CELE Steel & Timber Design — Steel Tension MembersMemory Anchors
Under the clock, Steel Tension Members facts fade unless they have a hook. Mnemonics are the hook. This page collects the memory anchors that reliably work for Filipino CELE candidates on Professional Regulation Commission (PRC) — Board of Civil Engineering's Steel & Timber Design items — acronyms, visual pairings, and short rhymes you can rehearse on your commute.
Exam context
For the Civil Engineer Licensure Examination, Professional Regulation Commission (PRC) — Board of Civil Engineering tests Steel & Timber Design under a "Core" label, with Steel Tension Members in the 1st slot across 5 chapters. CELE candidates must clear the 70% weighted average, no sub-test below 50% cut on the 2026 paper, which draws about a meaningful share of Steel & Timber Design questions. Date to watch: May and November 2026.
Steel Tension Members - Memory Anchors
Memory anchors are cognitive shortcuts that transform abstract formulas and code provisions into vivid, unforgettable mental images. Research in cognitive science shows that linking new information to emotionally charged stories, familiar analogies, or absurd visuals can increase long-term recall by up to 60% compared to rote repetition. For the PRC Civil Engineer Licensure Examination, where a single formula error can cost you the board, these anchors are your insurance policy. Each anchor below is designed to fire a specific neural pathway — so when you see 'tensile rupture' on the exam, your brain instantly retrieves φ = 0.75, not 0.90. Work through each anchor, visualize it clearly, and test yourself using the recall triggers. The goal: every concept in Steel Tension Members becomes as automatic as your own name.
Anchors
Tags
- formula
- definition
- classification
Topic
Two Limit States
Concept
Two Limit States: Yielding (φ = 0.90) and Rupture (φ = 0.75)
Anchor Id
A1
Difficulty
easy
Memory Aid
Imagine a barako coffee vendor named YIELDO who is very chill and generous — he gives you 90% of his brew (φ = 0.90). His rival RUPTURA is stingy and unpredictable — she only gives 75% (φ = 0.75) and sometimes cracks her cups. Yieldo uses the full pot (Ag, gross area); Ruptura uses a cracked pot (Ae, effective net area, because holes). Always order from the CHEAPER vendor — the one who gives LESS coffee governs your design.
Anchor Type
micro_story
Why It Works
The contrasting characters (generous Yieldo vs. stingy Ruptura) encode both the φ values and which area to use. The 'governing' principle (lower value controls) is embedded in 'order from the cheaper vendor.'
Example Usage
Exam asks: 'Which φ for tensile rupture?' → Think Ruptura is stingy → φ = 0.75. 'Which area?' → Ruptura uses a cracked pot → Ae (net effective area).
Recall Trigger
Think of two coffee vendors: Yieldo (90%) vs. Ruptura (75%)
Tags
- formula
- definition
Topic
Tensile Yielding
Concept
Yielding formula: φPn = 0.90 Fy Ag
Anchor Id
A2
Difficulty
easy
Memory Aid
YO-FA-G: Y = Yield, 0 = 0.90, F = Fy, A = Ag, G = Gross. Say it fast: 'YO-FAG!' Like a referee blowing the whistle — 'YO! F-A-G!' φ = 0.90 × Fy × Ag. The GROSS area (Ag) is the WHOLE section before any holes are cut.
Anchor Type
mnemonic
Why It Works
The acronym YO-FAG is short, punchy, and phonetically distinct. The referee image adds emotional intensity. Gross = whole = no holes is a simple logical extension.
Example Usage
Computing yield capacity: φPn = 0.90 × Fy × Ag. Recall YO-FAG → 0.90, Fy, Ag. Plug and compute.
Recall Trigger
YO-FAG for yielding
Tags
- formula
- definition
Topic
Tensile Rupture
Concept
Rupture formula: φPn = 0.75 Fu Ae
Anchor Id
A3
Difficulty
easy
Memory Aid
RUFA-E: R = Rupture, U = 0.75 (think 3/4 — rupture is three-quarters), F = Fu (ultimate), A = Ae (effective net). Pronounce it 'ROO-FAH-EH!' like a Filipina aunt who is 3/4 full of energy. She works on an EFFECTIVE area (Ae) — because holes have already been punched through her patience.
Anchor Type
mnemonic
Why It Works
RUFA-E as a name is culturally familiar and easy to vocalize. The 3/4 fraction maps naturally to 0.75. The 'effective area' concept is reinforced by the 'holes punched through' image.
Example Usage
For rupture: φPn = 0.75 × Fu × Ae. Recall RUFA-E → 0.75, Fu, Ae. Don't forget Ae = U × An.
Recall Trigger
Tita RUFA-E is 3/4 energized
Tags
- process
- definition
Topic
Governing Limit State
Concept
Governing limit state: lower design strength controls
Anchor Id
A4
Difficulty
easy
Memory Aid
A chain is only as strong as its WEAKEST LINK. Your body can handle 100 kg pressure on your back (yield), but one surgical cut (rupture) at a weak point and the whole system fails at a much lower load. In steel tension members, two failure modes compete — the LOWER φPn is the one that actually limits the member. The member fails via whichever mode is easier to trigger.
Anchor Type
analogy
Why It Works
The chain analogy is a universal cognitive anchor for 'weakest link' reasoning. The surgical cut makes the 'rupture at a reduced section' concept visceral and memorable.
Example Usage
After computing both φPn (yield) and φPn (rupture), circle the smaller value — that is the design tensile strength of the member.
Recall Trigger
Weakest link in the chain
Tags
- formula
- process
Topic
Net Area Calculation
Concept
Net area formula: An = Ag − Σ(dh × t)
Anchor Id
A5
Difficulty
medium
Memory Aid
Imagine a full sheet of pandesal (Ag = whole loaf). Every bolt hole is a bite taken out. Each bite = dh × t (hole diameter × plate thickness). The NET area (An) is what remains after all the bites. If you have staggered holes, the path zig-zags around the bites — each diagonal shortcut ADDS BACK a little area (the s²/4g correction), because a diagonal path is longer than a straight one.
Anchor Type
analogy
Why It Works
Pandesal is a universal Filipino food image. Bites = holes is intuitive. The diagonal shortcut visual maps perfectly to the stagger correction concept.
Example Usage
Gross plate area minus all hole areas: An = Ag − Σ(dh × t). For staggered: add s²/4g per diagonal segment.
Recall Trigger
Pandesal with bite-holes
Tags
- formula
- definition
Topic
Net Area — Hole Allowance
Concept
Hole diameter for design: dh = db + 2 mm (or +3 mm per local practice)
Anchor Id
A6
Difficulty
medium
Memory Aid
The HOLE is bigger than the BOLT — add 2 (or 3), that's the rule you're taught! Bolt diameter plus clearance gap, otherwise your net area's a trap. '2 mm standard, 3 mm local — forgetting this makes your answer comical!'
Anchor Type
rhyme
Why It Works
The rhyme creates a phonetic memory loop. The warning ('trap,' 'comical') creates mild anxiety that heightens retention — a known mnemonic technique.
Example Usage
20 mm bolt → dh = 22 mm (standard) or 23 mm (some local problems). Always use dh, not db, when subtracting hole areas from Ag.
Recall Trigger
Hole = Bolt + 2 (or 3) — the trap
Tags
- formula
- process
Topic
Staggered Holes
Concept
Staggered holes correction: add s²/4g per diagonal path segment
Anchor Id
A7
Difficulty
hard
Memory Aid
Picture a PACMAN game. The straight path across a plate eats one ghost (one hole). But the zig-zag path eats two ghosts (two holes) MINUS a power pellet (the s²/4g bonus). The power pellet gives back area because the diagonal path crosses more material. FORMULA IMAGE: draw an S for stagger (pitch) going sideways and a G for gage going up-down — the ratio is S-squared over 4G, looking like an hourglass tilted sideways.
Anchor Type
visual_association
Why It Works
The PACMAN ghost image encodes 'eating holes' (subtracting) and 'power pellet' encodes the bonus addition. The hourglass visual for s²/4g creates a spatial memory hook.
Example Usage
Zig-zag path through 2 holes, 1 diagonal: net width = Wg − 2dh + (s²/4g). The s²/4g is the power pellet added back.
Recall Trigger
Pacman diagonal path + power pellet bonus
Tags
- formula
- definition
- classification
Topic
Shear Lag and Effective Net Area
Concept
Effective net area: Ae = U × An
Anchor Id
A8
Difficulty
medium
Memory Aid
U is the UTILIZATION factor — how much of the net area is actually pulling its weight. When all parts of the section are connected (like a full-width plate bolted across its entire face), U = 1.0 — 100% participation, every fiber works. When only one leg of an angle is bolted, the unconnected leg is a FREELOADER — it doesn't fully transmit tension, so U < 1.0. The freeloader effect is called SHEAR LAG.
Anchor Type
analogy
Why It Works
The 'freeloader' concept is universally understood and creates mild social humor that sticks. 100% participation vs. freeloader maps cleanly to U = 1.0 vs. U < 1.0.
Example Usage
Angle connected by one leg: Ae = U × An where U = 0.85 (for one bolt) or per AISC 360 Table D3.1. Full plate: Ae = 1.0 × An = An.
Recall Trigger
Freeloader leg = shear lag = U < 1.0
Tags
- definition
- classification
Topic
Shear Lag Factor U
Concept
Shear lag: U = 1.0 only when ALL elements are connected
Anchor Id
A9
Difficulty
medium
Memory Aid
Imagine a barangay tanod team pulling a rope (the tension force). If ALL tanods grip the rope fully (all elements connected), U = 1.0 — full team effort. But if only the front row holds the rope and the back row just watches (one leg of an angle connected, other leg free), the back-row tanods contribute LESS because the force has to shear through the connecting leg to reach them. Their late arrival to the pulling effort is SHEAR LAG. The captain (engineer) multiplies their count by U < 1.0 to account for their lazy participation.
Anchor Type
micro_story
Why It Works
Barangay tanod is culturally familiar to Filipino students. The physical image of rope-pulling and late arrivers perfectly encodes the shear lag phenomenon.
Example Usage
Single-leg angle connection: U < 1.0 per AISC Table D3.1. Never assume U = 1.0 unless the problem states all elements are connected.
Recall Trigger
Lazy back-row tanods = shear lag = U < 1.0
Tags
- definition
- classification
Topic
Slenderness Limit
Concept
Slenderness recommendation: L/r ≤ 300 (not mandatory for rods)
Anchor Id
A10
Difficulty
easy
Memory Aid
Tension members have NO BUCKLING — they're being pulled, not pushed. But a very long, thin member will SAG and VIBRATE annoyingly (like a guitar string that's too loose). The code RECOMMENDS L/r ≤ 300 to prevent excessive sag/vibration. Remember: '300 is the TENSION limit — but it's just a SUGGESTION, not a LAW.' Think '300 Spartans' — they were warriors who CHOSE to stand firm (recommendation), not forced by law. Rods are exempt from even this suggestion.
Anchor Type
mnemonic
Why It Works
300 Spartans is a vivid cultural reference (the film). The 'suggestion not law' framing correctly encodes the non-mandatory nature of the limit. Guitar string sag is a physical sensation.
Example Usage
Check: L/r = 4000/25 = 160 < 300 ✓ — satisfies recommendation. Note: this is not a strength check; it is a serviceability guideline.
Recall Trigger
300 Spartans = L/r ≤ 300 recommendation
Tags
- process
- sequence
Topic
Design Procedure
Concept
Both limit states MUST be checked — don't skip one
Anchor Id
A11
Difficulty
easy
Memory Aid
Cardo, a CE board reviewer, only computed yielding and got 535 kN. He thought 'that's fine, I'm done.' In the exam, the answer was 535 kN (yielding governed) — he got it right BY ACCIDENT. But in the next problem, rupture governed at 420 kN and he wrote 510 kN (yield only). FAILED that item. Moral: ALWAYS compute BOTH. The correct answer is always the MINIMUM of the two. 'Two checks, one answer — always the minimum.'
Anchor Type
micro_story
Why It Works
The story creates a cautionary narrative with a real consequence (failing the board item). The moral sentence is short enough to memorize verbatim.
Example Usage
Step 1: Compute φPn (yield) = 0.90 Fy Ag. Step 2: Compute φPn (rupture) = 0.75 Fu Ae. Step 3: Design strength = min of the two.
Recall Trigger
Cardo's mistake — always compute BOTH
Tags
- formula
- classification
Topic
Phi Factors
Concept
φ = 0.90 for yielding vs. φ = 0.75 for rupture — getting them mixed up
Anchor Id
A12
Difficulty
easy
Memory Aid
YIELDING is like a GRade 90 student — consistent, predictable, near-perfect (φ = 0.90). RUPTURE is like a student who only shows up 75% of the time (φ = 0.75) — unreliable, sudden, and dangerous when absent. The 90-student always uses the FULL notebook (Ag = gross area). The 75-student works on an INCOMPLETE notebook (Ae = net effective area, with pages ripped out for bolt holes).
Anchor Type
visual_association
Why It Works
Grading is universally relatable to students. Mapping 90% grade → φ = 0.90 and 75% grade → φ = 0.75 uses an existing numerical framework in students' long-term memory.
Example Usage
See φ = 0.75 on exam → immediately know: tensile rupture, uses Fu and Ae. See φ = 0.90 → yielding, uses Fy and Ag.
Recall Trigger
90-grader (yield, Ag) vs. 75-attendance (rupture, Ae)
Tags
- definition
- classification
Topic
Material Properties
Concept
Fy (yield stress) is LOWER than Fu (ultimate/tensile stress)
Anchor Id
A13
Difficulty
easy
Memory Aid
Fy and Fu are like a student's normal study effort (Fy = 248 MPa, everyday capacity) vs. their all-out cramming before the board (Fu = 400 MPa, maximum capacity before breakdown). You reach Fy first (yield) — the steel bends but hasn't torn. You reach Fu later (ultimate) — the steel tears apart. 'Y before U in the alphabet, Y before U in stress.' Fy < Fu always.
Anchor Type
analogy
Why It Works
The cramming analogy is highly relatable to board examinees. 'Y before U in alphabet' creates a simple alphabetical ordering rule.
Example Usage
A36 steel: Fy = 248 MPa, Fu = 400 MPa. A572 Gr 50: Fy = 345 MPa, Fu = 448 MPa. Yielding uses Fy (lower), rupture uses Fu (higher but on smaller Ae).
Recall Trigger
Y before U — Fy < Fu always
Tags
- definition
- process
Topic
Block Shear
Concept
Block shear failure mode at connections
Anchor Id
A14
Difficulty
hard
Memory Aid
Picture a halo-halo glass being scooped out — a BLOCK of steel tears out along the bolt group like a rectangular block pulled free. Block shear combines SHEAR YIELDING on one plane and TENSILE RUPTURE on the perpendicular plane. Remember: 'Block Shear = SHEAR yield + TENSION rupture.' The block is the worst-case combination: it's the ice cream scooper pulling out a chunk of your connection.
Anchor Type
visual_association
Why It Works
Halo-halo scooping is a familiar Filipino image. The perpendicular planes (shear + tension) are encoded in the 'chunk pulled free' spatial image.
Example Usage
Block shear is a THIRD limit state at connections (in addition to yield and rupture of the member). Check all three when designing tension member connections.
Recall Trigger
Halo-halo scoop = block shear
Tags
- definition
- formula
Topic
Cross-sectional Areas
Concept
Gross area Ag = full cross-sectional area before holes
Anchor Id
A15
Difficulty
easy
Memory Aid
Ag is like your GROSS salary — the full amount before any deductions (SSS, PhilHealth, Pag-IBIG). The moment holes are cut, deductions happen → you get net area (An). If some of your salary is untaxed because your employer doesn't fully utilize it (shear lag), the effective take-home is Ae = U × An.
Anchor Type
analogy
Why It Works
Filipino employees are intimately familiar with gross vs. net salary deductions (SSS, PhilHealth, Pag-IBIG). This maps perfectly onto Ag → An → Ae progression with parallel deduction logic.
Example Usage
200 × 12 plate: Ag = 200 × 12 = 2400 mm². Two 22 mm holes: An = 2400 − 2(22)(12) = 1872 mm². U = 1.0: Ae = 1872 mm².
Recall Trigger
Gross salary → Ag; after deductions → An; take-home → Ae
Tags
- definition
- formula
- classification
Topic
LRFD vs ASD
Concept
ASD vs. LRFD: Ω values (Ωt = 1.67 yield, Ωt = 2.00 rupture)
Anchor Id
A16
Difficulty
medium
Memory Aid
LRFD uses φ (multiply up), ASD uses Ω (divide down). For tension members: φ-pairs are 0.90/0.75 and Ω-pairs are 1.67/2.00. Memory chunk: '90-75 and 167-200.' Note that 1/0.90 ≈ 1.11 ≠ 1.67 — the ASD values are NOT simply reciprocals of φ; they include a different safety model. But the GOVERNING logic is the same: check both, take the lesser capacity.
Anchor Type
chunking
Why It Works
Chunking the four numbers as '90-75 and 167-200' groups related values into a compressed numerical sequence, reducing cognitive load.
Example Usage
ASD: Pn/Ωt ≥ Pa. For yield: Pn/1.67; for rupture: Pn/2.00. Most PRC board problems use LRFD (φ values). Know ASD as backup.
Recall Trigger
90-75 and 167-200 (LRFD vs ASD pairs)
Tags
- classification
- definition
Topic
Types of Tension Members
Concept
Tension member types: plates, angles, W-shapes, rods, cables
Anchor Id
A17
Difficulty
easy
Memory Aid
PAWR-C: Plates, Angles, W-shapes (used as chords/ties in trusses), Rods, Cables. Say it as 'POWER-C' — tension members have POWER because they carry loads efficiently with no buckling. Each type has different shear lag concerns: Plates (U = 1.0 if fully connected), Angles (U < 1.0 if one leg), W-shapes (U depends on connection type), Rods (no slenderness limit), Cables (flexible, U = 1.0).
Anchor Type
acronym
Why It Works
PAWR-C / POWER-C is a phonetically strong acronym. Linking each letter to a conceptual note creates a two-level memory structure.
Example Usage
Board question: 'Which types of members are designed as tension members?' → PAWR-C. Then classify their U factors based on connection type.
Recall Trigger
POWER-C members for tension
Tags
- process
- sequence
Topic
Critical Failure Path
Concept
Critical failure path for staggered holes — check all paths
Anchor Id
A18
Difficulty
hard
Memory Aid
Detective Reyes is inspecting a steel plate. He checks EVERY possible escape route for a crack: straight across (path A), zig-zag left (path B), zig-zag right (path C). Each path has a different net width calculation. The NARROWEST escape route (smallest net width = smallest net area) is where the crack will actually propagate. Detective Reyes always says: 'Check every path — the weakest one GOVERNS.'
Anchor Type
micro_story
Why It Works
The detective framing creates active problem-solving imagery. 'Narrowest escape route = governing failure path' maps spatially onto the calculation. The story format aids episodic memory.
Example Usage
Multiple bolt lines: compute net width for ALL possible failure paths (straight and zig-zag). The minimum net width gives the governing An. Multiply by thickness → An governs design.
Recall Trigger
Detective Reyes checks every path
Tags
- process
- sequence
Topic
Design Procedure
Concept
Design steps for tension member: 5-step process
Anchor Id
A19
Difficulty
medium
Memory Aid
GNARE: G = Get Ag (gross area), N = compute Net area An (subtract holes), A = find Ae (apply shear lag U), R = compute Rupture capacity (0.75 Fu Ae), E = Evaluate yield capacity (0.90 Fy Ag) and take the minimum. 'GNARE' — like baring your teeth (gnare = growl) at the exam. Fifth step: ENSURE L/r ≤ 300.
Anchor Type
acronym
Why It Works
GNARE as a phonetic word ('growl') creates an action image. The 5-letter structure maps to 5 clear steps, reducing the design process to a single memorable sequence.
Example Usage
Step G: Ag = b × t. Step N: An = Ag − Σ(dh × t). Step A: Ae = U × An. Step R: φPn (rupture) = 0.75 Fu Ae. Step E: φPn (yield) = 0.90 Fy Ag. Answer = min(R, E).
Recall Trigger
GNARE at the exam — 5 steps for tension design
Tags
- definition
- classification
Topic
Professional Practice Context
Concept
RA 544 (Philippine Civil Engineering Law) — professional context
Anchor Id
A20
Difficulty
easy
Memory Aid
RA 544 is the CE's birth certificate — it defines who a Civil Engineer is and what we are authorized to design. When you sign structural plans for a tension member, you are invoking RA 544's authority. The NSCP 2015 is the CE's design bible — RA 544 gives you the right to use it. 'RA 544 = LICENSE, NSCP = RULEBOOK.' Both are needed: the license to practice and the code to follow.
Anchor Type
analogy
Why It Works
The birth certificate / bible analogy uses two universally understood documents. The clear role differentiation (license vs. rulebook) helps students understand why both RA 544 and NSCP matter in professional practice.
Example Usage
Board exam context: RA 544 establishes the CE profession. NSCP 2015 (adopting AISC 360) provides design provisions. A licensed CE (RA 544) must follow NSCP when designing tension members.
Recall Trigger
RA 544 = license, NSCP = rulebook
Revision Game
0.75 (φ for tensile rupture)
Clue
I am the resistance factor that makes rupture checks stricter. I am NOT 0.90. What number am I?
Memory Link
Tita RUFA-E is 3/4 energized — she only gives 75% (A3, RUFA-E mnemonic)
Gross Area (Ag)
Clue
I am the area you use for yielding — the full, uncut, no-holes-subtracted version of a cross-section. What am I called?
Memory Link
Gross salary before deductions — Ag is the full paycheck (A15)
s²/4g — the staggered hole correction term
Clue
I am the magic formula correction that adds back area when bolt holes are diagonally offset. My formula contains pitch squared divided by four times gage. What am I?
Memory Link
Pacman power pellet bonus for diagonal paths (A7)
Shear Lag Factor (U)
Clue
I am the factor that accounts for the lazy freeloader leg of an angle that doesn't fully participate in tension transfer. I am always ≤ 1.0. What am I called?
Memory Link
Lazy back-row barangay tanods = shear lag = U < 1.0 (A9)
L/r ≤ 300 (slenderness recommendation)
Clue
I am a slenderness limit recommendation for tension members. Exceeding me won't fail the strength check, but I prevent excessive sag. 300 famous warriors share my number. What ratio am I?
Memory Link
300 Spartans stood by recommendation, not royal decree (A10)
φPn = 0.90 × 248 × 2400 = 535,680 N = 535.7 kN
Clue
A 200×12 mm plate has Fy = 248 MPa and Ag = 2400 mm². I am the yield design strength in kN. Calculate me.
Memory Link
YO-FAG: 0.90 × Fy × Ag (A2). Recall Yieldo the generous coffee vendor (A1).
Ae = U × An
Clue
I am the formula for effective net area. I multiply the net area by a factor that is always ≤ 1.0. What is my equation?
Memory Link
U is the Utilization factor — RUFA-E uses the cracked pot Ae = U × An (A8, A3)
dh = 20 + 2 = 22 mm (standard) or 23 mm (local +3 mm practice)
Clue
A 20 mm bolt is installed in a punched hole with standard clearance. What is the design hole diameter dh used for net area calculations?
Memory Link
Hole = Bolt + 2 — the trap rhyme (A6): forgetting this is Pitfall 1 of the Fatal Four
Formula Mnemonics
Formula
φPn = 0.90 Fy Ag (Tensile Yielding)
Mnemonic
YO-FAG: Y=Yield, 0=0.90, F=Fy, A=Ag, G=Gross. 'YO-FAG!' shouts the referee at yielding.
When To Use
First limit state check for ANY tension member. Uses the full unreduced cross-section because at yielding, the holes have not yet caused fracture.
What Each Part Means
φ = 0.90 (resistance factor for yielding); Fy = specified minimum yield stress (MPa); Ag = gross cross-sectional area (mm²); Result in Newtons, divide by 1000 for kN.
Formula
φPn = 0.75 Fu Ae (Tensile Rupture)
Mnemonic
RUFA-E: R=Rupture, U=0.75, F=Fu, A=Ae, E=Effective. 'Tita RUFA-E is 3/4 energized!'
When To Use
Second limit state check. Always check this alongside yielding. Governs when the net section is significantly reduced by holes or when Fu × Ae is relatively small.
What Each Part Means
φ = 0.75 (lower resistance factor — rupture is sudden and non-ductile); Fu = specified minimum tensile/ultimate stress (MPa); Ae = effective net area = U × An (mm²); Result in Newtons.
Formula
An = Ag − Σ(dh × t)
Mnemonic
PANDESAL minus BITES: Gross loaf minus all bite-sized holes. Each bite = dh × t (width of hole × thickness).
When To Use
Whenever bolt holes are present. Used to calculate Ae = U × An. Always use dh (hole dia.), NOT bolt diameter.
What Each Part Means
An = net area (mm²); Ag = gross area (mm²); dh = hole diameter = bolt diameter + 2 mm (standard clearance); t = plate thickness (mm); Σ sums over ALL holes on the critical path.
Formula
Net width = Wg − Σdh + Σ(s²/4g) for staggered holes
Mnemonic
PACMAN path: Wg is the full plate, −Σdh removes bites (holes), +Σ(s²/4g) adds back the power-pellet bonus for each diagonal zig-zag. Then An = net width × t.
When To Use
When bolt holes are staggered (offset) in multiple lines. Check ALL possible failure paths; the one giving the MINIMUM net width governs.
What Each Part Means
Wg = gross plate width (mm); dh = hole diameter (mm); s = longitudinal spacing (pitch) between holes in the zig-zag path (mm); g = transverse gage distance between bolt lines (mm); s²/4g added for EACH diagonal segment in the failure path.
Formula
Ae = U × An
Mnemonic
U is the UTILIZATION. Ae = Utilized Net Area. Full connection: U=1.0, full utilization. One-leg angle: U<1.0, partial utilization (freeloader effect = shear lag).
When To Use
Always, when computing rupture capacity. U = 1.0 only for members where load is transmitted through ALL cross-sectional elements (e.g., full-width bolted plate). U < 1.0 for angles, tees, channels connected through one element.
What Each Part Means
U = shear lag factor (≤ 1.0, per AISC 360 Table D3.1); An = net area after hole deductions (mm²); Ae = effective net area for rupture calculation (mm²).
Formula
L/r ≤ 300 (Slenderness Recommendation)
Mnemonic
300 SPARTANS stood firm by RECOMMENDATION — not by royal decree. L = length of member, r = least radius of gyration. Exceeding 300 won't fail the strength check, but the member may sag or vibrate.
When To Use
Final serviceability check after strength design. Compute r_min from section properties table. If L/r > 300, consider a stiffer section even though strength may be adequate.
What Each Part Means
L = member length (mm); r = least radius of gyration of the cross-section (mm); 300 = NSCP recommended upper limit for tension members (not applicable to rods).
Quick Recall Chains
Chain Title
5-Step Tension Member Design (GNARE)
Recall Test
Close your eyes. What are the 5 letters of GNARE and what does each mean in tension design?
Memory Chain
GNARE: Detective Reyes (G)ets the gross area, (N)arrows it down by cutting holes, (A)pplies shear lag to get effective area, then (R)oars the rupture check, and finally (E)valuates yield — always taking the weaker result.
Items To Remember
- Step 1: Compute Gross Area (Ag)
- Step 2: Compute Net Area (An = Ag − Σdh·t)
- Step 3: Compute Effective Net Area (Ae = U·An)
- Step 4: Compute Rupture capacity (φPn = 0.75 Fu Ae)
- Step 5: Compute Yield capacity (φPn = 0.90 Fy Ag) and take minimum
Chain Title
Two Limit States with Correct φ and Area
Recall Test
Without looking: which limit state uses φ = 0.75? Which uses Ag? Which uses Fu?
Memory Chain
Yieldo (90% coffee, full pot = Ag, Fy) vs. Ruptura (75% coffee, cracked pot = Ae, Fu). You drink the smaller cup — the minimum governs.
Items To Remember
- Yielding: φ = 0.90, uses Fy, uses Ag (gross — no hole deduction)
- Rupture: φ = 0.75, uses Fu, uses Ae (effective net — holes deducted, U applied)
- Governing: minimum of the two design strengths
Chain Title
Net Area Calculation Steps for Staggered Holes
Recall Test
For a plate with 3 bolts in 2 staggered lines: how many possible failure paths exist? What formula applies to each diagonal segment?
Memory Chain
Detective Reyes walks across the plate (Wg), encounters every ghost hole (−dh), collects power pellets on diagonals (+s²/4g). The narrowest escape route (min net width × t) is where the crack will go.
Items To Remember
- Identify ALL possible failure paths (straight and zig-zag)
- For each path: start with gross width Wg
- Subtract each hole diameter dh crossed by the path
- Add s²/4g for each diagonal segment in the path
- Multiply minimum net width by thickness t to get An
- Governing An = minimum over all paths
Chain Title
Shear Lag Factor U — Classification
Recall Test
Angle bolted through one leg with 3 bolts: what is the approximate U value? Why is U < 1.0?
Memory Chain
Full team (U=1.0) → mostly present (U=0.90) → half-hearted (U=0.85) → solo tanod (U=0.80). The fewer people (connected elements) pulling together, the lower the U score. When in doubt, consult Table D3.1.
Items To Remember
- U = 1.0: all elements connected (full-width plate, all flanges bolted)
- U = 0.90: W-shape or tee, bf ≥ 2/3 d, connected through flanges with ≥ 3 bolts
- U = 0.85: angle with 2+ bolts per line, or W-shape connected through web
- U = 0.80: angle with exactly 1 bolt per line
- Always use AISC 360 Table D3.1 for exact values
Chain Title
Common Board Pitfalls — The Fatal Four
Recall Test
State the Fatal Four pitfalls in order. Which one is most commonly committed in board review problem sets?
Memory Chain
The Fatal Four traps: Bolt-Hole Blur (trap 1), One-State Laziness (trap 2), Freeloader Blindness (trap 3), and Phi Swap (trap 4). Remember: 'Blur-Lazy-Blind-Swap' — four ways to fail a board item.
Items To Remember
- Pitfall 1: Using bolt diameter instead of hole diameter (always add 2-3 mm)
- Pitfall 2: Skipping one limit state (ALWAYS check BOTH yield AND rupture)
- Pitfall 3: Assuming U = 1.0 for angle/tee with partial connection (check Table D3.1)
- Pitfall 4: Using φ = 0.90 for rupture instead of 0.75 (or vice versa)
Ready to practise for the CELE 2026?
Super Tutor's AI review plan adapts to your weak areas and builds a weekly practice schedule around your target CELE exam date.