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Cheat SheetCELE · Hydraulics & Fluid Mechanics

CELE Hydraulics & Fluid Mechanics — Hydrodynamics and Fluid MachineryCheat Sheet

The Hydrodynamics and Fluid Machinery cheat sheet from Super Tutor's CELE review — keep it for the last days before the exam.

Hydrodynamics and Fluid Machinery - Cheat Sheet

Final 30-minute reference for jet forces, pipe bends, pump and turbine power calculations, and affinity laws. Focus on momentum principle, energy conversion, and exam-critical formulas.

Jet Force & Momentum Principle

Formulas

F = ρQv or F = ρAv²

Meaning

ρ = density (1000 kg/m³), Q = discharge (m³/s), v = velocity (m/s), A = jet area (m²)

Watch out

Do NOT use γ (specific weight) here — momentum uses ρ (density). Common error: confusing 1000 kg/m³ with 9.81 kN/m³

When to use

Jet strikes a stationary flat plate normally (perpendicular impact)

F_n = ρQv sin(α)

Meaning

α = angle between jet and plate surface; F_n = normal force component

Watch out

α is measured from the plate surface, NOT from the jet direction. If plate is at 30° to jet, α = 30°, not 60°

When to use

Jet strikes an inclined flat plate; α = 90° recovers the normal-impact formula

F = ρQv(1 − cos θ)

Meaning

θ = angle through which vane turns the jet (deflection angle)

Watch out

This formula is for a STATIONARY vane. Moving vane uses relative velocity (v − u) where u = vane speed

When to use

Jet strikes a curved vane (stationary); θ = 180° gives max force (F = 2ρQv)

F_relative = ρQ_rel(v_rel)(1 − cos θ)

Meaning

v_rel = (v − u), Q_rel = A(v − u); jet moves with vane at speed u

Watch out

If v < u, the jet does not strike the vane — guard against this in problem setup

When to use

Vane is moving (e.g., turbine bucket moving at tangential speed u)

Common values

Value

1000 kg/m³

Symbol

ρ

Quantity

Water density

Value

9.81 kN/m³ or 9810 N/m³

Symbol

γ

Quantity

Water specific weight

Value

θ ≈ 165° to 170° (not 180° due to bucket geometry)

Symbol

θ_max

Quantity

Maximum deflection angle (Pelton bucket)

Important facts

  • Momentum is conserved: inlet momentum − outlet momentum = force × time
  • For a jet splitting on a smooth vane, assume discharge splits proportionally to deflection angles (conservation of Q)
  • Pressure force pA acts at pipe inlet/outlet; must be included in momentum balance for pipe bends
  • Kinetic energy loss = 0.5ρQ(v² inlet − v² outlet) when flow undergoes sudden expansion or collision

Key definitions

Momentum principle

Example

Jet hitting a plate: the plate exerts force on jet to stop it; by Newton's 3rd law, jet exerts equal/opposite force on plate

Force on a fluid = mass rate × change in velocity: ΣF = ρQ(v_out − v_in)

Relative velocity (moving vane)

Example

Jet at 20 m/s, vane moving at 5 m/s → relative velocity = 15 m/s

Velocity of jet relative to the vane frame = (v_jet − v_vane)

Deflection angle (θ)

Example

Pelton bucket turns jet 180° → θ = 180°, cos(180°) = −1, so F = 2ρQv (maximum)

Angle through which the vane changes the direction of the jet

Diagrams to know

  • Jet normal to flat plate (force perpendicular to plate)
  • Jet on inclined plate at angle α (resolve force into normal and tangential components)
  • Curved vane deflecting jet by angle θ (force along bisector of deflection for symmetric vane)
  • Moving vane with relative velocity triangle (jet velocity, vane velocity, relative velocity)

Reactions or equations

ΣF_x = ρQ(v_x,out − v_x,in)

Note

Positive direction is chosen; negative result means force opposes chosen direction

Conditions

Applies to control volume; subscripts x, y for coordinate directions

Force on Pipe Bends

Formulas

F_x = ρQ(v_{2x} − v_{1x}) + (p_1 A_1)_x − (p_2 A_2)_x

Meaning

Apply momentum in x-direction: ρ, Q as before; p_i = pressure (Pa), A_i = area (m²); subscript indicates component

Watch out

Pressure forces pA have direction components — a 90° bend has (p₁A₁) horizontal and (p₂A₂) vertical. Sign matters!

When to use

Pipe bend with inlet 1 and outlet 2; must account for both momentum change AND pressure forces

F_resultant = √(F_x² + F_y²)

Meaning

Magnitude of anchoring force (what the support/anchor must provide to hold the pipe)

Watch out

Direction of resultant: θ = arctan(F_y/F_x) — this is often asked in exams

When to use

After computing F_x and F_y separately; gives total magnitude

Common values

Value

101.325 kPa (absolute)

Symbol

p_atm

Quantity

Atmospheric pressure (gauge = 0)

Value

98.1 kPa (approximately 100 kPa)

Symbol

p = ρgh

Quantity

Pressure from 10 m water column

Important facts

  • For a horizontal pipe at same elevation: p₁ = p₂ if no friction (ideal case), so pressure forces may cancel on certain bend orientations
  • A 90° bend results in maximum force when inlet/outlet diameters are equal and pressures are equal
  • In practice, pressure at outlet may differ due to depth change (use hydrostatic pressure if pipe rises or falls)
  • Anchor reaction is perpendicular to the resultant force direction

Key definitions

Anchoring force

Example

90° horizontal bend: anchoring force = √(F_x² + F_y²) directed opposite to the resultant momentum + pressure force

Reaction force exerted by pipe supports/anchors to hold the bend against the dynamic force of flowing water

Control volume

Example

Includes the bend itself and the fluid within it; exterior forces (pressure at ends, anchor reaction) balance momentum change

Imaginary fixed region around the pipe bend; momentum balance applies across inlet and outlet faces

Diagrams to know

  • 90° horizontal bend: identify pressure forces at inlet (pointing right) and outlet (pointing up), plus momentum change
  • Reducing bend (larger to smaller diameter): velocity increases at outlet, pressure decreases (Bernoulli); both affect force
  • Vertical bend (pipe rising): account for weight of water in bend, change in elevation head, and hydrostatic pressure difference

Reactions or equations

F_y = ρQ(v_{2y} − v_{1y}) + (p_1 A_1)_y − (p_2 A_2)_y

Note

Common case: inlet vertical (v_1y ≠ 0), outlet horizontal (v_2y = 0) → requires both terms

Conditions

Same momentum principle applied to y-direction; complete vector analysis

Pump Power & Performance

Formulas

P_input = (γQH)/η

Meaning

γ = 9.81 kN/m³, Q = discharge (m³/s), H = head added by pump (m), η = pump efficiency (decimal 0–1)

Watch out

η goes in the denominator (divide by efficiency). Small η means large input power needed. Common error: multiply by η instead of dividing

When to use

Calculate motor/engine power required to drive a pump; H is the total head rise across pump

P_hydraulic = γQH

Meaning

Useful water power (output) delivered to the fluid; same units (kW if γ in kN/m³, Q in m³/s, H in m)

Watch out

This is NOT the input power — it is the energy imparted to water. Always multiply by efficiency to get actual motor power

When to use

When only the hydraulic power is asked (ideal case, η = 1); or to verify efficiency: η = P_hydraulic / P_input

Q_1 / Q_2 = N_1 / N_2

Meaning

Affinity law for discharge: proportional to rotational speed; N in rpm

Watch out

This is LINEAR: if speed doubles, discharge doubles. Do NOT square or cube

When to use

Pump speed changes (e.g., variable-frequency drive); find new discharge or speed from this ratio

H_1 / H_2 = (N_1 / N_2)²

Meaning

Affinity law for head: proportional to speed squared

Watch out

Square the speed ratio — very different from discharge law. If N doubles, H increases 4×

When to use

Pump speed changes; find new head. This is QUADRATIC

P_1 / P_2 = (N_1 / N_2)³

Meaning

Affinity law for power: proportional to speed cubed

Watch out

Cube the speed ratio. If N doubles, P increases 8×. This is why variable-speed drives save energy

When to use

Pump speed changes; find new power requirement. This is CUBIC (most aggressive)

NPSH_required ≤ NPSH_available

Meaning

NPSH = net positive suction head; R = required (depends on pump design), A = available (depends on site/conditions)

Watch out

If NPSH_available < NPSH_required, cavitation occurs (damage, noise, loss of efficiency). Site elevation and suction line losses reduce available NPSH

When to use

Check for cavitation risk on pump suction side; typically given in pump datasheets

Common values

Value

70–90%

Symbol

η

Quantity

Typical centrifugal pump efficiency

Value

9.81 kN/m³

Symbol

γ

Quantity

Specific weight of water

Value

2.34 kPa (absolute)

Symbol

p_v

Quantity

Vapor pressure of water at 20°C

Value

6–8 m (atmospheric pressure limits absolute)

Symbol

h_s,max

Quantity

Typical suction lift limit (centrifugal pump)

Important facts

  • Affinity laws assume pump operates at same point on efficiency curve (geometrically similar flow patterns)
  • When speed changes: Q ∝ N, H ∝ N², P ∝ N³ — power is most sensitive to speed changes
  • Pump operates at intersection of pump curve (P, H, η vs Q) and system curve (head losses vs Q)
  • Impeller diameter change also obeys affinity laws: Q ∝ D, H ∝ D², P ∝ D³
  • NPSH_available = p_atm/γ − h_s − h_f,suction − p_v/γ (where h_s = suction lift, h_f = friction loss, p_v = vapor pressure)
  • At high altitude, p_atm decreases → NPSH_available decreases → cavitation risk increases

Key definitions

Head (H)

Example

Pump lifts water 30 m vertically at low speed: H ≈ 30 m + suction losses + discharge losses

Height equivalent of pressure or energy per unit weight of water; combines pressure head, velocity head, and elevation head

Pump efficiency (η)

Example

Pump with η = 80%: input 100 kW → delivers 80 kW to water (20 kW lost as heat, friction, turbulence)

Ratio of hydraulic power output to input (shaft) power: η = (γQH) / P_input; typically 70–90% for centrifugal pumps

NPSH (net positive suction head)

Example

Atmospheric pressure 101.325 kPa, vapor pressure at 20°C ≈ 2.3 kPa, suction line elevation +2 m → NPSH_available calculated from Bernoulli

Pressure head available above vapor pressure at pump inlet; ensures fluid stays liquid inside pump

Cavitation

Example

High-speed pump at high altitude or with long suction line: low NPSH → cavitation → pitting of impeller vanes

Vapor bubble formation when local pressure drops below vapor pressure; bubbles collapse, causing erosion and noise

Diagrams to know

  • Pump performance curve: H and η vs discharge Q (typical bell-shaped η curve, H curve may slope down or flat)
  • System curve: H_total = H_static + H_friction(Q); intersection with pump curve = operating point
  • NPSH curve for a pump: shows NPSH_required increasing with Q; plot against NPSH_available from site
  • Affinity law comparison: three speed-ratio examples showing linear (Q), quadratic (H), and cubic (P) relationships

Reactions or equations

η = (γQH) / P_input = P_hydraulic / P_input

Note

Rearrange to find input power given η, Q, H or to find hydraulic power given input power and η

Conditions

Energy balance across pump; efficiency always between 0 and 1

Turbine Power & Classification

Formulas

P_output = η × γ × Q × H

Meaning

η = turbine efficiency (0–1), γ = 9.81 kN/m³, Q = discharge (m³/s), H = net head available (m)

Watch out

Multiply by η (opposite of pump formula where you divide). High efficiency and high head/flow = large power. Common exam trap: reversing pump/turbine formulas

When to use

Calculate electrical/mechanical power generated by a turbine from flow and head

H_net = H_gross − H_losses

Meaning

H_gross = total available head (elevation difference), H_losses = friction in intake, penstock, tailrace (m)

Watch out

H_losses can be 5–15% of H_gross in real projects; ignoring losses overestimates power

When to use

Refine power calculation to account for pipe/intake friction losses in hydropower plants

Specific speed: N_s = (N × √Q) / H^(3/4)

Meaning

N = rpm, Q = discharge (m³/s), H = head (m); N_s is dimensionless turbine characteristic; N_s in SI ≈ 0.87 × N_s (US)

Watch out

Specific speed determines turbine type — don't confuse with ordinary rpm; also be careful with unit consistency (SI vs US)

When to use

Classify turbine type: Pelton (low N_s ≈ 1–4), Turgo (N_s ≈ 4–10), Crossflow (N_s ≈ 10–100), Francis (N_s ≈ 60–300), Kaplan (N_s ≈ 200–900)

Common values

Value

1–4

Symbol

N_s (SI)

Quantity

Pelton wheel specific speed range

Value

60–300

Symbol

N_s (SI)

Quantity

Francis turbine specific speed range

Value

200–900

Symbol

N_s (SI)

Quantity

Kaplan turbine specific speed range

Value

90–95%

Symbol

η

Quantity

Typical Pelton efficiency

Value

88–92%

Symbol

η

Quantity

Typical Francis efficiency

Value

85–92% (varies with design head)

Symbol

η

Quantity

Typical Kaplan efficiency

Important facts

  • Impulse turbines: all available head converts to kinetic energy in jet; nozzle designs crucial; efficient single or multi-jet operation
  • Reaction turbines: submerged in pressurized casing; require draft tube to extract tail water energy; efficient over wider operating range
  • Francis turbine: curved runner blades, medium head/flow; most common for hydropower; runaway speed ≈ 1.5–1.8 × rated speed
  • Kaplan (propeller) turbine: adjustable blade pitch allows efficiency over wide flow range; large discharge, low head (tidal, run-of-river)
  • Pelton bucket design: enters at center, exits to sides (180° deflection ≈ 165–170° practical) to maximize momentum transfer with minimal splash
  • Power increases with H^1 (linear) and Q^1 (linear), so doubling head OR doubling flow doubles power; N_s = (N√Q)/H^0.75 guides selection

Key definitions

Impulse turbine

Example

Small flow, high head (>500 m); single or multiple jets on a bucket-wheel; efficient at part-load

Jet(s) strike moving buckets; momentum transfer drives rotor (NOT pressure drop across blades). Example: Pelton wheel

Reaction turbine

Example

Large flow, medium head (5–300 m); submerged runner in spiral casing; requires draft tube for efficiency

Pressure drop across moving blades accelerates flow through runner; both pressure and momentum contribute to torque. Examples: Francis, Kaplan

Net head (H_net)

Example

Reservoir at +100 m, tailwater at +10 m, losses = 8 m → H_net = 100 − 10 − 8 = 82 m

Effective pressure head delivered to turbine after subtracting intake, penstock, and tailrace friction losses

Specific speed (N_s)

Example

Francis turbine typically N_s = 60–300; Pelton typically N_s = 1–4

Dimensionless parameter combining speed, flow, and head; characterizes turbine geometry and performance

Diagrams to know

  • Pelton wheel: bucket geometry, jet entry/exit, tangential velocity vector diagram
  • Francis runner: spiral casing, curved blades, discharge direction; draft tube below
  • Kaplan runner: adjustable blades, hub, ring structure; axial flow; draft tube configuration
  • Turbine classification chart: N_s on x-axis (log scale), turbine type and head range labeled
  • Energy conversion: reservoir elevation → penstock kinetic energy → runner rotation → generator power

Reactions or equations

η = P_output / P_available = P_output / (γQH_net)

Note

Typical η = 85–92% for modern turbines; Pelton best (90–95%), Kaplan varies (85–92% depending on design head)

Conditions

Defines turbine efficiency; product of hydraulic, mechanical, and volumetric efficiencies

Practical Hydraulic Calculations & Unit Conversions

Formulas

γ = ρ × g; γ = 9.81 kN/m³ or 9810 N/m³

Meaning

ρ = density (1000 kg/m³), g = gravitational acceleration (9.81 m/s²); γ relates mass and weight

Watch out

Do NOT use 9.81 kN/m³ in momentum formulas — use ρ = 1000 kg/m³. Two different contexts!

When to use

When power formula requires γ instead of ρ; converting between weight and mass flows

Q [m³/s] = A [m²] × v [m/s]

Meaning

Discharge = area × velocity; fundamental continuity equation for incompressible flow

Watch out

Cross-sectional area must be perpendicular to flow direction; for pipe, A = π(D/2)²

When to use

Convert between velocity and discharge; find jet area from discharge and velocity

1 kW = 1 kN/m³ × 1 m³/s × 1 m = γ [kN/m³] × Q [m³/s] × H [m]

Meaning

Power in kW when using γ in kN/m³, Q in m³/s, H in m

Watch out

If using N/m³ for γ, power comes out in watts (W); if using kN/m³, power is in kW. Always verify units

When to use

Pump/turbine power calculations; simple dimensional check

Pressure head: h = p / γ [m]

Meaning

Convert pressure (Pa or kPa) to equivalent water column height (m); h = p / ρg

Watch out

γ = 9.81 kN/m³; if p = 98.1 kPa, h = 98.1 kPa / 9.81 kN/m³ = 10 m (exactly)

When to use

Total head analysis (elevation + pressure + velocity head); NPSH calculations

Velocity head: h_v = v² / (2g) [m]

Meaning

Kinetic energy expressed as equivalent head; g = 9.81 m/s²

Watch out

Even at high velocity (e.g., 10 m/s), velocity head = 100/(2×9.81) ≈ 5.1 m — often small compared to pressure/elevation head

When to use

Bernoulli equation; total head in pipes with significant velocity

Common values

Value

1000 kg/m³

Symbol

ρ

Quantity

Water density

Value

9.81 kN/m³

Symbol

γ

Quantity

Water specific weight (SI)

Value

9.81 m/s²

Symbol

g

Quantity

Gravitational acceleration

Value

9.81 kPa

Symbol

p = γh

Quantity

Pressure equivalent of 1 m water

Value

101.325 kPa = 10.33 m water

Symbol

p_atm

Quantity

Atmospheric pressure (standard)

Important facts

  • Bernoulli is valid along a streamline for frictionless, steady, incompressible flow
  • In real pipes, add friction head loss: H_friction ≈ f(L/D)(v²/2g) (Darcy-Weisbach); reduces net available head
  • Pressure units: 1 kPa = 1000 Pa = 0.00987 m of water (approximately); 100 kPa ≈ 10.2 m water column
  • Discharge in pipes remains constant (continuity): A₁v₁ = A₂v₂; if pipe reduces, velocity increases and pressure decreases (Bernoulli)

Key definitions

Total head (H_total)

Example

Pump inlet at −2 m elevation, p = 40 kPa, v = 1 m/s: total head = −2 + 40/9.81 + 1²/19.62 ≈ −2 + 4.08 + 0.05 ≈ 2.1 m

Sum of elevation, pressure, and velocity heads: H_total = z + p/γ + v²/(2g) (Bernoulli constant along streamline)

Static head

Example

Reservoir 40 m above discharge, zero gauge pressure: H_static = 40 m (ignoring velocity and losses)

Elevation difference + pressure head (no velocity component); H_static = Δz + Δp/γ

Diagrams to know

  • Hydraulic grade line (HGL): plot of (p/γ + z) vs distance; shows available pressure head at each point
  • Energy grade line (EGL): plot of (p/γ + z + v²/2g) vs distance; lies above HGL by velocity head; drops due to friction
  • Pump and system curve: H vs Q; operating point at intersection; affinity law scaling of pump curve for different speeds

Reactions or equations

Bernoulli: (p₁/γ) + z₁ + (v₁²/2g) = (p₂/γ) + z₂ + (v₂²/2g) + h_f

Note

If no friction (ideal): total head is constant. Real flow: head decreases downstream due to h_f

Conditions

Steady, incompressible flow along a streamline; h_f = friction loss between points 1 and 2

Must remember

  • Jet force on stationary flat plate: F = ρQv = ρAv² (MOMENTUM, NOT pressure). Use ρ = 1000 kg/m³, not γ = 9.81 kN/m³.
  • Moving vane force uses RELATIVE VELOCITY (v − u), not absolute jet velocity v. If vane speed u > jet speed v, vane misses the jet.
  • Curved vane deflects jet by angle θ: force F = ρQv(1 − cos θ). Maximum at θ = 180° (F = 2ρQv). Always check deflection angle in exam.
  • Pump INPUT power formula: P_input = (γQH) / η — divide by efficiency. Turbine OUTPUT power: P_output = η × γ × Q × H — multiply by efficiency. OPPOSITE conventions!
  • Affinity laws (with speed change): Q ∝ N (linear), H ∝ N² (quadratic), P ∝ N³ (cubic). Doubling speed quadruples head and octuples power — massive effect on motor sizing.
  • Impulse turbines (Pelton): high head (>500 m), small discharge, N_s = 1–4. Reaction turbines (Francis/Kaplan): medium head (5–300 m), large discharge, N_s = 60–900. Turbine TYPE determined by specific speed.
  • Pipe bend: include BOTH momentum change (ρQΔv) AND pressure forces (pA) in each direction. Forgetting pressure forces is a common exam killer.
  • NPSH_required > NPSH_available → cavitation (pump damage, noise, loss of prime). High altitude, high speed, long suction line ALL reduce NPSH_available — guard against cavitation.
  • Pressure head conversion: 1 kPa ≈ 0.102 m water; 100 kPa ≈ 10.2 m. Velocity head at 10 m/s = 100/(2×9.81) ≈ 5.1 m. Always include velocity head in Bernoulli if flow speed is high (>3 m/s).
  • Specific speed N_s = (N√Q) / H^(0.75) (SI units) uniquely identifies turbine type. Mixing SI and US units for N_s is a common error; always confirm unit system in exam question.

Last minute tips

  • ρ vs γ CRITICAL: Momentum formulas use ρ (kg/m³); power formulas use γ (kN/m³ or N/m³). Wrong choice = wrong answer by factor of 10. Double-check every formula substitution.
  • Pump vs Turbine Power: Pump divides by η (input/efficiency ratio), Turbine multiplies by η (output = efficiency × available power). Reverse it = instant wrong answer. Write both formulas side-by-side before solving.
  • Affinity Law Exponents: Remember Q is LINEAR (×N), H is QUADRATIC (×N²), P is CUBIC (×N³). If you guess wrong on exponent, entire calculation fails. Visual mnemonic: Q-line, H-square, P-cube.
  • Deflection Angle θ in Jet-Vane: θ is total deflection (how much the vane turns the jet), NOT the angle from horizontal. Pelton bucket deflects ~165° (not 180° due to geometry). Read problem carefully for angle definition.
  • Exam Time Saver: Always verify units before plugging numbers in. If γ in kN/m³, Q in m³/s, H in m → power in kW directly. If units mismatch, recalculate. One minute spent on unit check saves 5 minutes of debugging wrong answers.

Comparison tables

Impulse vs Reaction Turbines

FeatureImpulse (Pelton)Reaction (Francis/Kaplan)
Head range>500 m (very high)5–300 m (medium)
Discharge rangeSmall to mediumLarge
Specific speed (N_s, SI)1–460–300 (Francis); 200–900 (Kaplan)
Energy conversionPotential → kinetic (nozzle) → momentum transferPressure drop across blades; pressure + momentum
Runner typeBuckets on wheel rimSubmerged curved blades in spiral casing
Draft tube required?No (atmospheric discharge)Yes (extracts tail water energy)
Efficiency at rated load90–95%88–92% (varies)
Part-load efficiencyGood (maintains high efficiency down to ~30% load)Francis: moderate; Kaplan: excellent (adjustable blades)
Common applicationsHigh head: mountain reservoirs, run-of-riverFrancis: medium head hydropower; Kaplan: tidal, low-head run-of-river

Pump vs Turbine — Power & Efficiency

AspectPumpTurbine
FunctionAdds head (lifts fluid)Extracts head (generates power)
Energy conversionMechanical → hydraulicHydraulic → mechanical
Power formulaP_input = (γQH) / ηP_output = η × γ × Q × H
Efficiency locationDivide (denominator)Multiply (coefficient)
Typical efficiency70–90% (centrifugal)85–95% (modern turbines)
Affinity law: QQ ∝ N (linear)Q ∝ N (linear)
Affinity law: HH ∝ N² (quadratic)H ∝ N² (quadratic)
Affinity law: PP ∝ N³ (cubic)P ∝ N³ (cubic)
Cavitation risk?Yes — suction side (NPSH_required check)No — pressure side; operates under submergence

Jet Force Formulas — Quick Reference

ScenarioFormulaNotes
Jet on stationary flat plate (normal impact)F = ρQv = ρAv²v = jet velocity, A = jet area; result is force perpendicular to plate
Jet on inclined plate at angle αF_n = ρQv sin(α)α is angle between jet and plate surface; α = 90° gives normal impact formula
Jet on curved vane (stationary), deflection θF = ρQv(1 − cos θ)θ = 180° → F = 2ρQv (max force); θ = 90° → F ≈ 1.41ρQv
Jet on moving vane at speed u, deflection θF = ρ(v−u)Q_rel(1 − cos θ)Use relative velocity (v − u); if v < u, jet misses vane. Typical in turbines

Affinity Laws — Scaling Pump/Turbine Performance

ParameterRelationshipExample: if N doubles (×2)
Discharge (Q)Q₂ = Q₁ × (N₂/N₁)Q doubles (×2)
Head (H)H₂ = H₁ × (N₂/N₁)²H increases ×4
Power (P)P₂ = P₁ × (N₂/N₁)³P increases ×8 (cubic!)
Cavitation/NPSHNPSH_required ∝ N²NPSH requirement increases ×4; risk increases at high speed

Diagrams

Hydrodynamics & Fluid Machinery — Complete Concept Map

Complete concept hierarchy showing jet forces, pipe bends, pump and turbine fundamentals, affinity laws, and turbine classification by specific speed.

Pump Power Calculation Decision Tree

Decision flowchart for selecting correct pump power formula (input vs hydraulic) and verifying units before calculation.

Turbine Type Selection by Specific Speed

Decision tree for turbine selection based on calculated specific speed, including typical head ranges, discharge categories, and efficiency values.

Cavitation Risk Assessment (Pump Suction)

State diagram showing cavitation risk assessment process, threshold condition, and mitigation strategies for pump suction-side problems.

Power Loss Breakdown in Pump System

Pie chart showing typical allocation of input motor power in a pump system, highlighting that only 75% reaches the water (at η ≈ 75-80%).

Historical Turbine Development & Efficiency Progression

Timeline showing development of turbine types from early Pelton invention through modern high-efficiency designs, illustrating 140+ years of engineering advancement.

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