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CELE Construction Management & MethodsConstruction Methods, Equipment and OperationsSummary

The Construction Methods, Equipment and Operations chapter sits at position 3rd in the CELE Construction Management & Methods review, and it is a topic you cannot leave to exam week. Professional Regulation Commission (PRC) — Board of Civil Engineering's recent CELE papers show a clear preference for Construction Methods, Equipment and Operations questions that mix definition recall with applied problem-solving. This summary gives you the overview you need before diving into the full study notes.

Exam context

Professional Regulation Commission (PRC) — Board of Civil Engineering runs the Civil Engineer Licensure Examination on May and November 2026. Its Construction Management & Methods section sits under a "Core" weighting, and Construction Methods, Equipment and Operations is the 3rd chapter in the 5-chapter CELE Construction Management & Methods rotation. The CELE passing mark is 70% weighted average, no sub-test below 50%, and the most recent 2026 paper drew about a meaningful share of questions from Construction Management & Methods.

Construction Methods, Equipment and Operations - Summary

Economical construction delivery depends critically on selecting appropriate methods and equipment, then operating them productively. This chapter addresses the quantitative foundations of construction productivity—how to calculate equipment output, match truck fleets to loaders, and account for soil volume changes during earthmoving operations. These are routine examination topics in the PRC Civil Engineer Licensure Examination, particularly under Construction Management & Methods. Mastery of the formulas, cycle-time analysis, and volume calculations presented here is essential for both the written licensure exam and professional practice in the Philippines, where projects range from roadworks to urban development requiring efficient resource deployment.

Key Concepts

The fundamental equation for hourly output is Output = (Capacity per cycle) × (Cycles per hour) × (Efficiency). Cycles per hour is calculated as 3600 divided by cycle time in seconds. Efficiency reflects both working minutes per hour (e.g., a 50-minute hour yields efficiency = 50/60 ≈ 0.833) and job/site conditions (weather, management, worker experience). For excavators and loaders, a bucket fill factor (typically 0.85–1.0) is applied; for haulers, swell and shrinkage factors modify volumes. This formula is the backbone of all equipment productivity calculations and appears frequently on board exams.

Concept

Equipment Productivity Formula

Importance

Critical foundation for fleet sizing, project scheduling, and cost estimation. Incorrect application of efficiency or cycle-time units is a common exam pitfall.

Cycles per hour = 3600 seconds ÷ cycle time (in seconds). Cycle time includes all phases: load (for excavators/loaders), haul (for trucks), dump, and return. The 3600 constant converts seconds to an hourly basis. For example, a 30-second cycle yields 3600/30 = 120 cycles per hour. This is always the starting point before applying efficiency and bucket fill factors.

Concept

Cycles per Hour Calculation

Importance

Fundamental unit-conversion step; errors here propagate to all downstream calculations. Must always use seconds, not minutes, in this formula.

Efficiency accounts for realistic working conditions. A 50-minute hour (50 minutes of productive work per 60-minute hour) gives efficiency = 50/60 = 0.833. This reflects downtime for delays, breaks, setup, and weather. In the Philippines, tropical conditions (monsoon, heat) and logistics constraints often reduce efficiency below 0.90. Different site conditions may yield 0.70–0.85 efficiency on challenging projects. Engineers must adjust based on project specifics; 0.83 is a common default in exam problems.

Concept

Efficiency and Working Minutes per Hour

Importance

Often overlooked by students, but essential for realistic productivity estimates. Exam problems may specify efficiency as working minutes per hour or as a direct percentage; careful reading is required.

Bucket fill factor (typically 0.85–1.0) accounts for incomplete filling of excavator or loader buckets. Loose, wet, or sticky soil may not completely fill the bucket; hard, well-compacted material may overfill slightly. For standard conditions, use 0.90; for loose soils, 0.85; for dense soils or rock, up to 1.0. The formula becomes Output = Bucket capacity × Cycles/hr × Efficiency × Fill factor. This factor is multiplicative, not added to efficiency.

Concept

Bucket Fill Factor

Importance

Often grouped with efficiency but distinct; applying both correctly is necessary for accurate output estimates on exam problems involving soil excavation.

When soil is excavated from its in-place (bank) state, it breaks up and occupies more volume. Swell factor (typically 15–30%) increases bank volume to loose volume for haul-truck sizing. Formula: V_loose = V_bank × (1 + swell factor). For example, 100 m³ of bank soil at 25% swell becomes 125 m³ loose. This affects truck count, haul equipment capacity, and project duration. Sandy soils swell 10–15%; clays 20–30%; rock may swell 40% or more depending on blasting.

Concept

Swell (Volume Increase from Bank to Loose)

Importance

Essential for calculating haul volumes and truck requirements. Students often confuse swell with shrinkage; this is a common exam error. Swell is applied when soil leaves the borrow pit; shrinkage is applied when fill is compacted.

When loose soil is compacted to form a fill or embankment, it shrinks below its bank volume. Shrinkage factor (typically 5–15%) reduces the loose or bank volume when finding the required borrow. Formula: V_bank = V_compacted ÷ (1 − shrinkage factor). For example, to obtain 100 m³ compacted at 10% shrinkage, 100 ÷ 0.90 = 111.1 m³ of bank soil is needed. This calculation is crucial for bid preparation and material planning in Philippine projects.

Concept

Shrinkage (Volume Reduction During Compaction)

Importance

Directly affects project cost and resource planning. Rearrangement of the formula (V_compacted = V_bank × (1 − shrinkage)) may appear in exam problems; ensure you can work both directions.

To keep a loader or excavator productively busy, the truck fleet must be sized so that trucks arrive at approximately the rate the loader fills them. The formula is N = Truck cycle time ÷ Truck load time, where truck cycle = load time + haul time + dump time + return time. For example, if a truck cycle is 24 min and load time is 4 min, then N = 24 ÷ 4 = 6 trucks. Too few trucks cause loader idle time; too many cause truck queue and wasted cost. The result is typically rounded up to ensure continuous loader operation.

Concept

Fleet Matching: Number of Haul Trucks

Importance

Critical for fleet economics and schedule optimization. Exam problems often ask for truck count given cycle times; incorrect rounding (down instead of up) is a common mistake.

Truck cycle time = load time (time for loader to fill one truck) + haul time (travel from pit to site) + dump time (unload at destination) + return time (empty return to pit). Each component must be estimated from site conditions: haul distance (km), travel speed (km/h), dump logistics, and loader fill time. Return time is often shorter than haul time if using a faster route or lighter load. Accurate cycle-time estimation is essential for fleet sizing and is frequently tested on boards.

Concept

Truck Cycle Time Components

Importance

Underestimating haul distance or overestimating travel speed leads to too few trucks and loader starvation. Overestimating leads to excess trucks and idle cost. Realistic estimation requires site knowledge and sound judgment.

Excavators (0-range or mass-excavation) with buckets are used for digging and loading into trucks. Loaders are multipurpose (load trucks, spread material, grade). Dozers are used for pushing, spreading, and rough grading. Scrapers are economical for moving material over moderate distances (500–2000 m). Haulers (dump trucks) move material from pit to site or fill area. Graders finish surfaces. Each equipment type has optimal operating ranges; selecting the wrong type for a job leads to poor productivity and cost overruns. Philippine projects often combine multiple equipment types; understanding which tool suits which task is crucial.

Concept

Earthmoving Equipment Types and Applications

Importance

Exam questions may ask to identify the appropriate equipment or analyze productivity of a given fleet. Knowledge of typical output rates and cycle times is helpful.

Concreting involves five main stages: (1) Batching—mixing cement, aggregate, water, and admixtures to specification (per ACI 318-19 or PCA guidelines); (2) Transport—moving concrete by mixer truck or pump to the placement point; (3) Placing—depositing concrete into formwork via chute, pump, or bucket; (4) Consolidation—using vibration (internal or external) to remove air voids and ensure full contact with formwork; (5) Curing—maintaining moisture and temperature per ACI 318 (typically 7 days for standard Portland cement, longer in hot/dry climate such as the Philippines). Each stage affects concrete quality and schedule; delays in any stage can compromise subsequent work.

Concept

Concreting Operations: Batching, Transport, Placing, Consolidation, and Curing

Importance

Understanding the concreting process is essential for project scheduling and quality control. Exam questions may ask about optimal transport distance, pump size, vibration time, or curing requirements per ACI 318.

Formwork must resist fresh-concrete pressure (hydrostatic load = ρgh, where ρ ≈ 2400 kg/m³ for concrete, g ≈ 9.8 m/s², h = depth). Pressure increases linearly with depth; failure typically occurs at the base. Falsework (temporary support) must carry formwork, concrete, and live loads (workers, equipment). Improper bracing and insufficient capacity lead to collapse—a common source of construction accidents and failures. Design requires structural analysis per NSCP 2015 (National Structural Code of the Philippines) and ACI guidance. Form ties, struts, and bracing must be calculated and inspected.

Concept

Formwork and Falsework Design

Importance

Formwork failures are serious and occasionally fatal. Exam questions often test pressure calculations (P = ρgh) and understanding of bracing requirements. Knowledge of form tie spacing and strut calculations is typical for licensure-level questions.

Equipment productivity must be balanced against equipment cost, labor cost, and site conditions. A highly efficient large loader may be uneconomical on a small project; a smaller, lower-cost unit may be more appropriate. Similarly, fleet matching trades off truck investment against loader idle time. The goal is to minimize total cost per unit output, not to maximize output alone. This requires sensitivity analysis: calculating output and cost under different equipment scenarios, then selecting the economically optimal combination. On Philippine projects, equipment availability and rental rates significantly influence this decision.

Concept

Productivity Optimization and Economic Balance

Importance

Exam may include scenarios asking for the most economical equipment selection or fleet size. This requires both calculation skills and judgment; purely mathematical answers without economic reasoning may not score fully.

Important Points

  • Output = Capacity × Cycles/hr × Efficiency. Cycles/hr = 3600 ÷ cycle time (seconds). Always convert cycle time to seconds.
  • Efficiency reflects working minutes per hour and site conditions. A 50-min hour yields 0.833 efficiency; adjust for actual project conditions.
  • Bucket fill factor is separate from efficiency and is multiplied (not added) in the productivity formula.
  • Swell: V_loose = V_bank × (1 + swell factor). Occurs when soil is excavated; increases haul volume.
  • Shrinkage: V_bank = V_compacted ÷ (1 − shrinkage factor). Occurs during compaction; reduces fill volume below bank.
  • Fleet matching: N = Truck cycle time ÷ Truck load time. Round up to ensure loader is not idle.
  • Truck cycle = load + haul + dump + return. Each component must be realistically estimated.
  • Fresh concrete pressure: P = ρgh (ρ ≈ 2400 kg/m³). Pressure increases linearly with depth; base pressure is maximum.
  • Formwork must be designed and braced per NSCP 2015 and ACI 318 to prevent collapse.
  • Concreting requires coordinated timing of batching, transport, placement, consolidation, and curing. Delays in any stage affect schedule and quality.
  • Common exam errors: using minutes instead of seconds in cycle-time formula; forgetting efficiency factor; confusing swell with shrinkage; rounding truck count down instead of up.
  • Economic optimization balances equipment cost, labor, and productivity; highest output is not always most economical.

Chapter Objectives

  • Calculate hourly equipment productivity using capacity, cycle time, and efficiency factors
  • Determine the optimal number of haul trucks to match loader productivity (fleet matching)
  • Apply swell and shrinkage factors to account for soil volume changes in earthwork operations
  • Understand the relationship between cycle time, efficiency, and economic equipment selection
  • Analyze concreting, formwork, and excavation operations to identify productivity constraints and optimization opportunities
  • Apply board-style problem solving to real-world construction scenarios on Philippine projects

Concept Relationships

Once the loader's (or excavator's) output is calculated, the number of trucks required to match that output is determined by the truck cycle time and load time. The loader output (m³/hr) divided by the truck payload and adjusted for the truck cycle duration determines how many trucks prevent idle time. This is the practical feedback loop: calculate equipment productivity, then size the fleet to sustain it.

Relationship

Equipment Productivity → Fleet Sizing

Bank volume (in-place) is converted to loose volume using swell when excavating and hauling; loose volume is converted to compacted volume using shrinkage when placing fill. These factors are inverses: swell adds volume, shrinkage removes it. Students must apply them in the correct direction. For example, excavating 100 m³ bank at 25% swell yields 125 m³ to haul; if that loose material is then compacted at 10% shrinkage, the final volume is 125 × 0.90 = 112.5 m³ compacted (less than bank due to net shrinkage).

Relationship

Swell and Shrinkage → Volume Calculations

Cycle time determines productivity (cycles/hr = 3600/t_cycle); efficiency reduces that productivity to realistic levels. Together, they define how long a project will take. For example, if a loader outputs 150 m³/hr and 5000 m³ must be moved, the time is 5000 ÷ 150 ≈ 33.3 hours of actual operation. Site conditions (weather, access, breaks) extend this to calendar days; realistic scheduling requires adding contingency (typically 10–20% on Philippine projects due to tropical weather).

Relationship

Cycle Time and Efficiency → Project Duration

Truck cycle time and load time directly determine fleet size via N = cycle / load. A longer haul distance increases cycle time, requiring more trucks—raising capital cost and potentially adding idle trucks. A faster loader reduces load time, requiring fewer trucks. This trade-off is central to fleet economics: investing in a faster loader may save truck cost; investing in trucks may be cheaper than upgrading equipment. The economic optimum depends on rental rates, fuel costs, and job duration.

Relationship

Truck Cycle and Load Time → Fleet Economics

Concrete pressure P = ρgh varies with depth and concrete density. Formwork (boards, ties, struts) must be designed to resist this pressure. Base pressure is highest; formwork and bracing must be stronger (closer spacing, larger members) near the base. Pressure also depends on pour rate and temperature; fast pours and warm weather increase pressure. Formwork design (per NSCP 2015 and ACI) uses these pressures to size members and calculate tie spacing—a direct engineering chain from material property (concrete density and hydrostatic pressure) to structural member sizing.

Relationship

Fresh Concrete Pressure → Formwork Design

Batching → Transport → Placement → Consolidation → Curing form a sequential process. Delay or failure in any stage ripples forward. For example, delayed truck transport may cause concrete to set before placement, reducing workability; inadequate vibration creates voids and weak concrete; insufficient curing reduces strength. Scheduling and quality control must manage all five stages together, not independently. On Philippine projects, tropical heat accelerates setting and increases curing challenges; this interdependency is critical for success.

Relationship

Concreting Operations Sequence → Schedule and Quality

Excavator output (affected by efficiency and fill factor) determines how many truckloads are generated per hour. Swell increases the volume per truckload. Together, these factors determine truck utilization and haul cost. For example, if excavator output is low due to poor efficiency, fewer truckloads are generated per hour, leaving trucks idle; swell increases payload per truck, partially offsetting low excavator output. Optimizing haul cost requires balancing these factors.

Relationship

Efficiency and Swell → Haul Cost per Unit Volume

Practical Applications

Scenario

Earthmoving Project in Metro Manila: Excavation and Fill

Solution

Step 1: Excavator output. Cycles/hr = 3600/30 = 120. Efficiency = 50/60 = 0.833. Output = 1.5 × 120 × 0.833 × 0.9 = 150 m³/hr. Step 2: Truck cycle. Load time = 6 m³ ÷ 150 m³/hr = 0.04 hr = 2.4 min (approximately). Haul time = 15 km ÷ 30 km/h = 0.5 hr = 30 min. Dump time = 5 min. Return time = 15 km ÷ 40 km/h = 0.375 hr = 22.5 min. Cycle = 2.4 + 30 + 5 + 22.5 = 59.9 min ≈ 60 min. Step 3: Number of trucks. N = 60 ÷ 2.4 = 25 trucks (rounded up). Step 4: Loose volume. V_loose = 50,000 × (1.25) = 62,500 m³. Step 5: Project duration. Operating hours = 62,500 ÷ 150 = 416.7 hr. Calendar days = 416.7 ÷ 8 = 52.1 days ≈ 11 weeks. (In practice, add 10–20% for weather delays in the Philippines.)

Application

A contractor excavates 50,000 m³ of bank soil (25% swell) from a foundation pit and hauls it to a fill site 15 km away. An excavator (1.5 m³ bucket, 30 s cycle, 0.9 fill factor, 50-min hour efficiency) loads 6-m³ haul trucks. Each truck's haul distance is 15 km at average 30 km/h, dump time is 5 min, return is 15 km at 40 km/h. Calculate: (a) excavator output, (b) truck cycle time, (c) number of trucks required, (d) total loose volume to haul, (e) project duration if equipment operates 8 hours per day.

Scenario

Concrete Paving Project: Slipform Paver with Pump and Consolidation

Solution

Production chain: Batching (50 m³/hr) → Pump (30 m³/hr) → Placement & Consolidation (25 m³/hr) → Curing (7 days). Bottleneck is placement & consolidation at 25 m³/hr. In an 8-hr day, 25 × 8 = 200 m³ can be placed and consolidated; target is 500 m³/day, so 500 ÷ 200 = 2.5 days per day equivalent—impossible with one crew. Solution: operate multiple paver crews or extended hours (say 16 hr/day), or improve placement rate (add second pump, upgrade paver). Curing delay: at 200 m³/day placement with 7-day curing, inventory of curing concrete = 200 × 7 = 1400 m³ tied up. Project duration ≈ 20,000 m³ ÷ 200 m³/day = 100 days placement + 7 days final cure ≈ 107 days (15+ weeks). This analysis guides equipment selection and crew sizing.

Application

A 20 km highway paving project requires continuous concrete placement at 500 m³/day. Batching plant produces 50 m³/hr. Pump can deliver 30 m³/hr to the paver. Placement and vibration (consolidation) occurs at 25 m³/hr. Curing (by fog spray or wet burlap per ACI 318) takes 7 days minimum. Identify the bottleneck and calculate the impact on project schedule.

Scenario

Building Excavation in Poor Soil (Tropical Moisture and Weak Ground)

Solution

Step 1: Loader output. Cycles/hr = 3600/35 ≈ 102.9. Efficiency = 40/60 = 0.667 (low, due to tropical wet conditions). Output = 2.0 × 102.9 × 0.667 × 0.85 = 116.6 m³/hr. Step 2: Project duration. Loose volume to haul = 15,000 × (1.20) = 18,000 m³. Operating hours = 18,000 ÷ 116.6 = 154.2 hr. Days at 6 hr/day = 154.2 ÷ 6 = 25.7 days ≈ 26 days (plus weather/holiday contingency: ~35 calendar days for realistic schedule). Step 3: Bank volume for backfill. To obtain 15,000 m³ compacted backfill at 15% shrinkage, V_bank = 15,000 ÷ (1 − 0.15) = 15,000 ÷ 0.85 = 17,647 m³. The excavated soil (15,000 m³ bank at 20% swell = 18,000 m³ loose) is more than sufficient for backfill; 18,000 ÷ 1.15 ≈ 15,652 m³ compacted, covering the 15,000 m³ requirement with ~652 m³ surplus for grading and settlement.

Application

In a soft-clay site in Laguna province, a building excavation requires 15,000 m³ (bank volume, 20% swell, 15% shrinkage when compacted as backfill). Site is wet due to monsoon; equipment efficiency is reduced to 40 min/hr. A 2.0 m³ loader with 35 s cycle and 0.85 fill factor is available. Calculate: (a) realistic loader output given low efficiency, (b) project duration if operating 6 hr/day (accounting for equipment maintenance and site conditions), (c) bank volume needed to backfill the excavation to grade.

Scenario

Formwork Design for 5 m Deep Foundation Wall Under NSCP 2015 and ACI 318

Solution

Concrete pressure P = ρgh = 2400 kg/m³ × 9.8 m/s² × 5 m ≈ 117.6 kPa (or ~1.2 metric tons per m² at the base). At 1 m/hr pour rate, concrete at depth h at time t has pressure P(h,t) = ρg(h − ct), where c ≈ 0.6 m/hr is the rate of strength development (approximate). For initial phase (setting before full strength), base pressure is highest. ACI 318 and NSCP 2015 allow reduced pressure (∼0.8 P_max) if pour rate is slow or form releases early. Formwork design: plywood sheathing, joists (typically 2×6 or 2×8 timber), stringers, and horizontal tie rods must resist 117.6 kPa. Form ties (typically 12 mm steel rods) are spaced vertically at ~1.5–2.0 m intervals near the base; spacing decreases toward bottom due to increasing pressure. Struts and diagonal bracing support the formwork frame. Each design element is calculated per NSCP Section 6 (Loads and Forces) and ACI 318 Chapter 4 (Durability, Concrete Quality, Mixing, and Placing). Formwork failures from inadequate pressure calculation are serious; proper analysis is non-negotiable in practice.

Application

A reinforced concrete foundation wall is 5 m deep, poured continuously at an average rate of 1 m/hr (typical for vertical placement). Fresh concrete density ρ = 2400 kg/m³. Calculate the maximum fresh concrete pressure at the base and discuss formwork and tie-spacing implications per NSCP 2015 and ACI 318-19.

Scenario

Road Construction Fleet Matching: Dozer and Haul Trucks for Embankment Fill

Solution

Step 1: Dozer productivity (simplified). 5 min per 6 m³ implies 6 ÷ (5/60) = 72 m³/hr dozer capacity (assuming 50-min hour efficiency, reduce to ~60 m³/hr). Step 2: Truck fleet. Truck cycle for 8 km haul: haul time (8 km ÷ 25 km/h avg) = 19.2 min, dump 3 min, return 8 km ÷ 30 km/h = 16 min, total ≈ 38 min. Load time (truck capacity 6 m³, dozer fills at 72 m³/hr) = 6 ÷ 72 × 60 ≈ 5 min. Number of trucks = 38 ÷ 5 = 7.6 → round up to 8 trucks. Step 3: Project duration. Loose volume = 100,000 ÷ (1 − 0.10) [assume 10% shrinkage] = 111,111 m³. At 60 m³/hr dozer rate, hours = 111,111 ÷ 60 ≈ 1852 hr. Operating 8 hr/day = 1852 ÷ 8 ≈ 232 days or ~47 weeks (add contingency: ~55 weeks realistic). This analysis drives equipment rental decisions and bid pricing.

Application

A road embankment requires 100,000 m³ compacted fill. Borrow material is 8 km from the site. A dozer spreads and grades the fill; haul trucks deliver material. Dozer cycle (push, return, spread) is 5 min per 6 m³ loose load; truck cycle includes haul and return. Estimate truck requirements and project duration to keep dozer busy.

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In summary

Construction Methods, Equipment and Operations is a quantitatively rigorous chapter essential for professional practice and PRC licensure examination success. The core formulas—Output = Capacity × Cycles/hr × Efficiency, and Fleet Sizing = Cycle Time ÷ Load Time—are used repeatedly in real-world project planning, cost estimation, and schedule development. Students must master: (1) correct unit conversion (seconds in cycle-time formula, always), (2) realistic efficiency estimation (accounting for tropical climate and site conditions specific to the Philippines), (3) directional application of swell and shrinkage (swell enlarges haul volume; shrinkage reduces compacted fill below bank), and (4) economic trade-offs in equipment selection and fleet sizing. Formwork and concreting operations introduce structural design (fresh concrete pressure per NSCP 2015 and ACI 318) and sequential process management. Common exam errors stem from unit mistakes, forgetting efficiency, confusing swell/shrinkage direction, and rounding truck counts downward instead of up—all avoidable with careful problem setup and verification. This chapter bridges theory and practice: the formulas are simple, but their correct application under realistic site constraints (weather, logistics, material properties) requires judgment and experience. For Philippine civil engineers, competency in these methods is foundational to project success, cost control, and professional credibility.

Next steps

To deepen mastery of this chapter, students should: (1) Solve 5–10 additional board-style problems varying equipment type, haul distance, and site conditions (wet vs dry, remote vs urban), paying particular attention to unit conversion and efficiency adjustment. (2) Work through complete project case studies (e.g., DPWH or MMDA projects) calculating equipment requirements, schedule, and rough cost. (3) Study NSCP 2015 Chapter 4 (Loads and Forces) and Chapter 6 (Concrete) for formwork pressure and concreting requirements; review ACI 318-19 Chapters 3–4 for concrete specifications and curing. (4) Visit an active construction site (with permission) to observe equipment productivity, cycle times, and site delays in real conditions—particularly valuable for understanding how tropical weather and logistics affect efficiency in Philippine projects. (5) Practice problems under time pressure (30–40 minutes for a complex multi-part scenario) to build speed and confidence for the licensure examination. (6) Form study groups and discuss the economic trade-offs in fleet sizing and equipment selection; peer explanation reinforces conceptual understanding. Finally, review the common pitfalls mind map before every practice session and exam to internalize the correct approaches.

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