CELE Engineering Mathematics — Differential EquationsCheat Sheet
A printable cheat sheet for Differential Equations, built for CELE reviewers who want one go-to reference in the final stretch. Covers formulas, key definitions, common question types, and the Professional Regulation Commission (PRC) — Board of Civil Engineering-specific twists you will see on CELE day.
Exam context
On the CELE 2026, the Engineering Mathematics subtest carries a "Core" weight in Professional Regulation Commission (PRC) — Board of Civil Engineering's pattern. Differential Equations lands at position 7th out of 10 in the standard review order. Target score is 70% weighted average, no sub-test below 50%, and roughly a meaningful share of items come from Engineering Mathematics on a typical CELE paper.
Differential Equations - Cheat Sheet
Your last-minute rapid-fire reference for all differential equation formulas, methods, and exam-critical facts. Cover classification, first-order methods, higher-order linear equations, and engineering applications in under 30 minutes.
Sections
Formulas
Formula
Order = highest derivative present; Degree = power of highest-order derivative (after polynomial form)
Meaning
Order identifies the number of integration constants in general solution; Degree tells the highest power when DE is polynomial in derivatives
Watch Out
Degree applies only AFTER clearing radicals and fractions in derivatives; a DE may be nonlinear even if first-order
When To Use
Always identify order and degree FIRST before selecting solution method
Section Title
Classification & Fundamentals
Important Facts
- A first-order ODE requires ONE initial condition; second-order requires TWO (e.g., y and y' at a point)
- Number of arbitrary constants in general solution = order of the DE
- Linear ODEs have superposition property: if y₁ and y₂ are solutions, so is C₁y₁ + C₂y₂
- Nonlinear ODEs generally have NO superposition property
- Always verify your solution by substituting back into the original DE
Key Definitions
Term
Ordinary Differential Equation (ODE)
Example
dy/dx + 2y = x² (one independent variable x)
Definition
Equation relating a function of one independent variable to its derivatives; opposed to partial DEs with multiple independent variables.
Term
Linear ODE
Example
y'' + 3y' + 2y = 5 is linear; (y')² + y = 0 is nonlinear
Definition
The dependent variable y and all its derivatives appear to the first power only, with no products of y and its derivatives.
Term
Homogeneous ODE
Example
y' = 2y is homogeneous; y' = 2y + 3 is non-homogeneous
Definition
Right-hand side equals zero; e.g., y'' + 5y' + 6y = 0 (no forcing term).
Term
Particular Solution
Example
y = x² + 1 satisfying y(0) = 1
Definition
A specific solution satisfying given initial or boundary conditions; contains no arbitrary constants.
Term
General Solution
Example
y = C₁e^(2x) + C₂e^(3x) for a second-order ODE
Definition
Contains arbitrary constants (number = order of DE); represents all possible solutions.
Diagrams To Know
- ODE classification tree (Order, Linear/Nonlinear, Homogeneous/Non-homogeneous branches)
- Solution method decision flowchart based on ODE type
Formulas
Formula
Separable: dy/dx = g(x)h(y) ⟹ ∫[dy/h(y)] = ∫g(x)dx
Meaning
g(x) depends on x only; h(y) depends on y only; rearrange so all y terms on left, all x terms on right
Watch Out
DO NOT forget the constant of integration; do NOT cancel h(y) if it equals zero (singular solution may exist)
When To Use
When the RHS factors into a product of a function of x and a function of y
Formula
Linear first-order: dy/dx + P(x)y = Q(x); Integrating Factor μ = e^(∫P(x)dx)
Meaning
P(x) is coefficient of y; Q(x) is forcing term; multiply entire equation by μ
Watch Out
Sign in P(x) must match the ODE form EXACTLY; integrate P(x) carefully; don't add constant when finding μ
When To Use
Standard form dy/dx + P(x)y = Q(x); works for ALL such equations regardless of whether separable
Formula
After multiplying by μ: d/dx[μy] = Q(x)μ ⟹ μy = ∫Q(x)μ(x)dx
Meaning
LHS becomes exact derivative of product μy; integrate RHS to find y
Watch Out
The derivative d/dx[μy] = μ(dy/dx) + y(dμ/dx) = μ(dy/dx) + yP(x)μ — verify the product rule carefully
When To Use
Always the step after multiplying first-order linear ODE by integrating factor
Formula
Exact equation: M(x,y)dx + N(x,y)dy = 0 with ∂M/∂y = ∂N/∂x
Meaning
M is coefficient of dx; N is coefficient of dy; partial derivatives must be equal
Watch Out
ALWAYS verify ∂M/∂y = ∂N/∂x BEFORE proceeding; if not exact, may need integrating factor
When To Use
Check exactness first; if exact, solve by finding F(x,y) such that ∂F/∂x = M and ∂F/∂y = N
Formula
Solution to exact equation: F(x,y) = C where ∂F/∂x = M and ∂F/∂y = N
Meaning
Find F by integrating M w.r.t. x (treating y as constant), then integrate N w.r.t. y and match terms
Watch Out
When integrating M w.r.t. x, the arbitrary 'constant' is a function of y; use the N equation to determine it
When To Use
After confirming exactness; F is the implicit solution
Section Title
First-Order ODE Methods
Important Facts
- All linear first-order ODEs can be solved using the integrating factor method
- For separable equations, isolate dy/h(y) on one side and g(x)dx on the other BEFORE integrating
- Exact equations yield an implicit solution F(x,y) = C; do not always try to solve for y explicitly
- If ∂M/∂y ≠ ∂N/∂x, try multiplying by an integrating factor (often depends on x only or y only)
- Always apply initial conditions AFTER finding the general solution to determine the arbitrary constant
Key Definitions
Term
Integrating Factor (IF)
Example
For dy/dx + 2y = x, μ = e^(∫2dx) = e^(2x)
Definition
Function μ(x) that, when multiplied by an ODE, converts it to exact or allows direct integration; μ = e^(∫P(x)dx) for linear first-order
Term
Exact Equation
Example
(2x + y)dx + (x + 2y)dy = 0 is exact since ∂M/∂y = 1 = ∂N/∂x
Definition
Differential equation M dx + N dy = 0 where ∂M/∂y = ∂N/∂x; solution is F(x,y) = C (implicit form)
Term
Singular Solution
Example
For dy/dx = y², general solution is y = -1/(x+C); singular solution is y = 0
Definition
A solution not obtainable from the general solution for ANY value of the arbitrary constant; may arise from separable equations where h(y) = 0
Diagrams To Know
- Method selection flowchart: Is it separable? → Linear? → Exact? → Needs IF?
- Integration factor construction diagram showing μ = e^(∫P dx)
Formulas
Formula
General form: aₙ(d^n y/dx^n) + aₙ₋₁(d^(n-1) y/dx^(n-1)) + ⋯ + a₁(dy/dx) + a₀y = f(x)
Meaning
aᵢ are constant coefficients; y is dependent variable; f(x) is forcing function
Watch Out
If f(x) = 0, it's homogeneous; if f(x) ≠ 0, it's non-homogeneous; each requires different approach
When To Use
This is the canonical form for all linear constant-coefficient ODEs
Formula
Characteristic equation (homogeneous case f(x)=0): aₘ² + bm + c = 0 for ay'' + by' + cy = 0
Meaning
Replace y with e^(mx), y' with me^(mx), y'' with m²e^(mx); divide by e^(mx) to get characteristic equation
Watch Out
Do NOT forget to form the characteristic equation for each term; roots determine solution form
When To Use
ALWAYS for homogeneous linear constant-coefficient ODEs
Formula
Distinct real roots m₁, m₂: y = C₁e^(m₁x) + C₂e^(m₂x)
Meaning
C₁ and C₂ are arbitrary constants determined by initial conditions
Watch Out
If roots are negative, solution decays to zero; if positive, exponential growth
When To Use
When characteristic equation has two different real roots
Formula
Repeated real root m (multiplicity 2): y = (C₁ + C₂x)e^(mx)
Meaning
Second solution includes a factor of x to ensure linear independence; C₁ and C₂ are constants
Watch Out
CANNOT use y = C₁e^(mx) + C₂e^(mx) for repeated roots — you get linearly dependent solutions
When To Use
When characteristic equation has one repeated root (discriminant = 0)
Formula
Repeated root m (multiplicity k): y = (C₁ + C₂x + C₃x² + ⋯ + Cₖx^(k-1))e^(mx)
Meaning
For root of multiplicity k, include polynomial of degree k-1 as coefficient of e^(mx)
Watch Out
Number of terms = multiplicity; powers of x go from 0 to k-1
When To Use
When characteristic equation has a root with multiplicity k ≥ 2
Formula
Complex conjugate roots α ± βi: y = e^(αx)(C₁cos(βx) + C₂sin(βx))
Meaning
α is real part (damping); β is imaginary part (frequency); C₁ and C₂ determined by ICs
Watch Out
Do NOT use e^(αx)·e^(±βix) — convert to real trigonometric form using Euler's formula
When To Use
When characteristic equation yields complex roots
Formula
Superposition for homogeneous: If y₁ and y₂ are solutions, then y = C₁y₁ + C₂y₂ is also a solution
Meaning
Arbitrary linear combinations of solutions are solutions (applies to LINEAR homogeneous ODEs only)
Watch Out
Does NOT work for nonlinear ODEs
When To Use
Always; foundational property for building general solutions
Formula
Non-homogeneous solution: y = yₕ + yₚ where yₕ = complementary function, yₚ = particular solution
Meaning
yₕ solves the homogeneous part (ay'' + by' + cy = 0); yₚ satisfies the full non-homogeneous equation
Watch Out
Find yₕ first (using characteristic equation); then find yₚ using method of undetermined coefficients or variation of parameters
When To Use
ALWAYS for non-homogeneous constant-coefficient ODEs
Formula
Method of Undetermined Coefficients — Assume form for yₚ based on f(x); assume polynomial, exponential, or sinusoidal depending on f(x)
Meaning
Guess a form with unknown coefficients; substitute into ODE; solve for coefficients
Watch Out
If your assumed form for yₚ is a solution to the homogeneous ODE, multiply by x (or x² if repeated); avoid redundancy with yₕ
When To Use
When f(x) is polynomial, exponential, or sinusoidal (or sum/product thereof)
Formula
Particular solution via Undetermined Coefficients — Common guesses: f(x) = Pₙ(x) ⟹ yₚ = Axⁿ+Bxⁿ⁻¹+⋯; f(x) = e^(ax) ⟹ yₚ = Ae^(ax); f(x) = sin(bx) or cos(bx) ⟹ yₚ = Asin(bx)+Bcos(bx)
Meaning
Match the functional form of f(x) when guessing yₚ
Watch Out
If your guess matches part of yₕ, multiply entire yₚ by x; e.g., if yₕ contains e^(2x) and f(x) = e^(2x), use yₚ = Axe^(2x)
When To Use
Standard method for constant-coefficient non-homogeneous ODEs
Formula
Variation of Parameters (for any f(x), not just standard forms): yₚ = -y₁∫(y₂f/W)dx + y₂∫(y₁f/W)dx where W = y₁y₂' - y₂y₁' (Wronskian)
Meaning
y₁ and y₂ are two linearly independent solutions of homogeneous ODE; W is determinant of their Wronskian matrix
Watch Out
Wronskian W ≠ 0 for linearly independent solutions; can be tedious, but universally applicable
When To Use
When f(x) is not amenable to undetermined coefficients; works for ANY f(x)
Section Title
Higher-Order Linear ODEs with Constant Coefficients
Important Facts
- Solve characteristic equation FIRST; its roots determine the entire form of yₕ
- For distinct real roots: y = C₁e^(m₁x) + C₂e^(m₂x); for repeated root: y = (C₁ + C₂x)e^(mx); for complex α ± βi: y = e^(αx)(C₁cos βx + C₂sin βx)
- General solution of non-homogeneous ODE = yₕ + yₚ; ALWAYS find yₕ first
- If your guess for yₚ duplicates a term in yₕ, multiply the entire yₚ by x
- Wronskian determinant must be non-zero for solutions to be linearly independent
- Initial conditions (y(0) and y'(0)) applied to y = yₕ + yₚ to find C₁ and C₂
Key Definitions
Term
Characteristic Equation
Example
For y'' - 5y' + 6y = 0, characteristic equation is m² - 5m + 6 = 0 with roots m = 2, 3
Definition
Polynomial equation obtained by substituting y = e^(mx) into homogeneous linear constant-coefficient ODE; roots determine form of solution
Term
Complementary Function (yₕ)
Example
For y'' + y' = x, yₕ = C₁ + C₂e^(-x) (solution to y'' + y' = 0)
Definition
General solution to the homogeneous part of a non-homogeneous ODE; contains all arbitrary constants
Term
Particular Solution (yₚ)
Example
For y'' + y' = x, yₚ = x² - 2x is a particular solution
Definition
Any single solution to the non-homogeneous ODE; contains NO arbitrary constants
Term
Wronskian (W)
Example
For y₁ = e^(2x) and y₂ = e^(3x), W = e^(2x)·3e^(3x) - e^(3x)·2e^(2x) = e^(5x) ≠ 0
Definition
Determinant W = y₁y₂' - y₂y₁' used to check linear independence and in variation of parameters; W ≠ 0 iff y₁ and y₂ are linearly independent
Term
Linear Independence
Example
e^(2x) and e^(3x) are linearly independent; e^(2x) and 2e^(2x) are linearly dependent
Definition
Two solutions y₁ and y₂ are linearly independent if no constant k makes y₁ = ky₂; essential for a valid general solution
Diagrams To Know
- Characteristic equation solution tree (real distinct, real repeated, complex conjugate roots)
- Solution form template based on root type
- Non-homogeneous solution composition diagram (yₕ + yₚ)
Formulas
Formula
Exponential Growth/Decay: dy/dt = ky ⟹ y(t) = y₀e^(kt)
Meaning
y₀ is initial value; k is growth rate (k > 0) or decay rate (k < 0); t is time
Watch Out
Sign of k: positive = growth; negative = decay; find k from half-life or doubling time data
When To Use
Population growth, radioactive decay, bacterial culture, compound interest
Formula
Radioactive Decay Half-Life: t₁/₂ = ln(2)/|k| where y(t) = y₀e^(-|k|t)
Meaning
Time required for quantity to reduce to half; relates decay constant to observable half-life
Watch Out
Use ln(2) ≈ 0.693; half-life is POSITIVE even though k is negative
When To Use
When given half-life and asked to find amount remaining at a future time
Formula
Newton's Law of Cooling: dT/dt = -k(T - Tₛ) ⟹ T(t) = Tₛ + (T₀ - Tₛ)e^(-kt)
Meaning
T = temperature at time t; T₀ = initial temperature; Tₛ = surrounding temperature; k = cooling constant (k > 0)
Watch Out
Rate is proportional to temperature DIFFERENCE, not absolute temperature; ambient temperature Tₛ is constant
When To Use
Heat transfer, cooling of hot objects in ambient environment
Formula
Mixing Tanks (Brine/Solute): rate of change of solute = (rate in) - (rate out); input conc. × flow in - output conc. × flow out
Meaning
dQ/dt = C_in·F_in - C_out·F_out where Q = amount of solute, C = concentration, F = flow rate
Watch Out
Output concentration = Q(t)/V(t) where V(t) is volume at time t; volume may change if inflow ≠ outflow
When To Use
Tank mixing problems with inflow/outflow of solution at different concentrations
Formula
Mixing with Constant Volume: dQ/dt = (C_in·F) - (Q/V)·F ⟹ Linear first-order ODE in Q(t)
Meaning
When inflow = outflow, tank volume V is constant; C_in is concentration of inflow; F is volumetric flow rate
Watch Out
Output concentration is Q(t)/V because total amount Q is distributed in volume V
When To Use
Standard tank mixing setup (water in = water out)
Formula
Motion with Damping: m(d²x/dt²) + c(dx/dt) + kx = F(t)
Meaning
m = mass; c = damping coefficient; k = spring stiffness; F(t) = external force; x = displacement
Watch Out
Second-order ODE; damping term c(dx/dt) opposes motion; underdamped (c² < 4mk) gives oscillation
When To Use
Vibration analysis, spring-mass-damper systems in mechanics
Formula
Free Vibration (F(t)=0): Characteristic equation: mλ² + cλ + k = 0; discriminant Δ = c² - 4mk determines behavior
Meaning
λ = (−c ± √(c²−4mk))/(2m); Δ > 0 = overdamped; Δ = 0 = critically damped; Δ < 0 = underdamped (oscillatory)
Watch Out
Only Δ < 0 (underdamped) produces oscillations; overdamped and critically damped approach equilibrium without oscillating
When To Use
Predicting damping behavior of mechanical systems (no external forcing)
Common Values
Value
0.693
Symbol
ln(2)
Quantity
Natural logarithm of 2 (for half-life conversion)
Value
1.0
Symbol
ln(e)
Quantity
Natural logarithm of e
Value
1/e ≈ 0.368 or 36.8%
Symbol
e^(-1)
Quantity
Fraction remaining after one time constant τ
Section Title
Engineering Applications
Important Facts
- Growth/decay always results in exponential form y = y₀e^(kt); identify whether growth (k > 0) or decay (k < 0)
- Find k from ANY known data point: if population is P₀ at t = 0 and 2P₀ at t = 5, then k = ln(2)/5 ≈ 0.139 per unit time
- Newton's cooling assumes T_s (ambient) is constant; if ambient changes, problem becomes more complex
- In tank mixing, output concentration = current solute amount / tank volume; as solute is removed, concentration decreases
- Spring-mass-damper: underdamped systems oscillate with decreasing amplitude; critical damping is the 'ideal' for rapid approach to equilibrium without overshoot
- Half-life / Doubling time: For decay, N(t) = N₀(1/2)^(t/t₁/₂); for growth, N(t) = N₀·2^(t/t_double)
Key Definitions
Term
Decay Constant (k)
Example
For Cobalt-60 with t₁/₂ = 5.27 years, k = 0.693/5.27 ≈ 0.131 per year
Definition
Proportionality constant in dy/dt = -ky for decay processes; related to half-life by t₁/₂ = ln(2)/k
Term
Damping Ratio (ζ)
Example
For m = 1 kg, c = 2 N·s/m, k = 1 N/m: ζ = 2/(2√1) = 1 (critically damped)
Definition
Dimensionless parameter ζ = c/(2√(mk)) that classifies oscillatory behavior; ζ < 1 = underdamped (oscillation); ζ = 1 = critically damped; ζ > 1 = overdamped
Term
Time Constant (τ)
Example
RC circuit: τ = RC; for R = 1 kΩ, C = 1 μF, τ = 1 ms
Definition
Characteristic time scale of exponential decay/growth; for dy/dt = -ky, τ = 1/k; after time τ, quantity reduces to 1/e ≈ 37% of initial
Diagrams To Know
- Exponential decay curve (y = y₀e^(-kt)) showing half-life intervals
- Damping classification diagram (overdamped, critically damped, underdamped response curves)
- Tank mixing process flow diagram (input concentration/rate, tank volume, output concentration/rate)
Formulas
Formula
Laplace Transform definition: L{f(t)} = F(s) = ∫₀^∞ e^(-st)f(t)dt
Meaning
Converts function f(t) in time domain to F(s) in frequency domain; s is complex variable
Watch Out
Integral must converge (requires appropriate growth conditions on f); s must be large enough
When To Use
Transform ODE with initial conditions into algebraic equation; solves linear constant-coefficient ODEs with ICs
Formula
Linearity: L{af(t) + bg(t)} = aF(s) + bG(s)
Meaning
Transform of sum = sum of transforms; scaling is preserved
Watch Out
Works because integration is linear
When To Use
Apply to each term of ODE separately
Formula
First derivative: L{f'(t)} = sF(s) - f(0)
Meaning
Derivative in time domain ↔ multiplication by s minus initial condition in transform domain
Watch Out
Do NOT forget the initial condition −f(0); it becomes part of the algebraic equation
When To Use
Replace each y' with sY(s) - y(0) when transforming ODE
Formula
Second derivative: L{f''(t)} = s²F(s) - sf(0) - f'(0)
Meaning
Second derivative ↔ s² times transform minus initial value minus initial slope
Watch Out
Both y(0) AND y'(0) appear; order matters
When To Use
For second-order ODEs; replace each y'' with s²Y(s) - sy(0) - y'(0)
Formula
Heaviside step function: L{u(t-a)} = e^(-as)/s where u(t-a) = 0 for t < a, 1 for t ≥ a
Meaning
Shifted unit step; useful for modeling on/off forcing
Watch Out
Shift in time domain ↔ exponential factor e^(-as) in transform domain
When To Use
Piecewise forcing functions or delayed responses
Formula
Common transforms (memorize): L{1} = 1/s; L{e^(at)} = 1/(s-a); L{sin(bt)} = b/(s²+b²); L{cos(bt)} = s/(s²+b²); L{tⁿ} = n!/s^(n+1)
Meaning
Table of standard function pairs; used for forward and inverse transforms
Watch Out
Memorize at least 5–6 most common transforms; know the shifting theorem for translations
When To Use
Look up or recall when setting up transform equations and performing partial fraction decomposition
Formula
Partial Fraction Decomposition (for inverse transform): Expand F(s) = P(s)/Q(s) as sum of simpler fractions; identify each term with standard transform
Meaning
Break complex rational function into sum of simple fractions (each corresponding to a known time-domain function)
Watch Out
Degree of P < degree of Q required (if not, perform polynomial long division first); each pole contributes a residue term
When To Use
After solving the transformed algebraic equation for Y(s), decompose to find y(t) = L⁻¹{Y(s)}
Formula
Convolution theorem: L{f(t) * g(t)} = F(s)G(s) where f(t) * g(t) = ∫₀^t f(τ)g(t−τ)dτ
Meaning
Product in frequency domain ↔ convolution in time domain; useful for forcing functions
Watch Out
Convolution integral can be tedious; use only if partial fractions fail
When To Use
Inverse transforming products that do not factor into standard forms
Section Title
Laplace Transform Method (Alternative for Linear ODEs)
Important Facts
- Laplace method converts ODE with initial conditions into algebraic equation (linear); solve algebraically for Y(s), then invert
- Always write differential equation in standard form and identify initial conditions y(0), y'(0), etc. BEFORE applying transform
- Partial fraction decomposition is the key step in the inverse transform; break rational F(s) into sum of standard forms
- Convolution theorem extends method to non-standard forcing functions; less common in exam problems
- Laplace method excels for piecewise forcing (Heaviside functions) and delayed responses
Key Definitions
Term
Region of Convergence (ROC)
Example
For f(t) = e^(at), ROC is s > a (ensures e^((a-s)t) → 0 as t → ∞)
Definition
Set of s values (typically s > σ for some σ) for which the Laplace integral converges; must be specified for unique F(s)
Term
Inverse Laplace Transform
Example
L⁻¹{2/(s²+4)} = sin(2t) because L{sin(2t)} = 2/(s²+4)
Definition
Operation L⁻¹{F(s)} that recovers f(t) from F(s); typically done via partial fractions and lookup table
Diagrams To Know
- Laplace transform method flowchart (ODE with ICs → Transform → Algebraic equation → Solve → Inverse transform → Solution)
- Standard Laplace transform pair reference table
Must Remember
- CLASSIFICATION FIRST: Always identify order, degree, and type (separable/linear/exact/etc.) before choosing solution method.
- SEPARABLE: Get all y on one side, all x on the other, THEN integrate both sides. Remember the constant of integration!
- LINEAR FIRST-ORDER: Use integrating factor μ = e^(∫P(x)dx); multiply entire equation by μ, then recognize LHS as d/dx[μy].
- CHARACTERISTIC EQUATION for constant-coefficient homogeneous ODEs: Substitute y = e^(mx), get am² + bm + c = 0; roots determine solution form.
- SOLUTION FORMS based on characteristic roots: (1) Distinct real m₁, m₂ → y = C₁e^(m₁x) + C₂e^(m₂x); (2) Repeated m → y = (C₁ + C₂x)e^(mx); (3) Complex α ± βi → y = e^(αx)(C₁cos βx + C₂sin βx).
- NON-HOMOGENEOUS = yₕ + yₚ: Complementary function yₕ (solution to homogeneous part) + Particular yₚ (any solution to full ODE).
- UNDETERMINED COEFFICIENTS: Guess yₚ based on form of f(x); if guess matches a term in yₕ, multiply entire guess by x.
- EXPONENTIAL GROWTH/DECAY: y = y₀e^(kt); find k from one data point; k > 0 = growth, k < 0 = decay; use ln(2) ≈ 0.693 for half-life.
- NEWTON'S COOLING: dT/dt = −k(T − Tₛ) ⟹ T(t) = Tₛ + (T₀ − Tₛ)e^(−kt); Tₛ is ambient (constant), k > 0 is cooling rate.
- ALWAYS VERIFY your solution by substituting back into the original ODE; apply initial conditions AFTER finding general solution to find arbitrary constants.
Last Minute Tips
- READ THE PROBLEM CAREFULLY: Identify initial conditions, type of ODE, and what is being asked (general solution vs. particular solution). Many students lose points by solving the wrong type.
- IF STUCK ON METHOD: Try separable first (easiest); if not separable, check for linear form dy/dx + P(x)y = Q(x); if neither, try exact or look for a substitution. Do NOT guess randomly.
- CHARACTERISTIC EQUATION IS YOUR BEST FRIEND for constant-coefficient ODEs: Roots determine 90% of the answer; practice factoring quadratics quickly.
- FOR yₚ GUESSING (undetermined coefficients): Write down yₕ first, then compare your yₚ guess to it. If there is ANY overlap, multiply yₚ by x. This is the #1 mistake.
- LAPLACE TRANSFORM IS A SHORTCUT for initial value problems: If the problem gives y(0) and y'(0), consider Laplace; partial fractions is the bottleneck—practice it.
Comparison Tables
Rows
Values
- dy/dx = g(x)h(y)
- RHS factors into x and y parts
- All separable equations (simplest approach)
- Separate variables: ∫dy/h(y) = ∫g(x)dx
- Implicit or explicit form y = f(x, C)
Property
Separable
Values
- dy/dx + P(x)y = Q(x)
- Linear in y and y' only; y appears to first power
- Standard form or after rearrangement
- Multiply by μ = e^(∫P dx), then integrate
- Explicit y = [∫Q·μ dx + C]/μ
Property
Linear
Values
- M dx + N dy = 0 with ∂M/∂y = ∂N/∂x
- Check exactness condition first
- When separable or linear fails, or given as exact form
- Find F such that ∂F/∂x = M and ∂F/∂y = N; set F = C
- Implicit form F(x, y) = C
Property
Exact
Columns
- Method
- Recognizable Form
- When to Use
- Key Step
- Solution Type
Table Title
First-Order ODE Methods Comparison
Rows
Values
- Δ = b² − 4ac > 0
- m₁ ≠ m₂, both real
- y = C₁e^(m₁x) + C₂e^(m₂x)
- No oscillation; exponential growth/decay depending on sign of m
Property
Distinct Real
Values
- Δ = b² − 4ac = 0
- m₁ = m₂ = m (multiplicity 2)
- y = (C₁ + C₂x)e^(mx)
- Polynomial × exponential; slower approach to equilibrium than distinct roots
Property
Repeated Real
Values
- Δ = b² − 4ac < 0
- m = α ± βi where α = −b/(2a), β = √(4ac−b²)/(2a)
- y = e^(αx)(C₁cos(βx) + C₂sin(βx))
- Damped oscillation (α < 0) or growing oscillation (α > 0); frequency β
Property
Complex Conjugate
Columns
- Root Type
- Discriminant / Condition
- Roots
- General Solution yₕ
- Behavior
Table Title
Characteristic Equation Roots vs. Solution Form
Rows
Values
- yₚ = Axⁿ + Bxⁿ⁻¹ + ⋯ + Z
- yₚ = x(Axⁿ + Bxⁿ⁻¹ + ⋯ + Z) [if 0 is root of char. eqn]
- To avoid linear dependence with yₕ
- n + 1 coefficients
Property
Pₙ(x) = polynomial degree n
Values
- yₚ = Ae^(ax)
- yₚ = Axe^(ax) [if e^(ax) ∈ yₕ]
- Ensures yₚ not already in yₕ
- 1 coefficient (or 2 if multiplied by x)
Property
e^(ax)
Values
- yₚ = Asin(bx) + Bcos(bx)
- yₚ = x(Asin(bx) + Bcos(bx)) [if sin/cos in yₕ]
- Avoid duplication with yₕ terms
- 2 coefficients (or 4 if multiplied by x)
Property
sin(bx) or cos(bx)
Values
- yₚ = e^(ax)(A₀xⁿ + A₁xⁿ⁻¹ + ⋯ + Aₙ)
- yₚ = x·e^(ax)(A₀xⁿ + A₁xⁿ⁻¹ + ⋯ + Aₙ)
- Multiply entire yₚ by x if e^(ax) matches a yₕ term
- n + 1 coefficients (doubled if multiplied by x)
Property
e^(ax)·Pₙ(x)
Columns
- Forcing f(x)
- Guess for yₚ (if NOT in yₕ)
- Guess for yₚ (if matches yₕ term)
- Why Multiply by x
- Number of Unknowns
Table Title
Non-Homogeneous ODE: Forcing Function vs. Particular Solution Guess
Rows
Values
- dy/dt = ky
- k = growth rate (>0) or decay rate (<0)
- y(0) = y₀ (initial population)
- y(t) = y₀e^(kt)
Property
Exponential Growth/Decay
Values
- dN/dt = −(ln2/t₁/₂)N
- t₁/₂ = half-life time period
- N(0) = N₀ (initial atoms)
- N(t) = N₀(1/2)^(t/t₁/₂) or N₀e^(−kt) where k = ln2/t₁/₂
Property
Radioactive Decay (Half-Life)
Values
- dT/dt = −k(T − Tₛ)
- k = cooling coefficient; Tₛ = ambient temperature (constant)
- T(0) = T₀ (initial object temperature)
- T(t) = Tₛ + (T₀ − Tₛ)e^(−kt)
Property
Newton's Cooling
Values
- dQ/dt = C_in·F_in − (Q/V)·F_out
- C_in = inflow concentration; F_in, F_out = flow rates; V = tank volume
- Q(0) = Q₀ (initial solute amount)
- First-order linear; solve using integrating factor
Property
Tank Mixing (Constant Volume V)
Columns
- Application
- Differential Equation
- Key Constant
- Initial Condition
- Solution Form
Table Title
Application: Growth/Decay vs. Cooling vs. Mixing
Rows
Values
- ζ < 1
- Δ < 0 (complex roots α ± βi)
- Complex conjugate: m = −c/(2m) ± i√(4mk−c²)/(2m)
- Oscillates with decreasing amplitude; α = −c/(2m) < 0 (damping)
- Infinite (asymptotic approach)
Property
Underdamped
Values
- ζ = 1
- Δ = 0 (repeated real root)
- Repeated: m = −c/(2m) (multiplicity 2)
- Returns to equilibrium fastest without overshooting; no oscillation
- Shortest (optimal for many applications)
Property
Critically Damped
Values
- ζ > 1
- Δ > 0 (distinct real roots)
- Distinct: m₁, m₂ = [−c ± √(c²−4mk)]/(2m), both < 0
- No oscillation; slow exponential decay to equilibrium
- Longer than critical damping
Property
Overdamped
Columns
- Regime
- Damping Ratio ζ
- Discriminant Δ = c² − 4mk
- Root Type
- Response Behavior
- Time to Equilibrium
Table Title
Damping Classification (Spring-Mass-Damper System)
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