CELE Geotechnical Engineering — Slope Stability and Soil ImprovementRevision Notes
Final-week revision notes for Slope Stability and Soil Improvement. If you have already studied the full chapter, this page is your go-to refresher before sitting the CELE. Compact, high-yield, and aligned with what Professional Regulation Commission (PRC) — Board of Civil Engineering tests in the Geotechnical Engineering subtest.
Exam context
The Civil Engineer Licensure Examination is conducted by Professional Regulation Commission (PRC) — Board of Civil Engineering and is scheduled for May and November 2026. The Geotechnical Engineering subtest is marked as "Core" in the official pattern, and Slope Stability and Soil Improvement appears in position 11th of 11 in the CELE Geotechnical Engineering review rotation. Passing mark: 70% weighted average, no sub-test below 50%. Recent CELE 2026 papers have drawn roughly a meaningful share of questions from this subject.
Slope Stability and Soil Improvement - Revision Notes
Slope failures are among the most catastrophic geotechnical events in the Philippines, where typhoons, heavy rainfall, and volcanic soil conditions frequently trigger landslides. From the 2006 Southern Leyte mudslide to routine road-cut failures in the Cordillera, understanding slope stability is not just an exam topic — it is a life-safety engineering skill. This chapter covers the quantitative assessment of slope stability (Factor of Safety, infinite-slope analysis, method of slices, Taylor's stability number) and the suite of ground-improvement techniques used when in-situ soil is inadequate. These topics consistently appear in the PRC Civil Engineer Licensure Examination under Geotechnical Engineering.
Sections
Formulas
Example
If τ_f = 45 kPa and τ = 30 kPa, then FS = 45/30 = 1.50 — acceptable for permanent slope.
Formula
FS = τ_f / τ
Variables
τ_f = shear strength available (Mohr-Coulomb: c' + σ'tan φ'), kPa; τ = shear stress required for equilibrium along the failure plane, kPa
Application
Universal definition; applies to any slope geometry and soil type.
Exam Tips
- If a problem states 'undrained' or 'short-term' condition for clay, use c_u (undrained cohesion) and φ = 0.
- If a problem states 'long-term' or 'drained' condition, use c' and φ' with effective stresses.
- Always report FS to two decimal places in board-exam solutions.
Key Points
- FS is defined as the ratio of the maximum shear strength available to the shear stress mobilized along the failure surface.
- FS > 1.0 means the slope is stable; FS = 1.0 means the slope is at the verge of failure (limit equilibrium); FS < 1.0 means failure has already occurred.
- Design targets in Philippine practice: FS ≥ 1.3 for temporary cuts, FS ≥ 1.5 for permanent slopes and earth dams.
- A higher FS is required when soil parameters are uncertain, consequences are severe, or seismic loading must be considered.
- FS is always computed with respect to a specific failure surface — different assumed surfaces give different FS values; the critical surface gives the minimum FS.
Definitions
Term
Factor of Safety (FS)
Definition
Dimensionless ratio of the shear resistance available along a potential failure surface to the shear stress required to maintain equilibrium. FS = τ_f / τ.
Importance
Primary design criterion in slope stability; directly controls whether a slope is deemed safe or requires remediation.
Term
Critical Failure Surface
Definition
The trial failure surface (planar or circular arc) that yields the lowest computed FS. It is the most dangerous potential sliding plane.
Importance
Design must target the minimum FS surface, not just any assumed surface.
Term
Limit Equilibrium
Definition
The condition where FS = 1.0: driving forces exactly equal resisting forces. The slope is on the verge of failure.
Importance
All slope stability methods (Fellenius, Bishop, Taylor) are limit-equilibrium methods.
Section Title
1. Factor of Safety (FS) — The Core Concept
Common Mistakes
- Using FS = 1.3 for all cases — the required FS depends on the consequence of failure and quality of soil data.
- Forgetting that FS must be computed for multiple trial surfaces; one trial is never sufficient.
- Confusing total stress analysis (undrained, φ = 0) with effective stress analysis (drained, c', φ') — these apply to different drainage conditions.
Formulas
Example
Sandy slope: φ' = 32°, β = 20°. FS = tan32°/tan20° = 0.6249/0.3640 = 1.72. Stable.
Formula
FS = tan φ' / tan β
Variables
φ' = effective friction angle (degrees); β = slope angle from horizontal (degrees). Valid for dry or saturated-but-no-flow cohesionless soil (c' = 0).
Application
Quick check for sandy or gravelly slopes; provides the angle of repose directly.
Example
c' = 10 kPa, φ' = 28°, γ = 18 kN/m³, z = 3 m, β = 25°. γz = 54 kPa. cos²25° = 0.8214. tan28° = 0.5317. Numerator = 10 + 54(0.8214)(0.5317) = 10 + 23.59 = 33.59 kPa. Denominator = 54 × sin25° × cos25° = 54 × 0.4226 × 0.9063 = 20.68 kPa. FS = 33.59/20.68 = 1.62.
Formula
FS = [c' + γz cos²β tan φ'] / (γz sinβ cosβ)
Variables
c' = effective cohesion (kPa); γ = unit weight of soil (kN/m³); z = depth to failure plane (m); β = slope angle (degrees); φ' = effective friction angle (degrees).
Application
Cohesive or c-φ soil, no seepage, failure plane parallel to slope.
Example
For c' = 0: FS = (γ'/γ_sat) × (tan φ'/tan β). With γ' = 9 kN/m³ and γ_sat = 19 kN/m³: FS = (9/19) × (tan32°/tan20°) = 0.474 × 1.72 = 0.81 — the slope fails! This illustrates why seepage is critical.
Formula
FS = [c' + (γ - γ_w) z cos²β tan φ'] / (γ_sat z sinβ cosβ)
Variables
γ_sat = saturated unit weight (kN/m³); γ_w = 9.81 kN/m³; (γ_sat - γ_w) = γ' = buoyant/submerged unit weight. Used when seepage is parallel to slope and water table is at the surface.
Application
Worst-case seepage condition — governs design of slopes in typhoon-prone areas.
Exam Tips
- Memorize the two key formulas: FS_dry = tanφ'/tanβ and FS_cohesive = [c' + γz cos²β tanφ']/(γz sinβ cosβ).
- For seepage problems, replace γ with γ' in the resistance term and keep γ_sat in the driving term.
- Note: sin β cos β = (sin 2β)/2 — can simplify denominator calculations.
Key Points
- Applicable to long, uniform slopes where the failure plane is parallel to the ground surface — common in residual soil slopes and road cuts in the Philippines.
- The failure plane depth z is measured perpendicular to the slope surface.
- For a dry cohesionless slope (c' = 0), FS depends only on φ' and β — it is independent of depth z. The slope is stable as long as β < φ' (angle of repose).
- Cohesion adds resistance; the presence of seepage parallel to the slope dramatically reduces FS because pore pressure acts along the entire failure plane.
- With full seepage (water table at the surface, flow parallel to slope): FS_cohesionless = (γ'/γ_sat) × (tan φ'/tan β) ≈ 0.5 × FS_dry — seepage approximately halves FS for cohesionless soils.
- The cos²β term in the cohesive formula is frequently mis-remembered in board exams — it is cos²β, not cosβ.
Definitions
Term
Infinite Slope
Definition
An idealized slope of infinite lateral extent where the failure surface is a plane parallel to the slope face at a uniform depth z. End effects are neglected.
Importance
Provides closed-form FS expressions used directly in board problems and preliminary design.
Term
Angle of Repose
Definition
The maximum slope angle at which a dry cohesionless soil remains stable without sliding. Numerically equal to φ', the effective friction angle.
Importance
Design of stockpiles, road cuts in sand, and granular embankments.
Term
Seepage Force
Definition
The drag force exerted by water flowing through a soil mass. In slopes with parallel seepage, it increases the driving force while pore pressure reduces effective stress.
Importance
Seepage is the single most common trigger of slope failure in the Philippines during typhoon season.
Section Title
2. Infinite-Slope Analysis
Common Mistakes
- Using cosβ instead of cos²β in the cohesive infinite-slope formula — the correct term is γz cos²β tanφ' in the numerator.
- Applying the dry formula when a seepage condition is stated — always check whether seepage is present.
- Forgetting that for a dry cohesionless slope, FS is depth-independent — adding more soil above the failure plane doesn't help.
- Using γ (total unit weight) instead of γ' (buoyant unit weight) in the friction term when seepage is present.
Formulas
Example
A 3-slice problem: Σ(c'ℓ + N'tanφ') = 180 kN, ΣWsinα = 120 kN. FS = 180/120 = 1.50.
Formula
FS = Σ(c'ℓ + N' tan φ') / Σ(W sinα)
Variables
c' = effective cohesion (kPa); ℓ = arc length of slice base (m); N' = effective normal force on slice base (kN); φ' = effective friction angle; W = weight of slice (kN); α = angle of slice base to horizontal (degrees). Summation over all n slices.
Application
Fellenius/Swedish method. For each slice: N' = W cosα - u·ℓ where u = pore pressure at slice base.
Example
N_s = 0.06, c = 20 kPa, γ = 18 kN/m³. H_cr = c/(γ N_s) = 20/(18 × 0.06) = 20/1.08 = 18.5 m.
Formula
N_s = c / (γ H FS)
Variables
N_s = stability number (dimensionless, from Taylor's chart); c = cohesion (kPa); γ = unit weight (kN/m³); H = slope height (m); FS = factor of safety.
Application
Taylor's stability number relates slope geometry (β, φ) to the c-γ-H group. Given N_s from chart, solve for H_cr (at FS=1) or required c.
Example
For FS = 1.5: H_design = 18.5/1.5 = 12.3 m — the safe design height.
Formula
H_cr = c / (γ N_s)
Variables
H_cr = critical height at FS = 1.0 (m); c = cohesion (kPa); γ = unit weight (kN/m³); N_s = stability number from Taylor's chart.
Application
Determines the maximum unsupported height of a slope before failure. For a given FS: H_design = H_cr / FS.
Example
Soft clay: c_u = 25 kPa, γ = 16 kN/m³. H_cr = 4(25)/16 = 6.25 m. For FS = 1.5: H_safe = 6.25/1.5 = 4.2 m.
Formula
H_cr = 4c_u / γ (vertical cut, φ = 0)
Variables
c_u = undrained shear strength (kPa); γ = total unit weight (kN/m³). Valid for purely cohesive soil, short-term undrained condition.
Application
Quick estimate for excavation in soft clay — critical in urban construction in Manila Bay area soft soils.
Exam Tips
- In Taylor problems, if FS ≠ 1.0 is required: H_design = c/(γ N_s FS) — the FS simply appears in the denominator.
- For φ = 0 (undrained clay) quick check: N_s ≈ 0.261 for a vertical cut (β = 90°); H_cr ≈ 3.83c/γ.
- When a board problem says 'use Taylor's chart with N_s = ___', treat it as given data and apply the formula directly.
- Slice method: if the problem gives net driving moment ΣWsinα and net resisting moment, FS = Resisting/Driving — no need to track individual slices.
Key Points
- Used when the failure surface is a circular arc — applicable to most embankments, natural slopes, and earth dams.
- The failure mass above the trial circular arc is divided into vertical slices; forces on each slice are analyzed.
- Fellenius (Swedish) Method: Neglects inter-slice forces — simple but slightly conservative (underestimates FS by 5-15%).
- Bishop's Simplified Method: Accounts for horizontal inter-slice forces — more accurate and widely used in practice.
- Multiple trial circles must be analyzed; the one giving minimum FS is the critical circle.
- Taylor's Stability Number (Ns) provides a rapid solution for homogeneous slopes — ideal for board exam problems.
- Critical height H_cr is the maximum height of an unsupported slope at FS = 1.0.
- For a vertical cut in undrained clay (φ = 0): H_cr = 4c_u/γ (Terzaghi's approximation).
Definitions
Term
Taylor's Stability Number (N_s)
Definition
A dimensionless parameter N_s = c/(γHFS) that encapsulates the relationship between slope geometry (angle β) and soil strength (φ) for homogeneous slopes. Values are read from Taylor's stability chart.
Importance
Enables rapid calculation of critical height or required cohesion without drawing trial circles — very common in board exams.
Term
Method of Slices
Definition
A numerical procedure for analyzing the stability of slopes with circular failure surfaces by dividing the sliding mass into vertical slices and applying force or moment equilibrium to each slice.
Importance
The standard method for complex slope problems in practice and occasionally tested in board exams with 2-3 slices.
Term
Critical Circle
Definition
The circular failure arc among all trial arcs that produces the minimum factor of safety. This is the design-governing failure surface.
Importance
Must always search for the minimum FS — analyzing just one circle is a common and dangerous mistake.
Term
Bishop's Simplified Method
Definition
An iterative method of slices that satisfies moment equilibrium and vertical force equilibrium for each slice, accounting for horizontal inter-slice forces. More accurate than the Fellenius method.
Importance
Preferred method in professional practice; occasionally appears in advanced board problems.
Section Title
3. Finite Slope Analysis — Method of Slices and Taylor's Chart
Common Mistakes
- Using only one trial circle and reporting that FS — always the minimum governs.
- Forgetting to include pore pressure (u) when computing effective normal force N' in the slices method.
- Treating N_s as having units — it is dimensionless; H_cr = c/(γ N_s) gives meters only when c is in kPa and γ in kN/m³.
- Applying Taylor's chart results for φ = 0 (pure clay) to a c-φ soil without checking the correct φ curve.
Exam Tips
- Board exam questions often ask: 'Which improvement method is best for soft clay?' — Answer: Preloading with PVDs (wick drains) or stone columns.
- For liquefaction mitigation in saturated loose sand: vibroflotation, stone columns, or dynamic compaction.
- For existing slope stabilization: soil nailing, drainage (interceptor drains), or reinforced retaining wall.
- Know the drainage path shortening effect of PVDs: t_drain ∝ H² (Terzaghi), so halving the drainage path reduces time to 90% consolidation to one-quarter.
Key Points
- Soil improvement (or ground improvement) is used when the in-situ soil cannot meet strength, stiffness, or compressibility requirements for the intended structure.
- Four broad categories: Densification, Consolidation Acceleration, Reinforcement, and Stabilization.
- Selection depends on soil type: densification works well for sands; preloading and vertical drains work for soft clays; grouting for fissured rock or loose sand.
- In the Philippines, soft marine clay deposits underlie much of Metro Manila, Pampanga, and coastal cities — preloading with vertical drains is a common solution.
- Geosynthetics (geogrids, geotextiles) are widely used in road embankments over soft ground.
- Soil nailing is common for highway cut slopes in rock and stiff soil (e.g., NLEX, SCTEX slopes).
- Dewatering (wellpoints, deep wells) temporarily improves slope stability by lowering the phreatic surface.
- Lime and cement stabilization are used for subgrade improvement in road construction — relevant to Philippine road projects.
Definitions
Term
Densification
Definition
Methods that reduce void ratio and increase soil density by mechanical energy or vibration. Includes surface compaction, vibroflotation (for deep sands), dynamic compaction (dropping heavy weights), and stone columns.
Importance
Increases bearing capacity and reduces settlement; used for loose sand and fill materials.
Term
Preloading with Prefabricated Vertical Drains (PVDs)
Definition
A surcharge load (preload) is applied to compress soft clay while PVDs (wick drains) reduce the drainage path length from H (layer thickness) to 0.5 × drain spacing, dramatically accelerating consolidation.
Importance
Primary method for improving soft compressible clays — reduces long-term settlement and increases undrained strength before construction.
Term
Geosynthetics
Definition
Polymeric materials (geogrids, geotextiles, geomembranes) installed within or between soil layers to provide tensile reinforcement, separation, filtration, or drainage.
Importance
Cost-effective reinforcement for embankments over soft ground and retaining walls; geogrids are used in mechanically stabilized earth (MSE) walls.
Term
Soil Nailing
Definition
Steel bars (nails) installed in a regular pattern into an existing slope or excavation face, then covered with shotcrete facing. The nails reinforce the soil in tension and shear.
Importance
Used for stabilizing existing cuts and excavations; rapid installation; common in Philippine highway projects.
Term
Grouting
Definition
Injection of cementitious, chemical, or bituminous grout under pressure to fill voids, fissures, or pores in soil or rock, increasing strength and reducing permeability.
Importance
Used for rock foundation treatment, underpinning, and seepage cutoff in dams.
Term
Lime/Cement Stabilization
Definition
Mixing lime (CaO or Ca(OH)₂) or Portland cement into clay soil to cause pozzolanic reactions that increase strength and reduce plasticity and swell potential.
Importance
Widely used for subgrade stabilization in road construction; alters soil classification from expansive to non-expansive.
Term
Vibroflotation
Definition
A vibrating probe is jetted into loose sand to depths up to 30 m; vibration densifies the surrounding sand. The resulting densified columns (stone columns if backfilled with gravel) also carry load.
Importance
Effective for deep loose sand deposits — reduces liquefaction potential, a critical concern in Philippine seismic zones.
Term
Dynamic Compaction
Definition
A heavy tamper (8–36 tonnes) is repeatedly dropped from heights of 10–40 m onto the ground surface, generating high-energy stress waves that densify the soil below.
Importance
Rapid and cost-effective for large areas of loose fill, rubble, or collapsible soil.
Section Title
4. Soil Improvement Techniques
Common Mistakes
- Recommending vibroflotation for clay — it is effective only in clean sands and gravels; clay's low permeability prevents drainage during vibration.
- Confusing geotextile (fabric — for filtration/separation) with geogrid (grid — for reinforcement).
- Thinking preloading alone (without PVDs) is always practical — for thick clay layers, consolidation without drains may take decades.
- Forgetting that lime stabilization works by reducing plasticity (cation exchange) — it does not simply act as a cement binder.
Formulas
Example
FS = tan35°/tan28° = 0.7002/0.5317 = 1.317 ≈ 1.32. The slope is marginally stable — acceptable for temporary condition but borderline for permanent design.
Formula
FS = tan φ' / tan β
Variables
φ' = effective friction angle; β = slope angle.
Application
Exercise 1: Dry sand slope, φ' = 35°, β = 28°.
Example
γz = 76 kPa. cos²30° = 0.75. tan25° = 0.4663. Numerator = 15 + 76(0.75)(0.4663) = 15 + 26.58 = 41.58 kPa. Denominator = 76 × sin30° × cos30° = 76 × 0.5 × 0.8660 = 32.91 kPa. FS = 41.58/32.91 = 1.26. Marginal — consider drainage improvement.
Formula
FS = [c' + γz cos²β tan φ'] / (γz sinβ cosβ)
Variables
c' = 15 kPa, φ' = 25°, γ = 19 kN/m³, z = 4 m, β = 30°.
Application
Exercise 2: Cohesive infinite slope, no seepage.
Example
c_req = 1.5 × 18 × 12 × 0.05 = 16.2 kPa. The soil must have at least 16.2 kPa of cohesion to maintain FS = 1.5 at 12 m height.
Formula
c_req = FS × γ × H × N_s
Variables
FS = 1.5; γ = 18 kN/m³; H = 12 m; N_s = 0.05.
Application
Exercise 3: Required cohesion for H = 12 m slope at FS = 1.5.
Exam Tips
- In the PRC board exam, multiple-choice answers are spaced close together — rounding errors can lead to a wrong answer. Maintain precision throughout.
- If two answers look very close, re-examine whether you used cos²β or cosβ — this is the most common single-point error in this topic.
- Time management: infinite slope problems should take 3-5 minutes; Taylor problems 2-4 minutes; slice problems may take 8-12 minutes — budget accordingly.
Key Points
- Always identify the slope type first (infinite or finite), soil type (c=0, φ=0, or c-φ), and drainage condition (drained or undrained).
- Extract given values carefully: note units (kPa vs kN/m², degrees vs radians).
- Write the governing formula, substitute, and compute — show all intermediate steps for partial credit.
- Verify that the computed FS is reasonable: FS between 1.0 and 3.0 is typical; outside this range, recheck.
Section Title
5. Worked Board-Exam Problems
Common Mistakes
- In Exercise 2, using cos30° instead of cos²30° = (cos30°)² = (0.866)² = 0.750 — a single-step error that changes the entire answer.
- In Exercise 3, applying the formula as H_cr = c/(γ N_s) and forgetting that H_cr is the height at FS=1; for FS=1.5, multiply N_s by FS in the denominator or divide H_cr by FS.
- Rounding intermediate values too aggressively — carry at least 4 significant figures through the calculation.
Connections
- Mohr-Coulomb Failure Criterion (Shear Strength chapter): FS in slope stability uses τ_f = c' + σ'tanφ' directly — mastery of shear strength parameters is prerequisite to all FS calculations.
- Terzaghi's Consolidation Theory (Consolidation chapter): Preloading with PVDs is effective precisely because T_v ∝ H_dr²; PVDs reduce H_dr and thus dramatically reduce time for a given degree of consolidation.
- Pore Pressure and Effective Stress (Permeability chapter): Seepage effects in infinite slopes and the u term in slice methods directly use pore pressure concepts — u = γ_w × h_w.
- Soil Classification (Index Properties chapter): USCS classification determines which improvement method is appropriate (e.g., vibroflotation for SP/SW; preloading+PVDs for CH/MH).
- Retaining Walls (Foundation Engineering chapter): Mechanically Stabilized Earth (MSE) walls use geosynthetic reinforcement — a soil improvement application — and their stability analysis uses principles similar to slope stability.
- Seismicity (Earthquake Engineering chapter): Philippine seismic zones (per NSCP 2015 Table 208-3) influence the required FS — seismic loading reduces FS, and liquefaction (a slope failure mode) is addressed by densification techniques like vibroflotation.
- Compaction (Earthwork chapter): Surface compaction principles underlie the densification category of soil improvement; relative compaction (RC = γ_d,field / γ_d,max × 100%) is specified in DPWH road standards.
- Earth Pressure (Retaining Structures chapter): Slope stability and lateral earth pressure both use the same Mohr-Coulomb strength envelope — the failure wedge concept in Rankine/Coulomb theory is related to the infinite slope plane failure mechanism.
Exam Strategy
Slope Stability appears in the Geotechnical Engineering portion of the PRC Civil Engineer board exam, which typically comprises 20-25% of the total exam. Expect 3-6 questions per exam cycle on this topic. Prioritize mastery in this order: (1) Infinite slope — dry cohesionless formula (fastest to compute, highest frequency); (2) Taylor's stability number — given N_s, solve for H_cr or required cohesion; (3) Cohesive infinite slope with and without seepage; (4) Method of slices — likely only 2-3 slices if tested; (5) Soil improvement identification (conceptual/qualitative). For numerical problems: write the formula first, then substitute — this earns partial credit even if arithmetic is wrong. Watch your trigonometric identities: cos²β = (cosβ)², not cos(2β). For soil improvement questions, remember the soil type–method pairing: sand → vibroflotation/dynamic compaction; soft clay → preloading+PVDs or stone columns; existing slope → soil nailing or drainage. Review at minimum the three worked examples from the reference module and practice all four exercises. Allocate 5-8 minutes per numerical problem during the actual exam.
Quick Review Questions
A dry sandy slope has φ' = 30° and β = 30°. What is the factor of safety and what does this indicate?
For cohesionless dry soil, FS = tanφ'/tanβ. When β = φ', tanβ = tanφ', so FS = 1.0. Any disturbance (vibration, seepage) will cause failure. This is exactly why slopes in dry sand should never be inclined at or near the friction angle.
A 5-m deep failure plane exists in a slope (β = 20°) with c' = 12 kPa, φ' = 22°, γ = 18 kN/m³, no seepage. Calculate FS.
Step 1: γz = 18×5 = 90 kPa. Step 2: cos²20° = (0.9397)² = 0.8830. Step 3: tan22° = 0.4040. Step 4: sin20°cos20° = 0.3420×0.9397 = 0.3214. Numerator = 12 + 90(0.8830)(0.4040) = 12 + 32.12 = 44.12. Denominator = 90(0.3214) = 28.93. FS = 1.52. Acceptable for permanent slope.
Using Taylor's chart, N_s = 0.055 for a slope with c = 25 kPa and γ = 19 kN/m³. Find H_cr and the safe height at FS = 1.4.
H_cr = c/(γ N_s) at FS = 1.0. For a given FS: H_design = H_cr/FS = c/(γ N_s FS). Substituting: H_design = 25/(19 × 0.055 × 1.4) = 25/1.463 = 17.1 m.
A seepage-saturated cohesionless slope has γ_sat = 20 kN/m³, γ' = 10 kN/m³, φ' = 35°, β = 25°. Find FS with full parallel seepage.
With full seepage (phreatic surface at slope face, flow parallel to slope), the infinite slope formula for c'=0 reduces to FS = (γ'/γ_sat)(tanφ'/tanβ). Since γ'/γ_sat ≈ 0.5 for most soils, the FS is roughly halved compared to the dry case (dry FS = 1.502). FS = 0.75 < 1.0 means failure — a classic typhoon-induced landslide scenario.
What is the critical height for a vertical cut (β = 90°) in undrained clay with c_u = 30 kPa and γ = 17 kN/m³?
For a vertical unsupported cut in purely cohesive soil (φ = 0, undrained condition), Terzaghi's approximation gives H_cr = 4c_u/γ. This comes from N_s ≈ 0.261 for a 90° cut with φ = 0 from Taylor's chart: H_cr = c/(γ N_s) = 30/(17 × 0.261) = 6.76 m (chart-based) vs. 7.06 m (simplified formula). Both are acceptable in board exams.
Which ground improvement method is most appropriate for a 10-m thick deposit of soft marine clay underlying a proposed highway embankment? Why?
Soft marine clay has high compressibility and low permeability. Without treatment, it would consolidate slowly over decades under the embankment load, causing unacceptable long-term settlements. PVDs shorten the drainage path from 10 m (two-way drainage: 5 m) to approximately 0.5–1.0 m (half the drain spacing), reducing consolidation time from decades to months. A surcharge preload exceeding the final embankment load is applied first to pre-compress the clay, then removed, leaving a stronger and denser foundation.
A method-of-slices analysis gives ΣWsinα = 850 kN/m and the total resisting force Σ(c'ℓ + N'tanφ') = 1,190 kN/m. Find FS and state if it meets the design target for a permanent slope.
FS = Resisting/Driving = 1190/850 = 1.40. Philippine design practice (consistent with NSCP and international geotechnical guidelines) requires FS ≥ 1.5 for permanent slopes. FS = 1.40 < 1.50, so remediation is needed — options include flattening the slope, adding a retaining structure, installing drainage, or using soil reinforcement.
Why is vibroflotation NOT effective for improving soft clay deposits?
Vibroflotation works by liquefying and then re-densifying granular soil (sand and gravel with k > 10⁻⁴ m/s) around the vibrating probe. The process requires rapid dissipation of excess pore pressure. Clay particles are fine-grained and nearly impermeable; vibration simply remolds the clay without densification. For soft clay, the correct methods are preloading with PVDs, stone columns (which provide vertical drainage AND load transfer), or lime/cement stabilization.
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