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UPCAT PhysicsWork, Energy & ImpulseRevision Notes

Final-week revision notes for Work, Energy & Impulse. If you have already studied the full chapter, this page is your go-to refresher before sitting the UPCAT. Compact, high-yield, and aligned with what University of the Philippines tests in the Physics subtest.

Exam context

The University of the Philippines College Admission Test is conducted by University of the Philippines and is scheduled for Mid-2026 (announced by UP Admissions). The Physics subtest is marked as "Core" in the official pattern, and Work, Energy & Impulse appears in position 4th of 6 in the UPCAT Physics review rotation. Passing mark: UPG ≤ 2.2 typical. Recent UPCAT 2026 papers have drawn roughly 20 questions from this subject.

Work, Energy & Impulse - Revision notes

Work, Energy, and Impulse are fundamental concepts in Physics that explain how forces affect motion and energy transfer. This chapter covers the mathematical relationships between work done by forces, different forms of energy, and momentum changes in collisions. Understanding these concepts is crucial for solving problems in mechanics and analyzing real-world situations like sports, transportation, and machinery.

Sections

Formulas

Example

A person pulls a box with 50 N force at 30° angle, moving it 10 m. W = 50 × 10 × cos(30°) = 433 J

Formula

W = F × d × cos θ

Variables

W = work (J), F = force (N), d = displacement (m), θ = angle between force and displacement

Application

Calculate work done by any force acting at an angle to the direction of motion

Example

A motor does 1000 J of work in 5 seconds. P = 1000/5 = 200 W

Formula

P = W/t or P = F × v

Variables

P = power (W), W = work (J), t = time (s), F = force (N), v = velocity (m/s)

Application

Calculate power output of engines, motors, or human activities

Exam Tips

  • Always identify the force, displacement, and angle between them before calculating work
  • Remember: no displacement = no work, even with large forces
  • For power problems, check if you need W/t or F×v formula
  • Draw free body diagrams to visualize force directions clearly

Key Points

  • Work is done when a force acts on an object and causes displacement in the direction of the force
  • Work is a scalar quantity measured in joules (J)
  • Power measures how quickly work is done, measured in watts (W)
  • No work is done if force is perpendicular to displacement or if there's no displacement
  • Negative work occurs when force opposes motion (like friction or air resistance)

Definitions

Term

Work

Definition

The energy transferred to or from an object via the application of force along a displacement

Importance

Fundamental concept linking force, motion, and energy transfer in mechanical systems

Term

Power

Definition

The rate at which work is done or energy is transferred per unit time

Importance

Essential for understanding efficiency of machines and energy consumption

Section Title

Work and Power

Common Mistakes

  • Confusing work with force - work requires both force AND displacement
  • Forgetting to use the cosine of the angle when force is not parallel to displacement
  • Mixing up power and work units - power is watts (J/s), work is joules
  • Assuming work is always positive - it can be negative when force opposes motion

Formulas

Example

A 2 kg ball moving at 10 m/s has KE = ½ × 2 × 10² = 100 J

Formula

KE = ½mv²

Variables

KE = kinetic energy (J), m = mass (kg), v = velocity (m/s)

Application

Calculate energy of moving objects like cars, projectiles, or rotating wheels

Example

A 5 kg book on a 2 m shelf has PE = 5 × 9.8 × 2 = 98 J

Formula

PE = mgh

Variables

PE = gravitational potential energy (J), m = mass (kg), g = 9.8 m/s², h = height (m)

Application

Calculate stored energy due to position in gravitational field

Example

A spring with k = 100 N/m compressed by 0.1 m stores PE = ½ × 100 × 0.1² = 0.5 J

Formula

PE_elastic = ½kx²

Variables

PE_elastic = elastic potential energy (J), k = spring constant (N/m), x = compression/extension (m)

Application

Calculate energy stored in springs, rubber bands, or elastic materials

Exam Tips

  • Always square the velocity correctly in KE calculations
  • Choose a consistent reference point for measuring heights
  • Remember that energy is always positive (it's the square of velocity or height)
  • Use conservation of energy when mechanical energy is constant

Key Points

  • Kinetic energy depends on mass and velocity - doubling velocity quadruples KE
  • Gravitational potential energy depends on mass, height, and gravitational field strength
  • Elastic potential energy is stored in compressed or stretched springs
  • Energy can be converted from one form to another but total energy is conserved
  • At maximum height, KE = 0 and PE is maximum; at ground level, PE = 0 and KE is maximum

Definitions

Term

Kinetic Energy

Definition

The energy possessed by an object due to its motion

Importance

Explains why moving objects can do work and cause damage upon impact

Term

Potential Energy

Definition

The energy stored in an object due to its position or configuration

Importance

Represents the capacity to do work when the object's position changes

Term

Mechanical Energy

Definition

The sum of kinetic and potential energies in a mechanical system

Importance

Total mechanical energy is conserved in systems without friction or air resistance

Section Title

Kinetic Energy and Potential Energy

Common Mistakes

  • Forgetting the ½ factor in kinetic energy formula
  • Using wrong reference point for measuring height in potential energy
  • Confusing elastic potential energy with gravitational potential energy
  • Not recognizing that velocity squared means small velocity changes have large energy effects

Formulas

Example

A pendulum bob at the top has PE = mgh, KE = 0. At the bottom: PE = 0, KE = mgh

Formula

E_total = KE + PE = constant

Variables

E_total = total mechanical energy (J), KE = kinetic energy (J), PE = potential energy (J)

Application

Analyze motion in gravitational fields, pendulums, and roller coasters

Example

A car accelerating from 10 m/s to 20 m/s: ΔKE = ½m(20²) - ½m(10²) = 150m J

Formula

W_net = ΔKE = KE_final - KE_initial

Variables

W_net = net work done (J), ΔKE = change in kinetic energy (J)

Application

Calculate work done by all forces acting on an object

Exam Tips

  • Identify all energy forms present at different points in the motion
  • Set up energy equations: Initial total energy = Final total energy
  • Use conservation of energy for problems involving height changes
  • Apply work-energy theorem when forces other than gravity are involved

Key Points

  • Energy cannot be created or destroyed, only transformed from one form to another
  • In ideal systems without friction, mechanical energy (KE + PE) remains constant
  • Energy transformations occur continuously in pendulums, roller coasters, and falling objects
  • Real systems lose mechanical energy to heat due to friction and air resistance
  • The work-energy theorem states that work done equals change in kinetic energy

Definitions

Term

Conservation of Energy

Definition

The principle that energy cannot be created or destroyed, only converted between forms

Importance

Fundamental law of physics that governs all energy transformations in the universe

Term

Work-Energy Theorem

Definition

The net work done on an object equals its change in kinetic energy

Importance

Connects the concepts of work and energy, useful for solving complex motion problems

Section Title

Conservation of Energy

Common Mistakes

  • Ignoring friction and air resistance when applying conservation of energy
  • Forgetting to include all forms of energy in the system
  • Mixing up initial and final energies in calculations
  • Not recognizing when energy is lost to non-mechanical forms like heat

Formulas

Example

A 1000 kg car traveling at 20 m/s has momentum p = 1000 × 20 = 20,000 kg·m/s

Formula

p = mv

Variables

p = momentum (kg·m/s), m = mass (kg), v = velocity (m/s)

Application

Calculate momentum of moving objects in collisions and impacts

Example

A 0.5 kg ball changes velocity from 10 m/s to -5 m/s. Δp = 0.5(-5) - 0.5(10) = -7.5 kg·m/s

Formula

J = Δp = FΔt

Variables

J = impulse (N·s), Δp = change in momentum (kg·m/s), F = average force (N), Δt = time interval (s)

Application

Analyze impacts, collisions, and force applications over time

Example

Two cars collide: m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂' (before = after)

Formula

p_initial = p_final (for isolated systems)

Variables

p = momentum of the system before and after collision

Application

Solve collision problems where total momentum is conserved

Exam Tips

  • Always define positive direction before solving momentum problems
  • Draw before and after diagrams for collision problems
  • Remember that momentum is conserved even in explosive situations
  • Use impulse-momentum theorem when force and time are given

Key Points

  • Momentum is the product of mass and velocity - a measure of motion quantity
  • Impulse is the change in momentum caused by a force acting over time
  • Newton's second law can be expressed as F = Δp/Δt
  • In collisions, total momentum is conserved when no external forces act
  • Impulse equals the area under a force-time graph

Definitions

Term

Momentum

Definition

The product of an object's mass and velocity, representing its quantity of motion

Importance

Fundamental quantity in analyzing collisions and interactions between objects

Term

Impulse

Definition

The change in momentum of an object, equal to the product of average force and time

Importance

Explains why extending contact time reduces force in impacts (airbags, padding)

Term

Conservation of Momentum

Definition

In an isolated system, total momentum remains constant before and after collisions

Importance

Key principle for analyzing all types of collisions and interactions

Section Title

Momentum and Impulse

Common Mistakes

  • Forgetting that momentum is a vector - direction matters
  • Not considering the sign of velocity when calculating momentum changes
  • Confusing impulse with momentum - impulse is the CHANGE in momentum
  • Applying conservation of momentum when external forces are present

Connections

  • Work-Energy Theorem connects force concepts with energy changes
  • Conservation of Energy applies to all physical processes, not just mechanical systems
  • Momentum conservation explains recoil in guns and rocket propulsion
  • Impulse-momentum theorem explains safety features in cars and sports equipment
  • Power concepts relate to efficiency in machines and human activities
  • Energy transformations occur in all natural processes and technological applications

Exam Strategy

Focus on understanding the physical meaning of each formula before memorizing them. Practice drawing energy bar charts and momentum diagrams for visual problem-solving. Always identify what's conserved (energy or momentum) in each problem type. For collision problems, set up before-and-after equations systematically. Remember that work, energy, and power problems often require identifying multiple steps, so break complex problems into smaller parts. Pay attention to units and signs (positive/negative) as they indicate directions and energy flow.

Quick Review Questions

A 2 kg object moves 5 m when acted upon by a 10 N force parallel to its motion. How much work is done?

W = F × d = 10 N × 5 m = 50 J. Since force is parallel to displacement, cos(0°) = 1.

What is the kinetic energy of a 4 kg object moving at 6 m/s?

KE = ½mv² = ½ × 4 kg × (6 m/s)² = ½ × 4 × 36 = 72 J

If a 3 kg ball is dropped from 10 m height, what is its potential energy initially?

PE = mgh = 3 kg × 9.8 m/s² × 10 m = 294 J

A 1500 kg car traveling at 25 m/s brakes to a stop. What is its change in momentum?

Δp = m(v_final - v_initial) = 1500(0 - 25) = -37,500 kg·m/s. Negative indicates direction change.

If a machine does 500 J of work in 10 seconds, what is its power output?

P = W/t = 500 J / 10 s = 50 W

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