UPCAT Chemistry — Periodic Table, Bonding & Chemical LanguageFlash Cards
Flashcards for Periodic Table, Bonding & Chemical Language — the active-recall tool for UPCAT Chemistry aspirants. Each card tests a key concept, formula, or definition from the UPCAT 2026 syllabus. Use them daily in the final month before exam day.
Exam context
For the University of the Philippines College Admission Test, University of the Philippines tests Chemistry under a "Core" label, with Periodic Table, Bonding & Chemical Language in the 3rd slot across 7 chapters. UPCAT candidates must clear the UPG ≤ 2.2 typical cut on the 2026 paper, which draws about 20 Chemistry questions. Date to watch: Mid-2026 (announced by UP Admissions).
Periodic Table, Bonding & Chemical Language - Flashcards
Master the fundamental concepts of chemistry including periodic trends, chemical bonding types, molecular geometry, and chemical nomenclature. These flashcards cover essential topics for UPCAT and other college entrance exams, with balanced coverage of reactions, calculations, and conceptual understanding.
Cards
What is the trend for atomic size as you move across a period from left to right?
Atomic size DECREASES from left to right across a period. This happens because the number of protons increases, creating stronger nuclear attraction that pulls electrons closer to the nucleus. Example: Na > Mg > Al > Si > P > S > Cl
Tags
- periodic_trends
- atomic_size
- conceptual
Topic
Periodic Trends
Card Id
ptbl_001
Difficulty
medium
Image Prompt
Calculate the number of valence electrons in sulfur (S) and predict its ion charge.
Step 1: S is in Group 16 (6A), so it has 6 valence electrons. Step 2: To achieve noble gas configuration, S needs 2 more electrons. Step 3: S gains 2 electrons to form S²⁻ ion. Answer: 6 valence electrons, forms S²⁻ ion
Tags
- valence_electrons
- ion_formation
- numerical
Topic
Ion Formation
Card Id
ptbl_002
Difficulty
easy
Image Prompt
What type of bond forms between Mg and Cl₂? Write the balanced equation.
IONIC BOND forms between metal (Mg) and nonmetal (Cl). Balanced equation: Mg(s) + Cl₂(g) → MgCl₂(s). Mg loses 2 electrons to form Mg²⁺, each Cl gains 1 electron to form Cl⁻. Electrostatic attraction holds ions together.
Tags
- ionic_bonding
- reaction_equation
- reaction_problems
Topic
Chemical Bonding
Card Id
bond_003
Difficulty
medium
Image Prompt
Explain why NH₃ (ammonia) has a bent molecular geometry.
NH₃ has TRIGONAL PYRAMIDAL geometry, not bent. Using VSEPR theory: N has 3 bonding pairs (N-H bonds) and 1 lone pair. The lone pair takes up more space, pushing the H atoms closer together, creating a pyramid shape with bond angle ~107°.
Tags
- vsepr_theory
- molecular_geometry
- conceptual
Topic
Molecular Geometry
Card Id
bond_004
Difficulty
hard
Image Prompt
Name the compound CaCl₂ and write the formula for aluminum oxide.
CaCl₂ = Calcium chloride (Ca²⁺ + 2Cl⁻). For aluminum oxide: Al³⁺ + O²⁻. Using criss-cross method: Al₂O₃. Steps: Al³⁺ needs 3 electrons, O²⁻ provides 2, so need 2 Al and 3 O for balance.
Tags
- ionic_compounds
- nomenclature
- formula_writing
Topic
Chemical Nomenclature
Card Id
name_005
Difficulty
medium
Image Prompt
What type of intermolecular force exists between HF molecules?
HYDROGEN BONDING - the strongest type of dipole-dipole force. HF has highly polar H-F bond due to large electronegativity difference. H (δ+) of one HF molecule attracts F (δ-) of another HF molecule. This explains HF's high boiling point.
Tags
- hydrogen_bonding
- intermolecular_forces
- conceptual
Topic
Intermolecular Forces
Card Id
imf_006
Difficulty
medium
Image Prompt
Draw the Lewis structure for CO₂ and determine if it's polar or nonpolar.
Lewis structure: O=C=O (linear). Steps: C has 4e⁻, each O has 6e⁻ = 16 total. C forms double bonds with each O. Molecular geometry is LINEAR. Although C=O bonds are polar, they cancel out due to symmetry. Result: NONPOLAR molecule.
Tags
- lewis_structures
- molecular_polarity
- structural_problems
Topic
Lewis Structures
Card Id
lewis_007
Difficulty
hard
Image Prompt
Name the acid HClO₃ and write the formula for sulfurous acid.
HClO₃ = Chloric acid (from ClO₃⁻ chlorate ion, -ate becomes -ic). For sulfurous acid: comes from SO₃²⁻ sulfite ion (-ite becomes -ous), so formula is H₂SO₃. Remember: -ate → -ic acid, -ite → -ous acid
Tags
- acid_nomenclature
- oxyacids
- formula_writing
Topic
Acid Nomenclature
Card Id
acid_008
Difficulty
medium
Image Prompt
Why does ionization energy increase across a period?
Ionization energy increases across a period because: 1) Nuclear charge increases (more protons), 2) Atomic size decreases, 3) Electrons are held more tightly, 4) More energy needed to remove an electron. Example: Na < Mg < Al < Si < P < S < Cl
Tags
- ionization_energy
- periodic_trends
- conceptual
Topic
Periodic Trends
Card Id
trend_009
Difficulty
medium
Image Prompt
Name these binary covalent compounds: CO₂, N₂O₄, SF₆
CO₂ = Carbon dioxide. N₂O₄ = Dinitrogen tetroxide. SF₆ = Sulfur hexafluoride. Rules: First element keeps name, second gets -ide ending. Use prefixes: di- (2), tetra- (4), hexa- (6). Drop 'mono-' for first element.
Tags
- binary_compounds
- nomenclature
- molecular_compounds
Topic
Binary Compounds
Card Id
binary_010
Difficulty
easy
Image Prompt
Calculate formal charge of N in NH₃.
Formula: FC = valence e⁻ - nonbonding e⁻ - (bonding e⁻/2). For N in NH₃: Step 1: N has 5 valence e⁻, Step 2: N has 2 nonbonding e⁻ (1 lone pair), Step 3: N has 6 bonding e⁻ (3 bonds). FC = 5 - 2 - (6/2) = 0
Tags
- formal_charge
- lewis_structures
- numerical
Topic
Formal Charge
Card Id
formal_011
Difficulty
hard
Image Prompt
What happens when sodium metal reacts with chlorine gas?
2Na(s) + Cl₂(g) → 2NaCl(s). This is an ionic bond formation reaction. Na loses 1 electron: Na → Na⁺ + e⁻. Each Cl gains 1 electron: Cl + e⁻ → Cl⁻. Results in crystalline salt with high melting point due to strong electrostatic forces.
Tags
- ionic_bonding
- reaction_equation
- reaction_problems
Topic
Ionic Bond Formation
Card Id
metal_012
Difficulty
medium
Image Prompt
Predict the molecular geometry of water (H₂O) using VSEPR theory.
H₂O has BENT molecular geometry. Steps: 1) O has 2 bonding pairs (O-H bonds), 2) O has 2 lone pairs, 3) Total = 4 electron pairs → tetrahedral electronic geometry, 4) 2 lone pairs push bonding pairs closer → bent shape with ~104.5° bond angle.
Tags
- vsepr_theory
- molecular_geometry
- water
Topic
VSEPR Theory
Card Id
vsepr_013
Difficulty
medium
Image Prompt
Write the formula for calcium phosphate using the phosphate ion PO₄³⁻.
Ca²⁺ + PO₄³⁻ → Ca₃(PO₄)₂. Steps: 1) Ca has +2 charge, PO₄ has -3 charge, 2) Need 3 Ca²⁺ and 2 PO₄³⁻ for charge balance, 3) 3(+2) + 2(-3) = 0. Parentheses needed around polyatomic ion with subscript >1.
Tags
- polyatomic_ions
- ionic_compounds
- formula_writing
Topic
Polyatomic Ions
Card Id
polyatomic_014
Difficulty
hard
Image Prompt
Why do larger molecules have stronger London dispersion forces?
Larger molecules have MORE ELECTRONS that can shift to create temporary dipoles. More electrons = stronger temporary dipoles = stronger induced dipoles in neighboring molecules = stronger attractions. This explains why boiling points increase: CH₄ < C₂H₆ < C₃H₈ < C₄H₁₀.
Tags
- london_dispersion
- molecular_size
- intermolecular_forces
Topic
London Dispersion Forces
Card Id
dispersion_015
Difficulty
medium
Image Prompt
Calculate the number of bonding and nonbonding electrons in NH₃.
Step 1: Total valence electrons = N(5) + 3H(1) = 8 electrons. Step 2: NH₃ has 3 N-H bonds = 6 bonding electrons. Step 3: Nonbonding electrons = 8 - 6 = 2 electrons (1 lone pair on N). Answer: 6 bonding, 2 nonbonding electrons.
Tags
- electron_counting
- lewis_structures
- numerical
Topic
Electron Counting
Card Id
electron_016
Difficulty
medium
Image Prompt
Predict the bond type between H and F based on electronegativity difference.
H (2.1) and F (4.0): Δχ = 4.0 - 2.1 = 1.9. Since Δχ > 1.7, this forms an IONIC BOND (in compounds) or highly polar covalent bond (in HF molecule). F is much more electronegative, so electrons spend more time near F atom.
Tags
- electronegativity
- bond_polarity
- numerical
Topic
Bond Polarity
Card Id
electronegativity_017
Difficulty
medium
Image Prompt
A compound has molecular formula C₆H₁₂O₆. What is its empirical formula?
Step 1: Find the ratio C₆:H₁₂:O₆ = 6:12:6. Step 2: Divide by GCD (6): 6÷6 : 12÷6 : 6÷6 = 1:2:1. Step 3: Empirical formula = CH₂O. This represents the simplest whole-number ratio of atoms.
Tags
- empirical_formula
- molecular_formula
- numerical
Topic
Chemical Formulas
Card Id
empirical_018
Difficulty
medium
Image Prompt
Name the compounds FeO and Fe₂O₃ using proper nomenclature.
FeO = Iron(II) oxide. Fe₂O₃ = Iron(III) oxide. Since Fe is a transition metal with variable charges, use Roman numerals. In FeO: Fe has +2 charge. In Fe₂O₃: Fe has +3 charge. Always balance with O²⁻ to find metal charge.
Tags
- transition_metals
- roman_numerals
- nomenclature
Topic
Transition Metal Compounds
Card Id
transition_019
Difficulty
hard
Image Prompt
How does temperature affect the rate of evaporation according to kinetic molecular theory?
Higher temperature increases evaporation rate because: 1) Molecules have higher kinetic energy, 2) More molecules have enough energy to overcome intermolecular forces, 3) More molecules escape from liquid surface to gas phase. KE ∝ Temperature (KMT Postulate 4).
Tags
- kinetic_theory
- evaporation
- temperature
- conceptual
Topic
Kinetic Molecular Theory
Card Id
kinetic_020
Difficulty
medium
Image Prompt
Tag Distribution
Numerical
6
Conceptual
7
Nomenclature
6
Bonding Theory
5
Formula Writing
4
Periodic Trends
3
Reaction Problems
4
Molecular Geometry
3
Topic Distribution
Kinetic Theory
1
Periodic Trends
3
Chemical Bonding
4
Chemical Formulas
2
Molecular Geometry
3
Chemical Nomenclature
4
Intermolecular Forces
3
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