Adjustment of Level Nets and Traverses - Misconception Buster
In the PRC Geodetic Engineer Licensure Examination, the adjustment of level nets and traverses is a high-yield topic that consistently separates passers from failures. Many examinees lose marks not because they lack knowledge, but because they carry subtle wrong beliefs — about sign conventions, proportionality rules, formula selection, and what 'error of closure' actually means. This guide targets those hidden traps. By confronting each misconception directly, seeing why the wrong reasoning feels logical, and practicing with trap questions modeled after actual board exam style, you build the kind of critical thinking that converts partial understanding into full marks. Read every misconception carefully: if a trap question surprises you, that misconception is costing you points.
Common misconceptions
The correction to each section in a level-net adjustment has the SAME sign as the misclosure.
Exam impact
A sign error on correction gives a completely wrong adjusted elevation. In a multi-step problem, a wrong elevation propagates into all subsequent answers, costing multiple marks in one mistake.
The reality
The correction is ALWAYS opposite in sign to the misclosure. If the loop closes high by +0.012 m, the observed elevations were measured too high, so corrections must be negative (lower the elevations). Mathematically: c_i = −e × (L_i / ΣL). The sum of all corrections must equal −e, exactly cancelling the misclosure. This is a fundamental principle of adjustment: corrections neutralize the error.
Trap question
Question
A level loop has a misclosure of −0.018 m over four sections of 2, 1, 3, 4 km (total 10 km). What is the correction applied to the 3 km section?
c_3 = −e × (L_3/ΣL) = −(−0.018) × (3/10) = +0.018 × 0.3 = +0.0054 m. Because the misclosure is negative (the loop closed low), corrections are positive (elevations must be raised). The negative sign in the formula flips the misclosure sign.
Wrong answer
−0.0054 m (student applies same sign as misclosure, −0.018, and gets −0.0054 m)
Correct answer
+0.0054 m
Correct vs incorrect approach
Correct approach
c_3 = −e × (L_3/ΣL) = −(+0.012) × (3/8) = −0.0045 m. The correction is negative because the misclosure is positive. Adjusted elevation = observed elevation + (−0.0045 m).
Incorrect approach
Misclosure e = +0.012 m, section length 3 km, total 8 km. Student writes: c_3 = +0.012 × (3/8) = +0.0045 m. (Same sign as misclosure — WRONG.)
Why students believe it
Students intuitively think: 'There is a positive misclosure, so I add something positive to fix it.' The word 'correction' feels like it should go in the direction of the error. Many textbooks state the formula without emphasizing the negative sign, so students omit it or reverse it under exam pressure.
The Bowditch (compass) rule and the transit rule are interchangeable — either can be used for any traverse.
Exam impact
Exam problems often specify instrument type or field conditions. Choosing the wrong rule produces a different numerical correction and loses marks. Board questions also ask directly: 'Which rule is appropriate when angles are more precise than distances?' — a purely conceptual question with no computation.
The reality
The two rules rest on DIFFERENT assumptions about error sources. The Bowditch (compass) rule assumes angular and linear errors are proportional — corrections are proportional to LINE LENGTH. It is used when distances and angles have comparable precision. The transit rule assumes angular errors dominate — corrections are proportional to the MAGNITUDE of the latitude or departure of each line. It is used when angles are measured precisely (theodolite) but distances are less reliable. Choosing the wrong rule for the given scenario is a conceptual error that signals misunderstanding to examiners.
Trap question
Question
A traverse was measured using a first-order theodolite for angles and a fiberglass tape for distances. Which adjustment rule is more appropriate, and why?
A first-order theodolite measures angles to sub-second accuracy, while a fiberglass tape introduces distance errors from sag, temperature, and tension. The transit rule distributes corrections proportional to lat/dep magnitudes, implicitly placing more correction on longer lines where distance error is larger, which matches the actual error distribution.
Wrong answer
Bowditch rule, because it is the standard method for traverse adjustment.
Correct answer
Transit rule, because angular precision significantly exceeds distance precision.
Correct vs incorrect approach
Correct approach
When angular precision >> distance precision (e.g., theodolite angles + taped or paced distances), use the TRANSIT rule: c_lat,i = −ΣLat × |lat_i|/Σ|lat|, c_dep,i = −ΣDep × |dep_i|/Σ|dep|. When both are comparable, use the BOWDITCH rule: c_lat,i = −ΣLat × (L_i/ΣL).
Incorrect approach
Student uses the Bowditch rule because 'it is more common,' even when the problem states that a precise theodolite was used to measure angles and distances were measured by pacing.
Why students believe it
Both rules adjust latitudes and departures, both use proportional corrections, and both give a balanced traverse. Students learn them together and assume they produce the same result or that the choice is arbitrary. Some reviewers present them as 'two options' without explaining the critical difference in assumption.
The 'error of closure' (EC) is the same as the misclosure in latitudes or the misclosure in departures.
Exam impact
If a student uses only ΣLat or only ΣDep as EC, the relative precision is wrong, and any problem requiring a specific precision standard (e.g., 1/5000 for third-order work) yields an incorrect pass/fail judgment. This is a frequent source of wrong answers in board exam traverse problems.
The reality
The error of closure is a VECTOR quantity — the straight-line distance from the computed closing point back to the true closing point. It combines BOTH the latitude misclosure and the departure misclosure using the Pythagorean theorem: EC = √(ΣLat² + ΣDep²). You cannot use just one component. Using ΣLat or ΣDep alone underestimates the true closure error, and the relative precision computed from it is misleading.
Trap question
Question
A closed traverse with perimeter 2400 m has ΣLat = −0.60 m and ΣDep = +0.80 m. What is the relative precision of the traverse?
EC = √(0.60² + 0.80²) = √(0.36 + 0.64) = √1.00 = 1.00 m. Relative precision = 1.00/2400 = 1/2400. The student who used only one component got 1/3000, which is overly optimistic and completely wrong.
Wrong answer
1/3000 (student uses only ΣDep = 0.80, so 0.80/2400 = 1/3000)
Correct answer
1/2400
Correct vs incorrect approach
Correct approach
EC = √(0.30² + 0.40²) = √(0.09 + 0.16) = √0.25 = 0.50 m. Relative precision = 0.50/1000 = 1/2000. This is the true linear error of closure.
Incorrect approach
ΣLat = +0.30 m, ΣDep = −0.40 m. Student states EC = −0.40 m (the larger component) and computes relative precision = 0.40/1000 = 1/2500. WRONG — EC is not a single component.
Why students believe it
Students see ΣLat = +0.30 m and ΣDep = −0.40 m and pick the larger one (−0.40 m) as the 'error of closure' or simply call one of them the EC. The vector nature of the error is not intuitive — students are accustomed to scalar errors in leveling and apply the same thinking to traverses.
A higher relative precision fraction (larger denominator) means WORSE survey quality.
Exam impact
When the exam asks 'Does this traverse meet third-order precision of 1/5000?', a student with this misconception reverses the inequality and gives the opposite conclusion. This also leads to errors in selecting which traverse result to accept in a field scenario.
The reality
Relative precision is expressed as 1/n where a LARGER n means BETTER precision. 1/5000 = 0.0002 and 1/2000 = 0.0005. Since 0.0002 < 0.0005, a precision of 1/5000 is FIVE TIMES BETTER than 1/2000. In Philippine survey practice and NAMRIA standards, higher-order surveys demand larger denominators (e.g., first-order: 1/25000, third-order: 1/5000).
Trap question
Question
Traverse X has a relative precision of 1/4000. Traverse Y has a relative precision of 1/8000. Which traverse is more precise, and can Traverse X meet a third-order standard requiring at least 1/5000?
1/8000 < 1/4000 (numerically smaller error ratio = better precision). For Traverse X to meet 1/5000, its relative precision must be ≤ 1/5000. But 1/4000 = 0.00025 and 1/5000 = 0.0002; since 0.00025 > 0.0002, Traverse X is WORSE than required and fails the standard.
Wrong answer
Traverse X is more precise because 4000 < 8000. Traverse X meets 1/5000 because 4000 < 5000.
Correct answer
Traverse Y is more precise. Traverse X does NOT meet the 1/5000 standard.
Correct vs incorrect approach
Correct approach
1/6000 = 0.000167 and 1/3000 = 0.000333. Since 0.000167 < 0.000333, Traverse B (1/6000) has smaller relative error and is therefore MORE precise. Larger denominator = better precision.
Incorrect approach
Traverse A has relative precision 1/3000; Traverse B has 1/6000. Student concludes Traverse A is better because '3000 < 6000 and the smaller number means less error.' WRONG.
Why students believe it
Students see '1/5000' and '1/2000' and think: '5000 > 2000, so 1/5000 is worse.' This is a common inversion error seen when students are not comfortable reading fractions in the context of ratios. Fractions can be counterintuitive — the larger the denominator, the smaller the fraction.
After applying Bowditch corrections, the adjusted latitudes and departures of each line are the corrections themselves.
Exam impact
Using the correction as the adjusted value produces completely wrong coordinates for traverse stations. Area computations (DMD method) and coordinate transformations that follow will all be incorrect.
The reality
The CORRECTION is what you ADD to the OBSERVED latitude or departure to get the ADJUSTED latitude or departure. Adjusted Lat_i = Observed Lat_i + c_lat,i. The correction is only a small adjustment, not the full value. After adjustment, the sum of adjusted latitudes = 0 and sum of adjusted departures = 0, which is the check.
Trap question
Question
A traverse line has an observed latitude of +185.60 m and an observed departure of −92.30 m. The Bowditch corrections are c_lat = −0.045 m and c_dep = +0.030 m. What are the adjusted latitude and departure?
Adjusted Lat = 185.60 + (−0.045) = 185.555 m. Adjusted Dep = −92.30 + (+0.030) = −92.270 m. The corrections are small residuals; they modify the observed values, not replace them.
Wrong answer
Adjusted Lat = −0.045 m, Adjusted Dep = +0.030 m
Correct answer
Adjusted Lat = +185.555 m, Adjusted Dep = −92.270 m
Correct vs incorrect approach
Correct approach
Adjusted Lat_AB = Observed Lat_AB + c_lat = +120.35 + (−0.075) = +120.275 m. The correction is small relative to the observed value; the adjusted value remains close to the observed value.
Incorrect approach
Line AB: Observed Lat = +120.35 m, c_lat = −0.075 m. Student writes Adjusted Lat = −0.075 m. WRONG — they used the correction as the value.
Why students believe it
Students confuse the CORRECTION with the ADJUSTED VALUE. This is especially common when students are rushing through calculations or when they misread the procedure: 'apply the correction' sounds like 'the correction becomes the new value.' The confusion between increment and result is a persistent arithmetic trap.
The allowable misclosure for leveling is a fixed value in meters, independent of the survey distance.
Exam impact
A student with this misconception will incorrectly judge whether a leveling survey meets the required standard. They may accept a loop that exceeds the tolerance or reject one that is perfectly acceptable.
The reality
The allowable misclosure for leveling is expressed as e_allowable = m√K, where K is the total leveling distance in kilometers and m is a constant depending on order (e.g., ±12 mm for third-order, ±8 mm for second-order, ±4 mm for first-order in many standards). A 1 km loop and a 100 km loop have very different allowable misclosures. This is derived from the theory of error propagation: independent random errors in each setup add in quadrature, giving a net error proportional to √n_setups ∝ √K.
Trap question
Question
A closed level loop covering 16 km has a misclosure of +36 mm. The third-order standard uses e_allowable = 12√K mm. Does this loop meet the third-order standard?
e_allowable = 12√16 = 12 × 4 = 48 mm. The actual misclosure of 36 mm < 48 mm, so the loop passes. The student who used 12 mm (the coefficient, not the formula result) was confusing the constant m with the allowable misclosure.
Wrong answer
No, 36 mm exceeds the typical limit of ±12 mm for third-order leveling.
Correct answer
Yes, the loop meets third-order standard.
Correct vs incorrect approach
Correct approach
For third-order leveling: e_allowable = 12√K = 12√25 = 12×5 = 60 mm. The actual misclosure of 45 mm < 60 mm, so the loop PASSES third-order. But for second-order: e_allowable = 8√25 = 40 mm, so 45 mm > 40 mm — it FAILS second-order.
Incorrect approach
A level loop of 25 km has a misclosure of 45 mm. Student compares 45 mm to a memorized limit of '±50 mm' and concludes it passes. But this fixed value is arbitrary and wrong.
Why students believe it
Students memorize a number like '±12 mm' or '±5 mm' from examples in notes and assume this is a universal limit. They do not realize the standard is expressed as a tolerance formula that scales with distance, because random errors accumulate proportionally to √K (where K is the total distance in kilometers).
The Bowditch correction to a line's latitude depends on that line's latitude value — larger latitudes get larger corrections.
Exam impact
Mixing up the two rules produces wrong corrections for every line. This affects all adjusted latitudes, departures, and coordinates — cascading errors throughout the traverse computation.
The reality
In the BOWDITCH (compass) rule, latitude and departure corrections are proportional to LINE LENGTH, not to the latitude or departure value. c_lat,i = −ΣLat × (L_i/ΣL). The transit rule uses |lat_i|/Σ|lat| as the proportionality factor. A line with a small latitude but a long distance gets a LARGER Bowditch correction than a line with a large latitude but a short distance.
Trap question
Question
A traverse uses the Bowditch rule. Line AB has length 150 m and latitude +60.0 m. Line BC has length 300 m and latitude +20.0 m. ΣLat = +0.12 m. What is the latitude correction for Line BC?
Bowditch rule uses length proportions. ΣL = 150+300 = 450 m. c_lat,BC = −ΣLat × (L_BC/ΣL) = −0.12 × (300/450) = −0.12 × 0.667 = −0.08 m. Despite having a smaller latitude (20 m vs 60 m), Line BC gets a larger correction because it is longer.
Wrong answer
−0.03 m (student uses transit rule: 20/(60+20) = 0.25, so c = −0.12×0.25 = −0.03 m)
Correct answer
−0.08 m
Correct vs incorrect approach
Correct approach
Bowditch: c1_lat = −ΣLat × (200/500) = −ΣLat × 0.40; c2_lat = −ΣLat × (300/500) = −ΣLat × 0.60. Longer line (L=300m) gets larger correction, regardless of its latitude value.
Incorrect approach
Bowditch correction for Line 1 (L=200m, Lat=+80.0m) and Line 2 (L=300m, Lat=+50.0m). Student uses lat magnitudes: c1_lat proportional to 80/(80+50) = 0.615; c2_lat proportional to 50/130 = 0.385. This is the TRANSIT rule — not Bowditch.
Why students believe it
This is a confusion between the Bowditch rule and the transit rule. In the transit rule, corrections ARE proportional to the absolute value of the latitude. Students who study both rules together sometimes misremember which proportionality basis applies to which rule, especially under exam time pressure.
A balanced traverse (ΣLat = 0 and ΣDep = 0 after adjustment) means the traverse has no errors and is perfectly accurate.
Exam impact
This misconception leads to overconfidence in adjusted results and failure to report relative precision as a quality indicator. Exam questions may ask about the quality of a survey BEFORE adjustment — students who confuse pre- and post-adjustment states answer incorrectly.
The reality
Adjustment achieves MATHEMATICAL CLOSURE but does NOT eliminate the actual measurement errors — it distributes them. A traverse with relative precision of only 1/500 can still be 'balanced' after Bowditch adjustment. The adjusted values are best estimates, not truth. The ERROR OF CLOSURE before adjustment is the measure of quality. After adjustment, the traverse satisfies the geometric constraint (ΣLat = 0, ΣDep = 0) but the individual adjusted coordinates still carry distributed error.
Trap question
Question
After applying the Bowditch rule to a traverse, the sum of adjusted latitudes = 0.000 m and sum of adjusted departures = 0.000 m. What does this confirm?
Mathematical closure (ΣLat = ΣDep = 0) is a geometric constraint satisfied by construction after adjustment. It does not mean the measurements are error-free. The original error of closure (EC before adjustment) is the true quality indicator. A poor-quality traverse still closes mathematically after adjustment — it just has larger distributed errors in the adjusted coordinates.
Wrong answer
The traverse measurements were accurate and contain no errors.
Correct answer
The traverse satisfies mathematical closure; measurement errors have been distributed, not eliminated.
Correct vs incorrect approach
Correct approach
The adjusted traverse satisfies the geometric closure condition. The errors are redistributed proportionally to line lengths. The RELATIVE PRECISION (EC/perimeter before adjustment) remains the correct measure of survey quality. Adjustment is not error elimination — it is error distribution.
Incorrect approach
After applying Bowditch corrections and getting ΣLat = 0.000 m and ΣDep = 0.000 m, student states 'the traverse is now error-free.' WRONG — the error was distributed, not eliminated.
Why students believe it
Students confuse mathematical closure (the traverse 'closes' on paper after adjustment) with physical accuracy (the traverse correctly represents the ground). The Bowditch rule forces mathematical closure by construction — it distributes the misclosure so that corrections sum to cancel it. This looks like 'fixing' the errors.
In level-net adjustment, all sections must have corrections, even if a section has a fixed benchmark at both ends.
Exam impact
In network-style exam problems, incorrectly adjusting sections tied to multiple benchmarks produces wrong adjusted elevations that violate the fixed control. This is especially important for NAMRIA control surveys under PD 1 (geodetic control) and for cadastral surveys under PD 1529.
The reality
In a level NET (as opposed to a simple loop), sections connecting two FIXED benchmarks are fully constrained — their end elevations are known, so the misclosure for that section must be fully absorbed without altering the fixed values. Sections connecting to only one fixed point, or to floating points, receive corrections distributed by the network geometry. Proper level-net adjustment requires understanding which nodes are fixed and which are free. Least-squares network adjustment handles this rigorously through the normal equations.
Trap question
Question
In a level network, BM-1 (elevation 200.000 m) and BM-2 (elevation 215.000 m) are fixed national control points. Point P is a free intermediate point. Which elevation(s) will be changed during network adjustment?
Fixed control benchmarks (especially national control under RA 4374/RA 8560 administered by NAMRIA) are held fixed during adjustment. Their elevations are the ground truth the network must honor. Only free (unconstrained) points receive adjusted elevations. Changing a fixed benchmark elevation would corrupt the entire control network.
Wrong answer
The elevations of BM-1, BM-2, and P will all be adjusted to distribute the misclosure.
Correct answer
Only the elevation of Point P is adjusted; BM-1 and BM-2 remain at their fixed values.
Correct vs incorrect approach
Correct approach
BM-A and BM-B are fixed. Only Point X (free) has an unknown adjusted elevation. The network adjustment must satisfy the elevation difference constraints imposed by both fixed benchmarks. The section A-B serves as a check/constraint, not as a freely adjustable section.
Incorrect approach
A level net has BM-A (fixed, elevation 100.000 m), BM-B (fixed, 115.000 m), and Point X (free). Section A-X = 2 km, Section X-B = 3 km, Section A-B (direct) = 4 km. Student applies uniform Bowditch corrections to all three sections, changing the elevation at BM-B. WRONG — BM-B is fixed.
Why students believe it
Students learn the general formula c_i = −e × (L_i/ΣL) and apply it uniformly to all sections. They do not consider the role of fixed control points (benchmarks) in constraining the network. This is especially problematic in level networks with multiple fixed benchmarks where some sections are fully controlled.
The relative precision of a traverse is expressed as a decimal (e.g., 0.0005) rather than as a ratio 1/n.
Exam impact
While both forms convey the same mathematical value, board exam answer choices are presented as ratios (1/2000, 1/5000, etc.). A student computing a decimal and not converting it will not find their answer among the choices.
The reality
By convention, relative precision (also called relative accuracy or precision ratio) in surveying is ALWAYS expressed as 1/n where n is a whole number. To convert: if EC/perimeter = 0.0005, then n = 1/0.0005 = 2000, and the precision is 1/2000. Published standards (NAMRIA, NSCP) specify tolerances in this format (e.g., 1/5000 for third-order). Expressing it as a decimal is unconventional and risks comparison errors.
Trap question
Question
A traverse with a perimeter of 4500 m has an error of closure of 0.90 m. What is the relative precision?
Relative precision = EC/perimeter = 0.90/4500 = 0.0002. Converting: n = 4500/0.90 = 5000. Relative precision = 1/5000. The reciprocal shortcut: n = perimeter/EC = 4500/0.90 = 5000.
Wrong answer
0.0002 (student leaves it in decimal form)
Correct answer
1/5000
Correct vs incorrect approach
Correct approach
Relative precision = EC/perimeter = 0.75/3000 = 0.00025 = 1/4000. Always express as 1/n by taking the reciprocal: n = 3000/0.75 = 4000.
Incorrect approach
EC = 0.75 m, perimeter = 3000 m. Student writes: relative precision = 0.75/3000 = 0.00025. Stops here — does not convert to 1/n format.
Why students believe it
Relative precision is computed as EC/perimeter, which immediately gives a decimal. Students forget to convert this to the standard engineering format of 1/n. On exam papers, writing '0.0005' instead of '1/2000' may seem equivalent but signals unfamiliarity with surveying conventions and can cause errors when comparing to published standards.
Quick self-check
If a level loop has a positive misclosure, the corrections applied to each section must also be positive.
Answer
False
Corrections are OPPOSITE in sign to the misclosure. If e = +0.012 m (loop closed high), corrections are negative: c_i = −e × (L_i/ΣL) < 0. The corrections bring elevated readings back down.
The error of closure of a traverse is computed as EC = √(ΣLat² + ΣDep²).
Answer
True
The error of closure is the vector distance from the computed closing position to the true closing point. It combines both latitude and departure misclosures using the Pythagorean theorem. Using only one component underestimates the true closure error.
The Bowditch (compass) rule distributes traverse corrections proportionally to the absolute values of each line's latitude and departure.
Answer
False
The Bowditch rule distributes corrections proportionally to LINE LENGTH (c_lat,i = −ΣLat × L_i/ΣL). It is the TRANSIT rule that uses absolute values of latitudes and departures. Mixing these up is one of the most common board exam errors.
A relative precision of 1/8000 is better (more precise) than 1/3000.
Answer
True
1/8000 = 0.000125 and 1/3000 = 0.000333. A smaller numerical value means a smaller error ratio, hence better precision. The larger the denominator in 1/n, the better the survey precision.
After applying the Bowditch rule to a traverse, the sum of adjusted latitudes equals zero, proving the traverse measurements are accurate.
Answer
False
Adjustment forces mathematical closure (ΣLat_adj = 0, ΣDep_adj = 0) by distributing the misclosure. This satisfies a geometric constraint but does NOT prove accuracy — it only means errors are redistributed. The error of closure BEFORE adjustment is the quality indicator.
The allowable misclosure for leveling is a constant value (in mm) that does not depend on the total distance surveyed.
Answer
False
The allowable misclosure is e_allowable = m√K, where K is the total leveling distance in kilometers and m is an order-dependent constant. A longer loop allows a proportionally larger (but still controlled) misclosure because random errors accumulate as √K.
When both leveling distance and number of setups per section are given, using either as the proportionality basis in level-net adjustment always produces the same corrections.
Answer
False
The two bases give the same corrections ONLY when setup density (setups per km) is uniform throughout the loop. When terrain varies (more setups per km in hills), the two methods give different proportions and hence different corrections. Always use the basis specified in the problem.
The sum of all Bowditch latitude corrections for a traverse must equal the negative of the latitude misclosure (−ΣLat).
Answer
True
Each correction c_lat,i = −ΣLat × (L_i/ΣL). Summing all: Σc_lat,i = −ΣLat × Σ(L_i/ΣL) = −ΣLat × 1 = −ΣLat. This is the standard verification check for Bowditch adjustment. If your corrections sum to anything other than −ΣLat, you have a computational error.
Diagrams
Bowditch vs Transit Rule — Correct Decision Tree
Decision flowchart showing when to apply the Bowditch versus Transit rule for traverse adjustment, and the verification step. Addresses the critical misconceptions M2 and M8 about rule selection and proportionality basis.
Level-Net Adjustment — Correct Procedure and Sign Convention
Step-by-step flowchart for level-net adjustment procedure, emphasizing the critical sign convention (corrections oppose the misclosure) and the distance-dependent allowable misclosure formula. Directly addresses misconceptions M1 and M7.
Common Misconceptions Map — Adjustment of Level Nets and Traverses
Mind map organizing all 12 misconceptions by topic area: level-net adjustment issues, traverse closure concepts, and adjustment rule selection. Helps students see the big picture of where errors occur across the chapter.
Traverse Error of Closure — Correct vs Incorrect Computation
Side-by-side comparison flowchart showing the wrong method (using only one misclosure component) versus the correct vector method for computing error of closure, leading to the correct relative precision expression.
In summary
The adjustment of level nets and traverses involves several high-stakes conceptual areas where examinees consistently lose marks. The seven most important takeaways for the PRC board exam are: (1) Corrections ALWAYS oppose the misclosure in sign — this is non-negotiable. (2) Error of closure is a VECTOR: EC = √(ΣLat² + ΣDep²), never just one component. (3) Relative precision is 1/n where a LARGER n means BETTER quality — express it as a ratio, not a decimal. (4) Bowditch corrections are proportional to LINE LENGTH; transit corrections are proportional to |lat| or |dep| — the rule choice depends on which measurement (angle or distance) is more precise. (5) Allowable level misclosure is m√K — a formula scaled by distance, not a fixed value. (6) Adjustment distributes errors; it does not eliminate them — a balanced traverse is not an error-free traverse. (7) In level networks with multiple fixed benchmarks, only FREE (unconstrained) points receive adjusted elevations — fixed control is held unchanged. Master these seven points and you eliminate the most common sources of wrong answers in traverse and leveling adjustment problems on the PRC Geodetic Engineer Licensure Examination.