Simplify: (3^2)^3
Marks
2
Topic
Laws of Exponents - Power Rule
Difficulty
easy
Template Id
T7
Examiner Tip
State the exponent law you're using - it shows conceptual understanding
Model Answer
Given: (3^2)^3 Using Power Rule: (a^m)^n = a^(mn) (3^2)^3 = 3^(2×3) = 3^6 Calculating: 3^6 = 729 Therefore, (3^2)^3 = 729
Question Type
short_answer
Answer Structure
- Apply power rule for exponents [1 mark]
- Calculate final numerical value [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly applies power rule to get 3^6
Marks
1
Criteria
Evaluates 3^6 = 729 correctly
Common Mark Deductions
- Incorrect application of power rule
- Calculation errors
- Not showing the rule
Key Phrases To Include
- Power Rule
- (a^m)^n = a^(mn)
Express 2^(-3) as a positive exponent.
Marks
2
Topic
Laws of Exponents - Negative Exponent Rule
Difficulty
medium
Template Id
T8
Examiner Tip
Always express negative exponents as positive fractions unless specifically asked for decimal form
Model Answer
Given: 2^(-3) Using Negative Exponent Rule: a^(-n) = 1/a^n 2^(-3) = 1/2^3 = 1/8 Therefore, 2^(-3) = 1/8
Question Type
short_answer
Answer Structure
- Apply negative exponent rule [1 mark]
- Calculate final fraction form [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly applies negative exponent rule
Marks
1
Criteria
Calculates 1/8 as final answer
Common Mark Deductions
- Not knowing negative exponent rule
- Arithmetic errors
- Leaving answer as decimal instead of fraction
Key Phrases To Include
- Negative Exponent Rule
- a^(-n) = 1/a^n
Find the 8th term in the arithmetic sequence: 5, 9, 13, 17, ...
Marks
3
Topic
Arithmetic Sequences
Difficulty
medium
Template Id
T9
Examiner Tip
Always state the formula you're using - it demonstrates method knowledge even if calculation errors occur
Model Answer
Given: Arithmetic sequence 5, 9, 13, 17, ... To find: 8th term (a₈) Step 1: Identify first term and common difference a₁ = 5 d = 9 - 5 = 4 Step 2: Use arithmetic sequence formula aₙ = a₁ + (n-1)d a₈ = 5 + (8-1)×4 a₈ = 5 + 7×4 a₈ = 5 + 28 a₈ = 33 Therefore, the 8th term is 33.
Question Type
short_answer
Answer Structure
- Step 1: Identify first term and common difference [1 mark]
- Step 2: Apply arithmetic sequence formula [1 mark]
- Step 3: Calculate final answer [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly identifies a₁ = 5 and d = 4
Marks
1
Criteria
Uses correct formula aₙ = a₁ + (n-1)d
Marks
1
Criteria
Calculates a₈ = 33 correctly
Common Mark Deductions
- Wrong common difference calculation
- Formula errors
- Arithmetic mistakes
Key Phrases To Include
- arithmetic sequence
- common difference
- formula aₙ = a₁ + (n-1)d
Solve: x³ = 27
Marks
1
Topic
Basic Exponential Equations
Difficulty
easy
Template Id
T10
Examiner Tip
Memorize perfect cubes up to 10³ for quick recognition
Model Answer
x³ = 27 x = ∛27 = 3 Therefore, x = 3
Question Type
very_short_answer
Answer Structure
- Take cube root of both sides to find x = 3 [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly finds x = 3 by taking cube root
Common Mark Deductions
- Not recognizing 27 as perfect cube
- Calculation errors
Key Phrases To Include
- cube root
- ∛27 = 3
Find the pattern and next two terms: 1, 4, 9, 16, 25, ?, ?
Marks
3
Topic
Number Series - Perfect Squares
Difficulty
medium
Template Id
T11
Examiner Tip
Look for common mathematical sequences like squares, cubes, or factorial patterns
Model Answer
Given series: 1, 4, 9, 16, 25, ?, ? Step 1: Analyze the pattern 1 = 1² 4 = 2² 9 = 3² 16 = 4² 25 = 5² Step 2: Identify the sequence type This is a perfect squares sequence: n² Step 3: Find next two terms 6² = 36 7² = 49 Therefore, the next two terms are 36 and 49.
Question Type
short_answer
Answer Structure
- Step 1: Express each term as perfect square [1 mark]
- Step 2: Identify pattern as n² sequence [1 mark]
- Step 3: Calculate next two terms [1 mark]
Scoring Breakdown
Marks
1
Criteria
Recognizes each term as a perfect square
Marks
1
Criteria
Identifies pattern as consecutive squares
Marks
1
Criteria
Correctly finds 36 and 49
Common Mark Deductions
- Not recognizing perfect square pattern
- Calculation errors
- Finding only one term instead of two
Key Phrases To Include
- perfect squares
- n² sequence
- pattern
Simplify: 16^(1/4)
Marks
2
Topic
Laws of Exponents - Fractional Exponents
Difficulty
medium
Template Id
T12
Examiner Tip
Remember that fractional exponents represent roots - the denominator tells you which root to take
Model Answer
Given: 16^(1/4) Using Fractional Exponent Rule: a^(1/n) = ⁿ√a 16^(1/4) = ⁴√16 Since 16 = 2⁴, we have: ⁴√16 = ⁴√(2⁴) = 2 Therefore, 16^(1/4) = 2
Question Type
short_answer
Answer Structure
- Apply fractional exponent rule [1 mark]
- Evaluate the fourth root correctly [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly applies fractional exponent rule
Marks
1
Criteria
Evaluates to get final answer 2
Common Mark Deductions
- Not knowing fractional exponent rule
- Incorrect root calculation
- Not recognizing 16 as 2⁴
Key Phrases To Include
- Fractional Exponent Rule
- a^(1/n) = ⁿ√a
- fourth root
Explain the steps to simplify exponential expressions using the laws of exponents. Give an example.
Marks
5
Topic
Complete Laws of Exponents Overview
Difficulty
hard
Template Id
T13
Examiner Tip
Structure your answer with clear headings and always include a worked example to demonstrate application
Model Answer
Steps to Simplify Exponential Expressions: Step 1: Apply Product Rule Multiply terms with same base by adding exponents: aᵐ × aⁿ = aᵐ⁺ⁿ Step 2: Apply Quotient Rule Divide terms with same base by subtracting exponents: aᵐ ÷ aⁿ = aᵐ⁻ⁿ Step 3: Apply Power Rule Raise a power to another power by multiplying exponents: (aᵐ)ⁿ = aᵐⁿ Step 4: Apply Zero Exponent Rule Any non-zero number to power 0 equals 1: a⁰ = 1 Step 5: Apply Negative Exponent Rule Convert negative exponents to positive: a⁻ⁿ = 1/aⁿ Example: Simplify (2³ × 2⁵) ÷ 2⁴ Step 1: 2³ × 2⁵ = 2³⁺⁵ = 2⁸ (Product Rule) Step 2: 2⁸ ÷ 2⁴ = 2⁸⁻⁴ = 2⁴ (Quotient Rule) Step 3: 2⁴ = 16 Therefore, the expression simplifies to 16.
Question Type
long_answer
Answer Structure
- Step 1: Explain Product Rule with formula [1 mark]
- Step 2: Explain Quotient Rule with formula [1 mark]
- Step 3: Explain Power Rule with formula [1 mark]
- Step 4: Explain Zero and Negative Exponent Rules [1 mark]
- Step 5: Provide complete worked example [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly states Product Rule
Marks
1
Criteria
Correctly states Quotient Rule
Marks
1
Criteria
Correctly states Power Rule
Marks
1
Criteria
States Zero and Negative Exponent Rules
Marks
1
Criteria
Provides correct worked example
Common Mark Deductions
- Missing any of the five rules
- Incorrect formulas
- Poor or missing example
- Not showing step-by-step solution
Key Phrases To Include
- Product Rule
- Quotient Rule
- Power Rule
- Zero Exponent Rule
- Negative Exponent Rule
- worked example
Find the sum of first 6 terms of the geometric series: 2, 6, 18, 54, ...
Marks
5
Topic
Geometric Series - Sum Formula
Difficulty
hard
Template Id
T14
Examiner Tip
Always verify your common ratio with at least two consecutive pairs before proceeding
Model Answer
Given: Geometric series 2, 6, 18, 54, ... To find: Sum of first 6 terms (S₆) Step 1: Identify first term and common ratio a₁ = 2 r = 6/2 = 3 Step 2: Verify common ratio 18/6 = 3 ✓ 54/18 = 3 ✓ Step 3: Find the 5th and 6th terms a₅ = 2 × 3⁴ = 2 × 81 = 162 a₆ = 2 × 3⁵ = 2 × 243 = 486 Step 4: Use geometric series sum formula Sₙ = a₁(rⁿ - 1)/(r - 1) S₆ = 2(3⁶ - 1)/(3 - 1) S₆ = 2(729 - 1)/2 S₆ = 2(728)/2 S₆ = 728 Therefore, the sum of first 6 terms is 728.
Question Type
long_answer
Answer Structure
- Step 1: Identify first term and common ratio [1 mark]
- Step 2: Verify the common ratio [1 mark]
- Step 3: Find remaining terms if needed [1 mark]
- Step 4: Apply geometric series sum formula [1 mark]
- Step 5: Calculate final answer correctly [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly identifies a₁ = 2 and r = 3
Marks
1
Criteria
Verifies common ratio is consistent
Marks
1
Criteria
Uses correct geometric series sum formula
Marks
1
Criteria
Substitutes values correctly into formula
Marks
1
Criteria
Calculates final sum as 728
Common Mark Deductions
- Wrong common ratio
- Using wrong formula
- Calculation errors
- Not verifying the ratio
Key Phrases To Include
- geometric series
- common ratio
- sum formula Sₙ = a₁(rⁿ - 1)/(r - 1)
- verification
Identify the type of sequence and find the general term: 1/2, 1/4, 1/8, 1/16, ...
Marks
3
Topic
Sequence Identification and General Terms
Difficulty
medium
Template Id
T15
Examiner Tip
For geometric sequences, always express the general term in its simplest form
Model Answer
Given sequence: 1/2, 1/4, 1/8, 1/16, ... Step 1: Find the pattern (1/4)/(1/2) = 1/2 (1/8)/(1/4) = 1/2 (1/16)/(1/8) = 1/2 Step 2: Identify sequence type This is a geometric sequence with: a₁ = 1/2 r = 1/2 Step 3: Find general term For geometric sequence: aₙ = a₁ × rⁿ⁻¹ aₙ = (1/2) × (1/2)ⁿ⁻¹ aₙ = (1/2)ⁿ aₙ = 1/2ⁿ Therefore, this is a geometric sequence with general term aₙ = 1/2ⁿ
Question Type
short_answer
Answer Structure
- Step 1: Calculate ratios to find pattern [1 mark]
- Step 2: Identify as geometric sequence [1 mark]
- Step 3: Derive general term formula [1 mark]
Scoring Breakdown
Marks
1
Criteria
Correctly identifies common ratio as 1/2
Marks
1
Criteria
Recognizes geometric sequence pattern
Marks
1
Criteria
Derives correct general term aₙ = 1/2ⁿ
Common Mark Deductions
- Not identifying sequence type
- Wrong common ratio
- Incorrect general term formula
Key Phrases To Include
- geometric sequence
- common ratio
- general term
- aₙ = a₁ × rⁿ⁻¹
Mark Wise Strategy
Dos
- State the rule/formula if applicable
- Give a clear final answer
- Show one key step if needed
Donts
- Over-explain simple concepts
- Show unnecessary working
- Leave answer unclear
Marks
1
Strategy
Direct application of a single concept or rule. Show minimal working but ensure accuracy.
Expected Length
1-2 lines
Time Allocation
30 seconds to 1 minute
Dos
- State what rule you're using
- Show the key calculation step
- Present final answer clearly
Donts
- Skip the method/rule
- Make careless arithmetic errors
- Forget to state the final answer
Marks
2
Strategy
Apply one main concept with clear working. Show method and arrive at correct answer.
Expected Length
3-4 lines
Time Allocation
1-2 minutes
Dos
- Break into logical steps
- Show all working clearly
- Verify answer when possible
- Label steps appropriately
Donts
- Jump steps without explanation
- Mix up different concepts
- Forget intermediate calculations
Marks
3
Strategy
Multi-step solution requiring 2-3 concepts. Show clear progression from given to answer.
Expected Length
4-6 lines
Time Allocation
2-3 minutes
Dos
- Use clear headings/structure
- Provide complete explanations
- Include worked examples
- Cover all required points
- Show mastery of topic
Donts
- Rush through explanations
- Miss key concepts
- Provide incomplete examples
- Write without structure
Marks
5
Strategy
Comprehensive answer covering multiple concepts or detailed explanation with examples.
Expected Length
8-12 lines
Time Allocation
4-6 minutes
General Answer Writing Tips
- Always show your work step-by-step for numerical problems - partial credit is often given for correct methods
- Use proper mathematical notation and symbols - this demonstrates technical proficiency
- State the given information clearly at the beginning of your answer
- Circle or box your final answer to make it easily identifiable
- For exponent problems, apply laws systematically and show each step
- In number series questions, identify the pattern first, then explain your reasoning
- Use clear headings like 'Given:', 'To Find:', and 'Solution:' for organized presentation
- Double-check your arithmetic calculations before writing the final answer
Previous chapter
Ratio, Proportion & Percentage
Next chapter
Word Problems — Speed/Distance/Age, Discount & Interest
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