CELE Reinforced & Prestressed Concrete — Prestressed ConcreteStudy Notes
Thorough study notes for Prestressed Concrete — the fastest path from zero to ready for CELE Reinforced & Prestressed Concrete. Structured for self-study reviewers who cannot attend a review centre, these notes cover the full concept library plus the CELE-specific twists Professional Regulation Commission (PRC) — Board of Civil Engineering adds to its questions.
Exam context
On the CELE 2026, the Reinforced & Prestressed Concrete subtest carries a "Core" weight in Professional Regulation Commission (PRC) — Board of Civil Engineering's pattern. Prestressed Concrete lands at position 7th out of 7 in the standard review order. Target score is 70% weighted average, no sub-test below 50%, and roughly a meaningful share of items come from Reinforced & Prestressed Concrete on a typical CELE paper.
Prestressed Concrete - Study Notes
Prestressed concrete is a highly engineered material that introduces controlled internal compression into concrete members before service loads are applied. Unlike ordinary reinforced concrete (RC) which relies on steel reinforcement to control cracking, prestressed concrete uses the principle of precompression to keep the concrete in a state of compression (or low tension) under full service load. This fundamental difference allows prestressed members to span greater distances, use shallower depths, and achieve superior performance in terms of crack control and deflection resistance. For Filipino civil engineers preparing for the PRC Licensure Examination, mastery of prestressed concrete design is essential—particularly given the widespread use of prestressed members in Philippine infrastructure: bridge girders (DPWH designs), precast piles, hollow-core slabs in commercial buildings, and transfer beams in high-rise construction. This chapter covers the conceptual basis, analytical methods, loss mechanisms, and design procedures aligned with ACI 318-19, NSCP 2015 (which adopts ACI), and practical Philippine applications.
Summary
Prestressed concrete is a transformative design approach that introduces internal compression to counteract service-load tensile stresses, enabling longer spans, shallower sections, excellent crack control, and superior durability—all critical for modern infrastructure. The two primary methods—pre-tensioning (strand released after concrete cures, transferred by bond) and post-tensioning (tendons anchored after curing, mechanically transferred)—serve different project types but follow similar design principles. Service stress analysis (superposing axial prestress, eccentricity moment, and applied load moment) is straightforward arithmetic if sign conventions are carefully tracked. Prestress losses (elastic shortening, friction, anchorage seating, creep, shrinkage, relaxation) reduce the initial jacking force to an effective value; in tropical climates like the Philippines, time-dependent losses are significant and must be estimated using code-provided methods. Load balancing—selecting tendon force and sag to create an upward distributed load equal to (or greater than) a desired fraction of the applied load—elegantly minimizes bending moments and deflections, delivering 50% or greater moment reduction and 80%+ deflection reduction compared to non-prestressed design. Composite sections (precast beam + cast-in-place slab) require two-stage analysis: stress checks at transfer use beam properties; service checks use composite properties after the slab has cured and bonded. Design is inherently iterative, driven by multiple limits: transfer stage (top-fiber tension risk), service stage (bottom-fiber compression/tension risk), and deflection. Proper grouting of post-tensioned ducts and robust non-prestressed reinforcement are essential for durability and safety. NSCP 2015 (adopting ACI 318-19) provides the detailed analysis framework, loss calculation methods, and stress limits. For Filipino engineers designing critical structures (bridges, buildings, port facilities), prestressed concrete offers unmatched performance and economy—a core competency expected on the PRC Civil Engineer Licensure Examination.
Sections
Prestressing is the intentional application of an internal compressive stress in a concrete member to counteract or reduce the tensile stresses that will be induced by service loads. The core principle is simple: if you precompress a material that is weak in tension (like concrete), you can reduce or eliminate tension when external loads are applied. Consider an analogy common in Philippine engineering textbooks: imagine a masonry column made of stacked bricks (analogous to concrete). Stacked dry, it collapses under its own weight because bricks cannot handle tension at the mortar joints. But if you clamp the column from the top and bottom (applying compressive force), the bricks stay tightly bound and can carry load far better. Prestressing works the same way—the "clamp" is provided by high-strength steel tendons. The advantages of prestressed concrete are substantial: 1. **Crack Control:** Precompression keeps concrete in compression (or low tension) under service load, virtually eliminating flexural cracks. This greatly improves durability—cracks are the primary pathway for water and chloride ingress (critical in Philippine coastal environments). 2. **Reduced Deflection:** Precompression acts as an upward load (load balancing), reducing the net bending moment and deflection. NSCP 2015 and ACI 318 typically allow larger span-to-depth ratios for prestressed members. 3. **Longer Spans:** Because cracks and large deflections are suppressed, prestressed girders can span 50+ meters (versus 20–30 m for RC), making them ideal for long-span bridges and viaducts. 4. **Efficient Use of Material:** High-strength steel (tendons at 1,700–1,900 MPa) is fully stressed, and concrete is kept in a favorable stress state throughout—reducing concrete section and steel quantity. 5. **Factory Quality Control:** Pre-tensioned members (common in Philippine precast plants) benefit from controlled plant production, ensuring consistent quality and durability. However, prestressed concrete has costs and constraints: - Higher initial material and labor cost (tensioning equipment, specialised labor). - More complex analysis and design. - Less ductility than RC (though still adequate under proper design). - Sensitive to mishandling during production and installation (sudden loss of support can cause cracking).
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1. Fundamental Concepts: Prestress and Its Advantage
Examples
Example 1.1 — Why precompression matters
Problem
A concrete member spans 30 m. If designed as ordinary RC, the maximum allowable span-to-depth ratio (per NSCP 2015) is about 20, requiring a depth of h = 30,000 mm / 20 = 1,500 mm. If prestressed, the ratio can reach 35, requiring h = 30,000 / 35 ≈ 860 mm. Compare the volume of concrete and dead load.
Solution
Assuming a typical I-girder with web width 300 mm and flange dimensions, the RC section might have volume ~3.5 m³/m length, while the prestressed section is ~2.0 m³/m. Dead load reduction: (3.5 − 2.0) / 3.5 ≈ 43%, which significantly reduces internal moments and supports longer unsupported construction runs—critical in remote Philippine sites.
Key Insight
Lighter sections reduce dead load, which itself reduces the driving moment, creating a favorable spiral. This is why Philippine infrastructure heavily uses prestressed girders.
Key Points
- Prestressing introduces controlled internal compression to counteract tensile stresses from service loads.
- Primary benefits: crack control, reduced deflection, longer spans, and material efficiency.
- Critical advantage in tropical/coastal Philippine environments (durability via crack control).
- Prestressed members are suitable for infrastructure like bridges, viaducts, precast buildings, and long-span roofs.
- NSCP 2015 and ACI 318-19 govern design; also relevant: RA 9178 (National Building Code references prestressed design).
Prestress is applied to concrete by two fundamentally different methods, each suited to different applications: ### 2.1 Pre-tensioning In pre-tensioning, high-strength steel strands (typically seven-wire strands conforming to ASTM A416) are tensioned **before** the concrete is cast. The process is: 1. **Stressing:** Strands are pulled between two fixed abutments (at a precast plant) using hydraulic jacks, typically to 75% of the ultimate strand strength. For a common 12.7 mm (1/2") strand with f_pu = 1,860 MPa, the jacking stress is ~1,395 MPa. 2. **Casting:** Concrete is cast around the tensioned strands. 3. **Curing:** The concrete cures (steam or normal time). 4. **Release:** Once the concrete reaches sufficient strength (typically f'_ci ≥ 24.5 MPa, per ACI 318), the strands are released from the abutments. The concrete, now bonded to the strands via friction and mechanical interlock, prevents the strands from relaxing fully, retaining the precompressive stress. The transfer of prestress from strand to concrete is by **bond** (friction and adhesion) along the strand length. Near the ends, the strands slip slightly as the load is transferred—the "transfer length" (typically 40–50 strand diameters, or ~600–800 mm for 12.7 mm strands) is the distance over which full prestress is developed. **Advantages of pre-tensioning:** - Excellent bond (no unbonded length). - Long-term durability (no ducts or grout). - Ideal for repetitive members (hollow-core slabs, piles, standard girders)—amortizes plant cost. - Excellent quality control in a factory environment. **Disadvantages:** - Fixed geometry (tendons cannot be draped)—all members have the same eccentricity profile. - Requires large abutments and tensioning beds. - Elastic shortening losses occur before release. - Not practical for unique or curved members (e.g., irregular bridge decks). **Common pre-tensioned members in the Philippines:** - Precast hollow-core slabs (widely used in residential and commercial buildings). - Precast piles (for deep-water and soft-soil foundations). - Standard I-girders and box girders (DPWH bridge standards). - Architectural precast panels. ### 2.2 Post-tensioning In post-tensioning, tendons (cables or individual strands) are routed through ducts in the concrete member and tensioned **after** the concrete has cured to sufficient strength. The process is: 1. **Ducting:** Metal or plastic ducts are cast into the member, running along the intended tendon path (which can be straight, draped parabolic, or polygonal). 2. **Placement:** Strands or cables are threaded through the ducts after casting. 3. **Tensioning:** After concrete reaches sufficient strength, the tendons are tensioned using anchoring devices (typically fixed anchors at one end, movable jacks at the other). Tension is applied in stages, monitored by load cells and extension measurements, to minimize shock and ensure uniform stress. 4. **Anchoring:** Once tensioned, the tendons are anchored against fixed devices at each end (e.g., wedge-cone anchors). 5. **Grouting (optional but recommended):** The duct is filled with cement grout to protect the tendons from corrosion, restore structural continuity, and improve long-term performance. Grouting is **essential** in Philippine climate (high humidity, salt spray in coastal zones). **Advantages of post-tensioning:** - **Draped tendons:** Can be curved (parabolic, polygonal) to follow moment diagrams, improving load balancing and efficiency. - **Flexible geometry:** Suited to unique structures (curved bridges, irregular transfer beams, long-span slabs). - **Reduced dead load during construction:** Prestress is applied after concrete cures, allowing temporary supports to be removed earlier. - **Adaptable:** Tendon layout and force can be tailored to the specific structure. **Disadvantages:** - Friction losses occur during tensioning (especially significant for long or highly draped tendons). - Requires skilled labor and specialized equipment (jacking, grouting). - Ducts must be grouted to prevent corrosion and ensure durability—poor grouting is a common failure mode. - Slightly higher cost per member (but competitive for large, unique structures). **Common post-tensioned structures in the Philippines:** - Bridge decks and box girders (especially curved or long-span). - Transfer beams (supporting columns in high-rise buildings—common in Manila developments). - Long-span slabs (parking structures, auditoriums). - Marine/port structures (subject to corrosion—grouting is critical). - Building facades and special architectural elements. ### 2.3 Comparison Table | Aspect | Pre-tensioning | Post-tensioning | |--------|---|---| | **Timing** | Strand tensioned before casting | Tensioned after curing | | **Bond** | Bond over full length | Unbonded before grouting, bonded after | | **Geometry** | Straight or standard profile | Can be fully draped/curved | | **Transfer** | Bond friction (~600–800 mm) | Mechanical anchors (localized) | | **Applications** | Repetitive, standard shapes | Unique, long-span, variable sections | | **Friction loss** | Minimal (no duct) | Significant for draped tendons | | **Corrosion protection** | No duct (but strand quality critical) | Requires grouting (essential in Philippines) | | **Plant cost** | High (abutments, beds) | Lower per member | | **Philippine use** | Precast hollow-core, piles, standard girders | Bridges, transfer beams, special structures | For PRC exam purposes, be prepared to identify the appropriate method for a given structure and to explain the load transfer mechanism in each case.
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2. Pre-tensioning vs. Post-tensioning: Methods and Mechanisms
Examples
Example 2.1 — Transfer length in pre-tensioning
Problem
A 12.7 mm (1/2") seven-wire strand with f_pu = 1,860 MPa is used in a pre-tensioned beam. The strand is jacked to 75% f_pu. Estimate the transfer length and check the stress at 400 mm from the end of the beam.
Solution
Jacking stress: f_pj = 0.75 × 1,860 = 1,395 MPa. Transfer length per ACI 318: ℓ_t = (f_pj − f_r) d_b / 25.4, where f_r ≈ 310 MPa (residual), d_b = 12.7 mm. ℓ_t = (1,395 − 310) × 12.7 / 25.4 ≈ 542 mm. At 400 mm from the end: stress is not yet fully developed; approximate linear variation: f_p(400) ≈ (400/542) × 1,085 ≈ 800 MPa. In design, stresses within the transfer length must be checked for local bearing and splitting.
Key Insight
Transfer length is zone of stress concentration; anchorage provisions (spirals, confining reinforcement) are often needed near the ends of pre-tensioned members to prevent splitting failure.
Example 2.2 — Friction loss in post-tensioning
Problem
A post-tensioned beam is 20 m long with a parabolic tendon. The jacking stress is f_pj = 1,395 MPa. Estimate friction losses assuming a coefficient of friction μ = 0.25 and wobble coefficient K = 0.004 per meter. The maximum sag is 1.2 m (sag-to-span ratio ≈ 1.2/20 = 0.06).
Solution
Total angular change for parabolic profile: α = 8e/L = 8 × 1.2 / 20 = 0.48 rad ≈ 27.5°. Friction force loss: ΔP_friction / P = (1 − e^(−μα)) ≈ 1 − e^(−0.25 × 0.48) ≈ 1 − e^(−0.12) ≈ 0.113 (11.3%). Wobble loss: ΔP_wobble / P = KL = 0.004 × 20 = 0.08 (8%). Total loss ≈ 11.3% + 8% ≈ 19.3%. Thus, effective prestress ≈ (1 − 0.193) × 1,395 ≈ 1,125 MPa. This is significant and must be included in design.
Key Insight
Friction losses can be substantial in highly draped, long tendons. NSCP 2015 requires explicit calculation or use of empirical factors. Proper grouting after tensioning can slightly recover some stiffness but not prestress.
Key Points
- Pre-tensioning: strand tensioned before casting, transferred by bond; ideal for repetitive, standard shapes; common in Philippine precast plants.
- Post-tensioning: tendons in ducts, tensioned after curing, anchored mechanically; suitable for unique, draped, long-span structures.
- Transfer of prestress: pre-tensioning via friction bond over ~40–50 strand diameters; post-tensioning via mechanical anchorage (immediate).
- Friction losses in post-tensioning ducts depend on duct alignment (wobble) and tendon curvature—accounted for in design (ACI 318 Section 18.6).
- Grouting of post-tensioned ducts is essential in Philippine climate (tropical, salt-spray exposure)—poor grouting leads to strand corrosion and structural failure.
- NSCP 2015 and ACI 318 differ slightly in loss calculations and friction coefficients; always reference the applicable code (NSCP 2015 is mandatory for Philippine projects).
The service stress state in a prestressed beam is found by superposing three components: (1) the axial prestress, (2) the moment due to eccentricity of the prestress (secondary moment), and (3) the bending moment due to applied loads. This superposition is the cornerstone of prestressed concrete design. ### 3.1 Stress Components For a simply supported beam with uniform cross-section, mid-span section, consider: - **Prestress force:** P (in kN or N), acting at eccentricity e below the centroid (positive e means below = toward bottom fiber). - **Applied moment:** M (in kN·m), due to sustained and live loads, causing sagging (compressing top, tensioning bottom). The stress at the top fiber (y = c_top from centroid) is: $$f_{\text{top}} = \frac{P}{A} - \frac{Pec_{\text{top}}}{I} + \frac{Mc_{\text{top}}}{I}$$ The stress at the bottom fiber (y = c_bot = d − c_top) is: $$f_{\text{bot}} = \frac{P}{A} + \frac{Pec_{\text{bot}}}{I} - \frac{Mc_{\text{bot}}}{I}$$ Where: - P/A = axial prestress (compression, positive). - Pec/I = flexural effect of eccentric prestress; note the **sign difference** between top and bottom. - Mc/I = flexural effect of applied load. **Sign Convention (Critical for PRC exams):** - **Compression** is taken as **positive** (common in prestress analysis). - An eccentric prestress **below** the centroid (e > 0 downward) causes **extra compression at the bottom** and **relief (less compression or tension) at the top**. - Applied sagging moment causes **compression at the top** and **tension at the bottom**. The design goal is to balance these stresses so that: - **At transfer (initial, Pi applied):** concrete is just barely at the edge of tension (or safe compression) at the top fiber, and safely in compression at the bottom. - **In service (effective, Pe applied + full load):** both fibers are within allowable stresses (typically no tension, or very low allowable tension per ACI 318 Section 24.4.2). ### 3.2 Allowable Service Stresses (NSCP 2015 and ACI 318) NSCP 2015 adopts ACI 318-19 for prestressed concrete design. Key allowable stresses (for service load conditions) are: **Immediately after transfer (before time-dependent losses):** - **At top fiber:** f'_ci is the compressive strength at transfer (typically 24.5–27.6 MPa for rapid curing). Allowable compression = 0.6 f'_ci ≈ 14.7–16.6 MPa. Allowable tension (limited, to control cracking) = 0.5√(f'_ci) ≈ 2.5–2.8 MPa (if bonded reinforcement provided). - **At bottom fiber:** Allowable compression = 0.6 f'_ci (same as top). **In service (sustained load + live load, after losses):** - **Compressive stress:** 0.45 f'_c (where f'_c is 28-day concrete strength, typically 35–40 MPa for prestressed members). Allowable ≈ 15.75–18 MPa. - **Tensile stress:** 0 (zero; no tension in service, or very limited per ACI 318 Table 24.4.2). Some designers allow 0.5√(f'_c) ≈ 3–3.3 MPa if longitudinal bonded reinforcement is provided to control cracking. **Design approach (typical NSCP/ACI process):** 1. **At transfer:** Check that the top fiber does not exceed allowable tension (or compression), using Pi and initial moment M_i (if applicable, e.g., self-weight on temporary supports). 2. **In service:** Check that both fibers remain within allowable stresses under Pe and full applied moment (dead load + live load). Often, the **critical stress** is the **top fiber at transfer** (risk of cracking/delamination) or the **bottom fiber in service** (risk of over-compression or yielding of reinforcement if present). ### 3.3 Practical Example: Rectangular Beam Consider the example from the reference material: **Given:** - Section: 300 mm wide × 600 mm deep. - A = 180,000 mm², I = 5.4 × 10⁹ mm⁴, c_top = c_bot = 300 mm. - Prestress: P_e = 900 kN at e = 150 mm (below centroid). - Applied moment: M = 120 kN·m (due to sustained + live load). **Calculate section properties:** $$\frac{P}{A} = \frac{900 \times 10^3 \text{ N}}{180 \times 10^3 \text{ mm}^2} = 5.0 \text{ MPa}$$ $$\frac{Pec}{I} = \frac{900 \times 10^3 \text{ N} \times 150 \text{ mm} \times 300 \text{ mm}}{5.4 \times 10^9 \text{ mm}^4} = \frac{40.5 \times 10^9}{5.4 \times 10^9} = 7.5 \text{ MPa}$$ $$\frac{Mc}{I} = \frac{120 \times 10^6 \text{ N·mm} \times 300 \text{ mm}}{5.4 \times 10^9 \text{ mm}^4} = \frac{36 \times 10^9}{5.4 \times 10^9} = 6.67 \text{ MPa}$$ **Top fiber stress:** $$f_{\text{top}} = 5.0 - 7.5 + 6.67 = 4.17 \text{ MPa (compression)}$$ **Bottom fiber stress:** $$f_{\text{bot}} = 5.0 + 7.5 - 6.67 = 5.83 \text{ MPa (compression)}$$ **Interpretation:** - Both fibers are in **compression**—no cracking risk. - The top fiber has lower stress (4.17 MPa) because the eccentric prestress (below centroid) relieves the top, but the applied moment compresses it back down. - The bottom fiber has higher stress (5.83 MPa) because both the eccentric prestress and the applied load moment compress it. - Assuming f'_c = 35 MPa, allowable service compression = 0.45 × 35 = 15.75 MPa. Both actual stresses are **well within** the limit—indicating efficient, safe design with room for live-load growth or cost optimization (e.g., reducing P or section). ### 3.4 Transfer vs. Service: The Critical Fiber Flip One of the most common pitfalls in PRC exams is forgetting that the **critical fiber changes** between transfer and service: - **At transfer (immediately after release, with Pi and minimal load):** The top fiber is at maximum risk of **tension** (or over-compression if prestress is excessive). The bottom fiber is safe. **Check top fiber first.** - **In service (with Pe and full load):** The applied moment compresses the top and tensions the bottom. Now the **bottom fiber is at risk** (over-compression or insufficient precompression). **Check bottom fiber first.** Example scenario: - At transfer, top fiber: f = P_i/A − P_i e c_top/I = 8 − 10 = −2 MPa (tension). **Unsafe if allowable tension < 2 MPa.** - In service, bottom fiber: f = P_e/A + P_e e c_bot/I − M c_bot/I = 4 + 8 − 12 = 0 MPa (neutral). **Safe, but only just.** Designers must check **both stages** and iterate on section and prestress level to satisfy both. ### 3.5 Load Case Analysis NSCP 2015 and ACI 318 require stresses to be checked at multiple load cases: 1. **At transfer (immediately after release):** - Prestress force: P_i (initial, before losses). - Load: typically self-weight (if the member is propped) or zero (if simply supported during release). 2. **Service—sustained load (dead load only):** - Prestress force: P_s (after immediate/elastic losses). - Load: self-weight + other permanent loads. 3. **Service—total load (dead + live):** - Prestress force: P_e (effective, after all losses). - Load: self-weight + live load (and other temporary loads). Stress limits vary slightly between cases. For a typical exam problem, assume: - **At transfer:** Top fiber limited to ~0.5√(f'_ci) tension or 0.6 f'_ci compression. - **Service (sustained):** Slightly relaxed limits (some provisions allow 0.25 f'_c tension with bonded reinforcement). - **Service (total):** Most restrictive—typically zero tension unless bonded reinforcement is present. The correct approach is to **read the problem carefully** and **identify which load case is being asked about**, then apply the correct stress limits.
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3. Service Stresses in Prestressed Beams: Stress Superposition
Examples
Example 3.1 — Transfer stage stress check
Problem
A pre-tensioned I-beam has initial prestress P_i = 1,200 kN at eccentricity e = 250 mm. Section: A = 250,000 mm², I = 10 × 10⁹ mm⁴, c_top = 350 mm, c_bot = 350 mm. At transfer, load = self-weight moment M_sw = 80 kN·m. Check if top fiber is safe. f'_ci = 26 MPa. Allowable top-fiber tension at transfer = 0.5√(f'_ci) ≈ 2.55 MPa.
Solution
Axial: P_i/A = 1,200 × 10³ / 250 × 10³ = 4.8 MPa. Eccentricity moment (top): − P_i e c_top / I = − 1,200 × 10³ × 250 × 350 / (10 × 10⁹) = −10.5 MPa (relief). Applied moment (top): M c_top / I = 80 × 10⁶ × 350 / (10 × 10⁹) = 2.8 MPa (compression from self-weight). Top fiber: f_top = 4.8 − 10.5 + 2.8 = −3.0 MPa (tension). **Allowable: 2.55 MPa. Actual: −3.0 MPa (magnitude 3.0 > 2.55). UNSAFE.** Remedies: increase P_i, increase e, increase section depth (c_top), or reduce load (not practical). Design would iterate to find a safe combination.
Key Insight
Transfer top-fiber tension is often the limiting case in design. High eccentricity helps (adds compression to top) but increases loss-of-support risk. Designers balance multiple constraints.
Example 3.2 — Service stage stress check
Problem
Same beam as Example 3.1, but in service. Effective prestress P_e = 0.85 × 1,200 = 1,020 kN (after losses). Applied moment M_total = 200 kN·m (dead + live load). f'_c = 35 MPa. Allowable: compression ≤ 0.45 f'_c = 15.75 MPa, tension ≤ 0 (strict). Check both fibers.
Solution
Axial: P_e/A = 1,020 × 10³ / 250 × 10³ = 4.08 MPa. Eccentricity moment (both): ± P_e e c / I = ± 1,020 × 10³ × 250 × 350 / (10 × 10⁹) = ± 8.925 MPa. Applied moment: M c / I = 200 × 10⁶ × 350 / (10 × 10⁹) = 7.0 MPa. Top fiber: f_top = 4.08 − 8.925 + 7.0 = 2.155 MPa (compression). **Safe.** Bottom fiber: f_bot = 4.08 + 8.925 − 7.0 = 6.005 MPa (compression). **Safe.** Both fibers in compression, well within limits—design is conservative (can optimize).
Key Insight
Service bottom-fiber stress is the secondary check. If it violates limits (too much compression), increase eccentricity e or reduce P (both worsen transfer condition). Design requires iteration and judgment.
Key Points
- Service stress = axial prestress ± eccentricity moment ± applied load moment. Sign convention: compression positive.
- Eccentric prestress below centroid adds compression to bottom, relieves top—opposite of gravity moment.
- Critical fiber at transfer: top (tension risk). Critical fiber in service: bottom (over-compression risk).
- NSCP 2015/ACI 318 allowable stresses: at transfer, ~0.5–0.6 f'_ci; in service, ~0.45 f'_c for compression, ~0 for tension (strict).
- Must check **both** transfer and service stages; design often limited by transfer top-fiber tension.
- Applied moment superposition is straightforward arithmetic if sign conventions are clear and consistent.
The prestress force in a member decreases from the jacking value (P_i) to a smaller effective value (P_e) due to various loss mechanisms. These losses must be predicted and accounted for in design; underestimating losses can lead to insufficient precompression in service. ### 4.1 Classification of Losses Losses are classified as **immediate** (occurring during and shortly after tensioning) or **time-dependent** (ongoing over the life of the structure). #### 4.1.1 Immediate Losses **1. Elastic Shortening (ΔP_es)** When the prestress force is applied to the concrete member, the concrete itself undergoes elastic compression. The tendon, bonded to the concrete, follows this shortening and thus loses stress proportional to the shortening strain. **For pre-tensioning:** Elastic shortening occurs during concrete curing (before release), so the loss is subtracted from P_i to find the stress just after release. The loss depends on the stress in the concrete at the centroid of the prestressing steel: $$\Delta P_{\text{es}} = \frac{A_p}{A_c} \cdot E_p \cdot \epsilon_{\text{cc}} = \frac{A_p}{A_c} \cdot \frac{f_{\text{cir}}}{E_c}$$ where: - A_p = area of prestressing steel. - A_c = area of concrete. - E_p = modulus of elasticity of steel (~197 GPa for strands). - f_cir = stress in concrete due to prestress (P_i / A_c, approximately). - E_c = modulus of concrete (typically ~30–40 GPa for 35 MPa concrete). Typically, ΔP_es ≈ 2–4% of P_i for pre-tensioned members. **For post-tensioning:** Elastic shortening occurs slightly differently. As the tendon is tensioned, the concrete pushes back, and the anchorage point (jack) must move slightly to maintain the target stress. The loss is often negligible in post-tensioning because the jacking stage is brief and the member is already (mostly) at full load. However, if **sequential tensioning** is used (tensioning multiple tendons in stages), each earlier tendon loses stress due to elastic shortening caused by the later ones. This can be significant and is calculated as: $$\Delta P_{\text{es, sequential}} = \frac{A_p}{A_c} \cdot E_p \cdot \frac{\sum P_i}{E_c A_c}$$ For typical post-tensioned buildings with multiple tendons, sequential loss ≈ 3–5% per tendon. **2. Anchorage Seating Loss (ΔP_as)** **Post-tensioning only:** When a tendon is anchored (e.g., by driving wedges into a cone-shaped anchor head), the wedges slip slightly as they seat into their conical cavity. This slip—typically 5–10 mm for common anchors—causes the tendon to relax slightly near the anchor, losing stress over a distance ("seating distance") of typically 1–3 m. The loss is: $$\Delta P_{\text{as}} \approx \frac{\Delta L_{\text{seat}} \cdot E_p \cdot A_p}{L_{\text{tendon}}}$$ For a 20 m tendon with 6 mm seat slip, E_p = 197 GPa, A_p = 140 mm² (one strand): $$\Delta P_{\text{as}} \approx \frac{6 \times 197 \times 140}{20 \times 10^3} \approx 82.6 \text{ kN per strand} \approx 3–5\% \text{ (typical)}$$ Anchorage seating loss is reduced or eliminated by carefully selecting anchorage devices and monitoring the stressing process. **3. Friction Loss in Post-tensioning Ducts (ΔP_f)** As the tendon is pulled through a curved duct, friction between the tendon and the duct wall resists motion. The relationship is given by the **Capstan equation** (also called the Eytelwein formula): $$P(x) = P_0 e^{-\mu(\theta + Kx)}$$ where: - P(x) = tension at distance x along the tendon. - P_0 = initial (jacking) tension at the active (tensioning) end. - μ = coefficient of friction between tendon and duct (typically 0.20–0.30 for steel strand in metal or plastic duct). - θ = total angular change (in radians) of the tendon along the duct. - K = wobble coefficient, accounting for unintended curvature per unit length (typically 0.004–0.005 per meter for common practice). Rewritten in terms of force loss: $$\frac{\Delta P_f}{P_0} = 1 - e^{-\mu(\theta + KL)} \approx \mu(\theta + KL) \quad (\text{for small exponent})$$ **Example:** A parabolic tendon drapes over a 24 m span with sag e = 1.5 m. Angular change: θ = 8e/L = 8 × 1.5 / 24 = 0.5 rad. Wobble loss: KL = 0.004 × 24 = 0.096 rad. Total: 0.5 + 0.096 = 0.596 rad. With μ = 0.25: $$\Delta P_f / P_0 \approx 0.25 × 0.596 \approx 0.149 \text{ (14.9% loss)}$$ Friction loss can be large for heavily draped tendons and is a key design consideration. NSCP 2015 and ACI 318 provide friction coefficients; designers must use values appropriate to the actual materials and conditions. #### 4.1.2 Time-Dependent Losses **1. Concrete Creep (ΔP_cr)** Concrete continues to deform under sustained stress, gradually (over months to years). This creep increases concrete strain, which (if the tendon is bonded) pulls the tendon along, reducing its stress. The creep strain is related to the sustained stress and the creep coefficient C_c: $$\epsilon_{\text{creep}} = C_c \cdot \frac{f_c}{E_c}$$ where f_c is the sustained concrete stress and C_c ≈ 2–3 for typical long-term creep (10+ years) in tropical climates. Prestress loss due to creep: $$\Delta P_{\text{cr}} \approx A_p \cdot E_p \cdot C_c \cdot \frac{f_c}{E_c}$$ Typically, creep loss ≈ 5–8% of P_i for members in moderate conditions, and **higher in tropical/humid conditions** (like the Philippines), where concrete creep is accelerated. NSCP 2015 includes provisions for this. **2. Concrete Shrinkage (ΔP_sh)** Concrete shrinks as it loses moisture to the environment. Shrinkage occurs most rapidly in the first few weeks but continues for months. If the tendon is bonded (pre-tensioned or grouted post-tensioned), it resists the shrinkage, resulting in stress loss. Shrinkage strain (ultimate, after months to years): $$\epsilon_{\text{sh, ultimate}} \approx 400–800 \times 10^{-6} \quad (\text{depends on w/c, curing, ambient conditions})$$ Loss: $$\Delta P_{\text{sh}} = A_p \cdot E_p \cdot \epsilon_{\text{sh, ultimate}}$$ For a typical strand: $$\Delta P_{\text{sh}} \approx 140 \text{ mm}^2 \times 197 \text{ GPa} \times 500 \times 10^{-6} \approx 13.8 \text{ kN} \approx 2–4\% \text{ (typical)}$$ Shrinkage loss is roughly **proportional to surface-area-to-volume ratio**; thin members (slabs) shrink more than massive members (girders). In the Philippines, low humidity (coastal dry seasons) can exacerbate shrinkage loss. **3. Steel Relaxation (ΔP_rel)** High-strength steel (strands and wires) exhibits **stress relaxation**—gradual stress loss under sustained high stress, even if strain is held constant. This is a material property of the steel, independent of concrete behavior. Relaxation loss depends on: - **Initial stress level:** f_p / f_pu (higher stress → faster relaxation). - **Steel grade:** Low-relaxation strand (common, especially post-1970s) loses ~2–3%; stress-relieved wire loses ~10–15% over 1000 hours. - **Temperature:** Relaxation accelerates at higher temperatures (Philippine tropical climate slightly increases relaxation rate). For low-relaxation strand at f_p / f_pu = 0.75 (typical jacking), relaxation at 1000 hours ≈ 2.5% (one-day relaxation ~1%). At 10,000 hours: ~3.5–4%. Over 10+ years (approximately 87,600 hours), relaxation approaches 5–7% for low-relaxation strand. Typically, **relaxation loss ≈ 3–5%** of P_i for low-relaxation strands. ### 4.2 Total Losses and Effectiveness Factor **Approximate total losses (experienced in practice):** | Condition | Pre-tensioned | Post-tensioned | |-----------|---------------|----------------| | **Immediate** | ES: 2–4% | ES: 1–2% (minor), AS: 3–5%, Friction: 5–20% (depending on geometry) | | **Time-dependent (long-term)** | Creep: 5–8%, Shrinkage: 2–4%, Relaxation: 3–5% | Creep: 5–8%, Shrinkage: 2–4%, Relaxation: 3–5% (tendon only, concrete gains from grouting) | | **Total** | ~15–25% (typical 18–22%) | ~15–35% (typical 20–28%, higher if heavily draped) | **Effectiveness factor (loss ratio):** $$R = \frac{P_e}{P_i} = 1 - \frac{\sum \Delta P}{P_i}$$ For design, R ≈ **0.80–0.85** is commonly used. NSCP 2015 and ACI 318 provide detailed methods and tables for more precise calculations. ### 4.3 Design Practice: Using Losses The design process typically follows: 1. **Estimate total loss percentage** (using code methods or experience tables). 2. **Calculate effective prestress:** P_e = (1 − loss%) × P_i. 3. **Check stresses at transfer** using P_i (before losses occur) to ensure top fiber does not go into excessive tension. 4. **Check stresses in service** using P_e (after all losses) to ensure both fibers remain within allowable limits. 5. **Iterate** section and P_i if either stage violates limits. **A critical insight for exam candidates:** When a problem states "effective prestress P_e = 1,000 kN," this **already includes losses**. Do not apply losses twice. Conversely, if the problem states "jacking stress 1,400 MPa" or "initial prestress P_i = 1,200 kN," you must **calculate or apply losses** to find P_e for the service stage. Read the problem carefully. ### 4.4 Reducing Losses: Engineering Practice For critical structures or high-performance requirements, losses can be minimized: 1. **Use low-relaxation strand** (modern standard in most of the world, including Philippines). 2. **Limit jacking stress** (e.g., 0.75–0.80 f_pu instead of 0.85), reducing creep, shrinkage, and relaxation (but requiring larger section/more strands). 3. **Control concrete shrinkage** (low w/c ratio, proper curing, extended initial moist curing). 4. **Post-grouting** in post-tensioned members stabilizes concrete and can recover some stiffness (though not prestress). 5. **Optimize tendon routing** (minimize friction by avoiding sharp bends). 6. **Two-stage stressing** (partial stress immediately, final stress after some concrete curing)—reduces elastic shortening effects—not common but possible for special projects. In the Philippines, where tropical climate increases creep and shrinkage rates, careful attention to concrete mix design and curing (especially humidity control during the first week) is essential.
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4. Prestress Losses: Types, Magnitudes, and Design Practice
Examples
Example 4.1 — Calculating total losses for a post-tensioned beam
Problem
A post-tensioned beam, 25 m long, has a parabolic tendon with sag 1.5 m, jacking stress f_pj = 1,400 MPa, A_p = 560 mm² (four 12.7 mm strands). Estimate total losses. Given: μ = 0.25, K = 0.0045 m⁻¹, f'_c = 35 MPa, E_p = 197 GPa, concrete A_c ≈ 350,000 mm², E_c = 33 GPa. Assume 6 mm anchorage seating at both ends (treat as one-side loss for simplicity).
Solution
**Immediate losses:** 1. Friction: θ = 8 × 1.5 / 25 = 0.48 rad. KL = 0.0045 × 25 = 0.1125 rad. ΔP_f / P ≈ 0.25 × (0.48 + 0.1125) = 0.153 = **15.3%**. 2. Anchorage seating: Δ L_seat = 6 mm. ΔP_as ≈ (6 × 197 × 560) / (25 × 10³) ≈ 26.5 kN. As % of jacking force P_i = 1,400 × 560 / 1000 = 784 kN: **26.5 / 784 ≈ 3.4%**. 3. Elastic shortening (post-tensioning, sequential): f_cir ≈ P_i / A_c = 784 / 350 ≈ 2.24 MPa. ΔP_es ≈ (560 / 350,000) × 197 × (2.24 / 33) × 1000 ≈ 2.4 kN ≈ **0.3%** (negligible). Immediate total: **15.3 + 3.4 + 0.3 ≈ 19%**. **Time-dependent losses (10+ year estimate):** 1. Creep: f_c (sustained) ≈ 0.6 × 2.24 ≈ 1.34 MPa (taking ~60% of initial as sustained stress). C_c ≈ 2.5 (tropical climate). ΔP_cr ≈ (560 / 1000) × 197 × 2.5 × (1.34 / 33) ≈ 5.6 kN ≈ **0.7%**. 2. Shrinkage: ε_sh ≈ 600 × 10⁻⁶ (tropical). ΔP_sh ≈ (560 / 1000) × 197 × 600 × 10⁻⁶ ≈ 66 kN ≈ **8.4%**. 3. Relaxation (low-relaxation): ~4% for sustained ~10 years. ΔP_rel ≈ **4%**. Time-dependent total: **0.7 + 8.4 + 4 ≈ 13%**. **Total loss: 19 + 13 = 32%**. (Note: losses are somewhat additive; a conservative estimate.) Effective: P_e ≈ (1 − 0.32) × P_i = 0.68 × 1,400 = 952 MPa. This high loss reflects the long span (friction), tropical climate (shrinkage), and sustained load (creep, relaxation). Design would use P_e for service-stage checks. **Key insight:** For long, heavily draped tendons in tropical climates, losses can exceed 30%. Early design estimates using R ≈ 0.75–0.80 are prudent.
Key Insight
Post-tensioned members in the Philippines experience significant losses due to friction (if draped) and tropical humidity/temperature (creep, shrinkage). Detailed loss calculations are recommended for critical structures.
Example 4.2 — Comparing pre- and post-tensioned losses
Problem
Two identical 20 m simple-span girders, one pre-tensioned, one post-tensioned (straight tendons, no draped). Both have P_i ≈ 1,000 kN. Estimate effective prestress for each. Assume f'_c = 35 MPa, E_p = 197 GPa, A_p = 500 mm², A_c = 300,000 mm², E_c = 33 GPa.
Solution
**Pre-tensioned:** 1. Elastic shortening (at release): f_cir ≈ 1,000 / 300 ≈ 3.33 MPa. ΔP_es / P ≈ (500 / 300,000) × (197 / 33) × (3.33 / 1) ≈ 0.010 = **1.0%** (occurs before release, so P after release ≈ 990 kN immediately). 2. Creep (10 years): ΔP_cr / P ≈ **5–7%**. 3. Shrinkage: ΔP_sh / P ≈ **2–3%**. 4. Relaxation: ≈ **3–4%**. Total: ~1 + 6 + 2.5 + 3.5 = **13% loss**. P_e ≈ 870 kN. R ≈ **0.87**. **Post-tensioned (straight, no friction):** 1. Friction (straight tendon): ~0% (K and θ ≈ 0). 2. Anchorage seating: ~2–3% (minor for straight). 3. Elastic shortening: ~0.5% (brief jacking). 4. Creep, shrinkage, relaxation: Same as pre-tensioned, ~12–13%. Total: ~2 + 0.5 + 13 = **15.5% loss**. P_e ≈ 845 kN. R ≈ **0.85**. **Comparison:** Pre-tensioned is slightly more effective (R ≈ 0.87 vs. 0.85) for straight members because it avoids anchorage seating and jacking transients. However, the difference is small. For draped post-tensioned (not shown), friction dominates, and losses can reach 25–30%. **Key insight:** For simple shapes, pre-tensioning is efficient. For complex geometries requiring draped tendons, post-tensioning is necessary despite slightly higher losses.
Key Insight
Always compare the loss mechanisms specific to each method. In exam problems, identify whether the member is pre- or post-tensioned first, then apply the appropriate loss categories.
Key Points
- Prestress losses reduce force from P_i (jacking) to P_e (effective). Typical total: 15–25% depending on method.
- Immediate losses: elastic shortening (pre-tensioning), friction (post-tensioning), anchorage seating (post-tensioning).
- Time-dependent losses: creep, shrinkage, relaxation—significant in tropical climates like the Philippines.
- NSCP 2015/ACI 318 provide calculation methods for each loss type; must account for local conditions (humidity, temperature).
- Effectiveness factor R = P_e / P_i ≈ 0.80–0.85; use this for quick estimates, detailed calculations for critical structures.
- Design must check **both** P_i (transfer) and P_e (service); never apply losses twice; carefully distinguish jacking vs. effective stress in problem statements.
The load-balancing method is an elegant and intuitive design approach for prestressed concrete, particularly for post-tensioned members with draped tendons. It shifts the design perspective from stresses to loads, offering insight into how a well-designed tendon profile can significantly reduce bending moments and deflections. ### 5.1 Conceptual Basis: Upward Distributed Force Consider a simply supported beam with a parabolic tendon that drapes (sags) from the ends toward midspan. As the tendon curves downward, the internal tension in the tendon creates a distributed upward force on the concrete (by Newton's third law—the tendon pulls the concrete down, so the concrete pulls the tendon up, and the tension transmits a distributed upward load to the concrete). For a parabolic tendon with constant tension P (ignoring friction and losses momentarily), the distributed upward load w_bal is: $$w_{\text{bal}} = \frac{8Pe}{L^2}$$ where: - P = tendon force (kN). - e = sag (maximum deflection of tendon below the chord connecting end points, in meters). - L = span (meters). - w_bal = uniform distributed upward load (kN/m), equivalent to the load "balanced" by the tendon. **Derivation (brief):** A parabolic tendon has curvature κ = 8e/L². At any point, the vertical component of tension creates an upward force; integrating over the span yields w = P × κ = P × 8e/L² = (8Pe)/L². ### 5.2 Practical Implications: Moment Reduction If the actual gravity load on the beam equals w_bal, the internal moment in the concrete is approximately zero (or only the axial precompression remains). If the actual load is less than w_bal, the beam has a net upward load and a negative (hogging) moment. If the actual load exceeds w_bal, there is a sagging moment as usual, but reduced. **Example:** A simply supported beam, span L = 12 m, carries uniform load w = 18 kN/m. Tendon with sag e = 0.75 m and force P = 450 kN gives: $$w_{\text{bal}} = \frac{8 \times 450 \times 0.75}{12^2} = \frac{2700}{144} = 18.75 \text{ kN/m}$$ Since w ≈ w_bal, the applied load is nearly balanced. The internal moment is nearly zero, so the beam experiences primarily **axial precompression** P/A and minimal bending stress. The deflection is tiny. This is why prestressed beams with well-designed tendon profiles can span 50+ m with depth-to-span ratios of 1:50 or better, whereas RC beams at the same span might need depth ratios closer to 1:25. ### 5.3 Load-Balancing Design Procedure A common design approach is: 1. **Choose target load to balance:** Typically, balance a fraction of the sustained load (e.g., 60–80% of dead load + sustained live load), leaving the remainder (and temporary loads) to be resisted by bending of the section. 2. **Select sag e:** Limited by the geometry of the structure (e.g., available headroom, architectural constraints). For bridges, e/L ≈ 1/20 to 1/50 is typical. 3. **Solve for required tendon force:** P = w_bal L² / (8e). 4. **Select strands/tendons:** Determine the number and size of tendons to provide the required force, given material properties and jacking percentages. 5. **Verify stresses:** Check that the section (with chosen P and eccentricity profile) satisfies stress limits at transfer and service, accounting for unbalanced loads and other load cases. The elegance of load balancing is that it **separates concerns**: the tendon provides a known upward load (geometric + force property), and the remaining (unbalanced) load is analyzed using ordinary bending theory on a precompressed section. ### 5.4 Limitations and Refinements **1. Non-uniform loading:** The formula w_bal = 8Pe/L² applies to **uniform load**. For concentrated loads or non-uniform distributions, the equivalent "balancing load" varies along the span. A tendon profile can be optimized to balance a non-uniform load by adjusting the curvature profile (e.g., flatter near the supports, more sag at midspan), but this requires more complex tendon routing. **2. Friction and eccentric anchorage:** In post-tensioning, friction loss and the distance from anchorage points affect the actual stress profile and, therefore, the effective w_bal. The formula above assumes constant tension along the tendon; in practice, tension varies. **3. Deflection:** Even with perfect load balancing (w = w_bal), the beam is not perfectly rigid. The axial precompression P/A prevents bending deflection, but axial elastic strain (P × L / (E_c × A)) remains. For long-span structures, this axial strain, though small, can be significant. **4. Multiple load cases:** A single tendon profile balances **one specific load**. In practice, the structure experiences variable loads (e.g., asymmetric live load, wind, earthquake). Designers often balance the **permanent load** (dead load + essential live load) and accept that other load cases will produce some bending stress. ### 5.5 Example: Load-Balancing Design **Given:** Simply supported beam, L = 20 m, carries uniform dead load w_d = 12 kN/m and uniform live load w_l = 8 kN/m. Total w = 20 kN/m. Design to balance 100% of dead load + 50% of live load = 12 + 4 = 16 kN/m. Available sag: e = 1.2 m (architectural limit). **Find:** Required prestress force P. **Solution:** $$w_{\text{bal}} = 16 \text{ kN/m} = \frac{8Pe}{L^2} = \frac{8P \times 1.2}{20^2}$$ $$16 = \frac{9.6P}{400}$$ $$P = \frac{16 \times 400}{9.6} = \frac{6400}{9.6} \approx 666.7 \text{ kN}$$ **Verification of load balancing:** $$w_{\text{bal}} = \frac{8 \times 666.7 \times 1.2}{400} = \frac{6,400}{400} = 16 \text{ kN/m}$$ ✓ **Unbalanced load:** w_unbal = 20 − 16 = 4 kN/m (the remaining live load). This 4 kN/m is analyzed as ordinary bending on a precompressed section. The moment due to 4 kN/m is: $$M_{\text{unbal}} = \frac{w_{\text{unbal}} L^2}{8} = \frac{4 \times 20^2}{8} = \frac{1600}{8} = 200 \text{ kN·m}$$ This is **much smaller** than the total moment if the entire 20 kN/m load were resisted by bending: M_total = (20 × 400) / 8 = 1,000 kN·m. The prestress has reduced the design moment by 80%. **Benefit:** A section optimized for M ≈ 200 kN·m plus axial P = 666.7 kN is much smaller and lighter than a section for M = 1,000 kN·m with minimal axial stress. This is why load balancing yields efficient designs. ### 5.6 Practical Tendon Profile: Parabolic vs. Polygonal **Parabolic profile:** Smooth curve, suited for simply supported spans. Provides uniform w_bal over the span. **Polygonal (two-point) profile:** Two straight segments meeting at a point (often at midspan or near support). Easier to construct (fewer anchorages) but produces concentrated shear at the inflection point. Common in older designs. **Stepped or multiple-segment profile:** Used for complex loading (e.g., cantilevers + spans). Tendon follows the moment envelope more closely. For **Philippine infrastructure**, parabolic profiles are standard in modern bridge design (per DPWH guidelines), while polygonal profiles are common in building slabs (simpler formwork and construction). ### 5.7 Interaction with Structural Actions Load balancing is most effective when the **dominant load** is gravity (dead load + service live load). For structures subject to significant **dynamic** or **lateral** loads (e.g., seismic, wind, vibration from traffic), the full structural analysis must account for all load cases. Prestress helps with gravity-induced cracking but does not directly resist lateral load; lateral resistance requires adequate concrete strength, reinforcement, and section properties. In the Philippines, seismic design is mandatory (per NSCP 2015, which adopts IBC provisions). A structure must be designed for both gravity loads (with load balancing benefits for prestressed members) and seismic actions. The two must be checked separately (envelope approach).
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5. Load Balancing: Concept, Analysis, and Design Application
Examples
Example 5.1 — Moment reduction via load balancing
Problem
A simply supported footbridge, L = 16 m, experiences permanent load w_p = 6 kN/m and temporary (pedestrian) load w_temp = 4 kN/m. Total w_total = 10 kN/m. (a) If designed as ordinary RC (no prestress), the mid-span moment is M_RC = w_total × L² / 8 = 10 × 16² / 8 = 320 kN·m. (b) If prestressed with sag e = 0.8 m (sufficient for pedestrian clearance), and designed to balance all permanent load (6 kN/m), find the required P and the unbalanced moment. (c) Compare sections and estimate material savings.
Solution
(a) **RC design:** M_RC = 320 kN·m (as stated). (b) **Prestressed with load balancing:** $$w_{\text{bal}} = 6 \text{ kN/m} = \frac{8Pe}{L^2} = \frac{8P \times 0.8}{16^2} = \frac{6.4P}{256}$$ $$P = \frac{6 \times 256}{6.4} = 240 \text{ kN}$$ **Unbalanced load:** w_unbal = 10 − 6 = 4 kN/m (temporary load). **Moment due to unbalanced load:** $$M_{\text{unbal}} = \frac{4 \times 16^2}{8} = 128 \text{ kN·m}$$ **Reduction:** (320 − 128) / 320 = 60% moment reduction. (c) **Section comparison:** - **RC section (M = 320 kN·m):** Require moment of inertia ~I = M / (allowable stress) ≈ 320 × 10⁶ / 12 (assuming 12 MPa allowable flexural stress) ≈ 26.7 × 10⁶ mm⁴. A rectangular section 600 mm wide × 900 mm deep has I ≈ 40.5 × 10⁶ mm⁴ (slightly over-sized). Approximate volume per meter: 0.6 × 0.9 = 0.54 m³. For 16 m: ~8.6 m³ concrete. - **Prestressed section (M_unbal = 128 kN·m, P = 240 kN):** Moment requirement reduced by 60%; required I ≈ 10.7 × 10⁶ mm⁴. A section 500 mm × 600 mm has I ≈ 9 × 10⁶ mm⁴ (close fit). Volume per meter: 0.5 × 0.6 = 0.3 m³. For 16 m: ~4.8 m³ concrete. - **Savings:** 8.6 − 4.8 ≈ 3.8 m³ (44% reduction in concrete volume). For a structure with, say, four identical footbridges (total 12.8 m³ saved), this is significant in terms of cost, carbon footprint, and construction time. Additionally, the prestressed beam experiences minimal deflection (axial elasticity only) and no cracking—superior durability and serviceability. **Key insight:** Load balancing is a powerful design tool for gravity-dominated structures. The moment reduction directly translates to material savings and improved performance.
Key Insight
Moment reduction of 50–70% is typical when balancing permanent load; design becomes economical and durable.
Example 5.2 — Unbalanced load and shear force
Problem
A 10 m simply supported beam carries 8 kN/m uniform load. A parabolic tendon with P = 200 kN and e = 0.5 m balances the load. (a) Calculate w_bal and the unbalanced load. (b) Sketch the bending-moment diagram for the unbalanced load and find the max moment. (c) Sketch the internal shear force diagram (from unbalanced load only) and the external vertical shear produced by the tendon.
Solution
(a) **Load balancing:** $$w_{\text{bal}} = \frac{8 \times 200 \times 0.5}{10^2} = \frac{800}{100} = 8 \text{ kN/m}$$ The applied load w = 8 kN/m exactly matches w_bal. **Unbalanced load = 0 kN/m.** (b) **Bending moment:** Since unbalanced load = 0, the internal moment due to external loading = 0. (In practice, the tendon does not produce exactly zero internal moment everywhere due to friction variation and other real-world effects, but the idealized load-balance condition gives zero.) (c) **Shear force:** From unbalanced load = 0, no shear from bending. However, the tendon curvature produces an internal shear force. At any point in the span, the change in vertical component of tendon tension = shear force. For a parabolic tendon with sag e and span L, the vertical component varies linearly from +4Pe/L at mid-span support (upward) to −4Pe/L at the other support. Actually, for a simply supported beam with a parabolic tendon, the tendon tension is constant (P), but its direction changes. At distance x from the left support, the vertical component of tension is: $$V_{\text{tendon}}(x) = P \times \sin(\theta(x)) \approx P \times \frac{dy}{dx} = P \times \frac{8e(L - 2x)}{L^2}$$ At x = 0 (left support): V_tendon = 8 × 200 × 0.5 / 100 = 8 kN (upward, balancing reaction from 8 kN/m load). At x = 5 m (mid-span): V_tendon = 0 (tendon is horizontal at the lowest point). At x = 10 m (right support): V_tendon = −8 kN (downward, balancing the reaction). This shear force is **internal** to the prestressed member and is resisted by the prestress mechanism (axial tension in the tendon, compression in the concrete fiber). External shear reinforcement (stirrups) is minimal because the external shear = 0 (unbalanced load = 0). This is another benefit of load balancing: reduced shear reinforcement. **Key insight:** Perfect load balancing leads to zero external bending moment and shear, reducing the need for reinforcement and simplifying design. In practice, slight over- or under-balancing is typical to account for uncertainties.
Key Insight
Load balancing elegantly decouples the prestress mechanism (providing upward load) from the structural resistance (bending, shear). Design becomes cleaner and often more economical.
Key Points
- Load-balancing method: parabolic tendon with force P and sag e creates upward distributed load w_bal = 8Pe/L².
- If applied load ≥ w_bal, the member is primarily precompressed (minimal bending moment); if load > w_bal, unbalanced load produces bending (reduced from non-prestressed case).
- Load balancing is most effective for **uniform, gravity-dominated loads**; not effective for concentrated loads or lateral/dynamic loads without careful profile design.
- Typical design: balance 60–100% of permanent load, accept that remaining and temporary loads produce some bending on a strong, precompressed section.
- Benefit: large reduction in internal moments and deflections, allowing longer spans and shallower sections. Design efficiency gain is substantial (~50% moment reduction typical).
- Limitations: finite tendon force, friction losses, architectural constraints on sag, and multi-load-case verification still required.
Many prestressed structures in practice use **composite sections**—two-part members with different materials, properties, or casting times—to optimize cost, construction, and performance. ### 6.1 Composite Beam: Precast Beam + Cast-in-place Slab A common Philippines application (especially in DPWH bridge standards and building slabs) is a **precast prestressed beam supporting a cast-in-place (CIP) concrete slab**. The beam is pre-tensioned at a plant, transported to site, and erected. Then, forms are placed above the beam, reinforcement is tied, and concrete is cast to form the slab. After the slab cures, the composite section acts together. **Stress analysis changes:** 1. **Transfer stage (at plant, just after releasing strands):** Only the precast beam section resists moment. Stress = P_i / A_beam ± P_i e c / I_beam ± M_sw,beam c / I_beam, where M_sw,beam is the self-weight moment of the beam alone. 2. **Composite stage (after slab cures and bonds to the beam):** The moment due to slab self-weight and superimposed load is resisted by the **composite section** (beam + slab acting together). This is the long-term, in-service condition. - The neutral axis shifts (typically toward the slab due to its large area). - The moment of inertia increases significantly (composite I >> beam I). - Stresses in the beam at a given fiber reduce because M/I decreases (larger I). - Stress in the slab (newly formed from the composite action) is different from the beam. **Design procedure:** 1. Check beam stresses at transfer (using beam properties only) for the beam's self-weight moment. 2. Check composite-section stresses in service (using composite I and P_e) for the full applied moment (slab + superimposed load). 3. Ensure the interface between beam and slab is adequate (reinforcement, friction) to transfer shear and maintain composite action. **Practical detail:** In the Philippines, DPWH bridge designs often specify `600 mm` precast I-beams with a `200 mm` cast-in-place deck slab, creating a composite T-beam or box-beam. The precast beam carries its self-weight; the slab moment is shared by the composite section. ### 6.2 Hybrid Sections: Combining Prestressed and Reinforced Concrete Some members use both prestressing and conventional reinforcement (bonded longitudinal bars). This can be optimal when: - Prestress handles sustained loads (gravity, creep, shrinkage). - Reinforcement handles temporary or accidental loads (earthquake, impact, fatigue). - Cost is minimized by using less prestress and more conventional steel. Example: A building column subjected to both sustained axial load and occasional seismic moment. Prestressing reduces the sustained stress; reinforcement handles the bending. Stress analysis is similar (superposition), but the reinforcement yield and strain-hardening behavior must be verified (typically via section capacity analysis under combined action). ### 6.3 Grouted vs. Ungrouted Tendons in Post-tensioning **Grouted post-tensioned members** (ducts filled with cement grout after stressing): - Tendons are protected from corrosion (critical in the Philippine coastal environment and tropical humidity). - Concrete and steel are bonded along the tendon—more monolithic behavior, similar to pre-tensioned members. - Duct grouting ensures continuity; voids or incomplete grouting can fail catastrophically (water reaches tendon). **Ungrouted (unbonded) tendons:** - Tendons are protected by plastic sheathing or a thin grease coating (less effective, especially in saltwater). - Tendon is not bonded to concrete—stress redistribution after cracking is limited. - Used mainly in temporary structures or where grouting is impractical. - **Not recommended** for critical or long-lived structures in the Philippines due to corrosion risk. NSCP 2015 and ACI 318 emphasize grouting for all post-tensioned structures. Non-grouted members have seen failures in tropical climates (corrosion of strands leading to sudden loss of prestress). ### 6.4 Durability and Maintenance **Crack control via prestressing:** - Prestressed members inherently resist cracking (precompression) if designed correctly. - Even if fine hairline cracks form under overload, they close when load is removed (unlike RC, where cracks remain). - This greatly improves durability in harsh environments (salt, acid, freeze-thaw—though freeze-thaw is uncommon in the Philippines). **Corrosion protection:** - Pre-tensioned members: strands are bonded and surrounded by concrete. If the concrete cover is adequate, corrosion is unlikely over the design life (50–100 years). - Post-tensioned members: **grouting is essential**. Regular inspection of grout quality (via test cores or acoustic scanning) is recommended for critical structures. - In the Philippines, especially in coastal zones (e.g., Manila's waterfront infrastructure, port structures), pre-tensioned members (no grout interface) are often preferred for simplicity and durability. **Monitoring and maintenance:** - Prestressed structures require less maintenance than RC if designed and built correctly. - Periodic visual inspection (cracks, spalling, water stains) is recommended. - For post-tensioned structures, re-stressing or partial stressing (if prestress is found to be inadequate due to unexpected losses) is possible but expensive and should be avoided by good design. ### 6.5 Special Cases: Cantilevers, Continuous Spans, and Indeterminate Structures **Cantilever prestressed members:** - Hogging (negative) moment is the concern. Tendon should be placed **near the top** (above the centroid) to provide compression there. - Load balancing requires the tendon to curve **upward** (increasing curvature from support to free end), opposite to a simply supported span. This is less efficient geometrically but feasible. **Continuous prestressed beams:** - Internal supports create hogging moments at those supports and sagging moments in the spans. Tendon profile must be optimized to balance the moment envelope. - A typical profile (e.g., low at mid-spans, high at internal supports) requires more complex routing and is more difficult to construct than a simple parabolic profile. - Some designs use **selective stressing** (different tendon forces in different spans) to optimize each region. **Indeterminate structures:** - Prestress introduces internal forces (hyperstaticity) that can be difficult to analyze (especially distribution among redundant members). - Linear analysis (superposition) is valid if concrete remains elastic; for large prestress or overload, nonlinear analysis may be required. For PRC exam purposes, focus on **simply supported members** and **basic composite sections**. Complex statically indeterminate structures are less commonly examined at the PE level but may appear in advanced specialist exams. ### 6.6 Construction Sequence and Staged Loading Real-world construction introduces temporary conditions that differ from final design: 1. **Precast beam erected, before slab cast:** Beam carries only its own weight. Must not crack or deflect excessively during handling and erection (temporary support conditions may be needed). 2. **Slab cast, formwork propping:** Beam + formwork/props carry slab weight. Beam experiences temporary higher moment (props reduce but don't eliminate this). 3. **Slab cures, props removed:** Composite section comes into play. Full moment now shared. 4. **Superimposed load (finished flooring, live load):** Final service state. Stress checks at each stage are required (per NSCP 2015 / ACI 318 Section 24.2.2). Missing checks at intermediate stages is a common design error. **Example:** A precast beam, if over-stressed during the slab-casting stage (temporary), might develop cracks that persist and reduce long-term durability, even if final stresses are acceptable. ### 6.7 Connection Details: Bearing Pads, Supports, and Anchorages Prestressed members must be connected carefully to the supporting structure (columns, walls, abutments). Key considerations: 1. **Bearing pads:** Elastomeric or neoprene pads distribute the reaction and allow rotation. Size and material are critical to prevent local crushing of the beam end. 2. **Anchorages for post-tensioned members:** Wedge-cone anchors, barrel-and-wedge, or other mechanical devices must reliably transfer very high tension (often 500+ kN per tendon). Improper anchorage has caused catastrophic failures. 3. **Shear keys and friction considerations:** Horizontal shear (from temperature expansion, earthquake) must be resisted by friction or shear keys. Prestress contributes to friction (normal force), but explicit shear keys or reinforcement may be needed. 4. **Concrete bearing strength:** Local bearing stress at the support must not exceed allowable values (per ACI 318 Section 22.8: bearing stress ≤ 0.85 f'_c or more, depending on bearing area). In the Philippines, DPWH standards and PCA (Portland Cement Association) design guides specify these details; engineers must follow them rigorously.
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6. Composite Prestressed Sections: Practical Considerations
Examples
Example 6.1 — Composite beam stress check
Problem
A precast I-beam (A = 180,000 mm², I_beam = 5 × 10⁹ mm⁴, c_beam = 300 mm top and bottom) is pre-tensioned with P_i = 900 kN at e = 150 mm below centroid. After erection on supports, a CIP slab (200 mm thick, width 3000 mm) is cast on top of the beam. After curing, the composite section has I_comp ≈ 12 × 10⁹ mm⁴ (approximately, including slab contribution), and the centroid shifts upward by ~80 mm. (a) Check top-fiber stress in the beam at transfer (self-weight M_sw = 60 kN·m for beam alone). (b) Check top and bottom fiber stresses in service (effective prestress P_e = 750 kN, applied moment from slab + superimposed load M_total = 180 kN·m, analyzed using composite section). Assume f'_ci = 26 MPa, f'_c = 35 MPa.
Solution
**(a) Transfer (beam stage):** Axial: P_i / A = 900,000 / 180,000 = 5.0 MPa. Eccentricity moment (top): − P_i e c / I = − (900,000 × 150 × 300) / (5 × 10⁹) = −8.1 MPa. Beam self-weight moment (top): M c / I = (60 × 10⁶ × 300) / (5 × 10⁹) = 3.6 MPa. Top fiber: f_top = 5.0 − 8.1 + 3.6 = 0.5 MPa **compression**. Allowable at transfer: ~0.5 √(26) ≈ 2.55 MPa tension (or 0.6 × 26 = 15.6 MPa compression). **Safe** (no tension, barely any compression). **(b) Service (composite stage):** Need to recalculate section properties and centroid shift. Assume composite centroid is ~80 mm higher than beam centroid. Then: - Distance from new centroid to top of beam: c_top,new ≈ 300 + 80 = 380 mm. - Distance from new centroid to bottom of slab: c_bot,new ≈ (200 − 80) = 120 mm. Axial: P_e / A_total = 750 / (180,000 + slab area). Slab area ≈ 3,000 × 200 = 600,000 mm². Total A ≈ 780,000 mm². P_e / A ≈ 750,000 / 780,000 ≈ 0.96 MPa. Eccentricity moment at new centroid: The tendon is 150 mm below the **original** beam centroid (unchanged by slab casting). Its distance from the **new** composite centroid is (150 − 80) = 70 mm **below** the new centroid. Pe × c / I_comp: - Top of beam: (750,000 × 70 × 380) / (12 × 10⁹) = 1.79 MPa (compression, since tendon pulls top down indirectly). - Bottom of slab: (750,000 × 70 × 120) / (12 × 10⁹) = 0.53 MPa (tension, opposing bottom compression from precompression). Applied moment (M = 180 kN·m): - Top: (180 × 10⁶ × 380) / (12 × 10⁹) = 5.7 MPa (compression). - Bottom: (180 × 10⁶ × 120) / (12 × 10⁹) = 1.8 MPa (tension). Final stresses: - **Top of beam:** 0.96 + 1.79 + 5.7 = **8.45 MPa (compression)**. Allowable: 0.45 × 35 = 15.75 MPa. **Safe**. - **Bottom of slab:** 0.96 − 0.53 − 1.8 = **−1.37 MPa (tension)**. Allowable for service: 0 (strict) or ~0.5 √(35) ≈ 2.96 MPa (if bonded reinforcement present). **Marginal; likely acceptable if proper rebar is provided in slab**. **Note:** The analysis above is simplified (composite centroid is approximate). A rigorous calculation would use exact composite properties. The key point: stage 2 uses composite section properties, not beam-alone properties. **Key insight:** Composite sections require careful two-stage analysis. Intermediate stages (slab casting, while props are in place) also need checking to ensure the temporary condition doesn't over-stress the beam.
Key Insight
Always identify the critical stages: transfer (beam alone), intermediate (beam + formwork + slab weight), and final (composite section + full load). Design must satisfy all stages.
Key Points
- Composite sections (precast + cast-in-place slab) require **two-stage stress analysis**: beam alone at transfer, composite section at service.
- Effective section properties (I, c) change dramatically from stage 1 to stage 2; stresses must be re-evaluated.
- Post-tensioned members **must be grouted** to ensure long-term durability and protect tendons from corrosion (especially critical in the Philippines' tropical/coastal environment).
- Prestressing provides inherent crack control and better durability than RC in harsh environments.
- Construction sequence (temporary loading stages) must be checked; missing intermediate-stage checks is a common design error.
- Connection details (bearing pads, anchorages, shear keys) are critical and must follow code requirements (NSCP 2015, DPWH standards).
To consolidate the concepts, here is a comprehensive design example, following typical NSCP 2015 / ACI 318 procedures. ### Example: Design of a Simply Supported Prestressed Bridge Girder **Given:** - **Span:** L = 25 m (simply supported). - **Superimposed load:** Uniform dead load (besides self-weight) w_d = 12 kN/m. Live load w_l = 8 kN/m (design per DPWH/AASHTO standards). - **Concrete:** f'_c = 40 MPa (28-day), f'_ci = 32 MPa (at transfer). γ_c = 24 kN/m³. - **Prestressing:** Use low-relaxation 7-wire strands, 12.7 mm (1/2 in), f_pu = 1,860 MPa. Jacking stress f_pj = 0.75 × 1,860 = 1,395 MPa. Effective losses: R = 0.85, so P_e = 0.85 P_i. - **Design constraints:** - At transfer: top fiber stress ≤ 0.5√(f'_ci) = 0.5√32 ≈ 2.83 MPa tension (or just in compression if favorable). - In service: no tension allowed (strict), compression ≤ 0.45 f'_c = 18 MPa. - Deflection: not to exceed span/240 in service. **Design steps:** #### Step 1: Estimate section depth and cross-sectional area For long-span prestressed girders, typical depth-to-span ratio is 1:30 to 1:40. For 25 m, estimate h ≈ 25,000 / 35 ≈ 714 mm. Use **h = 750 mm** (round number, conducive to formwork). Assume a **T-section** (typical for bridge girders): flange width b_f = 3,000 mm (to accommodate a two-lane deck + cantilevers), flange thickness t_f = 250 mm. Web width b_w = 400 mm, web depth = 750 − 250 = 500 mm. (A precast hollow-core or box section might be optimized further, but a solid T is assumed here for simplicity.) Area calculation: - Flange: 3,000 × 250 = 750,000 mm². - Web: 400 × 500 = 200,000 mm². - Total: **A = 950,000 mm²** ≈ 0.95 m². Centroid: Located approximately 320 mm from the top (accounting for the large flange). c_top = 320 mm, c_bot = 750 − 320 = 430 mm. Moment of inertia (approximate, using parallel-axis theorem for component parts): - Flange: I_f = (3,000 × 250³) / 12 + 750,000 × (320 − 125)² ≈ 3.9 × 10⁹ + 22.8 × 10⁹ = 26.7 × 10⁹ mm⁴. - Web: I_w = (400 × 500³) / 12 ≈ 4.17 × 10⁹ mm⁴. - Total: **I ≈ 31 × 10⁹ mm⁴**. (More precise calculation requires detailed geometry; the above is an estimate.) #### Step 2: Calculate moments and loads **Self-weight of girder:** w_sw = γ_c × A = 24 × 0.95 = 22.8 kN/m. **Total loads in service:** w = w_sw + w_d + w_l = 22.8 + 12 + 8 = 42.8 kN/m. **Moments:** - M_sw = (22.8 × 25²) / 8 = 1,781 kN·m. - M_d = (12 × 25²) / 8 = 938 kN·m. - M_l = (8 × 25²) / 8 = 625 kN·m. - M_total = 1,781 + 938 + 625 = 3,344 kN·m. #### Step 3: Choose eccentricity and estimate prestress force To balance the permanent load (w_sw + w_d = 22.8 + 12 = 34.8 kN/m), choose sag e such that: $$w_{\text{bal}} = 34.8 = \frac{8 P e}{L^2}$$ Assume e = 250 mm (available space in a deep girder; not to interfere with ducts or reinforcement): $$P = \frac{34.8 \times 25^2}{8 \times 0.25} = \frac{21,750}{2} = 10,875 \text{ kN}$$ This seems very high (unrealistic for a single girder). Re-examine: perhaps e = 350 mm is more typical: $$P = \frac{34.8 \times 625}{8 \times 0.35} = \frac{21,750}{2.8} ≈ 7,768 \text{ kN}$$ Still quite high. In practice, for a 25 m span, a typical bridge girder might have 30–60 strands, which, with f_pj = 1,395 MPa and area ~140 mm² per strand, gives: $$P_i ≈ 40 \text{ strands} \times 140 \text{ mm}^2 \times 1,395 \text{ MPa} / 1000 ≈ 7,812 \text{ kN}$$ So 40 strands (or 50 for a larger girder) is reasonable. Let's **design for P_i ≈ 7,850 kN** (approximately 56 strands of 12.7 mm each). **Effective prestress:** P_e = 0.85 × 7,850 = 6,672 kN. #### Step 4: Check stresses at transfer **At transfer:** P_i = 7,850 kN, M = M_sw = 1,781 kN·m, e = 350 mm (below centroid). Axial compression: P_i / A = 7,850,000 / 950,000 = 8.26 MPa. Eccentricity moment (M_e = P_i × e = 7,850 × 0.35 = 2,747.5 kN·m): - At top: − (M_e × c_top) / I = − (2,747.5 × 10⁶ × 320) / (31 × 10⁹) = −28.4 MPa (relief/tension). - At bottom: + (M_e × c_bot) / I = + (2,747.5 × 10⁶ × 430) / (31 × 10⁹) = +38.1 MPa (compression). Applied moment (self-weight): - At top: + (M_sw × c_top) / I = + (1,781 × 10⁶ × 320) / (31 × 10⁹) = +18.4 MPa (compression). - At bottom: − (M_sw × c_bot) / I = − (1,781 × 10⁶ × 430) / (31 × 10⁹) = −24.7 MPa (tension). **Top fiber at transfer:** f_top = 8.26 − 28.4 + 18.4 = **−1.74 MPa (tension).** Allowable: 0.5√(32) ≈ 2.83 MPa tension. **1.74 < 2.83, so it passes,** but barely. If the allowable were stricter (e.g., zero tension), we'd need to reduce P_i or increase e, or increase f'_ci (faster curing). **Bottom fiber at transfer:** f_bot = 8.26 + 38.1 − 24.7 = **21.66 MPa (compression).** Allowable: 0.6 f'_ci = 0.6 × 32 = 19.2 MPa. **21.66 > 19.2, so it FAILS.** **Remedial action:** Increase e (place tendons lower, if geometry allows) or reduce P_i (increase the number of strands to a lower jacking stress, or use a different section). Let's reduce P_i to 7,000 kN and increase e slightly to 380 mm. (Iterative process; for brevity, assume this resolves the transfer check.) #### Step 5: Check stresses in service **In service:** P_e = 6,000 kN (after 15% losses), M_total = 3,344 kN·m, e = 380 mm. Eccentricity moment (M_e = 6,000 × 0.38 = 2,280 kN·m): - At top: − (2,280 × 10⁶ × 320) / (31 × 10⁹) = −23.5 MPa. - At bottom: + (2,280 × 10⁶ × 430) / (31 × 10⁹) = +31.6 MPa. Applied moment: - At top: + (3,344 × 10⁶ × 320) / (31 × 10⁹) = +34.5 MPa. - At bottom: − (3,344 × 10⁶ × 430) / (31 × 10⁹) = −46.4 MPa. **Top fiber in service:** f_top = 6.32 − 23.5 + 34.5 = **17.3 MPa (compression).** Allowable: 0.45 f'_c = 18 MPa. **17.3 < 18, passes.** ✓ **Bottom fiber in service:** f_bot = 6.32 + 31.6 − 46.4 = **−8.48 MPa (tension).** Allowable: 0 (strict) or up to ~0.5√(40) ≈ 3.16 MPa if bonded reinforcement is present. **−8.48 < 0, so it FAILS.** Again, design iteration is needed. Perhaps increase P_e or e further, or accept that the bottom fiber will have some non-prestressed (ordinary) reinforcement to carry the tension. In practical design, a few strands of bonded reinforcement in the bottom are often provided as a "safety net." For the purpose of this example, assume a revised design with P_e = 6,500 kN passes all checks (detailed calculations omitted for brevity). #### Step 6: Deflection check The effective prestress provides an "upward" distributed load w_bal = 8 × P_e × e / L² = 8 × 6,500 × 0.38 / 625 ≈ 31.5 kN/m. This is close to the permanent load (22.8 + 12 = 34.8 kN/m), so the beam is nearly load-balanced. Unbalanced load = 34.8 − 31.5 = 3.3 kN/m (plus live load 8 kN/m total unbalanced ≈ 11.3 kN/m). Defection due to unbalanced load (assuming moment of inertia I_eff ≈ 31 × 10⁹ mm⁴): $$\delta = \frac{5 w L^4}{384 E_c I}$$ With w = 11.3 kN/m, L = 25 m, E_c = 33 GPa: $$\delta = \frac{5 \times 11.3 \times 10^3 \times 25^4}{384 \times 33 \times 10^3 \times 31 \times 10^9} ≈ \frac{443 \times 10^9}{4 \times 10^{12}} ≈ 0.11 \text{ m} = 110 \text{ mm}$$ (Simplified; actual deflection is slightly less due to prestress contribution.) Allowable: L / 240 = 25,000 / 240 ≈ 104 mm. **Deflection 110 mm slightly exceeds limit; may need slightly larger I or more prestress.** Iterate. #### Step 7: Reinforcement details Provide: - **Longitudinal reinforcement (non-prestressed):** At least a few bars in the bottom layer to resist the service tension and control any cracking. Use #16 rebars, typically 4–6 bars. - **Transverse reinforcement (stirrups):** Design for shear per NSCP 2015 Section 22.4. At supports, higher shear; stirrup spacing reduces from ~150 mm near support to ~300 mm at mid-span. - **Confinement reinforcement:** At the ends (transfer zone), place helical or spiral reinforcement to prevent splitting of the concrete due to prestress transfer. ### Summary of Design Outcome After iteration (details omitted for brevity), the final design might be: - **Section:** T-beam, 3 m wide flange, 750 mm deep, web 400 mm wide. - **Prestress:** 50 strands, 12.7 mm, initial force P_i ≈ 7,850 kN, effective P_e ≈ 6,700 kN, eccentricity e ≈ 380 mm. - **Reinforcement:** 4 × #16 bars in bottom (non-prestressed), stirrups #10 @ 150 mm near support tapering to #10 @ 300 mm mid-span. - **Performance:** - Stresses at transfer and service: within limits. - Deflection: ~100 mm (at limit). - Crack control: excellent (prestress prevents cracking under service load). - Durability: high (proper cover, pre-tensioned construction, low water/chloride ingress risk). This girder would be manufactured in a precast facility, transported to the bridge site, and erected on bearing pads (elastomeric neoprene pads, ~50 mm thick). A cast-in-place deck slab would then be formed and cast on top, creating a composite section for the final stage. ### Key Lessons from This Example 1. **Iteration is essential:** Initial estimates are refined through multiple checks (transfer, service, deflection, reinforcement). 2. **Multiple limits:** Must satisfy stress limits at **both** transfer and service, **both** top and bottom fibers. Usually, one limit is tight and drives the design. 3. **Load balancing:** Choosing e and P to balance a significant fraction of the permanent load dramatically reduces the unbalanced moment and deflection—a major advantage of prestressing. 4. **Practical reinforcement:** Non-prestressed reinforcement is often added to ensure ductility and to carry any unexpected overload or impact loads. 5. **Composite action:** The design is staged—transfer stage uses beam properties, final stage uses composite properties (if a slab is cast on top). 6. **Code compliance:** NSCP 2015 / ACI 318 govern every step. Always reference the code sections (e.g., ACI 318 Section 24 for prestressed flexural members).
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7. Design Worked Example: Complete Prestressed Beam Design
Examples
Key Points
- Complete design requires iterative checks: estimate section, compute moments, choose prestress/eccentricity, verify stresses (both stages), check deflection and reinforcement.
- Critical limits typically include: (1) transfer top-fiber tension, (2) transfer bottom-fiber compression, (3) service bottom-fiber tension, (4) deflection.
- Load balancing by choosing appropriate P and e is the main design lever; reducing unbalanced moment directly reduces section size and deflection.
- Non-prestressed reinforcement is standard practice for safety, ductility, and durability (handles overload, construction shocks, long-term creep).
- Composite sections require two-stage analysis; final deflection and stress checks use the composite properties.
- Always follow NSCP 2015 and local code provisions (e.g., DPWH bridge standards in the Philippines).
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