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LET Elementary MathematicsPlane and Solid GeometryRevision Notes

Quick revision notes for Plane and Solid Geometry — the one-page refresher for LET Elementary aspirants. Every item on this page has appeared in recent LET Elementary Mathematics papers, so revising these is the shortest path to a confident performance in Professional Regulation Commission (PRC)'s LET Elementary 2026.

Exam context

For the Licensure Examination for Professional Teachers — Elementary, Professional Regulation Commission (PRC) tests Mathematics under a "Core" label, with Plane and Solid Geometry in the 4th slot across 7 chapters. LET Elementary candidates must clear the Weighted average of 75% with no grade below 50% cut on the 2026 paper, which draws about a meaningful share of Mathematics questions. Date to watch: Bi-annual.

Plane and Solid Geometry - Revision Notes

Geometry is one of the most consistently tested areas in the LET Mathematics component. For BEEd graduates preparing to teach Grades 1–6, mastery of plane and solid geometry is doubly important: you must solve LET items correctly AND understand how these concepts are taught under the K–12 Mathematics curriculum (DepEd). This chapter covers angles, triangles, polygons, circles, the Pythagorean theorem, perimeter, area, surface area, and volume. The winning approach is to memorize the formulas exactly, practice applying them step by step, and always check whether the question asks for length (linear units), area (square units), or volume (cubic units). Every formula in this chapter appears in actual LET items, so treat this review as both an exam tool and a teaching reference.

Sections

Formulas

Example

One angle is 32.5°, its complement is 90° − 32.5° = 57.5°

Formula

Complementary: A + B = 90°

Variables

A and B are two angle measures

Application

Find a missing angle when two angles together form a right angle

Example

One angle is 115°, its supplement is 180° − 115° = 65°

Formula

Supplementary: A + B = 180°

Variables

A and B are two angle measures

Application

Find a missing angle when two angles together form a straight line

Example

If ∠1 = 72°, then the vertically opposite ∠3 = 72°; adjacent ∠2 = 180° − 72° = 108°

Formula

Vertical angles: ∠1 = ∠3 and ∠2 = ∠4

Variables

Angles formed at the intersection of two lines

Application

Identify equal angles at an intersection without measuring

Exam Tips

  • Memorize the C-S-V pattern: Complementary = 90°, Supplementary = 180°, Vertical = equal.
  • When a transversal problem gives you one angle, use: corresponding → equal; alternate interior → equal; co-interior → subtract from 180°.
  • Always label angles before computing — draw the figure if allowed.

Key Points

  • An angle is measured in degrees (°). The full rotation is 360°.
  • Acute angle: less than 90°. Right angle: exactly 90°. Obtuse angle: between 90° and 180°. Straight angle: exactly 180°. Reflex angle: between 180° and 360°.
  • Complementary angles: two angles whose sum is 90°. Example: 35° and 55° are complementary.
  • Supplementary angles: two angles whose sum is 180°. Example: 110° and 70° are supplementary.
  • Vertical angles (vertically opposite angles): formed when two lines intersect. They are always EQUAL.
  • Adjacent angles on a straight line form a linear pair and are supplementary.
  • When a transversal crosses two PARALLEL lines: (1) Corresponding angles are EQUAL. (2) Alternate interior angles are EQUAL. (3) Co-interior (same-side interior) angles are SUPPLEMENTARY (sum to 180°).
  • LET TIP: Parallel-line transversal problems almost always give one angle and ask for another. Identify the relationship first (corresponding, alternate, co-interior), then apply the rule.

Definitions

Term

Transversal

Definition

A line that crosses two or more other lines at distinct points

Importance

Creates the corresponding, alternate interior, and co-interior angle pairs used in parallel-line problems

Term

Alternate Interior Angles

Definition

Angle pairs on opposite sides of the transversal, between the parallel lines

Importance

These are EQUAL when the lines are parallel — a key fact in many LET items

Term

Co-interior (Same-Side Interior) Angles

Definition

Angle pairs on the SAME side of the transversal, between the parallel lines

Importance

These are SUPPLEMENTARY (sum to 180°) when the lines are parallel

Section Title

Angles and Angle Pairs

Common Mistakes

  • Confusing complementary (90°) with supplementary (180°) — remember: 'C' comes before 'S' in the alphabet, and 90° comes before 180°.
  • Assuming alternate exterior angles are supplementary — they are actually EQUAL (like alternate interior angles).
  • Forgetting that vertical angles are equal only when formed by TWO straight lines crossing — not applicable to multiple intersecting lines.

Formulas

Example

If A = 40° and B = 70°, then C = 180° − 40° − 70° = 70° (isosceles triangle)

Formula

Angle sum: A + B + C = 180°

Variables

A, B, C are the three interior angles of the triangle

Application

Find a missing interior angle given the other two

Example

Remote interior angles are 45° and 65°. Exterior angle = 45° + 65° = 110°

Formula

Exterior angle: Ext = A + B (remote interior angles)

Variables

Ext is the exterior angle; A and B are the two non-adjacent interior angles

Application

Find an exterior angle or a missing interior angle

Example

A 1.5 m student has a 2 m shadow; flagpole has 16 m shadow. 1.5/2 = h/16 → h = 12 m

Formula

Similarity ratio: a/a' = b/b' = c/c' (= k, the scale factor)

Variables

a, b, c are sides of original; a', b', c' are sides of similar figure; k is scale factor

Application

Find an unknown side using proportional reasoning (cross-multiplication)

Example

Two similar triangles have sides in ratio 1:3. If smaller area = 10 cm², larger = 10 × 9 = 90 cm²

Formula

Area ratio: (Area₁/Area₂) = k²

Variables

k is the ratio of corresponding sides

Application

Find area of similar figure when the scale factor is known

Exam Tips

  • For 'can these form a triangle?' items: add the two SMALLER sides and check if the sum is GREATER than the largest side.
  • For isosceles triangle problems: identify the vertex angle first; base angles = (180° − vertex angle) ÷ 2.
  • For similarity problems involving shadows or heights: set up a proportion and cross-multiply.
  • The AA criterion is the easiest similarity test: if two angles are equal, the triangles are similar — use it first.

Key Points

  • The interior angles of ANY triangle always sum to 180°.
  • Classification by sides: Equilateral (all 3 sides equal, each angle = 60°), Isosceles (2 sides equal, base angles equal), Scalene (no sides equal).
  • Classification by angles: Acute (all angles < 90°), Right (one angle = 90°), Obtuse (one angle > 90°).
  • Exterior angle theorem: An exterior angle of a triangle equals the SUM of the two NON-ADJACENT (remote) interior angles.
  • Triangle inequality: The sum of any two sides must be GREATER than the third side. Example: sides 3, 4, 8 CANNOT form a triangle because 3 + 4 = 7 < 8.
  • Congruence postulates (same shape AND size): SSS, SAS, ASA, AAS, HL (for right triangles only).
  • Similarity criteria (same shape, proportional sizes): AA, SSS-proportional, SAS-proportional.
  • In SIMILAR triangles: corresponding angles are EQUAL and corresponding sides are in the SAME RATIO.
  • Areas of similar figures scale by the SQUARE of the ratio of corresponding sides. If sides are in ratio 1:3, areas are in ratio 1:9.
  • Base angles of an isosceles triangle are EQUAL.

Definitions

Term

Congruent Triangles

Definition

Triangles that are identical in both shape and size; all corresponding sides and angles are equal

Importance

Congruence proofs (SSS, SAS, ASA, AAS, HL) appear in LET reasoning items

Term

Similar Triangles

Definition

Triangles with the same shape but different sizes; corresponding angles are equal and corresponding sides are proportional

Importance

Used in indirect measurement problems (shadow problems, map-scale problems) which are common in LET

Term

Hypotenuse-Leg (HL) Theorem

Definition

Two RIGHT triangles are congruent if their hypotenuses and one pair of legs are equal

Importance

Only applies to RIGHT triangles — do not apply to other triangle types

Section Title

Triangles – Classification, Congruence, and Similarity

Common Mistakes

  • Using HL congruence for non-right triangles — HL is ONLY for right triangles.
  • Confusing congruence (SSS, SAS, ASA, AAS, HL) with similarity (AA, SSS-proportional, SAS-proportional).
  • Forgetting that the area ratio is k-SQUARED (not k) for similar figures.
  • In isosceles triangles, mixing up the vertex angle (between the equal sides) and the base angles (equal to each other).

Formulas

Example

Ladder foot is 6 m from wall, reaches 8 m up: c² = 6² + 8² = 36 + 64 = 100; c = 10 m (3-4-5 triple × 2)

Formula

a² + b² = c²

Variables

a and b are the two legs (shorter sides); c is the hypotenuse (longest side, opposite the right angle)

Application

Find the missing side of a right triangle given the other two sides

Example

Distance from (1, 2) to (4, 6): d = √[(4−1)² + (6−2)²] = √[9 + 16] = √25 = 5 units

Formula

Distance formula: d = √[(x₂ − x₁)² + (y₂ − y₁)²]

Variables

x₁, y₁ are coordinates of point 1; x₂, y₂ are coordinates of point 2

Application

Find the straight-line distance between two points on the Cartesian plane

Example

Midpoint of (2, 3) and (8, 7): M = ((2+8)/2, (3+7)/2) = (5, 5)

Formula

Midpoint formula: M = ((x₁+x₂)/2, (y₁+y₂)/2)

Variables

x₁, y₁ and x₂, y₂ are coordinates of the two endpoints

Application

Find the center point of a line segment on the coordinate plane

Exam Tips

  • Before computing, check if the numbers are a Pythagorean triple or a multiple of one — saves time.
  • For 'is this a right triangle?' items: square all three sides, add the two SMALLER squares, and check if they equal the LARGEST square.
  • Distance formula items on coordinate geometry are just the Pythagorean theorem in disguise — treat the horizontal and vertical differences as the two legs.

Key Points

  • The Pythagorean theorem applies ONLY to RIGHT triangles: a² + b² = c², where c is the HYPOTENUSE (the longest side, opposite the right angle).
  • Memorize these Pythagorean triples and their multiples: 3-4-5 (×2: 6-8-10; ×3: 9-12-15), 5-12-13, 8-15-17.
  • Recognizing triples saves computation time on the LET — no square roots needed.
  • Converse: If a² + b² = c², then the triangle IS a right triangle.
  • To find the HYPOTENUSE: c = √(a² + b²).
  • To find a LEG: a = √(c² − b²).
  • Common application: distance problems (ladder against wall, diagonal of a rectangle, distance between two points on a grid).

Definitions

Term

Hypotenuse

Definition

The side of a right triangle opposite the right angle; always the LONGEST side

Importance

Always place c (not a or b) as the hypotenuse in the formula; mixing this up is the most common error

Term

Pythagorean Triple

Definition

A set of three positive integers (a, b, c) that satisfy a² + b² = c², such as 3-4-5 or 5-12-13

Importance

Recognizing these triples instantly gives you the answer without computing square roots

Section Title

The Pythagorean Theorem

Common Mistakes

  • Putting one of the LEGS as c — always identify the hypotenuse (opposite the right angle) first.
  • Not recognizing multiples of Pythagorean triples (e.g., not seeing that 9-12-15 is just 3-4-5 × 3).
  • Using a² + b² = c² to find a leg: you must rearrange to a = √(c² − b²), not √(c² + b²).
  • Applying the Pythagorean theorem to non-right triangles.

Formulas

Example

Hexagon: (6 − 2) × 180° = 4 × 180° = 720°

Formula

Sum of interior angles = (n − 2) × 180°

Variables

n = number of sides of the polygon

Application

Find the total of all interior angles for any polygon

Example

Regular hexagon: 720° ÷ 6 = 120° per angle

Formula

Each interior angle of regular polygon = (n − 2) × 180° ÷ n

Variables

n = number of sides

Application

Find one interior angle of a regular (equilateral and equiangular) polygon

Example

Regular octagon: each exterior angle = 360° ÷ 8 = 45°

Formula

Sum of exterior angles = 360° (always)

Variables

Applies to any convex polygon

Application

Find a missing exterior angle or confirm a polygon is convex

Exam Tips

  • Quick check table — memorize: Triangle 180°, Quadrilateral 360°, Pentagon 540°, Hexagon 720°, Octagon 1080°.
  • Exterior angles ALWAYS total 360° — use this as a shortcut for exterior-angle problems.
  • 'Is every square a rhombus?' → YES. 'Is every rhombus a square?' → NO. Know the hierarchy.

Key Points

  • A polygon is a closed plane figure with straight sides.
  • Sum of interior angles of an n-sided polygon = (n − 2) × 180°.
  • Each interior angle of a REGULAR polygon (all sides and angles equal) = (n − 2) × 180° ÷ n.
  • Sum of EXTERIOR angles of ANY convex polygon = 360° (always, regardless of n).
  • Each exterior angle of a regular polygon = 360° ÷ n.
  • Know the angle sums for common polygons: Triangle (n=3): 180°; Quadrilateral (n=4): 360°; Pentagon (n=5): 540°; Hexagon (n=6): 720°; Octagon (n=8): 1080°.
  • Quadrilateral hierarchy: Square ⊂ Rectangle ⊂ Parallelogram; Square ⊂ Rhombus ⊂ Parallelogram; Trapezoid has exactly one pair of parallel sides.
  • Every square is a rectangle and a rhombus, but not every rectangle is a square.

Definitions

Term

Regular Polygon

Definition

A polygon with ALL sides equal (equilateral) AND all angles equal (equiangular)

Importance

The 'per-angle' formula only applies to REGULAR polygons; irregular polygons require adding all given angles

Term

Convex Polygon

Definition

A polygon where all interior angles are less than 180° and no vertex points inward

Importance

The 360° exterior angle rule applies to CONVEX polygons

Term

Parallelogram

Definition

A quadrilateral with two pairs of parallel sides; opposite sides are equal and opposite angles are equal

Importance

Parent figure for rectangles, rhombuses, and squares — knowing this hierarchy answers 'which is always true?' items

Section Title

Polygons – Interior and Exterior Angles

Common Mistakes

  • Using the per-angle formula for IRREGULAR polygons — it only works for regular (all-equal) polygons.
  • Forgetting that the exterior angle sum is ALWAYS 360°, not (n−2)×180°.
  • Thinking a rhombus must have right angles — a rhombus only requires four equal sides; right angles make it a SQUARE.
  • Confusing 'each exterior angle' (360°÷n) with 'each interior angle' (supplementary to the exterior angle).

Formulas

Example

Square with s = 9 m: Perimeter = 36 m; Area = 81 m²

Formula

Square: Perimeter = 4s; Area = s²

Variables

s = length of one side

Application

Fencing a square lot or finding the area of a square tile

Example

Rectangle 8 m × 5 m: Perimeter = 2(8 + 5) = 26 m; Area = 40 m²

Formula

Rectangle: Perimeter = 2(l + w); Area = l × w

Variables

l = length; w = width

Application

Most common formula on LET — used for rooms, lots, gardens

Example

Base = 12 m, height = 5 m: Area = ½ × 12 × 5 = 30 m²

Formula

Triangle: Area = ½ × b × h

Variables

b = base; h = perpendicular height (NOT slant side)

Application

Area of triangular lots or rooftop cross-sections

Example

Base = 10 cm, height = 6 cm: Area = 60 cm²

Formula

Parallelogram: Area = b × h

Variables

b = base; h = perpendicular height

Application

Area of tilted rectangular shapes

Example

Parallel sides 10 m and 6 m, height 4 m: Area = ½ × 16 × 4 = 32 m²

Formula

Trapezoid: Area = ½ × (a + b) × h

Variables

a and b = the two parallel sides; h = perpendicular height between them

Application

Area of trapezoidal lots or cross-sections of irrigation canals

Example

r = 7 cm: C = 2 × (22/7) × 7 = 44 cm; Area = (22/7) × 49 = 154 cm²

Formula

Circle: Circumference C = 2πr = πd; Area = πr²

Variables

r = radius; d = diameter = 2r

Application

Fencing a circular garden (circumference) or painting a circular floor (area)

Exam Tips

  • Read the problem twice: 'how much fencing?' = perimeter; 'how much tile/paint?' = area.
  • When r is a multiple of 7, use π = 22/7 — it cancels and avoids decimals.
  • For composite figures, sketch and label each part separately before computing.
  • For the trapezoid, the formula is the AVERAGE of the two parallel sides × height.

Key Points

  • Perimeter is the total LENGTH around a figure — always in LINEAR units (m, cm, km).
  • Area is the amount of SURFACE covered — always in SQUARE units (m², cm², km²).
  • For composite figures: split into standard shapes, compute each area, then ADD (or subtract for cutouts).
  • ALWAYS convert all lengths to the SAME unit before computing; mixing meters and centimeters causes errors by factors of 100 or 10,000.
  • Use π ≈ 3.1416 for general problems, or π = 22/7 when the radius is a multiple of 7 (e.g., r = 7, 14, 21) — 22/7 cancels cleanly.
  • Context clues for what to compute: 'fencing' or 'border' → PERIMETER; 'flooring,' 'painting,' or 'covering' → AREA; 'filling' or 'capacity' → VOLUME.

Definitions

Term

Perimeter

Definition

The total distance around the boundary of a plane figure

Importance

Used for 'how much fencing/border/trim is needed?' — LINEAR units only

Term

Area

Definition

The measure of the two-dimensional surface enclosed by a figure

Importance

Used for 'how much floor/paint/material is needed?' — always SQUARE units

Term

Height (of a geometric figure)

Definition

The PERPENDICULAR distance from the base to the opposite vertex or side — NOT the slant side

Importance

The most common source of error in triangle and trapezoid area problems

Term

Composite Figure

Definition

A shape made up of two or more standard geometric figures combined together

Importance

LET often shows L-shaped lots or rectangles with semicircular ends — decompose and add

Section Title

Perimeter and Area of Plane Figures

Common Mistakes

  • Using the slant side as the HEIGHT in triangle/parallelogram/trapezoid area formulas — height must be PERPENDICULAR to the base.
  • Forgetting to SQUARE the radius in the circle area formula (writing πr instead of πr²).
  • Mixing units (e.g., length in meters and width in centimeters) before multiplying for area.
  • Using the diameter instead of the radius in the area formula.
  • Forgetting to divide by 2 in the trapezoid area formula.

Formulas

Example

Cube s = 4 cm: V = 64 cm³; SA = 6 × 16 = 96 cm²

Formula

Cube: V = s³; SA = 6s²

Variables

s = edge length

Application

Volume of a cubic storage box or ice block

Example

Box 8 × 5 × 3 cm: V = 120 cm³; SA = 2(40 + 24 + 15) = 158 cm²

Formula

Rectangular Prism: V = l × w × h; SA = 2(lw + lh + wh)

Variables

l = length; w = width; h = height

Application

Capacity of a classroom aquarium or storage box

Example

r = 3 m, h = 10 m: V = 3.14 × 9 × 10 = 282.6 m³

Formula

Cylinder: V = πr²h; SA = 2πr² + 2πrh

Variables

r = radius of circular base; h = height

Application

Volume of a water drum or paint can

Example

r = 3 cm, h = 4 cm: l = √(9+16) = 5 cm; V = (1/3)(3.14)(9)(4) ≈ 37.68 cm³

Formula

Cone: V = (1/3)πr²h; SA = πr² + πrl

Variables

r = radius; h = vertical height; l = slant height = √(r² + h²)

Application

Volume of an ice cream cone or conical tank

Example

r = 3 cm: V = (4/3)(3.14)(27) ≈ 113.04 cm³; SA = 4(3.14)(9) ≈ 113.04 cm²

Formula

Sphere: V = (4/3)πr³; SA = 4πr²

Variables

r = radius

Application

Volume of a ball or spherical water tank

Example

Square base 6 × 6, height 4: V = (1/3)(36)(4) = 48 cubic units

Formula

Pyramid: V = (1/3) × B × h

Variables

B = area of the base; h = vertical height

Application

Volume of pyramid-shaped structures

Exam Tips

  • Cone and pyramid = 1/3 × (matching prism/cylinder formula). This 1/3 is tested repeatedly.
  • Surface area problems: list all faces, compute each, then add — do not skip any face.
  • Sphere: V and SA have a curious coincidence when r = 3: both ≈ 113.04 (with π ≈ 3.14). Know this for checking.
  • Cubic units for volume: if the answer has m² or cm², it is WRONG for a volume question.

Key Points

  • Surface area (SA) is the TOTAL area of all outer faces of a 3D solid — in SQUARE units.
  • Volume (V) is the amount of space enclosed by a solid — in CUBIC units.
  • A cone's volume is ONE-THIRD of the cylinder with the same base radius and height.
  • A pyramid's volume is ONE-THIRD of the prism with the same base and height.
  • The slant height (l) of a cone is NOT the same as the vertical height (h); they are related by l² = r² + h².
  • Sphere formulas involve r³ (volume) and r² (surface area) — both use the same radius.
  • Recognize context: 'how much water can the tank hold?' = VOLUME; 'how much paint to cover the tank?' = SURFACE AREA.

Definitions

Term

Surface Area

Definition

The sum of the areas of all outer faces (flat and curved) of a three-dimensional solid

Importance

Used for 'painting,' 'wrapping,' or 'covering' problems — answer in square units

Term

Volume

Definition

The measure of three-dimensional space enclosed within a solid

Importance

Used for 'filling,' 'capacity,' 'how much water' problems — answer in cubic units

Term

Slant Height (of a cone)

Definition

The distance from the apex of the cone to any point on the circular edge of the base, measured along the surface

Importance

Used in the SURFACE AREA formula of a cone; different from vertical height; compute with Pythagorean theorem if not given

Section Title

Surface Area and Volume of Solids

Common Mistakes

  • Using vertical height (h) instead of slant height (l) in the LATERAL SURFACE AREA of a cone.
  • Forgetting the factor of 1/3 for cone and pyramid volumes.
  • Confusing surface area (square units) with volume (cubic units) in the final answer.
  • Using diameter instead of radius in sphere or cylinder formulas.
  • Forgetting to count BOTH circular bases of a cylinder in the surface area formula (2πr² + 2πrh).

Formulas

Example

r = 14 m: C = 2 × (22/7) × 14 = 88 m

Formula

Circumference: C = 2πr = πd

Variables

r = radius; d = diameter

Application

Distance around a circular track or garden boundary

Example

r = 7 cm: A = (22/7) × 49 = 154 cm²

Formula

Area of circle: A = πr²

Variables

r = radius

Application

Area of a circular floor, plot, or table

Example

If C = 44 cm, then 2πr = 44; r = 44 ÷ (2 × 22/7) = 44 × 7/44 = 7 cm

Formula

Diameter: d = 2r

Variables

r = radius

Application

Convert between radius and diameter in any circle formula

Exam Tips

  • Given diameter d? Halve it to get r before plugging into any formula.
  • Given circumference C? Solve 2πr = C for r first, then find area if needed.
  • Use 22/7 when r = 7, 14, 21, 28 (multiples of 7) — it cancels and gives a whole number answer.
  • For a composite figure with a semicircle on top of a rectangle: Area = (l × w) + (πr²/2); Perimeter = 2l + w + πr (replace top side of rectangle with arc).

Key Points

  • Key parts: Center (O), Radius (r) — center to edge, Diameter (d = 2r) — across through center, Chord — joins two points on circle, Arc — part of circumference, Tangent — touches circle at exactly ONE point.
  • A tangent is PERPENDICULAR to the radius drawn to the point of tangency.
  • Central angle: vertex is at the CENTER; its measure equals the arc it intercepts.
  • The circumference (perimeter of a circle) = πd = 2πr.
  • If you know ANY ONE of radius, diameter, circumference, or area — you can find ALL the others.
  • π (pi) ≈ 3.1416 is the universal ratio of any circle's circumference to its diameter.
  • Semicircle area = πr² ÷ 2; semicircle perimeter = πr + 2r (arc + diameter).

Definitions

Term

Radius

Definition

The distance from the center of a circle to any point on its circumference

Importance

All circle formulas are written in terms of r — always find r first before computing

Term

Tangent

Definition

A line that touches a circle at exactly one point and is perpendicular to the radius at that point

Importance

The perpendicularity of a tangent and radius is a common deduction in geometry proofs and LET items

Term

Chord

Definition

A line segment joining any two points on a circle; the diameter is the longest possible chord

Importance

Distinguishing chord from radius and diameter prevents definition errors

Section Title

Circles – Parts, Formulas, and Relationships

Common Mistakes

  • Using d (diameter) in the area formula instead of r: writing πd² instead of πr².
  • Forgetting to find r first when given the diameter or circumference.
  • Confusing arc (part of the boundary) with chord (a straight line inside the circle).
  • Computing a semicircle perimeter as πr only — forgetting to add the diameter (2r) for the straight edge.

Connections

  • The Pythagorean theorem is the foundation of the distance formula in coordinate geometry — both compute the hypotenuse of a right triangle formed by horizontal and vertical distances.
  • Angle-sum rules for triangles (180°) connect to the polygon interior angle formula: a polygon of n sides can be divided into (n−2) triangles, each contributing 180°.
  • Similar triangle ratios directly connect to real-world indirect measurement (shadow problems, scale maps, architectural drawings) — a key topic in Grade 5–6 K–12 Math.
  • The area of a trapezoid formula is an extension of the parallelogram area: treating the trapezoid as an 'average-width' parallelogram gives ½(a+b)h.
  • Cone and pyramid volumes are exactly one-third of their corresponding cylinder and prism — connecting flat-base area formulas to 3D volume.
  • The circumference and area of a circle are linked through r: if you know C, you can find r, and then compute A = πr² — all three measures describe the SAME circle.
  • Complementary and supplementary angle relationships reappear in parallel-line transversal problems (co-interior angles) and in right-triangle geometry (two acute angles of a right triangle are complementary).
  • Surface area of a cylinder (2πr² + 2πrh) connects circle area (the two bases) and rectangle area (the lateral face 'unwrapped' = 2πr × h).
  • Quadrilateral properties (parallelogram, rectangle, rhombus, square) form a hierarchy that connects algebraic conditions with geometric figures — essential for 'which statement is always true?' items.
  • The 3-4-5 Pythagorean triple connects to the distance between coordinate points, the diagonal of a 3×4 rectangle, and the standard Grade 4–6 right-triangle problems in DepEd learning materials.

Exam Strategy

On the LET Mathematics component, Plane and Solid Geometry items reward careful formula recall and disciplined unit handling. Follow this approach for every geometry item: (1) READ carefully — identify whether the problem asks for length/perimeter (linear units), area (square units), or volume (cubic units); choosing the wrong formula type is the top error. (2) IDENTIFY the figure — is it a triangle, circle, cylinder, cone, etc.? Write the correct formula before substituting any values. (3) CHECK UNITS — if measurements are in different units (e.g., cm and m), convert BEFORE computing. (4) USE SHORTCUTS — recognize Pythagorean triples (3-4-5, 5-12-13, 8-15-17) to avoid square-root computation; use π = 22/7 when r is a multiple of 7. (5) REMEMBER THE ONE-THIRD RULE — cones and pyramids are always 1/3 of the matching prism or cylinder. (6) FOR SIMILAR FIGURES — sides are in ratio k, but areas are in ratio k². (7) VERIFY with context — does your answer make sense? A volume cannot be negative; an area in m² for a room should be roughly 20–60 m². Allocate about 1.5–2 minutes per geometry item; if stuck, eliminate obviously wrong units and use estimation. In Philippine elementary classrooms (K–12), geometry is taught from Grade 1 onward — knowing these concepts deeply also prepares you to teach them effectively, which is the ultimate goal of passing the LET under RA 7836.

Quick Review Questions

Two angles are supplementary. One angle is three times the other. Find both angles.

Let the smaller angle = x. Then the larger = 3x. Supplementary means they sum to 180°: x + 3x = 180° → 4x = 180° → x = 45°. The angles are 45° and 3 × 45° = 135°. Check: 45° + 135° = 180°. ✓

A right triangle has legs of 5 cm and 12 cm. What is the length of the hypotenuse?

Recognize the 5-12-13 Pythagorean triple. Verify: 5² + 12² = 25 + 144 = 169 = 13². c = √169 = 13 cm.

Find the sum of the interior angles of a decagon (10-sided polygon).

Sum = (n − 2) × 180° = (10 − 2) × 180° = 8 × 180° = 1,440°.

A circular garden has a radius of 7 m. Using π = 22/7, find its area and circumference.

Area = πr² = (22/7) × 7² = (22/7) × 49 = 22 × 7 = 154 m². Circumference = 2πr = 2 × (22/7) × 7 = 2 × 22 = 44 m.

A cylindrical water drum has a radius of 3 m and height of 10 m. Find its volume. (π ≈ 3.14)

V = πr²h = 3.14 × 3² × 10 = 3.14 × 9 × 10 = 3.14 × 90 = 282.6 m³.

Can a triangle be formed with sides 5 cm, 7 cm, and 13 cm? Explain.

By the Triangle Inequality, the sum of any two sides must be GREATER than the third. Check the two smaller sides: 5 + 7 = 12, which is NOT greater than 13. Therefore, these sides CANNOT form a triangle.

A 1.8 m tall teacher casts a 2 m shadow. At the same time, a tree casts a 15 m shadow. How tall is the tree?

Using similar triangles: height/shadow ratio is constant. 1.8/2 = h/15. Cross-multiply: 2h = 1.8 × 15 = 27. h = 27 ÷ 2 = 13.5 m.

A cone has a radius of 6 cm and a vertical height of 8 cm. Find its volume. (π ≈ 3.14)

V = (1/3)πr²h = (1/3)(3.14)(6²)(8) = (1/3)(3.14)(36)(8) = (1/3)(3.14)(288) = (1/3)(904.32) = 301.44 cm³.

Find the distance between points A(−1, 2) and B(3, 5) on the coordinate plane.

d = √[(3−(−1))² + (5−2)²] = √[4² + 3²] = √[16 + 9] = √25 = 5 units. This is a 3-4-5 Pythagorean triple.

A trapezoidal lot has parallel sides of 14 m and 8 m and a perpendicular height of 5 m. Find its area.

Area of trapezoid = ½ × (a + b) × h = ½ × (14 + 8) × 5 = ½ × 22 × 5 = ½ × 110 = 55 m².

Each interior angle of a regular polygon measures 144°. How many sides does the polygon have?

Each interior angle = (n−2)×180°/n = 144°. So (n−2)×180 = 144n → 180n − 360 = 144n → 36n = 360 → n = 10.

A sphere has a radius of 6 cm. Find its surface area. (π ≈ 3.14)

SA = 4πr² = 4 × 3.14 × 6² = 4 × 3.14 × 36 = 4 × 113.04 = 452.16 cm².

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