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CELE Hydraulics & Fluid Mechanics — Properties of FluidsMemory Anchors

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Memory anchors for Properties of Fluids reviewers. When plain memorisation is not enough, these mnemonic devices help you lock in the key concepts for the CELE 2026. Tested against the kinds of questions Professional Regulation Commission (PRC) — Board of Civil Engineering actually uses in CELE Hydraulics & Fluid Mechanics.

Exam context

For the Civil Engineer Licensure Examination, Professional Regulation Commission (PRC) — Board of Civil Engineering tests Hydraulics & Fluid Mechanics under a "Core" label, with Properties of Fluids in the 1st slot across 10 chapters. CELE candidates must clear the 70% weighted average, no sub-test below 50% cut on the 2026 paper, which draws about a meaningful share of Hydraulics & Fluid Mechanics questions. Date to watch: May and November 2026.

Properties of Fluids - Memory Anchors

Memory techniques can increase recall by up to 400% compared to passive re-reading. Your brain is wired to remember stories, vivid images, and emotional connections — NOT abstract formulas. These anchors convert dry engineering equations into unforgettable mental movies. For the PRC CE board exam, you need instant recall under pressure. Each anchor here plants a concept so deeply that seeing the first word of a problem immediately triggers the correct formula, unit, or approach. Use the recall triggers like mental hotkeys — one word unlocks a whole concept. Combine these with the Mermaid diagrams to build a complete visual map of fluid properties in your memory palace.

Anchors

Topic

Density and Specific Weight

Concept

Density (ρ) — mass per unit volume; water = 1000 kg/m³

Anchor Id

Difficulty

easy

Memory Aid

Think of ρ (rho) as 'RHO = Really Heavy Object per volume.' Water at 1000 kg/m³ is your BASELINE — imagine exactly 1 cubic meter of water (a big cube) weighing exactly 1000 kg, the mass of a small car. Everything else is compared to this car-sized cube of water.

Anchor Type

mnemonic

Why It Works

Anchoring the abstract value 1000 to a tangible object (a small car) gives the number a physical size and weight your brain can feel.

Example Usage

Problem asks for density of an oil with s=0.85. Trigger: 'RHO of water = 1000, multiply by s.' ρ_oil = 0.85 × 1000 = 850 kg/m³.

Recall Trigger

ρ symbol → 'Really Heavy Object' → 1000 kg/m³ for water

Topic

Density and Specific Weight

Concept

Specific weight (γ) — weight per unit volume; γ = ρg; water = 9.81 kN/m³

Anchor Id

Difficulty

easy

Memory Aid

γ (gamma) is density's HEAVIER BROTHER — it includes gravity. Think: 'Density goes to the gym (multiplies by g = 9.81) and becomes Specific Weight.' Density carries mass; Specific Weight carries weight (force). Water's specific weight: 9.81 kN/m³ — almost exactly 10 kN per cubic meter. Imagine 10 barangay councilors each weighing 100 kg standing on 1 m³ of water.

Anchor Type

analogy

Why It Works

The gym analogy creates a clear cause-effect relationship: applying g transforms mass to force. The Filipino barangay image is culturally vivid.

Example Usage

Given ρ = 850 kg/m³, find γ: 'density goes to the gym' → γ = 850 × 9.81 = 8338.5 N/m³ = 8.34 kN/m³.

Recall Trigger

γ → 'Density goes to the gym' → × 9.81 → kN/m³

Topic

Specific Gravity

Concept

Specific gravity (s) — dimensionless ratio to water; s = ρ/ρ_water = γ/γ_water

Anchor Id

Difficulty

easy

Memory Aid

Imagine a fluid standing before a judge (water) in a courtroom. The judge says: 'I am the standard. How do you compare to ME?' The fluid answers with a single number — its specific gravity. If s < 1, the fluid is lighter than water (it would float). If s > 1, it sinks. Mercury's answer: s = 13.6 — 'I am 13.6 times heavier than you, your honor.' The judge (water) always scores exactly 1.0.

Anchor Type

micro_story

Why It Works

The courtroom drama creates an emotional scene. The 'judge = water' anchor makes it clear why water always = 1.0 (it IS the reference).

Example Usage

s = 0.88 oil: 'lighter than water, will float.' ρ = 0.88 × 1000 = 880 kg/m³, γ = 0.88 × 9810 = 8632.8 N/m³.

Recall Trigger

Specific gravity → courtroom → fluid vs. water judge → ratio → dimensionless

Topic

Viscosity

Concept

Newton's Law of Viscosity: τ = μ(dv/dy)

Anchor Id

Difficulty

medium

Memory Aid

Picture spreading peanut butter (palaman) on pandesal. The thicker (more viscous) the peanut butter, the more force (τ) you need to spread it. The faster you spread (dv) over a thin layer (dy), the more resistance. μ is the 'thickness factor' of the peanut butter. Thin honey at room temperature = high μ. Water = very low μ. The formula τ = μ(dv/dy) says: 'Shear stress = viscosity × how fast you're shearing per unit thickness.'

Anchor Type

analogy

Why It Works

Every Filipino knows the difficulty of spreading thick palaman. This tactile analogy makes the abstract shear-velocity gradient relationship physically intuitive.

Example Usage

Oil film 1 mm thick, plate moves at 2 m/s, μ = 0.0015 Pa·s: τ = 0.0015 × (2/0.001) = 3.0 Pa.

Recall Trigger

Shear stress → peanut butter on pandesal → τ = μ(dv/dy)

Topic

Viscosity

Concept

Dynamic viscosity (μ) vs. kinematic viscosity (ν = μ/ρ)

Anchor Id

Difficulty

medium

Memory Aid

DYNAMIC μ is the MUSCLE — it measures actual resistance force (Pa·s). KINEMATIC ν is the NERD — it accounts for the fluid's own weight (density), giving m²/s. Remember the division: ν = μ/ρ as 'Nerds Divide Muscles by mass (density).' Units check: (Pa·s)/(kg/m³) = (N/m²·s)/(kg/m³) = m²/s. The Greek letters help: μ (mu) = Muscle, ν (nu) = Nerd.

Anchor Type

mnemonic

Why It Works

The Muscle vs. Nerd contrast creates two distinct character types that map perfectly onto the two different physical meanings. The division relationship becomes a personality conflict resolved by the formula.

Example Usage

If μ = 0.001 Pa·s and ρ = 1000 kg/m³: ν = 0.001/1000 = 1×10⁻⁶ m²/s (kinematic viscosity of water).

Recall Trigger

μ → Muscle (force-based, Pa·s); ν → Nerd (divided by ρ, m²/s)

Topic

Viscosity

Concept

Newtonian fluid — μ is independent of shear rate (dv/dy)

Anchor Id

Difficulty

medium

Memory Aid

Visualize NEWTON standing rigid and unmoving no matter how fast you push him — he resists with the SAME force per unit gradient regardless of speed. Non-Newtonian fluids are like 'tsismosa' neighbors: they react differently depending on how fast you approach them (cornstarch in water gets STIFFER the faster you stir; ketchup gets THINNER). Water, air, and light oils are Newtonian — they always follow the linear τ = μ(dv/dy) law.

Anchor Type

visual_association

Why It Works

The contrast between the rigid Newton and the reactive 'tsismosa' (gossip neighbor) creates a memorable dichotomy that sticks through humor and cultural relevance.

Example Usage

Board exam: 'Water is a Newtonian fluid because its dynamic viscosity does not change with shear rate — τ vs. dv/dy is a straight line through the origin.'

Recall Trigger

Newtonian → Newton standing rigid → constant μ → linear τ vs. dv/dy

Topic

Viscosity

Concept

Viscosity decreases with temperature for liquids (and increases for gases)

Anchor Id

Difficulty

medium

Memory Aid

Imagine Lola's coconut oil (langis ng niyog) on a cold morning in Baguio — it's solid/thick. Bring it to Manila noon heat — it flows freely. Liquids LOOSEN UP with heat: molecules move faster, intermolecular bonds (the 'glue' holding viscosity) break. Gases are OPPOSITE: heat gives gas molecules more energy to collide, increasing internal friction (viscosity rises). Remember: 'Liquids Loosen, Gases Get tougher with heat.'

Anchor Type

micro_story

Why It Works

The Lola's langis story uses a universally Filipino kitchen experience. The 'Liquids Loosen, Gases Get tougher' alliteration creates a phonetic hook.

Example Usage

Board question: 'As temperature increases, the dynamic viscosity of water...' Answer: DECREASES. Trigger: 'Lola's langis in Manila noon — thinner.'

Recall Trigger

Temperature effect on viscosity → Lola's coconut oil → liquids loosen with heat

Topic

Surface Tension and Capillarity

Concept

Surface tension (σ) — energy per unit area, units N/m

Anchor Id

Difficulty

medium

Memory Aid

Surface tension is the CLING WRAP of fluids. Imagine the water surface is wrapped in ultra-thin plastic film — it can support a needle or a small bangus (milkfish fry) walking on it. σ measures how tight that cling wrap is, in N/m (force per unit length) or equivalently J/m² (energy per unit area). Key value: water σ ≈ 0.0728 N/m at 20°C. Think '7.28 cents per meter of surface' to remember the magnitude.

Anchor Type

analogy

Why It Works

Cling wrap is a tangible everyday material with properties nearly identical to surface tension. The bangus reference is distinctly Filipino and memorable.

Example Usage

Given σ = 0.0728 N/m for water — this is the value to use in capillary rise problems unless another value is stated.

Recall Trigger

Surface tension → cling wrap on water → σ in N/m → 0.0728 N/m for water

Topic

Surface Tension and Capillarity

Concept

Capillary rise formula: h = 4σ cosθ / (γd)

Anchor Id

Difficulty

hard

Memory Aid

Use the phrase: '4 Sigma Cosines Go Down — Gamma Diameter.' Map it: 4σ cosθ is the NUMERATOR (going up = surface tension pulling up × 4 contacts), γd is the DENOMINATOR (going down = weight × tube width). Key: uses DIAMETER d (not radius). Common trap: some books use radius r → h = 2σcosθ/(γr). Both are equivalent, but the board exam formula uses diameter. Recall: 'Four Surfers Cosine the top; Gamma Diameter holds the bottom.'

Anchor Type

mnemonic

Why It Works

The numerator/denominator split into 'up force vs. down force' matches the physical derivation. The surfing image (4 surfers on top) makes it directional.

Example Usage

d = 2 mm, σ = 0.0728 N/m, θ = 0°, γ = 9810 N/m³: h = 4(0.0728)(1)/[9810(0.002)] = 0.0148 m = 14.8 mm.

Recall Trigger

'Four Surfers Cosine top, Gamma Diameter bottom' → h = 4σcosθ/(γd)

Topic

Surface Tension and Capillarity

Concept

Contact angle θ: water on glass θ ≈ 0° (rises); mercury on glass θ > 90° (depresses)

Anchor Id

A10

Difficulty

medium

Memory Aid

Picture WATER as a clingy friend (makulit) — it hugs clean glass at θ = 0°, climbing UP the tube (capillary rise). MERCURY is the cold, antisocial friend — it repels glass, arching AWAY and sinking DOWN (θ = 140°, capillary depression). The cosine is the key: cos(0°) = +1 → positive h = rise; cos(140°) ≈ −0.77 → negative h = depression. Image: water saying 'I love glass!' while mercury says 'Ayoko!'

Anchor Type

visual_association

Why It Works

The makulit vs. ayoko contrast (Filipino for 'clingy' vs. 'I don't want to') creates two distinct personality types that map directly to wetting angle behavior.

Example Usage

For mercury in a glass tube: θ > 90°, cosθ < 0, so h is negative → mercury level INSIDE is LOWER than outside (depression).

Recall Trigger

Contact angle → water = makulit (hugs glass, rises); mercury = ayoko (repels, sinks)

Topic

Compressibility

Concept

Bulk modulus E_B = dp/(dρ/ρ) — water ≈ 2.2 GPa

Anchor Id

A11

Difficulty

hard

Memory Aid

Imagine trying to squeeze a 1-liter water bottle with your bare hands. You push with all your might — it barely changes volume. That's the bulk modulus: E_B tells you how STUBBORN the fluid is to compression. Water's E_B ≈ 2.2 GPa = 2,200,000,000 Pa — a staggering number. Compare: steel E ≈ 200 GPa. Water is only 90× less stiff than steel in compression — no wonder water hammer causes pipe bursts! For most hydraulics problems, we treat water as INCOMPRESSIBLE because 2.2 GPa is enormous.

Anchor Type

micro_story

Why It Works

The water bottle squeezing experience is universal. Comparing to steel gives scale. The water hammer connection shows why incompressibility assumption sometimes breaks down.

Example Usage

ΔP = 2 MPa, E_B = 2.2 GPa: ΔV/V = ΔP/E_B = 2×10⁶/2.2×10⁹ = 0.000909 = 0.091% — barely compressed.

Recall Trigger

Bulk modulus → squeeze water bottle → barely moves → 2.2 GPa → nearly incompressible

Topic

Vapor Pressure

Concept

Vapor pressure and cavitation — cavitation occurs when local pressure ≤ vapor pressure

Anchor Id

A12

Difficulty

hard

Memory Aid

Vapor pressure is the fluid's BOILING POINT pressure at a given temperature. Think of it as the fluid's 'boiling trigger.' CAVITATION is what happens when a pump or turbine sucks so hard that local pressure drops to vapor pressure — the water BOILS LOCALLY, forming vapor bubbles. When these bubbles implode near metal surfaces, they release micro-shockwaves that pit and destroy metal. It's like the fluid 'biting back' — pumping water so hard it explodes. In Filipino: the fluid nagtatampo (throwing a fit) when pressure drops too low.

Anchor Type

analogy

Why It Works

The 'boiling trigger' concept connects vapor pressure to a familiar phenomenon. 'Nagtatampo' is a deeply Filipino emotional concept that makes the destructive cavitation effect memorable.

Example Usage

Board exam: 'Cavitation in a centrifugal pump occurs when suction pressure falls to the vapor pressure of the liquid.' To prevent it, ensure NPSH_available > NPSH_required.

Recall Trigger

Vapor pressure → boiling trigger → cavitation → bubbles implode → metal damage

Topic

Density and Specific Weight

Concept

Units: γ in N/m³ (or kN/m³); ρ in kg/m³ — differ by factor g = 9.81

Anchor Id

A13

Difficulty

easy

Memory Aid

Remember: 'γ is ρ's GRAVITY-BOOSTED twin.' The only difference: γ = ρ × g. If you see N/m³ or kN/m³ → it's γ (specific weight). If you see kg/m³ → it's ρ (density). Quick check: 1000 kg/m³ × 9.81 m/s² = 9810 N/m³ ≈ 9.81 kN/m³. The common board-exam trap is using ρ when γ is needed (or vice versa). Always ask: 'Is it mass-based or weight-based?' Mass = kg = ρ. Weight = N = γ.

Anchor Type

mnemonic

Why It Works

The 'gravity-boosted twin' metaphor creates a parent-child relationship where the child (γ) is always bigger than the parent (ρ) by factor g. The units test (N vs. kg) is a reliable self-check.

Example Usage

Trap question: 'Find the specific weight.' If you substitute ρ = 1000 directly instead of γ = 9810 N/m³ into a pressure formula, you'll be off by factor 9.81.

Recall Trigger

N/m³ → γ; kg/m³ → ρ; 'γ is ρ gravity-boosted'

Topic

Density and Specific Weight

Concept

Specific volume = 1/ρ

Anchor Id

A14

Difficulty

easy

Memory Aid

Specific volume is the FLIP of density — 'Flip rho, get volume per mass. Density flipped = space per kilogram of mass.' In units: m³/kg. Not commonly tested alone, but appears in thermodynamics crossover problems. Remember the rhyme: 'Density down, specific volume's crown — flip the fraction, don't get lost in action.' If ρ = 1000 kg/m³, then specific volume = 0.001 m³/kg.

Anchor Type

rhyme

Why It Works

The flip/inverse operation is anchored by the rhyme. The 0.001 value for water is memorable as '1 liter per kilogram' which is intuitive.

Example Usage

ρ = 850 kg/m³ → specific volume = 1/850 = 0.001176 m³/kg.

Recall Trigger

Specific volume → flip density → 1/ρ → m³/kg

Topic

Surface Tension and Capillarity

Concept

Capillary rise is INVERSELY proportional to tube diameter

Anchor Id

A15

Difficulty

medium

Memory Aid

Imagine two boba straws: a super-thin one (like a needle) and a fat one (like a jumbo boba straw). Dip both in water. The thin one — water shoots up high. The fat one — barely rises. This is the inverse relationship: h ∝ 1/d. The 'd' is in the DENOMINATOR of h = 4σcosθ/(γd). Halve the diameter → double the rise. This is why trees can pull water up to 100 meters through microscopic xylem tubes using capillarity.

Anchor Type

visual_association

Why It Works

Boba straws are universally known among Filipino students. The inverse visual (thin = high, fat = low) is counterintuitive at first, making it more memorable once understood.

Example Usage

If d is halved from 2 mm to 1 mm: h doubles from 14.8 mm to 29.6 mm. 'Thinner tube, higher rise.'

Recall Trigger

Thin boba straw → high capillary rise; fat straw → low rise; d in denominator

Topic

Viscosity

Concept

Shear stress force on a plate: F = τ × A = μ(V/t) × A

Anchor Id

A16

Difficulty

medium

Memory Aid

A plate slides on an oil film like a banca (outrigger boat) gliding on calm water. The force dragging it is F = τ × A. The shear stress τ = μ × (V/t), where V is speed and t is oil film thickness. Imagine pushing the banca: a thicker oil film (t big) = less resistance; faster banca (V big) = more resistance; bigger hull area (A big) = more drag. This is the board-exam 'sliding plate' problem — always three parts: find τ first, then multiply by A for F.

Anchor Type

micro_story

Why It Works

The banca analogy is culturally Filipino and perfectly maps the three physical variables. The three-step sequence (find τ, then F) creates a procedural memory.

Example Usage

Plate area 300 mm² = 300×10⁻⁶ m², oil film 0.5 mm = 0.0005 m, V = 1.5 m/s, μ = 0.1 Pa·s: τ = 0.1×(1.5/0.0005) = 300 Pa; F = 300 × 300×10⁻⁶ = 0.09 N.

Recall Trigger

Sliding plate → banca on oil film → F = μ(V/t) × A

Topic

Surface Tension and Capillarity

Concept

Units of surface tension σ: N/m (NOT N/m²)

Anchor Id

A17

Difficulty

medium

Memory Aid

Surface tension is FORCE per LENGTH of a line on the surface — like pulling a wire out of soap film. It's N/m (one-dimensional line), NOT N/m² (two-dimensional area — that's pressure or stress). Remember: 'σ sigma is SLIM — one dimension only: N/m.' The trap: students write N/m² because they confuse it with pressure. Check: if you see σ in a formula, its units must be N/m for dimensional consistency in h = 4σcosθ/(γd): [N/m]/[N/m³ × m] = m ✓

Anchor Type

mnemonic

Why It Works

The 'SLIM' mnemonic (one-dimensional) creates a physical image of a thin line rather than an area. The dimensional analysis check gives a self-verification tool.

Example Usage

Board trap: 'The unit of surface tension is ___.' Answer: N/m. If you wrote N/m², you fell for the common confusion with pressure.

Recall Trigger

σ is SLIM → one dimension → N/m, not N/m²

Topic

Compressibility

Concept

Compressibility: ΔV/V = ΔP/E_B (fractional volume change)

Anchor Id

A18

Difficulty

hard

Memory Aid

E_B is the fluid's 'stubbornness coefficient.' The higher E_B, the more stubborn (resistant to compression). Rearrange: ΔV/V = ΔP/E_B. Think of it as a loan payment: you pressure (ΔP) the fluid to compress, and E_B is the 'resistance' that determines how much it yields (ΔV/V). Water's E_B = 2.2 GPa → even a pressure of 2 MPa (20× atmospheric!) gives only ΔV/V = 2/2200 = 0.09% compression. That's why we say water is incompressible in standard hydraulics.

Anchor Type

analogy

Why It Works

The stubbornness metaphor is memorable and directional. The loan analogy clarifies the formula's proportionality. The 0.09% calculation anchors the 'nearly incompressible' claim with a real number.

Example Usage

ΔP = 5 MPa, E_B = 2.2 GPa: ΔV/V = 5×10⁶/2.2×10⁹ = 0.00227 = 0.227%. Water is barely compressed.

Recall Trigger

Bulk modulus → stubbornness coefficient → ΔV/V = ΔP/E_B

Topic

All fluid properties

Concept

Water properties at standard conditions: ρ=1000 kg/m³, γ=9.81 kN/m³, μ=1×10⁻³ Pa·s, ν=1×10⁻⁶ m²/s

Anchor Id

A19

Difficulty

easy

Memory Aid

The 'Water Four-Pack' at 20°C — memorize as a group: • ρ = 1000 (even thousands) • γ = 9.81 kN/m³ (same as g in different units!) • μ = 0.001 Pa·s = 1 mPa·s (milli-pascal-second) • ν = 0.000001 m²/s = 1 mm²/s (one millionth) Pattern: ρ and γ are 'big numbers' (1000, 9810); μ and ν are 'tiny numbers' (10⁻³, 10⁻⁶). The exponents go -3 and -6 for viscosities — two steps apart.

Anchor Type

chunking

Why It Works

Chunking all four standard water properties together lets you encode them as a single memory unit. The big/tiny pattern and the -3/-6 exponent staircase create internal logic.

Example Usage

Any board exam problem with water at standard conditions: automatically write ρ=1000, γ=9810, μ=0.001, ν=10⁻⁶ without re-deriving.

Recall Trigger

'Water Four-Pack' → 1000, 9.81k, 10⁻³, 10⁻⁶

Topic

Specific Gravity

Concept

Relationship: s < 1 = floats; s > 1 = sinks; s = 1 = neutrally buoyant

Anchor Id

A20

Difficulty

easy

Memory Aid

Remember this rhyme: 'Less than one — float for fun! More than one — down you run! Equal to one — you're done — neither up nor down, just floating in the sun!' Ice: s = 0.92 → floats (less than one). Mercury: s = 13.6 → sinks. A waterlogged log: s ≈ 1.0 → barely floats. This is your FIRST filter for any fluid statics problem involving multiple fluids.

Anchor Type

rhyme

Why It Works

The simple rhyme encodes three cases with positive emotional content (fun, sun). The familiar examples (ice floating, mercury sinking) anchor each case in real-world observation.

Example Usage

s = 0.85 oil on water: 'Less than one — float for fun!' → oil floats on water. Used in manometer problems with multiple fluids.

Recall Trigger

'Less than one — float for fun' → s controls buoyancy

Revision Game

Specific weight γ (gamma), γ = ρg, in units N/m³

Clue

I am the Greek letter that represents how heavy a fluid is per cubic meter. I equal my sibling (density) multiplied by 9.81. What am I?

Memory Link

A2 — 'Density goes to the gym and becomes Specific Weight'

Dynamic viscosity (μ) — increases as liquid temperature decreases

Clue

I am what happens when you cool Lola's coconut oil in Baguio — I increase in liquids as temperature drops. What property am I?

Memory Link

A7 — Lola's langis ng niyog analogy

The 1 mm tube rises 4× higher (h ∝ 1/d, so quartering the diameter quadruples the rise)

Clue

A boba straw with diameter 1 mm versus 4 mm is dipped in water. Which one shows a higher capillary rise, and by how much?

Memory Link

A15 — boba straw inverse diameter relationship

Newtonian fluid — μ is constant and independent of shear rate; τ vs. dv/dy is linear

Clue

I am a fluid that does NOT change my viscosity no matter how fast you shear me. Newton named a law after me. What type of fluid am I?

Memory Link

A6 — Newton standing rigid, constant μ regardless of shear speed

Fall (capillary depression): cos(140°) ≈ −0.766 → h is negative → mercury level inside tube is LOWER than outside

Clue

Mercury's contact angle with glass is about 140°. Will it rise or fall in a glass capillary tube? Calculate the sign of h using the formula.

Memory Link

A10 — mercury says 'Ayoko!' and falls away from glass

Specific gravity (s) = ρ_fluid / ρ_water = dimensionless ratio to water

Clue

I am the ratio that tells you instantly if a fluid will float or sink in water. I am dimensionless. If I equal 0.85, my fluid floats. If I equal 13.6, I am mercury and I sink. What am I?

Memory Link

A3 — courtroom scene: fluid answers to the judge (water) with its specific gravity score

P ≤ P_vapor (vapor pressure). Consequence: liquid boils locally forming vapor bubbles that implode violently, pitting metal surfaces (cavitation damage).

Clue

A pump cavitates when this condition is met. Complete the condition: 'Local pressure P ≤ ___.' What is the physical consequence?

Memory Link

A12 — fluid nagtatampo, vapor pressure as boiling trigger, cavitation destroys pumps

ρ = 1000 kg/m³; γ = 9810 N/m³ (9.81 kN/m³); μ = 0.001 Pa·s; ν = 1×10⁻⁶ m²/s

Clue

RAPID FIRE: Name the four standard water properties (20°C) with correct SI units in under 10 seconds. Go!

Memory Link

A19 — Water Four-Pack and the 1-9-1-1 pattern

F = viscous force on plate (N); τ = shear stress (Pa); A = plate area (m²); μ = dynamic viscosity (Pa·s); V = plate velocity (m/s); y = oil film thickness (m). Assumes linear velocity profile.

Start with ρ (kg/m³)
Multiply by g = 9.81 to get γ (N/m³)
Divide ρ by 1000 (or γ by 9810) to get s (dimensionless)
From s: ρ = s × 1000; γ = s × 9810

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CELE Hydraulics & Fluid Mechanics — Properties of FluidsMemory Anchors

Exam context

Properties of Fluids - Memory Anchors

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