FEUCAT Mathematics — Ratio & ProportionDetailed Explanation
Want to really understand Ratio & Proportion before tackling FEUCAT Mathematics questions? This detailed explanation breaks down every key concept, shows you why it matters for the FEUCAT 2026, and walks through the reasoning Far Eastern University expects on high-difficulty questions.
Exam context
On the FEUCAT 2026, the Mathematics subtest carries a "Core section" weight in Far Eastern University's pattern. Ratio & Proportion lands at position 2nd out of 9 in the standard review order. Target score is Competitive overall score, and roughly a meaningful share of items come from Mathematics on a typical FEUCAT paper.
Ratio & Proportion - Detailed explanation
Ratio and proportion are fundamental mathematical concepts that appear in almost every UPCAT Mathematics exam. They form the foundation for solving word problems involving mixtures, scale drawings, speed, percentages, and many other topics. Understanding these concepts will significantly boost your problem-solving skills and help you tackle complex mathematical scenarios with confidence. This comprehensive guide will take you through every aspect of ratios and proportions, from basic definitions to advanced problem-solving techniques commonly tested in Philippine college entrance exams.
Concepts
Understanding Ratios
A ratio is a comparison between two quantities of the same kind. It tells us how many times one quantity contains another or how the quantities relate to each other in size. Ratios help us understand relationships between different parts of a whole or between different quantities in a problem.
Examples
We compared the two quantities (girls and boys), then simplified by finding the GCD of 18 and 12, which is 6. The simplified ratio 3:2 means for every 3 girls, there are 2 boys.
Scenario
In a class of 30 students, 18 are girls and 12 are boys. Find the ratio of girls to boys.
Solution
Girls to boys = 18:12. Simplify by dividing both by 6: 18÷6 = 3, 12÷6 = 2. Therefore, the ratio is 3:2.
This is a continued ratio with three parts. We kept the original ratio and added the total as a third term. This type of ratio is useful for understanding parts versus the whole.
Scenario
A recipe calls for 2 cups of flour and 3 cups of sugar. What is the ratio of flour to sugar to total ingredients?
Solution
Flour:Sugar = 2:3. Total ingredients = 2+3 = 5 cups. Flour:Sugar:Total = 2:3:5.
Applications
- Comparing quantities in word problems
- Scaling recipes up or down
- Understanding maps and scale drawings
- Analyzing survey results and statistics
- Mixing solutions and alloys
Misconceptions
- Thinking ratios represent actual quantities (3:2 doesn't mean 3 and 2 items)
- Forgetting to check if quantities are in the same units
- Confusing the order of terms in a ratio
- Adding ratios incorrectly (you can't add 2:3 and 1:4 to get 3:7)
Related Concepts
- Fractions and decimal equivalents
- Greatest Common Divisor (GCD)
- Proportions and cross multiplication
- Percentages as ratios
Common Exam Questions
Example
Simplify 24:36 → GCD is 12 → 24÷12:36÷12 = 2:3
Approach
Find the GCD of both terms and divide
Question Type
Simplification problems
Example
If there are 45 apples and 60 oranges, the ratio is 45:60 = 3:4
Approach
Identify what quantities are being compared, set up the ratio, simplify if needed
Question Type
Word problems with ratios
Key Points To Remember
- Ratios compare quantities of the same kind (both in pesos, both in meters, etc.)
- Three ways to write ratios: 3:5, 3/5, or '3 to 5'
- Ratios can be simplified like fractions by dividing both terms by their GCD
- Order matters in ratios - 3:5 is different from 5:3
- Ratios express relationships, not actual quantities
Understanding Proportions
A proportion is a mathematical statement that shows two ratios are equal. It's like saying 'this ratio has the same value as that ratio.' Proportions are incredibly powerful for solving problems where you know three values and need to find the fourth. The key tool is cross multiplication, which comes from the fundamental property that if two fractions are equal, their cross products are equal.
Examples
We created a proportion comparing notebooks to cost. The relationship '3 notebooks per ₱45' should equal '8 notebooks per x pesos.' Cross multiplication gives us the equation to solve for the unknown cost.
Scenario
If 3 notebooks cost ₱45, how much do 8 notebooks cost?
Solution
Set up proportion: 3/₱45 = 8/x. Cross multiply: 3x = 45×8 = 360. Therefore, x = 360÷3 = ₱120.
The map scale gives us a fixed ratio between map distance and real distance. We maintain this same ratio to find the unknown real distance.
Scenario
On a map, 2 cm represents 5 km. If two cities are 7 cm apart on the map, what is their actual distance?
Solution
Set up proportion: 2 cm/5 km = 7 cm/x km. Cross multiply: 2x = 5×7 = 35. Therefore, x = 35÷2 = 17.5 km.
Applications
- Unit conversions and scaling
- Map reading and scale drawings
- Recipe scaling for different serving sizes
- Currency exchange calculations
- Similar triangles and geometry problems
Misconceptions
- Setting up proportions incorrectly (mixing up which values correspond)
- Forgetting to cross multiply or doing it incorrectly
- Not checking if the proportion makes logical sense
- Confusing direct and inverse relationships
Related Concepts
- Cross multiplication technique
- Direct and inverse variation
- Similar triangles in geometry
- Unit rates and conversions
Common Exam Questions
Example
If a/12 = 5/15, find a → Cross multiply: 15a = 60 → a = 4
Approach
Set up proportion, cross multiply, solve for unknown
Question Type
Missing term problems
Example
Speed problems: 60 km in 2 hours = x km in 5 hours
Approach
Identify the two related quantities, set up proportion with known and unknown values
Question Type
Word problem proportions
Key Points To Remember
- A proportion states that two ratios are equal: a/b = c/d
- Cross multiplication: if a/b = c/d, then a×d = b×c
- Use cross multiplication to solve for unknown values
- Check your answer by substituting back into the original proportion
- Proportions maintain the same relationship even when quantities change
Direct vs Inverse Proportion
Understanding whether quantities have a direct or inverse relationship is crucial for setting up correct proportions. In direct proportion, as one quantity increases, the other increases at the same rate (they move in the same direction). In inverse proportion, as one quantity increases, the other decreases at the same rate (they move in opposite directions). Identifying the type of relationship is often the key to solving complex word problems correctly.
Examples
The total work needed stays constant. When we triple the workers (4 to 12), the time should be divided by 3 (6÷3 = 2 days). We verify: 4×6 = 24 and 12×2 = 24.
Scenario
If 4 workers can build a wall in 6 days, how long will it take 12 workers to build the same wall?
Solution
This is inverse proportion (more workers = less time). Formula: workers × days = constant. So 4×6 = 12×x, which gives 24 = 12x, therefore x = 2 days.
Distance and time have a direct relationship when speed is constant. As time increases, distance increases proportionally. The speed (60 km/h) remains constant.
Scenario
A car travels 240 km in 4 hours. How far will it travel in 7 hours at the same speed?
Solution
This is direct proportion (more time = more distance). Set up: 240 km/4 hours = x km/7 hours. Cross multiply: 4x = 240×7 = 1680. Therefore x = 420 km.
Applications
- Work rate problems (workers, machines, time)
- Speed, distance, and time calculations
- Concentration and dilution problems
- Economic problems (supply, demand, price)
- Physics problems (pressure, volume, temperature)
Misconceptions
- Confusing direct and inverse relationships
- Not identifying what quantity remains constant
- Mixing up the formula setup for inverse proportions
- Forgetting to check if the answer makes logical sense
Related Concepts
- Linear relationships and graphing
- Hyperbolic relationships
- Rate problems and unit analysis
- Physics applications of proportion
Common Exam Questions
Example
Pipes filling tanks, workers completing jobs, machines producing items
Approach
Identify if more workers mean less time (inverse) or more work done (direct)
Question Type
Work rate problems
Example
If distance is constant, speed and time are inverse
Approach
Determine what stays constant: if speed is constant, distance and time are direct
Question Type
Speed and distance problems
Key Points To Remember
- Direct proportion: y = kx (both quantities change in the same direction)
- Inverse proportion: xy = k (quantities change in opposite directions)
- Ask yourself: 'If I double the first quantity, does the second double or halve?'
- Direct: more workers → more work done; Inverse: more workers → less time needed
- The constant k represents the rate or relationship strength
Partitive Proportion
Partitive proportion is used when you need to divide a total amount into parts that follow a specific ratio. This is extremely common in UPCAT problems involving profit sharing, inheritance division, or any situation where a whole must be split according to given ratios. The key is to find what one 'share' is worth, then multiply each part of the ratio by that share value.
Examples
We found that the total investment ratio has 10 parts. Each part is worth ₱5,000. Partner A invested 2 parts, so gets 2×₱5,000. The verification confirms our answer is correct.
Scenario
Three partners A, B, and C invested in a business in the ratio 2:3:5. If the total profit is ₱50,000, how much does each partner receive?
Solution
Total ratio parts = 2+3+5 = 10. One share = ₱50,000÷10 = ₱5,000. A gets 2×₱5,000 = ₱10,000. B gets 3×₱5,000 = ₱15,000. C gets 5×₱5,000 = ₱25,000. Check: ₱10,000+₱15,000+₱25,000 = ₱50,000 ✓
The money is divided proportionally to their ages. The oldest child (12 years) gets the most money, while the youngest (8 years) gets the least, but all in proportion to their ages.
Scenario
A mother divides ₱1,200 among her three children in the ratio of their ages: 8:10:12 years. How much does each child receive?
Solution
Total age ratio = 8+10+12 = 30. One share = ₱1,200÷30 = ₱40. Child 1 gets 8×₱40 = ₱320. Child 2 gets 10×₱40 = ₱400. Child 3 gets 12×₱40 = ₱480. Verification: ₱320+₱400+₱480 = ₱1,200 ✓
Applications
- Business profit and loss distribution
- Inheritance and estate division
- Resource allocation problems
- Partnership capital distribution
- Budget allocation across departments
Misconceptions
- Forgetting to add up all ratio parts first
- Using the ratio numbers as actual amounts
- Not verifying that all parts sum to the original total
- Confusing which person gets which ratio part
Related Concepts
- Weighted averages
- Percentage distributions
- Business mathematics
- Fraction of whole problems
Common Exam Questions
Example
Divide ₱840 in ratio 3:4:5 → 12 total parts → ₱70 per part → ₱210:₱280:₱350
Approach
Add ratio parts, find one share value, multiply each part
Question Type
Three-way division problems
Example
Investments of ₱20,000:₱30,000:₱50,000 give profits in ratio 2:3:5
Approach
Investment ratio determines profit share ratio
Question Type
Investment and profit sharing
Key Points To Remember
- Used to divide a total into parts following a given ratio
- Step 1: Add all parts of the ratio to find total shares
- Step 2: Divide the total amount by total shares to find one share
- Step 3: Multiply each ratio part by the value of one share
- Always verify that all parts add up to the original total
Percentages as Ratios
Percentages are simply ratios with 100 as the denominator. Understanding this connection allows you to solve percentage problems using proportion techniques. Every 'percent of' question can be converted into a proportion, making complex percentage problems much easier to handle. This is particularly useful for problems involving percentage increase, decrease, or finding percentages of quantities.
Examples
We converted the percentage to a ratio (35/100) and set it equal to our unknown over the total (x/240). Cross multiplication gives us the answer directly.
Scenario
What is 35% of 240?
Solution
Set up proportion: 35/100 = x/240. Cross multiply: 100x = 35×240 = 8,400. Therefore x = 84.
We're finding what percentage 180 is of 225. The proportion compares the part to whole on the left side, and the unknown percentage to 100 on the right side.
Scenario
If 180 students passed out of 225 total students, what percentage passed?
Solution
Set up proportion: 180/225 = x/100. Cross multiply: 225x = 180×100 = 18,000. Therefore x = 80%.
Applications
- Grade calculations and academic performance
- Discount and markup problems in business
- Statistical analysis and survey results
- Financial calculations (interest, taxes, tips)
- Growth and decline rate problems
Misconceptions
- Confusing 'percentage of' with 'percentage more than'
- Mixing up which number is the part and which is the whole
- Forgetting to convert between percentage and decimal forms
- Not understanding that 100% represents the whole amount
Related Concepts
- Decimal and fraction conversions
- Percentage increase and decrease
- Simple and compound interest
- Probability as percentages
Common Exam Questions
Example
Find 40% of 350 → 40/100 = x/350 → x = 140
Approach
Convert to fraction or use proportion method
Question Type
Percentage of a number
Example
What % is 45 of 180? → 45/180 = x/100 → x = 25%
Approach
Set up proportion: part/whole = x/100
Question Type
Finding what percentage one number is of another
Key Points To Remember
- Percent means 'per hundred' - it's a ratio with denominator 100
- 25% = 25/100 = 1/4 = 0.25
- Convert percentage problems into proportions for easier solving
- 'What percent of A is B?' becomes B/A = x/100
- 'Find x% of A' becomes x/100 = answer/A
Practice Problems
This is a direct proportion problem. As the number of people increases, the amount of flour needed increases proportionally. We maintain the same ratio of people to flour cups.
Problem
A recipe for 4 people uses 6 cups of flour. How many cups of flour are needed for 14 people?
Solution
Set up proportion: 4 people/6 cups = 14 people/x cups. Cross multiply: 4x = 6×14 = 84. Therefore x = 21 cups.
We found the unit rate (items per machine per hour), then multiplied by the new number of machines and hours. This systematic approach prevents errors in complex ratio problems.
Problem
If 8 machines can produce 240 items in 6 hours, how many items can 12 machines produce in 4 hours?
Solution
First find rate per machine per hour: 240 items ÷ (8 machines × 6 hours) = 5 items per machine per hour. Then: 12 machines × 4 hours × 5 items = 240 items.
This is a partitive proportion problem. We divided the total into shares based on the ratio, calculated the value of each share, then multiplied to find each person's amount.
Problem
Divide ₱2,100 among three people A, B, and C in the ratio 3:4:7.
Solution
Total ratio parts = 3+4+7 = 14. One share = ₱2,100÷14 = ₱150. A gets 3×₱150 = ₱450. B gets 4×₱150 = ₱600. C gets 7×₱150 = ₱1,050. Check: ₱450+₱600+₱1,050 = ₱2,100 ✓
More workers means less time needed, so this is inverse proportion. The total work remains constant at 300 worker-days. With 25 workers, it takes 12 days.
Problem
If 15 workers can complete a project in 20 days, how many days will it take 25 workers to complete the same project?
Solution
This is inverse proportion. Workers × days = constant work. 15×20 = 25×x, so 300 = 25x, therefore x = 12 days.
We knew that 420 votes represents 35% of the total. Using the percentage as a ratio (35/100), we can find the total number of votes cast in the election.
Problem
In a school election, candidate A received 420 votes, which was 35% of the total votes cast. How many total votes were cast?
Solution
Set up proportion: 420 votes/x total = 35/100. Cross multiply: 35x = 420×100 = 42,000. Therefore x = 1,200 total votes.
Exam Preparation Tips
- Always read the problem completely before setting up any ratios or proportions
- Identify whether the relationship is direct or inverse by asking 'if one doubles, does the other double or halve?'
- Check that all quantities in a ratio have the same units before comparing
- In partitive proportion problems, always verify that your parts add up to the given total
- Use cross multiplication systematically - write it out clearly to avoid arithmetic errors
- Convert percentages to ratios when the problem seems complex
- Practice identifying keywords: 'ratio of A to B', 'varies directly with', 'inversely proportional to'
- Draw diagrams or tables when dealing with multiple ratios or complex word problems
- Always substitute your answer back into the original problem to check reasonableness
- Master the basic proportion setup patterns for common UPCAT question types
- Time yourself on practice problems to improve speed and accuracy
- Pay special attention to unit conversions hidden within ratio problems
In summary
Mastering ratios and proportions is essential for UPCAT success, as these concepts appear throughout the mathematics exam in various forms. The key to success is recognizing the type of relationship (direct, inverse, or partitive) and applying the appropriate solving technique. Remember that consistent practice with cross multiplication, careful problem setup, and answer verification will build your confidence and accuracy. These skills will not only help you in the UPCAT but also form a strong foundation for advanced mathematics and real-world problem solving. Focus on understanding the underlying relationships rather than just memorizing formulas, and always check that your answers make practical sense in the context of the problem.
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