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GELE Surveying (Geomatics)Area and Volume Computation (Earthworks)Revision Notes

Revision notes for GELE Surveying (Geomatics) Area and Volume Computation (Earthworks) — designed for time-pressed reviewers. These notes skip the basics and focus on what Professional Regulation Commission (PRC) — Board of Geodetic Engineering consistently tests, so you spend your revision hours on the content most likely to appear on exam day.

Exam context

On the GELE 2026, the Surveying (Geomatics) subtest carries a "Core" weight in Professional Regulation Commission (PRC) — Board of Geodetic Engineering's pattern. Area and Volume Computation (Earthworks) lands at position 4th out of 9 in the standard review order. Target score is 70% weighted average, no sub-test below 50%, and roughly a meaningful share of items come from Surveying (Geomatics) on a typical GELE paper.

Area and Volume Computation (Earthworks) - Revision Notes

Earthworks computation is a consistently tested topic in the PRC Civil Engineer Licensure Examination under Surveying (Geomatics). It covers three major skill sets: (1) computing land areas from coordinate data using the Shoelace/DMD method, (2) computing irregular boundary areas using the Trapezoidal and Simpson's One-Third rules, and (3) computing earthwork volumes between cross-sections using the End-Area and Prismoidal methods. Mastery of these topics is essential not only for the board exam but also for professional practice in highway, dam, and subdivision engineering projects in the Philippines.

Sections

Formulas

Example

Vertices: A(0,0), B(4,0), C(0,3). A = (1/2)|[0(0−3) + 4(3−0) + 0(0−0)]| = (1/2)|0 + 12 + 0| = 6 m²

Formula

A = (1/2) |Σ(x_i · y_{i+1} − x_{i+1} · y_i)|

Variables

x_i, y_i = Cartesian coordinates of vertex i; n = total number of vertices; indices wrap: x_{n+1} = x_1, y_{n+1} = y_1

Application

Computing the area of any closed survey parcel or traverse polygon directly from coordinate data.

Example

A traverse with four courses: compute latitudes and departures from bearings and distances, then apply DMD rule course by course; sum DMD × Lat, divide absolute value by 2.

Formula

2A = Σ(DMD_i × Latitude_i); DMD_1 = Dep_1; DMD_{i+1} = DMD_i + Dep_i + Dep_{i+1}

Variables

DMD = Double Meridian Distance of a course; Lat = latitude (N = +, S = −); Dep = departure (E = +, W = −)

Application

Used when survey data is given as bearings and distances rather than Cartesian coordinates.

Exam Tips

  • Set up a table with columns: vertex, x, y, (x_i · y_{i+1}), (x_{i+1} · y_i) — this organizes the shoelace computation and reduces arithmetic errors.
  • Board problems often give four to six vertices; writing out the table row by row is the fastest error-free approach.
  • If bearing-distance data is given, always compute latitudes and departures first, then use DMD or convert to coordinates.
  • Quick check: for a right triangle with legs a and b, area = ab/2 — use this to verify simple cases.
  • Problems may state coordinates in 'northing and easting' — northing corresponds to y, easting corresponds to x.

Key Points

  • The Shoelace formula computes the area of any closed polygon given the Cartesian coordinates of its vertices in order (either clockwise or counter-clockwise).
  • The formula is: A = (1/2) |Σ(x_i · y_{i+1} − x_{i+1} · y_i)| where the subscripts wrap around (i.e., vertex n+1 = vertex 1).
  • Always close the polygon in the summation by returning to the first vertex.
  • The absolute value is taken to ensure a positive area regardless of vertex traversal direction.
  • The DMD (Double Meridian Distance) method, used with latitudes and departures from compass/traverse surveys, yields the same result as the shoelace formula but is expressed in terms of survey data.
  • For the DMD method: DMD of first course = departure of first course; DMD of next course = DMD of previous course + departure of previous course + departure of current course; 2A = Σ(DMD × latitude); take absolute value and divide by 2.
  • Units: if coordinates are in metres, area is in m²; divide by 10,000 for hectares.

Definitions

Term

Shoelace Formula

Definition

A mathematical algorithm that computes the area of a polygon from its vertex coordinates by cross-multiplying successive coordinate pairs and summing the differences.

Importance

The primary area computation method when coordinates are directly available from GPS, total station, or coordinate geometry problems.

Term

DMD (Double Meridian Distance)

Definition

The algebraic sum of the meridian distances of the two ends of a survey course, used as a multiplier with the latitude to compute double the area of a traverse.

Importance

Standard method in Philippine surveying practice for computing traverse areas from field-measured bearings and distances.

Term

Latitude

Definition

The north-south projection of a survey course: Lat = distance × cos(bearing angle). North = positive, South = negative.

Importance

Required for both DMD area computation and for checking traverse closure (sum of latitudes must equal zero for a closed traverse).

Term

Departure

Definition

The east-west projection of a survey course: Dep = distance × sin(bearing angle). East = positive, West = negative.

Importance

Required for DMD computation and traverse closure checks.

Section Title

1. Area by Coordinates (Shoelace / Double-Meridian-Distance Method)

Common Mistakes

  • Forgetting to close the polygon — the last term must multiply x_n by y_1 and x_1 by y_n.
  • Not taking the absolute value — the shoelace sum can be negative if vertices are listed clockwise.
  • In the DMD method, using the latitude of the wrong course as the multiplier.
  • Mixing up latitude (N-S) and departure (E-W) when computing from bearings.
  • Not converting area from m² to hectares when the problem asks for area in hectares (divide by 10,000).

Formulas

Example

Offsets at 5 m spacing: y_0=0, y_1=3, y_2=5, y_3=4, y_4=6, y_5=2 (5 intervals). A = 5×[(0+2)/2 + 3+5+4+6] = 5×[1+18] = 5×19 = 95 m²

Formula

A_trap = h × [(y_0 + y_n)/2 + y_1 + y_2 + ... + y_{n-1}]

Variables

h = uniform spacing between offsets (m); y_0, y_1, ..., y_n = offset lengths (m); n = number of intervals

Application

Computing the area of any irregular strip regardless of the number of offsets. Used when Simpson's rule cannot be applied (odd number of intervals).

Example

Offsets at 10 m: y_0=2, y_1=5, y_2=8, y_3=6, y_4=3 (4 intervals, n=4, even — applicable). A = (10/3)×[(2+3)+4(5+6)+2(8)] = (10/3)×[5+44+16] = (10/3)×65 = 216.7 m²

Formula

A_Simp = (h/3) × [(y_0 + y_n) + 4(y_1 + y_3 + ... y_{n-1,odd}) + 2(y_2 + y_4 + ... y_{n-2,even})]

Variables

h = uniform spacing (m); y_0, y_n = first and last offsets; odd-indexed offsets multiplied by 4; even-indexed interior offsets multiplied by 2; n must be even (even number of intervals)

Application

More accurate area computation for irregular boundaries when the number of intervals is even.

Exam Tips

  • Memorize the multiplier pattern for Simpson's: 1, 4, 2, 4, 2, ..., 4, 1 — the first and last are 1, odd positions are 4, even interior positions are 2.
  • When the problem gives an even number of offsets (odd number of intervals), apply Simpson's to the first even-interval group and add the remaining trapezoid separately.
  • Always verify: (number of offsets − 1) = number of intervals. Simpson's needs this to be even.
  • Board problems often present 5 or 9 offsets (4 or 8 intervals) — these are perfect for Simpson's rule.
  • Trapezoidal rule always underestimates area for a curve that is concave upward and overestimates for concave downward. Simpson's is more balanced.

Key Points

  • These rules apply when a boundary is irregular (e.g., a riverbank, road side slope) and is described by perpendicular offsets measured at equal intervals from a baseline.
  • Offsets are labelled y_0, y_1, y_2, ..., y_n measured at spacing h along the baseline.
  • Trapezoidal Rule treats each strip as a trapezoid; it is always applicable regardless of the number of intervals.
  • Simpson's One-Third Rule treats pairs of strips as parabolic segments; it requires an even number of intervals (i.e., an odd number of offsets: n must be even, so the count of offsets is n+1 which is odd).
  • Simpson's rule is more accurate than the trapezoidal rule for the same number of intervals because it fits a second-degree curve to each pair of strips.
  • If the number of intervals is odd (even number of offsets), apply Simpson's rule to all but the last strip, then add the last strip as a trapezoid.
  • Both rules assume equal spacing h between offsets.

Definitions

Term

Offset

Definition

A perpendicular distance measured from a baseline to the irregular boundary of an area at a specific station along the baseline.

Importance

The raw measurement input for both Trapezoidal and Simpson's rules; accuracy of offsets directly determines accuracy of computed area.

Term

Trapezoidal Rule

Definition

A numerical integration method that approximates the area under a curve by summing the areas of trapezoids formed between consecutive offsets.

Importance

Always applicable, simple to use; slightly less accurate than Simpson's for smooth curves because it assumes linear variation between offsets.

Term

Simpson's One-Third Rule

Definition

A numerical integration method that fits a second-degree parabola through each group of three consecutive offsets, giving a more accurate area estimate than the trapezoidal rule.

Importance

More accurate; preferred in board exam problems when even number of intervals is given. The multiplier pattern is 1-4-2-4-2-...-4-1.

Section Title

2. Area of Irregular Boundaries — Trapezoidal and Simpson's Rules

Common Mistakes

  • Applying Simpson's rule when the number of intervals is odd (even number of offsets) — check: count the offsets, subtract 1 to get the number of intervals; this must be even for pure Simpson's rule.
  • Forgetting to halve the end offsets in the Trapezoidal rule formula.
  • Misidentifying which offsets are 'odd-indexed' (multiplied by 4) vs 'even-indexed' (multiplied by 2) in Simpson's rule — remember: y_0 and y_n are each multiplied by 1, then alternate 4-2-4-2.
  • Confusing 'number of offsets' with 'number of intervals': n intervals requires n+1 offsets.
  • Forgetting that h is the spacing between offsets, not the total baseline length.

Formulas

Example

A_1 = 20 m², A_2 = 30 m², L = 50 m. V = (50/2)(20+30) = 25×50 = 1,250 m³

Formula

V_end = (L/2) × (A_1 + A_2)

Variables

L = distance between the two cross-sections (m); A_1, A_2 = cross-sectional areas at each end (m²); V = volume (m³)

Application

Quick earthwork volume estimate between two consecutive cross-sections in highway or canal construction.

Example

A_1 = 20 m², A_m = 24 m², A_2 = 30 m², L = 50 m. V = (50/6)(20 + 4×24 + 30) = (50/6)(20+96+30) = (50/6)(146) = 1,216.7 m³

Formula

V_prism = (L/6) × (A_1 + 4·A_m + A_2)

Variables

L = distance between end sections (m); A_1, A_2 = end cross-sectional areas (m²); A_m = cross-sectional area at the midpoint of L (m²)

Application

More accurate volume computation; the preferred method when mid-section dimensions are available or can be interpolated.

Example

From examples above: C_p = 1,250 − 1,216.7 = 33.3 m³ (end-area overestimates by 33.3 m³)

Formula

C_p = V_end − V_prism

Variables

C_p = prismoidal correction (m³); V_end = end-area volume (m³); V_prism = prismoidal volume (m³)

Application

Determines the magnitude of overestimation by the end-area method. Often computed directly from width and height differences at the two sections.

Example

L = 20 m, c_1 = 2.4 m, c_2 = 1.8 m, d_1 = 14.4 m, d_2 = 12.6 m. C_p = (20/12)(2.4−1.8)(14.4−12.6) = (1.667)(0.6)(1.8) = 1.80 m³

Formula

Prismoidal Correction for roadway sections (three-level): C_p = (L/12)(c_1 − c_2)(d_1 − d_2)

Variables

c_1, c_2 = center heights at the two end sections (m); d_1, d_2 = total widths at the two end sections (m); L = station interval (m)

Application

Direct computation of prismoidal correction for standard three-level highway cross-sections without needing to compute A_m explicitly.

Exam Tips

  • The board exam frequently gives A_1, A_m (or asks you to compute it), and A_2, then asks for both end-area and prismoidal volumes — solve both and compute the prismoidal correction.
  • Remember: L/2 for end-area; L/6 for prismoidal. The coefficient 4 in the prismoidal formula applies to A_m only.
  • When mid-section dimensions are given (not the area), compute A_m from the cross-section geometry first before applying the prismoidal formula.
  • For the mass diagram: a rising curve indicates net cut; a falling curve indicates net fill. The highest and lowest points correspond to transitions from cut to fill or fill to cut.
  • If the problem says 'prismoidal formula' or 'more accurate method', use V = (L/6)(A_1 + 4A_m + A_2). If it says 'average end-area' or 'end-area method', use V = (L/2)(A_1 + A_2).
  • Always check units: areas in m², distance in m → volume in m³. Convert to cubic meters then to bank cubic meters (BCM) if shrink/swell is specified.

Key Points

  • Earthwork volume computations are used in highway, dam, and canal design to estimate quantities of soil to be cut (excavated) or filled.
  • Two cross-sections, separated by a distance L (the station interval), define a solid whose volume is to be computed.
  • End-Area Method: assumes the volume is a prismoid and approximates it by averaging the two end cross-sectional areas.
  • Prismoidal Method: more accurate; uses the mid-section area A_m at the midpoint of L in addition to the two end areas.
  • The mid-section area A_m is computed from the actual dimensions at the midpoint of the segment — it is NOT the simple average of A_1 and A_2.
  • The Prismoidal Correction (C_p) is the difference between the end-area volume and the prismoidal volume: C_p = V_{end} − V_{prism}. If C_p > 0, end-area overestimates.
  • The mass diagram (mass-haul curve) plots cumulative algebraic sum of cut minus fill volumes along the project alignment to determine haul distances, borrow pits, and waste sites.
  • In Philippine highway practice, a free-haul distance and overhaul limit are specified; the mass diagram identifies sections requiring overhaul payment.

Definitions

Term

Cross-Section Area (A)

Definition

The area of the plane figure formed by cutting a road embankment, cut, or fill perpendicular to the project centerline at a given station.

Importance

The fundamental input to all earthwork volume calculations; computed from field cross-section notes or from design drawings.

Term

End-Area Method

Definition

A volume computation method that multiplies the average of two end cross-sectional areas by the distance between them: V = (L/2)(A_1 + A_2).

Importance

Standard method in Philippine highway practice due to its simplicity; slightly overestimates volume for tapering sections (non-prismatic shapes).

Term

Prismoidal Formula

Definition

An exact formula for the volume of a prismoid (a solid bounded by two parallel plane faces): V = (L/6)(A_1 + 4A_m + A_2), where A_m is the true mid-section area.

Importance

More accurate than the end-area method; required when precision is specified in contract documents or when the examiner provides mid-section data.

Term

Mid-Section Area (A_m)

Definition

The cross-sectional area of the earthwork solid at the exact midpoint (L/2) between the two end stations. It is computed from the actual dimensions at that midpoint, not from averaging A_1 and A_2.

Importance

Critical distinction for the board exam: A_m ≠ (A_1 + A_2)/2. Using the average instead of the true mid-section area is the most common exam error.

Term

Prismoidal Correction

Definition

The algebraic difference between the end-area volume and the prismoidal volume: C_p = V_end − V_prism. It is subtracted from the end-area volume to obtain the more accurate prismoidal volume.

Importance

Frequently tested in the PRC board exam. For most earthwork shapes, the end-area method overestimates, so C_p is positive.

Term

Mass Diagram (Mass-Haul Curve)

Definition

A plot of the cumulative algebraic sum of cut and fill volumes (cut positive, fill negative) along the project stationing. The ordinate at any station equals the net accumulated volume from the start of the project.

Importance

Used to determine the most economical distribution of earthwork — identifying free-haul sections, overhaul zones, borrow pits, and waste areas. A standard tool in Philippine highway design practice.

Term

Free-Haul Distance

Definition

The specified distance within which earth may be moved at no extra cost beyond the unit price for excavation. Haul beyond this distance (overhaul) is paid separately.

Importance

Relevant to mass diagram analysis and earthwork cost estimation in Philippine highway contracts (DPWH standard specifications).

Section Title

3. Earthwork Volumes — End-Area and Prismoidal Methods

Common Mistakes

  • Using A_m = (A_1 + A_2)/2 instead of computing the true mid-section area from the actual midpoint dimensions — this is the most critical prismoidal formula error.
  • Applying the end-area formula and calling it the prismoidal volume — the two formulas are different; know which one the problem asks for.
  • Forgetting to multiply by L/2 (end-area) or L/6 (prismoidal) — computing only A_1 + A_2 without applying the distance factor.
  • In mass diagram problems, treating cut as negative and fill as positive (or vice versa) inconsistently — convention: cut is positive (material available), fill is negative (material needed).
  • Not distinguishing between volume of cut and volume of fill when swell and shrinkage factors are involved — in some board problems, bank measure vs. compacted measure is specified.

Formulas

Example

5 offsets given → 4 intervals → even → Simpson's is applicable. 6 offsets → 5 intervals → odd → use Trapezoidal, or apply Simpson's to first 4 intervals and add last trapezoid.

Formula

DECISION: Simpson's applicable? → Check: (number of offsets − 1) = even? → YES → Simpson's; NO → Trapezoidal or split

Variables

Number of offsets = count of y values given; number of intervals = count of offsets minus 1

Application

Pre-computation decision rule to select the correct area method.

Exam Tips

  • On the board exam, when both Trapezoidal and Simpson's answers are among the choices, the question typically asks for Simpson's — it is more accurate and more commonly tested.
  • When the problem mentions 'prismoidal correction', you must compute both end-area and prismoidal volumes.
  • Always write down the formula first, then substitute values — this systematic approach prevents formula-substitution errors under exam pressure.

Key Points

  • Area by Coordinates: use when vertices (x, y) or northings and eastings are given — apply Shoelace/DMD.
  • Trapezoidal Rule: use for any number of offsets at equal spacing — always applicable.
  • Simpson's Rule: use when number of intervals is even (odd number of offsets) — more accurate than trapezoidal.
  • End-Area Volume: always computable from two end cross-sections — quick but slightly overestimates for tapering solids.
  • Prismoidal Volume: use when mid-section area or midpoint dimensions are given — more accurate.
  • Prismoidal Correction = V_end − V_prism; for most highway sections, this is positive (end-area overestimates).
  • Mass diagram: cumulative cut (+) and fill (−) plotted vs. station to plan haul economics.

Section Title

4. Summary of Key Formulas and Decision Framework

Common Mistakes

  • Skipping the decision step — always verify applicability of Simpson's rule before using it.
  • Mixing up which method is more accurate: Simpson's > Trapezoidal for irregular boundaries; Prismoidal > End-Area for earthwork volumes.

Connections

  • Traverse computation (bearings, distances, latitudes, departures) is a prerequisite for the DMD area method — errors in traverse adjustment propagate into area computations.
  • Cross-section design (cut slopes, fill slopes, roadway template) provides the geometric data needed to compute cross-sectional areas A_1, A_m, A_2 for earthwork volume formulas.
  • Numerical integration (Trapezoidal and Simpson's rules) is a fundamental concept shared with engineering mathematics and hydrology (computing runoff volumes from hydrographs).
  • The prismoidal formula is mathematically identical to Simpson's One-Third Rule applied over the length L with three 'ordinates' A_1, A_m, A_2 — recognizing this connection helps remember both formulas.
  • Mass diagram analysis connects to project planning and cost estimation — closely related to DPWH Item 100 (Clearing and Grubbing) and Item 104 (Embankment) in Philippine highway contracts.
  • GPS and total station surveys now provide direct coordinate output, making the Shoelace formula the dominant area computation method in modern Philippine surveying practice.
  • Earthwork volume computations underpin the Bill of Quantities (BOQ) required by Philippine procurement law (RA 9184 — Government Procurement Reform Act) for infrastructure projects.

Exam Strategy

In the PRC CE board exam, earthwork problems typically appear 3–6 times per examination and follow predictable patterns. For area problems: first identify whether coordinates or offsets are given. If coordinates → Shoelace formula (set up a two-column table). If offsets → count intervals; even → Simpson's; odd → Trapezoidal or hybrid. For volume problems: if both A_1 and A_2 are given → End-Area; if A_m is also given or can be computed → Prismoidal. Always compute both if time permits — the prismoidal correction is often a separate sub-question. Memorize the two multiplier sequences: End-Area uses L/2; Prismoidal uses L/6 with the 1-4-1 weight on A_1, A_m, A_2. For Simpson's rule, the offset multipliers follow 1-4-2-4-2-...-4-1. On the actual exam, read each problem twice: identify what is given, what is asked, and which formula applies before computing. Show all intermediate steps — partial credit may be awarded, and organized work prevents arithmetic errors.

Quick Review Questions

A parcel has vertices A(0,0), B(50,0), C(60,40), D(10,30). Compute its area using the Shoelace formula.

Set up the table: Σ(x_i · y_{i+1}): (0×0)+(50×40)+(60×30)+(10×0) = 0+2000+1800+0 = 3800. Σ(x_{i+1} · y_i): (50×0)+(60×0)+(10×40)+(0×30) = 0+0+400+0 = 400. Difference = |3800−400| = 3400. A = 3400/2 = 1700 m². Note: Let me recompute carefully. Vertices in order: A(0,0)→B(50,0)→C(60,40)→D(10,30)→back to A(0,0). Σ(x_i·y_{i+1}) = (0×0)+(50×40)+(60×30)+(10×0) = 0+2000+1800+0 = 3800. Σ(x_{i+1}·y_i) = (50×0)+(60×0)+(10×40)+(0×30) = 0+0+400+0 = 400. A = (1/2)|3800−400| = (1/2)(3400) = 1,700 m².

Six offsets are measured at 5 m intervals from a baseline: 0, 3, 5, 4, 6, 2 m. Compute the area using the Trapezoidal Rule.

Number of offsets = 6, number of intervals = 5 (odd → Trapezoidal is appropriate). A = h×[(y_0+y_5)/2 + y_1+y_2+y_3+y_4] = 5×[(0+2)/2 + 3+5+4+6] = 5×[1+18] = 5×19 = 95 m².

Five offsets at 10 m spacing are: 2, 5, 8, 6, 3 m. Compute the area using Simpson's One-Third Rule.

Number of offsets = 5, number of intervals = 4 (even → Simpson's applicable). Pattern: y_0=2 (×1), y_1=5 (×4), y_2=8 (×2), y_3=6 (×4), y_4=3 (×1). A = (10/3)×[(2+3)+4(5+6)+2(8)] = (10/3)×[5+44+16] = (10/3)×65 = 216.67 m².

Cross-sections A_1 = 20 m² and A_2 = 30 m² are 50 m apart. Compute the earthwork volume using the End-Area method.

V_end = (L/2)(A_1+A_2) = (50/2)(20+30) = 25×50 = 1,250 m³.

For the same cross-sections (A_1 = 20 m², A_2 = 30 m², L = 50 m) with a mid-section area A_m = 24 m², compute the prismoidal volume and the prismoidal correction.

V_prism = (L/6)(A_1+4A_m+A_2) = (50/6)(20+4×24+30) = (50/6)(20+96+30) = (50/6)(146) = 1,216.7 m³. Prismoidal correction: C_p = V_end − V_prism = 1,250 − 1,216.7 = 33.3 m³. The end-area method overestimates by 33.3 m³.

Cross-sections A_1 = 35 m², A_m = 28 m², A_2 = 22 m² are L = 40 m apart. Compute the prismoidal volume.

V_prism = (40/6)(35 + 4×28 + 22) = (40/6)(35+112+22) = (40/6)(169) = 6.667×169 = 1,126.7 m³. Let me recalculate: (40/6) = 6.6667; 35+112+22 = 169; 6.6667×169 = 1,126.7 m³. Note: Some references round (40/6) = 6.667; 6.667×169 = 1,126.7 m³ ≈ 1,126.7 m³. Cross-check: End-area V = (40/2)(35+22) = 20×57 = 1,140 m³. Prismoidal correction = 1,140 − 1,126.7 = 13.3 m³. Final answer: V_prism = 1,126.7 m³.

What is the key condition for applying Simpson's One-Third Rule to a set of offsets, and what should you do if the condition is not met?

Simpson's rule processes pairs of strips (each pair uses 3 offsets and covers 2 intervals). If the total number of intervals is odd, apply Simpson's rule to all but the last interval, then compute the area of the last strip as a trapezoid and add them together. This hybrid approach uses the best method for each portion of the data.

In the mass diagram, what does a rising portion of the curve indicate, and what does a falling portion indicate?

The mass diagram plots cumulative (cut − fill) volume vs. station. By convention, cut volumes are positive and fill volumes are negative. When cumulative volume increases (curve rises), more cut than fill is occurring at those stations. When cumulative volume decreases (curve falls), fill requirements exceed available cut material. Points where the curve reaches a local maximum or minimum mark transitions between cut and fill zones.

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