LET Elementary Mathematics Reviewer 2026

Answer: A. 5/12

Step 1: We need to find how much was spent, then subtract from 1 (the whole allowance). Step 2: Find the LCD of 3 and 4, which is 12. Rewrite: 1/3 = 4/12 and 1/4 = 3/12. Step 3: Total spent = 4/12 + 3/12 = 7/12. Step 4: Amount left = 1 − 7/12 = 12/12 − 7/12 = 5/12. Common mistake: Choosing 7/12, which is what was SPENT, not what was LEFT.

Answer: A. 4 1/4

Step 1: We add two mixed numbers: 2 1/2 + 1 3/4. Step 2: Convert to improper fractions: 2 1/2 = 5/2 and 1 3/4 = 7/4. Step 3: LCD of 2 and 4 is 4. Rewrite 5/2 = 10/4. Step 4: 10/4 + 7/4 = 17/4. Step 5: Convert back to mixed number: 17 ÷ 4 = 4 remainder 1, so the answer is 4 1/4 meters. Common mistake: Adding whole numbers (3) and fractions (1/2 + 3/4 = 5/4 = 1 1/4) separately gives 3 + 1 1/4 = 4 1/4 — same answer, but always check fraction addition carefully.

Answer: A. 25%

Step 1: To convert a decimal to a percent, multiply by 100 (or move the decimal point two places to the right). Step 2: 0.25 × 100 = 25. Step 3: Add the percent sign: 25%. Common mistake: Moving the decimal only one place gives 2.5%, which is incorrect. Remember: percent means 'per hundred,' so you always multiply by 100.

Answer: A. 75%

Step 1: This is Case 2 of percentage — find the RATE. Formula: Rate = Part ÷ Base. Step 2: Part = 30 (pupils who passed), Base = 40 (total pupils). Step 3: Rate = 30 ÷ 40 = 0.75. Step 4: Convert to percent: 0.75 × 100 = 75%. Common mistake: Using 30 as the base instead of 40. The base is always the TOTAL or WHOLE amount.

Answer: A. ₱400

Step 1: A 20% discount means the buyer pays 100% − 20% = 80% of the original price. Step 2: Convert 80% to decimal: 0.80. Step 3: Sale price = 0.80 × 500 = ₱400. Alternative method: Discount amount = 0.20 × 500 = ₱100; Sale price = 500 − 100 = ₱400. Common mistake: Choosing ₱100, which is only the DISCOUNT AMOUNT, not the sale price.

Answer: A. 30

Step 1: We need the unit rate — papers per teacher. Step 2: Total papers = 120, number of teachers = 4. Step 3: Papers per teacher = 120 ÷ 4 = 30. Step 4: So 1 teacher checks 30 papers in 3 hours. This is a direct proportion/unit rate problem. Common mistake: Multiplying 120 × 4 = 480, which would be the papers if there were 4 times as many teachers — wrong direction.

Answer: A. ₱450

Step 1: This is partitive proportion. Add the ratio parts: 1 + 2 + 3 = 6 total parts. Step 2: Value of one part = ₱900 ÷ 6 = ₱150. Step 3: The three shares are 1 × 150 = ₱150, 2 × 150 = ₱300, and 3 × 150 = ₱450. Step 4: The largest share (ratio 3) = ₱450. Verification: 150 + 300 + 450 = ₱900. ✓ Common mistake: Dividing ₱900 equally by 3, giving ₱300 each — this ignores the ratio.

Answer: A. 4 1/2

Step 1: This is a direct proportion. Set up the proportion: (1 1/2)/4 = x/12. Step 2: Convert 1 1/2 to an improper fraction: 3/2. Step 3: Cross-multiply: 4x = (3/2) × 12 = 18. Step 4: x = 18 ÷ 4 = 4.5 = 4 1/2 cups. Alternative: 12 servings is 3 times 4 servings, so multiply the rice by 3: 1 1/2 × 3 = 4 1/2 cups. ✓

Answer: B. 70 m²

Step 1: Identify the formula. Area of a rectangle = length × width. Step 2: Substitute the values. Area = 10 × 7. Step 3: Compute. Area = 70 m². The answer is 70 m². Note: 34 m² is the perimeter divided by 2 — a common mistake of confusing area with perimeter. Always remember area uses square units.

Answer: B. 52°

Step 1: Recall the definition. Complementary angles sum to 90°. Step 2: Set up the equation. Other angle = 90° − 38°. Step 3: Compute. Other angle = 52°. Verification: 38° + 52° = 90°. ✓ Common mistake: Students sometimes subtract from 180° (which gives the supplement, not the complement).

Answer: B. 50°

Step 1: Recall the triangle angle-sum theorem. The three interior angles of any triangle sum to 180°. Step 2: Add the two known angles. 55° + 75° = 130°. Step 3: Subtract from 180°. Third angle = 180° − 130° = 50°. Verification: 55 + 75 + 50 = 180°. ✓

Answer: C. 36 m

Step 1: Recall the formula. Perimeter of a square = 4 × side. Step 2: Substitute. Perimeter = 4 × 9. Step 3: Compute. Perimeter = 36 m. Common mistake: 81 m is the area (9²), not the perimeter. Always distinguish between perimeter (length around) and area (space inside).