FEUCAT Mathematics — Algebra — Sets, Exponents, Radicals, Polynomials & EquationsFlash Cards
The research on retention is unambiguous: retrieval practice beats re-reading for exam prep. These Algebra — Sets, Exponents, Radicals, Polynomials & Equations flashcards give FEUCAT candidates a structured way to apply that for the Mathematics subtest, card by card, against the concepts Far Eastern University uses most often on the 2026 paper.
Exam context
The Far Eastern University College Admission Test is conducted by Far Eastern University and is scheduled for Q3–Q4 2026. The Mathematics subtest is marked as "Core section" in the official pattern, and Algebra — Sets, Exponents, Radicals, Polynomials & Equations appears in position 3rd of 9 in the FEUCAT Mathematics review rotation. Passing mark: Competitive overall score. Recent FEUCAT 2026 papers have drawn roughly a meaningful share of questions from this subject.
Algebra — Sets, Exponents, Radicals, Polynomials & Equations - Flashcards
Master the fundamental building blocks of algebra through problem-solving! This comprehensive flashcard set covers sets, exponents, radicals, polynomials, and equations—essential topics for UPCAT and other college entrance exams. Each card focuses on practical problem-solving with step-by-step solutions to build your mathematical reasoning skills. Practice these problems regularly to develop confidence in algebraic manipulations and equation solving.
Cards
Find A ∪ B if A = {1, 3, 5, 7} and B = {2, 4, 6, 7}
Step 1: Union means all elements in either A or B (no duplicates). Step 2: List all elements from A: 1, 3, 5, 7. Step 3: Add elements from B not already in A: 2, 4, 6. Step 4: Note that 7 appears in both, so write it only once. Answer: A ∪ B = {1, 2, 3, 4, 5, 6, 7}
Tags
- set_operations
- union
- basic
Topic
Sets
Card Id
FC1
Difficulty
easy
Image Prompt
Find A ∩ B if A = {2, 4, 6, 8, 10} and B = {4, 8, 12, 16}
Step 1: Intersection means elements common to both A and B. Step 2: Check each element in A: 2 (not in B), 4 (in B ✓), 6 (not in B), 8 (in B ✓), 10 (not in B). Step 3: List common elements. Answer: A ∩ B = {4, 8}
Tags
- set_operations
- intersection
- basic
Topic
Sets
Card Id
FC2
Difficulty
easy
Image Prompt
Simplify: 2³ × 2⁵
Step 1: Apply product rule for exponents: aᵐ × aⁿ = aᵐ⁺ⁿ. Step 2: Same base (2), so add exponents: 2³ × 2⁵ = 2³⁺⁵. Step 3: Calculate: 2³⁺⁵ = 2⁸. Step 4: Evaluate: 2⁸ = 256. Answer: 256
Tags
- exponent_rules
- product_rule
- basic
Topic
Exponents
Card Id
FC3
Difficulty
easy
Image Prompt
Simplify: (3x²)³
Step 1: Apply power rule: (aᵐ)ⁿ = aᵐⁿ and (ab)ⁿ = aⁿbⁿ. Step 2: Raise each factor to the 3rd power: (3x²)³ = 3³ × (x²)³. Step 3: Calculate: 3³ = 27 and (x²)³ = x²ˣ³ = x⁶. Step 4: Combine results. Answer: 27x⁶
Tags
- exponent_rules
- power_rule
- intermediate
Topic
Exponents
Card Id
FC4
Difficulty
medium
Image Prompt
Solve for x: 2ˣ = 32
Step 1: Express 32 as a power of 2: 32 = 2⁵. Step 2: Substitute: 2ˣ = 2⁵. Step 3: Since bases are equal, exponents must be equal: x = 5. Step 4: Verify: 2⁵ = 32 ✓. Answer: x = 5
Tags
- exponential_equations
- same_base
- basic
Topic
Exponential Equations
Card Id
FC5
Difficulty
easy
Image Prompt
Simplify: √48
Step 1: Factor 48 into perfect square factors: 48 = 16 × 3 = 4² × 3. Step 2: Apply radical rule: √(a×b) = √a × √b. Step 3: √48 = √(16×3) = √16 × √3. Step 4: Simplify perfect square: √16 = 4. Answer: 4√3
Tags
- simplifying_radicals
- square_roots
- basic
Topic
Radicals
Card Id
FC6
Difficulty
easy
Image Prompt
Simplify: ∛54
Step 1: Factor 54 into perfect cube factors: 54 = 27 × 2 = 3³ × 2. Step 2: Apply cube root rule: ∛(a×b) = ∛a × ∛b. Step 3: ∛54 = ∛(27×2) = ∛27 × ∛2. Step 4: Simplify perfect cube: ∛27 = 3. Answer: 3∛2
Tags
- simplifying_radicals
- cube_roots
- intermediate
Topic
Radicals
Card Id
FC7
Difficulty
medium
Image Prompt
Rationalize the denominator: 6/√3
Step 1: To eliminate √3 from denominator, multiply by √3/√3. Step 2: (6/√3) × (√3/√3) = (6√3)/(√3×√3). Step 3: Simplify denominator: √3×√3 = 3. Step 4: Result: 6√3/3. Step 5: Simplify fraction: 6√3/3 = 2√3. Answer: 2√3
Tags
- rationalizing
- radicals
- intermediate
Topic
Radicals
Card Id
FC8
Difficulty
medium
Image Prompt
Add: (3x² + 5x - 2) + (2x² - 3x + 7)
Step 1: Remove parentheses: 3x² + 5x - 2 + 2x² - 3x + 7. Step 2: Group like terms: (3x² + 2x²) + (5x - 3x) + (-2 + 7). Step 3: Combine like terms: 5x² + 2x + 5. Answer: 5x² + 2x + 5
Tags
- polynomial_addition
- combining_like_terms
- basic
Topic
Polynomials
Card Id
FC9
Difficulty
easy
Image Prompt
Subtract: (4x³ - 2x + 1) - (x³ + 5x - 3)
Step 1: Distribute negative sign: 4x³ - 2x + 1 - x³ - 5x + 3. Step 2: Group like terms: (4x³ - x³) + (-2x - 5x) + (1 + 3). Step 3: Combine like terms: 3x³ - 7x + 4. Answer: 3x³ - 7x + 4
Tags
- polynomial_subtraction
- distributing_negative
- basic
Topic
Polynomials
Card Id
FC10
Difficulty
easy
Image Prompt
Multiply: (x + 4)(x - 3)
Step 1: Use FOIL method (First, Outer, Inner, Last). Step 2: First: x × x = x². Step 3: Outer: x × (-3) = -3x. Step 4: Inner: 4 × x = 4x. Step 5: Last: 4 × (-3) = -12. Step 6: Combine: x² - 3x + 4x - 12 = x² + x - 12. Answer: x² + x - 12
Tags
- polynomial_multiplication
- FOIL
- basic
Topic
Polynomials
Card Id
FC11
Difficulty
easy
Image Prompt
Factor: x² + 7x + 12
Step 1: Find two numbers that multiply to 12 and add to 7. Step 2: List factor pairs of 12: (1,12), (2,6), (3,4). Step 3: Check sums: 1+12=13, 2+6=8, 3+4=7 ✓. Step 4: Use 3 and 4: x² + 7x + 12 = (x + 3)(x + 4). Step 5: Verify: (x+3)(x+4) = x² + 4x + 3x + 12 = x² + 7x + 12 ✓. Answer: (x + 3)(x + 4)
Tags
- factoring
- trinomials
- intermediate
Topic
Polynomials
Card Id
FC12
Difficulty
medium
Image Prompt
Factor: x² - 9
Step 1: Recognize difference of squares pattern: a² - b². Step 2: Identify: x² - 9 = x² - 3². Step 3: Apply formula: a² - b² = (a + b)(a - b). Step 4: Substitute: x² - 3² = (x + 3)(x - 3). Step 5: Verify: (x+3)(x-3) = x² - 3x + 3x - 9 = x² - 9 ✓. Answer: (x + 3)(x - 3)
Tags
- factoring
- difference_of_squares
- intermediate
Topic
Polynomials
Card Id
FC13
Difficulty
medium
Image Prompt
Solve: 3x + 7 = 22
Step 1: Subtract 7 from both sides: 3x + 7 - 7 = 22 - 7. Step 2: Simplify: 3x = 15. Step 3: Divide both sides by 3: 3x/3 = 15/3. Step 4: Simplify: x = 5. Step 5: Check: 3(5) + 7 = 15 + 7 = 22 ✓. Answer: x = 5
Tags
- linear_equations
- one_step
- basic
Topic
Linear Equations
Card Id
FC14
Difficulty
easy
Image Prompt
Solve: 2(x - 3) = x + 4
Step 1: Distribute: 2x - 6 = x + 4. Step 2: Subtract x from both sides: 2x - x - 6 = x - x + 4. Step 3: Simplify: x - 6 = 4. Step 4: Add 6 to both sides: x - 6 + 6 = 4 + 6. Step 5: Simplify: x = 10. Step 6: Check: 2(10-3) = 2(7) = 14, and 10+4 = 14 ✓. Answer: x = 10
Tags
- linear_equations
- distributive_property
- intermediate
Topic
Linear Equations
Card Id
FC15
Difficulty
medium
Image Prompt
Solve using quadratic formula: x² - 5x + 6 = 0
Step 1: Identify a=1, b=-5, c=6. Step 2: Apply formula: x = [-b ± √(b²-4ac)] / (2a). Step 3: Calculate discriminant: b²-4ac = (-5)²-4(1)(6) = 25-24 = 1. Step 4: Substitute: x = [5 ± √1] / 2 = [5 ± 1] / 2. Step 5: Find solutions: x = (5+1)/2 = 3 or x = (5-1)/2 = 2. Answer: x = 2 or x = 3
Tags
- quadratic_formula
- quadratic_equations
- intermediate
Topic
Quadratic Equations
Card Id
FC16
Difficulty
medium
Image Prompt
Solve by factoring: x² - 4x - 5 = 0
Step 1: Find two numbers that multiply to -5 and add to -4. Step 2: Consider factor pairs: (-1,5), (1,-5). Step 3: Check: -1+5=4 (wrong sign), 1+(-5)=-4 ✓. Step 4: Factor: x² - 4x - 5 = (x + 1)(x - 5). Step 5: Set each factor to zero: x+1=0 or x-5=0. Step 6: Solve: x=-1 or x=5. Answer: x = -1 or x = 5
Tags
- factoring
- quadratic_equations
- intermediate
Topic
Quadratic Equations
Card Id
FC17
Difficulty
medium
Image Prompt
When do you use the quadratic formula instead of factoring?
Use quadratic formula when: 1) Trinomial doesn't factor easily with integers, 2) Discriminant is not a perfect square, 3) Coefficients are large or decimal. Example: x² + 3x + 1 = 0 has discriminant 9-4=5 (not perfect square), so factoring is difficult. Formula gives x = [-3 ± √5]/2.
Tags
- quadratic_formula
- when_to_use
- strategy
Topic
Quadratic Equations
Card Id
FC18
Difficulty
medium
Image Prompt
Solve the system: x + y = 8, 2x - y = 1
Step 1: Use elimination method. Step 2: Add equations to eliminate y: (x+y) + (2x-y) = 8 + 1. Step 3: Simplify: 3x = 9, so x = 3. Step 4: Substitute x=3 into first equation: 3 + y = 8. Step 5: Solve for y: y = 5. Step 6: Check in both equations: 3+5=8 ✓, 2(3)-5=1 ✓. Answer: x = 3, y = 5
Tags
- systems
- elimination_method
- intermediate
Topic
Systems of Equations
Card Id
FC19
Difficulty
medium
Image Prompt
Express in scientific notation: 0.00045
Step 1: Move decimal point right until you have one non-zero digit before decimal. Step 2: Count moves: 0.00045 → 4.5 × 10⁻⁴ (moved 4 places right). Step 3: Since we moved right, exponent is negative. Step 4: Verify: 4.5 × 10⁻⁴ = 4.5 × 0.0001 = 0.00045 ✓. Answer: 4.5 × 10⁻⁴
Tags
- scientific_notation
- small_numbers
- basic
Topic
Scientific Notation
Card Id
FC20
Difficulty
easy
Image Prompt
Tag Distribution
Basic
9
Medium
1
Radicals
3
Factoring
3
Intermediate
10
Exponent Rules
2
Set Operations
2
Equation Solving
7
Polynomial Operations
5
Topic Distribution
Sets
2
Radicals
3
Exponents
2
Polynomials
5
Linear Equations
2
Quadratic Equations
3
Scientific Notation
1
Systems Of Equations
1
Exponential Equations
1
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