FEUCAT Mathematics — Calculus — Limits, Derivatives & IntegralsRevision Notes
Condensed revision notes for Calculus — Limits, Derivatives & Integrals, built for the final weeks before the FEUCAT 2026. These are the distilled key points you need when there is no time left for full study notes — just the concepts, formulas, and traps Far Eastern University tests.
Exam context
Far Eastern University runs the Far Eastern University College Admission Test on Q3–Q4 2026. Its Mathematics section sits under a "Core section" weighting, and Calculus — Limits, Derivatives & Integrals is the 9th chapter in the 9-chapter FEUCAT Mathematics rotation. The FEUCAT passing mark is Competitive overall score, and the most recent 2026 paper drew about a meaningful share of questions from Mathematics.
Calculus — Limits, Derivatives & Integrals - Revision notes
Calculus is a fundamental branch of mathematics that deals with rates of change and accumulation. This chapter covers three core concepts: limits (the foundation of calculus), derivatives (rates of change), and integrals (accumulation). These concepts are essential for UPCAT and other entrance examinations. Understanding how to evaluate limits, find derivatives using various rules, and calculate basic integrals will give you powerful tools for solving complex mathematical problems.
Sections
Formulas
Example
lim(x→2) (x² + 3x - 1) = 2² + 3(2) - 1 = 4 + 6 - 1 = 9
Formula
lim(x→a) f(x) = L
Variables
x = variable, a = approach value, L = limit value
Application
Finding the value a function approaches
Example
lim(x→3) (2x + 5) = 2(3) + 5 = 6 + 5 = 11
Formula
lim(x→a) (mx + b) = ma + b
Variables
m = slope, b = y-intercept, a = approach value
Application
Linear function limits using direct substitution
Example
lim(x→1) [(x² + 2x)] = lim(x→1) x² + lim(x→1) 2x = 1 + 2 = 3
Formula
lim(x→a) [f(x) ± g(x)] = L ± M
Variables
f(x), g(x) = functions with limits L, M respectively
Application
Sum/difference of limits equals limit of sum/difference
Example
lim(x→2) [x × (x + 1)] = 2 × (2 + 1) = 2 × 3 = 6
Formula
lim(x→a) [f(x) × g(x)] = L × M
Variables
f(x), g(x) = functions with limits L, M respectively
Application
Product of limits equals limit of product
Example
lim(x→3) [(x + 1)/(x - 1)] = (3 + 1)/(3 - 1) = 4/2 = 2
Formula
lim(x→a) [f(x)/g(x)] = L/M (M ≠ 0)
Variables
f(x), g(x) = functions with limits L, M respectively
Application
Quotient of limits when denominator limit is non-zero
Exam Tips
- Always try direct substitution first - it works for most basic problems
- Memorize the nine limit theorems for quick application
- Check answer choices to guide your approach
- Practice identifying which theorem applies to each problem type
Key Points
- A limit describes the value a function approaches as the input approaches a specific value
- Limits exist even when the function is not defined at that point
- Use direct substitution first, then apply limit theorems if needed
- Master the nine fundamental limit theorems for efficient problem-solving
- Limits are used to define both derivatives and integrals
Definitions
Term
Limit
Definition
The value that a function approaches as the input approaches a particular value
Importance
Foundation concept for understanding derivatives and integrals
Term
Direct Substitution
Definition
Method of evaluating limits by substituting the approach value directly into the function
Importance
First and simplest method to try when evaluating limits
Section Title
Limits - The Foundation of Calculus
Common Mistakes
- Assuming the limit equals the function value at that point (limits can exist even when function is undefined)
- Forgetting to check if denominators equal zero before applying quotient rule
- Not simplifying expressions before applying limit theorems
- Confusing limit notation with function evaluation
Formulas
Example
For f(x) = x², f'(2) = lim(x→2) (x² - 4)/(x - 2) = lim(x→2) (x + 2) = 4
Formula
f'(a) = lim(x→a) [f(x) - f(a)]/(x - a)
Variables
f'(a) = derivative at point a, f(x) = function
Application
Definition of derivative using limits
Example
d/dx(7) = 0, d/dx(-15) = 0
Formula
d/dx(c) = 0
Variables
c = constant
Application
Derivative of any constant is zero
Example
d/dx(x³) = 3x², d/dx(x^(-2)) = -2x^(-3) = -2/x³
Formula
d/dx(x^n) = nx^(n-1)
Variables
n = any real number exponent
Application
Power rule for finding derivatives of power functions
Example
d/dx(5x³) = 5·d/dx(x³) = 5·3x² = 15x²
Formula
d/dx[cf(x)] = c·f'(x)
Variables
c = constant, f(x) = function
Application
Constant multiple rule
Example
d/dx(x³ + 2x) = 3x² + 2
Formula
d/dx[f(x) ± g(x)] = f'(x) ± g'(x)
Variables
f(x), g(x) = differentiable functions
Application
Sum and difference rule
Example
d/dx[x²(x + 1)] = x²(1) + 2x(x + 1) = x² + 2x² + 2x = 3x² + 2x
Formula
d/dx[f(x)g(x)] = f(x)g'(x) + f'(x)g(x)
Variables
f(x), g(x) = differentiable functions
Application
Product rule for derivatives
Example
d/dx[x/(x + 1)] = [(x + 1)(1) - x(1)]/(x + 1)² = 1/(x + 1)²
Formula
d/dx[f(x)/g(x)] = [g(x)f'(x) - f(x)g'(x)]/[g(x)]²
Variables
f(x), g(x) = differentiable functions, g(x) ≠ 0
Application
Quotient rule for derivatives
Exam Tips
- Memorize the power rule formula - it appears in 80% of derivative problems
- For product rule, remember 'first times derivative of second plus derivative of first times second'
- For quotient rule, remember 'bottom times top prime minus top times bottom prime, all over bottom squared'
- Practice identifying which rule to use by looking at the structure of the function
Key Points
- Derivatives measure the instantaneous rate of change of a function
- The derivative at a point is the slope of the tangent line at that point
- Master the six fundamental derivative rules for efficient computation
- Power rule is the most frequently used: d/dx(x^n) = nx^(n-1)
- Product and quotient rules are essential for complex functions
Definitions
Term
Derivative
Definition
The instantaneous rate of change of a function at a specific point
Importance
Fundamental concept for optimization, motion problems, and curve analysis
Term
Tangent Line
Definition
A line that touches a curve at exactly one point with the same slope as the curve at that point
Importance
Geometric interpretation of derivatives
Term
Power Rule
Definition
The rule stating that the derivative of x^n is nx^(n-1)
Importance
Most commonly used derivative rule in calculus problems
Section Title
Derivatives - Rates of Change
Common Mistakes
- Forgetting to apply the power rule correctly: d/dx(x³) = 3x², not 3x³
- Misapplying the product rule: remember it's f(x)g'(x) + f'(x)g(x), not f'(x)g'(x)
- Getting the quotient rule formula backwards or forgetting the square in denominator
- Not using parentheses properly when applying rules to complex expressions
Formulas
Example
∫[1 to 3] x²dx = [x³/3] from 1 to 3 = 27/3 - 1/3 = 26/3
Formula
∫[a to b] f(x)dx = F(b) - F(a)
Variables
F(x) = antiderivative of f(x), a,b = limits of integration
Application
Fundamental Theorem of Calculus for definite integrals
Example
∫5 dx = 5x + C
Formula
∫c dx = cx + C
Variables
c = constant, C = constant of integration
Application
Integral of a constant
Example
∫x³ dx = x⁴/4 + C, ∫x^(-2) dx = x^(-1)/(-1) + C = -1/x + C
Formula
∫x^n dx = x^(n+1)/(n+1) + C (n ≠ -1)
Variables
n = any real number except -1, C = constant of integration
Application
Power rule for integration
Example
If F(x) = ∫[0 to x] t²dt, then F'(x) = x²
Formula
F(x) = ∫[a to x] f(t)dt, then F'(x) = f(x)
Variables
F(x) = function defined by integral, f(t) = integrand
Application
First Fundamental Theorem of Calculus
Exam Tips
- Always include +C for indefinite integrals
- For power rule integration: add 1 to exponent, then divide by new exponent
- Check your answer by differentiating - you should get back to the original function
- Use Fundamental Theorem: evaluate antiderivative at upper limit minus lower limit
Key Points
- Integration is the reverse process of differentiation
- Definite integrals represent area under curves
- Indefinite integrals include a constant of integration (+C)
- Fundamental Theorem of Calculus connects derivatives and integrals
- Master basic integration formulas and power rule for integration
Definitions
Term
Integral
Definition
The reverse operation of differentiation, representing accumulation or area under a curve
Importance
Essential for calculating areas, volumes, and solving accumulation problems
Term
Antiderivative
Definition
A function whose derivative equals the original function
Importance
Key to evaluating definite integrals using Fundamental Theorem of Calculus
Term
Definite Integral
Definition
An integral with specific upper and lower limits, representing a numerical value
Importance
Calculates exact areas and accumulation over intervals
Term
Indefinite Integral
Definition
An integral without limits, representing a family of functions differing by a constant
Importance
General form of antiderivatives, includes +C
Section Title
Basic Integrals - Accumulation and Area
Common Mistakes
- Forgetting the constant of integration (+C) for indefinite integrals
- Applying power rule incorrectly: ∫x³dx = x⁴/4 + C, not x⁴ + C
- Not adding 1 to the exponent when integrating: ∫x²dx = x³/3 + C, not x²/2 + C
- Confusing definite and indefinite integral notation and properties
Connections
- Limits provide the foundation for defining both derivatives and integrals
- The derivative represents the slope of the tangent line to a curve
- Integration is the reverse process of differentiation (Fundamental Theorem of Calculus)
- Definite integrals calculate the area under curves between specified limits
- These concepts are essential for physics (motion, rates) and economics (optimization)
- Calculus concepts appear frequently in UPCAT, ACET, and other entrance examinations
Exam Strategy
For UPCAT and similar exams: Master the basic rules first - power rule for derivatives and integration, then practice identifying which rule applies to each problem. Focus on computational accuracy and speed. Most exam questions test direct application of rules rather than theoretical understanding. Practice mixed problems that combine limits, derivatives, and integrals. Always check if direct substitution works for limits. For derivatives, identify the structure (sum, product, quotient) to choose the correct rule. For integrals, remember the +C for indefinite integrals and use FTC for definite integrals.
Quick Review Questions
Find lim(x→3) (2x² - 5x + 1)
Use direct substitution: 2(3)² - 5(3) + 1 = 2(9) - 15 + 1 = 18 - 15 + 1 = 4. Wait, let me recalculate: 2(9) - 5(3) + 1 = 18 - 15 + 1 = 4. Actually: 18 - 15 + 1 = 4. Let me check: 2(9) = 18, 5(3) = 15, so 18 - 15 + 1 = 4.
Find the derivative of f(x) = 3x⁴ - 2x² + 7
Apply power rule and constant rule: d/dx(3x⁴) = 12x³, d/dx(-2x²) = -4x, d/dx(7) = 0. Therefore f'(x) = 12x³ - 4x + 0 = 12x³ - 4x.
Evaluate ∫(4x³ - 2x)dx
Apply power rule for integration: ∫4x³dx = 4(x⁴/4) = x⁴, ∫-2x dx = -2(x²/2) = -x². Therefore ∫(4x³ - 2x)dx = x⁴ - x² + C.
Find the derivative of y = (x² + 1)(x - 3) using the product rule
Let f(x) = x² + 1 and g(x) = x - 3. Then f'(x) = 2x and g'(x) = 1. Using product rule: y' = f(x)g'(x) + f'(x)g(x) = (x² + 1)(1) + (2x)(x - 3) = x² + 1 + 2x² - 6x = 3x² - 6x + 1.
Evaluate ∫[1 to 2] 3x²dx using Fundamental Theorem of Calculus
First find antiderivative: ∫3x²dx = x³ + C. Then apply FTC: ∫[1 to 2] 3x²dx = [x³] from 1 to 2 = 2³ - 1³ = 8 - 1 = 7.
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