Memory AnchorsCELE · Steel & Timber DesignReal content

CELE Steel & Timber Design — Steel Beams: Flexure and ShearMemory Anchors

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Memory anchors and mnemonic tricks for Steel Beams: Flexure and Shear. If you find yourself forgetting key facts from this chapter during CELE mocks, these anchors are your fix. Built for Professional Regulation Commission (PRC) — Board of Civil Engineering's question style and the time pressure of the CELE 2026.

Exam context

For the Civil Engineer Licensure Examination, Professional Regulation Commission (PRC) — Board of Civil Engineering tests Steel & Timber Design under a "Core" label, with Steel Beams: Flexure and Shear in the 3rd slot across 5 chapters. CELE candidates must clear the 70% weighted average, no sub-test below 50% cut on the 2026 paper, which draws about a meaningful share of Steel & Timber Design questions. Date to watch: May and November 2026.

Steel Beams: Flexure and Shear - Memory Anchors

Memory techniques can increase long-term retention by up to 400% compared to passive re-reading. The human brain encodes information through emotion, story, imagery, and pattern — not raw repetition. For board exam success, you need formulas and concepts to surface instantly under pressure. This collection of mnemonics, analogies, micro-stories, and visual anchors transforms dry steel design equations into vivid mental hooks. Each anchor is engineered to fire automatically when you see a related exam question — because in the licensure exam, speed and accuracy are everything.

Anchors

Topic

Plastic Moment Capacity

Concept

Plastic Moment formula: Mn = Mp = Fy × Zx

Anchor Id

Difficulty

easy

Memory Aid

Remember 'FiZz' — F-y times Z-x gives you the FIZZ (the full fizzy pop of a beam at its plastic limit). When a beam is fully braced and compact, it FIZZES with energy: Mp = Fy × Zx. The 'p' in Mp stands for 'POPPED' — the beam has yielded fully across the entire cross-section, like a soda can that has been fully pressurized.

Anchor Type

mnemonic

Why It Works

The phonetic link 'FiZz' encodes both variables Fy and Zx into a single sound cue, making formula recall near-instant.

Example Usage

Exam question asks for design flexural strength of a compact, braced W-section. Recall 'FiZz' → Mp = Fy × Zx → then apply φb = 0.90 to get φbMn.

Recall Trigger

Think of a fizzing soda — Fy × Zx = Mp

Topic

LRFD Resistance Factor — Flexure

Concept

φb = 0.90 for flexure (LRFD resistance factor)

Anchor Id

Difficulty

easy

Memory Aid

Nine-tenths for bending — that's the rule, my friend. φb = 0.90 — bend it, don't end it. Think: 'BENDING is NINE-ty percent sure.' The beam resists 90% of what it theoretically can, because real-world imperfections eat 10%.

Anchor Type

rhyme

Why It Works

Rhyme and numerical anchoring together. 0.90 is linked to 'ninety' which sounds like 'bending' in memory via the rhyme.

Example Usage

After computing Mn = Mp = Fy Zx, multiply by 0.90 to get φbMn. If Mn = 297.6 kN·m, then φbMn = 0.90 × 297.6 = 267.8 kN·m.

Recall Trigger

φb — bending — ninety percent — 0.90

Topic

Lateral-Torsional Buckling — Lp

Concept

Lp formula: Lp = 1.76 ry √(E/Fy) — maximum unbraced length for full Mp

Anchor Id

Difficulty

medium

Memory Aid

Use the memory phrase: 'ONE POINT SEVEN SIX, ry ROOTS E over Fy — STAY IN THE ZONE.' Picture a basketball player (ry = radius of gyration about y-axis) staying within the three-point zone (Lp). 1.76 is the magic number — almost 'one-and-three-quarters.' Chunk it: 1.76 — ry — square root — E over Fy. Say it like a chant: 'Seventy-six, ry, root E on Fy!'

Anchor Type

mnemonic

Why It Works

Chunking the four parts of the formula into a chant with rhythm locks the sequence in memory through auditory encoding.

Example Usage

Given ry = 40 mm, E = 200,000 MPa, Fy = 248 MPa: Lp = 1.76 × 40 × √(200,000/248) = 70.4 × 28.4 ≈ 2,000 mm = 2.0 m.

Recall Trigger

Basketball player staying in the zone → Lp = 1.76 ry √(E/Fy)

Topic

Lateral-Torsional Buckling Zones

Concept

The three LTB zones: Lb ≤ Lp (no LTB), Lp < Lb ≤ Lr (inelastic LTB), Lb > Lr (elastic LTB)

Anchor Id

Difficulty

medium

Memory Aid

Think of a JEEPNEY TRIP from Manila to Batangas. Zone 1 (Lb ≤ Lp): You're still in the city — smooth ride, full speed (Mn = Mp, no reduction). Zone 2 (Lp < Lb ≤ Lr): You're on the winding Tagaytay road — you slow down gradually (inelastic LTB, Mn drops linearly). Zone 3 (Lb > Lr): You're on a rough mountain trail — very slow, elastic buckling controls, Mn = Fcr × Sx (elastic LTB formula takes over).

Anchor Type

analogy

Why It Works

The Filipino jeepney road trip creates a vivid spatial journey that maps perfectly onto the three-zone LTB behavior. Distance traveled = Lb, speed = Mn.

Example Usage

If Lb = 1.5 m and Lp = 2.0 m: Lb ≤ Lp → Zone 1 (city) → No LTB → Mn = Mp. Full capacity available.

Recall Trigger

Jeepney trip: city → winding road → mountain trail = three LTB zones

Topic

Section Moduli: Plastic vs Elastic

Concept

Zx (plastic section modulus) vs Sx (elastic section modulus) — Zx > Sx

Anchor Id

Difficulty

easy

Memory Aid

Imagine twins named SX and ZX applying for a job as beam section moduluses. SX is the conservative older twin — he stops working the moment the outermost fiber yields (elastic limit). ZX is the ambitious younger twin — he keeps working even after the outer fiber yields, mobilizing the ENTIRE cross-section in plasticity. ZX always gets the bigger paycheck (Zx > Sx). The boss (AISC 360) hires ZX for plastic moment calculations. The shape factor (Zx/Sx ≈ 1.12 for I-shapes) is ZX's 12% salary premium.

Anchor Type

micro_story

Why It Works

Personification of abstract concepts makes them memorable. The 'twin' story encodes the comparison, the salary premium encodes the 12% ratio.

Example Usage

For plastic moment, always use Zx (not Sx): Mp = Fy × Zx. Common board pitfall is using Sx — remember ZX gets the bigger job.

Recall Trigger

The ambitious twin ZX with the bigger paycheck — Zx > Sx, shape factor ≈ 1.12

Topic

Shear Strength

Concept

Shear strength formula: Vn = 0.6 Fy Aw Cv

Anchor Id

Difficulty

easy

Memory Aid

Remember the phrase: 'SIX-TENTHS FyAwCv GIVES YOU SHEAR STRENGTH.' Chunked: 0.6 — Fy — Aw — Cv. Create an acronym for the variables after 0.6: 'F-A-C' (Fy, Aw, Cv) = 'FACT.' So: Vn = 0.6 × FACT. Remember: '0.6 times the FACT equals the shear.' The 0.6 comes from the von Mises yield criterion (shear yield stress ≈ 0.577Fy ≈ 0.6Fy).

Anchor Type

mnemonic

Why It Works

The word FACT as an acronym for F-A-C links three separate variables into one memorable word with positive connotations (facts are certain, reliable).

Example Usage

Given d = 450 mm, tw = 10 mm, Fy = 248 MPa, Cv = 1.0: Aw = 450 × 10 = 4,500 mm². Vn = 0.6 × 248 × 4,500 × 1.0 = 669,600 N = 669.6 kN.

Recall Trigger

0.6 × FACT → Vn = 0.6 Fy Aw Cv

Topic

Web Area for Shear

Concept

Aw = d × tw (web area uses full depth d, not clear web height)

Anchor Id

Difficulty

medium

Memory Aid

Picture a DOOR (the web of the I-beam). The DOOR HEIGHT is the full door height d (from floor to top frame, like the full depth of the beam). The DOOR THICKNESS is tw. The web area Aw is the door's face area: height × thickness = d × tw. The board exam trap is using only the clear web height (between flanges) — but AISC uses the FULL door height d. Visualize the door frame included — it's ALL the door, not just the inner panel.

Anchor Type

visual_association

Why It Works

Spatial visualization of a door creates a concrete 3D image that immediately communicates 'full height' as the key word.

Example Usage

Never use (d - 2tf) for Aw in the AISC shear formula. If d = 600 mm, tw = 12 mm → Aw = 600 × 12 = 7,200 mm² (full depth).

Recall Trigger

The DOOR — full door height d × door thickness tw = Aw

Topic

Shear Resistance Factor

Concept

φv = 1.0 for shear of typical rolled I-shapes (not 0.90)

Anchor Id

Difficulty

easy

Memory Aid

Engineer Mang Romy is inspecting a steel beam's web. His colleague asks, 'Mang Romy, ano ang phi for shear?' Mang Romy answers confidently: 'ISANG (ONE) — BUO! φv = 1.0 — buong-buo!' (meaning 'whole/complete' in Filipino). Unlike flexure which is nervous about imperfections (φb = 0.90, only 90%), the shear web of a stocky rolled I-shape is SO reliable that AISC gives it a perfect score: φv = 1.0. It's the straight-A student of resistance factors.

Anchor Type

micro_story

Why It Works

The Filipino word 'buo' (whole) encodes the value 1.0, and the contrast with φb = 0.90 reinforces the distinction students frequently confuse.

Example Usage

After computing Vn = 669.6 kN: φvVn = 1.0 × 669.6 = 669.6 kN. Do NOT use 0.90 for shear of typical rolled I-shapes.

Recall Trigger

'Buo!' — φv = 1.0 for rolled I-shape shear (not 0.90)

Topic

Web Shear Coefficient Cv

Concept

Cv = 1.0 when h/tw ≤ 2.24√(E/Fy) — stocky web, no shear buckling

Anchor Id

Difficulty

medium

Memory Aid

Cv is the 'CLAPBOARD VOTER' — it votes either 1.0 (full shear capacity) or less than 1.0 (shear buckling reduces capacity). For a STOCKY web (thick enough that h/tw ≤ 2.24√(E/Fy)), the voter shouts 'YES — FULL CAPACITY!' and Cv = 1.0. For a SLENDER web, the voter hesitates. The number 2.24 is almost 2 and a quarter — remember it as '2 and a quarter check' for the web slenderness limit.

Anchor Type

analogy

Why It Works

Voting metaphor (yes/no decision) maps cleanly onto the binary condition check. Filipino students engage well with civic-participation analogies.

Example Usage

Check: h/tw ≤ 2.24√(200,000/248) = 2.24 × 28.4 = 63.6. If web passes this check, use Cv = 1.0 in Vn formula.

Recall Trigger

Web slenderness check — '2 and a quarter √(E/Fy)' → Cv = 1.0 if web passes

Topic

Compact Section Classification

Concept

Compact section requirement — flange and web λ < λp so full yielding occurs before local buckling

Anchor Id

A10

Difficulty

medium

Memory Aid

A steel section is like a BIBINGKA MOLD. If the mold walls are THICK and SHORT (compact — λ < λp), the bibingka sets perfectly into its full plastic shape without the mold warping. If the mold is THIN and TALL (non-compact or slender), it wrinkles or collapses before the batter fully sets. The bibingka = the full plastic moment Mp. Only a compact mold gives you the perfect bibingka.

Anchor Type

analogy

Why It Works

Bibingka is a culturally familiar Filipino rice cake baked in a mold — the analogy maps perfectly onto plate buckling before full yielding.

Example Usage

Before using Mn = Mp = Fy Zx, verify the section is compact: check both flange (bf/2tf ≤ λp) and web (h/tw ≤ λp) slenderness.

Recall Trigger

Bibingka mold — thick walls (compact) → perfect shape (full Mp); thin walls (slender) → wrinkled (local buckling)

Topic

Moment Gradient Factor Cb

Concept

Cb (moment gradient factor) — increases Mn for non-uniform moment, capped at Mp

Anchor Id

A11

Difficulty

hard

Memory Aid

Cb is the 'CHEERLEADER BONUS' — when a beam has varying moment along its length (not constant), the cheerleader Cb cheers it on beyond the conservative uniform-moment assumption. A Cb > 1.0 means the beam is working in a more favorable loading pattern, so it earns a bonus. BUT the principal (Mp) sets a SALARY CAP — no matter how much Cb cheers, Mn cannot exceed Mp. Cb = 1.0 for uniform moment (no bonus — monotone cheerleader).

Anchor Type

micro_story

Why It Works

The 'cheerleader' and 'salary cap' metaphors encode both the upward effect of Cb and the critical ceiling of Mp simultaneously.

Example Usage

If LTB analysis gives Mn = 280 kN·m and Cb = 1.15 → Cb × Mn = 1.15 × 280 = 322 kN·m. But if Mp = 310 kN·m, the answer is capped: Mn = 310 kN·m.

Recall Trigger

Cheerleader Cb — bonus for non-uniform moment — capped at Mp

Topic

Inelastic LTB — Linear Reduction

Concept

Inelastic LTB zone: Mn varies linearly between Mp and 0.7FySx

Anchor Id

A12

Difficulty

hard

Memory Aid

Picture a DIMMER SWITCH (ang dimmer ng ilaw). At Lb = Lp, the light is FULL BRIGHT (Mn = Mp). As Lb increases past Lp, you slowly dim the light — linearly decreasing. At Lb = Lr, the light dims to 70% of a different reference (0.7FySx). The dimmer switch is LINEAR — not sudden. Beyond Lr, you switch to a different mechanism entirely (elastic buckling, a new formula). The dimmer perfectly represents the linear interpolation in the inelastic LTB zone.

Anchor Type

visual_association

Why It Works

The dimmer switch provides a physical, kinesthetic analogy for linear reduction — students can almost feel themselves turning the dial.

Example Usage

If Lb = 2.5 m, Lp = 2.0 m, Lr = 5.0 m: in inelastic LTB zone. Use linear interpolation formula between Mp and 0.7FySx based on position of Lb relative to Lp and Lr.

Recall Trigger

Dimmer switch — Lb between Lp and Lr → Mn dims linearly from Mp to 0.7FySx

Topic

Shape Factor — I-Sections

Concept

Shape factor ≈ 1.12 for I-shapes: Zx/Sx ≈ 1.12

Anchor Id

A13

Difficulty

easy

Memory Aid

Remember: 'I-shapes are 12% SMARTER than their elastic selves.' Zx = 1.12 × Sx for typical W-sections. The shape factor is the IQ boost from elastic to plastic thinking. If you only use Sx (elastic), you leave 12% of the beam's strength on the table — like scoring 88/100 when you could score 100/100. Encode it as: 'Z is 12% more than S for an I.'

Anchor Type

mnemonic

Why It Works

Percentage framing (12% smarter) is concrete and relatable, and the test-score analogy resonates with exam-focused students.

Example Usage

If Sx = 1,070 × 10³ mm³, then Zx ≈ 1.12 × 1,070 × 10³ = 1,198 × 10³ mm³ (approximate check). Always use actual tabulated Zx in computations.

Recall Trigger

I-beam is 12% smarter — Zx ≈ 1.12 Sx

Topic

Radius of Gyration ry and LTB

Concept

ry is the radius of gyration about the weak (y) axis — governs LTB

Anchor Id

A14

Difficulty

medium

Memory Aid

A steel beam is like a FLAGPOLE. It is STRONG against bending in its flat dimension (x-axis — strong axis) but WEAK laterally (y-axis — weak axis, the flagpole wobbles sideways in the wind). ry measures how resistant the cross-section is to that sideways wobble. A SMALLER ry means the beam wobbles more easily → shorter Lp → more susceptible to LTB. A larger ry → longer Lp → better resistance to lateral buckling.

Anchor Type

analogy

Why It Works

The flagpole wobbling in wind creates a perfect sensory image of lateral instability, linking ry directly to its physical meaning.

Example Usage

Larger ry → larger Lp = 1.76 ry √(E/Fy) → longer allowable unbraced length before LTB → more economical beam design.

Recall Trigger

Flagpole wobbling sideways = ry — weak axis radius of gyration → controls Lp

Topic

Common Pitfall — Zx vs Sx

Concept

Key board-exam pitfall: Using Sx instead of Zx for plastic moment

Anchor Id

A15

Difficulty

easy

Memory Aid

During the 2019 board exam (a fictional scenario for memory), Engineer Josie computed Mp = Fy × Sx and got an answer 12% lower than the correct answer. She failed by 1 point. Her ghost now haunts engineering review centers, whispering 'USE ZX! NOT SX! ZX IS PLASTIC! SX IS ELASTIC!' Every time you see 'plastic moment' — hear Josie's ghost: 'ZX! ZX! ZX!' The exam question always tests whether you know the difference.

Anchor Type

micro_story

Why It Works

The ghost story with emotional stakes (failing by 1 point) creates a memorable cautionary tale. Emotion dramatically enhances memory encoding.

Example Usage

Exam gives Sx = 850 × 10³ mm³ and Zx = 950 × 10³ mm³, Fy = 345 MPa. Mp = 345 × 950 × 10³ = 327.75 × 10⁶ N·mm. Use Zx, not Sx.

Recall Trigger

Josie's ghost whispering 'ZX!' → never use Sx for plastic moment

Topic

Elastic LTB Zone

Concept

Elastic LTB zone (Lb > Lr): Mn = Fcr × Sx — elastic critical stress governs

Anchor Id

A16

Difficulty

hard

Memory Aid

Picture a SPRING (elastic) that is stretched WAY too far — it no longer yields; it just snaps back elastically. When Lb > Lr, the beam buckles elastically (like an overstretched spring) before ANY yielding — so the plastic and inelastic tools are useless. The elastic critical stress Fcr (like the spring constant) takes over, multiplied by Sx (elastic modulus — appropriate now since there's NO yielding). Spring = elastic = Fcr × Sx.

Anchor Type

visual_association

Why It Works

The spring analogy directly encodes the word 'elastic' into a physical object, and the connection to Sx (elastic modulus) becomes logical rather than arbitrary.

Example Usage

If Lb > Lr, use Mn = Fcr × Sx where Fcr involves Cb, E, Lb, ry, and torsional properties. Beam never yields — purely elastic buckling.

Recall Trigger

Overstretched spring → elastic LTB → Mn = Fcr × Sx

Topic

Code References — NSCP 2015 and AISC 360

Concept

AISC 360 governs steel design; NSCP 2015 adopts AISC provisions for Philippine practice

Anchor Id

A17

Difficulty

easy

Memory Aid

Remember: 'NSCP ADOPTS AISC — Like a PARENT adopting a CHILD.' AISC 360 is the brilliant American parent; NSCP 2015 (National Structural Code of the Philippines, adopted under RA 544 — the Civil Engineering Law) is the Philippine parent that adopts AISC's provisions for local use. In the board exam, both codes speak the same language. RA 544 is the mother law that empowers the PRC to enforce these standards.

Anchor Type

mnemonic

Why It Works

The adoption metaphor clarifies the hierarchical relationship between codes and connects Philippine law to design standards — a common source of confusion.

Example Usage

When citing code in board exam problems: NSCP 2015 Section 502 (Steel) refers to AISC 360 provisions. Both φb = 0.90 and φv = 1.0 apply under Philippine practice.

Recall Trigger

AISC parent → NSCP adopts → RA 544 is the grandmother law

Topic

Local Buckling — FLB and WLB

Concept

Web local buckling (WLB) and flange local buckling (FLB) reduce Mn in non-compact sections

Anchor Id

A18

Difficulty

hard

Memory Aid

Imagine an ACCORDION (the musical instrument). A compact section is a well-made accordion with thick reeds — squeeze it all the way (full plasticity, full Mn). A non-compact section is a cheap accordion with thin reeds — they buckle inward before you fully squeeze (FLB or WLB reduces Mn). A slender section is a paper accordion — it collapses immediately (elastic local buckling, Mn heavily reduced). The squeeze = loading; accordion collapse = local buckling.

Anchor Type

analogy

Why It Works

The accordion analogy maps compression (squeezing) directly onto the mechanism of local buckling in plate elements.

Example Usage

Non-compact flange: Mn falls between Mp and FLB limit. Check: λpf < bf/2tf ≤ λrf. Mn is reduced by linear interpolation — same dimmer-switch concept, but for local buckling.

Recall Trigger

Accordion — thick reeds (compact, full squeeze), thin reeds (non-compact, partial), paper (slender, collapses) = FLB/WLB

Topic

Shear Yield Stress — von Mises

Concept

The 0.6 factor in Vn comes from shear yield stress τy ≈ 0.577Fy (von Mises), rounded to 0.6

Anchor Id

A19

Difficulty

medium

Memory Aid

Von Mises (the mathematician) once told AISC: 'Shear yields at 0.577 of the tensile yield stress.' AISC said 'Thank you, Mr. von Mises, but engineers like round numbers — we'll use 0.6.' So AISC rounded 0.577 up to 0.6 for convenience. Every time you write 0.6Fy in the shear formula, nod to von Mises — the man who gave us the theoretical basis, and AISC who simplified it to 0.6 for everyday use.

Anchor Type

micro_story

Why It Works

The conversational story between historical figures makes the origin of the 0.6 coefficient memorable rather than arbitrary.

Example Usage

Understanding why 0.6 appears in Vn = 0.6 Fy Aw Cv helps you never forget it — it's the shear yield stress approximation, not an arbitrary safety factor.

Recall Trigger

Von Mises says 0.577, AISC rounds to 0.6 → 0.6Fy in shear formula

Topic

Full Design Check Sequence

Concept

Full summary of design checks: compact? → braced? (Lb vs Lp) → apply φbMn or reduce for LTB/LB

Anchor Id

A20

Difficulty

hard

Memory Aid

Walk through your BAHAY (house) to check a beam: (1) GATE: Is the section COMPACT? (Check λ for flange and web — 'knock on the gate: compact or not?'). (2) DOOR: Is Lb ≤ Lp? ('open the door to full Mp'). (3) SALA/LIVING ROOM: Is Lp < Lb ≤ Lr? ('you're inside but dimming the lights — inelastic LTB'). (4) BASEMENT: Is Lb > Lr? ('deep underground — elastic LTB, use Fcr × Sx'). (5) KITCHEN: Check SHEAR — Vn = 0.6 Fy Aw Cv ('cook the shear strength').

Anchor Type

method_of_loci

Why It Works

The method of loci (memory palace) using the familiar Filipino bahay creates distinct spatial triggers for each design check in sequence.

Example Usage

In any board exam flexural design problem: follow the bahay path in order. Never skip the gate (compactness) or the door (Lp check) before computing Mn.

Recall Trigger

Walk through your bahay: Gate (compact?) → Door (Lp?) → Sala (inelastic LTB?) → Basement (elastic LTB?) → Kitchen (shear?)

Revision Game

Zx — the plastic section modulus

Clue

I am larger than my elastic twin, I come from full plasticity, and without me you cannot compute Mp. Who am I?

Memory Link

A5 — The ambitious twin ZX who earns 12% more than SX

Lp — the limiting unbraced length for full plastic moment

Clue

I am the distance beyond which a beam starts to lose its full bending strength. Stay within me and you get the full fizzy Mp. What am I?

Memory Link

A3 — Basketball player staying in the zone / 1.76 ry √(E/Fy)

φv = 1.0 — the shear resistance factor for typical rolled I-shapes

Clue

I am a resistance factor, but unlike my bending sibling (0.90), I am perfect — I equal 1.0. Engineers say I am BUO. What am I for?

Memory Link

A8 — Mang Romy says BUO — φv = 1.0

Aw = d × tw (using full depth d, not clear web height)

Clue

I am the web area for shear, but beware — I use the FULL door height, not just the inner panel. Compute me correctly or lose the board exam. What is my formula?

Memory Link

A7 — The DOOR analogy — full door height d times thickness tw

von Mises — origin of the 0.6 factor in Vn = 0.6 Fy Aw Cv

Clue

I am the famous German mathematician who told AISC that shear yielding occurs at 57.7% of tensile yield, though AISC rounds me to 60%. Who am I?

Memory Link

A19 — Von Mises tells AISC 0.577, AISC rounds to 0.6

Inelastic LTB zone — Zone 2 (Lp < Lb ≤ Lr), Mn interpolates from Mp to 0.7FySx

Clue

I am the zone of lateral-torsional buckling where Mn drops linearly — like a dimmer switch being slowly turned down from full brightness to 70% of a reference value. What zone am I?

Memory Link

A12 — The DIMMER SWITCH analogy

RA 544 — Republic Act 544, the Civil Engineering Law of the Philippines

Clue

I am the Filipino grandmother law that empowers the PRC and makes NSCP and AISC provisions enforceable in Philippine professional practice. What is my name and number?

Memory Link

A17 — RA 544 is the grandmother law that empowers NSCP to adopt AISC

Cb — the moment gradient factor; increases Mn but is capped at Mp

Clue

I am a moment-gradient factor greater than 1.0 when bending moment varies along the beam. I give a strength bonus — but even I cannot push the answer above Mp. What am I?

Memory Link

A11 — The CHEERLEADER BONUS capped by the salary cap of Mp

Cv = shear buckling coefficient, h = clear distance between flanges (mm), tw = web thickness (mm), E = 200,000 MPa, Fy = yield stress (MPa). For Fy = 248 MPa: limit = 2.24 × 28.4 ≈ 63.6.

Coefficient: 1.76
Geometric property: ry (weak-axis radius of gyration)
Material ratio: √(E/Fy)
Result: maximum unbraced length for full Mp

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CELE Steel & Timber Design — Steel Beams: Flexure and ShearMemory Anchors

Exam context

Steel Beams: Flexure and Shear - Memory Anchors

Anchors

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