Memory AnchorsCELE · Engineering MechanicsReal content

CELE Engineering Mechanics — Frames, Machines and CablesMemory Anchors

Summary Concepts Notes Revision Deep Dive Slides Flashcards Mistakes Cheat Mnemonics Templates

Mnemonics for Frames, Machines and Cables in the CELE 2026. Every one of these anchors has been designed to help you recall the concept under the pressure of Professional Regulation Commission (PRC) — Board of Civil Engineering's CELE Engineering Mechanics exam conditions.

Exam context

For the Civil Engineer Licensure Examination, Professional Regulation Commission (PRC) — Board of Civil Engineering tests Engineering Mechanics under a "Core" label, with Frames, Machines and Cables in the 4th slot across 8 chapters. CELE candidates must clear the 70% weighted average, no sub-test below 50% cut on the 2026 paper, which draws about a meaningful share of Engineering Mechanics questions. Date to watch: May and November 2026.

Frames, Machines and Cables - Memory Anchors

Memory techniques transform passive reading into active recall. Research shows that vivid analogies, emotional micro-stories, and acronym chains improve long-term retention by up to 60% compared to rereading notes. For the PRC Civil Engineer Licensure Examination, where you must recall formulas and procedures under pressure, these anchors give your brain a 'mental hook' — a shortcut that retrieves the full concept in seconds. Each anchor here is tied to a specific board-exam concept in Frames, Machines, and Cables. Read each one, close your eyes, visualize it, then test yourself using the recall trigger. With repetition, recall becomes automatic — exactly what you need on exam day.

Anchors

Topic

Frames

Concept

Frames have multi-force members (not two-force like trusses)

Anchor Id

Difficulty

easy

Memory Aid

Think of a TRUSS as a Filipino 'bilao' tray with only bamboo sticks — each stick is pulled or pushed from both ends only (two-force). A FRAME is like a 'bahay-kubo' — the posts and beams are nailed together and carry loads from windows, walls, and people standing in the middle. The bahay-kubo posts bend and shear; the bilao sticks only stretch or compress. Multi-force = multi-load, like a busy bahay-kubo.

Anchor Type

analogy

Why It Works

Connecting abstract structural mechanics to a familiar Filipino dwelling makes the distinction visceral and easy to picture during exams.

Example Usage

When a problem says 'frame,' immediately think: 'bahay-kubo post — multi-force — I must dismember and apply full equilibrium, not just axial force.'

Recall Trigger

Picture a bahay-kubo vs a bilao tray of bamboo sticks.

Topic

Frames

Concept

Analysis procedure for frames: (1) External reactions, (2) Dismember, (3) Pin forces by equilibrium

Anchor Id

Difficulty

medium

Memory Aid

Remember the acronym E-D-P: 'Every Dismembered Part.' Step 1 = External reactions (whole frame FBD). Step 2 = Dismember (separate each member). Step 3 = Pin forces (apply ΣFx, ΣFy, ΣM to each part). 'Every Dismembered Part' — like dissecting a frog in NSCP lab — you always check the whole frog first, then cut it open, then analyze each organ.

Anchor Type

acronym

Why It Works

The acronym E-D-P gives a three-step ordered sequence. The frog dissection analogy reinforces the 'whole before parts' logic.

Example Usage

Exam question asks for pin force at C in a frame. Recall E-D-P: first find support reactions at A and B (whole frame), then dismember at pin C, then apply ΣM=0 on one member.

Recall Trigger

Say 'E-D-P' and picture cutting open a frog.

Topic

Frames

Concept

Newton's Third Law at pins — equal and opposite forces on the two members sharing a pin

Anchor Id

Difficulty

medium

Memory Aid

Imagine two engineering students arm-wrestling at a pin joint. If Student A pushes Student B's arm to the RIGHT with 50 N, then Student B is pushing Student A's arm to the LEFT with exactly 50 N. Neither can cheat — the pin forces must be equal and opposite on both FBDs. If you draw the force going right on member 1, it MUST go left on member 2. Forgetting this is the #1 frame mistake in board exams — 'the arm-wrestling rule.'

Anchor Type

micro_story

Why It Works

A competitive physical scenario creates an emotional memory. The arm-wrestling image makes Newton's Third Law concrete and hard to forget.

Example Usage

When drawing the dismembered FBDs, after assigning pin force direction on member AB, immediately flip the arrow for member BC — arm-wrestling rule.

Recall Trigger

Two students arm-wrestling at a pin.

Topic

Frames

Concept

Two-force member: force acts along the line connecting the two pin ends

Anchor Id

Difficulty

easy

Memory Aid

Visualize a tug-of-war rope — two teams pull from both ends. The rope (two-force member) can ONLY be pulled along its own length. No matter how hard you try, you cannot pull a tug-of-war rope sideways. A two-force member is that rope: force is always axial (along the member), never transverse. Spot it by checking: is it loaded ONLY at two pin ends, with no loads in between? If yes — it's a tug-of-war rope!

Anchor Type

visual_association

Why It Works

Tug-of-war is universally understood. The visual of a rope that can only transmit axial force is physically intuitive.

Example Usage

In a frame problem, scan members first. Find the strut with pins only at both ends and no intermediate loads — label it as two-force, draw the force along the member, and immediately reduce the unknowns from 2 to 1.

Recall Trigger

Tug-of-war rope — force only along its length.

Topic

Machines

Concept

Machines transmit or modify force — input effort produces amplified output load

Anchor Id

Difficulty

easy

Memory Aid

A machine is like a BOTE-OPENER (bottle opener) at a fiesta. You push down gently on the long handle (effort arm), and the short end under the bottle cap pops it open with a huge force (load arm). The machine doesn't create energy — it trades DISTANCE for FORCE. Long effort arm = big mechanical advantage = big output force. This is the essence of every machine problem: find the ratio of effort arm to load arm.

Anchor Type

analogy

Why It Works

The bottle opener is a familiar Filipino social tool. It perfectly illustrates the lever principle and mechanical advantage in a tactile, everyday context.

Example Usage

For a machine problem, identify the pivot, measure effort arm and load arm, then M.A. = effort arm / load arm. Load = Effort × M.A.

Recall Trigger

Fiesta bote-opener — long handle, big pop.

Topic

Machines

Concept

Mechanical Advantage formula: M.A. = effort arm / load arm

Anchor Id

Difficulty

easy

Memory Aid

Short rhyme to remember the formula: 'Effort over load? No — that's not right. Arm over arm gives you the might. Effort ARM on top, load ARM below — Multiply by effort, and watch the load grow!'

Anchor Type

rhyme

Why It Works

Rhymes engage the auditory memory system and are naturally repetitive. The correction in the first line prevents the common mistake of using forces instead of arms.

Example Usage

Exam problem: effort = 80 N, effort arm = 0.6 m, load arm = 0.04 m. Recall the rhyme: arm over arm → M.A. = 0.6/0.04 = 15. Load = 80 × 15 = 1200 N.

Recall Trigger

Recite the first line: 'Effort over load? No — that's not right.'

Topic

Cables

Concept

Cable carries only tension — no compression, no shear, no bending

Anchor Id

Difficulty

easy

Memory Aid

A cable is like a KULOG-AT-KIDLAT (thunder and lightning) safety guideline: it only works ONE WAY. A clothesline (sampayan) can only be pulled taut — it cannot push clothes apart, cannot twist, cannot bend itself. The moment you try to push a clothesline, it goes slack. A cable is always in TENSION, never anything else. If a calculated cable tension comes out negative, the cable is slack — physically impossible in the model.

Anchor Type

analogy

Why It Works

The clothesline/sampayan is a daily household object every Filipino student has used. The one-way behavior is instantly relatable.

Example Usage

Before solving any cable problem, write at the top: 'T > 0 always.' If your answer is negative, recheck your geometry or load direction.

Recall Trigger

Picture a sampayan (clothesline) — pull only, never push.

Topic

Cables

Concept

Horizontal component H is constant throughout a cable

Anchor Id

Difficulty

medium

Memory Aid

Imagine you are sending a 'tabo' sliding across a table on a string. No matter how steep or shallow the string's angle at any point, the horizontal pull at your end never changes — you always exert the same sideways tug. That steady horizontal pull IS the constant H. The vertical pull changes because the angle changes, but horizontal? Constant. Always. Even when the cable dips and rises under multiple loads, H stays the same from support to support.

Anchor Type

micro_story

Why It Works

The tabo-on-string mental image creates a tangible sense of the horizontal component being 'locked in.' The micro-story replaces an abstract equation with a physical intuition.

Example Usage

In a cable with three point loads, find H from one segment using ΣM=0 at a point, then use the same H to find tension in every other segment: T = H/cosθ.

Recall Trigger

Tabo sliding across a table — the horizontal tug never changes.

Topic

Cables

Concept

Parabolic cable formula: H = wL²/8d

Anchor Id

Difficulty

hard

Memory Aid

Remember the formula H = wL²/8d using the phrase: 'Weightlifter LOADS up at EIGHT Decks.' W = load per meter (w), L = span (L²), 8 = eight, d = sag/deck depth. Or use the visual: picture the number '8' lying on its side — that's the infinity symbol of a cable sagging under uniform load. The '8' is in the DENOMINATOR with d (sag). Bigger sag = lower H (less horizontal pull needed). Bigger span or load = higher H.

Anchor Type

mnemonic

Why It Works

The phrase encodes the order of variables. The visual of '8 on its side' connects the denominator to the cable's sinuous shape.

Example Usage

Cable spans 40 m, sag 4 m, w = 6 kN/m. Recall: H = wL²/8d = 6(40²)/[8(4)] = 6(1600)/32 = 9600/32 = 300 kN.

Recall Trigger

Say 'Weightlifter Loads at Eight Decks' → w, L², 8, d → H = wL²/8d.

Topic

Cables

Concept

Maximum tension in a parabolic cable occurs at the supports (steepest angle)

Anchor Id

A10

Difficulty

medium

Memory Aid

Visualize a roller-coaster track (like Enchanted Kingdom's Space Shuttle). The cable is steepest where it connects to the towers — like the steep climb of a roller coaster at the sides. At the bottom (midspan), the ride is flat and easy; at the towers, the slope is maximum and so is the tension. MAX TENSION = MAX ANGLE = AT THE SUPPORTS. Draw a smiley-face parabola and mark 'DANGER: MAX T' at both ends, 'CALM: H only' at the bottom.

Anchor Type

visual_association

Why It Works

Roller coasters are exciting and emotionally charged. The spatial mapping of steepness to tension creates a geometric memory that transfers directly to cable diagrams.

Example Usage

For T_max: always compute at the support. T_max = √(H² + (wL/2)²). The wL/2 term is the vertical reaction at each support for a symmetric parabolic cable.

Recall Trigger

Enchanted Kingdom roller coaster — steepest at the towers, calmest at the bottom.

Topic

Cables

Concept

Parabola vs Catenary: uniform horizontal load → parabola; uniform load along cable length → catenary

Anchor Id

A11

Difficulty

medium

Memory Aid

Think of two types of bridges in the Philippines: • SUSPENSION BRIDGE (like those in Samar or the Passi bridge) carries a road deck — the load is uniform PER HORIZONTAL METER of deck → PARABOLA. The bridge deck straightens the load horizontally. • A HANGING CHAIN (like a rosary or kwintas hung between two fingers) carries its own weight along its LENGTH → CATENARY. The chain follows its own arc. Memory: DECK = PARABOLA (D and P share the same 'engineering drawing' feel). CHAIN = CATENARY (both start with 'C-A').

Anchor Type

analogy

Why It Works

Filipino infrastructure examples ground the abstract math. The alliterative links (D-P, C-C) reinforce the pairing.

Example Usage

Problem says 'cable carries a uniformly distributed load of 5 kN/m along the horizontal.' Recall: horizontal load = deck = PARABOLA → use H = wL²/8d.

Recall Trigger

DECK → Parabola. CHAIN → Catenary. (D-P, C-C)

Topic

Cables

Concept

Cable with concentrated loads — cable is straight between load points (funicular polygon)

Anchor Id

A12

Difficulty

medium

Memory Aid

Picture a PAROL (Philippine Christmas lantern) being held by two strings from its tips, with ornament balls hanging from the middle joints. The strings between each ornament are perfectly straight — no curves. The entire cable shape looks like a series of straight sticks arranged in a V-shape or W-shape. This is the funicular polygon. 'Funicular' = rope-like. Between any two adjacent loads, the cable is a straight line because there is no distributed load to curve it.

Anchor Type

visual_association

Why It Works

The parol is a deeply cultural Filipino image. The ornament weights create an instantly visualized funicular polygon with straight segments between loads.

Example Usage

Cable with two point loads: split into three straight segments. Find H from ΣM=0 at a point on the cable, then use T = H/cosθ for each segment's tension.

Recall Trigger

Parol with hanging ornaments — straight segments between each ball.

Topic

Frames

Concept

Dismembering a frame — separate each member and show pin forces with Newton's 3rd Law

Anchor Id

A13

Difficulty

medium

Memory Aid

Engineer Maria is analyzing a frame for a footbridge in her hometown in Batangas. She imagines she has a magical hacksaw — she cuts through every pin in the frame and separates the members into individual pieces. At each cut, she draws two equal-but-opposite arrows: one on each piece. She calls it her 'EQUAL AND OPPOSITE ACCOUNTING SYSTEM.' Like a sari-sari store ledger — every debit on one member's account is a credit on the other. The total of the system is zero. Maria never forgets Newton's Third Law because she remembers her ledger.

Anchor Type

micro_story

Why It Works

The sari-sari store ledger metaphor connects Newton's Third Law to a familiar financial system. The story has a named character (relatable) and a concrete setting.

Example Usage

After finding that pin C exerts 30 kN upward on member AB, immediately write: pin C exerts 30 kN DOWNWARD on member BC — ledger balanced.

Recall Trigger

Maria's magical hacksaw + sari-sari store ledger.

Topic

Frames

Concept

Identifying two-force members before solving — reduces unknowns

Anchor Id

A14

Difficulty

medium

Memory Aid

Before solving, do a TWO-FORCE PATROL. Ask three questions using the acronym P-I-N: P = Pinned at both ends? I = Is it straight? N = No intermediate loads? If all three are YES → TWO-FORCE MEMBER. Mark it, assign its force along its axis, and reduce unknowns. Think of a PIN as the keyword — a pure pin-to-pin member with nothing else is always two-force.

Anchor Type

mnemonic

Why It Works

The acronym P-I-N creates a checklist that uses the word 'pin,' which is already relevant to the topic. This prevents accidentally treating a beam with a midspan load as a two-force member.

Example Usage

Before solving, scan all members. For each: P — yes (pin at C and D). I — yes (straight). N — yes (no other loads). → Two-force member. Force along CD. Reduces unknowns from 2 to 1.

Recall Trigger

Do the P-I-N check: Pinned both ends? Is it straight? No intermediate loads?

Topic

Frames

Concept

Sum of moments to find strut force in a frame (avoid solving two simultaneous equations)

Anchor Id

A15

Difficulty

hard

Memory Aid

The PRC board exam trick: 'TAKE MOMENTS AT THE UNKNOWN PIN.' When you have two unknown pin components at point A (Ax and Ay) and one known strut force angle, take ΣM=0 about point A. The two unknowns (Ax, Ay) create ZERO moment because they pass through A. Only the strut force and external load appear — one equation, one unknown. This is called 'killing two unknowns with one moment.' Remember: 'TAKE MOMENTS AT THE MESSY PIN — it kills the mess instantly.'

Anchor Type

mnemonic

Why It Works

The phrase 'kills the mess' creates a vivid action image. This technique is the single most important frame-solving shortcut and deserves a dedicated anchor.

Example Usage

Frame with pin at A (unknown Ax, Ay) and strut force Fs at C. Take ΣM_A = 0: Fs × (perpendicular distance) − P × (distance) = 0. Solve Fs directly.

Recall Trigger

Messy pin with two unknowns → take ΣM at that pin → unknowns disappear.

Topic

Cables

Concept

Tension in each cable segment: T = H / cosθ

Anchor Id

A16

Difficulty

medium

Memory Aid

Think of H (horizontal component) as the 'backbone' of the cable — it never changes. The tension T in any segment is like the 'hypotenuse' of a right triangle where H is the base and V is the height. From basic trigonometry, cos θ = H/T, so T = H/cosθ. Visualize a right triangle at every joint: the bottom side is always H (constant), the slanted side is T (varies with angle). Steeper angle → longer hypotenuse → bigger T. This is why maximum tension is at the steepest segment (at supports).

Anchor Type

analogy

Why It Works

Connecting T = H/cosθ to the constant-base right triangle makes the formula derivable from first principles, reducing memorization to understanding.

Example Usage

Segment at angle 20° to horizontal, H = 40 kN. T = 40/cos20° = 40/0.940 = 42.6 kN. If angle is 35°, T = 40/cos35° = 48.8 kN. Steeper = bigger T. ✓

Recall Trigger

Right triangle with constant base H — T is always the hypotenuse.

Topic

Machines

Concept

Machines — same procedure as frames: dismember, apply equilibrium, find force ratio

Anchor Id

A17

Difficulty

easy

Memory Aid

Short board-exam rhyme: 'Frame or machine — the rule's the same: Disassemble, draw, and equilibrium claim. For machines, find what effort achieves — The load it lifts, the force it heaves. Arm over arm, that's your M.A. gain — Multiply by effort, and the load you'll name!'

Anchor Type

rhyme

Why It Works

The rhyme reinforces that machines and frames share the same analysis method, preventing students from thinking machines require a special formula beyond lever M.A.

Example Usage

Pliers problem: treat as a machine. Dismember at the pivot pin. Apply ΣM=0 on one handle: (Hand force × effort arm) = (Grip force × load arm). Solve for grip force.

Recall Trigger

Recite: 'Frame or machine — the rule's the same.'

Topic

Cables

Concept

For a cable with a single central point load, vertical equilibrium: 2T sinθ = P

Anchor Id

A18

Difficulty

medium

Memory Aid

Remember '2T sinθ = P' as 'TWO TALL SOLDIERS hold up the PRISONER.' Two cable segments (2T) each pull upward (sinθ component) to hold up the load P (the prisoner). Since the cable is symmetric, both sides have equal tension T. The '2' comes from two symmetrical segments. This only works when the load is exactly at midspan (symmetric). For off-center loads, the two tensions are different — the 'soldiers' are unequal.

Anchor Type

mnemonic

Why It Works

The soldier analogy gives the '2' a physical meaning (two segments). The prisoner = load P creates a memorable image of force balance.

Example Usage

Central load P = 10 kN, θ = 14°. T = P/(2sinθ) = 10/(2×0.2425) = 20.6 kN. Quick check: 2 × 20.6 × 0.2425 ≈ 10 kN ✓

Recall Trigger

'Two tall soldiers (2T sinθ) holding the prisoner (P).' → 2T sinθ = P.

Topic

Frames

Concept

Common board-exam pitfall: treating a multi-force member as two-force

Anchor Id

A19

Difficulty

hard

Memory Aid

Engineering student Carlos was in a hurry during the board exam. He saw a horizontal beam with a pin at each end — and immediately labeled it 'two-force.' But he forgot: the beam had a 20 kN load applied at its midpoint by a pulley! Carlos computed a wrong answer and lost 1 mark. The lesson: even if a member LOOKS like a two-force member, CHECK for intermediate loads first. 'Carlos's costly shortcut' — never skip the P-I-N check (Pinned both ends? Is it straight? No intermediate loads?).

Anchor Type

micro_story

Why It Works

A cautionary story with a named character creates an emotional memory. 'Carlos's costly shortcut' becomes a memorable warning phrase.

Example Usage

Before analyzing any frame: list ALL members, apply P-I-N check to each. Only those passing all three criteria are two-force. All others are multi-force → need full equilibrium.

Recall Trigger

'Don't be like Carlos!' Always do the P-I-N check before classifying members.

Topic

Cables

Concept

Cable sag relationship: larger sag → smaller H; smaller sag → larger H (and larger T_max)

Anchor Id

A20

Difficulty

medium

Memory Aid

Think of a HAMMOCK strung between two coconut trees. When you loosen the ropes and let it sag deeply, you can relax easily — the horizontal pull on the trees is LOW. When you tighten the ropes so the hammock is almost flat (small sag), the trees are pulled together with enormous force — you can feel the horizontal tension is HUGE. This is why suspension bridge cables must have a minimum sag — making them too flat would require impossibly large horizontal tension forces and anchors.

Anchor Type

analogy

Why It Works

The hammock is a universally understood rest object. The physical feeling of tightening ropes creating larger horizontal force makes H = wL²/8d immediately intuitive.

Example Usage

Problem: same cable, same load, sag reduced from 4 m to 2 m. H doubles: H₁ = wL²/8(4), H₂ = wL²/8(2) = 2H₁. T_max also increases. Confirm with formula.

Recall Trigger

Tight hammock (small d) = trees pulled hard (big H). Saggy hammock (big d) = trees relaxed (small H).

Revision Game

Frame

Clue

I am a structure that stands still, but my members feel more than just a push or pull — they bend, they shear, and they carry loads from multiple directions. What am I?

Memory Link

A1 (bahay-kubo analogy) — a frame is like a bahay-kubo, not a bilao tray of bamboo sticks.

Horizontal component H

Clue

I am the one force component in a cable that NEVER changes, no matter how steep or shallow the cable becomes. What am I?

Memory Link

A8 (tabo-on-string micro-story) — the horizontal tug of the string never changes, like H in a cable.

H = wL²/8d = 10(50²)/[8(5)] = 10(2500)/40 = 625 kN

Clue

A cable carries a uniform load of 10 kN/m on a 50 m span with a sag of 5 m. I am the formula you use to find H. State me.

Memory Link

A9 (Weightlifter Loads at Eight Decks mnemonic) — w, L², 8, d → H = wL²/8d.

E-D-P: External reactions → Dismember → Pin forces by equilibrium

Clue

I am the three-step acronym for solving frames. Say my letters and what each one stands for.

Memory Link

A2 (E-D-P acronym + frog dissection analogy)

M.A. = 0.5/0.025 = 20. Load = 40 × 20 = 800 N

Clue

A lever has an effort arm of 0.5 m and a load arm of 0.025 m. A 40 N effort is applied. What load is balanced? I am the formula and the answer.

Memory Link

A5 (bote-opener analogy) and A6 (rhyme: arm over arm gives the might)

Parabola

Clue

I am the shape a cable takes when it carries a uniform load per meter of HORIZONTAL distance (like a bridge deck). Name me.

Memory Link

A11 (DECK = PARABOLA, D-P alliteration; suspension bridge deck carries horizontal load)

Multi-force member. He should have done the P-I-N check: Pinned both ends? Straight? No intermediate loads? The beam fails 'N' (has an intermediate load) → multi-force.

Clue

I am the mistake Carlos made: he called a beam with a midpoint load a two-force member. What is the correct classification, and what check should he have done?

Memory Link

A19 (Carlos's costly shortcut micro-story) + A14 (P-I-N patrol)

At the supports — where the cable angle is steepest.

Clue

I am the location in a cable where the tension is maximum. In a parabolic cable, where am I?

Memory Link

A10 (Enchanted Kingdom roller coaster — steepest at the towers, T_max at the towers)

T = cable tension in each segment (kN) — equal by symmetry. θ = angle of each cable segment to horizontal (degrees). P = concentrated point load at midspan (kN). sinθ = vertical component factor. Note: H = T cosθ (computed after T is found).

False two-force: calling a multi-force member a two-force member
Forgotten Newton's 3rd Law: not flipping the pin force direction on the opposite FBD
Forgetting H is constant: recalculating H for each segment (it never changes!)
Finding T_max at midspan instead of at supports

Loading diagram…

Previous chapter

Analysis of Trusses

Next chapter

Friction

Ready to practise for the CELE 2026?

Super Tutor's AI review plan adapts to your weak areas and builds a weekly practice schedule around your target CELE exam date.

Start free See the full CELE guide CELE preparation guide

← Back to Engineering Mechanics hub

CELE Engineering Mechanics — Frames, Machines and CablesMemory Anchors

Exam context

Frames, Machines and Cables - Memory Anchors

Anchors

Tags

Topic

Concept

Anchor Id

Difficulty

Memory Aid

Anchor Type

Why It Works

Example Usage

Recall Trigger

Tags

Topic

Concept

Anchor Id

Difficulty

Memory Aid

Anchor Type

Why It Works

Example Usage

Recall Trigger

Tags

Topic

Concept

Anchor Id

Difficulty

Memory Aid

Anchor Type

Why It Works

Example Usage

Recall Trigger

Tags

Topic

Concept

Anchor Id

Difficulty

Memory Aid

Anchor Type

Why It Works

Example Usage

Recall Trigger

Tags

Topic

Concept

Anchor Id

Difficulty

Memory Aid

Anchor Type

Why It Works

Example Usage

Recall Trigger

Tags

Topic

Concept

Anchor Id

Difficulty

Memory Aid

Anchor Type

Why It Works

Example Usage

Recall Trigger

Tags

Topic

Concept

Anchor Id

Difficulty

Memory Aid

Anchor Type

Why It Works

Example Usage

Recall Trigger

Tags

Topic

Concept

Anchor Id

Difficulty

Memory Aid