Civil Service Exam (Subprofessional) Numerical Ability — Ratio, Proportion & PercentageFlash Cards
Flashcards specifically for Ratio, Proportion & Percentage in the Civil Service Exam (Subprofessional) 2026. Every card has been tuned to match Civil Service Commission (CSC)'s preferred question style. Practise them during your commute, at lunch, or before bed — they are designed for short bursts of high-retention review.
Exam context
Civil Service Commission (CSC) runs the Career Service Examination — Subprofessional Level on Bi-annual — March and August 2026. Its Numerical Ability section sits under a "~25% weightage" weighting, and Ratio, Proportion & Percentage is the 4th chapter in the 9-chapter Civil Service Exam (Subprofessional) Numerical Ability rotation. The Civil Service Exam (Subprofessional) passing mark is 80%, and the most recent 2026 paper drew about 17 questions from Numerical Ability.
Ratio, Proportion & Percentage - Flashcards
Master the fundamental concepts of ratios, proportions, and percentages with these comprehensive flashcards. These cards cover key definitions, formulas, problem-solving strategies, and real-world applications essential for Philippine entrance exams like UPCAT, CSE, and other standardized tests.
Cards
What is a ratio and how is it expressed?
A ratio is a relationship between two numbers or quantities that compares their sizes. It can be expressed in three ways: 1) Using colon notation (3:4), 2) Using fraction form (3/4), and 3) Using words ('3 to 4'). Example: If there are 15 boys and 10 girls in a class, the ratio of boys to girls is 15:10 or 3:2.
Tags
- concept_type:definition
- topic_area:ratio
- difficulty_level:easy
Topic
Basic Definitions
Card Id
FC1
Difficulty
easy
Image Prompt
What is a proportion and when are two ratios proportional?
A proportion states that two ratios are equal. Two ratios are proportional if their cross products are equal. For ratios a:b and c:d, they are proportional if a×d = b×c. Example: 5:10 and 3:6 are proportional because 5×6 = 10×3 = 30.
Tags
- concept_type:definition
- topic_area:proportion
- difficulty_level:easy
Topic
Basic Definitions
Card Id
FC2
Difficulty
easy
Image Prompt
Define percentage and explain its relationship to fractions and decimals.
Percentage means 'per hundred' and is expressed with the % symbol. It represents a fraction with denominator 100. Conversions: 1) Fraction to %: multiply by 100, 2) Decimal to %: multiply by 100, 3) % to decimal: divide by 100. Example: 3/4 = 0.75 = 75%.
Tags
- concept_type:definition
- topic_area:percentage
- difficulty_level:easy
Topic
Basic Definitions
Card Id
FC3
Difficulty
easy
Image Prompt
How do you solve for an unknown term in a proportion using cross multiplication?
Step 1: Set up the proportion (a:b = c:x). Step 2: Cross multiply (a×x = b×c). Step 3: Solve for x (x = bc/a). Example: Find x in 5:x = 3:9. Cross multiply: 3x = 5×9 = 45. Therefore, x = 45/3 = 15.
Tags
- concept_type:procedure
- topic_area:proportion
- difficulty_level:medium
Topic
Problem Solving Techniques
Card Id
FC4
Difficulty
medium
Image Prompt
What is the formula for finding a percentage of a number?
Formula: Percentage of a number = (Rate/100) × Base. Where Rate is the percentage value, and Base is the whole amount. Example: Find 25% of 200. Solution: (25/100) × 200 = 0.25 × 200 = 50.
Tags
- concept_type:formula
- topic_area:percentage
- difficulty_level:medium
Topic
Percentage Calculations
Card Id
FC5
Difficulty
medium
Image Prompt
How do you find what percentage one number is of another?
Formula: Rate = (Part/Whole) × 100%. Steps: 1) Identify the part and whole, 2) Divide part by whole, 3) Multiply by 100. Example: 150 out of 250 students are female. Rate = (150/250) × 100% = 0.6 × 100% = 60%.
Tags
- concept_type:procedure
- topic_area:percentage
- difficulty_level:medium
Topic
Finding Rate
Card Id
FC6
Difficulty
medium
Image Prompt
How do you find the original price when given a discounted price and discount rate?
Formula: Original Price = Discounted Price ÷ (100% - Discount Rate). Steps: 1) Convert discount rate to decimal, 2) Subtract from 1, 3) Divide discounted price by result. Example: Item costs ₱1,200 after 20% discount. Original = 1,200 ÷ (1 - 0.20) = 1,200 ÷ 0.80 = ₱1,500.
Tags
- concept_type:procedure
- topic_area:percentage
- difficulty_level:hard
Topic
Finding Base
Card Id
FC7
Difficulty
hard
Image Prompt
In a school of 500 students, the ratio of boys to girls is 3:2. How many boys and girls are there?
Step 1: Total ratio parts = 3 + 2 = 5. Step 2: Each part = 500 ÷ 5 = 100 students. Step 3: Boys = 3 × 100 = 300, Girls = 2 × 100 = 200. Verification: 300 + 200 = 500 ✓.
Tags
- concept_type:application
- topic_area:ratio
- difficulty_level:medium
Topic
Real-world Applications
Card Id
FC8
Difficulty
medium
Image Prompt
A shirt originally costs ₱800 but is sold at 25% discount. What is the sale price?
Method 1: Discount amount = 25% × ₱800 = 0.25 × 800 = ₱200. Sale price = ₱800 - ₱200 = ₱600. Method 2: Sale price = 800 × (100% - 25%) = 800 × 0.75 = ₱600.
Tags
- concept_type:application
- topic_area:percentage
- difficulty_level:medium
Topic
Discount Problems
Card Id
FC9
Difficulty
medium
Image Prompt
If a product is marked up by 30% from its cost price of ₱200, what is the selling price?
Markup amount = 30% × ₱200 = 0.30 × 200 = ₱60. Selling price = Cost price + Markup = ₱200 + ₱60 = ₱260. Alternative: Selling price = 200 × (100% + 30%) = 200 × 1.30 = ₱260.
Tags
- concept_type:application
- topic_area:percentage
- difficulty_level:medium
Topic
Markup and Profit
Card Id
FC10
Difficulty
medium
Image Prompt
What is the formula for calculating profit percentage?
Profit % = (Selling Price - Cost Price) / Cost Price × 100%. Example: Item bought for ₱500, sold for ₱650. Profit = ₱650 - ₱500 = ₱150. Profit % = (150/500) × 100% = 30%.
Tags
- concept_type:formula
- topic_area:percentage
- difficulty_level:medium
Topic
Profit and Loss
Card Id
FC11
Difficulty
medium
Image Prompt
A car depreciates by 15% each year. If it's worth ₱500,000 initially, what's its value after depreciation?
Depreciated value = Original value × (100% - Depreciation rate) = ₱500,000 × (100% - 15%) = ₱500,000 × 0.85 = ₱425,000. The car loses ₱75,000 in value.
Tags
- concept_type:application
- topic_area:percentage
- difficulty_level:medium
Topic
Depreciation
Card Id
FC12
Difficulty
medium
Image Prompt
How do you calculate tax on a purchase?
Total amount = Original price × (100% + Tax rate). Example: Item costs ₱1,000 with 12% VAT. Tax amount = ₱1,000 × 0.12 = ₱120. Total = ₱1,000 + ₱120 = ₱1,120. Or directly: ₱1,000 × 1.12 = ₱1,120.
Tags
- concept_type:procedure
- topic_area:percentage
- difficulty_level:medium
Topic
Tax Calculations
Card Id
FC13
Difficulty
medium
Image Prompt
Compare direct proportion and inverse proportion.
Direct Proportion: When one quantity increases, the other increases proportionally (y = kx). Example: More workers, more output. Inverse Proportion: When one quantity increases, the other decreases proportionally (xy = k). Example: More speed, less time for same distance.
Tags
- concept_type:comparison
- topic_area:proportion
- difficulty_level:medium
Topic
Types of Proportions
Card Id
FC14
Difficulty
medium
Image Prompt
A recipe calls for flour and sugar in ratio 4:1. If you use 200g flour, how much sugar is needed?
Set up proportion: 4:1 = 200:x. Cross multiply: 4x = 1 × 200 = 200. Solve: x = 200/4 = 50g. Therefore, 50g of sugar is needed for 200g of flour.
Tags
- concept_type:application
- topic_area:ratio
- difficulty_level:easy
Topic
Recipe and Mixture Problems
Card Id
FC15
Difficulty
easy
Image Prompt
If 5 machines can produce 100 items in 2 hours, how many items can 8 machines produce in 3 hours?
Step 1: Find rate per machine per hour = 100 ÷ (5 × 2) = 10 items/machine/hour. Step 2: Calculate for 8 machines in 3 hours = 8 × 3 × 10 = 240 items. Or use proportion: (5×2):100 = (8×3):x, so x = 240.
Tags
- concept_type:application
- topic_area:proportion
- difficulty_level:hard
Topic
Work and Time Problems
Card Id
FC16
Difficulty
hard
Image Prompt
What is the difference between markup and margin?
Markup: Percentage added to cost price. Formula: (Selling Price - Cost Price) / Cost Price × 100%. Margin: Percentage of selling price that is profit. Formula: (Selling Price - Cost Price) / Selling Price × 100%. Same profit amount, different base for calculation.
Tags
- concept_type:comparison
- topic_area:percentage
- difficulty_level:hard
Topic
Business Applications
Card Id
FC17
Difficulty
hard
Image Prompt
In a mixture of 60L, juice and water are in ratio 2:3. How much water should be added to make ratio 1:2?
Current: Juice = 24L, Water = 36L (from 2:3 ratio). Target ratio 1:2 means water = 2 × juice = 2 × 24 = 48L. Additional water needed = 48 - 36 = 12L.
Tags
- concept_type:application
- topic_area:ratio
- difficulty_level:hard
Topic
Mixture Problems
Card Id
FC18
Difficulty
hard
Image Prompt
Express the ratio 1.5:2.5:3.5 in simplest form.
Method: Multiply all terms by 10 to eliminate decimals: 15:25:35. Find GCD of 15, 25, 35 = 5. Divide by GCD: 15÷5:25÷5:35÷5 = 3:5:7. Therefore, simplest form is 3:5:7.
Tags
- concept_type:procedure
- topic_area:ratio
- difficulty_level:medium
Topic
Simplifying Ratios
Card Id
FC19
Difficulty
medium
Image Prompt
A student scored 85% on a test with 40 questions. How many questions were answered correctly?
Questions answered correctly = 85% × 40 = 0.85 × 40 = 34 questions. Verification: 34 out of 40 = 34/40 = 0.85 = 85% ✓. The student answered 34 questions correctly and got 6 wrong.
Tags
- concept_type:application
- topic_area:percentage
- difficulty_level:easy
Topic
Academic Applications
Card Id
FC20
Difficulty
easy
Image Prompt
Tag Distribution
Topic Area
Ratio
7
Percentage
9
Proportion
4
Concept Type
Formula
2
Procedure
5
Comparison
2
Definition
3
Application
8
Difficulty Level
Easy
4
Hard
4
Medium
12
Topic Distribution
Depreciation
1
Finding Base
1
Finding Rate
1
Profit And Loss
1
Mixture Problems
1
Tax Calculations
1
Basic Definitions
3
Discount Problems
1
Markup And Profit
1
Simplifying Ratios
1
Types Of Proportions
1
Academic Applications
1
Business Applications
1
Work And Time Problems
1
Percentage Calculations
1
Real World Applications
1
Problem Solving Techniques
1
Recipe And Mixture Problems
1
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