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BFP Entrance Exam Numerical AbilityAlgebra, Exponents & Number SeriesFlash Cards

Flashcards specifically for Algebra, Exponents & Number Series in the BFP Entrance Exam 2026. Every card has been tuned to match Bureau of Fire Protection (BFP)'s preferred question style. Practise them during your commute, at lunch, or before bed — they are designed for short bursts of high-retention review.

Exam context

For the Bureau of Fire Protection Entrance Examination, Bureau of Fire Protection (BFP) tests Numerical Ability under a "Core" label, with Algebra, Exponents & Number Series in the 5th slot across 9 chapters. BFP Entrance Exam candidates must clear the BFP-set percentile (typically 70%+) cut on the 2026 paper, which draws about a meaningful share of Numerical Ability questions. Date to watch: Announced by BFP per cycle.

Algebra, Exponents & Number Series - Flashcards

Master the essential concepts of algebra, exponents, and number series with these comprehensive flashcards. These cards cover fundamental algebraic operations, laws of exponents, and pattern recognition in number sequences - key skills for success in Philippine civil service exams and college entrance tests like UPCAT, NMAT, and ACET.

Cards

What is the Product Rule for exponents and how do you apply it?

The Product Rule states that when multiplying two exponents with the same base, you keep the base and add the powers: a^m × a^n = a^(m+n). Example: 5^3 × 5^2 = 5^(3+2) = 5^5. This rule works for any real numbers m and n, including negative exponents.

Tags

  • product_rule
  • exponent_operations
  • intermediate

Topic

Laws of Exponents

Card Id

FC1

Difficulty

intermediate

Image Prompt

Quotient Rule

The Quotient Rule for exponents: When dividing two exponents with the same base, keep the base and subtract the powers: a^m ÷ a^n = a^(m-n). Example: 10^5 ÷ 10^3 = 10^(5-3) = 10^2 = 100. This helps avoid negative exponents by putting the answer in the appropriate position.

Tags

  • definition
  • quotient_rule
  • basic

Topic

Laws of Exponents

Card Id

FC2

Difficulty

basic

Image Prompt

What happens when you raise a power to another power?

Use the Power Rule: (a^m)^n = a^(mn). Multiply the exponents together. Example: (2^3)^4 = 2^(3×4) = 2^12 = 4,096. Another example: Express 8^3 as a power with base 2: Since 8 = 2^3, then 8^3 = (2^3)^3 = 2^9.

Tags

  • power_rule
  • exponent_operations
  • intermediate

Topic

Laws of Exponents

Card Id

FC3

Difficulty

intermediate

Image Prompt

Zero-Exponent Rule

Any non-zero number raised to the power of zero equals 1: a^0 = 1 (where a ≠ 0). Examples: 5^0 = 1, (-3)^0 = 1, (999)^0 = 1. This rule is fundamental for simplifying expressions and solving equations.

Tags

  • definition
  • zero_exponent
  • basic

Topic

Laws of Exponents

Card Id

FC4

Difficulty

basic

Image Prompt

How do you handle negative exponents?

Negative Exponent Rule: a^(-m) = 1/a^m. A negative exponent means take the reciprocal and make the exponent positive. Example: 2^(-2) = 1/2^2 = 1/4. For fractions: (3/4)^(-2) = (4/3)^2 = 16/9.

Tags

  • negative_exponents
  • reciprocal
  • intermediate

Topic

Laws of Exponents

Card Id

FC5

Difficulty

intermediate

Image Prompt

Fractional Exponent Rule

Fractional exponents represent roots: a^(1/n) = ⁿ√a. The denominator of the fraction becomes the index of the root. Example: 4^(1/2) = √4 = 2, 8^(1/3) = ∛8 = 2. For a^(m/n) = ⁿ√(a^m) or (ⁿ√a)^m.

Tags

  • definition
  • fractional_exponents
  • advanced

Topic

Laws of Exponents

Card Id

FC6

Difficulty

advanced

Image Prompt

What are the 6 steps for simplifying exponential expressions?

1. Apply Product Rule (add exponents with same base) 2. Apply Quotient Rule (subtract exponents) 3. Apply Power Rule (multiply exponents) 4. Apply Zero-Exponent Rule (anything^0 = 1) 5. Apply Negative Exponent Rule (move to opposite position) 6. Simplify coefficients and reduce fractions

Tags

  • process
  • systematic_approach
  • intermediate

Topic

Simplifying Expressions

Card Id

FC7

Difficulty

intermediate

Image Prompt

Arithmetic Sequence

A sequence where the difference between consecutive terms is constant. Formula for nth term: aₙ = a₁ + (n-1)d, where a₁ is the first term, d is the common difference, and n is the term number. Example: 2, 5, 8, 11, 14... has d = 3.

Tags

  • definition
  • arithmetic_sequence
  • basic

Topic

Number Series

Card Id

FC8

Difficulty

basic

Image Prompt

How do you identify and continue a geometric sequence?

Geometric Sequence: Each term is obtained by multiplying the previous term by a constant ratio (r). Formula: aₙ = a₁ × r^(n-1). Example: 3, 6, 12, 24, 48... has r = 2. To find the next term, multiply the last term by the common ratio: 48 × 2 = 96.

Tags

  • geometric_sequence
  • pattern_recognition
  • intermediate

Topic

Number Series

Card Id

FC9

Difficulty

intermediate

Image Prompt

What characterizes a Fibonacci sequence?

Fibonacci Sequence: Each term is the sum of the two preceding terms. Pattern: aₙ = aₙ₋₁ + aₙ₋₂. Example: 1, 1, 2, 3, 5, 8, 13, 21... where 1+1=2, 1+2=3, 2+3=5, etc. This pattern appears frequently in nature and mathematics.

Tags

  • fibonacci
  • sum_pattern
  • intermediate

Topic

Number Series

Card Id

FC10

Difficulty

intermediate

Image Prompt

Solve: 8x⁵/4x² = ?

Apply the quotient rule and simplify coefficients: 8x⁵/4x² = (8/4) × (x⁵/x²) = 2 × x⁵⁻² = 2x³ Always separate coefficients from variables and apply exponent rules to each part.

Tags

  • application
  • quotient_rule
  • basic

Topic

Algebraic Simplification

Card Id

FC11

Difficulty

basic

Image Prompt

What is an exponent sequence and how do you recognize it?

Exponent Sequence: All terms are perfect powers (squares, cubes, etc.). Two types: 1. Perfect squares: 4, 9, 16, 25, 36, 49... (2², 3², 4², 5², 6², 7²...) 2. Perfect cubes: 8, 64, 216, 512, 1000... (2³, 4³, 6³, 8³, 10³...) Look for patterns in the base numbers or exponents.

Tags

  • exponent_sequence
  • perfect_powers
  • intermediate

Topic

Number Series

Card Id

FC12

Difficulty

intermediate

Image Prompt

Compare arithmetic and geometric sequences

Arithmetic Sequence: - Constant difference between terms - Linear growth pattern - Formula: aₙ = a₁ + (n-1)d - Example: 5, 8, 11, 14... Geometric Sequence: - Constant ratio between terms - Exponential growth/decay - Formula: aₙ = a₁ × r^(n-1) - Example: 5, 10, 20, 40...

Tags

  • comparison
  • sequence_types
  • intermediate

Topic

Number Series

Card Id

FC13

Difficulty

intermediate

Image Prompt

In the sequence 3, 8, 15, 24, 35, ?, what's the pattern and next term?

This is an alternating sequence. Find the differences: 8-3=5, 15-8=7, 24-15=9, 35-24=11 The differences form: 5, 7, 9, 11... (increasing by 2 each time) Next difference: 11+2=13 Next term: 35+13=48

Tags

  • application
  • alternating_sequence
  • advanced

Topic

Number Series

Card Id

FC14

Difficulty

advanced

Image Prompt

What is a mixed sequence in number series?

Mixed Sequence: Uses multiple arithmetic operations in a pattern. Example: 10, 22, 46, 94, 190, ? Pattern: multiply by 2, then add 2 10×2+2=22, 22×2+2=46, 46×2+2=94, 94×2+2=190, 190×2+2=382 These sequences require identifying the combination of operations used.

Tags

  • mixed_sequence
  • multiple_operations
  • advanced

Topic

Number Series

Card Id

FC15

Difficulty

advanced

Image Prompt

Simplify: (3x²y⁻²)(4xy³)

Multiply coefficients and apply product rule for exponents: (3x²y⁻²)(4xy³) = (3×4)(x²×x¹)(y⁻²×y³) = 12x²⁺¹y⁻²⁺³ = 12x³y¹ = 12x³y Remember: when multiplying with same base, add the exponents.

Tags

  • application
  • product_rule
  • intermediate

Topic

Algebraic Operations

Card Id

FC16

Difficulty

intermediate

Image Prompt

What is a two-stage sequence?

Two-Stage Sequence: The differences between consecutive terms form their own pattern (arithmetic or geometric). Example: 1, 3, 5, 9, 11 - missing terms can be found by analyzing that differences should be 2, 2, 4, 2, following a pattern. First find the pattern in differences, then fill in missing terms.

Tags

  • two_stage_sequence
  • difference_patterns
  • advanced

Topic

Number Series

Card Id

FC17

Difficulty

advanced

Image Prompt

Evaluate: 2⁻³ × 2⁵ ÷ 2¹

Apply exponent rules step by step: 2⁻³ × 2⁵ ÷ 2¹ = 2⁻³⁺⁵⁻¹ = 2¹ = 2 Alternatively: 2⁻³ × 2⁵ = 2² = 4, then 4 ÷ 2¹ = 4 ÷ 2 = 2 Both methods give the same answer.

Tags

  • application
  • multiple_operations
  • intermediate

Topic

Exponent Calculations

Card Id

FC18

Difficulty

intermediate

Image Prompt

Combination Sequence

Combination Sequence: Uses elements from different sequence types (like alternating between operations). Example: 3, 3, 3, 6, 3, 9, 3, 12... Pattern: Odd positions stay constant (3), even positions increase by 3 (3, 6, 9, 12...) This combines constant and arithmetic patterns.

Tags

  • definition
  • combination_sequence
  • advanced

Topic

Number Series

Card Id

FC19

Difficulty

advanced

Image Prompt

What are the key strategies for solving number series problems?

1. Look for constant differences (arithmetic) 2. Check for constant ratios (geometric) 3. Examine if terms are perfect powers 4. Try sum patterns (Fibonacci-type) 5. Look for alternating patterns 6. Check differences between differences 7. Consider mixed operations 8. Identify if it's a combination sequence Always verify your pattern with given terms before finding the answer.

Tags

  • strategy
  • systematic_approach
  • intermediate

Topic

Problem-Solving Strategies

Card Id

FC20

Difficulty

intermediate

Image Prompt

Tag Distribution

Basic

4

Advanced

6

Strategy

1

Comparison

1

Definition

5

Application

4

Intermediate

10

Topic Distribution

Number Series

8

Laws Of Exponents

6

Algebraic Operations

2

Problem Solving Strategies

4

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