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CELE Geotechnical EngineeringBearing Capacity of SoilsRevision Notes

Condensed revision notes for Bearing Capacity of Soils, built for the final weeks before the CELE 2026. These are the distilled key points you need when there is no time left for full study notes — just the concepts, formulas, and traps Professional Regulation Commission (PRC) — Board of Civil Engineering tests.

Exam context

The Civil Engineer Licensure Examination is conducted by Professional Regulation Commission (PRC) — Board of Civil Engineering and is scheduled for May and November 2026. The Geotechnical Engineering subtest is marked as "Core" in the official pattern, and Bearing Capacity of Soils appears in position 9th of 11 in the CELE Geotechnical Engineering review rotation. Passing mark: 70% weighted average, no sub-test below 50%. Recent CELE 2026 papers have drawn roughly a meaningful share of questions from this subject.

Bearing Capacity of Soils - Revision Notes

Bearing capacity is one of the most heavily tested topics in the PRC Civil Engineer Licensure Examination under Geotechnical Engineering. A footing transmits structural loads to the soil below; if the applied contact pressure exceeds the soil's resistance, a shear failure occurs — the footing punches or tilts into the ground. The ultimate bearing capacity (q_u) is the maximum pressure the soil can sustain before shear failure, while the allowable bearing capacity (q_a) is q_u reduced by a factor of safety (FS = 2.5 to 3). Mastery of Terzaghi's equation, the three bearing-capacity factors, shape corrections, the water-table correction, and the net versus gross distinction is essential for exam success.

Sections

Exam Tips

  • If the problem says 'dense sand' or 'stiff clay' → general shear, use full c and φ.
  • If the problem says 'loose sand' or 'soft to medium clay' → local shear, replace c with (2/3)c and tan φ with (2/3) tan φ.
  • Punching shear is rarely tested numerically; focus on identifying the mode conceptually.

Key Points

  • Bearing capacity failure is a shear failure in the soil mass beneath the footing — the soil cannot resist the applied contact pressure.
  • Three classical failure modes: (1) General Shear Failure — dense/stiff soils, well-defined slip surface, sudden collapse; (2) Local Shear Failure — medium-density soils, significant compression before collapse, less defined slip surface; (3) Punching Shear Failure — loose/soft soils, vertical shearing around the perimeter, no heave observed.
  • Shallow footing condition: embedment depth D_f ≤ B (width) — Terzaghi's classical assumption.
  • Deep footings (D_f > B) require Meyerhof or Hansen equations — outside standard Terzaghi scope.
  • The contact pressure q at the base of the footing equals Q / A (applied column load divided by footing area) for a centrically loaded footing.

Definitions

Term

Ultimate Bearing Capacity (q_u)

Definition

The maximum unit pressure (kPa) that the soil beneath a footing can sustain before general shear failure occurs.

Importance

This is the baseline from which the allowable bearing capacity is derived; every bearing-capacity problem begins with computing q_u.

Term

Allowable Bearing Capacity (q_a)

Definition

q_a = q_u / FS, where FS is the factor of safety (typically 2.5 to 3 for foundations). It is the design pressure limit applied to prevent shear failure.

Importance

This is the value compared against the actual contact pressure to determine if the footing size is adequate.

Term

Net Allowable Bearing Capacity (q_a,net)

Definition

q_a,net = (q_u − γ·D_f) / FS — the gross ultimate capacity minus the overburden pressure at the footing base, then divided by FS.

Importance

Used when computing the allowable column load, because the soil at depth D_f was already supporting the weight of soil above the footing level before the footing was placed.

Term

Surcharge Pressure (q)

Definition

q = γ·D_f — the effective overburden stress at the footing base level due to soil above the foundation.

Importance

This term directly appears in the N_q component of Terzaghi's equation; omitting it is the single most common board-exam error.

Term

General Shear Failure

Definition

Failure mode in dense sand or stiff clay where a well-defined continuous failure surface extends from the footing edge to the ground surface, often causing visible heaving on both sides.

Importance

Terzaghi's standard bearing-capacity factors (N_c, N_q, N_γ) apply to this mode.

Term

Local Shear Failure

Definition

Failure in medium-density or loose soils where significant compression occurs before failure; the slip surface does not reach the ground surface. Terzaghi accounted for this by reducing c and tan φ to 2/3 of their actual values.

Importance

When the problem states loose sand or medium clay, use reduced c' = (2/3)c and tan φ' = (2/3) tan φ before reading the bearing-capacity factors.

Section Title

1. Fundamental Concepts and Failure Modes

Common Mistakes

  • Forgetting to classify the failure mode before applying formulas — dense soils use full c and φ; loose soils use reduced values (2/3 reduction).
  • Confusing shallow and deep footing criteria — Terzaghi is valid only for D_f ≤ B.
  • Using the wrong failure mode chart when the problem does not explicitly state 'general shear' or 'local shear.'

Formulas

Example

c=15 kPa, φ=25°, γ=18 kN/m³, B=2 m, D_f=1 m, N_c=25.13, N_q=12.72, N_γ=8.34 → q=18(1)=18 kPa; q_u=15(25.13)+18(12.72)+0.5(18)(2)(8.34)=376.95+228.96+150.12=756.0 kPa

Formula

q_u = cN_c + qN_q + (1/2)γBN_γ

Variables

c = cohesion (kPa); N_c, N_q, N_γ = dimensionless bearing-capacity factors (functions of φ); q = γD_f = surcharge at footing base (kPa); γ = unit weight of soil (kN/m³); B = footing width (m)

Application

Strip (continuous) footing — general shear failure condition

Example

c_u=50 kPa, φ=0, B=2 m, D_f=1 m, γ=18 kN/m³ → q_u=1.3(50)(5.7)+18(1)+0=370.5+18=388.5 kPa

Formula

q_u = 1.3cN_c + qN_q + 0.4γBN_γ

Variables

Same as strip footing; shape factor 1.3 applies to cohesion term; 0.4 applies to width term in place of 0.5

Application

Square footing — general shear failure condition

Example

c=20 kPa, φ=20°, B=1.5 m, D_f=1 m, γ=17 kN/m³, N_c=17.69, N_q=7.44, N_γ=3.64 → q_u=1.3(20)(17.69)+17(7.44)+0.3(17)(1.5)(3.64)=460+126.5+27.9=614.4 kPa

Formula

q_u = 1.3cN_c + qN_q + 0.3γBN_γ

Variables

Same as strip; shape factor 0.3 on the width term replaces 0.5 (strip) or 0.4 (square)

Application

Circular footing (B = diameter) — general shear failure condition

Example

q_u=756 kPa, FS=3 → q_a=252 kPa

Formula

q_a = q_u / FS

Variables

q_a = gross allowable bearing capacity (kPa); FS = factor of safety (2.5 to 3, typically 3 in Philippine practice)

Application

Gross allowable bearing capacity — conservative approach for routine design

Example

q_u=388.5 kPa, γD_f=18 kPa, FS=3 → q_a,net=(388.5−18)/3=370.5/3=123.5 kPa; A=2×2=4 m² → Q_a=123.5(4)=494 kN

Formula

q_a,net = (q_u − γD_f) / FS

Variables

q_a,net = net allowable bearing capacity (kPa); γD_f = existing overburden stress at footing base level

Application

Net allowable bearing capacity — used to compute the allowable column load Q_a = q_a,net × A

Example

c=15 kPa, φ=28° → c'=10 kPa; tan φ'=(2/3)tan 28°=0.3535 → φ'=19.47° (≈19.5°); then use N_c, N_q, N_γ at φ'=19.5°

Formula

Local shear: c' = (2/3)c; tan φ' = (2/3)tan φ

Variables

c' = reduced cohesion for local shear (kPa); φ' = reduced friction angle for local shear (°); c = actual cohesion; φ = actual friction angle

Application

Applied when soil is loose sand or medium-dense soil subject to local shear failure before reading N_c, N_q, N_γ from tables

Exam Tips

  • Memorize the shape coefficient table: strip=(1.0, 1.0, 0.5); square=(1.3, 1.0, 0.4); circular=(1.3, 1.0, 0.3).
  • For φ=0 problems: write q_u=5.7c+q (strip) or 7.41c+q (square) directly — saves time.
  • Always write q=γD_f as your first step; it prevents the most common error of forgetting the surcharge term.
  • When the problem asks for 'allowable column load', use Q_a = q_a,net × B² (square) or q_a,net × A (rectangular).
  • Bearing-capacity factors are given in all board exam problem stems or supplementary tables — you do not need to memorize exact values for every angle, but memorize φ=0 values (5.7, 1, 0) and know the trend.

Key Points

  • Terzaghi (1943) derived the first rational bearing-capacity equation for shallow continuous (strip) footings, later extended to square and circular shapes.
  • The equation has three terms: cohesion term (cN_c), surcharge/overburden term (qN_q), and self-weight/width term (½γBN_γ).
  • Strip footing: q_u = cN_c + qN_q + ½γBN_γ
  • Square footing: q_u = 1.3cN_c + qN_q + 0.4γBN_γ
  • Circular footing (diameter B): q_u = 1.3cN_c + qN_q + 0.3γBN_γ
  • For purely cohesive soil (φ = 0): N_c = 5.7, N_q = 1, N_γ = 0; so q_u = 5.7c + q (strip) or q_u = 1.3(5.7)c + q = 7.41c + q (square).
  • For sand (c = 0): q_u = qN_q + ½γBN_γ (strip), with the cohesion term vanishing completely.

Definitions

Term

Bearing-Capacity Factor N_c

Definition

Dimensionless factor relating cohesion to bearing capacity. For φ=0: N_c=5.7 (Terzaghi). For φ>0, N_c increases rapidly. At φ=30°: N_c≈37.16; at φ=25°: N_c≈25.13.

Importance

Multiplied directly by cohesion c — the primary term for clay soils.

Term

Bearing-Capacity Factor N_q

Definition

Dimensionless factor relating surcharge (overburden) to bearing capacity. For φ=0: N_q=1. At φ=25°: N_q=12.72; at φ=30°: N_q=22.46.

Importance

Multiplied by q=γD_f — this is why embedment depth D_f increases bearing capacity; deeper footings gain capacity.

Term

Bearing-Capacity Factor N_γ

Definition

Dimensionless factor relating soil weight and footing width to bearing capacity. For φ=0: N_γ=0. At φ=25°: N_γ=8.34; at φ=30°: N_γ=19.13.

Importance

Multiplied by ½γB (or 0.4γB for square, 0.3γB for circular) — wider footings gain capacity; for φ=0 clay this term vanishes entirely.

Section Title

2. Terzaghi's Bearing Capacity Equation

Common Mistakes

  • Using 0.5 (strip coefficient) instead of 0.4 (square) or 0.3 (circular) on the γBN_γ term.
  • Forgetting to multiply by 1.3 on the cN_c term for square and circular footings.
  • For φ=0 clay, leaving N_γ=0 but still multiplying by 0.4 or 0.3 — result is still zero, but students sometimes apply 1.3 to the wrong term.
  • Computing q_u then reporting it as the allowable load without dividing by FS.
  • Omitting the surcharge term qN_q entirely when D_f is given.

Exam Tips

  • φ=0 values (5.7, 1, 0) must be memorized — they appear in virtually every clay problem.
  • The ratio N_q/N_c ≈ 0.5 at φ=0 and increases with φ — use as a quick sanity check.
  • If factors are not given and φ is given, the problem will provide them in the given data section.

Key Points

  • N_c, N_q, and N_γ are tabulated functions of the internal friction angle φ; they increase as φ increases.
  • At φ=0°: N_c=5.7, N_q=1.0, N_γ=0.0 (Terzaghi values for saturated clay).
  • At φ=10°: N_c≈9.61, N_q≈2.69, N_γ≈1.22.
  • At φ=20°: N_c≈17.69, N_q≈7.44, N_γ≈3.64.
  • At φ=25°: N_c≈25.13, N_q≈12.72, N_γ≈8.34.
  • At φ=30°: N_c≈37.16, N_q≈22.46, N_γ≈19.13.
  • At φ=35°: N_c≈57.75, N_q≈41.39, N_γ≈42.92.
  • The exponential growth of N_q and N_γ with φ explains why dense, highly frictional soils (gravels, dense sands) have dramatically higher bearing capacity.
  • Board exam problems always provide the required N values in the problem statement — focus on correctly applying them, not deriving them.

Section Title

3. Bearing-Capacity Factors — Reference Table

Common Mistakes

  • Interpolating incorrectly between table values — always use the values given in the problem.
  • Using Meyerhof N factors (different values) when the problem specifies Terzaghi — always check which formulation is specified.

Formulas

Example

γ_sat=20 kN/m³ → γ'=20−9.81=10.19 kN/m³; width term becomes ½(10.19)(2)(8.34)=85.0 kPa instead of ½(20)(2)(8.34)=166.8 kPa — a significant reduction

Formula

γ' = γ_sat − γ_w

Variables

γ' = effective (submerged) unit weight (kN/m³); γ_sat = saturated unit weight (kN/m³); γ_w = unit weight of water = 9.81 kN/m³

Application

Used in the ½γBN_γ term when the water table is at or above the footing base

Example

d_w=1 m, B=2 m, γ'=10 kN/m³, γ_moist=18 kN/m³ → γ_eff=10+(1/2)(18−10)=10+4=14 kN/m³

Formula

γ_eff = γ' + (d_w / B)(γ_moist − γ')

Variables

γ_eff = effective unit weight for width term (kN/m³); d_w = depth of water table below footing base (m); B = footing width (m); γ_moist = moist unit weight above water table (kN/m³)

Application

Case 2 interpolation when 0 < d_w ≤ B

Exam Tips

  • Draw a quick sketch of the footing and water table position before selecting the correction case.
  • Always compare d_w (depth to WT below footing base) with B to identify Case 2 or Case 3.
  • If WT is exactly at the footing base, use γ' in the width term and γ_moist·D_f for the surcharge.
  • A quick memory hook: 'Below the base, within B — interpolate; beyond B — ignore.'

Key Points

  • Groundwater reduces the effective unit weight of soil, thereby reducing the bearing capacity.
  • Case 1 — Water table at or above the footing base (d_w ≤ D_f): The surcharge q in the N_q term uses the moist/saturated unit weight above the water table; the width term ½γBN_γ uses the effective (submerged) unit weight γ' = γ_sat − γ_w.
  • Case 2 — Water table within depth B below the footing base (0 < d_w ≤ B): Linear interpolation applies; the effective unit weight in the width term is adjusted proportionally: γ_eff = γ' + (d_w/B)(γ − γ'). For d_w=0 use γ'; for d_w=B use γ (moist).
  • Case 3 — Water table deeper than B below the footing base: No correction required; use the moist unit weight γ throughout.
  • Typical values: γ_w = 9.81 kN/m³; γ' = γ_sat − γ_w (commonly 8–11 kN/m³ for typical saturated soils).
  • The N_q surcharge term is also affected when the water table is above the footing base — use effective stress in q = γD_f when fully submerged above the base.

Definitions

Term

Effective (Submerged) Unit Weight (γ')

Definition

γ' = γ_sat − γ_w. The net unit weight of saturated soil accounting for buoyancy. Typically ranges from 8 to 11 kN/m³.

Importance

Governs the magnitude of the self-weight term in bearing-capacity calculations when the soil below the footing is submerged.

Section Title

4. Water-Table Correction

Common Mistakes

  • Applying γ' to the surcharge term q=γD_f when the water table is below the footing base — the surcharge uses moist unit weight above the table.
  • Using γ_sat instead of γ' in the width term when water table is at the footing base.
  • Forgetting that Case 3 (water table > B below base) requires no correction at all.
  • Using γ_w = 10 kN/m³ instead of 9.81 kN/m³ — use 9.81 unless the problem specifies otherwise.

Formulas

Example

q_a,net=123.5 kPa, B=2 m square footing → A=4 m² → Q_a=123.5×4=494 kN

Formula

Q_a = q_a,net × A

Variables

Q_a = allowable column load (kN); q_a,net = net allowable bearing capacity (kPa); A = base area of footing (m²)

Application

Determining the maximum structural load the footing can support without shear failure

Exam Tips

  • When a problem asks for 'allowable column load', always use the NET allowable approach: Q_a = [(q_u − γD_f)/FS] × A.
  • If FS is not stated, use FS=3 as the default Philippine practice value.
  • Remember: q_a,net × A gives the load the SOIL can support from the COLUMN; footing self-weight is additional.

Key Points

  • The factor of safety for bearing capacity is typically FS = 3 for permanent structures; FS = 2.5 may be used with careful site investigation.
  • Gross allowable: q_a = q_u / FS — compared against the total contact pressure including the weight of footing and overburden.
  • Net allowable: q_a,net = (q_u − γD_f) / FS — represents the net additional pressure the footing imposes on the soil beyond the original overburden.
  • Allowable column load: Q_a = q_a,net × A_footing.
  • Settlement governs design in many cases — particularly for normally consolidated clays and loose sands — even when the shear bearing capacity is sufficient.
  • The PRC exam may ask you to check both bearing capacity (shear failure) and settlement separately; settlement calculations use consolidation theory (covered in a separate chapter).
  • In Philippine practice, the NSCP 2015 Section 304 provides prescriptive allowable bearing pressures for common soil types as a starting point for design, but computed q_a governs for actual design.

Definitions

Term

Factor of Safety (FS) for Bearing Capacity

Definition

FS = q_u / q_applied (gross) or FS = (q_u − γD_f) / (q_net applied). Recommended values: FS=3 for permanent buildings, FS=2 for temporary structures.

Importance

Accounts for load uncertainties, variability in soil properties, and consequences of failure. A lower FS must be justified by thorough site investigation.

Term

Settlement-Governed Design

Definition

When the computed allowable bearing capacity from shear analysis is higher than the bearing pressure that would cause excessive settlement, the latter governs. This is common in soft clays and loose sands.

Importance

Reminds the designer that bearing capacity is not the only criterion — deformation serviceability must also be checked.

Section Title

5. Allowable Bearing Capacity and Settlement Consideration

Common Mistakes

  • Applying FS directly to q_u to get allowable load without subtracting overburden first (net vs. gross distinction).
  • Forgetting that Q_a is the column load only — the weight of the footing itself must be added when checking soil pressure if required.
  • Not considering settlement when the problem states soft clay or loose sand conditions.

Formulas

Example

Step 1: q=γD_f=18(1)=18 kPa. Step 2: q_u=cN_c+qN_q+½γBN_γ=15(25.13)+18(12.72)+0.5(18)(2)(8.34)=376.95+228.96+150.12=756.0 kPa. Step 3: q_a=756.0/3=252.0 kPa. Answer: q_u=756.0 kPa; q_a=252.0 kPa.

Formula

EXAMPLE A — Strip footing on c-φ soil

Variables

Given: B=2 m, D_f=1 m, c=15 kPa, φ=25°, γ=18 kN/m³, N_c=25.13, N_q=12.72, N_γ=8.34, FS=3

Application

Find q_u and q_a for a strip footing (general shear)

Example

Step 1: q=18(1)=18 kPa. Step 2: q_u=1.3cN_c+qN_q+0=1.3(50)(5.7)+18(1)=370.5+18=388.5 kPa. Step 3: q_u,net=388.5−18=370.5 kPa. Answer: q_u=388.5 kPa; q_u,net=370.5 kPa.

Formula

EXAMPLE B — Square footing on saturated clay (φ=0)

Variables

Given: B=2 m (square), D_f=1 m, c_u=50 kPa, φ=0, γ=18 kN/m³, N_c=5.7, N_q=1, N_γ=0

Application

Find q_u and net ultimate capacity

Example

Step 1: q_a,net=q_u,net/FS=370.5/3=123.5 kPa. Step 2: A=2×2=4 m². Step 3: Q_a=q_a,net×A=123.5×4=494 kN. Answer: Q_a=494 kN.

Formula

EXAMPLE C — Allowable column load

Variables

Using Example B data with FS=3

Application

Find the allowable column load Q_a

Example

Step 1: q=γD_f=18(1)=18 kPa (moist soil above WT, no change). Step 2: γ'=20−9.81=10.19 kN/m³. Step 3: q_u=15(25.13)+18(12.72)+0.5(10.19)(2)(8.34)=376.95+228.96+84.98=690.9 kPa. Step 4: q_a=690.9/3=230.3 kPa. Comparison: Without WT correction q_a=252 kPa; with WT correction q_a=230.3 kPa — a 9% reduction. Answer: q_u=690.9 kPa; q_a=230.3 kPa.

Formula

EXAMPLE D — Strip footing with water table at base

Variables

Given: B=2 m, D_f=1 m, c=15 kPa, φ=25°, γ=18 kN/m³ (moist), γ_sat=20 kN/m³, γ_w=9.81 kN/m³, N_c=25.13, N_q=12.72, N_γ=8.34, FS=3

Application

Water table at the footing base — use γ' in the width term only

Exam Tips

  • On the board exam, write the formula first, substitute values, then compute — partial credit is awarded for correct setup even if arithmetic errors occur.
  • Box your final answer with units (kPa for pressures, kN for loads).
  • Always state which footing shape (strip/square/circular) before writing the formula — it signals to the examiner you know the correct form.

Key Points

  • Example A: Strip footing, c-φ soil, general shear.
  • Example B: Square footing, purely cohesive clay (φ=0).
  • Example C: Square footing, net allowable load.
  • Example D: Strip footing with water table at base.

Section Title

6. Comprehensive Worked Examples (Board-Exam Style)

Common Mistakes

  • In Example D, applying γ' also to the surcharge term q=γD_f when the water table is exactly at the base (not above it) — the moist unit weight governs the surcharge in this case.
  • In Example C, multiplying q_a (gross) by area instead of q_a,net — overestimates the net column load capacity.

Connections

  • Soil Classification and Index Properties (earlier chapter): φ and c values that feed into bearing-capacity equations come from shear-strength tests (direct shear, triaxial) — the connection between index properties and shear strength is a prerequisite.
  • Effective Stress Principle: The water-table correction directly applies Terzaghi's effective stress principle (σ' = σ − u) — bearing capacity depends on effective stresses, not total stresses.
  • Shear Strength of Soils: Terzaghi's N_c, N_q, N_γ are derived from Mohr-Coulomb failure criterion (τ_f = c + σ'tan φ) — bearing capacity is simply a macroscopic manifestation of shear strength mobilization.
  • Consolidation and Settlement: After computing q_a from shear analysis, the engineer must also compute settlement (primary consolidation for clay, elastic settlement for sand) — settlement often governs the final allowable bearing pressure.
  • Foundation Design (NSCP 2015 Section 304): Code prescribes minimum embedment depths and references allowable bearing pressures — connects theoretical bearing capacity to code-compliant Philippine structural design.
  • Retaining Walls and Lateral Earth Pressure: Similar passive and active failure wedges underpin both lateral earth pressure (Rankine/Coulomb) and Terzaghi's bearing-capacity wedge — understanding one reinforces the other.
  • Pile Foundations: When shallow foundation bearing capacity is insufficient, pile foundations are used — end-bearing piles use similar N_q concepts applied at pile tip depth, creating a direct conceptual bridge.
  • RA 544 (Civil Engineering Law): Requires that all geotechnical investigations and foundation designs be signed and sealed by a licensed Civil Engineer — places the bearing-capacity calculation within the legal framework of professional responsibility.

Exam Strategy

In the PRC CE board examination, bearing capacity problems appear consistently in the Geotechnical Engineering section. Follow this systematic attack plan: (1) Identify footing geometry (strip/square/circular) and write the correct form of Terzaghi's equation immediately. (2) Compute q = γD_f as your very first numerical step — this prevents the most common error. (3) Apply the water-table correction if given (identify Case 1, 2, or 3 by comparing water-table depth to B). (4) Check for local vs. general shear (dense/stiff = general; loose/soft = local → apply 2/3 reduction). (5) Compute q_u by substituting the provided N values. (6) Apply FS to get q_a or q_a,net as required. (7) Multiply by area only if asked for column load Q_a. Time management: A standard bearing-capacity computation takes 4–6 minutes; allocate accordingly. Never leave a bearing-capacity question blank — even writing the correct equation with partial substitution earns partial credit. Memorize the φ=0 special case (N_c=5.7, N_q=1, N_γ=0) and the shape coefficient table (1.3/1.0/0.5 → 1.3/1.0/0.4 → 1.3/1.0/0.3 for strip/square/circular) — these appear in more than 60% of bearing-capacity board problems.

Quick Review Questions

What is the Terzaghi bearing capacity equation for a STRIP footing under general shear conditions?

The three terms represent the contributions of cohesion (cN_c), surcharge/overburden (qN_q where q=γD_f), and soil self-weight and width ((1/2)γBN_γ). All three terms must be included even if one dominates — omitting any term is a common exam error.

How do the shape coefficients change the Terzaghi equation for a SQUARE footing compared to a strip footing?

Shape factors for square/circular footings reflect the three-dimensional nature of failure — the failure surface is more complex than a simple two-dimensional wedge. The 1.3 factor increases cohesion contribution; 0.4 (square) or 0.3 (circular) reduces the width term slightly relative to strip (0.5).

What are the Terzaghi bearing-capacity factors for a purely cohesive soil (φ = 0)?

For saturated clay under undrained loading (φ=0), the frictional components vanish. N_γ=0 means the width term disappears entirely — the footing width has no effect on q_u for φ=0 clay. This simplifies the square footing equation to q_u = 1.3(5.7)c_u + q = 7.41c_u + γD_f.

A footing rests on loose sand. Which failure mode applies, and how is the Terzaghi equation modified?

Loose soils compress significantly before developing a full failure surface. Terzaghi's 2/3 reduction accounts for this by using mobilized (reduced) strength parameters instead of peak values. This always results in a lower q_u than general shear.

The water table is located exactly at the base of a footing. Which unit weight is used in each term of the Terzaghi equation?

The water table at the footing base means the soil above the base is not submerged (no buoyancy), so the full moist/saturated weight acts as surcharge. Below the footing base, the soil is submerged, so buoyancy reduces the effective weight — γ' must be used in the width term.

A 2.5 m square footing at D_f = 1.5 m is on clay with c_u = 75 kPa and γ = 18 kN/m³. Using FS = 3, find the allowable column load Q_a.

Step 1: q = 18(1.5) = 27 kPa. Step 2: q_u = 1.3(75)(5.7) + 27(1) + 0 = 555.75 + 27 = 582.75 kPa. Step 3: q_u,net = 582.75 − 27 = 555.75 kPa. Step 4: q_a,net = 555.75/3 = 185.25 kPa. Step 5: A = 2.5² = 6.25 m². Step 6: Q_a = 185.25 × 6.25 = 1,157.8 kN. Note: Some references use q_a=q_u/FS then subtract overburden for net; the net approach shown here is more rigorous.

Why does increasing the embedment depth D_f increase the bearing capacity?

The soil above the footing level acts as a surcharge that confines the failure wedge. Greater confinement means higher resistance to shear. This is why engineers often specify deeper footings on weaker soils — not just to avoid the weak surface layer, but to gain the confinement benefit.

What is the difference between gross allowable bearing capacity (q_a) and net allowable bearing capacity (q_a,net)?

Before the footing is placed, the soil at depth D_f already supports the weight of soil above it (=γD_f). The foundation only adds NET pressure beyond this. Using q_a,net to determine Q_a is therefore more accurate for computing the allowable structural load the footing can carry.

How does the water-table depth below the footing base affect the bearing capacity when the water table is within depth B?

When d_w = 0 (WT at base), γ_eff = γ' (fully submerged). When d_w = B (WT at depth B below base), γ_eff = γ_moist (no correction). Intermediate depths are linearly interpolated, reflecting the partial influence of groundwater on the failure zone beneath the footing.

A strip footing on sand (c=0) with B=1.5 m, D_f=1.2 m, φ=30°, γ=17 kN/m³, N_q=22.46, N_γ=19.13. Find q_u.

Since c=0: q_u = qN_q + ½γBN_γ. Step 1: q = 17(1.2) = 20.4 kPa. Step 2: qN_q = 20.4(22.46) = 458.2 kPa. Step 3: ½γBN_γ = 0.5(17)(1.5)(19.13) = 243.9 kPa. Step 4: q_u = 458.2 + 243.9 = 702.1 kPa. (Minor rounding differences depending on γ precision used.)

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