GELE Cadastral Surveys & Land Laws — Subdivision and Consolidation SurveysExam Answer Templates

Marks

1

Topic

Subdivision Surveys — Definition

Difficulty

easy

Template Id

T1

Examiner Tip

The examiner looks for three elements in one sentence: the action (divides), the result (two or more lots), and the purpose (separate titling/description). Hit all three for the full mark.

Model Answer

A subdivision survey is a survey that divides an existing parcel of land into two or more smaller lots, each with its own defined boundaries, area, and technical description, for the purpose of separate titling, sale, or development.

Question Type

very_short_answer

Answer Structure

• One concise sentence: name the survey type + state its core purpose (dividing one parcel into multiple lots) + mention separate titling/description [1 mark]

Scoring Breakdown

Common Mark Deductions

• Writing 'it surveys a subdivision' (circular definition) — earns 0.
• Omitting 'two or more lots' or 'individual boundaries' — the definition is incomplete.
• Confusing subdivision survey with a cadastral survey (broader scope) — loses the mark.

Key Phrases To Include

• divides
• two or more lots
• individual boundaries
• technical description
• separate titling

Marks

2

Topic

Consolidation Surveys — Definition and Types

Difficulty

easy

Template Id

T2

Examiner Tip

The key distinguishing phrase for Cons-Subd is 'consolidation then re-subdivision in one plan.' Make that sequence explicit.

Model Answer

A consolidation survey merges two or more adjoining parcels of land into a single lot by dissolving their shared interior boundaries, resulting in one combined parcel with one technical description. [1 mark] A consolidation-subdivision (Cons-Subd) survey, by contrast, first consolidates the adjoining parcels into one, then immediately re-divides (re-subdivides) the combined parcel into new lots according to a development layout — effectively performing both operations in a single plan and instrument. [1 mark]

Question Type

short_answer

Answer Structure

• Sentence 1: Define consolidation survey — merging parcels, dissolving interior boundaries, single resulting lot [1 mark]
• Sentence 2: Define Cons-Subd — consolidation followed by re-subdivision in one operation, single plan [1 mark]

Scoring Breakdown

Common Mark Deductions

• Defining consolidation as 'combining data' rather than merging physical parcels — loses Mark 1.
• Describing Cons-Subd as simply a subdivision without mentioning the prior consolidation step — loses Mark 2.
• Failing to state that interior boundaries are dissolved in consolidation.

Key Phrases To Include

• merges adjoining parcels
• dissolving interior boundaries
• single parcel
• consolidation-subdivision
• re-divides
• single plan

Marks

2

Topic

Area Partition — Rectangle Formula

Difficulty

easy

Template Id

T3

Examiner Tip

Always derive the formula from first principles (A = w × x) in one line before writing x = A₁/w — it shows understanding and protects against rote-memory errors.

Model Answer

For a rectangular lot, the distance x from one end to the dividing line parallel to the shorter side is given by: x = A₁ / w where: A₁ = required area of the cut-off lot (m²) w = perpendicular width (the dimension parallel to the dividing line) (m) x = distance along the frontage at which the dividing line is placed (m) This formula follows from A₁ = w × x, solved for x.

Question Type

short_answer

Answer Structure

• Line 1: State the formula x = A₁ / w [1 mark]
• Lines 2–4: Correctly define all three variables with units [1 mark]

Scoring Breakdown

Common Mark Deductions

• Writing x = w / A₁ (inverted formula) — loses Mark 1.
• Omitting units on any variable — partial credit at examiner's discretion, commonly −½ mark.
• Not stating that w is the dimension parallel to (not perpendicular to) the dividing line — loses Mark 2.

Key Phrases To Include

• x = A₁ / w
• required area
• perpendicular width
• dividing line
• parallel to one side
• m²
• m

Marks

3

Topic

Area Partition — Equal Subdivision of Rectangle

Difficulty

easy

Template Id

T4

Examiner Tip

Identify w as the side parallel to the dividing line — this is the most common error. Draw a quick sketch to confirm before solving.

Model Answer

GIVEN: Lot dimensions: 60 m (frontage) × 25 m (depth) Total area = 60 × 25 = 1 500 m² Division: two equal lots; dividing line parallel to the 25 m side REQUIRED: (a) Distance x of dividing line from one end (b) Area of each lot SOLUTION: Each lot area: A₁ = 1 500 / 2 = 750 m² Using x = A₁ / w, where w = 25 m (dimension parallel to the dividing line): x = 750 / 25 = 30 m Check: A₁ + A₂ = 750 + 750 = 1 500 m² ✓ (equals original area) ANSWER: The dividing line is placed 30 m from one end (parallel to the 25 m side). Each lot has an area of 750 m².

Question Type

numerical

Answer Structure

• GIVEN block: state all known dimensions and total area [½ mark]
• Compute each lot area = Total / 2 = 750 m² [1 mark]
• Apply x = A₁ / w = 750 / 25 = 30 m with correct substitution [1 mark]
• Area balance check: parts sum to original [½ mark]

Scoring Breakdown

Common Mark Deductions

• Using w = 60 m instead of 25 m (using the wrong dimension as w) — gets x = 12.5 m, loses Mark 2.
• Omitting the area balance check — loses Mark 3 partially.
• No formula shown before substitution — examiner cannot award process marks if formula is absent.
• Missing units (m or m²) on final answer — common ½-mark deduction.

Key Phrases To Include

• x = A₁ / w
• 750 m²
• 30 m
• parallel to the 25 m side
• area check
• 1 500 m²

Marks

3

Topic

Area Partition — Unequal Cut of Rectangle

Difficulty

medium

Template Id

T5

Examiner Tip

The problem says 'parallel to the shorter side' — verify which side is shorter (40 m < 50 m) before assigning w.

Model Answer

GIVEN: Total area = 2 000 m² Frontage (w) = 40 m → Depth = 2 000 / 40 = 50 m Required cut-off area A₁ = 1 250 m² Dividing line: parallel to the 40 m frontage (i.e., parallel to the shorter side) REQUIRED: (a) Depth x of the cut-off lot (b) Remaining area A₂ SOLUTION: (a) x = A₁ / w = 1 250 / 40 = 31.25 m (b) A₂ = 2 000 − 1 250 = 750 m² Check: A₁ + A₂ = 1 250 + 750 = 2 000 m² ✓ ANSWER: (a) The dividing line is 31.25 m from the front boundary. (b) The remaining lot has an area of 750 m².

Question Type

numerical

Answer Structure

• GIVEN: total area, frontage, required area, orientation of dividing line [½ mark]
• Apply x = A₁/w = 1250/40 = 31.25 m [1 mark]
• A₂ = 2000 − 1250 = 750 m² [1 mark]
• Area check and final answer with units [½ mark]

Scoring Breakdown

Common Mark Deductions

• Setting w = 50 m (the depth) rather than 40 m (the frontage/shorter side) — fundamental geometric error.
• Computing A₂ = 2000 − x instead of 2000 − A₁ — conceptual error on remaining area.
• Not writing the area check — loses the verification mark.

Key Phrases To Include

• x = A₁ / w
• 31.25 m
• 750 m²
• area balance
• parallel to the frontage

Marks

2

Topic

Consolidation Surveys — Area and Boundary Treatment

Difficulty

easy

Template Id

T6

Examiner Tip

Part (b) requires a legal statement, not just a surveying statement. Mention the title consequence to earn the full mark.

Model Answer

(a) Total consolidated area: A = 900 + 1 100 + 750 = 2 750 m² (b) The shared (interior) boundaries between the three lots are dissolved and cease to exist as legal boundaries. Only the outer perimeter of the merged parcel is retained, re-monumented, and described in the new technical description. The original lot titles are cancelled and replaced by a single new title covering the consolidated 2 750 m² parcel.

Question Type

short_answer

Answer Structure

• Part (a): Correct summation of three areas = 2 750 m² [1 mark]
• Part (b): State that interior boundaries are dissolved; outer perimeter retained; new single title issued [1 mark]

Scoring Breakdown

Common Mark Deductions

• Arithmetic error in summation — loses Mark 1.
• Saying boundaries are 'removed from the plan' without stating they are legally dissolved — vague, loses Mark 2.
• Not mentioning title cancellation and issuance of a new single title.

Key Phrases To Include

• 2 750 m²
• interior boundaries dissolved
• outer perimeter retained
• single title
• original titles cancelled

Marks

2

Topic

Subdivision — Road/Easement Deduction

Difficulty

easy

Template Id

T7

Examiner Tip

Always deduct roads/easements from the total FIRST; individual lots are carved only from the saleable balance. State this principle explicitly.

Model Answer

GIVEN: Total parcel area = 5 000 m² Road reservation = 10% of total area REQUIRED: (a) Road lot area (b) Saleable lot area SOLUTION: (a) Road lot area = 0.10 × 5 000 = 500 m² (b) Saleable area = 5 000 − 500 = 4 500 m² ANSWER: Road lot: 500 m²; Saleable area: 4 500 m² Note: Under BP 220 and related HLURB/DHSUD rules, road lots and open-space reservations must be deducted before allocating individual lot areas in any approved subdivision development.

Question Type

numerical

Answer Structure

• Road lot = 10% × 5000 = 500 m² [1 mark]
• Saleable area = 5000 − 500 = 4500 m² with legal note on deduction before allocation [1 mark]

Scoring Breakdown

Common Mark Deductions

• Computing 10% of saleable area (circular error) instead of total parcel area.
• Forgetting to subtract the road lot to get saleable area — loses Mark 2.
• No legal basis cited (BP 220 or DHSUD rules) — partial deduction in law-emphasis items.

Key Phrases To Include

• road lot
• 10% reservation
• 500 m²
• 4 500 m²
• saleable area
• deducted before allocation
• BP 220

Marks

2

Topic

Subdivision Survey Documents

Difficulty

medium

Template Id

T8

Examiner Tip

Numbering your items clearly (1, 2, 3, 4) makes it easy for the examiner to count. Add the PD 1529 citation for the legal instrument to signal legal awareness.

Model Answer

The following documents are produced after a subdivision survey for plan approval and titling: 1. Subdivision Plan (SD Plan) — a scaled survey plan showing all new lots, bearings, distances, areas, and the dividing lines, signed and sealed by the Geodetic Engineer. 2. Technical Descriptions — written metes-and-bounds descriptions for each new lot, prepared for inclusion in the new certificates of title. 3. Computation Sheets — coordinate computation and area computation records supporting the plan. 4. Deed of Conveyance / Court Order / Instrument of Partition — the legal document authorising the subdivision (e.g., deed of sale, court decree, extrajudicial settlement), required by the Register of Deeds under PD 1529.

Question Type

short_answer

Answer Structure

• Item 1: Subdivision Plan [½ mark]
• Item 2: Technical Descriptions [½ mark]
• Item 3: Computation Sheets [½ mark]
• Item 4: Legal instrument / Deed of Conveyance [½ mark]

Scoring Breakdown

Common Mark Deductions

• Listing 'map' or 'drawing' without specifying 'Subdivision Plan' — too vague, may not earn the mark.
• Naming only two items for a 4-item question — loses 1 mark.
• Listing documents unrelated to subdivision (e.g., tax declaration, barangay clearance) — earns 0 for that item.

Key Phrases To Include

• Subdivision Plan
• Technical Descriptions
• Computation Sheets
• Deed of Conveyance
• PD 1529
• Register of Deeds
• signed and sealed

Marks

1

Topic

Legal Framework — PD 1529

Difficulty

medium

Template Id

T9

Examiner Tip

The Register of Deeds titles — approvals come from LRA/DENR. Keep the roles distinct.

Model Answer

Under PD 1529, the Register of Deeds cancels the original Certificate of Title (OCT or TCT) covering the mother lot and issues new Transfer Certificates of Title (TCTs) for each subdivided lot based on the approved subdivision plan and technical descriptions submitted by the registered owner.

Question Type

very_short_answer

Answer Structure

• Single sentence: state cancellation of original title + issuance of new TCTs per approved subdivision plan [1 mark]

Scoring Breakdown

Common Mark Deductions

• Saying the Register of Deeds 'approves the subdivision plan' — approval is done by LRA/DENR, not RD; loses the mark.
• Not citing PD 1529 when the question specifically references it.
• Describing the LRA's role instead of the Register of Deeds specifically.

Key Phrases To Include

• PD 1529
• Register of Deeds
• cancels original title
• Transfer Certificate of Title
• TCT
• approved subdivision plan

Marks

1

Topic

Subdivision Surveys — Terminology

Difficulty

easy

Template Id

T10

Examiner Tip

A distinction question requires BOTH sides of the comparison. State what each term is and how they differ in one structured sentence.

Model Answer

A lot line is any boundary line of an existing lot (including all outer perimeter lines). A dividing line is a newly established interior boundary line created by the subdivision survey that separates the original parcel into two or more new lots — it becomes a lot line for each new lot once the subdivision is approved.

Question Type

very_short_answer

Answer Structure

• One to two sentences: define lot line (existing boundary) vs. dividing line (new interior boundary created by subdivision) [1 mark]

Scoring Breakdown

Common Mark Deductions

• Using the terms interchangeably without distinction — earns 0.
• Defining only one term — loses the mark since the question asks for a distinction.

Key Phrases To Include

• lot line
• existing boundary
• dividing line
• newly established
• interior boundary
• subdivision

Marks

5

Topic

Area Partition — Multi-Lot Subdivision of Rectangle

Difficulty

hard

Template Id

T11

Examiner Tip

For multi-lot problems, always use cumulative distances (d₁, d₂, d₃…) measured from a fixed reference boundary. Verify every lot by both direct computation and the remaining-distance method. These two checks eliminate arithmetic errors and earn the verification marks.

Model Answer

GIVEN: Rectangular lot: 80 m (length along dividing direction) × 50 m (width parallel to dividing lines) Total area = 80 × 50 = 4 000 m² Lot A = 1 600 m²; Lot B = 1 500 m²; Lot C = remainder Dividing lines: parallel to the 50 m side (i.e., w = 50 m for all cuts) REQUIRED: (a) d₁ = distance from left boundary to Lot A / Lot B dividing line (b) d₂ = distance from left boundary to Lot B / Lot C dividing line (c) Area of Lot C SOLUTION: (a) Distance to first dividing line (Lot A boundary): Using x = A₁ / w: d₁ = 1 600 / 50 = 32.00 m (b) Width of Lot B: x_B = A_B / w = 1 500 / 50 = 30.00 m ∴ d₂ = d₁ + x_B = 32.00 + 30.00 = 62.00 m (c) Area of Lot C: A_C = 4 000 − 1 600 − 1 500 = 900 m² Verification using remaining distance: Remaining distance = 80 − 62 = 18 m A_C (check) = 50 × 18 = 900 m² ✓ AREA BALANCE CHECK: A_A + A_B + A_C = 1 600 + 1 500 + 900 = 4 000 m² ✓ (equals original parcel area — no deductions specified) ANSWER: (a) d₁ = 32.00 m from left boundary (b) d₂ = 62.00 m from left boundary (c) Lot C area = 900 m²

Question Type

numerical

Answer Structure

• GIVEN block: all dimensions, areas, orientation of dividing lines [½ mark]
• Part (a): d₁ = 1600/50 = 32.00 m with formula shown [1½ marks]
• Part (b): x_B = 30 m; d₂ = 32+30 = 62.00 m — cumulative distance correct [1½ marks]
• Part (c): A_C = 4000 − 1600 − 1500 = 900 m², verified via remaining distance [1 mark]
• Area balance check: sum = 4000 m² ✓ [½ mark]

Scoring Breakdown

Common Mark Deductions

• Setting d₂ = x_B = 30 m instead of cumulative d₁ + x_B = 62 m — loses Mark 3 (most common error on multi-lot problems).
• Using w = 80 m instead of 50 m — misidentifying the width parallel to the dividing lines.
• Not showing the formula x = A₁/w before substituting — loses process marks.
• Skipping the double verification of Lot C (subtraction AND remaining-distance check) — loses the verification mark.
• Arithmetic errors in the area balance check — loses the final mark even if individual answers are correct.

Key Phrases To Include

• x = A₁ / w
• d₁ = 32.00 m
• d₂ = 62.00 m
• cumulative distance
• 900 m²
• area balance
• 4 000 m²
• w = 50 m

Marks

5

Topic

Consolidation-Subdivision — Full Procedure

Difficulty

hard

Template Id

T12

Examiner Tip

A 5-mark long-answer must have 5 clearly distinguishable content points. Use numbered steps to make it easy for the examiner to award all 5 marks. Always include the geodetic reference (PRS92/PPCS-UTM) and legal framework (PD 1529, RA 8560) to signal professional-level knowledge.

Model Answer

A Consolidation-Subdivision (Cons-Subd) survey involves two sequential operations — consolidation of existing parcels and re-subdivision of the merged parcel — carried out in a single survey engagement. The procedure is as follows: 1. PRELIMINARY/OFFICE WORK (Pre-field) [1 mark] The Geodetic Engineer (GE) secures copies of all existing titles (TCTs/OCTs) and approved plans for the parcels to be consolidated, verifies ownership and lot descriptions with the Register of Deeds under PD 1529, obtains the DENR/LRA survey authority or BLM authority if required, and prepares a tentative consolidation-subdivision layout based on the development plan. 2. CONTROL AND TIE-IN SURVEY [1 mark] The GE establishes or recovers survey control using PPCS/UTM coordinates referenced to PRS92 (or WGS84 where applicable), ties all existing monuments of the subject lots to the control network, and verifies that existing boundaries match the technical descriptions in the titles. 3. BOUNDARY SURVEY AND CONSOLIDATION [1 mark] All existing lot corners of the parcels to be merged are located, occupied, and verified. The interior (shared) boundaries between lots are identified for dissolution. The outer perimeter of the consolidated parcel is surveyed and its area computed — this area must equal the sum of the individual lot areas. 4. RE-SUBDIVISION LAYOUT AND COMPUTATION [1 mark] New lot lines (dividing lines) are established within the consolidated parcel according to the approved subdivision layout. Areas of new lots are computed — typically using coordinate methods (double meridian distance or coordinate area formula) for irregular lots. New corners are set and monumented. The sum of all new lot areas plus any road/easement reservations must equal the consolidated area (area balance). 5. PLAN PREPARATION AND SUBMISSION [1 mark] The GE prepares the Cons-Subd Plan drawn to scale, showing all new lots with bearings, distances, areas, and lot numbers; prepares technical descriptions for each new lot; compiles computation sheets; and submits the plan package to the LRA/DENR for approval. Upon approval, the plan is presented to the Register of Deeds, which cancels the original titles and issues new TCTs for each new lot under PD 1529. Throughout, the GE ensures that the professional seal and signature appear on all plans and technical descriptions as required by RA 8560 (Geodetic Engineering Act).

Question Type

long_answer

Answer Structure

• Step 1: Preliminary/office work — secure titles, obtain authority, prepare layout [1 mark]
• Step 2: Control and tie-in survey — PPCS/UTM, PRS92, verify existing monuments [1 mark]
• Step 3: Boundary survey and consolidation — verify corners, dissolve interior boundaries, sum areas [1 mark]
• Step 4: Re-subdivision layout and computation — establish dividing lines, compute new areas, verify area balance [1 mark]
• Step 5: Plan preparation and submission — Cons-Subd Plan, technical descriptions, LRA/RD approval, title issuance [1 mark]

Scoring Breakdown

Common Mark Deductions

• Describing only the subdivision phase without the consolidation phase — loses Steps 1 and 3 marks.
• No mention of PPCS/UTM or PRS92 for the control survey — loses the geodetic framework mark.
• Not stating area balance verification — loses part of Step 4 mark.
• Omitting the plan approval and title issuance step (LRA/RD) — loses Step 5 mark.
• Not citing PD 1529 or RA 8560 — loses legal-framework marks in law-emphasis questions.
• Writing as continuous prose without numbered steps — harder for examiner to allocate marks; use numbered steps.

Key Phrases To Include

• consolidation-subdivision
• TCT/OCT
• PD 1529
• PPCS/UTM
• PRS92
• interior boundaries dissolved
• area balance
• dividing lines
• technical descriptions
• LRA approval
• Register of Deeds
• RA 8560
• signed and sealed

Marks

1

Topic

Area Partition — Area Balance Principle

Difficulty

easy

Template Id

T13

Examiner Tip

Every 'what is the significance' question needs both WHAT happens and WHY it matters. State both in one clear sentence.

Model Answer

The area balance check verifies that the sum of all new lot areas (plus any road lots, easements, or open-space reservations) equals the total area of the original parcel, thereby confirming mathematical consistency of the survey and preventing future disputes over missing or extra area in the titles.

Question Type

very_short_answer

Answer Structure

• One sentence: sum of parts equals original area + purpose (mathematical consistency + prevent disputes) [1 mark]

Scoring Breakdown

Common Mark Deductions

• Saying only 'areas must add up' without explaining why — too vague, may lose the mark.
• Not mentioning that road lots and easements are included in the balance — incomplete answer.

Key Phrases To Include

• sum of new lot areas
• equals original area
• road lots and deductions
• mathematical consistency
• prevent disputes

Marks

2

Topic

Legal Framework — PD 1529 and Titling

Difficulty

medium

Template Id

T14

Examiner Tip

Know the law-to-function mapping: PD 1529 → title registration (RD); RA 8560 → GE profession; CA 141 → public lands; RA 4374/8560 → cadastral surveys. Don't mix them up.

Model Answer

The primary law is Presidential Decree No. 1529, known as the Property Registration Decree. [1 mark] Under PD 1529, the registered owner must submit an approved subdivision plan — prepared, signed, and sealed by a duly licensed Geodetic Engineer — together with the technical descriptions of each new lot to the Register of Deeds. The Register of Deeds then cancels the original certificate of title and issues new Transfer Certificates of Title (TCTs) for each subdivided lot. [1 mark]

Question Type

short_answer

Answer Structure

• Sentence 1: Cite PD 1529 and its official title [1 mark]
• Sentence 2: Describe requirement — approved subdivision plan signed/sealed by GE submitted to Register of Deeds; original title cancelled; new TCTs issued [1 mark]

Scoring Breakdown

Common Mark Deductions

• Citing RA 8560 (GE Act) instead of PD 1529 — wrong law for registration; loses Mark 1.
• Not mentioning the GE's signature and seal requirement — loses part of Mark 2.
• Confusing LRA approval with Register of Deeds titling — these are different offices with different roles.

Key Phrases To Include

• Presidential Decree No. 1529
• Property Registration Decree
• approved subdivision plan
• signed and sealed
• licensed Geodetic Engineer
• Register of Deeds
• cancels original title
• new TCTs

Marks

5

Topic

Consolidation-Subdivision — Full Numerical Problem

Difficulty

hard

Template Id

T15

Examiner Tip

In Cons-Subd numerical problems, always identify clearly: (i) original lots for consolidation, (ii) new lots from re-subdivision. Carry the consolidated area exactly into the re-subdivision computation — rounding errors here lose marks.

Model Answer

GIVEN: Lot 1 = 1 200 m²; Lot 2 = 850 m²; Lot 3 = 1 500 m² Re-subdivision: 4 equal new lots New lot depth = 25 m (common depth, perpendicular to frontage) REQUIRED: (a) Consolidated total area (b) Area of each new lot (c) Frontage of each new lot SOLUTION: (a) Consolidated area: A_total = 1 200 + 850 + 1 500 = 3 550 m² (b) Area of each new lot (4 equal lots): A_new = 3 550 / 4 = 887.50 m² (c) Frontage of each new lot: Using Area = frontage × depth: Frontage = A_new / depth = 887.50 / 25 = 35.50 m AREA BALANCE CHECK: 4 × 887.50 = 3 550 m² ✓ (equals consolidated area — no road deductions specified) ANSWER: (a) Consolidated area = 3 550 m² (b) Each new lot = 887.50 m² (c) Each new lot frontage = 35.50 m

Question Type

numerical

Answer Structure

• GIVEN block with all three original areas and new lot parameters [½ mark]
• Part (a): 1200+850+1500 = 3550 m² [1 mark]
• Part (b): 3550/4 = 887.50 m² per lot [1½ marks]
• Part (c): Frontage = 887.50/25 = 35.50 m with formula Area = frontage × depth [1½ marks]
• Area balance check: 4 × 887.50 = 3550 m² ✓ [½ mark]

Scoring Breakdown

Common Mark Deductions

• Arithmetic error in consolidation sum (3550) — loses Mark 1 and cascades.
• Dividing by 3 (number of original lots) instead of 4 (number of new lots) — conceptual error, loses Mark 2.
• Using depth as the frontage and frontage as the depth — fundamental dimensional error, loses Mark 3–4.
• Skipping the area balance check — loses the final mark.
• Answers without units (m, m²) — standard ½-mark deduction.

Key Phrases To Include

• 3 550 m²
• 887.50 m²
• 35.50 m
• frontage = area / depth
• 4 equal lots
• area balance
• consolidated area