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CELE Construction Management & MethodsProject Planning and Scheduling (CPM/PERT)Revision Notes

Revision notes for CELE Construction Management & Methods Project Planning and Scheduling (CPM/PERT) — designed for time-pressed reviewers. These notes skip the basics and focus on what Professional Regulation Commission (PRC) — Board of Civil Engineering consistently tests, so you spend your revision hours on the content most likely to appear on exam day.

Exam context

The Civil Engineer Licensure Examination is conducted by Professional Regulation Commission (PRC) — Board of Civil Engineering and is scheduled for May and November 2026. The Construction Management & Methods subtest is marked as "Core" in the official pattern, and Project Planning and Scheduling (CPM/PERT) appears in position 2nd of 5 in the CELE Construction Management & Methods review rotation. Passing mark: 70% weighted average, no sub-test below 50%. Recent CELE 2026 papers have drawn roughly a meaningful share of questions from this subject.

Project Planning and Scheduling (CPM/PERT) - Revision Notes

Project Planning and Scheduling is a consistent topic in the PRC Civil Engineer Licensure Examination under Construction Management and Methods. The Critical Path Method (CPM) and Program Evaluation and Review Technique (PERT) are the two principal network-based scheduling tools used in Philippine construction practice. CPM is deterministic — each activity has a fixed duration; PERT is probabilistic — durations are uncertain and are modeled with three-point estimates. Mastery of these tools requires fluency in (1) building and reading activity networks, (2) executing the forward and backward pass, (3) computing float, (4) identifying the critical path, and (5) applying PERT statistics. Board questions typically ask you to identify the critical path, compute total float, find PERT expected durations, or estimate the probability of meeting a target completion date. All concepts in this chapter are directly applicable to construction site management responsibilities under Republic Act 544 (Civil Engineering Law of the Philippines).

Sections

Exam Tips

  • When given a list of activities with durations and predecessors, always enumerate ALL paths and their total durations before declaring the critical path.
  • In small networks (≤8 activities), enumerate paths by inspection; in larger ones, use the forward/backward pass.
  • If two paths have equal duration, BOTH are critical — state this explicitly in board exam answers.
  • The minimum project duration equals the length of the critical path — this is a definition, not a derived result.

Key Points

  • A project is broken into discrete activities, each with a defined duration and a set of predecessor activities that must be completed before it can start.
  • Two network representations exist: Activity-on-Arrow (AOA / Arrow Diagram Method, ADM) and Activity-on-Node (AON / Precedence Diagram Method, PDM). PDM is the modern industry standard and the one most commonly tested.
  • In PDM, each node (box) represents an activity. Arrows show dependency (finish-to-start unless otherwise stated).
  • The project network has a unique Start node and a unique Finish node.
  • The critical path is the LONGEST continuous path from Start to Finish — it sets the minimum project duration.
  • Activities on the critical path have ZERO total float — any delay in them directly delays the project.
  • Non-critical activities have positive total float, meaning they can be delayed within limits without affecting the project finish date.
  • A project may have more than one critical path (multiple paths of equal length).

Definitions

Term

Activity

Definition

A specific, definable task that consumes time and resources. Represented as a node in PDM.

Importance

Fundamental unit of a schedule. Board exams give you a list of activities with durations and dependencies.

Term

Predecessor

Definition

An activity that must be completed (or at least started, for non-FS relationships) before the successor can begin.

Importance

Defines the logical sequence that the forward pass must respect.

Term

Critical Path

Definition

The longest path through the network from Start to Finish. Its length equals the minimum project duration.

Importance

Board exams almost always ask you to identify it or compute its length.

Term

PDM (Precedence Diagram Method)

Definition

Network method where activities are shown as nodes (boxes) and arrows show dependencies. Also called Activity-on-Node (AON).

Importance

Standard in Philippine construction practice and board exam problems.

Term

AOA (Activity-on-Arrow)

Definition

Older network method where activities are on the arrows and nodes represent events. Requires dummy activities to show certain dependencies.

Importance

Less common in modern practice but may appear in older board exam formats.

Section Title

1. Network Fundamentals — Activities, Precedence, and the CPM Network

Common Mistakes

  • Choosing the SHORTEST path as the critical path — it is always the LONGEST.
  • Forgetting to include all paths when enumerating; missing a hidden longer path.
  • Confusing Activity-on-Arrow with Activity-on-Node notation when reading network diagrams.
  • Assuming there is only one critical path — there can be multiple paths of equal (maximum) duration.

Formulas

Example

Activity C has ES = 5 days and duration d = 4 days. Therefore EF = 5 + 4 = 9 days.

Formula

EF = ES + d

Variables

EF = Early Finish, ES = Early Start, d = activity duration (days or other time unit)

Application

Applied to every activity during the forward pass, left to right through the network.

Example

Activity E is preceded by C (EF=9) and D (EF=11). Therefore ES_E = max(9, 11) = 11 days.

Formula

ES_j = max(EF of all predecessors of j)

Variables

ES_j = Early Start of activity j; the maximum is taken over all activities immediately preceding j.

Application

Used at every merge point in the network — whenever an activity has two or more predecessors.

Exam Tips

  • Always label each node with a four-value box: [ES | EF] on top and [LS | LF] on bottom (to be filled in backward pass).
  • Work strictly left to right. Do not jump ahead to compute backward pass times until the entire forward pass is complete.
  • Double-check by confirming: the project duration from the forward pass should equal the length of the path you identify as critical.
  • Board problems often give you a partially completed network and ask you to find one missing ES or EF — apply EF = ES + d directly.

Key Points

  • The forward pass computes the EARLIEST time each activity can start (Early Start, ES) and finish (Early Finish, EF).
  • It moves from left to right (from Start toward Finish) through the network.
  • For the very first activity (or any activity with no predecessors), ES = 0.
  • EF = ES + duration (d). This is the single most important CPM formula.
  • When an activity has MULTIPLE predecessors, its ES = the MAXIMUM EF among all its predecessors. (You must wait for ALL predecessors to finish before you can start.)
  • The EF of the last activity (or the maximum EF of all activities ending the project) = project early finish = minimum project duration.
  • All early times are computed using the MAXIMUM rule at merge points (nodes with multiple incoming arrows).

Definitions

Term

Early Start (ES)

Definition

The earliest possible time an activity can begin, given that all its predecessors have been completed as early as possible.

Importance

ES values are computed in the forward pass and are needed to determine total float.

Term

Early Finish (EF)

Definition

The earliest time an activity can finish: EF = ES + d.

Importance

EF of the last activity gives the shortest possible project duration.

Term

Merge Point

Definition

A node in the network where two or more arrows converge — the activity at a merge point has multiple predecessors.

Importance

The MAX rule must be applied here. Forgetting to take the maximum is the most common forward-pass error.

Section Title

2. Forward Pass — Early Start and Early Finish

Common Mistakes

  • At a merge point, taking the MINIMUM instead of the MAXIMUM EF of predecessors — this violates the logic that ALL predecessors must finish first.
  • Starting the first activity at ES = 1 instead of ES = 0 — the convention is ES = 0 for the project start.
  • Forgetting to update ES of ALL successors when computing EF of a given activity.
  • Carrying forward only one predecessor's EF at a merge point and ignoring the others.

Formulas

Example

Activity B has LF = 15 days and duration d = 6 days. Therefore LS = 15 - 6 = 9 days.

Formula

LS = LF - d

Variables

LS = Late Start, LF = Late Finish, d = activity duration

Application

Applied to every activity during the backward pass, right to left through the network.

Example

Activity A feeds into B (LS=5) and C (LS=3). Therefore LF_A = min(5, 3) = 3 days.

Formula

LF_i = min(LS of all successors of i)

Variables

LF_i = Late Finish of activity i; the minimum is taken over all activities immediately following i.

Application

Used at every burst point — whenever an activity has two or more successors.

Exam Tips

  • Remember: Forward pass → MAX at merges; Backward pass → MIN at bursts. This asymmetry is a classic exam trap.
  • After completing both passes, verify: for critical activities, ES = LS and EF = LF. If this does not hold, recheck your arithmetic.
  • In board problems with 4–6 activities, always show both passes in a table with columns: Activity, d, ES, EF, LS, LF, TF — this prevents errors and earns partial marks.
  • The LF of the project's terminal node must equal its EF from the forward pass — this is the anchor for the backward pass.

Key Points

  • The backward pass computes the LATEST time each activity can start (Late Start, LS) and finish (Late Finish, LF) WITHOUT delaying the project.
  • It moves from right to left (from Finish toward Start) through the network.
  • For the very last activity (or any activity with no successors), LF = project duration (the EF from the forward pass).
  • LS = LF − d. Paired with EF = ES + d for the forward pass.
  • When an activity has MULTIPLE successors, its LF = the MINIMUM LS among all its successors. (The activity must finish in time for the earliest-starting successor.)
  • All late times are computed using the MINIMUM rule at burst points (nodes with multiple outgoing arrows).
  • Critical activities satisfy: ES = LS and EF = LF (equivalently, TF = 0).

Definitions

Term

Late Finish (LF)

Definition

The latest time an activity can finish without delaying the project end date.

Importance

LF is the starting point of the backward pass; it is set equal to the project's early finish for the last activity.

Term

Late Start (LS)

Definition

The latest time an activity can begin without delaying the project end date: LS = LF - d.

Importance

Used together with ES to compute Total Float.

Term

Burst Point

Definition

A node in the network where two or more arrows diverge — the activity at a burst point has multiple successors.

Importance

The MIN rule must be applied here when computing LF during the backward pass.

Section Title

3. Backward Pass — Late Start and Late Finish

Common Mistakes

  • At a burst point, taking the MAXIMUM instead of the MINIMUM LS of successors — using the maximum would violate the constraint of not delaying any successor.
  • Setting LF of the last activity equal to something other than the project duration from the forward pass.
  • Confusing the forward-pass rule (MAX at merges) with the backward-pass rule (MIN at bursts).
  • Not completing the full backward pass before computing float values.

Formulas

Example

Activity D: ES=7, EF=10, LS=10, LF=13. TF = 10-7 = 3 days (verified: 13-10 = 3 days). Activity D is non-critical.

Formula

TF = LS - ES = LF - EF

Variables

TF = Total Float; LS = Late Start; ES = Early Start; LF = Late Finish; EF = Early Finish

Application

Computed for every activity after both the forward and backward passes are complete.

Example

Activity X has EF=8. Its only successor Y has ES=11. FF = 11-8 = 3 days. X can be delayed 3 days without affecting Y.

Formula

FF = min(ES of successors) - EF

Variables

FF = Free Float; ES of successors = the Early Start of each activity immediately following the activity in question; EF = Early Finish of the activity.

Application

Used when you need to know how much an activity can slip without affecting any immediate successor's schedule.

Exam Tips

  • Board exam questions on float usually give you four values (ES, EF, LS, LF) and ask for TF — apply TF = LS - ES directly.
  • If asked which activity is NOT on the critical path, identify the one with TF > 0.
  • Free float is tested less often than total float, but know that FF = min(ES_successors) - EF.
  • A common board question: 'By how many days can Activity X be delayed without affecting the project?' — this is asking for TF.

Key Points

  • Float (also called slack) measures the scheduling flexibility of a non-critical activity.
  • TOTAL FLOAT (TF): The maximum amount of time an activity can be delayed from its ES without delaying the PROJECT finish. TF = LS - ES = LF - EF.
  • FREE FLOAT (FF): The maximum amount of time an activity can be delayed from its ES without delaying the ES of ANY of its IMMEDIATE SUCCESSORS. FF = min(ES of successors) - EF of the activity.
  • TF ≥ FF always — total float is the more general measure.
  • Critical activities have TF = 0 (and FF = 0).
  • Non-critical activities have TF > 0 and may have FF = 0 (they can use their float only at the expense of sharing it with other activities on the same sub-path).
  • If an activity uses all its total float, it becomes critical — this is called a SECONDARY critical path.
  • Crashing (compressing) a non-critical activity does NOT shorten the project duration.

Definitions

Term

Total Float (TF)

Definition

The time an activity can be delayed beyond its ES without delaying the project completion. TF = LS - ES.

Importance

The primary float measure. Critical path activities have TF = 0. Most frequently tested in board exams.

Term

Free Float (FF)

Definition

The time an activity can be delayed beyond its ES without delaying the ES of any of its immediate successors.

Importance

FF ≤ TF. FF is the 'usable' float without borrowing from successor activities.

Term

Independent Float

Definition

Float available even if all predecessors finish at their latest times AND all successors start at their earliest times. Rarely tested but may appear in advanced problems.

Importance

Represents the most conservative scheduling flexibility. Always ≤ FF ≤ TF.

Section Title

4. Float (Slack) — Total Float and Free Float

Common Mistakes

  • Confusing Total Float and Free Float — TF is relative to the project; FF is relative to successors.
  • Computing TF as EF - ES (this gives the duration, not the float).
  • Stating that an activity with TF > 0 can be delayed by TF without affecting anything — it can affect successor float even if not the project finish.
  • Forgetting that using float on one activity reduces the float available to other activities on the same path.

Formulas

Example

Activity F: a=4, m=6, b=14 days. t_e = (4 + 4×6 + 14)/6 = (4+24+14)/6 = 42/6 = 7 days.

Formula

t_e = (a + 4m + b) / 6

Variables

t_e = expected (mean) activity duration; a = optimistic duration (shortest realistic time); m = most likely duration (modal value); b = pessimistic duration (longest realistic time)

Application

Compute t_e for each activity before constructing the network or performing passes. Replace fixed duration d with t_e in all CPM formulas.

Example

Activity F: a=4, b=14. σ² = ((14-4)/6)² = (10/6)² = (1.667)² = 2.78 days².

Formula

σ² = ((b - a) / 6)²

Variables

σ² = variance of activity duration; b = pessimistic estimate; a = optimistic estimate

Application

Compute for each critical path activity. Sum the variances of critical path activities to get project variance.

Example

Critical path activities have σ²: 4, 1, 4. σ_project = √(4+1+4) = √9 = 3 days.

Formula

σ_project = √(Σσ²_cp)

Variables

σ_project = project standard deviation; Σσ²_cp = sum of variances of ALL activities on the critical path

Application

After identifying the critical path and computing each activity's σ², sum only the critical path variances and take the square root.

Example

T_E = 30 days, σ_project = 3 days, target T = 33 days. Z = (33-30)/3 = 1.00. From Z-table: P = 84.1%.

Formula

Z = (T - T_E) / σ_project

Variables

Z = standard normal deviate; T = target completion date; T_E = expected project duration (sum of t_e on critical path); σ_project = project standard deviation

Application

After computing T_E and σ_project, use this Z-score with a standard normal (Z) table to find P(finish by T).

Exam Tips

  • Memorize the PERT formulas as a pair: t_e = (a+4m+b)/6 and σ = (b-a)/6. The σ² = [σ]² naturally.
  • When asked for project standard deviation from variances, ALWAYS sum σ² first, THEN take √ — never sum σ directly.
  • For probability problems, set up the Z-score clearly: Z = (T - T_E)/σ_project, then look up the Z-table. Board exams often provide the Z-table or specify the probability for given Z values.
  • If the problem gives you t_e and asks you to back-calculate a or b, set up the t_e equation algebraically and solve — this is a common variation.
  • A quick check: t_e should always be between a and b, and t_e ≥ m only if b is much larger than m (skewed distribution).

Key Points

  • PERT (Program Evaluation and Review Technique) is used when activity durations are UNCERTAIN and cannot be fixed with confidence.
  • Three time estimates are used for each activity: optimistic (a), most likely (m), and pessimistic (b).
  • The expected (mean) duration t_e uses a BETA distribution approximation: t_e = (a + 4m + b) / 6.
  • The most likely estimate m is WEIGHTED BY 4 — a critical formula detail tested every board cycle.
  • The variance of each activity: σ² = ((b - a) / 6)².
  • The standard deviation of each activity: σ = (b - a) / 6.
  • For the CRITICAL PATH, the project expected duration = sum of t_e values of critical activities.
  • Project variance = SUM of σ² values of critical path activities only (not all activities).
  • Project standard deviation: σ_project = √(Σσ²_critical path).
  • To find the probability of completing by a target date T: compute Z = (T - T_E) / σ_project, then use the standard normal distribution table.
  • PERT uses the same forward/backward pass and float calculations as CPM, but with t_e replacing fixed durations.

Definitions

Term

Optimistic Estimate (a)

Definition

The shortest time in which an activity can realistically be completed, assuming everything goes perfectly.

Importance

Lower bound of the three-point estimate. Used in both t_e and σ² formulas.

Term

Most Likely Estimate (m)

Definition

The most probable duration for an activity under normal conditions. The MODE of the distribution.

Importance

Receives weight 4 in the t_e formula — the most critical detail to remember about PERT.

Term

Pessimistic Estimate (b)

Definition

The longest time an activity might take if nearly everything goes wrong (excluding catastrophic events).

Importance

Upper bound. Together with a, it determines the activity variance σ².

Term

Beta Distribution

Definition

The probability distribution assumed for individual activity durations in PERT. The t_e = (a+4m+b)/6 formula is derived from this distribution.

Importance

Justifies the PERT formula. You do not need to derive it for board exams, but understanding which distribution is assumed is part of the theory.

Section Title

5. PERT — Three-Point Estimates, Expected Duration, and Variance

Common Mistakes

  • Forgetting the weight of 4 for m: writing t_e = (a + m + b) / 3 instead of (a + 4m + b) / 6.
  • Dividing by 3 instead of 6 in the t_e formula.
  • Including the variance of NON-critical activities in the project variance — only critical path variances are summed.
  • Computing σ = (b-a)/6 but then squaring it incorrectly: σ² = (b-a)²/6 instead of the correct ((b-a)/6)² = (b-a)²/36.
  • Using σ_project instead of σ²_project when summing — always sum VARIANCES (σ²), then take the square root at the end.

Formulas

Example

Activity G: NC = ₱50,000, CC = ₱80,000, ND = 8 days, CD = 5 days. Crash Slope = (80,000 - 50,000)/(8-5) = ₱10,000/day.

Formula

Crash Slope = (CC - NC) / (ND - CD)

Variables

CC = Crash Cost; NC = Normal Cost; ND = Normal Duration; CD = Crash Duration (minimum achievable)

Application

Compute for each critical activity. Rank by crash slope (ascending) to determine the cheapest activities to crash first.

Exam Tips

  • Board problems on crashing usually ask: 'What is the minimum cost to reduce project duration by X days?' — apply the crash slope ranking procedure.
  • Always state the critical path at each step of the crashing process, as it may change.
  • If two paths become simultaneously critical, you must crash one activity on each path simultaneously — add both their crash slopes for the combined cost.
  • The total crash cost = Σ(crash slope × days crashed) for each activity crashed.

Key Points

  • Crashing means REDUCING the duration of an activity by adding resources (more workers, equipment, overtime) at an additional cost.
  • The CRASH COST SLOPE (cost per day saved) = (Crash Cost - Normal Cost) / (Normal Duration - Crash Duration).
  • Only crashing CRITICAL PATH activities shortens the project duration.
  • Among critical path activities, crash the one with the LOWEST cost slope first (cheapest to crash).
  • After each crash iteration, re-examine the network — the critical path may shift as you compress it.
  • Continue crashing until: (a) the target duration is reached, (b) all critical activities are fully crashed, or (c) a NEW path becomes critical at equal length, requiring simultaneous crashing of multiple paths.
  • The minimum project duration achievable is bounded by the fully crashed critical path.
  • The optimal solution balances crashing cost against indirect cost savings (overhead) from shorter duration.

Definitions

Term

Normal Duration (ND)

Definition

The activity duration under normal (un-crashed) resource allocation.

Importance

Baseline duration used in the CPM network before crashing.

Term

Crash Duration (CD)

Definition

The minimum achievable duration for an activity with maximum additional resources.

Importance

Lower bound for crashing — you cannot reduce an activity below its crash duration.

Term

Crash Slope

Definition

The additional direct cost per unit of time saved by crashing. Units: ₱/day (or $/day).

Importance

The selection criterion for crashing: always crash the activity with the lowest slope first.

Section Title

6. Crashing — Cost–Time Trade-offs

Common Mistakes

  • Crashing a NON-critical activity and expecting to shorten the project — this only wastes money.
  • Forgetting to re-evaluate the critical path after each crashing step — new paths may become critical.
  • Computing crash slope with the formula inverted: (ND - CD)/(CC - NC) — this gives days saved per peso, not pesos per day.
  • Crashing beyond the crash duration — each activity has a physical lower limit on duration regardless of resources added.

Connections

  • CPM/PERT scheduling is the quantitative backbone of Construction Project Management, connecting directly to Resource Allocation (leveling resources using float), Cost Management (crashing uses direct cost curves), and Risk Management (PERT's probabilistic framework formalizes schedule risk).
  • The forward/backward pass procedure is an application of dynamic programming — the same MAX/MIN logic appears in Operations Research network flow problems tested in Engineering Mathematics.
  • PERT's Z-score probability calculation directly applies Normal Distribution and Statistical Inference from Engineering Mathematics and Statistics, reinforcing the connection between probability theory and practical engineering decisions.
  • Crashing cost-time trade-offs are linked to Construction Cost Estimating (direct vs. indirect costs) and to Engineering Economy (present worth of cost savings from shortened duration — tested in both Construction Management and Engineering Economy boards).
  • Activity sequencing and dependency logic connect to Construction Methods — understanding which structural activities (e.g., formwork, rebar, concrete curing per NSCP 2015 Chapter 4 requirements) physically cannot be reversed or parallelized is essential for building realistic networks.
  • Float management relates to Contract Administration under Philippine construction law (RA 4566, Contractor's License Law; and RA 9184, Government Procurement Reform Act) — delays in critical activities can trigger liquidated damages clauses in government contracts.
  • The concept of project minimum duration from CPM is consistent with the scheduling requirements implicit in DPWH Standard Specifications for Roads and Bridges and the implementing rules of RA 544, which govern the professional responsibilities of licensed civil engineers in project delivery.

Exam Strategy

For CPM/PERT problems in the PRC Board Exam: (1) ALWAYS start by identifying all activities, durations, and predecessors — draw or mentally organize the network before computing anything. (2) Execute the FULL forward pass (left to right, MAX at merges), then the FULL backward pass (right to left, MIN at bursts) — do not skip steps. (3) Compute TF for every activity; those with TF = 0 are critical. (4) For PERT problems, compute t_e and σ² for each activity FIRST, then proceed with the CPM pass using t_e as the duration. (5) For probability questions, set up Z = (T - T_E)/σ_project clearly. (6) For crashing questions, rank critical activities by crash slope and crash cheapest first, re-checking the critical path after each step. Allocate 8–12 minutes for a full network problem. Partial marks are awarded for correct formulas and intermediate steps even if the final answer is wrong — always show your work. The most common board trap is declaring the SHORTEST path critical instead of the longest — write the path lengths explicitly before declaring the critical path.

Quick Review Questions

An activity has a = 5, m = 8, b = 17 days. What are the expected duration t_e and variance σ²?

t_e = (a + 4m + b)/6 = (5 + 4×8 + 17)/6 = (5 + 32 + 17)/6 = 54/6 = 9 days. σ² = ((b-a)/6)² = ((17-5)/6)² = (12/6)² = (2)² = 4 days².

A network has three paths with durations 12, 15, and 14 days. What is the project duration, and what is the total float on the 12-day path?

The critical path is the longest = 15 days. This is also the project duration. The 12-day path has TF = 15 - 12 = 3 days (it can be delayed 3 days before it becomes critical).

Activity X has ES = 4 days, duration d = 6 days, and LF = 14 days. Find EF, LS, and TF.

EF = ES + d = 4 + 6 = 10 days. LS = LF - d = 14 - 6 = 8 days. TF = LS - ES = 8 - 4 = 4 days (verify: LF - EF = 14 - 10 = 4 days ✓). TF > 0, so Activity X is NOT on the critical path.

The critical path has three activities with variances 4, 1, and 4 days². What is the project standard deviation?

Project variance = Σσ²_cp = 4 + 1 + 4 = 9 days². Project standard deviation = √9 = 3 days. Remember: sum variances FIRST, then take the square root — never sum standard deviations directly.

An activity has ES = 7, EF = 10, LS = 10, LF = 13. Is it on the critical path? Compute TF.

TF = LS - ES = 10 - 7 = 3 days (or equivalently LF - EF = 13 - 10 = 3 days). Since TF ≠ 0, the activity is non-critical. A critical activity requires TF = 0, which would mean ES = LS and EF = LF.

Activity A (8 days) and Activity B (10 days) both precede Activity C (4 days). What is the ES of C and the project duration?

Forward pass: A runs from ES=0 to EF=8; B runs from ES=0 to EF=10. C starts after BOTH A and B finish: ES_C = max(EF_A, EF_B) = max(8, 10) = 10 days. EF_C = ES_C + d_C = 10 + 4 = 14 days = project duration. Critical path is B → C.

The expected project duration is 45 days with σ_project = 5 days. What is the Z-score for a target completion date of 50 days?

Z = (T - T_E) / σ_project = (50 - 45) / 5 = 5/5 = 1.00. This corresponds to approximately 84.1% probability of completing by day 50 (from standard normal tables, P(Z ≤ 1.00) ≈ 0.8413).

Crashing Activity G costs ₱10,000/day. Crashing Activity H (also on the critical path) costs ₱7,000/day. Which should be crashed first to shorten the project at minimum cost?

Crash the critical path activity with the LOWEST crash slope (cost per day) first. H has ₱7,000/day < G's ₱10,000/day. Crashing H first saves time at a lower cost. Continue with H until it is fully crashed or a new critical path emerges, then re-evaluate.

What is the key difference between Total Float and Free Float?

TF = LS - ES; it measures slack relative to the project's end date. FF = min(ES of successors) - EF; it measures slack relative to successors. TF ≥ FF always. Critical activities have both TF = 0 and FF = 0. Non-critical activities may have TF > 0 but FF = 0 if they share float with downstream activities.

In PERT, which time estimate receives the greatest weight in the t_e formula, and what is that weight?

t_e = (a + 4m + b)/6. The weights are: a gets weight 1, m gets weight 4, b gets weight 1. Total weight = 6. This reflects the assumption that the most probable duration should dominate the expected value. The formula is derived from the beta distribution. The most common board exam error is to use (a + m + b)/3, which is wrong.

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