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Civil Service Exam (Subprofessional) Numerical AbilityWord Problems — Speed/Distance/Age, Discount & InterestRevision Notes

Quick revision notes for Word Problems — Speed/Distance/Age, Discount & Interest — the one-page refresher for Civil Service Exam (Subprofessional) aspirants. Every item on this page has appeared in recent Civil Service Exam (Subprofessional) Numerical Ability papers, so revising these is the shortest path to a confident performance in Civil Service Commission (CSC)'s Civil Service Exam (Subprofessional) 2026.

Exam context

On the Civil Service Exam (Subprofessional) 2026, the Numerical Ability subtest carries a "~25% weightage" weight in Civil Service Commission (CSC)'s pattern. Word Problems — Speed/Distance/Age, Discount & Interest lands at position 6th out of 9 in the standard review order. Target score is 80%, and roughly 17 items come from Numerical Ability on a typical Civil Service Exam (Subprofessional) paper.

Word Problems — Speed/Distance/Age, Discount & Interest - Revision notes

This chapter focuses on solving real-world mathematical problems involving speed, distance, time, age relationships, discounts, and interest calculations. These problem-solving skills are essential for Civil Service examinations and practical applications in business, finance, and everyday life. Understanding these concepts will help you tackle word problems systematically and accurately.

Sections

Formulas

Example

A car travels 210 km in 3 hours. Speed = 210 ÷ 3 = 70 km/hr

Formula

Speed = Distance ÷ Time

Variables

Speed (km/hr, m/s), Distance (km, m), Time (hr, min, sec)

Application

Finding how fast someone or something is moving

Example

A train travels at 60 km/hr for 4 hours. Distance = 60 × 4 = 240 km

Formula

Distance = Speed × Time

Variables

Distance (km, m), Speed (km/hr, m/s), Time (hr, min, sec)

Application

Finding how far someone traveled

Example

180 km at 60 mph, return at 90 mph. Times: 3hr + 2hr = 5hr. Average = 360 ÷ 5 = 72 mph

Formula

Average Speed = Total Distance ÷ Total Time

Variables

Average Speed (km/hr), Total Distance (km), Total Time (hr)

Application

Finding average speed for trips with different speeds

Exam Tips

  • Always identify what is given and what needs to be found
  • Create a table for complex problems with multiple speeds or times
  • Remember: Distance has units like km, m; Speed has units like km/hr, m/s; Time has units like hr, min
  • For average speed problems, never add the speeds - always use total distance ÷ total time

Key Points

  • Speed is the distance traveled per unit time (Speed = Distance ÷ Time)
  • Distance is the total path covered (Distance = Speed × Time)
  • Time is the duration of travel (Time = Distance ÷ Speed)
  • Average speed = Total distance ÷ Total time (for round trips or multiple segments)
  • Unit conversions: 1 km/hr = 5/18 m/s, 1 m/s = 18/5 km/hr
  • For problems with two different speeds, create a table with distance, speed, and time for each segment

Definitions

Term

Speed

Definition

The rate at which distance is covered over time

Importance

Essential for calculating travel time and distance in transportation problems

Term

Average Speed

Definition

Total distance traveled divided by total time taken

Importance

Used when speed varies during the journey or for round trips

Section Title

Speed, Distance, and Time Problems

Common Mistakes

  • Adding speeds instead of using the average speed formula for round trips
  • Forgetting to convert units (hours to minutes, km/hr to m/s)
  • Not creating a systematic table for multi-segment journeys
  • Confusing distance with displacement in physics contexts

Formulas

Example

If Karylle is now 15, then 4 years ago she was 15 - 4 = 11 years old

Formula

Present Age ± n = Past/Future Age

Variables

Present age (years), n (number of years), Past/Future age (years)

Application

Converting between different time periods in age problems

Example

If ages are in ratio 3:2, and x = 5, then ages are 15 and 10 years

Formula

Age Ratio: If a:b, then ages are ax and bx

Variables

a, b (ratio numbers), x (common multiplier)

Application

When ages are given in ratio form

Exam Tips

  • Create a table with columns for each person and rows for different time periods
  • Clearly define your variable (usually the present age of one person)
  • Check your final answer by substituting back into the original problem
  • Age problems often have two equations that need to be solved simultaneously

Key Points

  • Age problems involve relationships between people's ages at different times
  • Present age, past age (n years ago), and future age (n years later) are key concepts
  • If present age is x, then: Past age = x - n, Future age = x + n
  • Age ratios: If ages are in ratio a:b, then ages are ax and bx
  • Set up equations based on the given relationships between ages
  • Use variables to represent unknown ages and solve systematically

Definitions

Term

Age Relationship

Definition

Mathematical connection between people's ages at different time periods

Importance

Forms the basis for setting up equations in age problems

Term

Time Period Shift

Definition

Moving between past, present, and future ages by adding or subtracting years

Importance

Essential for translating word problems into mathematical equations

Section Title

Age Word Problems

Common Mistakes

  • Confusing past and future age calculations (adding instead of subtracting)
  • Not maintaining consistency in time periods across all people in the problem
  • Forgetting to check if the solution makes logical sense (negative ages, etc.)
  • Setting up incorrect equations from complex word relationships

Formulas

Example

List price ₱1500, selling price ₱1200. Discount = 1500 - 1200 = ₱300

Formula

Discount = List Price - Selling Price

Variables

Discount (₱), List Price (₱), Selling Price (₱)

Application

Finding the amount of discount given

Example

Discount ₱30 on list price ₱150. Discount % = (30 ÷ 150) × 100 = 20%

Formula

Discount % = (Discount ÷ List Price) × 100

Variables

Discount % (percentage), Discount (₱), List Price (₱)

Application

Finding the percentage rate of discount

Example

List price ₱1500, 20% discount. Selling price = 1500 × (1 - 0.20) = ₱1200

Formula

Selling Price = List Price × (1 - Discount Rate)

Variables

Selling Price (₱), List Price (₱), Discount Rate (decimal form)

Application

Quick calculation of final price after discount

Exam Tips

  • Always identify which values are given: list price, selling price, discount amount, or discount %
  • Remember: Discount % is always calculated based on the list price, not selling price
  • Check if your discount percentage makes sense (should be less than 100%)
  • Practice both methods: direct calculation and using (100% - discount%) approach

Key Points

  • Discount is the reduction in the original price of an item
  • List price (marked price) is the original tagged price
  • Selling price is the actual price paid after discount
  • Discount can be expressed as amount (₱) or percentage (%)
  • Types: Trade discount, quantity discount, promotional discount
  • Alternative calculation: Selling price = List price × (100% - Discount%)

Definitions

Term

List Price

Definition

The original marked price of an item before any discounts

Importance

Starting point for all discount calculations

Term

Discount Rate

Definition

The percentage reduction applied to the list price

Importance

Determines how much customers save on their purchase

Term

Selling Price

Definition

The final price customers pay after discount is applied

Importance

The actual amount received by the seller

Section Title

Discount Problems

Common Mistakes

  • Confusing discount amount with discount percentage
  • Using selling price instead of list price in percentage calculations
  • Forgetting to convert percentage to decimal form in calculations
  • Not distinguishing between different types of discounts in complex problems

Formulas

Example

₱60,000 at 10% for 9 months. I = 60,000 × 0.10 × 0.75 = ₱4,500

Formula

Simple Interest: I = Prt

Variables

I (interest), P (principal), r (rate as decimal), t (time in years)

Application

Calculating interest earned or paid on loans and investments

Example

₱2M at 0.5% for 5 years. F = 2,000,000(1 + 0.005 × 5) = ₱2,050,000

Formula

Future Value (Simple): F = P(1 + rt)

Variables

F (future value), P (principal), r (rate), t (time)

Application

Finding total amount after simple interest

Example

₱15,000 at 3% for 3 years. F = 15,000(1.03)³ = ₱16,390.91

Formula

Future Value (Compound): F = P(1 + r)ᵗ

Variables

F (future value), P (principal), r (rate), t (time)

Application

Calculating compound interest growth

Exam Tips

  • Always convert percentage to decimal and time to years before calculating
  • For simple interest: I = Prt, then F = P + I
  • For compound interest: F = P(1 + r)ᵗ, then I = F - P
  • Remember: Simple interest grows linearly, compound interest grows exponentially
  • Check units: P and F in pesos, r as decimal, t in years, I in pesos

Key Points

  • Simple interest is calculated only on the principal amount
  • Compound interest is calculated on principal plus accumulated interest
  • Principal (P) is the original amount borrowed or invested
  • Rate (r) is the annual interest rate (convert % to decimal)
  • Time (t) must be expressed in years
  • Maturity/Future value is the total amount after interest
  • Simple interest: I = Prt, Future value: F = P + I or F = P(1 + rt)
  • Compound interest: F = P(1 + r)ᵗ, Interest: I = F - P

Definitions

Term

Principal

Definition

The original amount of money borrowed or invested

Importance

Base amount on which all interest calculations are made

Term

Simple Interest

Definition

Interest calculated only on the principal amount throughout the investment period

Importance

Common in basic loans and simple investment scenarios

Term

Compound Interest

Definition

Interest calculated on principal plus previously earned interest

Importance

Reflects real-world investment growth and compound growth scenarios

Term

Maturity Value

Definition

Total amount (principal + interest) at the end of the investment period

Importance

Final amount received by investor or paid by borrower

Section Title

Interest Problems (Simple and Compound)

Common Mistakes

  • Forgetting to convert percentage rates to decimal form (divide by 100)
  • Not converting months to years (divide months by 12)
  • Using simple interest formula when compound interest is required
  • Confusing interest amount with total maturity value
  • Incorrect calculation of compound interest exponents

Connections

  • Speed-distance-time problems connect to physics concepts of motion and velocity
  • Interest calculations are fundamental to banking, finance, and economics
  • Discount problems relate to business mathematics and consumer economics
  • Age problems develop logical reasoning and equation-solving skills used in algebra
  • All problem types require unit conversion skills essential in science and engineering
  • These concepts appear in various forms across Civil Service, UPCAT, and professional examinations

Exam Strategy

For word problems, always follow the systematic approach: (1) Read carefully and identify what's given and what's asked, (2) Choose appropriate formulas, (3) Set up equations or calculations step by step, (4) Solve systematically, (5) Check your answer for reasonableness. Create tables for complex problems involving multiple variables or time periods. Practice converting units and working with percentages in decimal form. Remember that most exam questions test your ability to translate word problems into mathematical expressions, so focus on understanding the relationships described in the problems rather than just memorizing formulas.

Quick Review Questions

A car travels 150 km in 2.5 hours. What is its speed in km/hr?

Speed = Distance ÷ Time = 150 ÷ 2.5 = 60 km/hr

If a shirt originally costs ₱800 and is sold for ₱640, what is the discount percentage?

Discount = 800 - 640 = ₱160. Discount % = (160 ÷ 800) × 100 = 20%

John is twice as old as Mary. In 5 years, John will be 35. How old is Mary now?

John's present age = 35 - 5 = 30. Since John is twice Mary's age: Mary = 30 ÷ 2 = 15

What simple interest is earned on ₱10,000 at 6% per year for 8 months?

I = Prt = 10,000 × 0.06 × (8/12) = 10,000 × 0.06 × 0.667 = ₱400

A person travels 60 km at 40 km/hr, then 80 km at 50 km/hr. What is the average speed?

Time1 = 60/40 = 1.5 hr, Time2 = 80/50 = 1.6 hr. Average = (60+80)/(1.5+1.6) = 140/3.1 = 45.16 km/hr

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