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CELE Engineering MathematicsAlgebra and FundamentalsRevision Notes

Revision notes for CELE Engineering Mathematics Algebra and Fundamentals — designed for time-pressed reviewers. These notes skip the basics and focus on what Professional Regulation Commission (PRC) — Board of Civil Engineering consistently tests, so you spend your revision hours on the content most likely to appear on exam day.

Exam context

The Civil Engineer Licensure Examination is conducted by Professional Regulation Commission (PRC) — Board of Civil Engineering and is scheduled for May and November 2026. The Engineering Mathematics subtest is marked as "Core" in the official pattern, and Algebra and Fundamentals appears in position 1st of 10 in the CELE Engineering Mathematics review rotation. Passing mark: 70% weighted average, no sub-test below 50%. Recent CELE 2026 papers have drawn roughly a meaningful share of questions from this subject.

Algebra and Fundamentals - Revision Notes

Algebra and Fundamentals is one of the highest-yield topics in the MSTE (Mathematics, Surveying, and Transportation Engineering) component of the PRC Civil Engineer Licensure Examination. Expect 8–12 questions per board exam covering quadratic and polynomial equations, arithmetic and geometric progressions, the binomial theorem, logarithms, and classic word problems (work, mixture, age, motion). This revision note condenses every exam-critical formula, decision rule, and worked example you need to maximize your score. Study the flowcharts carefully — they will help you select the correct formula under time pressure.

Sections

Formulas

Example

Simplify 3^4 · 3^(−2) = 3^(4+(−2)) = 3^2 = 9

Formula

a^m · a^n = a^(m+n)

Variables

a = base (real number, a ≠ 0); m, n = exponents (integers or rationals)

Application

Combining exponential expressions with the same base

Example

8^(2/3) = (cube-root of 8)^2 = 2^2 = 4

Formula

a^(m/n) = (n-th root of a)^m

Variables

a = radicand; m = power; n = index of the radical

Application

Converting between radical and exponential form

Example

4th root of (x^4) = |x|; cube-root of (x^3) = x

Formula

n-th root of (a^n) = |a| for even n; = a for odd n

Variables

a = any real number; n = index

Application

Simplifying even-indexed radicals to avoid sign errors

Exam Tips

  • When simplifying large exponents on the board exam, break them into factors of known values: 2^10 = 1024, 2^8 = 256.
  • Convert all radical expressions to fractional exponents before applying algebra rules — it prevents index-handling errors.
  • If the answer choices are numerical, substitute a simple value (e.g., a = 2) to verify your simplification.
  • Expect 1–2 items per board exam on exponent/radical simplification. They are straightforward scoring opportunities — do not rush.

Key Points

  • Product rule: a^m · a^n = a^(m+n). The base must be the same.
  • Power rule: (a^m)^n = a^(mn). Multiply the exponents.
  • Quotient rule: a^m / a^n = a^(m−n).
  • Zero exponent: a^0 = 1 for any a ≠ 0.
  • Negative exponent: a^(−n) = 1/a^n. Move the base to the denominator.
  • Fractional exponent: a^(m/n) = n-th root of a^m = (n-th root of a)^m.
  • Radical product: n-th root of (ab) = (n-th root of a)(n-th root of b).
  • Radical quotient: n-th root of (a/b) = (n-th root of a)/(n-th root of b).
  • Rationalizing denominators — multiply numerator and denominator by the conjugate when a radical appears in the denominator.
  • Simplify before solving: factor out perfect powers from under the radical sign to reduce arithmetic errors.

Definitions

Term

Radicand

Definition

The expression under a radical sign.

Importance

Identifying the radicand correctly prevents incorrect simplification steps.

Term

Rationalization

Definition

The process of eliminating radicals from the denominator of a fraction by multiplying by an appropriate conjugate or radical expression.

Importance

Board exam answer choices are always in rationalized form; failure to rationalize leads to mismatched answers.

Section Title

Laws of Exponents and Radicals

Common Mistakes

  • Writing (a+b)^n = a^n + b^n — this is WRONG. The binomial theorem must be applied.
  • Applying the product rule when bases differ: 2^3 · 3^2 ≠ 6^5.
  • Forgetting the absolute value when simplifying even-indexed radicals: square-root of x^2 = |x|, not simply x.
  • Negative exponent means reciprocal, NOT negative: 2^(−3) = 1/8, not −8.
  • Confusing the index of a radical with the exponent of the radicand.

Formulas

Example

log(100 · 1000) = log 100 + log 1000 = 2 + 3 = 5. Verify: log(100,000) = log(10^5) = 5 ✓

Formula

log(MN) = log M + log N

Variables

M, N > 0; base is any positive number ≠ 1

Application

Expanding or condensing logarithmic expressions

Example

log_2(32) = log(32)/log(2) = 1.50515/0.30103 = 5. Verify: 2^5 = 32 ✓

Formula

log_b(x) = log(x) / log(b)

Variables

x > 0, b > 0, b ≠ 1

Application

Evaluating logarithms with non-standard bases on a scientific calculator

Example

Solve 3^x = 50: x·log 3 = log 50 → x = log(50)/log(3) = 1.69897/0.47712 ≈ 3.561

Formula

log M^p = p · log M

Variables

M > 0; p = any real number

Application

Solving exponential equations by taking logarithms of both sides

Exam Tips

  • Memorize: log 2 ≈ 0.3010, log 3 ≈ 0.4771, log 7 ≈ 0.8451. These values appear constantly in board exam computation.
  • When the equation has logs on both sides with the same base, cancel the log: log_b(A) = log_b(B) → A = B.
  • To solve 10^x = N, take log of both sides: x = log N. To solve e^x = N, take ln: x = ln N.
  • In board exams, the word 'logarithm' without specifying a base always means base 10.

Key Points

  • Definition: log_b(x) = y means b^y = x. The logarithm is an exponent.
  • Common log (log) uses base 10; natural log (ln) uses base e ≈ 2.71828.
  • log(MN) = log M + log N — product rule.
  • log(M/N) = log M − log N — quotient rule.
  • log(M^p) = p·log M — power rule.
  • Change of base: log_b(x) = ln(x)/ln(b) = log(x)/log(b).
  • log_b(b) = 1; log_b(1) = 0; log_b(b^x) = x; b^(log_b x) = x.
  • Logarithm is defined only for positive arguments: log(x) requires x > 0.
  • When solving logarithmic equations, always check for extraneous solutions by substituting back into the original equation.

Definitions

Term

Common Logarithm

Definition

Logarithm with base 10, written as log(x). It is the default base on most scientific calculators.

Importance

Used extensively in sound level (dB), pH, Richter scale, and board exam computation items.

Term

Natural Logarithm

Definition

Logarithm with base e ≈ 2.71828, written as ln(x). It is the inverse of the exponential function e^x.

Importance

Appears in calculus-based engineering problems and growth/decay problems in board exams.

Term

Antilogarithm

Definition

The inverse operation of a logarithm: if log(x) = y, then x = 10^y (antilog of y).

Importance

Required when solving for the argument after isolating the log side of an equation.

Section Title

Logarithms

Common Mistakes

  • Writing log(M+N) = log M + log N — this is WRONG. The product rule applies to log(MN), not log(M+N).
  • Writing log(M−N) = log M − log N — this is WRONG. The quotient rule applies to log(M/N).
  • Dividing logs incorrectly: log(M)/log(N) ≠ log(M/N).
  • Forgetting to check domain: log(x−3) requires x > 3, not x > 0.
  • Applying change of base incorrectly: log_b(x) = log(x)/log(b), NOT log(b)/log(x).

Formulas

Example

Solve 2x²+3x−5=0: a=2, b=3, c=−5. x=[−3±√(9+40)]/4=[−3±7]/4. x=(4/4)=1 or x=(−10/4)=−2.5

Formula

x = [−b ± √(b² − 4ac)] / (2a)

Variables

a = coefficient of x²; b = coefficient of x; c = constant term

Application

Finding roots of any quadratic equation; fallback when factoring is not immediately obvious

Example

For 2x²+3x−5=0: Sum=−3/2=−1.5 (check: 1+(−2.5)=−1.5 ✓); Product=−5/2=−2.5 (check: 1×(−2.5)=−2.5 ✓)

Formula

Sum = −b/a; Product = c/a

Variables

a, b, c from standard form ax²+bx+c=0

Application

Verifying computed roots; constructing a quadratic from known root properties

Example

Find the remainder when x³−3x²+2x−5 is divided by (x−2): f(2)=8−12+4−5=−5. Remainder=−5.

Formula

Remainder = f(k) when dividing f(x) by (x−k)

Variables

f(x) = polynomial; k = the value substituted

Application

Finding remainders without performing full polynomial division

Exam Tips

  • Try factoring first — it is faster. If b²−4ac is a perfect square, the quadratic factors over the integers.
  • The sum/product of roots check takes 5 seconds and catches arithmetic errors before you bubble your answer.
  • Board exam items on polynomials often ask for the remainder or the value of an unknown coefficient — use the Remainder or Factor Theorem directly.
  • If asked for a quadratic equation with roots r₁ and r₂, write: x²−(r₁+r₂)x+(r₁·r₂)=0.
  • Memorize: for equal roots (tangent to x-axis), set D=0. For real roots (crosses x-axis), set D≥0.

Key Points

  • Standard form: ax^2 + bx + c = 0, where a ≠ 0.
  • Quadratic formula: x = [−b ± √(b²−4ac)] / (2a). This always works — memorize it.
  • Discriminant D = b²−4ac determines the nature of roots.
  • D > 0: two real, distinct roots. D = 0: one repeated real root. D < 0: two complex conjugate roots.
  • Sum of roots: x₁ + x₂ = −b/a. Product of roots: x₁ · x₂ = c/a. These allow quick verification.
  • Factoring: ax^2 + bx + c = a(x − x₁)(x − x₂) once roots are known.
  • For a polynomial of degree n, there are exactly n roots (counting multiplicity) in the complex number system (Fundamental Theorem of Algebra).
  • Remainder Theorem: when f(x) is divided by (x−k), the remainder = f(k).
  • Factor Theorem: (x−k) is a factor of f(x) if and only if f(k) = 0.
  • Synthetic division is the fastest way to evaluate polynomials and perform polynomial long division on board exams.

Definitions

Term

Discriminant

Definition

The expression D = b²−4ac under the radical in the quadratic formula. Its sign determines the nature and number of real roots.

Importance

Board exam items frequently ask 'for what values of k does the equation have equal roots?' — set D=0 and solve for k.

Term

Repeated Root

Definition

A root that occurs more than once, corresponding to a tangent point of the parabola to the x-axis. Occurs when D=0.

Importance

When D=0, the single root x=−b/(2a) is the vertex x-coordinate of the parabola.

Term

Synthetic Division

Definition

A shortcut algorithm for dividing a polynomial by a linear factor (x−k), using only the coefficients.

Importance

Essential for the board exam — faster than long division and enables application of the Remainder and Factor Theorems.

Section Title

Quadratic and Polynomial Equations

Common Mistakes

  • Sign error in the quadratic formula: the formula starts with −b, not +b.
  • Forgetting to check if the quadratic is in standard form (= 0) before applying the formula.
  • Assuming integer roots when the discriminant is not a perfect square — leave answers as exact surds or decimals.
  • In the Remainder Theorem, dividing by (x+k) means substituting x=−k, NOT x=+k.
  • Dropping a coefficient of zero in synthetic division — always include placeholder zeros for missing degree terms.

Formulas

Example

AP: 3, 7, 11, 15,... Find a₁₀: a₁₀ = 3 + (10−1)(4) = 3 + 36 = 39

Formula

a_n = a₁ + (n−1)d

Variables

a_n = nth term; a₁ = first term; d = common difference; n = term number

Application

Finding any specific term in an arithmetic sequence

Example

Sum of first 10 terms, a₁=3, d=4: S₁₀=(10/2)[2(3)+9(4)]=5[6+36]=5(42)=210

Formula

S_n = (n/2)(a₁ + a_n) = (n/2)[2a₁ + (n−1)d]

Variables

S_n = sum of first n terms; a₁ = first term; a_n = last term; d = common difference

Application

Summing consecutive terms of an AP, including sum of first n positive integers

Example

GP: 2, 6, 18,... Sum of first 5 terms: S₅ = 2(3⁵−1)/(3−1) = 2(243−1)/2 = 242

Formula

S_n = a₁(r^n − 1)/(r − 1)

Variables

a₁ = first term; r = common ratio; n = number of terms

Application

Summing a finite geometric series

Example

GP: 8, 4, 2, 1,... r=1/2. S∞ = 8/(1−1/2) = 8/(1/2) = 16

Formula

S∞ = a₁/(1−r), valid only when |r| < 1

Variables

a₁ = first term; r = common ratio with |r| < 1

Application

Summing an infinite converging geometric series (e.g., repeating decimals, diminishing returns)

Exam Tips

  • Board exam problems often give you two non-consecutive AP terms and ask for the sum — set up two equations using a_n = a₁+(n−1)d and solve simultaneously.
  • The sum of the first n positive integers: S = n(n+1)/2 — this is an AP with a₁=1 and d=1. Memorize this result.
  • For infinite GP, always verify |r|<1 before applying S∞=a₁/(1−r). Board exams sometimes set a trap with r>1.
  • Repeating decimals can be expressed as infinite GPs: 0.333... = 3/10 + 3/100 + ... = (3/10)/(1−1/10) = 1/3.
  • Inserting k arithmetic means between a and b: the common difference d=(b−a)/(k+1).

Key Points

  • Arithmetic Progression (AP): each term is obtained by adding a constant d (common difference).
  • AP general term: a_n = a₁ + (n−1)d.
  • AP sum of n terms: S_n = (n/2)[2a₁ + (n−1)d] = (n/2)(a₁ + a_n).
  • Arithmetic mean of two numbers a and b: AM = (a+b)/2.
  • Geometric Progression (GP): each term is obtained by multiplying by a constant r (common ratio).
  • GP general term: a_n = a₁ · r^(n−1).
  • GP sum of n terms: S_n = a₁(r^n − 1)/(r − 1) for r ≠ 1.
  • Infinite GP sum (converges only when |r| < 1): S∞ = a₁/(1−r).
  • Geometric mean of two numbers a and b: GM = √(a·b) (positive root for positive terms).
  • Harmonic Progression (HP): a sequence whose reciprocals form an AP. Solve HP problems by working with the AP of reciprocals.
  • Relationship: AM ≥ GM ≥ HM (Arithmetic Mean − Geometric Mean − Harmonic Mean inequality).

Definitions

Term

Common Difference (d)

Definition

The constant value added to each term of an AP to get the next term. d = a_n − a_(n−1).

Importance

Always compute d first in an AP problem. It unlocks both the general term and the sum formula.

Term

Common Ratio (r)

Definition

The constant factor multiplied to each term of a GP to get the next term. r = a_n / a_(n−1).

Importance

Determining convergence of an infinite GP requires knowing |r|. If |r| ≥ 1, the infinite sum does not exist.

Term

Harmonic Progression

Definition

A sequence of numbers whose reciprocals form an arithmetic progression.

Importance

Board exams often disguise HP problems by asking for the harmonic mean or the nth term — always convert to AP first.

Section Title

Arithmetic and Geometric Progressions

Common Mistakes

  • Using the wrong 'n': ensure n is the number of TERMS, not the last term value.
  • Applying the infinite GP formula when |r| ≥ 1 — the series diverges and S∞ does not exist.
  • For GP problems, computing r by subtraction (like an AP) instead of division.
  • In the AP sum formula, forgetting to multiply by n/2 or applying n instead of n/2.
  • Confusing arithmetic mean (average) with geometric mean (square root of product) in mean-insertion problems.

Formulas

Example

Find the 6th term of (2x−1)^9: r=5, T₆=C(9,5)·(2x)^4·(−1)^5=126·16x⁴·(−1)=−2016x⁴

Formula

T_(r+1) = C(n,r) · a^(n−r) · b^r

Variables

T_(r+1) = (r+1)th term; n = exponent; r = term index starting at 0; a, b = bases of the binomial

Application

Finding a specific term in a binomial expansion without expanding the entire expression

Example

C(9,5) = 9!/(5!·4!) = (9·8·7·6)/(4·3·2·1) = 3024/24 = 126

Formula

C(n,r) = n! / [r!(n−r)!]

Variables

n = total items; r = items chosen; ! = factorial

Application

Computing binomial coefficients; also used in probability and combinations

Exam Tips

  • To find the term containing x^k in (a+bx)^n, set the power of x in T_(r+1) equal to k and solve for r, then substitute back.
  • For the term independent of x (constant term), set the power of x equal to zero and solve for r.
  • In multiple-choice board exams, expand only the specific term asked — never expand the full binomial.
  • Pascal's Triangle is fast for n ≤ 6; use the C(n,r) formula for n > 6.
  • The sum of all binomial coefficients = 2^n. This is a quick sanity check: sum all your computed coefficients and verify.

Key Points

  • Binomial expansion: (a+b)^n = Σ C(n,k) · a^(n−k) · b^k for k=0 to n.
  • C(n,k) = n! / [k!(n−k)!] is the binomial coefficient.
  • The (r+1)th term (general term): T_(r+1) = C(n,r) · a^(n−r) · b^r.
  • Total number of terms in the expansion of (a+b)^n is n+1.
  • The middle term: for even n, there is one middle term at position (n/2)+1; for odd n, there are two middle terms.
  • Pascal's Triangle gives the binomial coefficients for small values of n.
  • The sum of all coefficients is obtained by substituting a=1, b=1: (1+1)^n = 2^n.
  • The sum of coefficients of odd-positioned terms equals the sum of even-positioned terms = 2^(n−1).

Definitions

Term

Binomial Coefficient C(n,r)

Definition

The number of ways to choose r objects from n objects, also equal to the coefficient of the (r+1)th term in the binomial expansion.

Importance

Board exam items on binomial theorem almost always require computing C(n,r) — practice evaluating it rapidly.

Term

General Term of Binomial Expansion

Definition

The formula T_(r+1)=C(n,r)·a^(n−r)·b^r which gives the value of any specific term in (a+b)^n without full expansion.

Importance

This is the single most tested formula in binomial theorem board exam items. Know it cold.

Section Title

Binomial Theorem

Common Mistakes

  • Indexing error: the (r+1)th term has b raised to r (not r+1). T₆ has r=5 because T_(5+1)=T₆.
  • Forgetting to apply the negative sign when b is negative: (2x−1)^9 means b=−1, not b=1.
  • Computing C(n,r) with the wrong denominator — always use r! times (n−r)!.
  • Confusing the term number with the value of r: the 4th term means r=3.
  • Applying (a+b)^2 = a²+2ab+b² to higher powers — the middle terms will be wrong without using the theorem.

Formulas

Example

Pipe A fills in 3 h, Pipe B in 5 h, Drain C empties in 4 h. Rate = 1/3+1/5−1/4 = (20+12−15)/60 = 17/60. Time = 60/17 ≈ 3.53 h

Formula

Rate_combined = 1/t_A + 1/t_B − 1/t_C

Variables

t_A, t_B = time for A and B to finish alone (working); t_C = time for C to empty alone (draining); Rate_combined = net work rate

Application

Finding the combined rate when multiple workers/pipes work simultaneously, with one opposing

Example

Mix 20 L of 30% acid with x L of 50% acid to get 40%. 0.30(20)+0.50(x)=0.40(20+x). 6+0.5x=8+0.4x. 0.1x=2. x=20 L

Formula

C₁V₁ + C₂V₂ = C_f(V₁+V₂)

Variables

C₁, C₂ = concentrations of solutions being mixed; V₁, V₂ = volumes; C_f = final concentration

Application

Mixture problems involving two solutions combined to produce a desired concentration

Example

Two trains start from stations 300 km apart moving toward each other at 60 km/h and 90 km/h. Time to meet: 300/(60+90) = 300/150 = 2 h

Formula

D = R × T (Distance = Rate × Time)

Variables

D = distance (km or m); R = speed (km/h or m/s); T = time (h or s)

Application

All motion problems — rearrange as R=D/T or T=D/R as needed

Exam Tips

  • Work problems: always write the fraction of job done = Rate × Time. If the job is 'complete', set the fraction = 1.
  • Board exam work problems with drain pipes: Rate_net = Rate_fill − Rate_drain. A negative result means the tank never fills.
  • Motion problems: draw a simple sketch showing directions. Label it with D, R, T for each object.
  • Age problems: build a table with columns 'Now' and 'x years ago/from now' — fill in all ages systematically.
  • Mixture problems: always verify that V_final = V₁ + V₂ and C_final is between C₁ and C₂. If not, you set up the equation wrong.

Key Points

  • WORK PROBLEMS: Rate = 1/(time to complete alone). Combined rate = sum of individual rates. Time together = 1/(combined rate).
  • For work problems, identify who is working WITH (rates add) and who is working AGAINST (rates subtract), e.g., a drain pipe subtracts.
  • MIXTURE PROBLEMS: Amount of component in mixture = (concentration)(volume). Set up: initial + added = final.
  • MOTION PROBLEMS: Distance = Rate × Time (D=RT). For two objects, identify whether they move toward each other (rates add), away from each other (rates add), or in the same direction (rates subtract).
  • AGE PROBLEMS: Define the present age as the variable. Past age = present − years past. Future age = present + years future. Set up equations based on the stated relationships.
  • COIN/NUMBER PROBLEMS: The value of coins = (number of coins)(face value). Sum all values to get total.
  • Always define your variable clearly at the start of the solution. This is half the battle in word problems.
  • After solving, substitute back into the original problem statement (not just the equation) to verify the answer makes physical sense.

Definitions

Term

Work Rate

Definition

The fraction of a job completed per unit time, equal to 1/(time to complete alone). Unit: jobs per hour or jobs per day.

Importance

The fundamental concept of work problems. Add rates for workers doing the same job; subtract rates for opposing workers.

Term

Concentration

Definition

The fraction (or percentage) of a pure substance in a mixture. Always expressed as a decimal in calculations (30% → 0.30).

Importance

Must be applied to the volume to get the amount of pure substance. Setting up the amount equation is the key step.

Section Title

Word Problems — Work, Mixture, Age, and Motion

Common Mistakes

  • Adding times instead of rates in work problems: 'A takes 6 days and B takes 4 days, so together they take 10 days' is WRONG. Add rates: 1/6+1/4=5/12, so time=12/5=2.4 days.
  • In mixture problems, writing the equation using percent instead of decimal (using 30 instead of 0.30).
  • In motion problems, adding speeds when objects move in the same direction (should subtract) or subtracting when they move toward each other (should add).
  • In age problems, not adjusting ALL ages consistently (past or future). If you go back 5 years, every person is 5 years younger.
  • Setting up the equation without defining the unknown — leads to confusion and sign errors halfway through.

Connections

  • Quadratic equations appear in structural engineering (beam deflection, projectile trajectory of falling debris) and in the NSCP load combination expressions.
  • Geometric progressions model compound interest — directly applicable to engineering economics (PRC board exam topic) and present-worth/future-worth calculations.
  • Logarithms are the mathematical foundation of the decibel scale (noise in construction sites), the Richter scale, and Manning's roughness formula logarithmic expressions.
  • The Binomial Theorem is the basis of probability distributions (binomial distribution) used in quality control and reliability engineering.
  • Work-rate problems are directly analogous to parallel resistance in electrical engineering and parallel flow paths in hydraulics (Pipes in parallel — add conductances, not resistances).
  • Arithmetic progressions generalize to series solutions of differential equations encountered in Structural Analysis and Fluid Mechanics.
  • The discriminant concept extends to the characteristic equation of a second-order ODE — critical damping (D=0), overdamping (D>0), underdamping (D<0).
  • Sum and product of roots relate to Vieta's formulas, used in analysis of control systems and filter design in Electrical Engineering.
  • Mixture problems are the algebraic model behind concrete mix design (water-cement ratio, aggregate proportioning) and soil stabilization problems.
  • The change-of-base formula for logarithms is applied in the Hazen-Williams and Darcy-Weisbach equations when solving for friction factor iteratively.

Exam Strategy

In the MSTE board exam, Algebra and Fundamentals items are among the most straightforward to score if you have your formulas memorized and your problem-setup process is disciplined. Follow this 4-step board exam protocol: (1) READ the problem completely before writing anything — identify the type (AP, GP, quadratic, work, mixture, motion). (2) WRITE the governing formula immediately (do not derive from scratch under exam pressure). (3) SUBSTITUTE carefully, watching signs, especially for negative bases, negative common differences, and drain-type work problems. (4) VERIFY using sum/product of roots, back-substitution, or a quick sanity check (e.g., combined time must be less than the faster individual time). Prioritize: work problems and progressions appear on every board exam — master these first. Then quadratic equations and logarithms. Binomial theorem is high-yield but narrower in scope. Allocate no more than 3 minutes per algebra item. If stuck after 2 minutes, use the answer choices: substitute each back into the original equation and identify which one satisfies it (reverse-engineering). In the week before the exam, practice 20 word problems per day without a calculator for the first pass — this builds the setup instinct that saves time on exam day.

Quick Review Questions

Simplify: 8^(2/3) × 4^(−1/2).

8^(2/3) = (cube-root of 8)^2 = 2^2 = 4. 4^(−1/2) = 1/4^(1/2) = 1/2. Product = 4 × (1/2) = 2.

What is log₃(81)?

We need y such that 3^y = 81 = 3^4. Therefore log₃(81) = 4. Alternatively, log₃(81) = log(81)/log(3) = 1.90849/0.47712 = 4.

Find the discriminant of 3x²−7x+5=0 and state the nature of the roots.

D = b²−4ac = (−7)²−4(3)(5) = 49−60 = −11. Since D < 0, the equation has no real roots — the two roots are complex conjugates.

The 4th term of an AP is 13 and the 9th term is 33. Find the common difference d and the first term a₁.

Using a_n=a₁+(n−1)d: a₄=a₁+3d=13 ... (1); a₉=a₁+8d=33 ... (2). Subtracting (1) from (2): 5d=20 → d=4. From (1): a₁=13−12=1.

Find the sum to infinity of the GP: 12, 4, 4/3, ...

Common ratio r = 4/12 = 1/3. Since |r|=1/3 < 1, the infinite sum exists. S∞ = a₁/(1−r) = 12/(1−1/3) = 12/(2/3) = 12 × (3/2) = 18.

Find the 4th term of (x + 2)^7.

The (r+1)th term formula: T_(r+1)=C(n,r)·a^(n−r)·b^r. For the 4th term, r=3, n=7, a=x, b=2. T₄=C(7,3)·x^(7−3)·2^3 = 35·x⁴·8 = 280x⁴.

Worker A can finish a report in 8 hours, Worker B in 12 hours. Working together, how long will it take?

Rate_A = 1/8, Rate_B = 1/12. Combined rate = 1/8 + 1/12 = 3/24 + 2/24 = 5/24 job/hour. Time = 1/(5/24) = 24/5 = 4.8 hours.

How many liters of pure alcohol must be added to 40 L of a 20% alcohol solution to produce a 50% alcohol solution?

Let x = liters of pure alcohol (100% concentration) added. 0.20(40) + 1.00(x) = 0.50(40+x). 8 + x = 20 + 0.5x. 0.5x = 12. x = 24 L.

What value of k makes kx²−3x+3=0 have exactly one real solution?

Exactly one real solution means a repeated root, so the discriminant D = 0. D = (−3)²−4(k)(3) = 9−12k = 0. Solving: 12k = 9 → k = 9/12 = 3/4.

Two cars leave the same point traveling in opposite directions. Car A at 80 km/h and Car B at 60 km/h. How long until they are 420 km apart?

Opposite directions: effective separation rate = 80+60 = 140 km/h. Time = Distance/Rate = 420/140 = 3 hours.

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