Elementary Algebra - Revision Notes
Algebra is the bridge between arithmetic and higher mathematics. For the LET (Elementary Level), this chapter tests your ability to manipulate algebraic expressions, solve equations and inequalities, work with systems of equations, apply special products and factoring, solve quadratic equations, and — most critically — translate word problems into mathematical sentences. As a future Grade 1–6 teacher, you will model algebraic thinking for your pupils through DepEd's K–12 BEC Curriculum (e.g., patterns and algebra in Grade 3–6 Mathematics). Mastery here means mastery of reasoning, not just calculation. Most LET errors in this domain come from sign slips, so work slowly and deliberately. This review covers every high-yield topic and includes worked examples, formula sheets, common mistakes, and exam strategies.
1. Algebraic Expressions and Laws of Exponents
Formulas
aᵐ · aⁿ = aᵐ⁺ⁿ
Example
x³ · x⁴ = x³⁺⁴ = x⁷
Variables
a = any nonzero base; m, n = exponents
Application
Use when MULTIPLYING powers with the SAME base — add the exponents.
aᵐ ÷ aⁿ = aᵐ⁻ⁿ
Example
x⁵ ÷ x² = x⁵⁻² = x³
Variables
a = any nonzero base; m, n = exponents
Application
Use when DIVIDING powers with the SAME base — subtract the exponents.
(aᵐ)ⁿ = aᵐⁿ
Example
(x²)³ = x²ˣ³ = x⁶
Variables
a = base; m, n = exponents
Application
Use for a POWER OF A POWER — multiply the exponents.
(ab)ⁿ = aⁿbⁿ
Example
(2x)³ = 2³ · x³ = 8x³
Variables
a, b = bases; n = exponent
Application
Use for the POWER OF A PRODUCT — apply the exponent to each factor.
a⁰ = 1 (a ≠ 0)
Example
(5xy)⁰ = 1
Variables
a = any nonzero base
Application
Any nonzero base raised to the zero power equals 1.
a^(-n) = 1/aⁿ
Example
3^(-2) = 1/3² = 1/9
Variables
a = nonzero base; n = positive integer
Application
Negative exponent means the reciprocal of the positive exponent.
Exam tips
- The LET frequently tests combined operations with exponents. Practice expressions like (2x³)² × 3x step by step: first square the parentheses to get 4x⁶, then multiply by 3x to get 12x⁷.
- When evaluating expressions, rewrite each substitution explicitly in parentheses before computing to avoid sign errors.
- Memorize all six exponent laws as a single table — the LET often presents items that require two or three laws in sequence.
- Watch for the phrase 'simplify' — it signals that you must apply exponent laws to reduce the expression to its simplest form.
Key points
- A TERM is a number, a variable, or a product of both: 5, x, -3xy². The COEFFICIENT is the numerical factor; the DEGREE is the sum of variable exponents in a term.
- LIKE TERMS have identical variable parts and CAN be combined: 4x + 3x = 7x. Unlike terms (4x and 3x²) CANNOT be combined.
- EVALUATING an expression means substituting values for variables and following the order of operations (PEMDAS/GEMDAS). Always place substituted negative numbers in parentheses to avoid sign errors.
- LAWS OF EXPONENTS are the most frequently tested rules in this section. Memorize all six laws and their conditions.
- The zero exponent rule: any nonzero base raised to 0 equals 1 (a⁰ = 1, a ≠ 0). Example: 7⁰ = 1.
- Negative exponents indicate reciprocals: a^(-n) = 1/aⁿ. Example: 2^(-3) = 1/8.
- When simplifying expressions with multiple exponent laws, apply them in order: parentheses first, then outer exponents, then multiply/divide.
Definitions
Term
A single number, variable, or product of numbers and variables (e.g., 5, x, -3xy²).
Importance
Understanding terms is essential for combining like terms and simplifying expressions — a basic LET algebra skill.
Coefficient
The numerical factor of a term. In -3xy², the coefficient is -3.
Importance
Identifying coefficients correctly prevents errors when combining like terms or applying the distributive property.
Degree of a Term
The sum of the exponents of all variables in a term. The degree of 4x²y³ is 2 + 3 = 5.
Importance
Degree determines how terms are classified and affects how equations are solved.
Like Terms
Terms that have exactly the same variable parts (same variables raised to the same powers). Example: 4x²y and -7x²y are like terms.
Importance
Only like terms can be combined through addition or subtraction — a fundamental simplification rule.
Common mistakes
- Adding exponents when the bases are DIFFERENT: x² · y³ ≠ (xy)⁵. The product law only applies to the SAME base.
- Applying a power to only one factor: (2x)³ ≠ 2x³. The correct answer is 8x³ because 2³ = 8.
- Forgetting that a⁰ = 1, not 0. Many examinees write 5⁰ = 0 — this is wrong.
- Sign errors when substituting negative values: if x = -2, then x² = (-2)² = 4, NOT -4.
- Combining unlike terms: 3x² + 5x cannot be simplified to 8x² or 8x — they are unlike terms.
2. Linear Equations and Inequalities
Formulas
ax + b = c → x = (c - b) / a
Example
2x + 5 = 11 → 2x = 6 → x = 3. Check: 2(3) + 5 = 11 ✓
Variables
a = coefficient of x; b = constant added to variable term; c = constant on right side
Application
Standard form of a one-variable linear equation. Subtract b from both sides, then divide by a.
ax + b > c (or <, ≥, ≤) → reverse symbol if dividing/multiplying by negative a
Example
-2x < 6 → divide both sides by -2 and REVERSE: x > -3
Variables
a = coefficient; b, c = constants
Application
Solve like an equation BUT reverse the inequality symbol when multiplying or dividing by a negative number.
Exam tips
- For LET word problems, the most important step is SETTING UP the equation correctly. The solving is mechanical once the equation is written.
- When solving multi-step equations, write each step on its own line. This prevents sign errors and helps you track your work.
- Memorize the reversal rule: 'FLIP the sign when you FLIP the sign of what you divide by.' Practice with at least five inequality problems.
- LET items may ask you to identify which inequality symbol goes in a blank based on a word problem — translate 'at least' as ≥ and 'at most' as ≤.
Key points
- A LINEAR EQUATION has the variable to the first power only (no x², x³, etc.). Its solution is a SINGLE value.
- The general solving strategy: (1) Clear parentheses using the distributive property; (2) Combine like terms on each side; (3) Move variable terms to one side; (4) Move constant terms to the other side; (5) Divide by the coefficient of the variable.
- INEQUALITIES are solved using the same steps as equations, with ONE critical difference: when you MULTIPLY or DIVIDE both sides by a NEGATIVE number, you must REVERSE the inequality symbol.
- The solution of a linear inequality is a RANGE of values, not a single number. It can be expressed as an inequality (x ≤ -3), in interval notation ((-∞, -3]), or shown on a number line.
- CHECKING your answer is essential: substitute your solution back into the original equation and verify both sides are equal.
- The DISTRIBUTIVE PROPERTY (a(b + c) = ab + ac) is the foundation of solving equations with parentheses.
Definitions
Linear Equation
An equation where the variable appears to the first power only. Its graph is a straight line. Example: 3x - 7 = 11.
Importance
The most common equation type in LET word problems — mastering the solution procedure is non-negotiable.
Inequality
A mathematical statement using <, >, ≤, or ≥ to show that two expressions are not necessarily equal. Example: x + 3 > 7.
Importance
LET items often ask for the solution set or ask which values satisfy a given inequality.
Distributive Property
a(b + c) = ab + ac. Multiplication distributes over addition (and subtraction).
Importance
The single most-used property in algebra — used to clear parentheses before solving and to factor expressions.
Common mistakes
- FORGETTING TO REVERSE the inequality symbol when dividing by a negative: -2x < 6 gives x > -3, NOT x < -3.
- Adding instead of subtracting when moving terms: in 2x + 5 = 11, subtracting 5 gives 2x = 6, NOT 2x = 16.
- Distributing only to the first term: 3(2x - 4) ≠ 6x - 4. The correct distribution gives 6x - 12.
- Stopping after getting 4x = 16 without dividing to find x = 4.
- Checking the answer in a simplified version of the equation rather than the ORIGINAL — always check in the original.
3. Systems of Linear Equations
Formulas
Substitution: From Eq.1, express x = (expression in y), then substitute into Eq.2
Example
x + 2y = 11 and 3x - y = 5. From Eq.1: x = 11 - 2y. Substitute: 3(11 - 2y) - y = 5 → 33 - 7y = 5 → y = 4 → x = 3. Solution: (3, 4).
Variables
x, y = unknowns in the system
Application
Best when one equation already has an isolated variable or a coefficient of 1.
Elimination: Multiply equations by constants to make one variable's coefficients equal, then add/subtract equations
Example
2x + 3y = 12 and 4x - 3y = 6. Add both: 6x = 18 → x = 3. Substitute: 2(3) + 3y = 12 → y = 2. Solution: (3, 2).
Variables
x, y = unknowns; multipliers chosen to create equal or opposite coefficients
Application
Best when neither equation has an isolated variable or a coefficient of 1.
Exam tips
- For LET coin/money problems, always write TWO equations: one for the COUNT of items and one for the TOTAL VALUE. This naturally forms a system.
- If elimination requires fractions, switch to substitution — it is usually faster and less error-prone for LET-style problems.
- Identify the type of system before solving: if you see that one equation is a multiple of the other, it is dependent — there is no unique solution.
- Practice translating two-condition word problems (e.g., 'the sum is 12 AND the difference is 4') directly into a system of two equations.
Key points
- A SYSTEM OF LINEAR EQUATIONS is two or more equations in two or more unknowns. The solution is the ORDERED PAIR (x, y) that satisfies ALL equations simultaneously.
- THREE METHODS to solve: (1) SUBSTITUTION — solve one equation for one variable, substitute into the other; (2) ELIMINATION — add or subtract equations to cancel one variable; (3) GRAPHING — the solution is the INTERSECTION POINT of the two lines.
- THREE TYPES OF SOLUTIONS: (1) CONSISTENT AND INDEPENDENT — one solution (lines intersect at one point); (2) INCONSISTENT — no solution (lines are parallel, no intersection); (3) DEPENDENT — infinitely many solutions (same line, identical equations).
- Substitution method is most efficient when one variable has a coefficient of 1 or -1, making isolation easy.
- Elimination method is most efficient when coefficients of one variable are the same or are easy multiples of each other.
- Always CHECK your solution pair in BOTH original equations.
Definitions
System of Linear Equations
Two or more linear equations with the same set of variables, considered together. The solution satisfies all equations simultaneously.
Importance
Many LET word problems (coin problems, age problems, mixture problems) are most cleanly solved using a two-equation system.
Consistent and Independent
A system with exactly ONE solution. The two lines intersect at one point.
Importance
Most LET system problems are consistent and independent — they have a unique answer.
Inconsistent
A system with NO solution. The two lines are parallel and never intersect.
Importance
LET items may ask you to identify or classify a system — knowing the three types is essential.
Dependent
A system with INFINITELY MANY solutions. The two equations represent the same line.
Importance
Recognizing dependence (e.g., one equation is a multiple of the other) prevents wasted effort trying to find a unique solution.
Common mistakes
- Substituting into the SAME equation you solved from, instead of the OTHER equation — this gives an identity (0 = 0) and no new information.
- Forgetting to distribute the multiplier when substituting: substituting x = 11 - 2y into 3x gives 3(11 - 2y) = 33 - 6y, not 33 - 2y.
- Not scaling BOTH terms of an equation when multiplying to eliminate: multiply EVERY term, including the constant.
- Writing the solution as two separate values (x = 3, y = 4) instead of the required ordered pair (3, 4).
- Checking only in one equation instead of both — an error may be hidden if only one is checked.
4. Special Products and Factoring
Formulas
(a + b)² = a² + 2ab + b²
Example
(x + 5)² = x² + 2(x)(5) + 5² = x² + 10x + 25
Variables
a, b = any algebraic expressions
Application
Square of a sum. The middle term is TWICE the product of the two terms.
(a - b)² = a² - 2ab + b²
Example
(2x - 3)² = 4x² - 12x + 9
Variables
a, b = any algebraic expressions
Application
Square of a difference. The middle term is NEGATIVE twice the product.
(a + b)(a - b) = a² - b²
Example
(x + 7)(x - 7) = x² - 49
Variables
a, b = any algebraic expressions
Application
Product of sum and difference. Results in ONLY two terms — the difference of squares.
FOIL: (x + p)(x + q) = x² + (p + q)x + pq
Example
(x + 3)(x + 5) = x² + 8x + 15 (since 3 + 5 = 8 and 3 × 5 = 15)
Variables
p, q = constants in the binomials
Application
Multiplying two binomials. For factoring: find p and q such that p + q = b and pq = c in x² + bx + c.
Rational Expression: (numerator factored) / (denominator factored) → cancel common factors
Example
(x² - 9)/(x - 3) = (x + 3)(x - 3)/(x - 3) = x + 3 (for x ≠ 3)
Variables
Numerator and denominator are polynomials
Application
Factor both numerator and denominator completely, then cancel any common factors.
Exam tips
- The LET tests special products in BOTH directions: given a product, find the factored form AND given a factored form, find the expanded product.
- For general trinomial factoring (x² + bx + c), list ALL factor pairs of c, then check which pair sums to b. Be systematic.
- Memorize the sign patterns: (a + b)² has all positive terms; (a - b)² has a negative middle term only; (a + b)(a - b) has NO middle term.
- When simplifying rational expressions on the LET, always state the restriction (x ≠ 3 in the example above) — but in multiple choice, focus on the simplified form.
Key points
- SPECIAL PRODUCTS are patterns for multiplying binomials that you must recognize INSTANTLY in both directions (expanded and factored). Memorizing these patterns allows you to multiply without FOIL and to factor by pattern recognition.
- FACTORING is the reverse of multiplication. It is one of the most frequently tested skills in the LET algebra section.
- ALWAYS check for a COMMON MONOMIAL FACTOR first before applying any other factoring technique.
- THREE MAIN SPECIAL PRODUCT/FACTORING PATTERNS: (1) Square of a binomial; (2) Difference of two squares; (3) General trinomial (FOIL in reverse).
- The GENERAL TRINOMIAL x² + bx + c factors into (x + p)(x + q) where p × q = c and p + q = b. Find the factor pair, then write the binomials.
- Simplifying RATIONAL EXPRESSIONS (algebraic fractions) requires factoring numerator and denominator, then cancelling COMMON FACTORS — not just terms.
Definitions
Common Monomial Factor (CMF)
The greatest factor (number and/or variable) that divides evenly into every term of a polynomial. Always factor this out FIRST.
Importance
Overlooking the CMF makes subsequent factoring harder and can lead to incomplete factoring — a frequent LET error.
Difference of Two Squares
An expression of the form a² - b², which factors as (a + b)(a - b). Both terms must be PERFECT SQUARES and there must be a MINUS sign between them.
Importance
Appears frequently in simplifying rational expressions and in LET multiple-choice items asking for the factored form.
Perfect Square Trinomial
A trinomial of the form a² ± 2ab + b², which factors as (a ± b)². The first and last terms are perfect squares, and the middle term is twice the product of their square roots.
Importance
Recognizing this pattern speeds up factoring and is essential for completing the square in quadratic equations.
Common mistakes
- Forgetting the MIDDLE TERM in squaring a binomial: (x + 5)² ≠ x² + 25. The correct answer is x² + 10x + 25.
- Applying the difference of squares to a SUM: x² + 25 CANNOT be factored using this pattern (sum of squares is prime over the reals).
- Cancelling TERMS instead of FACTORS in rational expressions: (x² + 5)/(x + 5) ≠ x. You can only cancel factors after factoring completely.
- Incorrect signs in general trinomial factoring: for x² - 5x + 6, the numbers are -2 and -3 (both negative), giving (x - 2)(x - 3), not (x + 2)(x + 3).
- Not checking for a CMF first: 2x² - 8 should first be factored as 2(x² - 4), then as 2(x + 2)(x - 2).
5. Quadratic Equations
Formulas
Quadratic Formula: x = [-b ± √(b² - 4ac)] / (2a)
Example
For 2x² + 3x - 5 = 0: a = 2, b = 3, c = -5. Discriminant = 9 + 40 = 49. x = (-3 ± 7)/4. So x = 1 or x = -5/2.
Variables
a = coefficient of x²; b = coefficient of x; c = constant term
Application
Use when factoring is not possible or not obvious. Works for ALL quadratic equations.
Discriminant: D = b² - 4ac
Example
For x² - 4x + 4 = 0: D = 16 - 16 = 0 → one repeated real root (x = 2).
Variables
a, b, c = coefficients from ax² + bx + c = 0
Application
Evaluate BEFORE solving to predict the number and type of roots.
Square Root Method: x² = k → x = ±√k
Example
x² = 49 → x = ±7. Or: x² - 81 = 0 → x² = 81 → x = ±9.
Variables
k = positive constant (when b = 0 in the quadratic)
Application
Use when the equation has NO linear term (no bx). Isolate x² first, then take the square root of both sides.
Exam tips
- The LET often asks for the nature of roots using the discriminant — memorize: D > 0 (two real roots), D = 0 (one repeated root), D < 0 (no real roots).
- Try factoring FIRST. If the discriminant is a perfect square, the equation factors nicely. If not, use the formula.
- After solving, VERIFY by substituting each root back into the original equation — even under time pressure, checking one root quickly confirms your work.
- For items that ask for the SUM or PRODUCT of roots, use Vieta's formulas: sum = -b/a and product = c/a.
Key points
- A QUADRATIC EQUATION has the standard form ax² + bx + c = 0, where a ≠ 0. The variable appears to the SECOND POWER.
- THREE METHODS OF SOLUTION: (1) FACTORING — fastest when applicable; (2) SQUARE ROOT METHOD — for equations with no bx term (ax² = c); (3) QUADRATIC FORMULA — always works.
- The ZERO-PRODUCT PROPERTY: if A × B = 0, then A = 0 OR B = 0 (or both). This is the legal basis for setting each factor equal to zero.
- The DISCRIMINANT (b² - 4ac) determines the NATURE OF THE ROOTS without actually solving: positive → two distinct real roots; zero → one repeated real root; negative → no real roots (complex roots).
- Quadratic equations can have AT MOST TWO roots.
- Always REWRITE the equation in standard form (ax² + bx + c = 0) BEFORE applying any method.
Definitions
Quadratic Equation
A polynomial equation of degree 2, written in standard form as ax² + bx + c = 0 (a ≠ 0).
Importance
The starting point for any solution method — always rewrite in standard form before solving.
Zero-Product Property
If the product of two factors equals zero, then at least one factor must equal zero: if AB = 0, then A = 0 or B = 0.
Importance
This is the LEGAL JUSTIFICATION for the factoring method — you must understand why you set each factor to zero.
Discriminant
The expression b² - 4ac under the radical in the quadratic formula. It determines the number and type of roots.
Importance
LET items may ask directly: 'What is the nature of the roots of this equation?' — compute the discriminant to answer.
Roots (Solutions)
The values of the variable that satisfy the quadratic equation. A quadratic has at most two roots.
Importance
The LET asks for roots, solutions, zeros, and x-intercepts — these all refer to the same values.
Common mistakes
- Forgetting the ± in the square root method: x² = 49 has TWO solutions, x = 7 AND x = -7.
- Dividing by x to solve x² = 5x → x = 5, losing the solution x = 0. Never divide by a variable — factor instead: x(x - 5) = 0, giving x = 0 or x = 5.
- Misidentifying a, b, c when the equation is not in standard form: always rearrange to ax² + bx + c = 0 BEFORE reading off the coefficients.
- Arithmetic error in the discriminant: be careful with the signs: b² - 4ac where c is negative adds 4|a||c| to b².
- Setting only ONE factor to zero: (x - 3)(x + 5) = 0 requires BOTH x - 3 = 0 AND x + 5 = 0 to find both roots.
6. Translating Words into Equations (Word Problems)
Formulas
d = rt (Distance = Rate × Time)
Example
Two jeepneys travel toward each other at 40 kph and 60 kph. If they are 200 km apart, when do they meet? 40t + 60t = 200 → 100t = 200 → t = 2 hours.
Variables
d = distance; r = rate (speed); t = time
Application
Write a separate d = rt expression for each object in a motion problem, then set up an equation using the given condition (same distance, same time, etc.).
Count equation: x + y = total number of items; Value equation: (value₁)x + (value₂)y = total value
Example
₱5 coins (x) and ₱10 coins (y), 12 coins worth ₱95: x + y = 12 and 5x + 10y = 95. Solving: x = 5, y = 7.
Variables
x, y = numbers of each type of item
Application
Used for coin problems, ticket problems, mixture-quantity problems.
Exam tips
- For every LET word problem, write 'Let n = ...' before anything else. This forces clarity and prevents mid-solution confusion.
- After setting up the equation, re-read the problem to confirm your equation captures ALL given conditions.
- Translate the key word phrases immediately: 'sum' = +, 'difference' = -, 'product' = ×, 'quotient' = ÷, 'is' = =, 'at least' = ≥, 'at most' = ≤.
- In number problems, verify by substituting your answer back into the WORDS of the problem, not just the equation.
- For problems with two unknowns (coins, ages, etc.), set up a SYSTEM of equations — this is more reliable than trying to express everything in one variable.
Key points
- TRANSLATION is the most tested skill in the LET algebra section. The ability to convert a verbal description into a mathematical equation is the make-or-break skill.
- POLYA'S FOUR-STEP PROBLEM-SOLVING MODEL (relevant to DepEd K–12 BEC): (1) UNDERSTAND the problem — identify what is asked and what is given; (2) DEVISE A PLAN — choose a strategy; (3) CARRY OUT THE PLAN — solve; (4) LOOK BACK — check the answer against the original conditions.
- Carefully distinguish 'n - 5' (5 less than a number) from '5 - n' (a number less than 5). Order matters in subtraction.
- CONSECUTIVE INTEGERS: n, n + 1, n + 2 ... CONSECUTIVE EVEN OR ODD: n, n + 2, n + 4 ... (same formula for both — the parity is determined by the starting value of n).
- COIN/MONEY PROBLEMS require TWO equations: one for the COUNT and one for the TOTAL VALUE.
- MOTION PROBLEMS use: DISTANCE = RATE × TIME (d = rt), with a separate expression for each moving object.
- AGE PROBLEMS: Define present ages, then add or subtract the number of years for future/past ages.
- Always DEFINE YOUR VARIABLE explicitly before writing the equation ('Let n = the unknown number').
Definitions
Consecutive Integers
Integers that follow each other in order with a difference of 1: n, n + 1, n + 2, ...
Importance
A recurring LET word-problem type — always use n, n + 1, n + 2 as your representation.
Consecutive Even/Odd Integers
Even or odd integers that follow in order with a difference of 2: n, n + 2, n + 4. For odd, n must be odd; for even, n must be even.
Importance
The representation is the SAME for both even and odd (differ by 2) — parity is determined by the value of n.
Polya's Problem-Solving Model
A four-step approach: Understand → Plan → Solve → Check. Standard in the DepEd K–12 Mathematics curriculum.
Importance
The LET tests not just computation but the process of problem-solving — understanding Polya's steps is both an algebra skill and a professional teaching competency.
Common mistakes
- '5 less than a number' is n - 5, NOT 5 - n. The subtracted quantity comes FIRST in the phrase but SECOND in the expression.
- Using n, n + 1, n + 3 for consecutive integers — the correct consecutive integers differ by EXACTLY 1.
- Setting up the equation for what you want to find but forgetting to define the variable first, leading to ambiguity.
- Not checking the answer in the WORDS of the problem — an answer may satisfy the equation but violate a condition ('both numbers are positive') stated in the problem.
- In age problems, adding the number of years only to ONE person's age instead of both.
7. Functions, the Cartesian Plane, and Slope
Formulas
Slope: m = (y₂ - y₁) / (x₂ - x₁)
Example
Slope through (1, 2) and (4, 11): m = (11 - 2)/(4 - 1) = 9/3 = 3. The line rises 3 units for every 1 unit to the right.
Variables
(x₁, y₁) and (x₂, y₂) = any two distinct points on the line
Application
Use to find the steepness and direction of a line. Always subtract in the SAME ORDER (y₂ - y₁ over x₂ - x₁).
Slope-intercept form: y = mx + b
Example
In y = 3x - 2, the slope is 3 and the y-intercept is -2 (the line crosses the y-axis at the point (0, -2)).
Variables
m = slope; b = y-intercept (where the line crosses the y-axis)
Application
Use to quickly identify slope and y-intercept from a linear equation or to write the equation of a line.
Exam tips
- For LET items on slope: identify the two points clearly, label them (x₁, y₁) and (x₂, y₂), then substitute carefully.
- The y-intercept is the value of y when x = 0. In y = mx + b, the y-intercept is simply b.
- To find the x-intercept (where the line crosses the x-axis), set y = 0 and solve for x.
- Know the four quadrant sign patterns: memorize 'All Students Take Calculus' as a mnemonic for which trig ratios are positive (I: All, II: Sine, III: Tangent, IV: Cosine), which also helps recall quadrant signs.
Key points
- A FUNCTION assigns exactly ONE output value to each input value. Every x-value maps to exactly one y-value. Notation: f(x) = ... (read 'f of x').
- To EVALUATE a function, substitute the given value for x in the function rule. Example: if f(x) = 2x² - 3x + 1, then f(-2) = 2(4) - 3(-2) + 1 = 8 + 6 + 1 = 15.
- The CARTESIAN PLANE has two perpendicular axes: horizontal (x-axis) and vertical (y-axis), meeting at the ORIGIN (0, 0). Points are located by ordered pairs (x, y).
- The plane is divided into FOUR QUADRANTS numbered counter-clockwise from the upper right: QI (+, +), QII (-, +), QIII (-, -), QIV (+, -).
- SLOPE-INTERCEPT FORM: y = mx + b, where m = slope and b = y-intercept.
- SLOPE (m) = rise/run = (y₂ - y₁)/(x₂ - x₁). Positive slope rises to the right; negative slope falls; zero slope is horizontal; UNDEFINED slope is vertical.
- The slope connects directly to RATE of change in motion problems — a key link between algebra and real-world applications.
Definitions
Function
A rule that assigns exactly one output (y-value) to each input (x-value). Formally: for every x in the domain, there is exactly one y in the range.
Importance
The concept of function is foundational in algebra and appears in LET items on evaluating expressions and interpreting graphs.
Slope
The measure of steepness of a line, defined as rise over run: m = (y₂ - y₁)/(x₂ - x₁). It describes the rate of change of y with respect to x.
Importance
Slope is directly tested in LET items involving linear graphs and connects to rate problems in word problems.
Quadrant
One of the four regions of the Cartesian plane formed by the x- and y-axes. Quadrant I is upper right (+,+), II upper left (-,+), III lower left (-,-), IV lower right (+,-).
Importance
LET items may ask in which quadrant a given point lies or how the sign of coordinates determines the quadrant.
Common mistakes
- Reversing the x and y coordinates when plotting: (3, 5) means 3 units HORIZONTAL and 5 units VERTICAL, not the other way.
- Incorrect subtraction order in the slope formula: (y₁ - y₂)/(x₂ - x₁) gives the WRONG sign for the slope. Be consistent with your order.
- Confusing zero slope (horizontal line, m = 0) with undefined slope (vertical line, m is undefined because the denominator is 0).
- Substituting negative values without parentheses when evaluating functions: f(-2) = 2(-2)² should give 2(4) = 8, not -8.
8. Radicals
Formulas
√(ab) = √a × √b (a, b ≥ 0)
Example
√72 = √(36 × 2) = √36 × √2 = 6√2
Variables
a, b = non-negative radicands
Application
Split the radicand into a perfect square times another factor, then simplify.
Rationalization: (1/√a) × (√a/√a) = √a/a
Example
3/√5 = (3/√5) × (√5/√5) = 3√5/5
Variables
a = positive radicand in the denominator
Application
Multiply numerator and denominator by the radical to eliminate the radical from the denominator.
Exam tips
- Know the perfect squares up to at least 15² = 225: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225.
- To simplify √n quickly, divide n by perfect squares from largest to smallest until you find one that divides evenly.
- In the quadratic formula, simplify the discriminant (√(b² - 4ac)) as a first step before completing the formula.
Key points
- A RADICAL (√) asks for a root. The square root of a number n is the value that, when squared, gives n: √49 = 7 because 7² = 49.
- To SIMPLIFY a radical, factor the radicand (the number under the root) and pull out any PERFECT SQUARE FACTORS: √50 = √(25 × 2) = 5√2.
- PRODUCT RULE for radicals: √(ab) = √a × √b. This is the rule used to simplify.
- QUOTIENT RULE: √(a/b) = √a / √b (for b ≠ 0).
- A radical is in SIMPLEST FORM when: (1) no perfect square factor remains under the radical; (2) no fractions appear under the radical; (3) no radicals appear in the denominator (rationalized).
- To RATIONALIZE a denominator (eliminate the radical from it), multiply numerator and denominator by the radical in the denominator: 1/√2 × √2/√2 = √2/2.
Definitions
Radical
The symbol √ (or the nth root symbol ⁿ√) used to denote roots. The square root is the most common radical.
Importance
Radicals appear in quadratic formula computations and in simplifying expressions — both tested on the LET.
Radicand
The expression under the radical sign. In √50, the radicand is 50.
Importance
Understanding the radicand is the first step in simplifying any radical expression.
Rationalization
The process of eliminating radicals from the denominator of a fraction by multiplying by an appropriate form of 1.
Importance
LET items on simplifying radical expressions often require rationalization for the final simplified form.
Common mistakes
- √(a + b) ≠ √a + √b. Example: √(9 + 16) = √25 = 5, NOT 3 + 4 = 7. The product rule applies, NOT the sum rule.
- Leaving a perfect square factor under the radical: √72 simplified to 6√2, not left as √72 or 2√18.
- Forgetting the ± when taking a square root to solve an equation: x² = 25 gives x = ±5, not just x = 5.
Connections
- The DISTRIBUTIVE PROPERTY connects MULTIPLYING POLYNOMIALS (special products) with FACTORING — they are the same process in opposite directions. Mastery of one reinforces the other.
- The LAWS OF EXPONENTS used to simplify expressions also appear inside the QUADRATIC FORMULA when simplifying the discriminant — a direct link between Sections 1 and 5.
- FACTORING (Section 4) is a prerequisite for the FACTORING METHOD of solving QUADRATIC EQUATIONS (Section 5) and for SIMPLIFYING RATIONAL EXPRESSIONS.
- LINEAR EQUATIONS (Section 2) are the foundation of SYSTEMS OF LINEAR EQUATIONS (Section 3) — you apply the same solving technique (isolation, inverse operations) to each equation in a system.
- SLOPE (Section 7) is the algebraic version of RATE in MOTION WORD PROBLEMS (Section 6): slope = rate of change = Δy/Δx, directly parallel to speed = distance/time.
- EVALUATING FUNCTIONS (Section 7) uses the same ORDER OF OPERATIONS and SUBSTITUTION skills as evaluating algebraic expressions (Section 1) — same process, new notation.
- WORD PROBLEM TRANSLATION (Section 6) ties together ALL algebraic tools: you may set up a linear equation, an inequality, a system, or a quadratic depending on the problem — translation is the gateway to choosing the right tool.
- RADICALS (Section 8) appear in the QUADRATIC FORMULA whenever the discriminant is not a perfect square — simplifying radicals is a direct skill needed within quadratic problem-solving.
- The K–12 BEC Mathematics curriculum (Patterns and Algebra strand, Grades 4–6) directly parallels this chapter: pupils explore number patterns (linear sequences), write number sentences (simple equations), and solve simple word problems — teaching these skills requires the algebraic fluency developed here.
Quick review questions
Simplify (2x³)² × 3x.
Answer
12x⁷
First, apply the power of a product rule: (2x³)² = 2² × (x³)² = 4x⁶. Then multiply by 3x: 4x⁶ × 3x = (4 × 3)(x⁶ × x¹) = 12x⁷.
Solve for x: 3(2x - 4) = 2x + 4.
Answer
x = 4
Distribute: 6x - 12 = 2x + 4. Collect variable terms: 6x - 2x = 4 + 12, so 4x = 16. Divide: x = 4. Check: 3(8 - 4) = 3(4) = 12 = 2(4) + 4 = 12 ✓
Solve the inequality: 5 - 2x ≥ 11.
Answer
x ≤ -3
Subtract 5 from both sides: -2x ≥ 6. Divide by -2 and REVERSE the inequality symbol: x ≤ -3. Check with x = -4: 5 - 2(-4) = 13 ≥ 11 ✓
Factor completely: x² - 5x + 6.
Answer
(x - 2)(x - 3)
Find two numbers whose product is 6 and sum is -5. The numbers -2 and -3 satisfy this: (-2)(-3) = 6 and (-2) + (-3) = -5. So x² - 5x + 6 = (x - 2)(x - 3).
Solve: 2x² + 3x - 5 = 0 using the quadratic formula.
Answer
x = 1 or x = -5/2
a = 2, b = 3, c = -5. Discriminant = 3² - 4(2)(-5) = 9 + 40 = 49. x = (-3 ± √49)/(2×2) = (-3 ± 7)/4. So x = 4/4 = 1 or x = -10/4 = -5/2.
The sum of three consecutive integers is 72. What are the integers?
Answer
23, 24, and 25
Let the integers be n, n+1, n+2. Then n + (n+1) + (n+2) = 72 → 3n + 3 = 72 → 3n = 69 → n = 23. The integers are 23, 24, 25. Check: 23 + 24 + 25 = 72 ✓
A jeepney driver has ₱5 and ₱10 coins — 12 coins in all — worth ₱95. How many of each coin does he have?
Answer
5 five-peso coins and 7 ten-peso coins
Let x = ₱5 coins and y = ₱10 coins. Count: x + y = 12. Value: 5x + 10y = 95. Substitute y = 12 - x: 5x + 10(12 - x) = 95 → 5x + 120 - 10x = 95 → -5x = -25 → x = 5. So y = 7. Check: 5(5) + 10(7) = 25 + 70 = 95 ✓
What is the nature of the roots of x² - 4x + 4 = 0?
Answer
One repeated real root (x = 2)
Compute the discriminant: D = b² - 4ac = (-4)² - 4(1)(4) = 16 - 16 = 0. Since D = 0, there is exactly one repeated real root. Solving: (x - 2)² = 0, so x = 2.
Simplify: (x² - 9)/(x - 3).
Answer
x + 3 (for x ≠ 3)
Factor the numerator as a difference of squares: x² - 9 = (x + 3)(x - 3). So (x + 3)(x - 3)/(x - 3) = x + 3. The restriction x ≠ 3 applies because the original expression is undefined at x = 3.
Find the slope of the line passing through (1, 2) and (4, 11).
Answer
m = 3
Using the slope formula: m = (y₂ - y₁)/(x₂ - x₁) = (11 - 2)/(4 - 1) = 9/3 = 3. The line rises 3 units for every 1 unit it moves to the right.
Maria is 3 times as old as her son. In 12 years, she will be twice as old as her son. Find their present ages.
Answer
Son: 12 years old; Maria: 36 years old
Let son = x, Maria = 3x. In 12 years: 3x + 12 = 2(x + 12) → 3x + 12 = 2x + 24 → x = 12. Son is 12, Maria is 36. Check: In 12 years, Maria is 48 and son is 24; 48 = 2 × 24 ✓
If f(x) = 2x² - 3x + 1, find f(-2).
Answer
f(-2) = 15
Substitute x = -2 (in parentheses to avoid sign errors): f(-2) = 2(-2)² - 3(-2) + 1 = 2(4) + 6 + 1 = 8 + 6 + 1 = 15.
Diagrams
Elementary Algebra – Chapter Overview Mind Map
A comprehensive mind map showing all major topics in Elementary Algebra and how they branch from the central subject. Use this to orient yourself before studying and to do a final check that you have reviewed every subtopic.
How to Solve Any Linear Equation – Step-by-Step Flowchart
A decision-tree flowchart guiding you through every step of solving a linear equation. Follow the arrows and answer each decision question to arrive at the correct solution. The check step at the end is mandatory — always verify your answer in the original equation.
Choosing the Right Method to Solve a Quadratic Equation
A decision flowchart for selecting the most efficient method to solve any quadratic equation. Start at the top, answer each decision question, and follow the path to the appropriate method. The discriminant branch also tells you the nature of the roots before you finish solving.
Polya's Problem-Solving Model Applied to LET Word Problems
This flowchart applies Polya's four-step problem-solving model (standard in the DepEd K–12 BEC curriculum) to LET word problems. Notice that Step 4 (Look Back) checks against the WORDS of the problem, not just the equation — a critical distinction that prevents acceptance of extraneous or unreasonable answers.
Factoring Strategy Flowchart – Which Method to Use
A step-by-step decision flowchart for choosing the correct factoring strategy. Always start by checking for a Common Monomial Factor (CMF). Then identify the number of terms and the pattern to determine which factoring technique applies. This systematic approach prevents the most common LET factoring error: jumping to a technique without first factoring out the CMF.
Distribution of LET Algebra Item Types (Approximate)
This pie chart shows the approximate distribution of Elementary Algebra items on the LET by topic area, based on the PRC LET syllabus and past exam patterns. Word problem translation and factoring together account for over half the algebra items — prioritize these areas in your review while ensuring you also cover the other topics thoroughly.
Exam strategy
In the LET Elementary Level, Elementary Algebra items test four core abilities: (1) simplifying and evaluating algebraic expressions; (2) solving equations/inequalities/systems; (3) factoring and special products; and (4) translating word problems. Allocate approximately 30% of your algebra practice time to word problem translation — this is where the most items are gained or lost. When taking the exam, read each word problem twice: once to understand, once to identify the variable and the conditions. Write 'Let n = ...' before anything else. For equation-solving items, always perform a quick check by substituting your answer back. For items asking about the nature of roots, go straight to the discriminant — do not solve the full equation. Watch for sign traps (distributing a negative, reversing inequality symbols, squaring a negative value), as these account for the majority of errors on this section. On factoring items, look for the common monomial factor first, then identify the pattern (difference of squares, perfect square trinomial, or general trinomial). In the quadratic formula, identify a, b, and c from the STANDARD FORM of the equation — never from a rearranged version. Finally, connect this content to your future classroom: the DepEd K–12 BEC Patterns and Algebra strand introduces algebraic thinking as early as Grade 3, so your mastery here supports both the LET and your professional readiness as an elementary school teacher under the standards set by RA 7836 (Philippine Teachers Professionalization Act).