CELE Steel & Timber Design — Steel Tension MembersSummary
Think of this page as the pre-read for your CELE Steel & Timber Design session on Steel Tension Members. PRC has built Steel Tension Members questions around a stable set of concepts across the last a meaningful share of items on recent papers, and this summary lays those concepts out in the order you should tackle them during self-study.
Exam context
Professional Regulation Commission (PRC) — Board of Civil Engineering runs the Civil Engineer Licensure Examination on May and November 2026. Its Steel & Timber Design section sits under a "Core" weighting, and Steel Tension Members is the 1st chapter in the 5-chapter CELE Steel & Timber Design rotation. The CELE passing mark is 70% weighted average, no sub-test below 50%, and the most recent 2026 paper drew about a meaningful share of questions from Steel & Timber Design.
Steel Tension Members - Summary
Steel tension members are among the simplest structural elements in civil engineering design, yet they are critical in frameworks, trusses, bracing systems, and hangers. Unlike compression or flexural members, tension members experience uniform axial stress with no buckling concerns. However, the presence of bolt holes introduces stress concentrations and reduced cross-sectional area, creating two distinct failure modes that must both be evaluated under NSCP 2015 and AISC 360-16 standards. This chapter equips reviewees with the analytical tools and practical procedures to design and verify tension members under LRFD and ASD methodologies, incorporating the essential concepts of gross area yielding, net area rupture, shear-lag reduction, and slenderness limits.
Key Concepts
The full cross-sectional area of the tension member before accounting for holes. For a rectangular plate, Ag = width × thickness; for rolled shapes (angle, channel), Ag is tabulated in steel manuals. This area is used in the yielding limit state. Example: a 200 mm × 12 mm plate has Ag = 2400 mm².
Concept
Gross Section Area (Ag)
Importance
Essential for calculating yield strength; the higher allowable stress (Fy) is applied to the full gross area, making this the 'optimistic' scenario. Yielding is ductile and provides warning before failure.
The effective cross-sectional area after subtracting the area of bolt holes. The hole diameter used in calculation is NOT the bolt diameter, but the bolt diameter plus a standard clearance (typically 2–3 mm to account for punching tolerance and clearance hole practice). NSCP 2015 and AISC 360 generally use dh = db + 2 mm or local practices up to +3 mm. Formula: An = Ag − Σ(dh × t), where dh is hole diameter and t is material thickness. Example: Two 20 mm bolts (dh = 22 mm) in a 12 mm plate: subtraction = 2 × 22 × 12 = 528 mm², so An = 2400 − 528 = 1872 mm².
Concept
Net Area (An) and Hole Allowance
Importance
Critical to the rupture limit state. Net area governs when Fy·Ag is large relative to Fu·Ae. Forgetting hole allowance is a common exam error—always add 2–3 mm to bolt diameter.
When holes are arranged in multiple lines and staggered (offset longitudinally), the failure path may zigzag through the plate rather than straight across. For each diagonal segment, add the term s²/(4g) to the net width, where s is the longitudinal pitch (spacing along the member axis) and g is the transverse gage (perpendicular spacing between hole lines). The net width becomes: Wnet = Wg − Σdh + Σ[s²/(4g)]. This accounts for the fact that the zig-zag path is longer and the material has more 'effective width' than a straight cut. Example: Two staggered hole lines, pitch s = 50 mm, gage g = 75 mm: s²/(4g) = 2500/(300) = 8.33 mm added per diagonal; a 200 mm plate with 2 holes becomes 200 − 44 + 8.33 = 164.33 mm net.
Concept
Staggered Bolt Holes and Zig-Zag Failure Paths
Importance
Essential for realistic net-area calculation in multi-hole arrangements. Ignoring stagger artificially reduces capacity; exam problems often include staggered holes to test this understanding.
Not all parts of a cross-section may be equally effective in transmitting the tensile load, especially when only some elements (e.g., one leg of an angle) are connected. The effective net area is Ae = U·An, where U ≤ 1 is the shear-lag reduction factor. U = 1.0 when the entire cross-section is connected (e.g., a plate bolted across its full width, or a rolled shape bolted through the web and both flanges). U < 1.0 applies to angles bolted through one leg only, channels bolted through the web only, or tees bolted through the stem. AISC 360 and NSCP 2015 provide U-factor tables; common values are U = 0.85 for an angle connected by one leg, U = 0.80 for a channel connected by the web.
Concept
Effective Net Area (Ae) and Shear-Lag Factor (U)
Importance
The rupture check uses Ae, not An. Applying U = 1.0 when shear lag exists is unsafe and a frequent exam mistake. Always verify which elements are bolted.
The member reaches yield when the tensile stress equals Fy across the entire gross section. The nominal strength is Pn = Fy·Ag. This is a ductile failure mode (member deforms visibly before fracture). Under LRFD (NSCP 2015), the design strength is φt·Pn = 0.90·Fy·Ag. Under ASD, the allowable strength is Pn/Ωt = Fy·Ag / 1.67. Yielding produces a lower nominal strength (Fy < Fu) but applies to the full area (Ag > Ae), and the higher safety factor (φ = 0.90 vs. 0.75) reflects the ductile nature.
Concept
Tensile Yielding Limit State
Importance
One of two limit states that must be checked. The governing (lower) design strength controls. Yielding is always checked first; if it governs, rupture is less critical but must still be verified for completeness.
The member fails by fracture when the tensile stress reaches Fu (ultimate/tensile strength) across the net effective section. The nominal strength is Pn = Fu·Ae. This is a sudden, brittle failure with little warning. Under LRFD, the design strength is φt·Pn = 0.75·Fu·Ae. Under ASD, the allowable strength is Pn/Ωt = Fu·Ae / 2.00. The lower φ-factor (0.75) reflects the sudden nature and stress concentration at holes; the higher stress (Fu) and reduced area (Ae) both increase the nominal value, but the lower φ combines with Ae to create a 'conservative' scenario.
Concept
Tensile Rupture Limit State
Importance
The governing limit state in many practical cases, especially when holes are present. Always calculate both yield and rupture, then use the lower design strength. Forgetting rupture or misapplying φ-factors is a common error.
LRFD requires φt·Pn ≥ Pu (factored load). Calculate Pn for both yielding and rupture, apply the appropriate φ-factor to each, and take the minimum. The governing state is the one with the lower design strength. Example: Plate with Fy = 248 MPa, Fu = 400 MPa, Ag = 2400 mm², Ae = 1872 mm². Yield: 0.90 × 248 × 2400 = 535.68 kN. Rupture: 0.75 × 400 × 1872 = 561.6 kN. Governing = 535.68 kN (yield governs because it is lower). Design rule: φt·Pn = min(0.90·Fy·Ag, 0.75·Fu·Ae). ASD uses the same logic with safety factors instead of φ.
Concept
Two-State Design Process and Load Comparison
Importance
The core analytical framework of the chapter. Reviewees must understand that we check both states and use the minimum. Confusion about which state governs is a frequent exam pitfall.
LRFD (Load and Resistance Factor Design, used in NSCP 2015) applies a resistance factor φ to reduce nominal strength: Design Strength = φ·Pn. For tension members, φt = 0.90 for yielding (ductile, predictable) and φt = 0.75 for rupture (sudden, stress-concentrated). ASD (Allowable Stress Design) applies a safety factor Ω to divide nominal strength by a factor: Allowable Strength = Pn/Ω. For yielding, Ωt = 1.67; for rupture, Ωt = 2.00. These reflect the confidence and ductility of each failure mode. Higher φ (or lower Ω) = greater confidence; lower φ (or higher Ω) = greater uncertainty.
Concept
φ-Factors in LRFD and Ω-Factors in ASD
Importance
Critical for correct calculations. Exam questions often specify LRFD or ASD; using the wrong factor gives a wrong answer. φ = 0.90 vs. 0.75 is the most common mistake in rupture checks.
Although tension members do not fail by buckling (no Euler instability), NSCP 2015 and AISC 360 recommend limiting the slenderness ratio L/r ≤ 300 to avoid excessive vibration, sag, or deflection under dynamic loads. L is the unbraced length and r is the minimum radius of gyration. For a circular rod, r = d/4 (where d is diameter). Example: 4 m rod with r = 25 mm → L/r = 4000/25 = 160 < 300 ✓. This is NOT a strength check; it is a serviceability and practical recommendation. The recommendation is less stringent for short, stiff members.
Concept
Slenderness Ratio (L/r) and Vibration/Sag Recommendation
Importance
Often overlooked by reviewees because tension members have no buckling limit, but the exam may ask whether a slender rod 'satisfies code' — you must check L/r ≤ 300 as a secondary criterion. Not mandatory, but important for practical design.
At a bolted connection, the material around the bolt group can fail in shear along one or more planes before net-section rupture occurs. Block shear involves a combination of shear rupture along one plane and tension rupture (or yielding) along a perpendicular plane. The nominal block-shear strength is Pn = 0.6·Fu·Anv + U_bs·Fy·Agt (or 0.6·Fy·Avg + U_bs·Fu·Ant, whichever is lower), where Anv is the net shear area, Agt is the gross tension area, and U_bs is a factor. Although detailed block-shear analysis is beyond this summary, reviewees must recognize that it is checked in connection design and can govern in some cases.
Concept
Block Shear Failure
Importance
A third limit state beyond gross and net tension. Block shear is tested in advanced problems and in connection design; it often controls when bolt groups are closely spaced or when few bolts engage the tension plane.
NSCP 2015 Section 5.3.6 (Bolted Connections) and AISC 360-16 Section J3.2 specify that the hole diameter for design is 1.5 times the bolt diameter for standard holes, or the nominal bolt diameter plus 2 mm for design purposes in common practice. Philippine practice often uses dh = db + 2 to 3 mm. This accounts for punching tolerance (±1–2 mm) and the standard clearance (1–1.5 mm) between bolt and hole. Using the bolt diameter directly is unconservative and violates code.
Concept
Hole Allowance Practice in NSCP 2015 and AISC 360
Importance
A procedural detail that is frequently tested in calculations. Always add the clearance; the exam often includes a problem to catch those who neglect it.
Important Points
- Always check BOTH limit states (yield and rupture) and take the LOWER design strength as governing.
- Use the hole allowance (dh = db + 2–3 mm), not the bolt diameter alone, when calculating net area. This is a frequent exam error.
- For staggered holes, the net width is reduced by hole area but increased by the stagger term s²/(4g) for each diagonal path segment. The zig-zag path is longer, so material is regained.
- The shear-lag factor U ≤ 1.0 applies when not all elements are connected (e.g., angle bolted through one leg). U = 1.0 only for fully connected sections (plate bolted across full width, or shape bolted through all elements).
- LRFD φ-factors: φ = 0.90 (yield, ductile) and φ = 0.75 (rupture, sudden). ASD Ω-factors: Ω = 1.67 (yield) and Ω = 2.00 (rupture). Mixing these factors is a critical error.
- Rupture strength uses Fu (higher stress, ~400 MPa for Grade 250 steel) on Ae (reduced by holes); yielding uses Fy (lower stress, ~248 MPa) on Ag. Each can govern depending on the proportion of holes.
- Slenderness L/r ≤ 300 is recommended for vibration/sag control, not a strength requirement. Tension members do not buckle; this is a serviceability check.
- Block shear failure is a potential third limit state at connections; in truss and bracing connections, it must be verified alongside tension rupture.
- The governing design strength is the MINIMUM of yield and rupture after applying appropriate φ or Ω factors. The state with the lower design strength controls the member capacity.
- For design (sizing), solve for Ag or Ae given the required Pu, then select a standard section. For verification (given section), calculate both design strengths and compare to Pu.
Chapter Objectives
- Understand the two critical limit states for steel tension members: gross-section yielding and net-section rupture
- Calculate net area accounting for bolt holes and staggered hole patterns using the proper hole allowance
- Apply the shear-lag factor (U-factor) to determine effective net area for various connection configurations
- Perform tensile strength calculations using both LRFD (with φ-factors 0.90 and 0.75) and ASD (with Ω-factors 1.67 and 2.00) approaches
- Evaluate slenderness ratio recommendations and their role in limiting vibration and sag in tension members
- Solve board-style design and verification problems involving plates, angles, channels, and composite sections
- Assess block shear failure at connections and understand its role in overall member capacity
- Apply NSCP 2015 and AISC 360-16 requirements in professional licensure exam contexts
Concept Relationships
Concept Pair
- Gross Area Yielding
- Net Area Rupture
Relationship
These are the two competing limit states. Yielding uses Fy·Ag (full area, lower stress); rupture uses Fu·Ae (reduced area, higher stress). Which governs depends on the ratio of holes to material. A heavily perforated member may be rupture-governed; a minimally perforated one is usually yield-governed. Both must be calculated to find the true design strength.
Practical Example
A 200×12 mm plate with two 20 mm bolts: Fy·Ag = 248×2400 = 595.2 kN (nominal), Fu·Ae = 400×1872 = 748.8 kN (nominal). After φ-factors: 0.90×595.2 = 535.7 kN (yield governs) vs. 0.75×748.8 = 561.6 kN (rupture). Yield controls the design at 535.7 kN.
Concept Pair
- Hole Allowance
- Net Area Calculation
Relationship
The hole allowance (dh = db + 2–3 mm) is added to the bolt diameter to account for punching tolerance and clearance. This increase in hole size reduces the net area more than using the bolt diameter alone. A 2–3 mm error per hole compounds in multi-hole sections; for three bolts, that is 6–9 mm of error in total subtraction.
Practical Example
Three 24 mm bolts: using db only (dh = 24 mm) vs. proper allowance (dh = 26 mm). Subtraction difference = 3×(26−24)×t = 6t mm². For a 12 mm plate, that is 72 mm² or ~2% error in net area—significant for capacity.
Concept Pair
- Stagger Pitch and Gage
- Effective Net Width
Relationship
Staggered holes increase the effective net width (and thus net area) because the failure path must zigzag, traveling a longer distance. The gain per diagonal is s²/(4g). Larger pitch (s) increases the gain; larger gage (g) decreases it. This relationship allows the engineer to optimize hole placement for maximum net area.
Practical Example
Two hole lines, s = 60 mm, g = 80 mm vs. s = 40 mm, g = 80 mm. Gain 1: 3600/(320) = 11.25 mm. Gain 2: 1600/(320) = 5 mm. Increased pitch improves capacity by allowing a longer zig-zag path.
Concept Pair
- Shear-Lag Factor (U)
- Connection Type and Effective Net Area
Relationship
The U-factor accounts for the fact that not all parts of a section transmit stress equally. An angle bolted through one leg, with the other leg unconnected, has U < 1.0 because stress must 'lag' or redistribute through shear from the connected leg to the unconnected leg. The reduction factor U depends on the connection pattern and is provided in tables. Ae = U·An means that even a section with good net area (An) can have a low effective net area if U is small.
Practical Example
L 75×75×8 angle: Ag = 1150 mm². If connected by one leg only with U = 0.85, and net area An = 1050 mm², then Ae = 0.85×1050 = 892.5 mm² (about 78% of Ag). A fully connected angle with U = 1.0 and same An would have Ae = 1050 mm².
Concept Pair
- φ-Factor and Failure Mode Ductility
- Design Safety Philosophy
Relationship
The φ-factor reflects the predictability and ductility of the failure mode. Yielding (φ = 0.90) is ductile and occurs gradually, giving warning; the higher φ reflects greater confidence. Rupture (φ = 0.75) is sudden and occurs at stress concentrations (holes); the lower φ reflects greater uncertainty. This philosophical approach is central to LRFD: ductile, predictable failures get higher φ; sudden, brittle failures get lower φ.
Practical Example
A member that yields first: Fy·Ag·0.90 governs. The member deforms, construction stops, engineer can repair it. A member that ruptures suddenly: Fu·Ae·0.75 governs, with lower φ to prevent the sudden fracture that could cause collapse.
Concept Pair
- Slenderness Ratio L/r
- Member Stiffness and Serviceability
Relationship
L/r is a dimensionless ratio of unbraced length to stiffness. Higher L/r indicates a slender, flexible member prone to vibration and sag under dynamic loads. The recommendation L/r ≤ 300 ensures adequate stiffness. This is NOT a strength criterion (tension members do not buckle) but rather a serviceability and practical limit to prevent annoying oscillations or visible deflection.
Practical Example
A 6 m diagonal tie rod with d = 16 mm (r ≈ 4 mm): L/r = 6000/4 = 1500, far exceeding 300. The rod would sag visibly and vibrate. Using d = 20 mm (r ≈ 5 mm) gives L/r = 1200, still poor. A larger section or intermediate support is needed.
Practical Applications
In roof or floor trusses, the horizontal tie members (bottom chord) carry tensile forces that tie together the truss legs and prevent them from spreading. These are typically bolted at the joints. The engineer must check both yield and rupture on the net area through the bolt group. The design procedure: (1) estimate load from structural analysis, (2) assume a section size, (3) calculate Ag and An (with hole allowance), (4) check φt·Pn = min(0.90 Fy Ag, 0.75 Fu Ae) ≥ Pu. If capacity is insufficient, increase section size or add bolts (which may reduce net area if holes dominate).
Application
Truss Tie Members in Building Frames
Real World Context
In Philippine commercial buildings, the National Building Code (NBC, which references NSCP) requires that all structural components be designed to resist seismic loads in addition to gravity. Truss ties must carry not only sustained loads but also dynamic tension from wind and earthquakes, making the rupture check critical.
Bracing members (diagonals, K-braces, V-braces) and sag rods (which suspend piping or equipment) are tension members. Sag rods are often small-diameter round rods or angles. The design follows the same two-state approach, but slenderness is a concern because a slender rod under cyclic load (vibration) can fail by fatigue or excessive deflection. The L/r ≤ 300 recommendation is particularly important for sag rods in mechanical systems.
Application
Bracing and Sag Rods
Real World Context
In industrial piping systems common in Philippine refineries and chemical plants, sag rods suspending heavy pipe must be designed for static weight plus vibration damping. A slender rod (L/r > 300) would oscillate excessively, leading to wear and fatigue failure at welds.
Hangers for suspended floors, mezzanines, or equipment racks are tension members. They may be threaded rods, flat bars, or angles. The design is governed by axial tension, but the designer must also consider the stress concentration at the threads (for threaded rods) or at the bolted ends (for bars and angles). The effective area Ae may be significantly less than Ag due to threading or limited connection.
Application
Hangers and Suspension Systems
Real World Context
Multi-story commercial buildings in Manila often use suspended mezzanine platforms hung from above by steel rods or bars. RA 544 (Architecture Law) requires structural safety calculations; designers must verify that hangers do not rupture and that they do not sag excessively (L/r ≤ 300).
When designing or checking a bolted joint in a tension member, the designer calculates the net area through the bolt group, applies the shear-lag factor U (which depends on connection geometry), and verifies the rupture strength. Block shear is also checked if the bolt pattern is compact. The position and spacing of bolts affect both An and U; staggered bolts can improve the net area if the stagger is sufficient.
Application
Bolted Joint Design and Verification
Real World Context
In Philippine steel fabrication shops, a structural detailer prepares bolt patterns for shop drawings. They must calculate the net area for verification and ensure that the design strength (0.75 Fu Ae) exceeds the applied factored load. A mistake here can result in connection failure during erection or service.
Under NSCP 2015 seismic provisions, bracing members in special moment-resisting frames or concentrically braced frames carry large tension forces during earthquakes. These members must be ductile and capable of large inelastic deformations. The tension design strength is checked, and detailing requirements (bolt spacing, edge distance) are applied to ensure ductility. The shear-lag factor is carefully evaluated because incomplete connections reduce effectiveness.
Application
Design of Tension Members for Seismic Bracing
Real World Context
Seismic design is mandatory in the Philippines (NSCP 2015, based on ASCE 7 and IBC). Buildings in Metro Manila, Cebu, and other seismic zones require bracing members designed to yield in tension while maintaining ductility. Rupture of bracing members during an earthquake would be catastrophic; hence the careful checking of both limit states.
When designing a tension member, the engineer selects from available sections: plates, angles, channels, double angles, or built-up sections. For each, Ag is known (from tables or calculation) and Ae is calculated with the appropriate U-factor. The design strength is min(0.90 Fy Ag, 0.75 Fu Ae). The engineer adjusts the section size until design strength meets the required capacity. This process is iterative and often uses spreadsheets or design software.
Application
Cold-Formed and Hot-Rolled Section Selection
Real World Context
Philippine steel structural companies maintain inventory of hot-rolled angles, channels, and I-beams per ASTM A36 or local equivalent. For a given tension load, the designer quickly estimates the required Ag, selects a trial section from tables, calculates Ae with bolting details, checks both limit states, and accepts or rejects the section.
In summary
Steel tension members are fundamental components in structural frameworks, trusses, bracing systems, and suspension structures throughout the Philippines and worldwide. The modern design approach, codified in NSCP 2015 and AISC 360-16, requires evaluation of two distinct limit states: tensile yielding on the gross section (ductile, predictable) and tensile rupture on the net effective section (sudden, at stress concentrations). The engineer must calculate both design strengths, apply the appropriate resistance factors (φ = 0.90 for yield, φ = 0.75 for rupture in LRFD), and use the lower value as the governing design strength. Accurate calculation of net area—accounting for bolt hole allowances (dh = db + 2–3 mm), staggered hole paths (s²/4g), and shear-lag reduction (U ≤ 1.0)—is essential to avoid unsafe or overly conservative designs. Secondary considerations include slenderness limits (L/r ≤ 300 for vibration control) and block shear verification at multi-bolt connections. The design workflow is iterative: assume a section, calculate Ag and Ae, check both limit states, verify that the minimum design strength exceeds the factored load, and confirm serviceability. Mastery of this two-state philosophy, the correct application of φ-factors and U-factors, and the proper treatment of holes in net-area calculation are critical for success on the PRC Civil Engineer Licensure Examination and in professional practice. The examples and procedures outlined in this chapter provide the foundation for designing safe, economical, and code-compliant tension members in buildings, bridges, industrial structures, and other applications across the Philippine construction industry.
Next steps
To consolidate understanding of steel tension members and prepare for the PRC Licensure Examination, reviewees should: (1) Work through 10–15 board-style practice problems covering simple plates, angles, and composite sections with various hole configurations; (2) Solve at least 5 problems each for yield-governed, rupture-governed, and 'both critical' scenarios to build intuition for which state dominates; (3) Practice calculating net area with staggered holes, emphasizing the s²/4g term and the importance of identifying the critical zigzag path; (4) Verify several multi-bolt connections using provided U-factor tables and compare effective areas to gross areas to understand shear-lag effects; (5) Review past PRC examination questions on tension members (typically 2–3 problems per exam) and analyze the solutions to identify common traps (wrong φ-factor, forgetting hole allowance, omitting rupture check); (6) Study connection details and block shear calculations in NSCP 2015 Section 5 and AISC 360 Chapter J to understand how tension members are actually joined and verified in practice; (7) Develop a personal checklist for tension member design that includes section selection, Ag calculation, hole enumeration and dh assignment, An calculation with stagger gain, U-factor determination, Ae calculation, yield check, rupture check, governing state selection, Pu comparison, L/r verification, and block shear verification if applicable; (8) Discuss case studies of actual tension member failures (historical or from professional literature) to appreciate the consequences of design errors; (9) Finally, perform 5 full design exercises starting from a given load, selecting trial sections, iterating until capacity is adequate, and documenting the design in report form. These activities will develop the fluency and confidence needed to tackle any tension member problem on the licensure examination and in professional design practice.
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