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UPCAT ChemistryMolecular Theory — VSEPR, IMFA & KMTFlash Cards

If you only have 15 minutes a day for Molecular Theory — VSEPR, IMFA & KMT in the lead-up to the UPCAT, spend them on these flashcards. UP rewards reviewers who can recall a fact without a cue — that's what flashcards train, and this deck is built around exactly the cues UPCAT papers usually supply.

Exam context

For the University of the Philippines College Admission Test, University of the Philippines tests Chemistry under a "Core" label, with Molecular Theory — VSEPR, IMFA & KMT in the 5th slot across 7 chapters. UPCAT candidates must clear the UPG ≤ 2.2 typical cut on the 2026 paper, which draws about 20 Chemistry questions. Date to watch: Mid-2026 (announced by UP Admissions).

Molecular Theory — VSEPR, IMFA & KMT - Flashcards

Master the fundamental theories that govern molecular behavior and structure. This comprehensive flashcard set covers VSEPR theory for predicting molecular shapes, intermolecular forces (IMFA) that affect physical properties, and kinetic molecular theory (KMT) that explains gas behavior. These concepts are essential for understanding chemical bonding, molecular interactions, and gas laws in chemistry.

Cards

What does VSEPR stand for and what is its main purpose?

VSEPR stands for Valence Shell Electron Pair Repulsion theory. Its main purpose is to predict the 3D molecular geometry by assuming that electron pairs around a central atom repel each other and arrange themselves to minimize repulsion.

Tags

  • vsepr_theory
  • molecular_geometry
  • basic_concept

Topic

VSEPR Theory

Card Id

vsepr_01

Difficulty

easy

Image Prompt

A molecule has 2 bonding pairs and 0 lone pairs. What is its molecular geometry and bond angle?

Molecular geometry: Linear. Bond angle: 180°. Example: BeF₂ or CO₂. The two bonding pairs arrange themselves as far apart as possible in a straight line.

Tags

  • vsepr_calculation
  • linear_geometry
  • bond_angles

Topic

VSEPR Geometry

Card Id

vsepr_02

Difficulty

medium

Image Prompt

Determine the molecular geometry of NH₃ (3 bonding pairs, 1 lone pair).

NH₃ has trigonal pyramidal geometry. The lone pair on nitrogen occupies more space than bonding pairs, compressing the H-N-H bond angles to approximately 107° (less than the tetrahedral 109.5°).

Tags

  • vsepr_calculation
  • pyramidal_geometry
  • lone_pair_effect

Topic

VSEPR Geometry

Card Id

vsepr_03

Difficulty

medium

Image Prompt

Why do lone pairs affect molecular geometry differently than bonding pairs?

Lone pairs occupy more space than bonding pairs because they are attracted to only one nucleus, while bonding pairs are shared between two nuclei. This causes lone pairs to repel other electron pairs more strongly, compressing bond angles.

Tags

  • lone_pair_effect
  • electron_repulsion
  • conceptual

Topic

VSEPR Theory

Card Id

vsepr_04

Difficulty

medium

Image Prompt

What is the molecular geometry of water (H₂O) and explain why it's bent?

H₂O has bent (angular) geometry with bond angle ~104.5°. Oxygen has 2 bonding pairs and 2 lone pairs. The lone pairs repel the bonding pairs, compressing the H-O-H angle from the tetrahedral 109.5° to 104.5°.

Tags

  • bent_geometry
  • water_structure
  • lone_pair_compression

Topic

VSEPR Geometry

Card Id

vsepr_05

Difficulty

medium

Image Prompt

What are the three main types of intermolecular forces (IMFA)?

1. London Dispersion Forces (weakest) - present in all molecules 2. Dipole-Dipole Forces - between polar molecules 3. Hydrogen Bonding (strongest) - between molecules with H bonded to N, O, or F

Tags

  • imfa_types
  • force_strength
  • basic_concept

Topic

Intermolecular Forces

Card Id

imfa_01

Difficulty

easy

Image Prompt

Explain what causes London dispersion forces and give an example.

London dispersion forces are caused by temporary dipoles formed when electrons randomly cluster in one region of an atom/molecule, creating an instantaneous dipole that induces dipoles in neighboring molecules. Example: Forces between nonpolar molecules like CH₄ or noble gases like He.

Tags

  • london_forces
  • temporary_dipoles
  • nonpolar_molecules

Topic

London Dispersion Forces

Card Id

imfa_02

Difficulty

medium

Image Prompt

Why do larger molecules have stronger London dispersion forces?

Larger molecules have more electrons, creating larger electron clouds that are more easily polarized. This leads to stronger temporary dipoles and greater attractive forces between molecules. Example: I₂ (solid) vs F₂ (gas) at room temperature.

Tags

  • molecular_size
  • polarizability
  • electron_cloud

Topic

London Dispersion Forces

Card Id

imfa_03

Difficulty

medium

Image Prompt

What are the requirements for hydrogen bonding to occur?

Requirements: 1. Hydrogen must be covalently bonded to N, O, or F (highly electronegative atoms) 2. The H must interact with a lone pair on another N, O, or F atom Examples: H₂O, NH₃, HF can form hydrogen bonds.

Tags

  • hydrogen_bonding
  • electronegativity
  • lone_pairs

Topic

Hydrogen Bonding

Card Id

imfa_04

Difficulty

medium

Image Prompt

Arrange these in order of increasing boiling point: CH₄, NH₃, H₂O. Explain your reasoning.

Order: CH₄ < NH₃ < H₂O Reasoning: CH₄ has only weak London forces. NH₃ can form hydrogen bonds (stronger). H₂O can form more hydrogen bonds (2 lone pairs on O) and has the strongest intermolecular forces, requiring the most energy to overcome.

Tags

  • boiling_point
  • force_comparison
  • hydrogen_bonding

Topic

IMFA Comparison

Card Id

imfa_05

Difficulty

hard

Image Prompt

State the five postulates of the Kinetic Molecular Theory (KMT).

1. Gas particle volume is negligible compared to container volume 2. No attractive forces between particles 3. Particles in constant random motion 4. Collisions are completely elastic 5. Average kinetic energy is directly proportional to absolute temperature

Tags

  • kmt_postulates
  • gas_behavior
  • fundamental_theory

Topic

Kinetic Molecular Theory

Card Id

kmt_01

Difficulty

medium

Image Prompt

What does 'completely elastic collisions' mean in KMT?

Completely elastic collisions mean that no kinetic energy is lost during collisions between gas particles or with container walls. The total kinetic energy of the system remains constant, though individual particles may gain or lose energy.

Tags

  • elastic_collisions
  • kinetic_energy
  • conservation

Topic

Elastic Collisions

Card Id

kmt_02

Difficulty

medium

Image Prompt

According to KMT, what happens to molecular motion at absolute zero (0 K)?

At absolute zero (0 K), all molecular motion ceases according to KMT. This is because average kinetic energy is directly proportional to absolute temperature, so when T = 0 K, kinetic energy = 0, meaning no particle movement.

Tags

  • absolute_zero
  • molecular_motion
  • temperature_relationship

Topic

Temperature and Motion

Card Id

kmt_03

Difficulty

medium

Image Prompt

How does KMT explain gas pressure?

Gas pressure results from collisions of gas particles with container walls. More frequent and forceful collisions create higher pressure. Pressure depends on: 1. Number of particles (more particles = more collisions), 2. Temperature (higher T = faster particles = harder collisions), 3. Volume (smaller volume = more frequent collisions).

Tags

  • pressure_explanation
  • particle_collisions
  • gas_properties

Topic

Gas Pressure

Card Id

kmt_04

Difficulty

medium

Image Prompt

Calculate the average kinetic energy of gas molecules at 300 K using KE = (3/2)kT.

Given: T = 300 K, k = 1.38 × 10⁻²³ J/K Step 1: KE = (3/2)kT Step 2: KE = (3/2)(1.38 × 10⁻²³)(300) Step 3: KE = (1.5)(4.14 × 10⁻²¹) Answer: KE = 6.21 × 10⁻²¹ J per molecule

Tags

  • kinetic_energy
  • temperature_calculation
  • numerical_problem

Topic

Kinetic Energy Calculation

Card Id

kmt_05

Difficulty

hard

Image Prompt

How do IMFA affect the validity of KMT for real gases?

Real gases deviate from KMT because: 1. Intermolecular forces exist (violates 'no attractive forces' postulate), 2. Particle volume becomes significant at high pressure (violates 'negligible volume' postulate). These effects are most noticeable at low temperature and high pressure.

Tags

  • real_gases
  • kmt_deviations
  • imfa_effects

Topic

Real vs Ideal Gases

Card Id

integration_01

Difficulty

hard

Image Prompt

Explain why polar molecules generally have higher boiling points than nonpolar molecules of similar size.

Polar molecules have dipole-dipole forces in addition to London dispersion forces, while nonpolar molecules only have London forces. The additional dipole-dipole attractions require more energy to overcome during boiling, resulting in higher boiling points.

Tags

  • polarity
  • boiling_point
  • dipole_forces

Topic

Polarity and Physical Properties

Card Id

integration_02

Difficulty

medium

Image Prompt

Why does NH₃ have a higher boiling point than PH₃ despite similar molecular shapes?

NH₃ can form hydrogen bonds because N is highly electronegative, while PH₃ cannot form hydrogen bonds because P is less electronegative. Hydrogen bonding in NH₃ creates stronger intermolecular forces, requiring more energy to overcome, resulting in a higher boiling point.

Tags

  • hydrogen_bonding
  • electronegativity
  • boiling_point_comparison

Topic

Hydrogen Bonding Effects

Card Id

integration_03

Difficulty

hard

Image Prompt

Predict the molecular geometry of SF₄ (4 bonding pairs, 1 lone pair).

SF₄ has a seesaw (distorted tetrahedral) geometry. The lone pair occupies an equatorial position in the trigonal bipyramidal electron arrangement, causing distortion. Bond angles are less than 109.5° due to lone pair repulsion.

Tags

  • seesaw_geometry
  • five_electron_pairs
  • advanced_vsepr

Topic

VSEPR Complex Geometries

Card Id

application_01

Difficulty

hard

Image Prompt

Why is ice less dense than liquid water?

In ice, water molecules form an ordered hexagonal crystal structure held together by hydrogen bonds, creating open spaces. In liquid water, molecules are closer together due to random motion. The open structure of ice makes it less dense, so ice floats on water.

Tags

  • ice_structure
  • density
  • hydrogen_bonding_effects

Topic

Hydrogen Bonding Applications

Card Id

application_02

Difficulty

medium

Image Prompt

Tag Distribution

Basic Concepts

4

Force Comparisons

4

Numerical Problems

2

Geometry Predictions

5

Advanced Applications

5

Topic Distribution

VSEPR Theory

5

Intermolecular Forces

6

Integration/Applications

4

Kinetic Molecular Theory

5

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